Internat.
J. Math. & Math. Sci.VOL. 15 NO. (1992) 103-106
I"-GROUP CONGRUENCES ON REGULAR F-SEMIGROUPS
A.SETH
Department
ofPure
Mathematics, University of Calcutta 35, Ballygunge Circular Road, Calcutta 700 019.India.
(Received April 23, 1990 and in revised form September 16, 1990)
103
ABSTRACT. In
this paper aF-group
congruence on a regular F-semigroup is defined, some equivalent expressions for anyF-group congruence
on a regular F-semigroup and those for the leastF-group congruence
in particular are given.KEY WORDS AND PHRASES.
Regular F-semigroup, a-idempotent, Right(left)
F-ideal, Right(left)
simple F-semigroup,F-group, Congruence,
Normal family.1980 AMS
SUBJECT CLASSIFICATION CODE.
20M.1.
INTRODUCTION.
Let
S andF
be two nonempty sets,S
is called aF-semigroup
if for all a,b,cE S, a,B F
(i) aab G S and (ii)(aab)Bc aa(bBc)
hold.S
is called regularF-semigroup
if for any a
E
S there exista’ S, a,B F
such that aaoa’Ba. We
saya’
is (,B)-inverse of a if aaoa’Ba
anda’ a’Baoa’
hold and in this case we writea’ VB(a). An
element e of S is called =-idempotent ifee
e holds inS.
A right(left)
F-ideal of a F-semigroup S is a nonempty subsetI
of S such thatI FS _ I
(SFI C_.
I).A F-semigroup S
is said to be left (right) simple if it has no proper left (right) F-ideal.For
some fixed aE F
if we define aob ab for all a,b S thenS
becomes a semigroup.We
denote this semigroup byS.
Throughout our discussionwe shall use the notations and results of
Sen
and Saha[1-2]. For
the sake of com- pleteness let us recall the following results of Sen and Saha[1].
THEOREM
1.1.S=
is a group if and only if S is both left simple and rightsimple F-semigroup.
(Theorem
2.1 of[1 ]).
COROLLARY
1.2.Let S
be a F-semigroup. IfSa
is agrou
for someE F
thenS
is a group for all aF.
(Corollary 2.2 of[1]).
A
F-seigroup S is called aF-group
ifSa
isagroup.for some(hence
forall)a F.
THEOREM
1.3. A regular F-semigroup S will be aF-group
if and only if for all=,B F,
ef fe f andeBf fe
e for any two idempotents eee
and ffBf
ofS. (Theorem
3.3 of[1]).
2.
F-GROUP CONGRUENCES IN A REGULAR F-SEMIGROUP.
An
equivalence relation O on a F-semigroup S is called acongruence
if(a,b)
O implies(ccm,cb)
and(aac,bc) E D
for all a,b,cS, F A
congruence O in a regular F-semigroupS
is calledF-group
congruence ifS/D
is aF-group
(InS/O
we define(aO)(bO) (ab)O).
Henceforth we shall assume S to be a regularF-
semigroup and
E
a to be its set of a-idempotents.A
family{K
a
a F}
of subsets of S is said to be a normal family if (i)E a_ K
a for all aF
(ii) for each a
K
a and bK
B, aabK
B
andaBb K
a(iii) for each
a’ VaB(a)
andc Ky, aacYa’
andaycaa’ E
KB.
104 A. SETH
Now let e
E E
a and fE E
andE r. Let
xE V:(eBf).
Thenfexbe E.
ThusE
for allD r,
consequently for allr. We
further note that in an orthodoxr-semigroup
S ofSen
and Saha[2] {E
a r} is a normal family ofS.
let N be the collection of all normal families
K.
of S(iEA)
where1
K
i{Ki
r}.Let
UaiAia
and U{U a r}.
Then obviouslyE U.
Also if
a Ua,
bUS,
thena Ki
for allA,
bKiB
for all i ^. Thusab
Ki8
andaBb, Ki
for all iA
implyingaab U
andaBb
Ua.
Similarly we can show that if aV(a)
and cUe
thenaecya’, ayca’
UB.
Thus U is a normalfamily of subsets of S and U is the least member in N if we define a partial order in N by
K
i
Kj
iffKiaC_ Kj
for alla r. We
also observe that whenS
is orthodox r-semigroup, U{E
a
r}.
THEOREM
2.1Let
S be a regularr-semigroup.
Then for eachK {Ke r} N,
o K {(a,b) SxS a=e fBb
for somea,B r
and eK=,
fKS}
is ar-group
congruence in
S.
PROOF. Let
aS
anda’ VBa)
Thena=(a’a) (aa’)Ba
implies(a a)
OK Next
let(a,b)
OK.
