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New York Journal of Mathematics

New York J. Math.1(1995) 184{195.

A Non-quasiconvex Subgroup of a

Hyperbolic Group with an Exotic Limit Set

Ilya Kapovich

Abstract. We construct an example of a torsion free freely indecomposable nitely presented non-quasiconvex subgroupH of a word hyperbolic groupGsuch that the limit set ofH is not the limit set of a quasiconvex subgroup of G. In particular, this gives a counterexample to the conjecture of G. Swarup that a nitely presented one-ended subgroup of a word hyperbolic group is quasiconvex if and only if it has nite index in its virtual normalizer.

Contents

1. Introduction 184

2. Some Denitions and Notations 185

3. The Proofs 187

References 195

1. Introduction

A subgroupH of a word hyperbolic groupGis quasiconvex (or rational) inGif for any nite generating setAof Gthere is >0 such that every geodesic in the Cayley graph ;(GA) ofGwith both endpoints inH is contained in-neighborhood ofH. The notion of a quasiconvex subgroup corresponds, roughly speaking, to that of geometric niteness in the theory of classical hyperbolic groups (see Swa], KS], Pi]). Quasiconvex subgroups of word hyperbolic groups are nitely presentable and word hyperbolic and their nite intersections are again quasiconvex. Non- quasiconvex nitely generated subgroups of word hyperbolic groups are quite rare and there are very few examples of them. We know only three basic examples of this sort. The rst is based on a remarkable construction of E. Rips R], which allows one, given an arbitrary nitely presented group Q, to construct a word hyperbolic groupGand a two-generator subgroupH ofGsuch thatH is normal in G and the quotient is isomorphic to Q. The second example is based on the existence of a closed hyperbolic 3-manifold bering over a circle, provided by results of W. Thurston and T. Jorgensen. The third example is obtained using the result

Received June 15, 1995.

Mathematics Subject Classication. Primary 20F32 Secondary 20E06.

Key words and phrases. hyperbolic group, quasiconvex subgroup, limit set.

This research is supported by an Alfred P. Sloan Doctoral Dissertation Fellowship

c

1995StateUniversityofNewYork

ISSN1076-9803/95

184

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of M. Bestvina and M. Feign BF] who proved that ifF is a non-abelian free group of nite rank and is an automorphism of F without periodic conjugacy classes then the HNN-extension ofF alongis word hyperbolic.

If G is a word hyperbolic group then we denote the boundary of G (see Gr], GH] and CDP]) by@G. For a subgroupH of Gthe limit set@G(H) of H is the set of all limits in@Gof sequences of elements ofH.

In this note we construct an example of a non-quasiconvex nitely presented one-ended subgroup H of a word hyperbolic group G such that the limit set of H is exotic. By exotic we mean that the limit set of H is not the limit set of a quasiconvex subgroup ofG. This result is of some interest since in the previously known examples non-quasiconvex subgroups were normal in the ambient hyperbolic groups and thus (see KS]) had the same limit sets. Our subgroupH also provides a counter-example to the conjecture of G. A. Swarup Swa] which stated that a nitely presented freely indecomposable subgroup of a torsion-free word hyperbolic group is quasiconvex if and only if it has nite index in its virtual normalizer (this statement was known to be true for 3-dimensional Kleinian groups). The subgroup H, constructed here, coincides with its virtual normalizer. Here, by the virtual normalizer of a subgroupH of a groupGwe mean the subgroup

V NG(H) =fg2G j jH :H\gHg;1j<1jgHg;1:H\gHg;1j<1g:

2. Some Denitions and Notations

A geodesic in a metric space (Xd) is an isometric embedding : 0l] ! X where l 0 and 0l] is a segment of the real line. We say that a metric space (Xd) is geodesic if any two points ofX can be joined by a geodesic path inX. A path : 0l] !X is called -quasigeodesic if it is parametrized by its arclength and for anyt1t220l]

jt1;t2j d((t1)(t2)) +: Ifxy andzare points in a metric space (Xd) we set

(xy)z= 12(d(zx) +d(zy);d(xy)):

The quantity (xy)z is called the Gromov inner product of xandywith respect to z.

Let be a triangle in a metric space (Xd) with geodesic sides , and and verticesxyz. (See Figure 1.)

We say that the points pqr on , and are the vertices of the inscribed trianglefor ifd(xp) =d(xr) = (yz)x, d(yp) =d(yq) = (xz)y andd(zr) = d(zq) = (xy)z. In this situation is called-thin if for eacht20d(xp)]

d(p0r0)

where p0r0 are points on , with d(xp0) = d(xr0) = t and if the symmetric condition holds fory andz.

