Volume 2010, Article ID 345701,12pages doi:10.1155/2010/345701
Research Article
Some Nonlinear Weakly Singular Integral
Inequalities with Two Variables and Applications
Hong Wang and Kelong Zheng
School of Science, Southwest University of Science and Technology, Mianyang, Sichuan 621010, China
Correspondence should be addressed to Kelong Zheng,[email protected] Received 23 October 2010; Accepted 22 December 2010
Academic Editor: Radu Precup
Copyrightq2010 H. Wang and K. Zheng. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
Some nonlinear weakly singular integral inequalities in two variables which generalize some known results are discussed. The results can be used as powerful tools in the analysis of certain classes of differential equations, integral equations, and evolution equations. An example is presented to show boundedness of solution of a differential equation here.
1. Introduction
Various singular integral inequalities play an important role in the development of the theory of differential equations, functional differential equations, and integral equations. For example, Henry1proposed a linear integral inequality with singular kernel to investigate some qualitative properties for a parabolic differential equation, and Sano and Kunimatsu 2gave a modified version of Henry type inequality. However, such results are expressed by a complicated power series which are sometimes inconvenient for their applications. To avoid the shortcoming of these results, Medve ˇd3presented a new method to discuss nonlinear singular integral inequalities of Henry type and their Bihari version as follows:
ut≤at t
0
t−sβ−1sγ−1Fsusds, ut≤at
t
0
t−sβ−1Fswusds,
1.1
and the estimates of solutions are given, respectively. In 4, Medve ˇd also generalized his results to an analogue of the Wendroffinequalities for functions in two variables. From then
on, more attention has been paid to such inequalities with singular kernel see5–9. In particular, Ma and Yang 8 used a modification of Medve ˇd method to obtain pointwise explicit bounds on solutions of more general weakly singular integral inequalities of the Volterra type, and later Ma and Peˇcari´c9used this method to study nonlinear inequalities of Henry type. Recently, Cheung et al. 10 applied the modified Medve ˇd method to investigate some new weakly singular integral inequalities of Wendrofftype and applications to fractional differential and integral equations.
In this paper, motivated mainly by the work of Ma et al.8,9and Cheung et al.10, we discuss more general form of nonlinear weakly singular integral inequality of Wendroff type for functions in two variables
u x, y
≤a x, y
x
0
y
0
xα−sαβ−1sγ−1
yα−tαβ−1 tγ−1f
x, y, s, t
wus, tds dt. 1.2
Our results can generalize some known results and be used more effectively to study the qualitative properties of the solutions of certain partial differential and integral equations.
Moreover, an example is presented to show the usefulness of our results.
2. Main Result
In what follows,R denotes the set of real numbers, andR 0,∞.CX, Y denotes the collection of continuous functions from the setXto the setY.D1zx, yandD2zx, ydenote the first-order partial derivatives ofzx, ywith respect toxandy, respectively.
Before giving our result, we cite the following definition and lemmas.
Definition 2.1 see 8. Let x, y, z be an ordered parameter group of nonnegative real numbers. The group is said to belong to the first-class distribution and is denoted by x, y, z ∈ I if conditionsx ∈ 0,1,y ∈ 1/2,1, andz ≥ 3/2−yare satisfied; it is said to belong to the second-class distribution and is denoted byx, y, z∈IIif conditionsx∈0,1, y∈0,1/2andz >1−2y2/1−y2are satisfied.
Lemma 2.2see8. Letα, β, γ, andpbe positive constants. Then, t
0
tα−sαpβ−1spγ−1ds tθ αB
p γ−1
1
α , p
β−1 1
, t∈R, 2.1
where Bξ, η 1
0sξ−11 − sη−1ds (Reξ > 0,Reη > 0) is well-known B-function and θpαβ−1 γ−1 1.
Lemma 2.3see8. Suppose that the positive constantsα, β, γ,p1, andp2 satisfy the following conditions:
1ifα, β, γ∈I,p11/β;
2ifα, β, γ∈II,p2 14β/13β.
