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http://jipam.vu.edu.au/

Volume 2, Issue 3, Article 27, 2001

GENERALIZED AUXILIARY PROBLEM PRINCIPLE AND SOLVABILITY OF A CLASS OF NONLINEAR VARIATIONAL INEQUALITIES INVOLVING

COCOERCIVE AND CO-LIPSCHITZIAN MAPPINGS

RAM U. VERMA UNIVERSITY OFTOLEDO, DEPARTMENT OFMATHEMATICS,

TOLEDO, OHIO43606, USA.

[email protected]

Received — ; accepted 15 March, 2001 Communicated by D. Bainov

ABSTRACT. The approximation-solvability of the following class of nonlinear variational in- equality (NVI) problems, based on a new generalized auxiliary problem principle, is discussed.

Find an elementxKsuch that

h(ST) (x), xxi+f(x)f(x)0 for allxK,

whereS, T :KH are mappings from a nonempty closed convex subsetKof a real Hilbert spaceH into H, and f : K Ris a continuous convex functional on K.The generalized auxiliary problem principle is described as follows: for given iteratexk Kand, for constants ρ >0andσ >0), findxk+1such that

ρ(ST) yk

+h0 xk+1

h0 yk

, xxk+1

+ρ(f(x)−f(xk+1))0 for all xK, where

σ(ST) xk

+h0 yk

h0 xk

, xyk

+σ(f(x)f(yk)) 0 for all x K, wherehis a functional onKandh0the derivative ofh.

Key words and phrases: Generalized auxiliary variational inequality problem, Cocoercive mappings, Approximation- solvability, Approximate solutions, Partially relaxed monotone mappings.

2000Mathematics Subject Classification. 49J40.

1. INTRODUCTION

Recently, Zhu and Marcotte [23], based on the auxiliary problem principle introduced by Co- hen [3], investigated the approximation-solvability of a class of variational inequalities involv- ing the cocoercive and partially cocoercive mappings in the Rnspace. The auxiliary problem technique introduced by Cohen [3], is quite similar to that of the iterative algorithm character- ized as the auxiliary variational inequality studied by Marcotte and Wu [12], but the estimates

ISSN (electronic): 1443-5756

c 2001 Victoria University. All rights reserved.

025-01

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for the approximate solutions seem to be significantly different, which makes a difference es- tablishing the convergence of the sequence of approximate solutions to a given solution of the original variational inequality under consideration. On the top of that, using the auxiliary prob- lem principle, one does not require any projection formula leading to a fixed point and eventu- ally the solution of the variational inequality, which has been the case following the variational inequality type algorithm adopted by Marcotte and Wu [12]. Recently Verma [21] introduced an iterative scheme characterized as an auxiliary variational inequality type of algorithm and ap- plied to the approximation-solvability of a class of nonlinear variational inequalities involving cocoercive as well as partially relaxed monotone mappings [18] in a Hilbert space setting. The partially relaxed monotone mappings seem to be weaker than cocoercive and strongly mono- tone mappings. In this paper, we first intend to introduce the generalized auxiliary problem principle, and then apply the generalized auxiliary problem principle, which includes the aux- iliary problem principle of Cohen [3] as a special case, to approximation-solvability of a class of nonlinear variational inequalities involving cocoercive mappings. The obtained results do complement the earlier works of Cohen [3], Zhu and Marcotte [23] and Verma [18] on the approximation- solvability of nonlinear variational inequalities in different space settings.

LetH be a real Hilbert space with the inner producth·,·iand normk·k. LetS,T : K →H be any mappings andK a closed convex subset of H. Letf : K →Rbe a continuous convex function. We consider a class of nonlinear variational inequality (abbreviated as NVI) problems:

find an elementx ∈K such that

(1.1) h(S−T) (x), x−xi+f(x)−f(x)≥0 for all x∈K.

Now we need to recall the following auxiliary result, most commonly used in the context of the approximation-solvability of the nonlinear variational inequality problems based on the iterative procedures.

Lemma 1.1. An elementu∈K is a solution of the NVI problem (1.1) if h(S−T)(u), x−ui+f(x)−f(u)≥0 for all x∈K.

A mappingS:H →H is said to beα-cocoercive [19] if for allx, y ∈H, we have kx−yk2 ≥α2kS(x)−S(y)k2+kα(S(x)−S(y))−(x−y)k2, whereα >0is a constant.