Then there exist eK,
fK B
for some,B r
such thatae
fBb. Let a’ V(a)
andb’E V(b)
such thatbe((b’fBb)y(a’Sa)
((beb’)(aaeya’))Sa. But b’fBb K e, a’Sa Ky
and so(b’fgb)Y(a’Sa) K e
andbgb’
K, aaeya’ K5
and so(beb’)(aeya’) KS. Consequently, (b,a)
OK Now
let(a,b) OK, (b,c)
OK
Then there exist,B,Y,5 r, e K,
fK B,
gKy,
h
K5
such that aefBb
and bg hSc.But a(eyg) (ae)yg (fBb)Yg fB(bYg)
fg(hSc)
(fBh)c
where e’fgK
andfBh E KS.
Thus(a,c)
OK
and consequently OK
is an equivalence relation.Let (a,b) OK, r,
cs.
Thenae fBb
for somea,Br
and some eKa,
feKB. Let c’ Vy6(c)
yE V61(bec),
xE V(aec).
Now (agc)(c’5((cY2x52a)ae)ec)Y1 (y51(bec)) (aecY2x)2fB(becYlY)51(bgc). But
cY2x2a EeC K e,
so(cY2x2a)ae K e, c’((cY2x2a)ae)8c Ky.
Againy61(bgc) Ey C__ Ky
and consequently(c’6((cY2x2a)ae)ec)Y1(Y61bec) Ky. By
asimilar
argument welcan
show that(agcY2x)62fB(becY1Y) K6
Thus(aec,bc)
0K.
Also it is immediate from the foregoing by duality that
(cg,cgb)
1 OK
Thus OK
is a congruence onS.
Also as S is regular, S/pK
is a regular r-semigroup.Let
eE a,
f
E B.
Thenear,
faeK B, eBf, fBe K a. Now (eaf)Bf (eaf)f
shows that(eaf,f) K
and(fae)Bf (fae)Bf
implies that(fae,f)
OK.
Thus(eOK)a (fOK)=fOK
and
(fOK)a(eOK) fO
K, Similarly we can show(eK)B(f K)
eDK
and(fPK)(eOK)
eOK.
So
it follows from Theorem 1.3 thatS/ K
is ar-group.
Thus OK
is ar-group
congru- ence onS.
For
any normal familyK {K
a a
r}
ofs,
the closureKW
ofK
is the family defined byKW {(KW)y
yr}
where(KW)y {x S eax Ky
for some ar
ande
KQ}. We
callK
closed ifK KW.
THEOREM 2.2
For
eachK N, DK {(a’b) SsS
aYb’(. "oorsome b’ VC(b)}.
PROOF. Let (a,b) PK"
ThenfBa
bee for somea,B r
and eK
a, fK B-
Then
fB(ayb’) baeyb’ K
for someb’ V(b).
Consequentlyayb’ (KW).
Conversely, letab’ (KW)
for someb’ Vy(b).
Theneaayb’e K
for somea r
and ee K a.
There-fore
eaa{b’
f where fK. So (bg(a’eaa)yb’)a be(a’fa),
for somea’ Ve(a)
where
bg(a’eea)yb’ K 6
anda’fa KS.
Consequently(a,b) K"
For
anycongruence
0 onS,
let ker, 0{(ker )a
a6 r}
where(ker
O)
a
{x
Seox
for some eEa }"
-GROUP CONGRUENCES ON REGULAR -SEMIGROUPS 105
LEMWA
"2.3.For
any KE ,
ker OK W.PR()F.
To
prove ker oK KW, we are to show that (k.erOK)a (k:’)r
for a]F- For
this let x (kerOK)a
for some aF.
TheneOKX
for some ela
that isef gyx
for some ;3,7 F, eEa,
fK,
gKy.
So gyxK
asef E K.
1’busx
(KW) Next
let x (KW) ThengyxE
K for some yF
and g K Now for some e Eea(gyx) (eg)yx
where gyxK
and eagE
K ThuseoKx.
Consequently x(er OK)a.
So (kerOK)
a (KW)u for all aE F.
t
K N and suppose ayb’(KW)
6 for some b’Vy(b). en
eaayb’ K6 for some aE F
and eE
Ka.
Then for anya’ V(a), a’b(eYb’)6a K@and (a’eaaYb’6a)Oa’bb
(a’ea)yb’6(aOa’)b KO. us a’b E ()8"
Conversely, supposea’b (KW)
0 for somea’ V(a). The fB(a’b) E K
for someB F
and fK B
anda0(fBa’b)a’ m.
Therefore for some b
V6y(b), (aOfBa’bOa’)(aYb’) (a0fBa’)bb0(a’ba)Yb’ K
erefore ayb’
(KW). us
ayb’(KW)
6 for some (all)b’ V(b)iffa’b (KW)
for some (all)
a’ V(a).
Interchanging roles of a and b we see thatba’
for some (all)
a’ V(a)
iffb’6a (4)
for some (all)b’ V$(b). Moreover,
thesyetric property of 0
K
shows that ayb(KW)
for some(all)
by(b)
iffboa’ (KW)
b for some (all)
a’ V(a). us
we have the following.LIA
2.4.For
each N,aOKb
iff one of the following equivalent conditions hold.(i)
ayb’E (KW)
6 for some(all)
(ii)
b’a E (KW)y
for some(a11) b’e V6(b)
(iii)
a’bE (KW)
for some(all) a’
(iv)
ba’ E (KW)
for some (all)a’ V(a).
