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El e c t ro nic

Journ a l of

Pr

ob a b il i t y

Vol. 16 (2011), Paper no. 88, pages 2439–2451.

Journal URL

http://www.math.washington.edu/~ejpecp/

A Note on Rate of Convergence in Probability to Semicircular Law

Zhidong Bai Jiang Hu Guangming Pan§ Wang Zhou

Abstract

In the present paper, we prove that under the assumption of the finite sixth moment for elements of a Wigner matrix, the convergence rate of its empirical spectral distribution to the Wigner semicircular law in probability isO(n−1/2)when the dimensionntends to infinity..

Key words:convergence rate, Wigner matrix, Semicircular Law, spectral distribution.

AMS 2010 Subject Classification:Primary 60F15; Secondary: 62H99.

Submitted to EJP on March 18, 2010, final version accepted November 17, 2011.

Z. D. Bai was partially supported by CNSF 10871036. J. Hu was partially supported by the Fundamental Research Funds for the Central Universities 10ssxt149. G.M. Pan was partially supported by a grant M58110052 at the Nanyang Technological University. W. Zhou was partially supported by grant R-155-000-095-112 at the National University of Singapore

KLASMOE and School of Mathematics & Statistics, Northeast Normal University, Changchun, 130024, P.R.C. and Department of Statistics and Applied Probability, National University of Singapore. E-mail: [email protected]

KLASMOE and School of Mathematics & Statistics, Northeast Normal University, Changchun, 130024, P.R.C. E-mail:

[email protected]

§Division of Mathematical Sciences, School of Physical and Mathematical Sciences, Nanyang Technological University.

E-mail: [email protected]

Department of Statistics and Applied Probability, National University of Singapore, Singapore 117546. E-mail:

[email protected]

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1 Introduction and the result.

A Wigner matrixWn = n1/2€ xi jŠn

i,j=1 is defined to be a Hermitian random matrix whose entries on and above the diagonal are independent zero-mean random variables. It is an important model for depicting heavy-nuclei atoms, which began with the seminal work of Wigner in 1955 ([16]).

Details in this area can be found in[13].

There are various mathematical tools in the study of Wigner matrices in the past half century (see [1]). One of the most popular instruments is the limit theory of empirical spectral distribution (ESD). Here, for anyn×nmatrixAwith real eigenvalues, the ESD ofAis defined by

FA(x) = 1 n

n

X

i=1

IAix),

where λAi denotes the i-th smallest eigenvalue of A and I(B)denotes the indicator function of an eventB. It is proved that, under assumptions of for alli,j,E|xi j|2=σ2, the ESDFWn(x)converges almost surely to a non-random distributionF(x)which has the destiny function

f(x) = 1 2πσ

p

4σ2x2, x ∈[−2σ, 2σ]. (1) This is also known as the Wigner semicircular law (see[16],[6]).

The rate of convergence is important in establishing the central limit theorem for linear spectral statistics of Wigner matrices ([7, 6]). There are some partial results in this area. In[2], Bai proved that under the assumption of supnsupi,jEx4i j<∞, the rate of

n=kEFWnFk:=sup

x |EFWn(x)−F(x)|

tending to 0 isO(n1/4). Bai et al. in[4]obtained that the rate established in[2]was still valid in probability for

p=kFWnFk:=sup

x |FWn(x)−F(x)|

Under a stronger condition that supnsupi,jEx8i j <∞, Bai et al. in[5]showed that∆n=O(n1/2) and∆p=Op(n2/5)(Bai and Silverstein improved this condition up to supnsupi,jExi j6 <∞in their book[6] ). Here and in the sequel, the notation Rn = Op(rn) means for any " > 0, there exists anC > 0 such that supnP(|Rn| ≥C rn)< ". Later, Götze et al. in[10]derived∆n =O(n1/2) as well assuming fourth moment, and∆p=Op(n−1/2)at the cost of the twelfth moment of the matrix entries. There are some other results with some special assumptions on the matrix entries. If the entries ofWn have a normal distribution, then the optimal order∆n=O(n1)was shown in[11]. When the distribution of the entries satisfies a Poincare inequality or a uniformly subexponential decay, the order of∆p can be improved toOp(n2/3log2n)andOp(n1logCn)with some constant C respectively. For which one can refer to[9, 8].

In this note we prove that the twelfth moment condition in [10] could be reduced to the sixth moment assumption while still getting∆p=Op(n−1/2). Our main result of this paper is as follows.

