Numerical simulation of bacterial flora in the
intestine of zebrafish larvae
著者
楊 金有
学位授与機関
Tohoku University
学位授与番号
11301甲第18814号
(ゼブラフィッシュ稚魚の腸内フローラの
数値シミュレーション)
○ 1 2
A.veronii
t
h h
h h h h
t Qin Q0 δf c h Qin Q0 δf c h Qin(δf c h δf(Qin Q0 c h h Qin Q0 δf c t Qin Q0 δf c h Qin Q0 δf c h P a(z) Pt c Qin Q0 δf h Qin δf c δf(Qin Q0 c h h (Qin Q0 δf c
×10 7 nc/N t ϕmax ϕmax = 1.0× 10 11 2 ϕmax = 5.0× 10 11 2 ϕmax = 1.0× 10 10 2 nc/N ϕmax nc/N t ‒ ϕmax ϕ0 nc/N ϕ0 Qin(Db = 1× 10 11 2 Db Qin = Q0
ϕ0 Qin Db Qin(Db = 1× 10−11 2 Db Qin = Q0 t ϕmax ×10−11 2 ϕ max ×10−11 2 ϕ max ×10−10 2 nc/N Uϕ UQ UD Uϕ Uϕ UQ UD
108
P roteobacteria Lactobacillales
Aeromonas
Aeromonas V ibrio
̶ ̶
Wl(z, t) = W24(z) + g(z, t), g(z, t) = δgexp ! −t τg " exp # ln0.5 λ2 g (z− zg0)2 $ , Wl(z, t) g(z, t) δg τg λg zg0 W24(z) i.e. t t zf 0 f (z, t) W (z, h + t)
40 80 120 160 200 240 0 0.4 0.8 1.2 1.6 Diameter [ µ m] z [mm] a From paper From equation 40 80 120 160 200 240 0 0.4 0.8 1.2 1.6 Diameter [ µ m] z [mm] b From paper From equation 40 80 120 160 200 240 0 0.4 0.8 1.2 1.6 Diameter [ µ m] z [mm] c From paper From equation 40 80 120 160 200 240 0 0.4 0.8 1.2 1.6 Diameter [ µ m] z [mm] d From paper From equation 40 80 120 160 200 240 0 0.4 0.8 1.2 1.6 Diameter [ µ m] z [mm] e From paper From equation 40 80 120 160 200 240 0 0.4 0.8 1.2 1.6 Diameter [ µ m] z [mm] f From paper From equation h h h h h h
W (z, h + t) = Wl(z, h) + fan(z, t) + fre(z, t) + ct ∂g(z, t) ∂t |(t=h), fan(z, t) =−δfJ(z, dan)exp % ln0.5 λ2 f {z − H(t, ∆tan)Uc− zf 0}2 & , fre(z, t) =−δfJ(z, dre)exp % ln0.5 λ2 f {z − H(t, ∆tre)Uc − zf 0}2 & , h fan(z, t) fre(z, t) δf λf Uc J(z, d) J(z, d) = ⎧ ⎨ ⎩ 1, when |z − zf 0| ≤ d exp[−(|z − zf 0| − d) l ], when |z − zf 0| > d . d l d H(t, ∆t) ∆t c c i.e. i.e. ρ µ = 10−3 · = ρW Uc/µ
t V0 1 I0 1 I24 sum V10 I24 sum I0 1 Q0 = ! V24 sum − V10× I24 sum I0 1 " / (24× 60 × 60) = 8.3×10−17 3/ V24 sum Q0
0
5
10
15
20
25
80
100 120 140 160 180 200 220 240 260
Velocity [
µ
m/s]
y [µm]
Front line 1
Mesh number 202,752
Mesh number 404,096
Mesh number 806,784
Mesh number 1,511,488
5
10
15
20
25
30
35
40
45
100
120
140
160
180
200
220
240
Velocity [
µ
m/s]
y [µm]
Front line 2
Mesh number 202,752
Mesh number 404,096
Mesh number 806,784
Mesh number 1,511,488
14
16
18
20
22
24
26
28
30
32
80
100 120 140 160 180 200 220 240 260
Velocity [
µ
m/s]
y [µm]
Front line 3
Mesh number 202,752
Mesh number 404,096
Mesh number 806,784
Mesh number 1,511,488
4
6
8
10
12
14
16
18
230 240 250 260 270 280 290 300 310 320
Velocity [
µ
m/s]
y [µm]
Back line 1
Mesh number 202,752
Mesh number 404,096
Mesh number 806,784
Mesh number 1,511,488
5
10
15
20
25
30
35
250
260
270
280
290
300
310
Velocity [
µ
m/s]
y [µm]
Back line 2
Mesh number 202,752
Mesh number 404,096
Mesh number 806,784
Mesh number 1,511,488
6
8
10
12
14
16
18
20
240
250
260
270
280
290
300
310
320
