New Contractive Conditions Of Integral Type And Fixed Point Theorems In Cone Metric Space Deepak Kumar
Faculty of Mathematics, Govt. Post Graduate College, Ambala Cantt.-133001, Haryana (India) E-mail: [email protected]
Abstract: The aim of this paper is to extend the concept of F. Khojasteh, Z. Goodarzi and A. Razani to some new contractive conditions of integral type in cone metric space.
[Kumar, D. New Contractive Conditions Of Integral Type And Fixed Point Theorems In Cone Metric Space.
Academ Arena 2019;11(7):8-14]. ISSN 1553-992X (print); ISSN 2158-771X (online).
http://www.sciencepub.net/academia. 2. doi:10.7537/marsaaj110719.02.
Key words: Cone Metric Space, Contractive Conditions, Fixed Point.
1. Introduction:
The concept of cone metric space was introduced by Huang and Zhang [1] in 2007 and some fixed point theorems was proved. Initially Branciari [2]
introduced the contractive condition of integral type and extended Banach fixed point theorem. Later on F.
Khojasteh, Z. Goodarzi and A. Razani [3] gave the concept of cone integrable function and proved Branciari’s theorem in cone metric space. The aim of
this paper is to extend the concept of [3], to some new contractive conditions of integral type in cone metric space.
The following definitions and lemmas are useful for us to prove the main results.
Definition 1.1[1]: Let Ε be a real Banach space and P a subset of Ε
. P is called a cone if the following hold.
(1) P is closed, non-empty and P 0 .
(2) If a,bR and a,b 0, then axbyP, x, yP. (3) xP and xP implies x0.
Let PΕ be a cone. We define a partial ordering with respect to P as x y
if and only if yxP and y
x will imply that x y but xy, while x y will mean that yxintP, where intP denotes
the interior of P.
The cone P is called normal if there is a numberM 0 such that 0 x y implies x M y
Ε
x, y . The least positive number M is called the normal constant.
Example: Suppose ΕR2
, Px, yΕ x, y0
. X R. Let d :XX Ε be defined as
x y bx y x y
d , ,
where bR and b 0. Then X, d
is cone metric space.
Definition 1.2[1]: Let X, d be a cone metric space and let xn
be a sequence in X. Then (1) xn
is said to converges to some x X if for every cΕ with 0 c, a natural number N such that n N , dxn, xc
. (2) xn
is said to be Cauchy sequence if for every cΕ with 0 c, a natural number N such that N
n
m
, , dxn, xmc
. x,yP (3) A cone metric space X, d
is complete if every Cauchy sequence is convergent.
Definition 1.3[3]: Let P be a normal cone in Ε
and , Ε where . Then we define
,xΕ:s 1s,s0,1,
, xΕ:s1s, s0,1.
Definition 1.4[3]: The set P1 x0, x1,x2,...,xn
is called a partition of , if and only if the sets xj xjnj
1, 1
are pairwise disjoint and ,nj1xj1, xj
. Definition 1.5[3]: Let P1 x0, x1, x2,..., xn
be a partition of ,
and , P
be an increasing function. We define cone lower sum and cone upper sum as
1
1
0
, 1
j j j
n
j con
n P x x x
L
,
1 1
1
0
, 1
j j j
n
j con
n P x x x
U
, respectively.
The function is called cone integrable function on , if and only if for all partitions P1 of ,
, 1 lim , 1
limL P S Uncon P
n con con
n n
, where Scon is unique. We shall write Scon dp
or t dp t
.
Lemma 1.1[3]: If , , then dp dp
for 1X, P
a1 b2dp a 1dp b 2dp
for 1,21X, P and a, bR
where 1X, P
denotes the set all cone integrable functions.
Definition 1.6[3]: A function :PΕ is said to be subadditive cone integrable function if and only if P
,
dp dp
dp
0 0 0 .
2. Main Results:
Theorem 2.1: Let X, d
be a complete cone metric space with normal cone P. Let : P P be a nonvanishing and subadditive cone integrable map on each , Pfor which 0
0
dp , 0. Let
X X
T : be a mapping such that
dp c
dp d xT y d yT x
y T x T
d
0 , ,
,
0 for each
2
, 1 0 ,
, y X c
x
. Then T has a unique fixed point in X.