Then, fori1,2,
B pi
γ−1 1 α , pi
β−1 1
∈0,∞, θipi
α β−1
γ−1 1≥0
2.2
are valid.
Assume that
A1ax, y∈CR2, Randfx, y, s, t∈CR4, R; A2wu∈CR, Ris nondecreasing andw0 0.
Letax, y max0≤τ≤x,0≤η≤yaτ, ηandfx, y, s, t max0≤τ≤x,0≤η≤y fτ, η, s, t.
Theorem 2.4. Under assumptions (A1) and (A2), ifum, n∈CR2, Rsatisfies1.2, then (1) forα, β, γ∈I,
u x, y
≤
W1−1
W1 A1
x, y B1
x, y
x 0
y
0
f
x, y, s, t1/1−β ds dt
1−β
2.3
for 0≤x≤Xand 0≤y≤Y, where
M1 1 αB
βγ−1 αβ ,2β−1
β
, A1
x, y
2β/1−βa
x, y1/1−β , B1
x, y
2β/1−β M21
xy1/βαβ−1γ−11β/1−β
,
2.4
W1−1is the inverse ofW1,
W1 u
u0
dξ w1/1−β
ξ1−β, u≥u0>0, 2.5
andX, Y ∈Rare chosen such that
W1 A1
x, y B1
x, y
x 0
y
0
f
x, y, s, t1/1−β
ds dt∈Dom W1−1
, 2.6
(2) forα, β, γ∈II,
u x, y
≤
W2−1
W2
A2
x, y B2
x, y
x 0
y
0
f
x, y, s, t14β/β ds dt
β/14β
2.7
for 0≤x≤Xand 0≤y≤Y, where
M2 1 αB
γ 14β
−β α
13β , 4β2 13β
,
A2 x, y
213β/βa
x, y14β/β , B2
x, y
213β/β
M22
xy14β/13βαβ−1γ−1113β/β
,
2.8
W2−1is the inverse ofW2,
W2 u
u0
dξ w14β/β
ξβ/14β, u≥u0>0, 2.9
andX, Y ∈Rare chosen such that
W2 A2
x, y B2
x, y
x 0
y
0
f
x, y, s, t14β/β
ds dt∈Dom W2−1
. 2.10
Proof. With the definition of ax, y and fx, y, s, t, clearly, ax, y and fx, y, s, t are nonnegative and nondecreasing inxandy. Furthermore,ax, y ≥ax, yandfx, y, s, t ≥ fx, y, s, t. From1.2, we have
u x, y
≤a x, y
x
0
y
0
xα−sαβ−1sγ−1
yα−tαβ−1 tγ−1f
x, y, s, t
wus, tds dt. 2.11
Next, for convenience, we introduce indicespi,qi. Denote that ifα, β, γ∈I, then letp11/β and q1 1/1−β; ifα, β, γ ∈ II, then let p2 14β/13βand q2 14β/β.
Then 1/pi1/qi1 holds fori1,2.
Using the H ¨older inequality with indicespi,qito2.11, we get
u x, y
≤a x, y
x 0
y
0
xα−sαpiβ−1spiγ−1
yα−tαpiβ−1
tpiγ−1ds dt 1/pi
× x
0
y
0
f
x, y, s, tqi
wus, tqids dt 1/qi
.
2.12
By
A1A2· · ·Anr ≤nr−1
Ar1Ar2· · ·Arn
, Ai≥0, r≥1, 2.13
from2.12and Lemma2.2, we have uqi
x, y
≤2qi−1
a
x, yqi x
0
y
0
xα−sαpiβ−1spiγ−1
yα−tαpiβ−1tpiγ−1ds dt qi/pi
× x
0
y
0
f
x, y, s, tqi
wus, tqids dt
2qi−1a x, yqi
2qi−1 Mi2
xyθiqi/pix
0
y
0
f
x, y, s, tqi
wus, tqids dt
,
2.14
where
Mi 1 αB
pi γ−1
1 α , pi
β−1 1
2.15
andθiis given in Lemma2.3fori1,2.
