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Comment.Math.Univ.Carolin. 35,4 (1994)795–797 795

Checking positive definiteness or stability of symmetric interval matrices is NP-hard

Jiˇr´ı Rohn*

Abstract. It is proved that checking positive definiteness, stability or nonsingularity of all [symmetric] matrices contained in a symmetric interval matrix is NP-hard.

Keywords: positive definiteness, stability, nonsingularity, NP-hardness Classification: 15A48, 15A18, 68Q25

As is well known, a square (not necessarily symmetric) matrix A is called positive definite if xTAx > 0 for each x6= 0, stable if Reλ <0 for each eigen- value λof A, and Schur stable if ̺(A) <1. We prove here that checking these properties is NP-hard (see [1]) for a symmetric interval matrix AI =

A, A :=

A;A≤A≤A . By definition, AI is called symmetric if both A and A are symmetric; hence, a symmetricAI may contain nonsymmetric matrices. IfAI is symmetric andA∈AI, then 12(A+AT)∈AI. Letλmin(A) denote the minimal eigenvalue of a symmetric matrixA. We have these results:

Theorem. For a symmetric interval matrixAIwith rational bounds, each of the following problems is NP-hard:

(i) check whether eachA∈AI is positive definite,

(ii) check whether each symmetricA∈AI is positive definite, (iii) check whether eachA∈AI is stable,

(iv) check whether each symmetricA∈AI is stable, (v) check whether eachA∈AI is nonsingular,

(vi) check whether each symmetricA∈AI is nonsingular, (vii) check whether each symmetricA∈AI is Schur stable,

(viii) given rational numbersa, b,a < b, check whetherλmin(A)∈(a, b)for each symmetricA∈AI.

Proof: Let us call a symmetric real n×n matrix A = (aij) an MC-matrix if aii = n and aij ∈ {0,−1} for i 6=j (i, j = 1, . . . , n). Then for each x 6= 0 we havexTAx≥nkxk22−P

i6=j|xixj|= (n+ 1)kxk22− kxk21≥ kxk22>0, henceAis

*This work was supported by the Charles University Grant Agency under grant GAUK 237.

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796 J. Rohn

positive definite (and so isA−1). For an MC-matrixA and a positive integerL, let us form three symmetric interval matrices

AI=

A−1− 1

LeeT, A−1+ 1 LeeT

, AI0=

−A−1− 1

LeeT,−A−1+ 1 LeeT

and

AI1=

I+ 1

m(−A−1− 1

LeeT), I+ 1

m(−A−1+ 1 LeeT)

,

wheree= (1,1, . . . ,1)T,I is the unit matrix andm=kA−1k+Ln+ 1. Hence, AI0 ={−A;A∈AI},AI1 ={I+m1A;A∈AI0} and̺(A)≤ kAk< mfor each A∈AI. We shall prove that the following assertions are mutually equivalent:

0) zTAz≥L for somez∈ {−1,1}n,

1) AI contains a matrix which is not positive definite,

2) AI contains a symmetric matrix which is not positive definite, 3) AI0 contains an unstable matrix,

4) AI0 contains a symmetric unstable matrix, 5) AI contains a singular matrix,

6) AI contains a symmetric singular matrix,

7) AI1 contains a symmetric matrix which is not Schur stable, 8) λmin(A)∈/(0, m) for some symmetricA ∈AI.

We prove 0)⇒6)⇒2)⇒8)⇒2)⇒4)⇒7)⇒4)⇒3)⇒1)⇒5)⇒0). 0)⇒ 6): IfzTAz≥Lfor somez∈ {−1,1}n, then the matrixA =A−1−(zTAz)−1zzT is symmetric, belongs toAI and satisfies AAz= 0, hence it is singular. 6)⇒2) is obvious. 2)⇔8): For a symmetric A∈AI, since̺(A)< m, we have thatA is not positive definite if and only if λmin(A)∈/ (0, m). 2)⇒4): If a symmetric A∈AI is not positive definite, then λmax(−A) =−λmin(A)≥0, hence−A is unstable and−A∈AI0. 4)⇔7): For each symmetricA ∈AI0, since̺(A)< m, we have thatAis unstable if and only ifI+m1A ∈AI1is not Schur stable. 4)⇒3) is obvious. 3)⇒1): If ˜A∈AI0is unstable, then by Bendixson theorem 0≤Reλ≤ λmax(21( ˜A+ ˜AT)), hence forA =−12( ˜A+ ˜AT) we haveA ∈AIandλmin(A)≤0, so thatA is not positive definite. 1)⇒5): Let ˜A∈AI be not positive definite.

Put t0 = supn

t∈[0,1] ;A−1+t(12( ˜A+ ˜AT)−A−1) is positive definiteo . Then the matrixA =A−1+t0(12( ˜A+ ˜AT)−A−1) is symmetric, belongs to AI (due to its convexity) and is positive semidefinite, but not positive definite, hence λmin(A) = 0, so that A is singular. 5) ⇒0): Let Ax= 0 for some A ∈ AI, x 6= 0. Define z ∈ {−1,1}n by zj = 1 if xj ≥ 0 and zj =−1 otherwise (j = 1, . . . , n). Then eT|x|=zTx=zTA(A−1−A)x≤ |zTA|L1eeT|x|, which implies L ≤ |zTA|e = zTAz (since A is diagonally dominant). This proves that the

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Checking positive definiteness or stability of symmetric interval matrices is NP-hard 797 assertions 0) to 8) are equivalent. Now, in [3, Theorem 2.6] it is proved that the decision problem

Instance. An MC-matrixAand a positive integerL.

Question. IszTAz≥L for somez∈ {−1,1}n?

is NP-complete. In view of the above equivalences, this problem can be polyno- mially reduced to each of the problems (i)–(viii), hence all of them are NP-hard.

Comments. The result (v) was proved in [3, Theorem 2.8]; here it was included for completeness. Cf. also Nemirovskii’s results in [2]. Characterizations of posi- tive definiteness, stability and Schur stability of symmetric interval matrices are given in [4].

References

[1] Garey M.E., Johnson D.S.,Computers and Intractability: A Guide to the Theory of NP- Completeness, Freeman, San Francisco, 1979.

[2] Nemirovskii A., Several NP-hard problems arising in robust stability analysis, Math. of Control, Signals, and Systems6(1993), 99–105.

[3] Poljak S. and Rohn J.,Checking robust nonsingularity is NP-hard, Math. of Control, Sig- nals, and Systems6(1993), 1–9.

[4] Rohn J., Positive definiteness and stability of interval matrices, SIAM J. Matrix Anal.

Appl.15(1994), 175–184.

Faculty of Mathematics and Physics, Charles University, Malostransk´e n´am. 25, 118 00 Prague 1, Czech Republic

(Received March 23, 1994)

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