Proof: Let xX, choose x1X
such that x1 T x
. Let x2X
be such that x2 T x
. Continuing in this way we can define xn Txn1Tn x
for n1,2,3,...
dp
dp n n
n
n x dT x T x
x
d
1 0 , 1
, 0
dp cd xn xnd xn xn
, 1, 1
0
dp cd xn xn
1, 1
0
But dxn1,xn1 dxn1,xndxn,xn1
, therefore
n dp
n x
x
d
0 ,
1
dp cd xn xnd xnxn
1, , 1
0
Since is cone subadditive, so
dp c
dp c
dp n n n n
n
n x d x x d x x
x
d
1 1 0 , 1
, 0 ,
0
dp k
c dp
dp c n n n n
n
n x d x x d x x
x
d
1 1 0 , 1
, 0 ,
0 1 , where c
k c
1
dp kn d x x
1,0
0
dp k
dp n dT x x
x x
d n n
0 ,
, 0
1
Since 0k 1, and 0
0
dp for each 0, so
0
lim ,
0
1
d xn xn dp
n
, which implies, that lim n1, n0
n d x x
. To show xn
is Cauchy sequence, we shall show that lim , 0
n n
n d T x T x
for each positive integer
.
Let 0 be any integer. By triangular inequality
xn xn dxn xn dxn xn dxn xn
d , , 1 1, 2 ... 1,
dp
dp n n n n
n
n x d x x d x x
x
d
0 , ... , ,
0
1 1
dp dp
dp n n n n n n
n
n T x dx x dx x d x x
x T
d
0 , ... ,
, 0 ,
0
1 1
1
Since is cone subadditive
dp dp
dp d x x d x x
x x
d n n n n n
1 1 2 1,1
0 ,
0 ,
0 ...
kn kn kndx x dp
1, 0
0 2
1 ...
knkn kn kn dT x x dp
,
0 1 2
1 ...
k dp kn dT x x
,
1 0
Letting n,
0
lim ,
0
1
dT xn T xn dp
n
. Which implies that lim , 0
n n
n d T x T x
for each positive integer .
Hence xn
is a Cauchy sequence. Since X is complete cone metric space so xn
is convergent to some X
z . i.e. xn z
n
lim
.
dp
dp n
n dT z T x
x z T
d
0 ,
, 0
1
dp c d zxn d xnT z
, ,
0
1
dp c
dp
c d zxn d xnT z
,
0 ,
0
1
As n
dp c
dp d zT z
z z T
d
0 ,
, 0
which implies that dT z ,z0 i.e. T z z. Thus z is a fixed point of T.
Uniqueness: Let T has two fixed point z and w i.e. T z z and T w w.
dp c
dp
dp dT z T w d zT w dwT z
w z
d
0 , ,
, 0 ,
0
dp c
dp
c d zw d wz
,
0 ,
0
c dp dp c d zw
w z
d
0 ,
,
0 1
dp kd zw
,
0 where c
k c
1
Which implies that dz, w0 i.e. zw. This shows that T has a unique fixed point in X.
Theorem 2.2: Let X, d
be a complete cone metric space with normal cone P. Let : P P be a nonvanishing and subadditive cone integrable map on each , Pfor which 0 dp 0, 0. Let
X X
T : be a mapping such that
dp b
dp a
dp d xy d yT x
y T x T
d
0 ,
, 0 ,
0 . For a,bR s.t. a 12b and 2
0b 1
. Then T has unique fixed point.
Proof: Let xX, choose x1X such that x1 T x . Let x2X be such that x2 T x . Continuing in this way we can define xn Txn1Tn x
for n1,2,3,...
dp
dp n n
n
n x dT x T x
x
d
1 0 , 1
, 0
dp b
dp
ad xnxn d xn xn
1 1, 1
0 ,
0
Using triangle inequality and cone subadditivity,
dp b
dp b
dp
ad xnxn d xn xn d xn xn
1 1 , 1
0 ,
0 ,
0
dp k
b dp b
dp a n n n n
n
n x d x x d x x
x
d
1 1 0 , 1
, 0 ,
0 1 , where b
b k a
1
dp k
dp k
dp n d x x n dT x x
x x
d n n
0 ,
, 0 ,
0
0 1 1
Since
1 1
b
b k a
then as n,
0
lim ,
0
1
d xn xn dp
n
Which implies that lim n1, n0
n d x x
. It is easy to show that xn
is a Cauchy sequence (See previous theorem). Since X is complete cone metric space so there is some zX such that
z xn
n
lim
.