Sinceqi≥0 andθi≥0i1,2, thenax, y qi andxyθiqi/pi are also nondecreasing inxandy. Taking any arbitraryxandywithx≤X,y≤Y, we obtain
uqi x, y
≤2qi−1a x,yqi
2qi−1 M2i
xyθiqi/pix 0
y
0
f
x,y, s, t qi
wus, tqids dt 2.16
for 0≤x≤x, 0 ≤y≤y. Denote Ai
x,y
2qi−1a
x,yqi, 2.17
and let
zi x, y
Ai x,y
2qi−1 M2i
xyθiqi/pix
0
y
0
f
x,y, s, t qi
wus, tqids dt
. 2.18
Then,uqix, y≤zix, yorux, y≤z1/qi ix, y. Meanwhile,zi0, y Aix, y, and zix, y is nondecreasing inxandy. Considering
D1zi x, y
2qi−1 M2i
xyθiqi/piy
0
f
x,y, x, t qi
wux, tqids dt
≤2qi−1
M2i
xyθiqi/piy
0
f
x,y, x, t qi
wzix, t1/qiqi dt
,
2.19
we have
D1zi x, y wqi
z1/qi i
x, y ≤2qi−1 Mi2
xyθiqi/piy 0
f
x,y, x, t qi dt
, 2.20
where we apply the fact thatwqiz1/qi ix, yis nondecreasing iny. Integrating both sides of the above inequality from 0 tox, we obtain
Wi
zi
x, y
≤Wi
zi
0, y
2qi−1 M2i
xyθiqi/pix
0
y
0
f
x,y, s, t qi ds dt
Wi
Ai
x, y
2qi−1 M2i
xyθiqi/pix
0
y
0
f
x,y, s, t qi ds dt
2.21
for 0≤x≤x, 0 ≤y≤y, where
Wiu u
u0
dξ wqi
ξ1/qi, u≥u0>0. 2.22
From assumptionA2,Wiis strictly increasing so its inverseWi−1is continuous and increas- ing in its corresponding domain. Replacingxandybyxandy, we have
Wi
zi
x, y
≤Wi
Ai
x, y 2qi−1
M2i
xyθiqi/pix
0
y
0
f
x,y, s, t qi ds dt
.
2.23
Sincexandyare arbitrary, we replacexandybyxandy, respectively, and get
Wi zi
x, y
≤Wi Ai
x, y
2qi−1 M2i
xyθiqi/pix
0
y
0
f
x, y, s, tqi ds dt
. 2.24
for 0≤x≤Xand 0≤y≤Y. The above inequality can be rewritten as
zi x, y
≤Wi−1
Wi Ai
x, y
2qi−1 M2i
xyθiqi/pix
0
y
0
f
x, y, s, tqi ds dt
. 2.25
Therefore, we have u
x, y
≤z1/qi i x, y
≤
Wi−1
Wi
Ai
x, y 2qi−1
Mi2
xyθiqi/pix
0
y
0
f
x, y, s, tqi ds dt
1/qi
2.26
for 0≤x≤Xand 0≤y≤Y.
Finally, considering two situations fori1,2 and using parametersα,β, γto denote pi,qi,Mi, andθiin the above inequality, we can obtain the estimations, respectively. we omit the details here.
Remark 2.5. Medve ˇd4, Theorem 2.2investigated the special caseαγ1,fx, y, s, t Fs, t of inequality1.2under the assumption that “wusatisfies the conditionq.” However, in our result, theqcondition is eliminated. If we takeα1 andwu u, then we can obtain the result of linear case4, Theorem 2.4.
Remark 2.6. Letupx, y vx, y, thenux, y v1/px, yoruqx, y vq/px, y. Therefore, if we takewv vq/p, the formula2.6in10is the special case of inequality1.2, and we can obtain more concise results than2.7and2.9in10. Moreover, here the conditionp ≥qalso can be eliminated.
