Existence Of Solutions To Nonlinear th-Order Coupled Klein-Gordon Equations With Nonlinear
Sources And Memory Terms
Khaled Zennir
y, Amar Guesmia
zReceived 5 December 2014
Abstract
In this article, we consider a system of th-order derivatives of the dependent variables of coupled Klein-Gordon equations to improve recent results obtained in [10, 31, 33] using idea in [25]. Using the potential well method, we prove that the solutions of (1) exist globally, under some conditions on the initial datum.
1 Introduction
In this paper, we consider a system of th-order derivatives of the dependent variables of coupled Klein-Gordon equations
8>
>>
>>
><
>>
>>
>>
:
u001+ ( 1) u1+m21u1+ 1(t)Rt
0g1(t s) u1(x; s)ds+ju01jr 2u01
=ju1jp 2u1ju2jp;
u002+ ( 1) u2+m22u2+ 2(t)Rt
0g2(t s) u2(x; s)ds+ju02jr 2u02
=ju2jp 2u2ju1jp
(1)
where mi; i = 1;2 are non-negative constants, r; p 2; 1. In a bounded domain Rn Yaojun Ye [33] introduced related problem to (1) with = 1; i = 0; i = 1;2, supplemented with the initial and Dirichlet boundary conditions. By using the potential well method, global existence is discussed and asymptotic stability is also given, by using multiplied method.
Erhan Piskin and Necat Polat [10] considered a system of class of nonlinear higher- order wave equations (1) withmi=gi= 0; i= 1;2and strong nonlinearity in sources.
Under suitable conditions on the initial datum, theorems of global existence and decay rate are proved.
In (1),ui =ui(t; x); i= 1;2;wherex2 is a bounded domain ofRn;(n 1)with a smooth boundary @ , t >0. Our system is supplemented with the following initial conditions
ui(x;0) =ui0(x)2H0( ); i= 1;2; (2)
Mathematics Sub ject Classi…cations: 35L05, 35B40, 35G31, 58J45.
yLaboratory LAMAHIS,University 20 Août 1955- Skikda 21000, Algeria
zLaboratory LAMAHIS,University 20 Août 1955- Skikda 21000, Algeria
121
u0i(x;0)) =ui1(x)2L2( ); i= 1;2; (3) and boundary conditions
ui(x) = @ui
@ = = @ 1ui
@ 1 = 0forx2@ andi= 1;2; (4) where is the outward normal to the boundary.
We mention here that
jr uj2= ( =2u)2for pair value of and
jr uj2=jr( ( 1)=2u)j2for odd where
jruj2= Xn i=1
@u
@xi 2
and u= Xn i=1
@2u
@x2i:
This kind of systems (gi6= 0; i= 1;2) appears in the models of nonlinear viscoelasticity.
Viscoelastic materials have properties between two types, elastic materials and viscous
‡uids. This two types of materials are usually considered in basic texts on continuum mechanics. At each material point of an elastic material the stress at the present time depends only on the present value of the strain. On the other hand, for an incompressible viscous ‡uid the stress at a given point is a function of the present value of the velocity gradient at that point. Such materials have memory: the stress depends not only on the present values of the strain and/or velocity gradient, but also on the entire temporal history of motion.
The systems of nonlinear wave equations go back to Reed [27] who proposed a system in three space dimensions, where this type of system was completely analyzed.
Existence and uniqueness of global weak solutions, asymptotic behavior for an anal- ogous hyperbolic-parabolic system of related problems have attracted a great deal of attention in the last decades, and many results have appeared. See in this directions [5, 6, 7, 8, 12, 17, 22, 21, 24] and references therein.
We mention the work of [2], where authors studied the following system:
( utt u+jutjm 1ut=f1(u; v);
vtt v+jvtjr 1vt=f2(u; v);
(5) in (0; T) with initial and boundary conditions and the nonlinear functions f1
and f2 satisfying appropriate conditions. They proved under some restrictions on the parameters and the initial data many results on the existence of a weak solution. They also showed that any weak solution with negative initial energy blows up in …nite time using the same techniques as in [11].
