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Acta Math. Univ. Comenianae

Vol. LXI, 1(1992), pp. 91–93 91

DIFFERENCES BETWEEN VALUES OF A QUADRATIC FORM

A. SCHINZEL

J. W. S. Cassels, A. Pfister and the writer proved independently in 1989 the following theorem: let f(x, y) be a primitive quadratic form, n an odd integer.

Thenn is a difference of two values off over Z(see [2], Proposition 4.3). Using this result J. Bochnak proved (unpublished) that the same condition holds if either the discriminant off is not divisible by 16 orn6≡2 (mod 4).The aim of this paper is to prove the following more general theorem.

Theorem. Letf be a primitive quadratic form inkvariables,n∈Z. If either f 6≡ ±g2 (mod4) for every linear formg orn6≡2 (mod4), thenn is a difference of two values of f and fork >1in infinitely many ways.

Proof. Let us consider the representation ofnby

f(x1, . . . , xk)−f(xk+1, . . . , x2k) =f⊥(−f)

in the ring ofp-adic integersZp. Ifpis odd, we have (see [3], Theorem 33) f ∼f0⊥pf1⊥ · · · ⊥plfl=h,

wherefj is either 0 or a form of a unit determinant inZp. Sincef is primitive we havef06= 0 and by the quoted theorem

f0= Xm i=1

aix2i, m≥1.

We take

x1=n+a1

2a1 , xk+1= n−a1

2a1

and sincex1−xk+1= 1

h(x1,0, . . . ,0)−h(xk+1,0, . . . ,0) =n

Received November 25, 1991.

1980Mathematics Subject Classification(1991Revision). Primary 11E25.

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92 A. SCHINZEL

is a representation of n byh⊥(−h), hence there exists a representation of n by f⊥(−f) inZp. Forp= 2 consider first the case off non-classic and apply Theorem 33a of [3] to 2f. We obtain

(1) 2f ∼f0⊥2f1⊥ · · · ⊥2lfl= 2h,

wherefj is either 0 or a form of a unit determinant inZ2.Sincef is primitive and non-classic we havef06= 0 and by Theorem 33a eitherf0= 2x1x2+g0(x3, . . . , xm) orf0= 2x21+ 2x1x2+ 2x22+g0(x3, . . . , xm).

In the first case we have

h(n,1,0, . . . ,0)−h(0, . . . ,0) =n, in the second case

h(n−1,1,0, . . . ,0)−h(n−1,0, . . . ,0) =n, thusnis represented byf⊥(−f).

Assume now thatf is classic. Then by Theorem 33 of [3]

f ∼f0⊥2f1⊥ · · · ⊥2lfl=g,

where fi satisfy the same conditions as in formula (1). Since f is primitive we havef06= 0 and by Theorem 33 of [3]

f0=

m0

X

i=1

aix2i, ai odd m0≥1.

Ifn≡1 (mod 2) we have the representation h

n+a1

2a1 ,0, . . . ,0

−h

n−a1

2a1 ,0, . . . ,0

=n.

Ifn≡2 (mod 4) we usef 6≡ ±g2 (mod 4), hence eitherm0≥2 orm0= 1, f1=

1+mX1

i=2

aix2i, ai odd m1≥1.

In the first case we have the representation h

n+a1−a2

2a1 ,1,0, . . . ,0

−h

n−a1−a2

2a1 ,0, . . . ,0

=n.

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DIFFERENCES BETWEEN VALUES OF A QUADRATIC FORM 93 In the second case, we have the representation

h

0,n+ 2a2

4a2 ,0, . . . ,0

−h

0,n−2a2

4a2 ,0, . . . ,0

=n.

Ifn≡0 (mod 4) we have the representation h

n

4a1+ 1,0, . . . ,0

−h n

4a1

−1,0, . . . ,0

=n.

Thus in every case we have a representation ofnbyf⊥(−f) in everyZp, hence by Lemma 4.1, Chapter 7 and Theorem 1.5, Chapter 9 of [1] if rank off ≥2,nhas a representation byf⊥(−f). If rank off = 1,f =εg2, whereε=±1,gis a linear form, hencen6≡2 (mod 4) and we solveg(x1, . . . , xk) = εn+12 , g(xk+1, . . . , x2k) =

εn1

2 (nodd) org(x1, . . . , xk) =εn4 +1, g(xk+1, . . . , x2k) = εn4 −1 (n≡0 mod 4).

It remains to prove that ifk >1 the number of representations is infinite. Let f =

Xk i=1

aix2i + Xk i<j

aijxixj.

The equation

(2) f(x1, . . . , xk)−f(x1−r1, . . . , xk−rk) =n is equivalent to

Xk j=1

xj

2ajrj+X

j<k

ajkrk+X

i<j

aijri

=n+f(r1, . . . , rk).

Hence if fork > 1 and somer1, . . . , rk (2) has one solution in integers it has infinitely many.

References

1.Cassels J. W. S.,Rational quadratic forms, Academic Press, 1978.

2.Huisman J.,The underlying real algebraic structure of complex elliptic curves(to appear).

3.Jones B. W.,The arithmetic theory of quadratic forms, J. Wiley, 1950.

A. Schinzel, Mathematical Institute PAN, P.O.Box 137, 00-950 Warszawa, Poland

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