Certain Aspects of Some Arithmetic Functions in Number Theory
1Nicu¸sor Minculete, Petric˘a Dicu
Abstract
The purpose of this paper is to present several inequalities about the arithmetic functions σ(e), τ(e), σ(e)∗, τ(e)∗ and other well-known arithmetic functions. Among these, we have the following:
pσ∗k(n)·σl∗(n) σ∗k−l
2
(n) ≤ nl−4k ·σ∗k(n) +nk−4l·σl∗(n) 2·σk−l
2 (n) ≤n
l−k
4 ·nk+l2 + 1
2 ,
for anyn, k, l∈N∗, q
σk(e)∗(n)·τ(e)∗(n) σ(ke−)∗l
2
(n) ≤nl−4k ·σ(ke)∗(n) +nk−4l ·τ(e)∗(n) 2·σ(ke−)∗l
2
(n) ≤
≤ n
l−k
4 · nk+l2 + 1
2 , for any n, k, l ∈ N∗, σk(e)(n)·σl(e)(n) ≤ τ(e)(n)· σk(e+)l(n), for any n, k, l ∈ N∗ and σ(ke+1)∗(n)
σ(ke)∗(n) ≥ σ(e)∗(n)
τ(e)∗(n) ≥ τ(n), for any n, k∈N∗, whereτ(n) is the number of the natural divisors ofnandσ(n) is the sum of the divisors ofn.
2000 Mathematics Subject Classification: 11A25
Key words and phrases: the sum of the natural divisors ofn, the number of the natural divisors of n, the sum of the kth powers of the unitary divisors
of n, the number of the unitary divisors of n, the sum of the exponential divisors ofn, the number of the exponential divisors of n, the sum of the e-unitary divisors of n, and the number of the e-unitary divisors ofn.
1Received 3 November, 2009
Accepted for publication (in revised form) 16 June, 2010
135
1 Introduction
Let n be a positive integer, n ≥ 1. We note with σk(n) the sum of the kth powers of divisors of n, so, σk(n) = X
d|n
dk, whence we obtain the following equalities: σ1(n) =σ(n) and σ0(n) = τ(n)- the number of divisors of n (see [6]). If dis a unitary divisor ofn, then we have
d,n d
= 1. Letσk∗(n) denote the sum of the kth powers of the unitary divisors of n. We note d||n.
Next we have to mention that the notion of ”exponential divisor” was intro- duced M. V. Subbarao in [9].
Letn >1 be an integer of canonical from n=pa11pa22...parr. The integer d =
r
Y
i=1
pbii is called an exponential divisor (or e-divisor) of n =
r
Y
i=1
paii >1, if bi|ai for every i= 1, r. We note d|(e)n. Let σ(e)(n) denote the sum of the exponential divisors of n and τ(e)(n) denote the number of the exponential divisors of n. In [11] L. T´oth and N. Minculete introduced the notion of ” exponential unitary divisors” or ”e-unitary divisors”. The integer d =
r
Y
i=1
pbii is called a e-unitary divisor of n =
r
Y
i=1
paii > 1 if bi is a unitary divisor of ai, so
bi,ai
bi
= 1, for every i = 1, r. Let σ(e)∗(n) denote the sum of e-unitary divisor ofn, andτ(e)∗(n) denote the number of the e-unitary divisors of n. We note d|(e)∗. By convention, 1 is an e-unitary divisor of n >1, the smallest e-unitary divisor ofn=pa11pa22...parr >1 isp1p2...pr, where p1p2...pr=γ(n) is called the ”core” ofn.
Other aspects of these arithmetic function can be found in the papers [7] and [10].
In [6], J. S´andor shows that
(1)
pσk(n)·σl(n) σk−l
2 (n) ≤n−(
k−l)
4 ·n
k+l
2 + 1
2 , for alln, k, l∈N∗. In [8], J. S´andor and L. T´oth proved the inequalities
(2) nk+ 1
2 ≥ σ∗k(n) τ∗(n) ≥√
nk,
and
(3) σk∗+m
σm∗(n) ≥√ nk, for all n≥1 and k, m≥0, real numbers.