Velocity [
µ
m/s]
y [µm]
Back line 3
Mesh number 202,752
Mesh number 404,096
Mesh number 806,784
Mesh number 1,511,488
t10−4 10−5 D(t) = 1 N N * i=1 [ i(t)− i(0)]2 6t i i i i(t2) = i(t1) + + t2 t1 idt D D δf
(Uc) (∆t) (dre) (dan) δf ‒ Qin ‒ Q0 c ‒ h ‒ δf ‒ ∆T ∆Tre ∆Tan dre dan λf δf zf 0 δg τg λg zg0 c Uc ρ 3 µ · Qin ‒ Q0 Q0 × −17 3
i.e. z < zf 0 t Qin Q0, δf = 0.3 c h Qin Q0, δf = 0.3 c h D D D 10−12 2/ Qin Q0 Q0 Q0 δf δf D t δf h D h h
Qin
0
2
4
6
8
10
0
500
1000
1500
2000
2500
D
[10
-12
m
2
/s]
t [s]
Qin Q0 δf c h t Qin Q0, δf c h c0 2 4 6 8 10 0 500 1000 1500 2000 2500 D [10 -12 m 2 /s] t [s]
A
0Q0 1Q0 2Q0 3Q0 4Q0 5Q0 0 2 4 6 8 10 0 500 1000 1500 2000 2500 D [10 -12 m 2 /s] t [s]B
δf=0.1R δf=0.2R δf=0.3R δf=0.4R δf=0.5R 0 2 4 6 8 10 0 500 1000 1500 2000 2500 D [10 -12 m 2 /s] t [s]C
0 h 3 h 6 h 12 h 24 h Qin(δf c h δf(Qin Q0 c h h Qin Q0 δf cP a(z) Pt P a(z) c Pt c Pt c Qin Qin g(z, t) δf δf δf h h
t Qin Q0 δf
-0.01
0
0.01
0.02
0.03
0.04
0.05
0
0.5
1
1.5
Pressure [Pa]
z [mm]
A
Without anterograde peristalsis
With anterograde peristalsis
-0.01
0
0.01
0.02
0.03
0.04
0.05
0
0.5
1
1.5
P
a
(z)
[Pa]
z [mm]
B
Without anterograde peristalsis
With anterograde peristalsis
Qin Q0 δf c h
-0.01
0
0.02
0.04
0.06
0.08
0
10
20
30
40
P
t
[Pa]
c
A
Without anterograde peristalsis
With anterograde peristalsis
0.025
0.027
0.029
0.031
0.033
0.035
0
1
2
3
4
5
P
t
[Pa]
Q
in
[Q
0
]
B
Without anterograde peristalsis
With anterograde peristalsis
0.015
0.02
0.025
0.03
0.035
0.1
0.2
0.3
0.4
0.5
P
t
[Pa]
δ
f
C
Without anterograde peristalsis
With anterograde peristalsis
0.026
0.028
0.03
0.032
0.034
0
6
12
18
24
P
t
[Pa]
h [hours]
D
Without anterograde peristalsis
With anterograde peristalsis
Pt
c Qin Q0 δf h Qin δf c
δf(Qin Q0 c h h (Qin Q0 δf
DB DB = kBT /(6µr) kB T µ r ◦ · D B 10−12 / D 10−12 / · HAM = A0 + M0σS/σ0 A0 M0 σ0 σs σs 10 3 ·
Aeromonas V ibrio
zf 0 f (z, t) W (z, t) ⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩ W (z, h + t) = W0(z, h) + fan(z, t) + fre(z, t), fan(z, t) =−δfJ(z, dan)exp % ln0.5 λ2 f {z − H(t, ∆tan)Uc − zf 0}2 & , fre(z, t) = −δfJ(z, dre)exp % ln0.5 λ2 f {z − H(t, ∆tre)Uc− zf 0}2 & , W0(z) fan(z, t) fre(z, t) δf λf Uc J(z, d) J(z, d) = ⎧ ⎨ ⎩ 1, when |z − zf 0| ≤ d exp[−(|z − zf 0| − d) l ], when |z − zf 0| > d . d l d H(t, ∆t ∆t
⎧ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎩ ∇ · = 0, ∂ ∂t + ( · ∇) = − 1 ρ∇p + µ ρ∇ 2 . ∇ ρ p µ ρ m3 µ 10−3 · ρW Uc µ Q0 Q0 8.3× 10−17 3/
‒
∂b ∂t + ∇b = Db∇ 2n + ! λg n KM + n − λ d " b b Db λg λd KM i.e. ∂n ∂t + ∇n = Dn∇ 2n + Y n n KM + n b Dn Yn 3 5.3×10−7 1012 −3 i.e. ≤ 3ϕ = ϕmax -−a (z − z0)2 . ϕmax Aeromonas z0 i.e. 5.66 × 106 ϕmax = b∇ϕ b ϕ ϕ 2 ∇ϕ λg
∂b ∂t + ( +∇ϕ) ∇b = Db∇ 2b +/λ g− λd− ∇2ϕ)b λg = ⎧ ⎨ ⎩ 3.2× 10−4s−1, (b≤ 6.5 × 1015m−3) 0. (b≥ 6.5 × 1015m−3) 6.5× 1015 b 6.5× 1015 ‒ ‒ ‒ δf
Uc ∆t dre dan Db 10 12 10 10 2 Q in ‒ Q0 Aeromonas ‒ nc/N i.e.
