Stable
rank
for
a
pair of
$\mathrm{C}^{*}$-algebras
立命館大学理工
大坂 博幸(Hiroyuki Osaka)
1
Introduction and Main Result
The (topological) stable rank of $\mathrm{R}\mathrm{i}\mathrm{e}\mathrm{f}\mathrm{f}\mathrm{e}\mathrm{l}[19]$ is noncommutative generalization of the
di-mension ofa compact Hausdorffspace. In fact, when$X$ is a compact Hausdorffspace, the
stable rank of $C(X)$ is $[ \frac{\dim X}{2}]+1$, where $\dim X$ is covering dimension of$X$. Recall that
a unital $\mathrm{C}^{*}$-algebra $A$ has stable rank $n$ if for any element
$a_{1},$ $a_{2},$$\cdots,$$a_{n}$ and $\epsilon>0$ there
exist $b_{1},$$b_{2},$
$\cdots,$$b_{n}$ in $A$ such that
(1)$||a_{i}-b_{i}||<\epsilon$
(2) $\Sigma_{i=1i}^{n}b*bi>0$.
The condition (2) is equivalent to that there exist $c_{1},$$c_{2,n},$$\cdots C$ in$A$such that $\Sigma_{i=1}^{n}C_{i}b_{i}=1$.
If$A$has no umital, we define stable rank of$A$ as stable rank ofthe unitaization of$A$. Note
that stable rank one condition is equivelent to that the set of invertible elemenets is dense
ina given $\mathrm{C}^{*}$-algebra.
Many mathematicians tried to determine stable rank of interesting $\mathrm{C}^{*}$-algebras, in
par-ticular, simple umital $\mathrm{C}^{*}$-algebras ([5] [6] [8] [10] [11] [12] [13] [14] [15] [18] [20] [21] [22]
etc). For examples, AF $\mathrm{C}^{*}$-algebras and non-commutative tori have stable rank one ([18]),
Toeplitz algebra has stable rank two, and Cuntz algebra has an infinity ([19]).
It has been a problem of considerable interest to determine stable rank of a crossed
product algebra $A\cross_{\alpha}G$ ofa unital $\mathrm{C}^{*}$-algebra $A$ with stable rank one by a finite group
$G$. Blackadar presented this problem in the case that $A$ is an AF $\mathrm{C}^{*}$-algebra ([2]), and
constructeda symmetry $\alpha$ on $A=C[0,1]\otimes UHF$ whose crossed product algebra $A\cross_{\alpha}Z_{2}$
has stable rank two. So, to consider the above problem, we need the assumption of the
simplicity on a given $\mathrm{C}^{*}$-algebra $A$.
Inthis directionJeongand the author conclude ([10] [11]) that a crossed product algebra
$A$ $\mathrm{X}_{\alpha}G$ has the cancellation property if $A$ is simple with stable rank one and the
SP-property. Recall that a $\mathrm{C}^{*}$-algebra $A$ is said to have the $\mathrm{S}\mathrm{P}$-property if any non-zero
hereditary subalgebra of$A$ has non-zero projection. For example, an AF $\mathrm{C}^{*}$-algebra has
the$\mathrm{S}\mathrm{P}$-property. Therefore, wecould concludeby [1] that acrossed product algebra$A\cross_{\alpha}G$
has stable rank one ifwe addreal rank zero condition to this crossed product algebra, that
is, the set of self-adjoint elements with finite spectra in $A$ $\mathrm{X}_{\alpha}G$ is dense in the set of
rank one, however, we
can
not always hope thata
given crossedproduc.t
algebra $\mathrm{h}..\mathrm{a}\mathrm{s}$ realrank zero.
