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Volume 2010, Article ID 837951,14pages doi:10.1155/2010/837951

Research Article

On Boundedness of Weighted Hardy Operator in L

p·

and Regularity Condition

Aziz Harman

1

and Farman Imran Mamedov

1, 2

1Education Faculty, Dicle University, 21280 Diyarbakir, Turkey

2Institute of Mathematics and Mechanics of National Academy of Science, Azerbaijan

Correspondence should be addressed to Farman Imran Mamedov,[email protected] Received 22 September 2010; Accepted 26 November 2010

Academic Editor: P. J. Y. Wong

Copyrightq2010 A. Harman and F. I. Mamedov. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

We give a new proof for power-type weighted Hardy inequality in the norms of generalized Lebesgue spacesLRn. Assuming the logarithmic conditions of regularity in a neighborhood of zero and at infinity for the exponentspxqx, βx, necessary and sufficient conditions are proved for the boundedness of the Hardy operatorHfx

|y|≤|x|fydyfromL

|x|β·Rninto

L

|x|β·−n/p·−n/q·RN. Also a separate statement on the exactness of logarithmic conditions at zero

and at infinity is given. This shows that logarithmic regularity conditions for the functionsβ, pat the origin and infinity are essentially one.

1. Introduction

The object of this investigation is the Hardy-type weighted inequality |x|β·−n/p·−n/q·Hf

LRnC|x|β·f

LRn, Hfx

|y|≤|x|f y

dy 1.1

in the norms of generalized Lebesgue spacesLRn. This subject was investigated in the papers1–7. For the one-dimensional Hardy operator in 1, the necessary and sufficient condition was obtained for the exponents β, p, q. We give a new proof for this result in more general settings for the multidimensional Hardy operator. Also we prove that the logarithmic regularity conditions are essential one for such kind of inequalities to hold. In that proposal, we improve a result sort of8 since, there is an estimation by the maximal function|x|−nHfx≤CMfx.

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At the beginning, a one-dimensional Hardy inequality was considered assuming the the local log condition at the finite interval 0, l. Subsequently, the logarithmic condition was assumed in an arbitrarily small neighborhood of zero, where an additional restriction pxp0was imposed on the exponent. In3,9it was shown that it is sufficient to assume the logarithmic condition only at the zero point. In10the case of an entire semiaxis was considered without using the conditionpxp0. However, a more rigid conditionβ <

1−1/p was introduced for a range of exponents. The exact condition was found in 1.

They proved this result by using of interpolation approaches. In this paper, we use other approaches, analogous to those in10, based on the property of triangles forpx-norms and binary decomposition near the origin and infinity. We consider the multidimensional case, and the conditionβx const is not obligatory, while the necessary and sufficient condition is obtained by a set of exponentsp, q, βwithout imposing any preliminary restrictions on their valuesTheorems3.1and3.2. InTheorem 3.3, it has been proved that logarithmic conditions at zero and at infinity are exact for the Hardy inequality to be valid in the caseqp.

Problems of the boundedness of classical integral operators such as maximal and singular operators, the Riesz potential, and others in Lebesgue spaces with variable exponent, as well as the investigation of problems of regularity of nonlinear equations with nonstandard growth condition have become of late the arena of an intensive attack of many authorssee 11–18.

2. Lebesgue Spaces with a Variable Exponent

As to the basic properties of spacesL, we refer to19. Throughout this paper, it is assumed thatpxis a measurable function inΩ, whereΩ∈Rnis an open domain, taking its values from the interval1,∞withp supx∈Rnp <∞. The space of functionsLΩis introduced as the class of measurable functionsfxinΩ, which have a finiteIpf :

Ω|fx|pxdx- modular. A norm inLΩis given in the form

f

LΩinf

λ >0 :Ip

f λ ≤1

. 2.1

Forp>1,p<∞the spaceLΩis a reflexive Banach space.

Denote byΛ a class of measurable functionsf : Rn → Rsatisfying the following conditions:

∃m∈

0,1

2 , ∃f0∈R, sup

x∈B0,m

fx−f0ln 1

|x| <∞, 2.2

∃M >1, ∃f∞∈R, sup

x∈Rn\B0,M

fxf∞ln|x|<∞. 2.3

For the exponential functionsβx, px, andqx, we further assumeβ, p, q∈Λ.