A mappingS :H →His calledα-cocoercive [12] if there exists a constantα >0such that hS(x)−S(y), x−yi ≥αkS(x)−S(y)k2 for all x, y ∈H.

Sis calledr-strongly monotone if for eachx, y ∈H, we have

hS(x)−S(y), x−yi ≥rkx−yk2 for a constant r >0.

This implies that

kS(x)−S(y)k ≥rkx−yk,

that is,Sisr-expanding, and whenr= 1, it is expanding. The mappingSis calledβ−Lipschitz continuous (orβ−Lipschitzian) if there exists a constantβ ≥0such that

kS(x)−S(y)k ≤βkx−yk for all x, y ∈H.

We note that ifS isα-cocoercive and expanding, thenS isα-strongly monotone. On the top of that, if S is α-strongly monotone and β−Lipschitz continuous, then S is

α β2

cocoercive forβ >0. Clearly everyα-cocoercive mappingSis α1

−Lipschitz continuous.

Proposition 1.2. [21]. LetS :H →H be a mapping from a Hilbert spaceHinto itself. Then the following statements are equivalent:

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(i) For eachx, y ∈Hand for a constantα >0, we have

kx−yk2 ≥α2kS(x)−S(y)k2+kα(S(x)−S(y))−(x−y)k2. (ii) For eachx, y ∈H, we have

hS(x)−S(y), x−yi ≥αkS(x)−S(y)k2, whereα >0is a constant.

Lemma 1.3. For all elementsv, w∈H, we have kvk2+hv, wi ≥ −1

4kwk2.

A mappingS :H →His said to beγ−partially relaxed monotone[18] if for allx, y, z ∈H, we have

hS(x)−S(y), z−yi ≥ −γkz−xk2 for γ >0.

Proposition 1.4. [18]. LetS :H → H be anα-cocoercive mapping onH. ThenS is 1

− partially relaxed monotone.

Proof. We include the proof for the sake of the completeness. SinceSisα-cocoercive, it implies by Lemma 1.1, for allx, y, z ∈H, that

hS(x)−S(y), z−yi = hS(x)−S(y), x−yi+hS(x)−S(y), z−xi

≥ αkS(x)−S(y)k2+hS(x)−S(y), z−xi

= α

kS(x)−S(y)k2+ 1

α

hS(x)−S(y), z−xi

≥ − 1

kz−xk2, that is,S is 1

−partially relaxed monotone.

A mappingT :H →His said to beµ-co-Lipschitz continuous if for eachx, y ∈H and for a constantµ >0, we have

kx−yk ≤µkT(x)−T(y)k. This clearly implies that

hT(x)−T(y), x−yi ≤µkT(x)−T(y)k2. Clearly, everyµ-co-Lipschitz continuous mappingT is

1 µ

−expanding.

2. GENERALIZEDAUXILIARY PROBLEM PRINCIPLE

This section deals with the approximation-solvability of the NVI problem (1.1), based on the generalized auxiliary nonlinear variational inequality problem principle by Verma [18], which includes the auxiliary problem principle introduced by Cohen [3] and later applied and studied by others, including Zhu and Marcotte [22]. This generalized auxiliary nonlinear variational inequality (GANVI) problem is as follows: for a given iteratexk, determine an xk+1 such that (fork ≥0):

(2.1)

ρ(S−T) yk

+h0 xk+1

−h0 yk

, x−xk+1

+ρ f(x)−f xk+1

≥0 for all x∈K,

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where (2.2)

σ(S−T) xk

+h0 yk

−h0 xk

, x−yk

+σ f(x)−f yk

≥0 for all x∈K, and for a strongly convex functionhonK(whereh0 denotes the derivative ofh).

Whenσ =ρin the GANVI problem (2.1)-(2.2), we have GANVI problem as follows: for a given iteratexk, determine anxk+1 such that (fork≥0):

(2.3)

ρ(S−T) yk

+h0 xk+1

−h0 yk

, x−xk+1

+ρ f(x)−f xk+1

≥0 for all x∈K, where

(2.4)

ρ(S−T) xk

+h0 yk

−h0 xk

, x−yk

+ρ f(x)−f yk

≥0 for all x∈K.