Theorem 1.1. Assume that

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• Exi j=0, for all1≤ijn,

• E|x2ii|=σ2>0,E|xi j|2=1, for all1≤i< jn,

• supnsup1≤i<j≤nE|x3ii|,E|xi j|6<∞. Then we have

p:=kFWnFk=Op(n1/2). (2) Remark 1.2. It is not clear what the exact rate and the optimal conditions are in Theorem 1.1.

The rest of this paper is organized as follows. The main tool of proving the theorem is introduced in Section 2. Theorem 1.1 is proved in Section 3 and some technical lemmas are given in Sec- tion 4. Throughout this paper, constants appearing in inequalities are represented byC which are nonrandom and may take different values from one appearance to another.

2 The main tool

For any function of bounded variationH on the real line, its Stieltjes transform is defined by sH(z) =

Z 1

λzd H(λ), z∈C+≡ {z∈C+:z>0}.

Our main tool to prove the theorem is a Berry-Esseen type inequality which is proved in[2]. Lemma 2.1. (Bai inequality) Let F be a distribution function and let G be a function of bounded variation satisfying R

|F(x)−G(x)|d x <. Denote their Stieltjes transforms by sF(z) and sG(z) respectively, where z=u+i v∈C+. Then

kFGk ≤ 1

π(1−ζ)(2ρ−1) Z A

−A

|sF(z)−sG(z)|du

+2πv1 Z

|x|>B

|F(x)G(x)|d x

+v1sup

x

Z

|u|≤2vε

|G(x+u)−G(x)|du

! ,

where the constants A > B > 0, ζ and ε are restricted by ρ = π1R

|u|≤ε 1

u2+1du > 12, and ζ =

4B

π(AB)(2ρ−1)∈(0, 1).

Here we should notice that we can use the same methods in[10]to prove our theorem. However, Götze-Tikhomirov inequality (see Corollary 2.3 in[10]) involves the supremum of|sn(z)−Esn(z)|

overℑz in some interval. This makes the proof rather complicated. Therefore in this paper, we use Bai inequality instead of Götze-Tikhomirov inequality which could make the presentation simpler.

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3 The proof of Theorem 1.1.

We will firstly introduce a new technique which can handle the moment conditions efficiently. That is given in Lemma 3.2. Then, by using this lemma and dividing the expression ofE|sn−Esn|2, we prove our theorem step by step.

Before proving the theorem, we introduce some notation. DenoteIn be the identity matrix of size nandai be theith column ofWn with xii removed. DefineD(z) =n1/2WnzIn,Di(z) =D(z)− n−1aiai andsn=sn(z) =sFWn(z). Moreover write

βi

n1/2xiizn1aiDi 1aiŠ−1

, γi =aiDi 1ait rDi 1

"i=n1/2xiin1aiDi 1ai+Esn(z), ˆγi=aiDi2ait rDi 2 ξi =t rD−1t rD−1i , an= (z+Esn(z))−1.

Throughout this section, we denotez =u+i v, u∈[−16, 16]and 1≥ vv0 = C0n−1/2 with an appropriate constantC0. Lets=s(z) =sF(z), we know that (see (3.2) in[2])

s(z) =−1 2

 z

p z2−4

‹

for allz∈C+. Then we have

Z 16

16

1

|z+2s(z)|du≤ Z 16

16

1 p|z2−4|

du≤ Z 16

16

1 p|u2−4|

du<10. (3)

In addition, by Lemma 2.1 and Theorem 8.2 in[6], we have for some positive constantC, EkFWnFk ≤C

Z 16

−16

E|sn(z)−Esn(z)|du+O(n1/2). (4) Therefore, the rest of the proof is reduced to the lemma below.

Lemma 3.1. Under the assumptions in Theorem 1.1, for any1> vv0 =C0n1/2 with sufficiently large C0>0, we have

Esn(z)−Esn(z)

2C

n|z+2s(z)|2. 3.1 Known results and a preliminary lemma

Following the same truncation, centralization and rescaling steps in [6], in this section we may assume the random variables satisfy the conditions as follows

|xi j| ≤n1/4, Exi j=0, E|xi j|2=1 for alli,j.

Bai in[2]derived the equation

sn(z) = 1

nt rD1= 1 n

Xn

i=1

βi,

(5)

which together with the fact

βi=−an+anβi"i, (5)

implies

sn(z) =−an+an n

Xn i=1

βi"i. (6)

For eachiwe have

|ℑβi1|=|ℑ€

z+n1aiDi 1aiŠ

| ≥v.