Let
N denote the collection of all closed families inN,
thenN
N.THEOREM
2.5. The mappingK
0K {(a,b)
SSaYb’ K
for someb’ V(b)}
is a one to one order preserving mapping of N onto the set of
F-group
congruences onS.
PROOF. Let
O be aF-group
congruence on S.Let
us denote ker OThen
K {x
S xOe whene Ea}
ThenE
CK a-
by
K
and(ker O)
byK.
aLet
aKa,
bE K B
then ape andbof
where eEa
and f EB. Now (ab)o (aO)(bo) (eo)a(fo) fo.
Thus abof, where fE B.
Thus abK B.
SimilarlyaBb K=.
Next
leta’ V(a)
and cK
Then cog where gE
Then(cya’)O (aO)(co)y(a’O) (ao)a((gO)y(a’o)) (ao)(a’o) (aa’)O.
Thusacya’Oaaa’
whereaa’ E B. Hence
acya’ K
B.
Similarlyayca’ K B.
ThereforeK
is a normal family of subsets ofS.
Next (KW)y {x
S exKy
where eK
for someF}.
ThenKy C_ (KW)y. To
show
(KW)y Ky,
let x()y.
Then eaxKy
for someF
ande K a.
Consequently(ex)O
gO where gEy or(eo)(xO)
gO or, xO go or, xKy.
Thus(KW)y Ky.
Therefore
K
KW and soK
ker ON.
Thus if O is aF-group
congruence, then ker OK N.
We shall now prove that OK
O. If(a,b)
OK
thenaYb’E K5
forsome
b’ V$(b).
ThusaYb’
O h for some hE5
and aO(aO)Y((b’Sb)o)=(hO)(bO)=bO.
Thus
OK
O.Conversely,
if(a,b)
O and b’V$(b),tIenyb,’o byb’ E0
n’a,b). K.
Therefore O O
K
Thus from above and by lemma 2.3 for anyN, K
/OK-iS
a one-to-one mapping from
N
onto the set of allF-group
congruences onS.
Also it is easy to see thatK
/ OK
is an order preserving mapping.Let
I be aF-group
congruence onS,
by the proof of Theorem 2.5OK,
whereK
kerN.
Thus eachF-group
congruence is of the form OK
for someK
NN.
106 A. SETH Thus hy lemma 2.3 we have,
THEOREH
2.6. The leastF-group
congruenceo
on S is given by 0 0Uandkero=.
EOREH
2.7.For
anyF-group
congruence OK
withK
inN,
on a regular F-semigroup, the following are equivalent.(i) (ii) (iii) (iv)
(v)
(vi) (vii) (viii)PROOF.
aOKb.
axYb’ E K
for somex K
a’&xb
K0 for someK
bxga’
K
for somex K
b’xaE
K, for some xK
(
F) and some(all) b’ V(b).
(E
F) and some(all) a’ V(a).
(B F)
and some(all) a’ V(a)
(B F)
and some (all)b’V(b).
ae
fBb
for some=,B F
and some eK,
fKS.
e
bBf
for some, F
and some eK,
fK.
KBBaKaO KBbK
for some,B F.
(ii)
=>
(iii)Suppose
axyb’K
for some xK
and b’Vy(b).
Then forany
a’ V(a), a’(axyb’)b (a’a)(x(b’b)) K
8 asa’a K@
and xyb’bK.
(iii)
=>
(vi)Let a’xb K8
fora’ V(a)
and xK.
Then ag(a’xub)
(aa’x)b
which is (vi) asa’xb K@
and aga’xK.
(vi)
=>
(viii)Let
a=efBb
for some,B F
and eK
fE K B.
Then we havefBaaee fBfBbe
implyingKBBaK KBBbK b.
(viii)
=>
(ii)Let K^BaK
(lKBbK
b. ThenxBay XlBb=y
for some x,xK B
y,yl K=.
Ifa’ EV(), b’ V(b),them’a’xBa EK
8 and(a’xBa)y KO
and we have,ag(a’xBa=y)yb’ (a@a’)b(xBay)yb’ (aga’)b(XlBb=yl)Yb’ (a@a’)XlB(b=YlYb’) K
as
baYlfb’ K, XlB(b=YlYb’) K
anda@a’ K.
Thus (ii), (iii), (vi) and (viii) are equivalent.
Interchanging the roles of a and b we see that (iv),
(v),
(vii) and (viii) are equivalent. Also (i) and (vi) are equivalent by Theorem 2.1. Thus all the conditions (i) (viii) are equivalent.COROLLARY
2.8.Let o
denote the leastF-group
congruence on a regular F-semi- groupS.
Then the following are equivalent.(i) (ii) (iii) (iv)
(v)
(vi)(vii)
(viii)aOb.