We will many times use the following statement in the proof of main results.

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Lemma 2.1. Lets ∈ Λbe a measurable function such that−∞ < s, s < ∞. Then the condition 2.2for the functionsxis equivalent to the estimate

C−13 |x|s0 ≤ |x|sxC3|x|s0 2.4

when|x| ≤mand the condition2.3forsxis equivalent to the estimate

C4−1|x|s∞ ≤ |x|sxC4|x|s∞ 2.5

when|x| ≥M. Where the constantsC3, C4>1 depend ons0,s∞,s,s,s0,s∞,m,M,C1, C2.

To proveLemma 2.1, for example2.4, it suffices to rewrite the inequality2.4in the form

C3−1≤ |x|sx−s0C3 2.6

and pass to logarithmic in this inequalitysee also,1,7,17.

For 1 < p < ∞, p denotes the conjugate number of p,p p/p−1. It is further assumed thatp∞forp1, andp1 forp∞, 1/∞0, 1/0∞. We denote byC, C1, C2

various positive constants whose values may vary at each appearance.Bx, rdenotes a ball with center atxand radiusr >0. We writeuvif there exist positive constantsC3, C4such thatC3uxvxC4ux. ByχE, we denote the characteristic function of the setE.

3. The Main Results

The main results of the paper are contained in the next statements. The theorem below gives a solution of the two-weighted problem for the multidimensional Hardy operator in the case of power-type weights.

Theorem 3.1. Letqxpxand βxbe measurable functions taken from the classΛ. Let the following conditions be fulfilled:

0< ppx, qxq <∞, −∞< ββxβ<∞. 3.1

Then the inequality1.1for any positive measurable functionfis fulfilled if and only if

p0>1, p∞>1, β0< n

1− 1

p0 , β∞< n

1− 1

p∞ . 3.2

We have the following analogous result for the conjugate Hardy operatorHfx

|y|≥|x|fydy.

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Theorem 3.2. Letqxpxand βxbe measurable functions taken from the classΛ. Let the conditions3.1be fulfilled. Then the inequality 1.1 for any positive measurable functionf and operatorHfis fulfilled if and only if

p0>1, p∞>1, β0> n

1− 1

p0 , β∞> n

1− 1

p∞ . 3.3

In the next theorem, we prove that the logarithmic conditions near zero and at infinity are essentially one.

Theorem 3.3. If condition2.2or2.3does not hold, then there exists an example of functionsp, β, and a sequencefbelow indexkviolating the inequality

|x|β·−nHf

LRnC|x|β·f

LRn. 3.4

4. Proofs of the Main Results

Proof ofTheorem 3.1.

Sufficiency. Letfx≥0 be a measurable function such that |x|β·f

LRn≤1. 4.1

We will prove that

|x|β·−n/p·−n/q·Hf

LRnC5. 4.2

Assume that 0< δ < mis a sufficiently small number such thatn/px> n/p0−ε for allxB0, δ, whereε n/p0−β0/2. Let, furthermore,M < N <∞be a sufficiently large number such thatn/px> n/p∞−δ1for allx∈Rn\B0, N, whereδ1 n/p∞− β∞/2.

By Minkowski inequality, forpx-norms, we have |x|β·−n/p·−n/q·Hf

LRn≤|x|β·−n/p·−n/q·Hf

LB0,δ

|x|β·−n/p·−n/q·Hf

LB0,N\B0,δ

|x|β·−n/p·−n/q·

{t:|t|<N}ftdt

LRn\B0,N

|x|β·−n/p·−n/q·

{t:N<|t|<|x|}ftdt

LRN\B0,N

:i1i2i3i4.

4.3

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The estimate near zeroi1.

By Minkowski inequality, we have the inequalities

i1

|x|β·−n/p·−n/q·

k0 {t:2−k−1|x|<|t|<2−k|x|}ftdt

LB0,δ

k0

|x|β·−n/p·−n/q·

{t:2−k−1|x|<|t|<2−k|x|}ftdt

LB0,δ

.

4.4

DenoteBx,k {y ∈ Rn : 2−k−1|x| < |y| < 2−k|x|}andpx,k minpx,infy∈Bx,kpy.