In [20], authors considered the nonlinear viscoelastic system 8>
><
>>
:
utt u+ Rt 0
g(t s) u(x; s)ds+jutjm 1ut=f1(u; v);
vtt v+ Rt 0
h(t s) v(x; s)ds+jvtjr 1vt=f2(u; v);
(6)
forx2 andt >0 where
f1(u; v) =aju+vj2( +1)(u+v) +bjuj ujvj( +2); f2(u; v) =aju+vj2( +1)(u+v) +bjuj( +2)jvj v;
and they prove a global nonexistence theorem for certain solutions with positive initial energy, the main tool of the proof is a method used in [28].
The non-critical case of (1) where gi = 0; m = 2; i = 1;2, has been studied re- cently in [26]. M. A. Rammaha and Sawanya Sakuntasathien focus on the global well-posedness of the system of nonlinear wave equations
8<
:
utt u+ djujk+ejvjl jutjm 1ut=f1(u; v);
vtt v+ d0jvj +e0juj jvtjr 1vt=f2(u; v);
(7)
in a bounded domain Rn, n= 1;2;3;and 0< r; m <1, with Dirichlet boundary conditions. The nonlinearitiesf1(u; v)andf2(u; v)act as strong sources in the system.
Under some restriction on the parameters in the system, they obtained several results on the existence and uniqueness of solutions. In addition, they proved that weak solutions blow up in …nite time whenever the initial energy is negative and the exponent of the source term is more dominant than the exponents of both damping terms. This last result was extended by A. Benaissa et al. in [3] with positive initial energy, r; m >1 and forn >0.
The gender of our systems (mi6= 0; i= 1;2) has been proposed …rst by Segal [30]
in the next coupled Klein-Gordon equations which is considered in the study of the quantum …eld theory and de…nes the motion of a charged meson in an electromagnetic
…eld (
u001 u1+m21u1+h1u1u22= 0;
u002 u2+m22u2+h2u21u2= 0;
(8) where m1; m2; h1 andh2 are non-negative constants.
Whengi= 0; i= 1;2;Yaojun Ye generalized the problem (8), where author studied coupled nonlinear Klein-Gordon equations with nonlinear damping and source terms, in a bounded domain with the initial and Dirichlet boundary conditions
( u001 u1+m21u1+aju01j u01=bju1j u1ju2j +2; u002 u2+m22u2+aju02j u02=bju2j u2ju1j +2;
(9)
where m1; m2; a; b are non-negative constants, > 0 and 0. The existence of global solutions is discussed by using the potential well method and the asymptotic stability is also given by applying a Lemma due to V. Komornik [14].
REMARK 1.1. Noting here that our contribution is: We investigate the same system in [33] with the presence of the viscoelastic terms and potential functions, under additional condition (18), we prove that the solutions stay in the stable set (13).
2 Preliminaries
From now on, we denote by ci, i = 0;1;2; :::, used throughout this paper, various positive constants which may be di¤erent at di¤erent occurrences and in the sequel, for the sake of simplicity we will denote the tderivative valuedv=dtbyv0 andd2v=dt2 byv00.
We assume that, for i = 1;2; the relaxation functions gi : R+ ! R+ and the potential i:R+ !R+ are nonincreasing di¤erentiable satisfying:
gi(0)>0, +1>
+1
Z
0
gi(s)ds,1 i(t) Zt 0
gi(s)ds li>0, and i(t)>0: (10)
The following notation will be used throughout this paper ( )(t) =
Z t 0
(t )k (t) ( )k22d : (11) The following technical Lemma will play an important role.
