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192 Proc. JapanAcad., 71, Ser.A (1995) [Vol. 71(A),

A Recurrence Formula for the Bernoulli Numbers

By

Masanobu KANEKO

Departmentof Liberal Arts and Sciences, KyotoInstitute of Technology (Communicated by Shokichi IYANAGA,M.J. A.,Oct. 12, 1995)

1. The theorem.

Let B, (n 0,1,2

be the Bernoulli numbers defined by the formal power series

x

=B,,X

x

!

e

1

=0

and put

/n-’- (n "+" 1)Bn. As

is well known and easily seen,

/1 1

and

/n-

0 for all odd in- tegers

>--3. In

this note we present the following recurrence relation.

Theorem. The

n’s

satisfy

1

l(n+ 1)/n+ (n> 1)

(1) B,= n+ 1

=o

Remark. The formula has a strong resembl- ance to the usual recurrence

B,= +1

--o

B

(see

[21

for example) but needs half the number of terms to calculate

B.,.

We

shall give two proofs. The first proof uses a continued fraction expansion and its con- vergents of the defining power series of

B,.

This method faithfully traces our original way of dis- covering the formula and seems to apply to sear- ching similar kinds of formulas for various num- bers defined by nice generating functions. The second and much simpler proof is due to

Don

Zagier, to whom the author expresses his grati- tude for permitting him to include the proof in the paper.

2.

Convergents

of continued fraction expan-

sion.

Let f(x) 1+ cx+ cx +

be a

formal power series

(over

some field) with con- stant term 1.

Suppose f(x)

has a continued frac- tion expansion

1

ax a.x ax

(2) f(x) 1+ 1+

1+ 1+

with non-zero

ai’s

and let

Q,(x) 1 a,x a,_,x

P,,(x) 1+ 1+

l

+ a,,x

be its n-th convergent. The polynomials

P,(x)

and

Qn(x)

are uniquely determined from

f(x)

by the following conditions:

(3) P, (0) Q, (0)

1.

(4) deg P,,(x) deg Q,,(x) rn

if n =.

2m, deg P,,(x) deg Qn (x) +

1 m

+ 1

ifn

2m + 1

(5) f(x) Q.(x)/P.(x) mod

xn+l

(in the ring of formal power series).

Both

P(x)and Qn (x)

satisfy the same re-

currence relations

(6) P. (x) P_ (x) + axP._ (x) V,(x) Vn_l(X) + anxV,,_z(x) (n >_ 2)

with the initial conditions

Po- 1, Pl-- 1

alX’

Qo QI

1.

Now

we put

f(x) (//2) coth ((/2),

where cothy

(e-+ e-)/(e - e-).

This is a

generating function of even index Bernoulli num- bers:

f(z) Z B,.,

=o

(2n)

In

this case, the coefficients

a

in

(2)

are

given by

a 1/12,

(4+ 1))anda,+

4

(2;)/(12(4+4))

4

(--> 1).

This can be deduced from the famous expansion

tanh / 1

x x

/

1+3+5+

with the aid of a formula for the inverse of a given continued fraction expansion

([3,

p.

332]),

but we omit the details here. The key point of our proof of the theorem lies in the explicit de- scription of the convergents of the continued frac- tion expansion

off(x) (-- (v/2) coth((/2)).

Lemma.

With the notations asabove, we have

_> 0)

,0 2i 2i (2i+1)

m

P2m-1 (X)

2

Z (2m-

2i-

1)(2m +

i)

m(4m

2i+1

- 1)

2i+1i=o (2i+1)!

(m__>l)

Q.m(X) , (m > O)

=o 2i 2i

(2i)!

(2)

No. 8] RecurrenceFormula forBernoulli Numbers 193

Q.m_l (X)

1

Z (m-

i)(4m

+

2i-

1)

m

(4

m

1)

(2m+i)(4m)

2i 2i -1 (2i)

x (m

2

1).

Proof E.

Heine

[1,

p.

245]

gave the conver- gents of the continued fraction expansion of

1/f(x).

Taking the properties

(4)

and

(5)

of the convergents into account, we see that the

2m-th

convergent for

l/f (x)

is just the inverse of that for

f(x),

i.e.

P(x)/Q(x),

thus we obtain the formula for

P(x)and Qeu(x).

Thanks to the recurrence

(6),

odd index

P’s

and

Q’s

are calcu- lated from even index ones and the lemma fol- lows.

3. Proof of the theorem.

By

the approx- imation property

(5),

we have

(7) B

(2i)

P. (x) .(x) mod x

and

2n- X 2n

(s) mod

x

2n 2n-

Equating the coefficients of x

x

of

(7)

and x2n-1 of

(8)

by using

Lemma,

we get respectively

1

(2n+1)+(n>1)

(9) 4

2n

+

1 =o 2i

1 --1

(10) 4.- 4n(2n + 1)(4n + 1)

i=O

(2n +

2i

+ 1)(2n + 2i)( 2n 2i + 1

--1

) + - (n > 2)

() ,_=_

1

(2i-1)

2n(4n -

2i

1)

=o

-

Multiplying

(10)

by

4(2+ 1)(4+ 1), (11)

by

4(4 - 1)

and

1 (

adding

2n

them

)2n+2i_2(n>

give us

2)

(12) B4n_ 2n

=

2i-- 1

or

(13) /4+2 2n+2

1

1(2n+2)

=0 2i+

1

.++ (n _> 1).

We

can unify (9.),

(13)

and

B

1/2 into

(1)

in the theorem (recall that

1 1

and

Bodd__3

0),

hence completes the proof.

4. Another proof. The simple proof sket- ched below is due to

D.

Zagier.

In

general, define an involution

*

on the set

of sequences

{bo, bl, b2,...}

by

B* (x) e-XB( x)

where

B(x)

is the following generating function:

Xn

B(x) =o bn (n 1)!"

(

i.e., by

b- (-- 1) =o , (n+l))

i+ 1

b.

Then

the expression

is seen to be anti-invariant under

*

and hence

vanishes if

B*() B().

This is the case when

B() /(e x- 1),

thus we have

Replacing n by n 1 and observing

B+-

0,

we getthe theorem.

5. Acknowledgement. This work was done during the author’s stay in Cologne,

Germany

in

1993/94. He

is very grateful to Prof.

Peter

Schneider and the Alexander von Humboldt Foundation for their hospitality and support.

[11

12]

[3]

References

Heine, E.: Ueber die Zaehler und Nenner der Naeherungswerthe von Kettenbruechen.Jour. fuer die reine undangew. Math., 57 231-247 (1860).

Ireland, K. and Rosen, M.: A Classical Introduc- tion to Modern Number Theory. 2nd ed., Sprin- ger, GTM 84 (1990).

Perron, O.: Die Lehre yon den Kettenbruechen.

Teubner (1929).

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