Thus we have

i| ≤v1. (7)

From the definition of"i it follows that

"i =n1/2xiin1γi+n1ξi−(sn−Esn), (8) and

sn=−an+ an n3/2

Xn i=1

βixii+an n2

Xn i=1

βiγi+an n2

Xn i=1

βiξian(sn−Esn)sn. (9)

Then, we have the the following lemma.

Lemma 3.2. Under the assumption in Theorem 1.1, we have for any v>v0 P |βi|>2

C

n2v2. (10)

Proof. From integration by parts and Theorem 1.1 in[10], we have for 1>v>v0,

|Esn(z)−s(z)|=

Z

−∞

d(EFWn(x)−F(x)) xz

=

Z

−∞

EFWn(x)−F(x) (x−z)2 d x

C, which together with the fact that|s(z)| ≤1 ( see (3.3) in[2]) implies

|Esn(z)| ≤C.

Then applying Lemma 4.2 and Lemma 4.3 we have for 1>v>v0, E|sn(z)| ≤C and 1

nE|t rDi1| ≤C.

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By Lemma 4.1 we can check that

E|γi|4CE€t rDi 1(Di 1)Š2

+n1/2t r€

Di 1(Di 1)Š2

C€

v2E|t rDi 1|2+n1/2v3E|t rDi1

C n2

v2 . (11)

Thus, from (8), Lemma 4.2 and Lemma 4.3 we have forv>v0, E|"i|4C

n2v2. (12)

In addition, by the proof of Lemma 5.1 and (5.59) in[10], we can see that

|an| ≤1 for allvv0. (13)

Therefore from the equation (5) we can obtain P |βi|>2

≤P

|an"i|> 1 2

≤24E|"i|4C n2v2, which complete the proof.

3.2 The proof of Lemma 3.1

Notice that in this subsection, we will use the equality (5) and (8) frequently. From (9), we have Esn−Esn

2=E(sn−Esn)(sn−Esn)

=E(sn−Esn)sn=an(S1+S2+S3+S4), where

S1= 1 n3/2

Xn

i=1

E(sn−Esn)xiiβi, S2=− 1 n2

Xn

i=1

E(sn−Esniβi,

S3= 1 n2

n

X

i=1

E(sn−Esniβi, S4=−E|sn−Esn|2sn.

We first considerS1. From (5), we have S1= 1

n3/2

n

X

i=1

E(sn−Esn)xiiβi

= an n3/2

n

X

i=1

E€−(sn−Esn)xii+anE(sn−Esn)xii"ian(sn−Esn)xiiβi"i2Š

= an n3/2

Xn

i=1

E −S11+S12S13 .

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By Lemma 4.2 we have

|ES11|= 1 nEξixii

≤E|xii| nv =O

1 n v

. (14)

From (12), (13), Hölder’s inequality and Lemma 4.3, we obtain

|ES12| ≤€

E|sn−Esn|4E|"i|4(E|xii|2)2Š1/4

C

n3/2v2. (15)

Next we consider the termS13. Using (12), (13), Lemma 3.2, Lemma 4.3 and the fact|βi| ≤v1we have

|ES13| ≤2€

E|sn−Esn|4(E|"i|4)2E|xii|4Š1/4

+v−1€

E|sn−Esn|4(E|"i|4)2Š1/4€

E|xii|2I(|βi|>2)Š1/2

C

nv. (16)

Therefore combining inequalities (13)-(16) we obtain

|S1|=O 1

n

. (17)

Furthermore, we have the following expression forS2, S2=−1

n2

n

X

i=1

E(sn−Esniβi

= an n2

Xn i=1

E(sn−Esnia2n n2

Xn i=1

E(sn−Esni"iβi

=S21+S22+S23+S24+S25, where

S21= an n2

n

X

i=1

E(snn1t rDii, S22=− an n5/2

n

X

i=1

E(sn−Esn)xiiγiβi,

S23= an n3

n

X

i=1

E(sn−Esniγ2i, S24=−an n3

n

X

i=1

E(sn−Esniβiξi,

S25= an n2

Xn i=1

E|sn−Esn|2γiβi.