LEMMA 2.1. For anyv2C1(0; T; H ( ))we have Z
(t) Z t
0
g(t s) v(s)v0(t)dsdx
= 1 2
d
dt (t) (g r v) (t) 1 2
d dt (t)
Z t 0
g(s) Z
jr v(t)j2dxds 1
2 (t) (g0 r v) (t) +1
2 (t)g(t) Z
jr v(t)j2dxds 1
2
0(t) (g r v) (t) +1 2
0(t) Z t
0
g(s)ds Z
jr v(t)j2dxds:
PROOF. It’s not hard to see Z
(t) Z t
0
g(t s) v(s)v0(t)dsdx
= (t)
Z t 0
g(t s) Z
r v0(t)r v(s)dxds
= (t)
Z t 0
g(t s) Z
r v0(t) [r v(s) r v(t)]dxds (t)
Z t 0
g(t s) Z
r v0(t)r v(t)dxds:
Consequently,
Z (t)
Z t 0
g(t s) v(s)v0(t)dsdx
= 1 2 (t)
Z t 0
g(t s)d dt
Z
jr v(s) r v(t)j2dxds (t)
Z t 0
g(s) d dt
1 2
Z
jr v(t)j2dx ds;
which implies, Z
(t) Z t
0
g(t s) v(s)v0(t)dsdx
= 1
2 d dt (t)
Z t 0
g(t s) Z
jr v(s) r v(t)j2dxds 1
2 d dt (t)
Z t 0
g(s) Z
jr v(t)j2dxds 1
2 (t) Z t
0
g0(t s) Z
jr v(s) r v(t)j2dxds +1
2 (t)g(t) Z
jr v(t)j2dxds 1 2
0(t) Z t
0
g(t s) Z
jr v(s) r v(t)j2dxds
+1 2
0(t) Z s
0
g(s)ds Z
jr v(t)j2dxds:
This completes the proof.
The energy functionalE(t)associated with our system is given by
E(t) =1 2
X2 i=1
ku0ik22+J(t) (12)
where
J(t) = 1 2
X2 i=1
1 i(t) Z t
0
gi(s)ds kr uik22
+1 2
X2 i=1
i(t)(gi r ui) +1 2
X2 i=1
m2ikuik22
1
pku1u2kpp: Now, we introduce the stable set as follows:
W = (u1; u2)2(H0( ))2:I(t)>0and J(t)< d [ f(0;0)g (13)
where
I(t) = X2 i=1
1 i(t) Z t
0
gi(s)ds kr uik22
+ X2 i=1
i(t)(gi r ui) + X2 i=1
m2ikuik22 ku1u2kpp:
REMARK 2.2. We notice that the mountain pass leveldgiven in (13) de…ned by d= inf
8<
: sup
(u1;u2)2(H0( ))2nf(0;0)g 0
J( (u1; u2)) 9=
;: Also, by introducing the so called "Nehari manifold"
N = n
(u1; u2)2(H0( ))2n f(0;0)g:I(t) = 0 o
: It is readily seen that the potential depthdis also characterized by
d= inf
(u1;u2)2NJ(t):
This characterization of dshows that dist((0;0);N) = min
(u1;u2)2Nk(u1; u2)k(H0( ))2:
The notation k:k stands for the norm in L2 and we denote by k:kX the norm in the space X. Also, the following imbedding will be used frequently without mention kukp Ckr uk2 foru2H0( )where
( 2 p <+1 if n= ;2 ;
2 p n2n2 if; n 3 : (14)
We introduce the following de…nition of weak solution to (1)-(4)
DEFINITION 2.3. A pair of functions (u1; u2) is said to be a weak solution of (1)-(4) on [0; T] ifu1; u2 2 Cw([0; T]; H0( )), u01; u02 2Cw([0; T]; L2( )), (u10; u20)2 H0( ) H0( ),(u11; u21)2L2( ) L2( )and(u1; u2)satis…es
Z t 0
Z
ju1jp 2u1ju2jp dxds = Z t
0
Z
u001 dxds+m21 Z t
0
Z
u1 dxds +
Z t 0
Z
r u1r dxds+ Z t
0
Z
ju01jr 2u01 dxds Z t
0
Z
1(t) Z s
0
g1(t )r u1(x; )r d dxds
and Z t
0
Z
ju2jp 2u2ju1jp dxds = Z t
0
Z
u002 dxds+m22 Z t
0
Z
u2 dxds +
Z t 0
Z
r u2r dxds+ Z t
0
Z
ju02jr 2u02 dxds Z t
0
Z
2(t) Z s
0
g2(t )r u2(x; )r d dxds for all test functions ; 2H0( )\L2( )and almost allt2[0; T]whereCw([0; T]; X) denotes the space of weakly continuous functions from[0; T]into Banach spaceX.
