井戸 絢子 (奈良女子大学 D1)
On Reeb graphs derived from
Heegaard splittings with distance 2g
20 / 12 / 2010 結び目の数学Ⅲ@日本大学
1. Preliminaries
M : a closed orientable 3-manifold
Def. A ∪P B : a (genus g) Heegaard splitting of M ⇔ A, B ⊂ M : genus g handlebodies s.t.
・ M = A ∪ B ,
・ A ∩ B = ∂A = ∂B = P : Heegaard surface
S : a closed orientable surface of genus ≥ 2 Def.(curve complex)
CS : the curve complex of S
s.t. ・ the vertices correspond to isotopy classes of essential simple closed curves on S
・ the edges are drawn between vertices corresponding to disjoint curves.
S C
sA∪PB : a genus g (≥2) Heegaard splitting of M Def. (Hempel distance)
D(A), D(B) : the subsets of the curve complex CP corresponding to curves on P bounding disks in A , B.
d(P):= d(D(A), D(B)) : the Hempel distance of P
d(P)=0
DA
DB
d(P)=1
d(P)=2
DA
DA
DB
DB
Thm. [Cf. Scharlemann-Tomova, 2006]
P, Q : genus g Heegaard surfaces in M
Suppose that Q is not isotopic to P, then d(P) 2≦ g.
( i.e. d(P)>2g ⇒ Q is isotopic to P )
Fact [Cf. Berge-Scharlemann, 2010]
P, Q : genus 2 Heegaard surfaces in M
Suppose d(P)=4. Then Q is isotopic to P.
M.Scharlemann, M.Tomova, Alternate Heegaard genus bounds distance, Geom. Topol. 10(2006) 593--617 H. Rubinstein and M. Scharlemann, Genus two Heegaard splittings of ori-entable 3-manifolds, in Proceedings of the 1998 Kirbyfest, Geometry and TopologyMonographs 2 (1999) 489-553.
J. Berge and M. Scharlemann, Multiple genus 2 Heegaard splittings: a missed case, ArXiv preprint arXiv:0910.3921
Rubinstein -Scharlemann gave the list of 3-mfds each admitting inequivalent genus 2 Heegaard splittings. Recently, Berge-Scharlemann pointed out there is a missing case in the list, and gave the complete list. Their result implies the following fact.
Question
P, Q : genus g Heegaard surfaces in M
Suppose d(P)=2g. Is Q isotopic to P ? Question
P, Q : genus g Heegaard surfaces in M
Suppose d(P)=2g. Is Q isotopic to P ?
In this talk, we show that Q is isotopic to a canonical position w.r.t. P, if Q is not isotopic to P and d(P)=2g. And as an application, we give an alternative proof of the above fact.
M = ΣA
∪
P×(0,1)∪
ΣBA
∪
PB : a Heegaard splitting of M ΣA, ΣB : spines of A, Bspine of handlebody
Ps=f (s) -1 (s∈(0, 1)) : level surface of f We may suppose
P×(0,1) → (0,1)
can be extended to a smooth map f : M → [0,1]
s.t. ・f (ΣA)=0, f (ΣB)=1 ・each level surface is isotopic to P.
: a sweep-out of P
2. Main result
2-1. Sweep-out
0
M
1Σ
AΣ
BP
sP, Q: Heegaard surfaces in M f :a sweep out of P f |Q: Q → [0,1]
x~y (x, y ∈ M) ⇔ ∃s∈ [0,1] s.t. x, y are in the same comp. of (f|Q) (s).
Q / ~ : Reeb graph
Reeb graph of Q-1
2-2. Reeb graph
Lemma. [Tao Li, Cf. Johnson]
P, Q : Heegaard surfaces in M ΣA, ΣB : spines of A, B fix f : sweep out of P Suppose that d(P) 2. Then ≧ Q can be isotoped so that
(1) Q∩ΣA and Q∩ΣB consists of finitely many points ; (2) Q is transverse to each Ps, s∈(0,1),
except for finitely many critical levels s1,..., sn ∈(0,1) ; (3) at each critical level si, Q is transverse to Psi,
except for a single saddle or circle tangency;
(4) at each regular level Ps, every component of Q∩Ps is an essential curve on Ps.
T.Li. Saddle tangencies and the distance of Heegaard splittings, Algebr. Geom. Topol. 7 (2007), 1119—1134.
J. Johnson, Flipping and stabilizing Heegaard splittings, preprint 2008),ArXiv:math.GT/08054422.
Q :
circle tangency:Lemma. [Tao Li, Cf. Johnson]
∃si, sj (si<sj) s.t. ∀s∈ (si, sj) : regular value, each comp. of Ps∩Q is essential on both Ps and Q. For any small ε>0, Psi-ε∩Q contains a curve bounding a meridian disk in A, and Psj+ε∩Q contains a curve bounding a meridian disk in B.
Thm. [Cf. Scharlemann-Tomova, 2006]
si ess. curves on P and Q sj
By making use surfaces satisfying the above Lemmas, Tao Li and Johnson give an alternative proof of the following theorem.
Q
P, Q: Heegaard surfaces in M f :a sweep out of P f |Q: Q → [0,1]
x~y (x, y ∈ M) ⇔ ∃s∈ [0,1] s.t. x, y are in the same comp. of (f|Q) (s).
Q / ~ : Reeb graph
Reeb graph of Q-1
2-2. Reeb graph
si+ε sjーε
P, Q : genus g Heegaard surfaces in M
Suppose that Q is not isotopic to P and d(P)=2g, then Q can be isotoped so that the corresponding Reeb graph G is as follows.
d(D(A),c)=1 1
2
3
3 2g-1
2g-3
2g-3
v
2v
1v
2g-1 2g-2v
2g-22g-1
Main result
s
i+εs
jーεApplication; an alternative proof of the following fact
Fact [Cf. Berge-Scharlemann, 2010]
P, Q : genus 2 Heegaard surfaces in M
Suppose d(P)=4. Q is isotopic to P.
Outline of proof
PX,PY : P∩X, P∩Y QA, QB : Q∩A, Q∩B s
P
Q
A B
X Y
PX PY
QA
QB
Suppose Q is not isotopic to P
M
and d(P)=4 1
1
2
3
3
Remark. PX (resp. PY, QA, QB) is incompressible in X (resp. X, Y, A, B)
Lem. [Rubinstein-Scharlemann 1999]
Suppose that PX, PY, QA, QB are incompressible in respectively X, Y , A, B. Then PX
∂–compresses to one of QA or QB , and PY ∂–compresses to the other.
P
Q
A B
X Y
M
∂-comp. disks
PX PY
QA
QB
P
Q
A B
X Y
M
P*=Q*
P*, Q* : subsurfaces in P, Q
s.t. P* and Q* are isotopic (χ(P*)= -2 )
The curves corresponding to points of these levels are disjoint on P.
P*= Q*
1
1
2
3
3
∴ d(P) 3 : a contradiction ≦