In [3, 4], we found the inequalities (4)
pσk(n)·σl(n) σk−l
2 (n) ≤ nl−4kσk(n) +nk−4lσl(n) 2σk−l
2 (n) ≤n−(
k−l)
4 ·nk+2l + 1
2 ,
for everyn, k, l∈Nwithn≥1 and k−l 2 ∈N, (5)
pσk+2(n)·σk(n)
σ(n) ≤
√1nσk+2(n) +√nσk(n)
2σ(n) ≤ 1
√n·nk+1+ 1
2 ,
for everyn, k∈N andn≥1,
(6) q
σk(e)(n)τ(e)(n) σk−l
2 (n) ≤ n
l−k
4 σk(e)(n) +n
k−l 4 τ(e)(n) 2σ(ke−)l
2
(n) ≤n−(
k−l)
4 ·nk+2l + 1
2 ,
for everyn, k, l∈Nwithn≥1 and k−l 2 ∈N,
(7) q
σk(e+2) (n)·τ(e)(n) σ(e)(n) ≤
√1nσk(e+2) (n) +√
nτ(e)(n) 2σ(e)(n) ≤ 1
√n ·nk+1+ 1
2 ,
for everyn, k∈N n≥1,
(8)
q
σk(e)(n)·τ(e)(n)
τ(e)(n) ≤ σ(ke)(n) +τ(e)(n)
2τ(e)(n) ≤ nk+ 1 2 , and
(9) σk(e)(n)
τ(e) ≤
nk+ 1 2
2
, for everyn, k∈N andn≥1.
2 Main results
An inequality which is due to J.B. Diaz and F.T. Matcalf is proved in [2], namely:
Lemma 1 Let n be a positive integer,n≥2. For every a1, a2, ..., an∈R and for every b1, b2, ..., bn ∈ R∗ with m ≤ ai
bi ≤ M and m, M ∈ R, we have the following inequality:
(10)
n
X
i=1
a2i +mM
n
X
i=1
b2i ≤(m+M)
n
X
i=1
aibi.
Theorem 1 For every n, k, l ∈ N with n ≥ 1 and k−l
2 ∈ N, the following relation
(11)
pσk∗(n)·σ∗l(n) σ∗k−l
2
(n) ≤ nl−4k ·σk∗(n) +nk−4l·σl∗(n) 2·σ∗k−l
2
(n) ≤n
l−k 4 ·n
k+l
2 + 1
2 is true.
Proof. Forn= 1, we have equality in relation (11). Forn≥2, in the Lemma above, making the substitutions ai =
q
dki and bi = 1 q
dli
, where di is the unitary divisors of n, for all i= 1, τ∗(n). Since 1≤ ai
bi = q
dki+l ≤n
k+l
2 and
aibi=d
k−l 2
i , we takem= 1 andM =nk+2l. Therefore, inequality (10) becomes
τ∗(n)
X
i=1
dki +n
k+l 2 ·
τ∗(n)
X
i=1
1 dli
≤ 1 +n
k+l 2
τ∗(n)
X
i=1
d
k−l 2
i , which is equivalent to
σk∗(n) +n
k+l
2 ·σ∗l(n) nl ≤
1 +n
k+l 2
·σ∗k−l 2
(n), so that
(12) σ∗k(n) +n
k−l
2 ·σ∗l(n)≤ 1 +n
k+l 2
·σ∗k−l 2
(n), for everyn, k, l∈Nwithn≥2.
The arithmetical mean is greater than the geometrical mean or they are equal, so for everyn, k, l∈Nwithn≥2, we have
(13)
q
nk−2l·σ∗k(n)·σl∗(n)≤ σk∗(n) +n
k−l
2 ·σl∗(n)
2 .