A geodesic metric space (Xd) is called -hyperbolic if there is0 such that all geodesic triangles are-thin.

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x

p

r

z p’

y

γ

β α

q

r’

Figure 1

If G is a nitely generated group and G is a nite generating set for G, we denote the Cayley graph ofGwith respect to G by ;(GG) and denote bydG the word metric on ;(GG). Also, for any g 2 G we dene the word length of g as lG(g) =dG(1g). It is easy to see that (;(GG)dG) is a geodesic metric space. Ifw is a word in the generatorsG, we denote bywthe element ofGwhichwrepresents.

A nitely generated groupGis called word hyperbolic if for each nite generating setGforGthere is0 such that the Cayley graph ;(GG) with the word metric dG is-hyperbolic.

A subgroup H of a word hyperbolic group G is called quasiconvex in G if for some (and therefore for any) nite generating set G ofG there is >0 such that every geodesic in the Cayley graph ;(GG) of Gwith both endpoints inH lies in the-neighborhood ofH.

If G is a word hyperbolic group with a nite generating set G, we say that a sequence of pointsfgn2Gjn2Ng denes a point at innityif

nlim!1ijinf

n(gigj)1=1

where the Gromov inner product is taken in dG-metric. Two sequences (an)n2N

and (bn)n2N dening points at innity are called equivalent if

nlim!1ijinf

n(aibj)1=1:

The boundary@GofGis dened to be the set of equivalence classes of sequences dening points at innity. Ifa2@Gis the equivalence class of a sequence (an)n2N, we say that (an)n2N converges toaand write limn

!1

an =a. The boundary @Gcan be endowed with a natural topology which makes it a compact (and metrizable) space. It turns out that the denition of@Gand the topology on it are independent of the choice of the word metric forG. Moreover,Gacts on@Gby homeomorphisms and the action is given byg limn!1an = limn!1gan where g2Gand (an)n2N

denes a point at innity. IfS is a subset of G(e.g., a subgroup ofG), we dene the limit set@G(S) to be the set of limits in@Gof sequences of elements ofS.

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3. The Proofs

Proposition A.

LetF be the fundamental group of a closed hyperbolic surfaceS. Letbe an automorphism of F induced by a pseudo-anosov homeomorphism of S. TakeGto be the mapping-torus group of , that is

G=hFtjtft;1=(f) f2Fi:

Letx2F be an element which is not a proper power in F (and so, obviously,x is not a proper power in G). LetG1 be a copy of G. The group G1 contains a copy F1 of F and a copyx1 ofx. Set

M=Gx

=x1G1 (1)

andH =sgp(FF1).

Then1. M is torsion-free and word hyperbolic.

2. H is nitely presented, freely indecomposable and non-quasiconvex in M.

Proof.

The groupGis torsion free and word hyperbolic since it is the fundamental group of a closed 3-manifold of constant negative curvature (see Th]). Thus, M is word hyperbolic by the combination theorem for negatively curved groups (see BF], KM]). Notice that H = sgp(FF1) = F x

=x1F1 and so H is torsion-free, nitely presentable and freely indecomposable. Moreover,H is word hyperbolic by the same combination theorem.

SupposeH is quasiconvex in M. It is shown in BGSS] thatF is rational with respect to some automatic structure onH sinceH =FCF1whereC=hxi=hx1i is cyclic. Therefore,F is quasiconvex in H (see, for example, Swa]). Thus, since H is quasiconvex inM andF is quasiconvex inH, the subgroupF is quasiconvex in M. However,F is innite and has innite index in its normalizer inM, which (see KS]) implies thatF is not quasiconvex in M. This contradiction completes the proof of Proposition A.

Theorem B.

LetG,G1,M, andH be as in Proposition A. LetK be the limit set

@M(H) of H in the boundary @M ofM. Then

H =StabM(K) =ff 2MjfK=Kg:

Before proceeding with the proof, we choose a nite generating setG forGand its copy G1. Then G denes the word length lG and the word metric dG for G. Analogously,GG1 is a nite generating set forM =GCG1 which denes the word length lM and the word metric dM on M. Fix a > 0 such that all dM- geodesic triangles are-thin. We also denote by C the subgroup of M generated byx=x1. The elementx=x1will sometimes be denoted byc. ThusM =GCG1 and H = F CF1. We need to accumulate some preliminary information before proceeding with the proof of Theorem B.