In thuis talk wetry to estimate stable rankofa given umital $\mathrm{C}^{*}$-algebra $B$ by stable rank
of a $\mathrm{C}^{*}$-subalgebra $A$ with
common
unit. Incase
that $B$ is a crossed product algebra of$A$ by a finite group $G,$ $sr(B)\leq sr(A)\cross|G|([11])$. More generally, we have the following
result:
Theorem 1 Let $1\in A\subset B$ be unital $C^{*}$-algebras. Suppose that $B$ is a finitely generated
lefl
$A$-module, thatis, there are some$n$ elements$v_{1},$$v_{2},$$\cdots,$$v_{n}$ in$B$ such that$\sum_{i=1}^{n}Av_{i}\Leftarrow B$.
Then, $sr(B)\leq sr(A)\cross n$.
2
Stable
rank
We prove main theorem with using the techmique of matrix algebras. To this end the
following lemma is needed.
Lemma 2 (Spatial case of $\mathrm{R}\mathrm{i}\mathrm{e}\mathrm{f}\mathrm{f}\mathrm{e}\mathrm{l}[19]$) Let $n\in \mathrm{N}$.
$sr(M_{n}(A))\leq sr(A)$.
Proof. We will give a sketch of the proof. Suppose that $sr(A)=m$. Take $m$ elements
$T_{1},$
$\cdots,$$T_{m}$ from $M_{n}(A)$. Set $S=(T_{1}, T_{2}, \cdots, T_{m})^{t}$ in $M_{nm,m}(A)$. Let $(a_{1}, a_{2}, \cdots, a_{nm})$ be
thefirst rowin $S$. Since $sr(A)=m$, we may assumethat there exist
$c_{2)},$$\cdots c_{m+}1$ suchthat
$c_{2}a_{2}+C_{3}a_{3}+\cdot\cdot$$,$ $+cm+1am+1=1-a_{1}$. Consider $(1$ $c_{2}1$ $..$. $c_{m+1}..$
.
$.0.$ . $101^{S}$.Then, the new first row is $(1, b_{2,n}\ldots, b)^{t}m$. Doing the iteration there is an invertible
matrix $R\in M_{nm}(A)$ such that $RS=di\mathrm{a}g(1, S/),$ $S’\in M_{nm-1,n-1}$. By induction there is
$U\in M_{n-1,nm-1}$ such that $US’=I_{n-1}$. Note that $||R^{-1}di\mathrm{a}g(1, s’)-S||$ is small.
Write
$R^{-1}\mathrm{d}i\mathrm{a}g(1, S’)=(s_{1\backslash /}, \cdots s_{m})^{t}$
diag$(1, U)R=(U_{1}, \cdots, U_{m})$,
where $s_{1},$
$\cdots,$$s_{m},$$U_{1},$$\cdots,$$U_{m}$ are in $M_{n}(A)$. Then, we have $||T_{i}-S_{i}||$ is small, and
Definition 3
Define
$Lg_{n}(A)= \{(a_{1}, a_{2}, *\cdot\cdot, a_{n})\in A^{n}|\sum^{n}i=1Aai=A\}$.
Then, $sr(A)\leq n$
if
and onlyif
$Lg_{n}(A)$ is dense in $A^{n}$.Proof of Theorem 1.
We give only the proof of the case of$sr(A)=1$ and $G=\mathrm{Z}_{2}$. That is, wewill show that
$sr(A\cross_{\alpha}Z_{2})\leq 2$ for a unital $\mathrm{C}^{*}$-algebra $A$. In general case we can guess it from the proof
of Lemma 2.
Take $a_{0}+a_{1}u,$ $b_{0}+b_{1}u$ in $A\cross_{\alpha}Z_{2}$, where $u$ is a unitary implementing $\alpha$. Let $\epsilon>0$ be
given. Consider
$=$
.Since $sr(M_{2}(A))=1$ by Lemma 2, there exists an invertible element
$\in M_{n}(A)$
such that$||-||< \frac{\epsilon}{2}$.