By2.2andLemma 2.1, forxB0, δ,tBx,k, we have|x|βx ∼ 2kβ0tβt. To prove this equivalence, we use that|t| ∼ |x|2−k,|x|βx ∼ |x|β0and|t|βt ∼ |t|β0. Therefore, and due to Holder’s inequality, forxB0, δ, we get

|x|βx−n/px−n/qx

Bx,k

ftdt

C62kβ0|x|−n/px−n/qx

Bx,k

|t|βtftdt

C62kβ0|x|−n/p0−n/qx

Bx,k

|t|βtftpx,k

dt 1/p

x,k

2−k|x|n/px,k .

4.5

aIfpx,k/px, then by2.2andLemma 2.1,

2−k|x|n/p

x,k

tn/pttn/p0∼2−kn/p0|x|n/p0∼2−kn/p0|x|n/px. 4.6

Demonstrate details in proof of4.6. FortBx,kandxB0, δ, we have 2−k−1|x|<

|t| ≤2−k|x|. Then

2−k|x|n/p

x,k

∼ |t|n/px,k. 4.7

By hypothesisa,px,kattains in the intervalBx,k, because there exists a pointyBx,kwhere px,kpy. Obviously, the pointy depends onx, k. Then|t|n/px,k ∼ |t|n/py. By virtue of 2−k−1|x|<|y| ≤2−k−1|x|, we have|t|/2 <|y| ≤2|t|. Hence,|t|n/py ∼ |y|n/py, byLemma 2.1,

|y|n/py∼ |y|n/p0∼ |t|n/p0.

bIfpx,kpx, then by choice ofδ, 2−k|x|n/px,k

∼2−kn/px|x|n/px≤2−kn/p0εk|x|n/px; xB0, δ. 4.8

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Applying estimate4.8to both hypothesesaandb, by choosing ofεandδ, the right-hand part of4.5is less than

C7|x|−n/qx2−kε

Bx,k

|t|βtftpx,k

dt 1/p

x,k

. 4.9

Simultaneously,

Bx,k

|t|βtftpx,k

dt

Bx,k∩{t∈Rn:|t|βtft≥1}

|t|βtftpt dt

Bx,k

dt≤12−knδnC8.

4.9

By4.5and4.9, we have

Iq;B0,δ

|x|β·−n/p·−n/q·

Bx,k

ftdt

C92−kεq

B0,δ|x|−n

Bx,k

|t|βtftp

x,kdt

qx/px,k dx

C9C8q/p−12−kεq

B0,δ

Bx,k

|t|βtftpt 1 dt

|x|−ndx

4.10

which, due to Fubini’s theorem, yields

C9Cq8/p−12−kεq

{t:|t|<2−kδ}

ft|t|βtpt

B0,2k1|t|\B0,2k|t||x|−ndx

dt C102−kεqln 2

{t:|t|<2−kδ}

ft|t|βtpt

1 dtC112−kεq.

4.11

Therefore,

|x|β·−n/p·−n/q·

Bx,k

ftdt

LB0,δ

C122−kεq/q. 4.12

By4.12and4.4, we get

i1C12 k0

2−kεq/qC13<∞. 4.13

The estimate at infinityi4.

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PutfNt ftχ|t|>N. Analogously to the case of4.4, we have

i4

k0

|x|β·−n/p·−n/q·

{t:2−k−1|x|<|t|<2−k|x|}fNtdt

LRn\B0,N

. 4.14

By|t| ∼ |x|2−k, condition2.3andLemma 2.1forx∈Rn\B0, N,tBx,k, we have

|x|βx ∼ |x|β∞∼2kβ∞tβ∞∼2kβ∞tβt. 4.15

Therefore, by virtue of Holder’s inequality,

|x|βx−n/px−n/qx

Bx,k

fNtdt

C142kβ∞|x|−n/px−n/qx

Bx,k

|t|βtfNtdt

C142kβ∞|x|−n/px−n/qx

Bx,k

|t|βtfNtp

x,kdt 1/p

x,k

2−k|x|n/p

x,k

.