δf ∆T ∆Tre ∆Tan dre dan λf δf zf 0 × 12 ‒ 10 2 g × 4 −1 d × 5 −1 KM 3 × 16 κ × 7 × 10 2 Uc ρ 3 µ · Qin ‒ Q0
N nc/N nc/N ‒ 5.3× 10 7 t 1012 n c/N nc/N ‒ 5.3 × 10 7 107 n c/N nc/N nc/N ‒
0
0.2
0.4
0.6
0.8
1
0
2
4
6
8
10
n
c
/N
Time [h]
Without nutrient flux across the wall With nutrient flux across the wall
ϕmax ‒ ϕmax nc/N ϕmax nc/N ϕmax nc/N ϕmax 1.0× 10 10 2 ϕmax
D
bQ
in nc/N nc/N ϕmax ϕ0 nc/N Qin ϕ0 Db × 11 2 Qin Qin Qin i.e. Qin Q0 ϕ0 Qin Q0 ϕ0 Qint ϕmax
ϕmax = 1.0× 10 11 2 ϕmax = 5.0× 10 11 2
0
0.2
0.4
0.6
0.8
1
0
2
4
6
8
10
ϕmax=1×10-10[m2/s] 5×10-11[m2/s] 1×10-11[m2/s] 5×10-12[m2/s] 1×10-12[m2/s]n
c
/N
Time [h]
nc/N ϕmax0
0.2
0.4
0.6
0.8
1
10
-12
10
-11
ϕ
0
10
-10
10
-9
0.75
Maximum n
c
/N
ϕ
max
[m
2
/s]
nc/N t ‒ ϕmax ϕ0 nc/N10
-11
10
-10
10
-9
10
-2
10
-1
10
0
10
1
slope 1ϕ
0
[m
2
/s]
Q
in
/Q
0
A
10
-11
10
-10
10
-9
10
-12
10
-11
10
-10
10
-9
slope 1ϕ
0
[m
2
/s]
D
b
[m
2
/s]
B
ϕ0 Qin(Db = 1× 10 11 2 Db Qin= Q0ϕ0 Qin = Q0 Db 3 10 11 2 ϕ0 Db Db 1 10 11 2 ϕ0 Db nc/N nc/N ϕ0 nc/N ϕ0 Qin Db ϕ0 ϕ0
10
-11
10
-10
10
-9
0.1
1
10
ϕ
0
[m
2
/s]
Q
in
/Q
0
A
With peristalsis
Without peristalsis
10
-11
10
-10
10
-9
10
-12
10
-11
10
-10
ϕ
0
[m
2
/s]
D
b
[m
2
/s]
B
With peristalsis
Without peristalsis
ϕ0 Qin Db Qin(Db = 1× 10−11 2 Db Qin= Q0t
ϕmax ×10−11 2
0
0.2
0.4
0.6
0.8
1
0
2
4
6
8
10
ϕmax=1×10-10[m2/s] 5×10-11[m2/s] 1×10-11[m2/s] 5×10-12[m2/s] 1×10-12[m2/s]n
c
/N
Time [h]
nc/Nϕ = ϕmax 2 L ! L 2 − |z − z0| " ϕmax z0 i.e. Uϕ i.e. Uϕ ∼ϕ0 UQ UD UQ i.e. UQ ∼ in Am Am z0 UD UD ∼ b Uϕ UQ UD Uϕ UQ UD Uϕ UQ UD Uϕ
Uϕ UQ UD
Uϕ
Uϕ UQ UD Uϕ UQ+ UD Uϕ UQ UD ϕ0 Qin Qin Qin UQ UQ Qin UD Qin Db UQ UQ UD Qin ϕ0 Qin Qin ϕ0 Db Db UQ Qin Am Db ϕ0 UD UD UD ∼ b Db UD ϕ0 ‒ ϕmax ϕ0 nc/N Qin Db ϕ0
Qin Db Qin Db ϕ0 Qin
Db ϕ0
10 12 / ‒ ϕmax ϕ0 nc/N Qin Db ϕ0 Qin Db Qin Db ϕ0 Qin Db
ϕ0
Uϕ
‒
‒
‒
‒
‒ ‒ ‒ ‒ ‒ ‒ ‒ ‒ ‒
‒ ‒ 楊金有 下權谷祐児 石川拓司 ゼブラフィッシュの腸内フローラシミュレ ーション 日本流体力学会年会 年度年次大会 講演論文集 大 阪 年 月 楊金有 下權谷祐児 石川拓司 ゼブラフィッシュ稚魚の腸内輸送現象の シミュレーション 日本流体力学会年会 年度年次大会 講演論文集 東京 年 月 楊金有 下權谷祐児 石川拓司 ゼブラフィッシュ稚魚の腸内流れのシミュ レーション 日本機械学会第 回バイオエンジニアリング講演会 講演論 文集 名古屋 年 月