Consider
$=$
.Then, $(c_{0}+c_{1}u, d_{0}+d_{1}u)\in Lg_{2}(A\cross_{\alpha}\mathrm{Z}_{2})$, and $||\mathit{0}_{0}+a_{1}u-(c_{0}+c_{1}u)||<\epsilon,$
$||b_{0}+b_{1}u-\coprod$ $(d_{0}+d_{1}u)||<\in \mathrm{i}$. Hence, $sr(A\cross_{\alpha}\mathrm{Z}_{2})\leq 2$.
Corollary 4 Let $1\in A\subset B$ be a pair
of
unital $C^{*}- algebra\mathit{8}$, and $E:Barrow A$ be afaithful
conditional expectation
of index-finite
type. That is, there $exi_{\mathit{8}}t_{S}$ a quasi-basis $\{v_{i}^{*}, v_{i}\}_{i=}^{n}1$such that $x= \sum_{i=1}E(xv_{i}^{*}n)v_{i},$ $\forall x\in B$. Then, $sr(B)\leq sr(A)\mathrm{x}n$.
Corollary 5 Let $1\in A$ be a unital $C^{*}$-algebra and $G$ be a
finite
group. $Then_{f}$$sr(A\cross_{\alpha}G)\leq sr(A)\cross|G|$.
3
Application
Question 6 Let$A$ be a $AFC^{*}$-algebra and $G$ be a
finite
group. Then $sr(A\mathrm{x}_{\alpha}c)\leq 1$.Theorem 7 $(\mathrm{J}\mathrm{e}\mathrm{o}\mathrm{n}\mathrm{g}-\mathrm{o}\mathrm{S}\mathrm{a}\mathrm{k}\mathrm{a}[11])$ Let $A$ be a simple unital$C^{*}$-algebra with $sr(A)=1$ and
$SP$-property.
If
$G$ is afinite
group and$\alpha$ is an actionof
$G$ on A then the $cro\mathit{8}\mathit{8}ed$product$A\cross_{\alpha}G$ has cancellation.
Here, a $C^{*}$-algebra has $\mathrm{S}\mathrm{P}$-property if each of
its
non-zero
hereditary $C^{*}$-subalgebrascontains a
non-zero
projection.In particular,
Corollary 8 Under the $a\mathit{8}sumpti_{\mathit{0}}n\mathit{8}$
of
the above theorem,if
$A\cross_{\alpha}Gha\mathit{8}$ real rankzero, that is, any $\mathit{8}elf$-adjoint element can be approximated by a self-adjint
element with
finite
$spectra_{f}$ then $sr(A\cross_{\alpha}G)=1$.
Remark 9 Generally, we can not hope that a given simple crossedproduct algebra$A\cross_{\alpha}G$
has real rank zero, even
if
A $\dot{u}UHF$ , and$G=\mathrm{Z}_{2}[7]$.If one consider a crossed product by the integer group $\mathrm{Z}$ then there is no
conditional
expectation ofindex-finite type fromthe crossed product $A\cross_{\alpha}\mathrm{Z}$ onto $A$, but
we
have thefollowing cancellation theorem:
Theorem 10 $(\mathrm{J}\mathrm{e}\mathrm{o}\mathrm{n}\mathrm{g}-\mathrm{o}_{\mathrm{S}\mathrm{a}}\mathrm{k}\mathrm{a}[11])$ Let $A$ be a simple unital $C^{*}$-algebra with $sr(A)=1$
and $SP$-property.
If
$\alpha$ is an outer actionof
the integer group $\mathrm{Z}$ on$A_{\mathit{8}u}ch$ that $\alpha_{*}=id$ on$K_{0}(A)$ then the crossed product $A\cross_{\alpha}\mathrm{Z}$ has cancellation.
Example 11 Simple $AFC^{*_{a}}-lgebra\mathit{8}$ and non-commutative tori $A_{\theta}$ are $example\mathit{8}$
for
$C^{*}-$algebras in $Theorem\mathit{8}7$ and 10.
$*\vee’\vee\doteqdot \mathrm{X}\ovalbox{\tt\small REJECT}$
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