4.16

iIfpx,k/pxandtBx,k, by2.3andLemma 2.1, we have

2−k|x|n/p

x,k

tn/pttn/p ∼2−kn/p|x|n/p∼2−kn/p|x|n/px. 4.17

iiIfpx,kpx, then by choice ofδ1,

2−k|x|n/p

x,k

∼2−kn/px|x|n/px≤2−kn/p∞δ1k|x|n/px. 4.18

In both hypothesesiandiiby choosing ofδ1, we have

|x|βx−n/px−n/qx

Bx,k

fNtdt≤C15|x|−n/qx2−kδ1

Bx,k

|t|βtfNtpx,k

dt 1/p

x,k

. 4.19

On the other hand,

Bx,k

|t|βtftp

x,kdt

Bx,k∩{t∈Rn:|t|βtft≥Gt}

|t|βtft Gt

p

x,k

Gtpx,kdt

Bx,k

Gtpdt, 4.20

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whereGt 1/1t2. Hence,

Bx,k

fNt|t|βtpt

Gtpx,k−pt

Bx,k

Gtdt. 4.21

By2.3, fortBx,k, we have

Gtpx,k−pt

1t2pt−p

x,kC16. 4.22

Then4.21implies

Bx,k

|t|βtfNtp

x,kdtC17. 4.23

Therefore,

Iq;Rn\B0,N

|x|βx−n/px−n/qx

Bx,k

fNtdt

Cq17/p2−kδ1q

Rn\B0,N|x|−n

Bx,k

|t|βtfNtpt dt

dx,

4.24

by Fubini’s theorem,

Cq17/p−12−kδ1qln 2

{t:|t|>2−kN}

fNt|t|βtpt

dtC182−kδ1q. 4.25

From4.25and expansion4.14, we get

i4C18 k0

2−kqδ1/qC19. 4.26

The estimate in the middlei2, i3. We have

i2

|x|β·−n/p·−n/q·

{t∈Rn:|t|<|x|}ftdt

LB0,N\B0,δ

B0,Nftdt

|x|β·−n/p·−n/q·

LB0,N\B0,δ

C20

B0,Nftdt,

4.27

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from which, by virtue of Holder’s inequality, forpx-norms, we obtain the estimate

B0,Nftdt≤|t|β·ft

LB0,N

|t|−β·

Lp·B0,N. 4.27

Using t−βtptt−β0p0 by Lemma 2.1for tB0, N and taking the condition β0 <

n/p0into account, we find

Ip;B0,N

|t|−β·

B0,N|t|−βtptdtC21

B0,N|t|−β0p0dtC22. 4.28 From4.27and4.28, it follows that

i2C23. 4.29

Furthermore, we have

i3

B0,Nftdt

|x|βx−n/px−n/qx

LRn\B0,δ

. 4.30

The boundedness of the first term follows by4.27. Due to2.3andLemma 2.1, forx ∈ Rn\B0, N, we have

|x|βx−n/pxqx−n∼ |x|β∞−n/p∞qx−n. 4.31

Applying condition4.31, we get

Iq;Rn/B0,N

|x|β·−n/p·−n/q·

C24

Rn\B0,N|x|−n−2δ1dxC25. 4.32

Then

i3C251/p. 4.33

Necessity. Letβ0 > n/p0. Fix a sufficiently largeτ >0 and apply inequality1.1by the test function

fτt t−n/pt−βtχB0,δ/τ\B0,δ/2τt. 4.34

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We come to a contradiction

Ip

|t|β·fτ

B0,δ/τ\B0,δ/2τ|x|−ndxC0ln 2<∞, Iq

|t|β·−n/p·−n/q·

B0,tfτ

y dy

B0,1\B0,δ/τ|t|βt−n/pt−n/qtqt

B0,δ/τ\B0,δ/2τ

y−n/p0−β0dy qt

dt

δ

n/p0−β0q

B0,1\B0,δ/τ|t|β0−n/p0qt−ndt−→ ∞

4.35

asτ → ∞.

If 0< p0≤1, then by virtue of inequalities4.35and3.2we obtain

Iq

|t|βt−n/pt−n/qt

B0,tfτ

y dy

−→ ∞, asτ −→ ∞. 4.36

Also,

Ip

|t|βtfτt

C0ln 2, 4.37

and we come to a contradiction.

