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Lemma 1. For t ∈ O(V ) and 0 6= α ∈ V , we have ts α t −1 = s tα . Theorem 2. W = hs α | α ∈ ∆i.

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June 27, 2016

For today’s lecture, we let V be a finite-dimensional vector space over R, with positive- definite inner product. Let Φ be a root system in V with simple system ∆. and let W = W (Φ) = hs α | α ∈ Φi. Let Π = Φ ∩ R ≥0 ∆ be the unique positive system in Φ containing ∆.

Lemma 1. For t ∈ O(V ) and 0 6= α ∈ V , we have ts α t −1 = s tα . Theorem 2. W = hs α | α ∈ ∆i.

Definition 3. For w ∈ W , we define the length of w, denoted `(w), to be

`(w) = min{r ∈ Z | r ≥ 0, ∃α 1 , . . . , α r ∈ ∆, w = s α

1

· · · s α

r

}.

By convention, `(1) = 0.

Lemma 4. For w ∈ W and α ∈ ∆, the following statements hold:

(i) wα > 0 = ⇒ `(ws α ) = `(w) + 1.

(ii) wα < 0 = ⇒ `(ws α ) = `(w) − 1.

Theorem 5. Let α 1 , . . . , α r ∈ ∆ and w = s 1 · · · s r ∈ W , where s i = s α

i

for 1 ≤ i ≤ r. If

`(w) < r, then there exist i, j with 1 ≤ i < j ≤ r such that w = s 1 · · · s i−1 s i+1 · · · s j−1 s j+1 · · · s r . Notation 6. For w ∈ W , we write

n(w) = |Π ∩ w −1 (−Π)|.

Corollary 7. If w ∈ W , then n(w) = `(w).

Theorem 8. The group W (Φ) acts simply transitively on P (Φ) and S(Φ).

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Notation 9. Let S = {s α | α ∈ ∆}. For I ⊂ S, we define

W I = hIi,

∆ I = {α ∈ ∆ | s α ∈ I}, V I = R∆ I ,

Φ I = Φ ∩ V I , Π I = Π ∩ V I .

Proposition 10. Let I ⊂ S.

(i) Φ I is a root system with simple system ∆ I .

(ii) Π I is the unique positive system of Φ I containing the simple system ∆ I . (iii) W (Φ I ) = W I .

(iv) Let ` be the length function of W with respect to ∆. Then the restriction of ` to W I coincides with the length function ` I of W I with respect to the simple system ∆ I .

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