Consequently, from the relations (12) and (13) and taking into account that the relation ”≤” is transitive, we deduce the inequality
pσ∗k(n)·σ∗l(n) σ∗k−l
2
(n) ≤ n
l−k
4 ·σk∗(n) +n
k−l
4 ·σl∗(n) 2·σ∗k−l
2
(n) ≤n
l−k 4 ·n
k+l
2 + 1
2 .
Remark 1 For k= l in inequality (11), we obtain the relation of J. S´andor and L. T´oth, namely
(14) nk+ 1
2 ≥ σk∗(n) τ∗(n), for everyn, k∈N with n≥1.
Theorem 2 For every n, k, l ∈ N with n ≥ 1 and k−l
2 ∈ N, the following relation
(15) q
σk(e)∗(n)·τ(e)∗(n) σ(ke−)∗l
2
(n) ≤ nl−4k ·σk(e)∗(n) +nk−4l ·τ(e)∗(n) 2·σ(ke−)∗l
2
(n) ≤n
l−k 4 ·n
k+l
2 + 1
2 is true.
Proof. Forn= 1, we have equality in relation (15). Forn≥2, in the Lemma above, making the substitutions ai = q
dki and bi = 1 q
dli
, where di is the e-unitary divisor of n, for all i= 1, τ(e)∗(n). Since k−l
2 ∈N, we havek≥l, so, we deduce 1≤ ai
bi = q
dki+l ≤nk+2l andaibi=d
k−l 2
i . Hence, we takem= 1 and M =nk+2l.
Therefore, inequality (10) becomes
τ(e)∗(n)
X
i=1
dki +n
k+l 2 ·
τ(e)∗(n)
X
i=1
1 dli
≤ 1 +n
k+l 2
τ(e)∗(n)
X
i=1
d
k−l 2
i ,
which is equivalent to
σ(e)∗(n) +nk+2l ·
τ(e)∗(n)
X
i=1
1 dli
≤
1 +nk+2l σ(ke−)∗l
2
. But
τ(e)∗(n)
X
i=1
1 dli
≥
τ(e)∗(n)
X
i=1
1
nl = τ(e)∗(n) nl . Therefore, we obtain the inequality
σ(ke)∗(n) +n
k+l
2 ·τ(e)∗(n) nl ≤
1 +n
k+l 2
·σ(ke−)∗l 2
(n) which means that
(16) σk(e)∗(n) +nk−2l ·τ(e)∗(n)≤
1 +nk+2l
·σ(ke−)∗l 2
(n), for everyn, k, l∈Nwithn≥2.
The arithmetical mean is greater than the geometrical mean or they are equal, so for everyn, k, l ∈Nwithn≥2, we have
(17)
q
nk−2l ·σk(e)∗(n)·τ(e)∗(n)≤ σ(ke)∗(n) +n
k−l
2 ·τ(e)∗(n)
2 .
Consequently, from the relations (16) and (17), we deduce the inequality q
σk(e)∗(n)·τ(e)∗(n) σ(ke−)∗l
2
(n) ≤ nl−4k ·σk(e)∗(n) +nk−4l·τ(e)∗(n) 2·σ(ke−)∗l
2
(n) ≤n
l−k
4 ·nk+2l + 1
2 .
Remark 2 For k=l, we obtain the relation
(18) σk(e)∗(n)
τ(e)∗(n) ≤
nk+ 1 2
2
, for everyn, k∈Nwith n≥1.
Remark 3 For k=l= 1, we obtain the relation (19)
s
σ(e)∗(n)
τ(e)∗(n) ≤ σ(e)∗(n) +τ(e)∗(n)
2·τ(e)∗(n) ≤ n+ 1 2 for everyn, k∈Nwith n≥1.
Remark 4 From inequality(19), we deduce another simple inequality, namely
(20) σ(e)∗(n)
τ(e)∗(n) ≤n for everyn≥1.