In order to state the local existence result, we introduce the following complete metric space (the proof is similar to that in [29, 32, 31])
YT = f(u; v) :u; v2C([0; T];H0( ) H0( )); u0; v02C [0; T];L2( ) L2( )
THEOREM 2.4. Let(u10; u20)2 (H0( ))2 and (u11; u21)2(L2( ))2 fori= 1;2 be given. Suppose thatr >2andpsatis…es
( 1 p <+1 if n= ;2 ;
1 p 4n 2n if n 3 : (15)
Then, under assumptions on two functionsgi,i= 1;2, the problem (1)-(4) has a unique local solution(u1(t; x); u2(t; x))2YT forT small enough.
3 Global Existence Result
LEMMA 3.1. Suppose that (10) and (15) hold. Let (u1; u2)be the solution of the system (1)-(4). Then the energy functional is a non-increasing function, that is for all t 0,
E0(t) = 1 2
X2 i=1
i(t)(gi0 r ui) 1 2
X2 i=1
i(t)gi(t)kr uik22
+1 2
X2 i=1
0(t)(gi r ui) 1 2
X2 i=1
0(t) Z t
0
gi(s)ds kr uik22
1 2
X2 i=1
0(t)(gi r ui) 1 2
X2 i=1
0(t) Z t
0
gi(s)ds kr uik22: (16)
We will prove the invariance of the setW:That is for somet0>0if(u1(t0); u2(t0))2 W; then(u1(t); u2(t))2W fort t0 andi= 1;2. We begin with by the existence of the potential depth in the next Lemma.
LEMMA 3.2. dis a positive constant.
PROOF. We have
J( (u1; u2)) =
2
2 X2 i=1
1 i(t) Z t
0
gi(s)ds kr uik22+
2
2 X2 i=1
i(t)(gi r ui)
+
2
2 X2
i=1
m2ikuik22 2p
p ku1u2kpp:
Using (10) to get
J( (u1; u2)) K( );
where
K( ) =
2
2 X2 i=1
likr uik22+
2
2 X2 i=1
m2ikuik22 2p
p ku1u2kpp: By di¤erentiating the second term in the last equality with respect to ;to get
d
d K( ) = X2 i=1
likr uik22+ X2 i=1
m2ikuik22 2 2p 1ku1u2kpp:
For 1= 0and
2= 2 2(p11) P2
i=1likr uik22+P2
i=1m2ikuik22
ku1u2kpp
!2(p11)
;
then we have
d
d K( ) = 0:
As
d
d K( 2) = 0; K( 1) = 0;
and since
d2 d 2K( )
= 2 <0;
we see that
sup
0
j( ) sup
0
K( ) =K( 2)
= 22(p2p1) P2
i=1likr uik22+P2
i=1m2ikuik22
ku1u2kpp
!2(p21)
X2 i=1
likr uik22+ X2 i=1
m2ikuik22
!