Here we will use the method which we used to handle the bound ofS1. Firstly, we expressS21 as follows

S21= an n3

n

X

i=1

E((1+n1aiD−2i aiii

=S211+S212,

(8)

where

S211=−|an|2 n4

Xn i=1

E(ˆγii S212= |an|2 n3

Xn i=1

E((1+n1aiDi2aii"ii. From Lemma 4.1 and Hölder’s inequality we get

|S211| ≤ C n4

n

X

i=1

€E|γˆi|2E|γi|2Š1/2

C

n2v2. Applying Lemma 4.2, Hölder’s inequality and (12), we obtain

S212= |an|2 n2

n

X

i=1

E(snn−1t rD−1i "ii

C n3v

n

X

i=1

€E|"i|2E|γi|2Š1/2

C

n2v2. From the last two inequalities we obtain

|S21|=O 1

n2v2

. (18)

ForS22, we use Lemma 4.2 to get

|S22| ≤ C n7/2

Xn i=1

E|t rDi 1−Et rDi 1||xiiγiβi|+ C n7/2v

Xn i=1

E|xiiγiβi|. Notice thatxii andγi are independent. From Hölder’s inequality and Lemma 3.2 we have

E|xiiγiβi| ≤CE|xiiγi|+€

E|xiiγi|2E|βiI(|βi|>2)|2Š1/2

=O(n1/2v1/2). Similarly we can get

E|t rDi1−Et rDi 1||xiiγiβi| ≤€

E|t rDi1−Et rDi 1|4E|γi|4Š1/4

=O(n1/2v2), which implies

|S22| ≤ C

n2v2. (19)

Now considerS23. Using Lemma 4.2 again we obtain

|S23| ≤ C n3

n

X

i=1

E|t rDi 1−Et rDi 1||γ2iβi|+ C n3v

n

X

i=1

E|γ2iβi|

C n3

Xn i=1

E|t rDi 1−Et rDi 1||γ2iβi|+ C n2v2. Applying Lemma 3.2 and Hölder’s inequality we obtain

E|t rDi 1−Et rDi 1||γ2iβi| ≤2E|t rDi 1−Et rDi 1||γ2i| +€

(E|t rDi 1−Et rDi1|2i|4)E|βiI(|βi|>2)|2Š1/2

≤€

E|t rDi1−Et rDi 1|2i|4Š1/2

.

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It follows from (11) that

E|t rDi 1−Et rDi 1|2i|4

CE|t rDi 1−Et rDi1|2€

v2|t rDi 1|2+n1/2v3|t rDi 1

C v2E|t rDi 1−Et rDi 1|4+C n2

v2 E|t rDi 1−Et rDi 1|2

C n2

v2 E|t rDi 1−Et rDi 1|2+ C v8

C n2

v2 E|t rD−1−Et rD−1|2+ C v8. Then, we conclude that

|S23| ≤ C nv

Esn−Esn

21/2

+ C

n2v2. (20)

From Lemma 3.2, Lemma 4.2, Lemma 4.3 and Hölder’s inequality, it is easy to check that

|S24| ≤ C n2v

Xn

i=1

€E|sn−Esn|4E|γi|4Š1/4€

E|βi|2I(|βi|>2)Š1/2

C

n2v2. (21) ForS25, we use (5) to represent it in the form

S25=− a2n n2

Xn

i=1

E|sn−Esn|2γi+ an2 n2

Xn

i=1

E|sn−Esn|2γi"iβi

=−S251+S252.

Using Lemma 4.3 and Hölder’s inequality we obtain

|S251| ≤C n4

Xn

i=1

E|ξi−Eξi|2i|+ C n4

Xn

i=1

E|ξi−Eξi||t rD−1i −Et rD−1i ||γi|

C

n5/2v5/2+ C

n5/2v3 =O 1

n2v2

. (22)

Similarly we can obtain that E|sn−Esn|2γi"iβi≤€

E(|sn−Esn|8i|4)E|"i|4Š1/4€

2+E|βi|2I(|βi|>2)Š1/2

C

n1/2v1/2

€E(|sn−Esn|8i|41/4

C

n1/2v1/2

n8E(|ξi−Eξi|8i|4) +n8E(|t rDi 1−Et rDi 1|8i|4)1/4

C

n3v4. From the last inequality and (22) we obtain

|S25| ≤ C

n2v2. (23)

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Combining inequalities (18)-(21) and (23), we conclude that, forvv0

|S2| ≤ C nv

Esn−Esn

21/2

+ C

n2v2. (24)

From Lemma 3.2, Lemma 4.3 and Hölder’s inequality, we can check that

|S3| ≤ C n2v

Xn

i=1

€E|sn−Esn|2(2+E|βi|2I(|βi|>2))Š1/2

C n v

€E|sn−Esn|2Š1/2

. (25)