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h

x

z y u

u

v V

V

i

i j i

j j

vj

Ui

U

V v

w U

u

1

hk

Figure 2

Lemma 1.

LetA be a word hyperbolic group with a xed nite generating set S. LetH andK be quasiconvex subgroups ofA such that for every a2A

aHa;1\K=f1g

Then there is a constantr0>0 such that for everyh2H andk2K lA(hk)r0 lA(k)

Proof.

Fix a nite generating set H for H and a nite generating setK for K. SinceK andH are quasiconvex inA, there is >0 such that every geodesic 1h], h2H in the Cayley graph ofAlies in the-neighborhood ofH and every geodesic 1k], k2K lies in the-neighborhood ofK. Also, there is >0 such that every dH-geodesic (dK-geodesic) word denes a -quasigeodesic in the Cayley graph of A.

Let h 2 H and k 2 K. Fix dG-geodesic representatives uvw of h, k and hk respectively. Also, x a dH-geodesic representative U of h and adK-geodesic representativeV ofk. Consider the geodesic triangle in the Cayley graph ofA with sidesuvw(see Figure 2).

Consider the inscribed trianglexyz in the triangle (see Figure 2). It has the following properties:

1. dA(1x) =dA(1z),dA(hx) =dA(hy),dA(hky) =dA(hkz)

2. the segment 1u] of U is -uniformly close to the segment 1z] of w and similar conditions hold for the other two corners of in particular, dA(xy) dA(xz) dA(yz).

We claim thatdA(xh) =dA(yh) is small. More precisely, let N be the num- ber of words in the generating set of A of length at most + 2+ 2. Suppose dA(hu)>4(+ 1)(N+ 1). Then there is a sequence of verticesu1:::uN+1 on the segment of u between x and h such that dA(ukus) = 4(+ 1)jk;sj. For

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each k = 1:::N + 1 there is a vertex Uk on U such that dA(Ukuk) + 1.

Note that whenk6=s,dA(UkUs)4(+ 1)jk;sj;2(+ 1)2(+ 1)>0 and therefore all the verticesU1:::UN+1 represent dierent elements of A. Also, for everyk = 1:::N+ 1 there is a unique vertex vk on the segment of V between handy such thatdA(huk) =dA(hvk). Note that since the triangle is-thin, we havedA(ukvk),k= 1:::N+ 1. Finally, for everyk= 1:::N+ 1 there is a vertexVk ofV such that dA(vkVk)+ 1. Thus dA(UkVk)+ 2(+ 1), k= 1:::N+1. For eachkwe choose adA-geodesic path k fromUk toVk in the Cayley graph ofA. By the choice ofN there arei < j such that i= j= . Put a= . Thena;1h0a=k0 where h0 2H is the element represented by the segment of U from Uj to Ui and k0 2 K is the element represented by the segment of V fromVi toVj. Sinceh0 6= 1, this contradicts our assumption that any conjugate of H intersectsK trivially. Thus we have established that

dA(hu)4(+ 1)(N+ 1) =r

Therefore l(w) dA(zkh) = dA(vkh) l(v);r and lA(hk) = l(w) min(1=21=r) l(v) = min(1=21=r) lA(k) which concludes the proof of Lemma 1.

Corollary 2.

LetAbe a word hyperbolic group with a xed nite generating setA and letabbe elements of innite order inA such that no nontrivial power of ais conjugate inAto a power ofb. Then there is a constant r1>0 such that for every mn2Z

lA(ambn)jnj r1

Proof.

This directly follows from Lemma 1 and the fact that cyclic subgroups of word hyperbolic groups are quasiconvex ABC].

Lemma 3.

Assume that conditions of Theorem B are satised. Let p 2 C or p= p1:::ps be a strictly alternating product of elements of G;C and G1;C, whereps2G1;C. Let y 2Gbe such that no power of y is conjugate in G to a power ofx. Then there is a constantD >0 such that for every n2Z

lM(pyn)D jnj

Proof.