Remark 2.7. Whenα, β, γdoes not belong toIorII, there are some technical problems which we do not discuss here.
3. Some Corollaries
Corollary 3.1. Let functionsux, y,ax, y,fx, y, s, tbe defined as in Theorem2.4, and letkbe a constant with 0< k≤1. Suppose that
u x, y
≤a x, y
x
0
y
0
xα−sαβ−1sγ−1
yα−tαβ−1 tγ−1f
x, y, s, t
us, tkds dt. 3.1
Then,
(1) forα, β, γ∈I, ifk1,
u x, y
≤2βa x, y
exp 1−β
B1 x, y
x 0
y
0
f
x, y, s, t1/1−β ds dt
, 3.2
if 0< k <1,
u x, y
≤
2βa
x, y1−k/1−β
1−kB1
x, y
x 0
y
0
f
x, y, s, t1/1−β ds dt
1−β/1−k
3.3
forx≥0,y≥0, whereax, y, fx, y, s, t, B1x, yare defined as in Theorem2.4, (2) forα, β, γ∈II,
ifk1,
u x, y
≤213β/14βa x, y
exp β
14βB2 x, y
x 0
y
0
f
x, y, s, t14β/β
ds dt
, 3.4
if 0< k <1, u
x, y
≤ 213βa
x, y14β1−k/β
1−kB2
x, y
x 0
y
0
f
x, y, s, t14β/β ds dt
β/14β1−k
, 3.5
forx≥0,y≥0, whereax, y, fx, y, s, t, B2x, yare defined as in Theorem2.4.
Proof. Clearly, inequality3.1is the special case of1.2. Takingwu uk, we can get3.1.
iIfk1,
Wiu u
u0
dξ ξ ln u
u0
, u≥u0>0,
Wi−1u u0eu, Dom Wi−1
0,∞, i1,2.
3.6
iiIf 0< k <1,
Wiu u
u0
dξ ξk 1
1−k
u1−k−u1−k0 ,
Wi−1u
u1−k0 1−ku1/1−k
, Dom Wi−1
0,∞, i1,2.
3.7
Therefore, the positive numbersXandY in2.6and2.10can be taken as∞, and the results can be obtained by simple computation. We omit the details.
Corollary 3.2. Let functionsux, y,ax, y,fx, y, s, tbe defined as in Theorem2.4. Suppose that gx, y, s, t∈CR4, Randux, ysatisfies
u x, y
≤a x, y
x
0
y
0
xσ−sσμ−1sτ−1
yσ−tσμ−1 tτ−1g
x, y, s, t
us, tds dt
x
0
y
0
xα−sαβ−1sγ−1
yα−tαβ−1 tγ−1f
x, y, s, t
wus, tds dt.
3.8
Then,
iifα, β, γ,σ, μ, τ∈I,
u x, y
≤ W1−1
W1
A1
x, y Ω1
x, y1/1−β
Ω1
x, y1/1−β B1
x, y
x 0
y
0
f
x, y, s, t1/1−β ds dt
1−β 3.9
for 0≤x≤X1and 0≤y≤Y1, where
Ω1
x, y
2μexp 1−μ
B1 x, y
x 0
y
0
g
x, y, s, t1/1−μ ds dt
, 3.10
W1,W1−1,A1x, y,B1x, yare defined as in Theorem2.4, andX1, Y1 ∈Rare chosen such that
W1
A1
x, y Ω1
x, y1/1−β Ω1
x, y1/1−β B1
x, y
x 0
y
0
f
x, y, s, t1/1−β
ds dt∈Dom W1−1
,
3.11
iiifα, β, γ,σ, μ, τ∈II,
u x, y
≤
W2−1
W2
A2
x, y Ω2
x, y14β/β
Ω2
x, y14β/β B2
x, y
x 0
y
0
f
x, y, s, t14β/β ds dt
β/14β 3.12
for 0≤x≤X2and 0≤y≤Y2, where
Ω2
x, y
213μ/14μexp
μ 14μB2
x, y
x 0
y
0
g
x, y, s, t14μ/μ ds dt
, 3.13
W2,W2−1,A2x, y,B2x, yare defined as in Theorem2.4, andX2, Y2 ∈Rare chosen such that
W2
A2
x, y Ω2
x, y14β/β Ω2
x, y14β/β B2
x, y
x 0
y
0
f
x, y, s, t14β/β ds dt
∈Dom W2−1
.