Therefore, it remians to get the bound ofS4. Now we recall the equality (9), then we have S4=anE|sn−Esn|2an(S41+S42+S43+S44),

and

S4=−EsnE|sn−Esn|2−E|sn−Esn|2(sn−Esn). (26) Here

S41= 1 n3/2

Xn

i=1

E|sn−Esn|2xiiβi, S42=− 1 n2

Xn

i=1

E|sn−Esn|2γiβi,

S43= 1 n2

n

X

i=1

E|sn−Esn|2ξiβi,

S44=−EsnE|sn−Esn|2(sn−Esn)−E|sn−Esn|2(sn−Esn)2. Comparing (26) withS44, we obtain that

(1+anEsn)E|sn−Esn|2(sn−Esn)

=−(an+Esn)E|sn−Esn|2

+an(S41+S42+S43−E|sn−Esn|2(sn−Esn)2), which implies that

−E|sn−Esn|2(sn−Esn)

=bnan1(an+Esn)E|sn−Esn|2

bn(S41+S42+S43−E|sn−Esn|2(sn−Esn)2), where bn= (z+2Esn(z))1. Thus denotingδn=n1Pn

i=1Eβi"i, we conclude that S4=(−Esn+bnan1(an+Esn))E|sn−Esn|2

bn(S41+S42+S43−E|sn−Esn|2(sn−Esn)2)

=(anδnbnEsn)E|sn−Esn|2

bn(S41+S42+S43−E|sn−Esn|2(sn−Esn)2)

=(an+anδnbn)E|sn−Esn|2

bn2nE|sn−Esn|2+S41+S42+S43−E|sn−Esn|2(sn−Esn)2).

(11)

It is obvious thatS42 andS25 have the same bound. Using Lemma 3.2, Lemma 4.2 and Lemma 4.3 we get the following three inequalities

|E|sn−Esn|2(sn−Esn)2| ≤E|sn−Esn|4C n4v6,

|S43| ≤ 1 nv

€E|sn−Esn|4Š1/2

C

n3v4, and

|E|sn−Esn|2xiiβi| ≤ |E|sn−Esn|2xiian|+|E|sn−Esn|2xiian"iβi|

C

n2v3

E|sn−Esn|16E|xii|8Š1/8€

E|"i|4Š1/4€

2+E|βi|2I(|βi|>2)Š1/2

=O 1

n2v3

. Furthermore, from the definition ofδn and (12), we have

n|=

n1 Xn

i=1

€En1Di 1−Esn+Eβi"2iŠ

C nv. Therefore, we obtain

S4=anE|sn−Esn|2+O |bn|

n2v2

, which combined with (17), (24) and (25) implies

|1−a2n|E|sn−Esn|2C1|anbn|

n +C2|an| pn

€E|sn−Esn|2Š1/2

.

Then, from (6.91) and (6.95) in[10]which are under the existing fourth moment assumption, for 1>v>v0,

|1−a2n| ≥ |an(z+2s(z))|and|bn| ≤2|z+2s(z)|1, we obtain the following inequality

E|sn−Esn|2C1

n|z+2s(z)|2 + C2 pn|z+2s(z)|

€E|sn−Esn|2Š1/2

. Solving this inequality, we obtain

E|sn−Esn|2C n|z+2s(z)|2, which complete the proof of the Lemma.

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4 Basic lemmas

In this section we list some results which are needed in the proof.

Lemma 4.1. (Lemma B.26 of[6]) LetA be an n×n nonrandom matrix and X= (x1, . . . ,xn) be a random vector of independent entries. Assume thatExi =0, E|xi|2 = 1, and E|xj|lνl. Then, for any p≥1,

E|XAXt rA|pCp

ν4t r(AA)p/2

+ν2pt r(AA)p/2 , where Cpis a constant depending on p only.

Lemma 4.2. (Lemma 2.6 of[14]). Let z∈C+with v=ℑz,AandBn×n withBHermitian,τ∈R, andq∈CN. Then

|t r((BzI)1−(B+τqqzI)1)A| ≤ kAk v .

Lemma 4.3. (Lemma 8.7 of[6]) Under the assumption in Theorem 1.1, we have for any l≥1 E|sn(z)−Esn(z)|2lC

n2lv3l. (27)

Acknowledgement: The authors would like to thank the referee for his/her helpful suggestions.

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