1 p22(p2p1)
P2
i=1likr uik22+P2
i=1m2ikuik22
ku1u2kpp
!2(p2p1)
ku1u2kpp
= 22(p2p1) p 1 p
P2
i=1likr uik22+P2
i=1m2ikuik22
ku1u2kp
!2(p2p1) :
It follows from the Holder inequality for someC >0and assumptions (10)
ku1u2kp ku1k2pku2k2p C2kr u1k2kr u2k2 1
2C2 X2 i=1
kr uik22
! 1 2C2
X2 i=1
likr uik22+ X2 i=1
m2ikuik22
!
;
which implies that
ku1u2kp
P2
i=1likr uik22+P2
i=1m2ikuik22
1 2C2:
Sincep >1, we obatin that
sup
0
j( ) 22(p2p1) p 1 p
" P2
i=1likr uik22+P2
i=1m2ikuik22
ku1u2kp
#2(p2p1)
(p 1)
p C(p2p1) =d >0:
Then, by the de…nition ofd;we conclude thatd >0forp >1:
LEMMA 3.3. W is a bounded neighborhood of0 inH0( ).
PROOF. Foru2W;andu6= 0;we have J(t) = 1
2 X2 i=1
1 i(t) Z t
0
gi(s)ds kr uik22+1 2
X2 i=1
i(t)(gi r ui)
+1 2
X2 i=1
m2ikuik22
1
pku1u2kpp
= p 2
2p
" 2 X
i=1
1 i(t) Z t
0
gi(s)ds kr uik22
+ X2 i=1
i(t)(gi r ui) + X2
i=1
m2ikuik22
# +1
pI(t) p 2
2p
" 2 X
i=1
1 i(t) Z t
0
gi(s)ds kr uik22
+ X2 i=1
i(t)(gi r ui) + X2
i=1
m2ikuik22
#
: (17)
By using (10), (17) becomes
J(t) p 2
2p X2 i=1
1 i(t) Z t
0
gi(s)ds kr uik22
p 2 2p
X2 i=1
likr uik22
p 2
2p min(l1; l2) X2 i=1
kr uik22:
It follows that X2 i=1
kr uik22
1 min(l1; l2)
2p
p 2 J(t)< 1 min(l1; l2)
2p
p 2 d=R:
Consequently,8(u1; u2)2W;we have (u1; u2)2B;where
B= (
(u1; u2)2(H0( ))2: X2 i=1
kr uik22< R )
:
This completes the proof.
In the following Lemma, we will see that if the initial data (or for somet0>0) is in the setW, then the solution stays there forever.
LEMMA 3.4. Suppose that (10), (15) and C2
(2 min(l1; l2))
p 2pE(0) p 2
(p 1)
<1: (18)
hold, where C is the best Poincare’s constant. If (u10; u20) 2 W and (u11; u21) 2 L2( ) 2, then the solution(u1(t); u2(t))2W fort 0.
PROOF. Since(u10; u20)2W, we see that I(t) =
X2 i=1
kr ui0k22+ X2 i=1
m2ikui0k22 ku10u20kpp >0:
Consequently, by continuity, there exists Tm T such that I(u(t)) =
X2 i=1
1 i(t) Z t
0
gi(s)ds kr uik22+ X2 i=1
i(t)(gi r ui)
+ X2 i=1
m2ikuik22 ku1u2kpp 0 fort2[0; Tm]: This gives
J(t) = 1 2
X2 i=1
1 i(t) Z t
0
gi(s)ds kr uik22+1 2
X2 i=1
i(t)(gi r ui) (19) +1
2 X2 i=1
m2ikuik22
1
pku1u2kpp
= p 2
2p
" 2 X
i=1
1 i(t) Z t
0
gi(s)ds kr uik22+ X2 i=1
i(t)(gi r ui)
+ X2 i=1
m2ikuik22
# +1
pI(u(t)) p 2
2p
" 2 X
i=1
1 i(t) Z t
0
gi(s)ds kr uik22+ X2 i=1
i(t)(gi r ui)
+ X2 i=1
m2ikuik22
# :
By using (10) and the fact that Rt
0gi(s)ds R1
0 gi(s)ds; we easily see that, for t 2 [0; Tm],
X2 i=1
kr uik22
1 min(l1; l2)
2p
p 2 J(t) 1
min(l1; l2) 2p
p 2 E(t) 1
min(l1; l2) 2p
p 2 E(0):
We then exploit (10), (15) and from the Holder inequality for someC >0. So we have ku1u2kp ku1k2pku2k2p C2kr u1k2kr u2k2 1
2C2 X2 i=1
kr uik22
! : forC=C(n; p; ):
Consequently, we have ku1u2kpp 2 pC2p
X2 i=1
kr uik22
!p
2 pC2p X2 i=1
kr uik22
!p 1 X2 i=1
kr uik22
!
