Research Article
Bernoulli polynomials of the second kind and their identities arising from umbral calculus
Taekyun Kima,b, Dae San Kimc,∗, Dmitry V. Dolgyd, Jong-Jin Seoe
aDepartment of Mathematics, College of Science, Tianjin Polytechnic University, Tianjin City, 300387, China.
bDepartment of Mathematics, Kwangwoon University, Seoul 139-701, S. Korea.
cDepartment of Mathematics, Sogang University, Seoul 121-742, Republic of Korea.
dSchool of Natural Sciences, Far Eastern Federal University, 690950 Vladivostok, Russia.
eDepartment of Applied Mathematics, Pukyong National University, Pusan 608-739, S. Korea.
Communicated by S.-H. Rim
Abstract
In this paper, we study the Bernoulli polynomials of the second kind with umbral calculus viewpoint and derive various identities involving those polynomials by using umbral calculus. c2016 All rights reserved.
Keywords: Bernoulli polynomial of the second kind, umbral calculus.
2010 MSC: 05A40, 11B68, 11B83.
1. Introduction and preliminaries
As is well known, the ordinary Bernoulli polynomials are defined by the generating function to be t
et−1ext=
∞
X
n=0
Bn(x)tn
n!, (see [2, 10, 15, 17]). (1.1)
When x= 0, Bn =Bn(0) are called the Bernoulli numbers. The Bernoulli polynomials of the second kind are given by the generating function to be
t
log (1 +t)(1 +t)x=
∞
X
n=0
bn(x)tn
n!, (see [19, 21, 22]). (1.2)
∗Corresponding author
Email addresses: [email protected], [email protected](Taekyun Kim),[email protected](Dae San Kim), [email protected](Dmitry V. Dolgy ),[email protected](Jong-Jin Seo)
Received 2015-10-08
When x= 0, bn=bn(0) are called the Bernoulli numbers of the second kind.
The first few Bernoulli numbers bnof the second kind are b0= 1, b1= 1
2, b2=− 1
12, b3 = 1
24, b4 =− 19
720, b5= 3 160,· · · . By (1.2), we easily get
bn(x) =
n
X
l=0
n l
bl(x)n−l, (1.3)
where (x)n=x(x−1)· · ·(x−n+ 1), (n≥0), and
bn(x) =Bn(n)(x+ 1), (see [21, 22]), (1.4) whereB(α)n (x) are the Bernoulli polynomials of orderα.
The stirling number of the second kind is given by xn=
n
X
l=0
S2(n, l) (x)l, (n≥0). (1.5)
The Stirling number of the first kind is defined by (x)n=x(x−1)· · ·(x−n+ 1) =
n
X
l=0
S1(n, l)xl, (n≥0). (1.6) LetCbe the complex number field and letF be the set of all formal power series in the variablet:
F= (
f(t) =
∞
X
k=0
aktk k!
ak ∈C )
. (1.7)
Let us assume thatPis the algebra of polynomials in the variablexoverCandP∗ is the vector space of all linear functionals on P. hL|p(x)i denotes the action of the linear functional L on a polynomial p(x). For f(t)∈ F, we define the continuous linear functional f(t) onP by
hf(t)|xni=an, (n≥0), (see [21]). (1.8) Thus, by (1.7) and (1.8), we get
D tk
xnE
=n!δn,k, (n, k≥0), (see [1–22]), (1.9) whereδn,k is the Kronecker’s symbol.
For fL(t) =
∞
P
k=0
hL|xki
k! tk, we have hfL(t)|xni =hL|xni,(n≥0). Thus, we see that fL(t) = L. The mapL7→fL(t) is a vector space isomorphism fromP∗ ontoF. Henceforth, F is thought of as both a formal power series and a linear functional. We call F the umbral algebra. The umbral calculus is the study of umbral algebra. The order o(f(t)) of the non-zero power series f(t) is the smallest integer k for which the coefficient of tk does not vanish (see [8, 21]). If o(f(t)) = 1, then f(t) is called a delta series and if o(f(t)) = 0, thenf(t) is called an invertible series. Forf(t), g(t)∈ F with o(f(t)) = 1 ando(g(t)) = 0, there exists a unique sequencesn(x) of polynomials such that
D
g(t)f(t)k sn(x)
E
=n!δn,k, wheren, k≥0.