Ifβ∞n/p∞, then, using condition2.3andLemma 2.1assuming 0< τ <1, we again obtain

Ip

|t|βtfτt

C0ln 2,

Iq

|t|βt−n/pt−n/qt

B0,tfτtdy

Rn\B0,δ/τ|t|βt−n/ptqt−n

B0,δ/τ\B0,δ/2τ

y−n/p∞−β∞dy

dt

δ

n/p∞−β∞q

Rn\B0,δ/τ|t|β∞−n/p∞qt−ndt−→ ∞

4.38

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asτ → ∞. Ifβ∞ n/p∞, then from4.38we have

Iq

|t|βt−n/pt−n/qt

B0,tfτtdy

∞. 4.39

From4.38and3.2, we derive, as above, the necessity of the conditionp∞>1.

This completes the proof ofTheorem 3.1.

The proof ofTheorem 3.2easily follows fromTheorem 3.1by using the equivalence of inequalities

|x|βx−n/px−n/qxHfx

LRnC|x|βxfx

LRn, |z|n−βz−2n/qzHfx

LRnC|z|−βz−2n/pzfz

LRn,

4.40

where px, qx, and βx stand for the functions px/|x|2, qx/|x|2, and βx/|x|2, respectively. The equivalence readily follows from the equality

g

LRn|z|−2n/pzg

LRn 4.41

for any functiong:Rn → R, wheregz gz/|z|2, which easily can be proved by changing of variablexz/|z|2in the definition ofpx-norm.

5. Exactness of the Logarithmic Conditions

Proof ofTheorem 3.3. Assume δk 1/4k,k ∈ N,fkx |x|−n/px−βxχB0,2δk\B0,δkx, and βx β0. Define the functionp:0,∞ → 1,∞as

px

⎧⎨

p0, xB0,k\B0, δk,

pk, xB0,k\B0,k, k∈N 5.1

wherep0 > 1,pk p0αk,β0 ∈ R, and{αk}is an arbitrary sequence of positive numbers satisfying the condition

k−→ ∞ ask−→ ∞. 5.2

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Thenαkln1/δk → ∞, and condition2.2does not hold for the functionpx. Since

Ip

|x|βxfkx

B0,2δk\B0,δk

|t|β0· |t|−n/p0−β0p0

dt

B0,2δk\B0,δk|t|−ndtC0 k

δk

dt

t ωn−1ln 2, Ip

H

|·|β·−nfk·

B0,4δk\B0,2δk

B0,2δk\B0,δk|t|−n/pt−β0dt pk

|x|β0−npkdx

C

B0,3δk\B0,2δkδkn−n/p0−β0pk|x|β0−np0αkdx

k−nαk/p0 ek/p0ln1/δk−→ ∞

5.3

ask → ∞, we see that this contradicts inequality3.4.

The given functionfkxand the exponential functionspxandβxare also suitable for proving the necessity of condition2.3for the functionp. For this we define the numbers δkfrom the equalityδk4k, k ∈N. Letfkx |x|−n/px−βχB0,2δk\B0,δkx,βx β, and x∈Rn. We define the functionpas

px

⎧⎨

p, xB0,k\B0, δk,

pk, xB0,k\B0,k, k∈N 5.4

wherep> 1,β ∈R,pk pαk, and{αk}is an arbitrary sequence of positive numbers satisfying the conditionk → ∞ ask → ∞. Thenαklnδk → ∞; hence, condition2.3 does not hold for the functionpx. Furthermore, we have

Ip

|x|βxfkx

B0,2δk\B0,δk

|t|β· |t|−n/p−βp

dtωn−1ln 2,

Ip

|x|βx−nfkx

B0,4δk\B0,2δk

B0,2δk\B0,δk|t|−n/pt−βdt pk

|x|β−npkdx

C

B0,3δk\B0,2δkδkn−n/p−βpk|x|β−np−αkdx

k k/pCek/plnδk −→ ∞

5.5

ask → ∞, which contradicts inequality3.4.

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The same reasoning brings us to the proof of the exactness of conditions2.2and 2.3for the functionβxalso. For instance, to show the necessity of condition2.2, it can be assumed thatpxp0>1,x∈Rn,

βx

⎧⎨

β0αk, xB0,k\B0, δk,

β0, xB0,k\B0,kk∈N. 5.6 Then

Ip

|x|βx−nfkx

−pk 0αk −→ ∞ ask−→ ∞, Ip

|x|βxfkx

C0ln 2.

5.7

This completes the proof ofTheorem 3.3.

Acknowledgment

F. I. Mamedov was supported partially by the INTAS Grant for the South-Caucasian Republics, no. 8792.

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