3.14
Proof. By the two mentioned lemmas, it follows from3.8that
u x, y
≤Pi x, y
x
0
y
0
xσ−sσμ−1sτ−1
yσ−tσμ−1 tτ−1g
x, y, s, t
us, tds dt, 3.15
wheregx, y, s, t max0≤τ≤x,0≤η≤ygτ, η, s, tand
Pi
x, y a
x, y
M2i
xyθi1/pix
0
y
0
fqi
x, y, s, t
wus, tqids dt 1/qi
. 3.16
iForα, β, γ,σ, μ, τ∈I,
applying Corollary3.1to3.15, we have
u x, y
≤2μP1
x, y exp
1−μ B1
x, y
x 0
y
0
g
x, y, s, t1/1−μ ds dt
. 3.17
Letting
Ω1
x, y
2μexp 1−μ
B1
x, y
x 0
y
0
g
x, y, s, t1/1−μ ds dt
, 3.18
we get
u x, y
≤P1
x, y Ω1
x, y a
x, y Ω1
x, y Ω1
x, y M21
xyθ11/p1x 0
y
0
fq1
x, y, s, t
wus, tq1ds dt 1/q1
.
3.19
Since inequality3.19is similar to2.12, we can repeat the procedure of proof in Theorem2.4 and get3.9.
iiAs for the case thatα, β, γ,σ, μ, τ∈II, the proof is similar to the argument in the proof of caseiwith suitable modification. We omit the details.
Remark 3.3. Whenα, β, γ∈I,σ, μ, τ∈IIorα, β, γ∈II,σ, μ, τ∈I, we can get the results which are similar to that in Corollary3.2and omit them here.
4. Application
In this section, we will apply our result to discuss the boundedness of certain partial integral equation with weakly singular kernel.
Suppose thatux, y∈CR2, Rsatisfies the inequality as follow:
u x, y
≤ 1 2
x
0
y
0
x−s−1/3s−1/6
y−t−1/3
t−1/6e−s−2t
us, tds dt 4.1
forx≥0,y≥0. Then,4.1is the special case of inequality1.2that is,
a x, y
1
2, α1, β 2
3, γ 5 6, f
x, y, s, t
e−s−2t, wu
us, t.
4.2
Obviously,α, β, γ 1,2/3,5/6∈I. Lettingp13/2,q1 3, we have
a
x, y 1
2, f
x, y, s, t
e−s−2t, A1
x, y 22
1 2
3 1
2, M1B 3
4,1 2
,
B1 x, y
22
B 3
4,1 2
2
xy1/42
4
B 3
4,1 2
4 xy,
W1u u
u0
dξ
ξ 2√ u−√
u0
,
W1−1u √ u0u
2 2
, Dom W1−1
0,∞.
4.3
Applying2.3in Theorem2.4, we get forx≥0,y≥0
u x, y
≤
W1−1
W1
A1
x, y B1
x, y
x 0
y
0
e−s−2t3
ds dt 1/3
W1−1
W1 1
2
4
B 3
4,1 2
4 xy
x
0
y
0
e−3e−6tds dt 1/3
W1−1 √
2−2√ u02
9
B 3
4,1 2
4 xy
1−e−3x
1−e−6y1/3
√
2 2 1
9
B 3
4,1 2
4 xy
1−e−3x
1−e−6y2/3
4.4
which implies thatux, yin4.1is bounded.
Acknowledgments
This work is supported by Scientific Research Fund of Sichuan Provincial Education Depart- mentno. 09ZC109. The authors are very grateful to the referees for their helpful comments and valuable suggestions.
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