Note that if p 2 C, then, since every conjugate of C in G intersects hyi trivially, Corollary 2 implies that

lG(pyn)r1 jnj

for some constantr1 >0 independent of pn. Theorem D of BGSS] implies that GandG1 are quasiconvex inM. Therefore there is a constantr >0 such that for everyg2G

lM(g)r lG(g) and therefore

lM(pyn)r r1 jnj

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From now on we assume thatp62Cthat is p=p1:::ps is a strictly alternating product of elements of G;C and G1;C with ps2G1;C. To prove Lemma 3 in this case, recall that by the theorem of G. Baumslag, S. Gersten, M. Shapiro, and H. Short BGSS], cyclic amalgamations of hyperbolic groups are automatic. In the proof of this theorem they construct an actual automatic language for a cyclic amalgam of two hyperbolic groups, which, therefore, consists of quasigeodesic words (see ECHLPT], Theorem 3.3.4). We will explain how their procedure works in the case of the group M = GCG1 (we use the fact that dG jC= dG1 jC). Fix a lexicographic order on the generating setG of Gand a copy of this order on the generating setG1 ofG1. We will say that adG-geodesic word uis minimal in the coset classuC iflG(u) lG(u c) for every c 2 C and wheneverl(u) = l(u0) for somedG-geodesic wordu0withu02uC thenuis lexicographically smaller thanu0. It is clear that any coset class gC, g 2G has a unique minimal representativeu. Similarily, one denes minimal representatives for coset classesg1C,g12G1.

Theorem D of BGSS] provides an explicit construction of an automatic language Lin the alphabet M=GG1 forM such that everye2M has a unique repre- sentative inL. Note that, in general, Theorem D of BGSS] gives a construction of such an automatic language forMin a bigger alphabet thanGG1. More precisely, they need to nd rst a generating setG0 containingG forGand a generating set

G

1

0 containingG1 forG1 such that for some constant1>0

jlG0(c);lG10(c)j1 for everyc2C:

Then they construct the automatic language forM in the alphabetG0G10. How- ever, by the choice ofM we already have

lG(c) =lG1(c) for everyc2C

and so the BGSS] procedure gives us an automatic language L with uniqueness in the alphabetGG1. (Although an automatic group has an automatic language over every nite generating set of this group, in this particular case we need not just the fact that M is automatic and possesses an automatic language over M but, rather, the fact thatM has an automatic language overM with some very particular properties given by the BGSS] construction). We will now describe how, given an elemente2M, one can nd its representative inL.

Supposee2M. Ife2C, thene=xk and we take adG-geodesic representative of xk to be the representative of e in the automatic languageL for M. Suppose e62C. First, writeeas a strictly alternating product of elements from

e=e1:::ej

of elements fromG;CandG1;C. Then expresse1ase1=w1cn1 wherew1is the minimal representative in the coset classe1C. Then expresscn1e2ascn1e2=w2cn2 where w2 is the minimal representative in the coset class cn1e2C. And so on for i= 12:::j;1. Finally, we expresscnj;2ej;1 aswj;1cnj;1 where wj;1 is the minimal representative in the coset classcnj;2ej;1C.

We put wj to be the lexicographically minimal among all dG-geodesic (dG1- geodesic) representatives ofcnj;1ej. As a result we obtain the word w=w1:::wj

such thatw=e. This wordwis the required representative ofein L.

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Note that in the casee62Cwe havew1C=e1C,Cwj =Cej andCwiC=CeiC for 1 < i < j. Note also that there is >0 such that all words in L dene - quasigeodesics in the Cayley graph ofM. This, in particular, means that for every w2L

l(w) lM(w) +:

Suppose now thatpand y are as in Lemma 3 and n2 Zn6= 0. We will nd the representativewofpynin the automatic languageLonM using the procedure described above. Note that hyi\hxi =f1gand so yn 2 G;C since C = hxi. Therefore p1:::psyn is a strictly alternating product of elements of G;C and G1;C. It is clear from the construction thatwhas the following form:

w=q1:::qsv where

1. qi is a dG-geodesic word when pi 2 G;C and qi is a dG1-geodesic word whenpi2G1;C

2. q1C=p1C andCqiC=CpiC wheni >1

3. v is adG-geodesic word andv=cyn for some c2C 4. w=p1:::psyn =pyn

Corollary 2 implies thatl(v) =lG(cyn)r1 jnjfor somer1>0 depending only onxyand independent ofn.

Therefore l(w) = l(q1:::qsv) l(v) r1 jnj. Since the language L consists of-quasigeodesics with respect todM, we conclude thatlM(pyn) l(w)

;

r1

jnj;which implies the statement of Lemma 3.

Lemma 4.

Suppose conditions of Theorem B are satised. Let u1:::um 62 H be a strictly alternating product of elements from G;C and G1;C such that um 2G1;C. Let p1:::ps be a strictly alternating product of elements of F ;C andF1;C. Letq0 belong toG1ifp12F;Candq0belong toGwhenp12F1;C (we allow q02C).