Forσ = 0 andyk = xk, the GANVI problem (2.1)-(2.2) reduces to: for a given iterate xk , determine anxk+1such that (fork ≥0):

(2.5)

ρ(S−T) xk

+h0 xk+1

−h0 xk

, x−xk+1

+ρ f(x)−f xk+1

≥0 for all x∈K.

Next, we recall some auxiliary results crucial to the approximation-solvability of the NVI problem (1.1).

Lemma 2.1. [23]. Leth :K → Rbe continuously differentiable on a convex subsetK ofH.

Then we have the following conclusions:

(i) Ifhisb-strongly convex, then

h(x)−h(y)≥ hh0(y), x−yi+ b

2

kx−yk2 for all x, y ∈K.

(ii) If the gradienth0 isp−Lipschitz continuous, then

h(x)−h(y)≤ hh0(y), x−yi+ b

2

kx−yk2 for all x, y ∈K.

We are just about ready to present, based on the GANVI problem (2.1) – (2.2), the approximation- solvability of the NVI problem (1.1) involvingγ−cocoercive mappings in a Hilbert space set- ting.

Theorem 2.2. LetH be a real Hilbert space andS : K → H aγ−cocoercive mapping from a nonempty closed convex subset K of H into H. Let T : K → H be a µ-co-Lipschitz continuous mapping. Suppose that h : K → R is continuously differentiable and b-strongly convex, andh0, the derivative of h, isp−Lipschitz continuous. Thenxk+1 is a unique solution of (2.1) – (2.2). If in addition, ifx ∈Kis any fixed solution of the NVI problem (1.1), thenxk is bounded and converges tox for0< ρ < 2bγ,ρ+σ < band

xk+1−xk, xk−yk

≥0.

Proof. Before we can show that the sequences

xk converges to x, a solution of the NVI problem (1.1), we need to compute the estimates. Sincehisb−strongly convex, it ensures the

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uniqueness of solutionxk+1 of the GANVI problem (2.1) – (2.2). Let us define a function Λ by

Λ(x) := h(x)−h(x)− hh0(x), x −xi

≥ b

2

kx−xk2 for x∈K,

wherex is any fixed solution of the NVI problem (1.1). It follows foryk ∈K that Λ yk

= h(x)−h yk

h0 yk

, x−yk

= h(x)−h yk

h0 yk

, x−xk+1+xk+1−yk . Similarly, we can have

Λ xk+1

=h(x)−h xk+1

h0 xk+1

, x−xk+1 . Now we can write

Λ yk

−Λ xk+1 (2.6)

=h xk+1

−h yk

h0 yk

, xk+1−yk +

h0 xk+1

−h0 yk

, x−xk+1

≥ b

2

xk+1−yk

2+

h0 xk+1

−h0 yk

, x−xk+1

≥ b

2

xk+1−yk

2

(S−T) yk

, xk+1−x

+ρ f xk+1

−f(x) , forx=x in (2.1).

If we replacexbyxk+1in (1.1) and combine with (2.6), we obtain Λ yk

−Λ xk+1

≥ b

2

xk+1−yk

2

(S−T) yk

, xk+1−x

−ρ

(S−T) (x), xk+1−x

= b

2

xk+1−yk

2

(S−T) yk

−(S−T) (x), xk+1−x

= b

2

xk+1−yk

2

(S−T) yk

−(S−T) (x), xk+1−yk+yk−x

= b

2

xk+1−yk

2

(S−T) yk

−(S−T) (x), yk−x

(S−T) yk

−(S−T) (x), xk+1−yk .

SinceS isγ−cocoercive andT isµ-co-Lipschitz continuous, it implies that Λ yk

−Λ xk+1 (2.7)

≥ b

2

xk+1−yk

2+ργ

(S−T) yk

−(S−T) (x)

2

(S−T) yk

−(S−T) (x), xk+1−yk

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= b

2

xk+1−yk

2+ργ

(S−T) yk

−(S−T) (x) 2

+ 1

γ

(S−T) yk

−(S−T) (x), xk+1−yk

≥ b

2

xk+1−yk

2

ρ 4(γ−µ)

xk+1−yk

2 (by Lemma 1.3)

= 1 2

b−

ρ 2(γ−µ)

xk+1−yk

2 for γ−µ >0.