C2p(2 min(l1; l2)) p 2p p 2
(p 1)
E(0)(p 1) X2 i=1
likr uik22
!
X2 i=1
likr uik22
!
; where
=C2p(2 min(l1; l2)) p 2p p 2
(p 1)
E(0)(p 1): Which means, by the de…nition ofli; i= 1;2;
ku1u2kpp
X2 i=1
likr uik22
!
X2 i=1
1 i(t) Z t
0
gi(s)ds kr uik22
X2 i=1
1 i(t) Z t
0
gi(s)ds kr uik22+ X2 i=1
i(t)(gi r ui) + X2 i=1
m2ikuik22: Therefore,I(t)>0for allt2[0; Tm], by taking the fact that
t7!limTm
C2p(2 min(l1; l2)) p 2p p 2
(p 1)
E(0)(p 1) <1:
This shows that the solution (u1(t); u2(t))2W; for all t2[0; Tm]: By repeating this procedure Tmextends toT:
THEOREM 3.5. Suppose that (10), (15) and (18) hold. If(u10; u20)2W;(u11; u21)2 L2( ) 2. Then the local solution (u1; u2) is global in time such that (u1; u2)2 GT where
GT = (u; v) :u; v2L1 R+;H0( ) H0( ) andu0; v02L1 R+;L2( ) L2( ) :
PROOF. In order to prove Theorem 3.5, it su¢ ces to show that the following norm X2
i=1
ku0ik22+ X2 i=1
kr uik22+ X2 i=1
m2ikuik22
is bounded independently oft. To achieve this, we use (12), (16) and (19) to get E(0) E(t) =J(t) +1
2 X2 i=1
ku0i(t)k22
p 2 2p
" 2 X
i=1
1 i(t) Z t
0
gi(s)ds kr uik22+ X2 i=1
i(t)(gi r ui)
+ X2
i=1
m2ikuik22
# +1
2 X2 i=1
ku0i(t)k22+1 pI(t) p 2
2p
" 2 X
i=1
likr uik22+ X2 i=1
i(t)(gi r ui) + X2 i=1
m2ikuik22
#
+1 2
X2 i=1
ku0i(t)k22+1 pI(t) p 2
2p
" 2 X
i=1
likr uik22+ X2 i=1
m2ikuik22
# +1
2 X2 i=1
ku0i(t)k22: SinceI(t)and i(t)(g ru)(t)are positive, hence
X2 i=1
ku0i(t)k22+ X2 i=1
kr uik22+ X2 i=1
m2ikuik22 CE(0);
where Cis a positive constant depending only on pandli. This completes the proof.
Open problem Let us mention here that, it will be interesting to discuss the as- ymptotic stability of this problem where also, one can establish a general decay rate estimate for the energy, which will depend on the behavior of both and g under following assumption
There exists a non-increasing di¤erentiable function i; i= 1;2 :R+ !R+ satis- fying i(t)>0; gi0(t) i(t)gi(t);8t 0;and perhaps other conditions imposed by the nature of our system.
Acknowledgments. The authors want to thank the referee for his/her careful reading of the proofs.
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