Then either q0p1:::psu1:::um ends (when rewritten in the normal form with respect to(1)) in the element of G1;C or q0p1:::psu1:::Aum2C.

Proof.

Indeed,um2 G1;C and soq0p1:::psu1:::umends (when rewritten in the normal form with respect to (1)) in the element ofG1;C unlessu;1m :::u;11 is a terminal segment ofq0p1:::ps that is eithermsand

ps;m+1:::psu1:::um2C (2)

or q0p1:::psu1:::um2C (3)

It is clear that (2) is impossible since ps;m+1:::ps 2 H = gp(FF1), C H andu1:::um62H. If (3) holds, we haveq0p1:::psu1:::um2Cas required. Thus Lemma 4 is established.

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Lemma 5.

Letz=u1:::um62H be a strictly alternating product of elements of G;C andG1;C such thatum2G1;C. Let y 2G be such that no nontrivial power ofy is conjugate inGto a power ofx=c. Then there is a constantK0>0 with the following property.

Letn2Zand h2H. Let v be a dM-geodesic from 1 to hand let u be a dM- geodesic from 1 to zyn. Take the vertex v(N) of v at the distance N from 1 and the vertexu(N) ofuat the distance N from1 (see Figure 3). Then

dM(u(N)v(N))K0 N:

Proof.

Recall thatH =sgp(FF1) =FCF1M =GCG1. Let >0 be such that any word from the automatic languageL on M denes a-quasigeodesic in the Cayley graph ofM.

Let ^ui be a dG-geodesic (dG1-geodesic) representative of ui, im. Let Y be a dG-geodesic representative ofy. Since the elementzis xed and the cyclic subgroup

hyi is quasiconvex inM, there is a constant1 >0 such that for everyk2Zthe word ^u1:::u^m;1u^mYk is a 1-quasigeodesic with respect to dM. In particular, U = ^u1:::u^m;1u^mYn is a 1-quasigeodesic representative of zyn with respect to dM. Put 2=max(1). Let >0 be such that any two2-quasigeodesics with common endpoints in the Cayley graph of M are-Hausdor-close. We will also assume that is such that for every k 2 Zand every point x0 on a dM-geodesic from 1 tozyk there is k02Z,k020k], such thatdM(x0zyk0).

Ifh2Candh;1 =xm, putp1=h;1 and letw1be adG-geodesic representative ofp1.

Ifh62C leth;1 =p1p2:::ps be the strictly alternating product of elements of F;C and F1;C. Note thatp1p2:::ps is also a strictly alternating product of elements ofG;C and G1;C. We then can nd the representativewof h;1 in the automatic languageLonM which was described in Lemma 3.

Clearly,w=w1w2:::ws, where

1. w1C=p1C andw1is minimal in the cosetw1C

2. forj < s CwjC=CpjC andwj is minimal in the cosetwjC 3. Cws=Cpsthat is ws=cpsfor some c2C

4. eachwi is adG ordG1-geodesic word.

Note that sincepj 2FF1 andCF,CF1, the conditions above imply that wj 2FF1forj = 1:::s.

Letv be adM geodesic from 1 tohand letube adM geodesic from 1 tozyn. AssumeN is a positive number such thatN l(v) andN l(u).

Letv(N) be the point on the geodesicv at the distanceN from 1. Letu(N) be the point on the geodesicuat the distanceN from 1 (see Figure 3).

Recall thatz=u1:::umandy are xed,um2G1;C. Recall further thatY is adG-geodesic representative ofy. By the choice ofthere is a vertexV(N) ofwand a vertexU(N) =zyk of U such that dM(u(N)U(N)), dM(v(N)V(N)) (see Figure 3). The segment S1 of w from V(N) to 1 is a terminal segment of w=w1:::ws, and it has the form

S1=qiwi+1:::ws

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v(N)

v V(N)

1

Y

Y

Y

Y

Y

Y u(N)

zyn

s

i+1

1

h

u

U(N)=zyk z

w

w

w

qi

Figure 3

where is and qi is a nonempty terminal segment of wi. The segmentS2 of U from 1 toU(N) is an initial segment of U = ^u1:::u^m;1u^mYn of the form

S2= ^u1:::u^m;1u^mYk

for some integer k 2 0n]. Notice that dM(1u1:::um;1u^myk) N ; and therefore

jkjlM(y)lA(yk)N;l(^u1:::^um;1u^m); and

jkj(1=lA(y))(N ;l(^u1:::u^m;1u^m);): Thus, for some constantK1>0 independent ofhn, we have

jkjK1 N:

By Lemma 4, either qiwi+1:::wsu1:::um 2 C orqiwi+1:::wsu1:::um ends in the element of G1 ;C, when rewritten in normal form with respect to (1).