Similarly, we can have Λ xk

−Λ yk (2.8)

=h yk

−h xk

h0 xk

, yk−xk +

h0 yk

−h0 xk

, x−yk

≥ b

2

yk−xk

2+

h0 yk

−h0 xk

, x−yk

≥ b

2

yk−xk

2+σ T xk

, yk−x

+σ f yk

−f(x) , forx=x in (2.2).

Again, if we replacexbyykin (1.1) and combine with (2.8), we obtain Λ xk

−Λ yk (2.9)

≥ b

2

yk−xk

2

(S−T) xk

, yk−x

−σ

(S−T) (x), yk−x

= b

2

yk−xk

2

(S−T) xk

−(S−T) (x), yk−x+xk−xk

= b

2

yk−xk

2

(S−T) xk

−(S−T) (x), xk−x

(S−T) xk

−(S−T) (x), yk−xk

≥ b

2

yk−xk

2

σ 4(γ−µ)

yk−xk

2

= 1

2 b−

σ 2(γ−µ)

yk−xk

2. Finally, we move toward finding the required estimate

Λ xk

−Λ xk+1 (2.10)

= Λ xk

−Λ yk

+ Λ yk

−Λ xk+1

≥ 1

2 b−

σ 2(γ−µ)

yk−xk

2+ 1

2 b−

ρ 2(γ−µ)

xk+1−yk

2

= 1

2 b−

σ 2(γ−µ)

yk−xk

2+ 1

2 b−

ρ 2(γ−µ)

×

xk+1−xk 2+

xk−yk

2+ 2

xk+1−xk, xk−yk

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= 1

2 b−

ρ 2(γ−µ)

xk+1−xk 2+

b−

σ+ρ 4(γ−µ)

yk−xk

2

+

b−

ρ 2(γ−µ)

xk+1−xk, xk−yk

≥ 1

2 b−

ρ 2(γ−µ)

xk+1−xk

2 forb− ρ

2(γ−µ) >0, b− 4(γ−µ)σ+ρ >0and

xk+1−xk, xk−yk

≥0.

It follows from (2.10) that forxk+1 =yk =xkthatxkis a solution of the variational inequal- ity. If not, the conditionsb− 2(γ−µ)ρ >0,b− 4(γ−µ)σ+ρ >0and

xk+1−xk, xk−yk

≥0ensure that the sequence

Λ(xk)−Λ(xk+1) is nonnegative and, as a result, we have

k→∞lim

xk+1−xk = 0.

On the top of that,

x−xk

22b

Λ xk

and the sequence

Λ xk is decreasing , that means

xk is a bounded sequence. Assume that x0 is a cluster point of

xk . Then as k → ∞ in (2.1) – (2.2), x0 is a solution of the variational inequality because there is no loss generality ifxis replaced byx0. If we associatex0toΛ0and defineΛ0 by

Λ0 xk

= h(x0)−h xk

h0 xk

, x0−xk

≤ p 2

x0−xk

2 (by Lemma 2.1), then we have

Λ0 xk

≤p 2

x0−xk

2. Since the sequence

Λ0 xk is strictly decreasing, it follows thatΛ0 xk

→ 0. On the other hand, we already have

Λ0 xk

≥ b

2

x0 −xk

2. Thus, we can conclude that the entire sequence

xk converges tox0, and this completes the proof. Forσ =ρin Theorem 2.2, we find:

Theorem 2.3. LetH be a real Hilbert space andT :K → Haγ−cocoercive mapping from a nonempty closed convex subsetK ofH intoH. Leth:K →Rbe continuously differentiable andb−strongly convex, andh0, the derivative ofh, isp−Lipschitz continuous. Thenxk+1 is a unique solution of (2.3) – (2.4).

If in addition,x ∈K is any fixed solution of the NVI problem (1.1), then

xk is bounded and converges toxfor0< ρ < 2bγ and

xk+1−xk, xk−yk

≥0.

Whenσ = 0andyk=xk, Theorem 2. reduces to:

Theorem 2.4. [23]. LetH be a real Hilbert space and T : K → H aγ−cocoercive mapping from a nonempty closed convex subset K of H into H. Let h : K → R be continuously differentiable and b−strongly convex, and h0, the derivative of h, is p−Lipschitz continuous.

Thenxk+1 is a unique solution of (2.5).

If in addition,x ∈K is any fixed solution of the NVI problem (1.1), then

xk is bounded and converges toxfor0< ρ < 2bγ.

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