The sequencesn(x) is called the Sheffer sequence for (g(t), f(t)) which is denoted bysn(x)∼(g(t), f(t)).
For p(x) ∈P, we have eyt
p(x)
=p(y) and eytp(x) = p(x+y). Let f(t)∈ F and p(x) ∈P. Then we see that
f(t) =
∞
X
k=0
f(t) xk
k! tk, p(x) =
∞
X
k=0
tk p(x)
k! xk. (1.10)
Thus, by (1.10), we get
p(k)(0) = D
tk p(x)
E ,
D
1|p(k)(x) E
=p(k)(0). (1.11)
From (1.11), we have
tkp(x) =p(k)(x) = dkp(x)
dxk , (k≥0). Forsn(x)∼(g(t), f(t)), we have
dsn(x) dx =
n−1
X
l=0
n l
D f(t)
xn−lE
sl(x), (n≥1), (1.12)
wheref(t) is the compositional inverse off(t) withf(f(t)) =f f(t)
=t, 1
g f(t) =exf(t)=
∞
X
n=0
sn(x)tn
n!, for allx∈C, (1.13)
f(t)sn(x) =nsn−1(x), (n≥1), sn(x+y) =
n
X
j=0
n j
sj(x)pn−j(y), (1.14) wherepn(x) =g(t)sn(x),
hf(t)|xp(x)i=h∂tf(t)|p(x)i, (1.15) and
sn+1(x) =
x−g0(t) g(t)
1
f0(t)sn(x), (n≥0), (see [1, 13, 16, 21]). (1.16) Assume thatpn(x)∼ 1, f(t)
and qn(x)∼ 1, g(t)
. Then the transfer formula is given by qn(x) =x
f(t) g(t)
n
x−1pn(x) (n≥1). (1.17)
Forsn(x)∼(g(t), f(t)), rn(x)∼(h(t), l(t)), we have sn(x) =
n
X
m=0
Cn,mrm(x), (n≥0), (1.18)
where
Cn,m = 1 m!
*h f(t)
g f(t) l f(t)m
xm +
, (see [12, 21]). (1.19)
In this paper, we study the Bernoulli polynomials of the second kind with umbral calculus viewpoint and derive various identities involving those polynomials by using umbral calculus.
2. Bernoulli polynomials of the second kind
For α∈N, the Bernoulli polynomials of the second kind with orderα are defined by t
log (1 +t) α
(1 +t)x =
∞
X
n=0
b(α)n (x)tn
n!. (2.1)
Note that bn(x) =b(1)n (x). When x= 0,b(α)n =b(α)n (0) are called the Bernoulli numbers of the second kind with orderα. Indeed, we note that
b(α)n (x) =Bn(n−α+1)(x+ 1). Let us consider the following two sheffer sequences :
qn(x)∼
1,
log (1 +t) t
α
et−1
and
(x)n∼ 1, et−1 . Thus, by (1.17), we get
qn(x) =x
t log (1 +t)
αn
x−1(x)n
=x
t log (1 +t)
αn
(x−1)n−1
=xb(αn)n−1 (x−1), (n≥1). That is,
xb(αn)n−1 (x−1)∼
1,
log (1 +t) t
α
et−1
. From (1.2) and (1.13), we have
bn(x)∼ t
et−1, et−1
. (2.2)
By (2.2), we get
t
et−1bn(x)∼ 1, et−1
, (x)n∼ 1, et−1
. (2.3)
Thus, we see that
bn(x) = et−1
t (x)n= et−1 t
n
X
l=0
S1(n, l)xl (2.4)
= et−1
n
X
l=0
S1(n, l) l+ 1 xl+1
=
n
X
l=0
S1(n, l) l+ 1
(x+ 1)l+1−xl+1 .