Therefore, by Lemma 3, there is a constantD >0 independent ofh,nsuch that lM(qiwi+1:::wsu1:::umyk) =lM(S1S2)Djkj

and hence lM(qiwi+1:::wsu1:::umyk) K1 D N. It remains to recall that

jdM(u(N)v(N));lM(qiwi+1:::wsu1:::umyk)j 2to conclude that there is a constant K2 > 0 independent of hn such that dM(u(N)v(N)) K2 N. This completes the proof of Lemma 5.

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Proof of Theorem B.

Suppose z 2 StabM(K). We will show that z 2 H by induction on the syllable length ofz with respect to presentation (1). When the syllable length of z is 0, that is z 2 C, the statement is obvious. Suppose now that z 2 StabM(K);H, the syllable length of z is m > 0 and the statement has been proved for elements ofStabM(K) of smaller syllable length. Writez as a strictly alternating productz =u1:::um of elements fromG;C andG1;C. If um 2 F F1, then um 2 H \StabM(K), and so u1:::um;1 2 StabM(K).

Therefore, u1:::um;1 2H by the inductive hypothesis, um2 H, and so z 2 H. Thus,um2(G;F)(G1;F1). Assume for deniteness thatum2G1;F1, that is,um=f1tj1 for somej6= 0, f12F1.

Choosey 2F so that no power of y is conjugate in Gto a power of x. Fix a dG-geodesic representativeY ofy.

Let y+ = limn

!1

yn 2 @M. By denition of K we have y+ 2 K and therefore zy+2K. This means that for anyN >0 there is an elementh2H and a positive poweryn ofysuch that (hzyn)1> N, the Gromov inner product taken in thedM- metric. This means thatlM(h)N,lM(zyn)N anddM(h(N)(zyn)(N)) where h(N) and (zyn)(N) are elements of M represented by initial segments of lengthN ofdM-geodesic representatives ofhandzyn.

ThenlM(h(N)(zyn)(N))K0 N whereK0is the constant independent ofh, nwhich is provided by Lemma 5. Thus,

lM(h(N)(zyn)(N))K0 N

and therefore N (1=K0) . This contradicts the fact that N can be chosen arbitrarily big.

Therefore,z62StabM(K), which completes the proof of Theorem B.

Corollary 6.

LetM,G,G1,C andH be as in Theorem B. Then

(a) the limit set of H is not the limit set of a quasiconvex subgroup of M (b) the virtual normalizerV NM(H) of H in M is equal to H.

Proof.

(a) Suppose there is a quasiconvex subgroup Q1 of M such that @M(H) =

@M(Q1) =K. Clearly,Q1is innite since Kis nonempty. Set Q=StabM(K) =fy2MjyK=Kg:

Since Q1 is innite and quasiconvex in M and Q = StabM(@M(Q1)), it follows from Lemma 3.9 of KS] that Q contains Q1 as a subgroup of nite index and thereforeQis also quasiconvex inM. On the other hand, Theorem B implies that H =StabM(K), and soH =Q. This contradicts the fact thatH is not quasiconvex inM by Proposition A.

(b) It is not hard to see that A V NB(A) StabB(@B(A)) when A is an innite subgroup of a word hyperbolic group B. Indeed, if g 2 V NB(A), then A0 = A\gAg;1 has nite index n in A. Let A = A0 A0c1 A0cn;1, and let D = maxflA(ci)ji = 1:::n;1g. Suppose p 2 @B(A). Then there is a sequence am 2 A such that p = limm

!1

am. For each m there is b 2 B with

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lB(b)D+lB(g) such thatgamb =am2A0. Thereforegp 2@B(A0) =@B(A).

Since p2 @B(A) was chosen arbitrarily, we have g@B(A) @B(A). Since by the same argument g;1@B(A) @B(A), we conclude that g@B(A) = @B(A). Thus, AV NB(A)StabB(@B(A)).

For the subgroupH ofM we have H V NM(H) StabM(@M(H)). On the other hand,StabM(@M(H)) =H by Theorem B. Therefore,H =V NM(H).

References

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