Theorem 3 For everyn, k, l∈Nwithn≥1, there are the following relations:
σ(ke)(n)·σl(e)(n)≤τ(e)(n)·σk(e+)l(n), (21)
σk(e)(n)
σl(e)(n) ≥ σ(e)(n) τ(e)(n)
!k−l
≥τk−l(n), (22)
σk(e+1) (n)
σ(ke)(n) ≥τ(n) (23)
and
(24) σk(e+1) (n)
σk(e)(n) ≥ σ(e)(n)
τ(e)(n) ≥τ(n)
Proof. For n= 1, we obtain equality in the relation above.
Letn=pa11pa22...parr >1. We apply Chebyshev’s Inequality for oriented system and, we deduce the inequality
σ(ke)(n)·σl(e)(n) = X
d|(e)n
dk· X
d|(e)n
dl≤τ(e)(n) X
d|(e)n
dk+l=τ(e)(n)σ(ke+)l, so
σk(e)(n)·σ(le)(n)≤τ(e)(n)·σ(ke+)l(n).
From [1], we shall use the inequality ak1+ak2 +...+akn
al1+al2+...+aln
≥
a1+a2+...+an
n
k−l ,
for every a1, a2, ..., an > 0 and for all k, l ∈ N with k ≥ l, and by replacing a1, a2, ...,with the exponential divisors ofn, we obtain the following inequality:
X
d|(e)n
dk X
d|(e)n
dl ≥
X
d|(e)n
d τ(e)(n)
k−l
which is equivalent to
σ(ke)(n)
σ(le)(n) ≥ σ(e)(n) τ(e)(n)
!k−l .
We know from [5] that σ(e)(n)
τ(e)(n) ≥τ(n) and from the inequality σk(e)(n)
σl(e)(n) ≥ σ(e)(n) τ(e)(n)
!k−l
, we deduce an interesting inequality, namely σ(ke)(n)
σ(le)(n) ≥τk−l(n).
We observe that making the substitution k→k+ 1 and l→k in inequality σ(ke)(n)
σ(le)(n) ≥ σ(e)(n) τ(e)(n)
!k−l , we have
σk(e+1) (n)
σk(e)(n) ≥τ(n).
If we assign values ofk from 1 tok−1, we have the following relations:
σ(ke)(n) ≥ τ(n)σ(ke−)1(n), σ(ke−)1(n) ≥ τ(n)σ(ke−)2(n),
...
σ(2e)(n) ≥ τ(n)σ(1e)(n),
and taking the product of these relations, we deduce the inequality σk(e)(n)≥τk−1(n)σ(e)(n)≥τk(n)τ(e)(n).
Therefore, we obtain
σ(ke)(n)≥τk(n)τ(e)(n).
In relation σ(ke)(n)
σ(le)(n) ≥ σ(e)(n) τ(e)(n)
!k−l
, making the substitutions k→k+ 1 and l→k, we obtain the inequality
σ(ke+1) (n)
σk(e)(n) ≥ σ(e)(n)
τ(e)(n) ≥τ(n).
Theorem 4 For everyn, k, l∈Nwithn≥1, there are the following relations:
σk(e)∗(n)·σ(le)∗(n)≤τ(e)(n)·σ(ke+)∗l(n), (25)
σk(e)∗(n)
σl(e)∗(n) ≥ σ(e)∗(n) τ(e)∗(n)
!k−l
≥τk−l(n), (26)
σk(e+1)∗(n)
σk(e)∗(n) ≥τ(n) (27)
and
(28) σ(ke+1)∗(n)
σ(ke)∗(n) ≥ σ(e)∗(n)
τ(e)∗(n) ≥τ(n).
Proof. We make the same proof as in Theorem 3, by repacing the exponential divisors with the e-unitary divisors.
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Nicu¸sor Minculete
”Dimitrie Catemir” University of Bra¸sov Str. Bisericii Romˆane, no. 107
Bra¸sov, Romˆania
e-mail: [email protected] Petric˘a Dicu
”Lucian Blaga” University of Sibiu Str. Dr. I. Rat¸iu, no. 5-7
Sibiu, Romˆania
e-mail: [email protected]