When x= 0, we have
bn=
n
X
l=0
S1(n, l) l+ 1 . By (1.12), we get
d
dxbn(x) =
n−1
X
l=0
n l
D
log (1 +t)|xn−lE
bl(x) (2.5)
=
n−1
X
l=0
n l
* ∞ X
m=1
(−1)m−1 m tm
xn−l +
bl(x)
=
n−1
X
l=0
n l
(n−l−1)! (−1)n−l−1bl(x)
=
n−1
X
l=0
n!
l!(n−l)(−1)n−l−1bl(x), (n≥1). Therefore, by (2.5), we obtain the following lemma.
Lemma 1. Forn≥1, we have d
dxbn(x) =
n−1
X
l=0
n!
l!(n−l)(−1)n−l−1bl(x). From (1.9), we have
bn(y) = t
log (1 +t)
(1 +t)y
xn
(2.6)
=
* t log (1 +t)
∞
X
m=0
(y)m tm m!xn
+
=
n
X
m=0
(y)m n
m
t log (1 +t)
xn−m
=
n
X
m=0
(y)m n
m
bn−m.
Therefore, by (2.6), we obtain the following proposition.
Proposition 2. Forn≥0, we have
bn(x) =
n
X
m=0
n m
bn−m(x)m
=
n
X
m=0
m!
n m
x m
bn−m.
By (1.2), we get
bn(x) = t
log (1 +t)(x)n=
n
X
l=0
S1(n, l)
t log (1 +t)
xl (2.7)
=
n
X
l=0
S1(n, l)
l
X
m=0
bm
m!tmxl
=
n
X
l=0
S1(n, l)
l
X
m=0
l m
bmxl−m
=
n
X
l=0 l
X
m=0
S1(n, l) l
m
bl−mxm.
By (1.14), we get
bn(x+y) =
n
X
j=0
n j
bj(x) (y)n−j. (2.8)
Let
Pn={p(x)∈C[x]|degp(x)≤n}, (n≥0).
Then it is an (n+ 1)-dimensional vector space overC. Now, we consider the polynomial p(x) in Pn which is given by
p(x) =
n
X
m=0
Cmbm(x). (2.9)
Thus, by (2.9), we get
t
et−1 et−1m
p(x)
=
n
X
l=0
Cl t
et−1 et−1m
bl(x)
(2.10)
=
n
X
l=0
Cll!δm,l=m!Cm. From (2.10), we have
Cm= 1 m!
t et−1
et−1m
p(x)
. (2.11)
Therefore, by (2.11), we obtain the following theorem.
Theorem 3. Let p(x)∈Pn with
p(x) =
n
X
m=0
Cmbm(x). Then, we have
Cm= 1 m!
t et−1
et−1m
p(x)
.
For example, let us takep(x) =Bn(x)∈Pn. Then, we have Bn(x) =
n
X
m=0
Cmbm(x), (2.12)
where
Cm = 1 m!
t et−1
et−1m
Bn(x)
(2.13)
=
n
X
l=m
S2(l, m) n
l
t et−1
Bn−l(x)
=
n
X
l=m
S2(l, m) n
l n−l
X
k=0
Bn−l−k
n−l k
t et−1
xk
=
n
X
l=m n−l
X
k=0
S2(l, m) n
l
n−l k
Bn−l−kBk.
Therefore, by (2.12) and (2.13), we obtain the following theorem.
Theorem 4. Forn≥0, we have Bn(x) =
n
X
m=0
( n X
l=m n−l
X
k=0
n l
n−l k
S2(l, m)Bn−l−kBk )
bm(x). Remark. From (2.13), for m≥1, we have
Cm = 1 m!
t et−1
et−1m
Bn(x)
(2.14)
= 1 m!
D
et−1m−1
tBn(x)E
= n m!
D
et−1m−1
Bn−1(x)E
= n
m!(m−1)!
n−1
X
l=m−1
S2(l, m−1)1 l!
D tl
Bn−1(x) E
= n m
n−1
X
l=m−1
S2(l, m−1)
n−1 l
Bn−1−l.
Therefore, by (2.12) and (2.14), we get Bn(x) =
n
X
m=1
(n m
n−1
X
l=m−1
S2(l, m−1)
n−1 l
Bn−1−l
)
bm(x) +
n
X
k=0
n k
Bn−kBk.
The classical polylogarithm function is given by Lik(x) =
∞
X
n=1
xn
nk, (k∈Z, x >0). (2.15) The poly-Bernoulli polynomials are defined by the generating function to be
Lik 1−et et−1 ext=
∞
X
n=0
Bn(k)(x)tn
n!. (2.16)
Thus, by (2.16), we see that
B(k)n (x)∼
et−1 Lik(1−e−t), t
. (2.17)
Let us take p(x) =Bn(k)(x)∈Pn.Then we have Bn(k)(x) =
n
X
m=0
Cmbm(x), (2.18)
where
Cm = 1 m!
t
et−1 et−1m
Bn(k)(x)
(2.19)
=
n
X
l=m
S2(l, m) n
l
t et−1
Bn−l(k) (x)
=
n
X
l=m
S2(l, m) n
l n−l
X
j=0
n−l j
B(k)n−l−j
t et−1
xj
=
n
X
l=m n−l
X
j=0
n l
n−l j
S2(l, m)Bn−l−j(k) Bj,
where B(k)n = Bn(k)(0) are the poly-Bernoulli numbers. Therefore, by (2.18) and (2.19), we obtain the following theorem.
Theorem 5. Forn≥0, we have Bn(k)(x) =
n
X
m=0
n
X
l=m n−l
X
j=0
n l
n−l j
S2(l, m)Bn−j−l(k) Bj
bm(x). Let us considerp(x) =xn∈Pn. Then, we have
xn=
n
X
m=0
Cmbm(x), (2.20)
where
Cm= 1 m!
t et−1
et−1m
xn
(2.21)
=
n
X
l=m
S2(l, m) n
l
t et−1
xn−l
=
n
X
l=m
S2(l, m) n
l
Bn−l.
Thus, by (2.20) and (2.21), we get xn=
n
X
m=0
( n X
l=m
S2(l, m) n
l
Bn−l
)
bm(x). (2.22)
Let us consider the following two Sheffer sequences : bn(x)∼
t
et−1, et−1
, (2.23)
and
B(k)n (x)∼
et−1 Lik(1−e−t), t
. Then, by (1.17) and (1.18), we get
Bn(k)(x) =
n
X
m=0
Cn,mbm(x), (2.24)
where
Cn,m= 1 m!
*Lik 1−e−t et−1
t et−1
et−1m
xn +
(2.25)
=
n
X
l=m
S2(l, m) n
l *
Lik 1−e−t et−1
t et−1xn−l
+
=
n
X
l=m
S2(l, m) n
l n−l
X
j=0
n−l j
Bn−l−j
*Lik 1−e−t et−1
xj +
=
n
X
l=m n−l
X
j=0
n l
n−l j
S2(l, m)Bn−l−jBj(k). Therefore, by (2.24) and (2.25), we obtain the following theorem.
Theorem 6. Forn≥0, we have Bn(k)(x) =
n
X
m=0
n
X
l=m n−l
X
j=0
n l
n−l j
S2(l, m)Bn−l−jBj(k)
bm(x). Let us consider the following Sheffer sequences:
bn(x)∼ t
et−1, et−1
, (2.26)
Bn(x)∼
et−1 t , t
. Then we have
bn(x) =
n
X
m=0
Cn,mBm(x), (2.27)
where
Cn,m = 1 m!
t log (1 +t)
t
log (1 +t)(log (1 +t))m
xn
(2.28)
=
n
X
l=m
n l
S1(l, m)
* t log (1 +t)
2
xn−l +
=
n
X
l=m
n l
S1(l, m)b(2)n−l,
whereb(2)n are di-Bernoulli numbers of the second kind.
Therefore, by (2.27) and (2.28), we get bn(x) =
n
X
m=0 n
X
l=m
n l
S1(l, m)b(2)n−l
!
Bm(x). (2.29)
Acknowledgement
This paper is supported by grant No. 14-11-00022 of Russian Scientific fund.
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