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ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu

H ´ENON EQUATION WITH NOLINEARITIES INVOLVING SOBOLEV CRITICAL GROWTH IN H0,rad1 (B1)

EUDES M. BARBOZA, OLIMPIO H. MIYAGAKI, F ´ABIO R. PEREIRA, CL ´AUDIA R. SANTANA

Abstract. In this article we study the H´enon equation

−∆u=λ|x|µu+|x|α|u|2α−2u inB1, u= 0 on∂B1,

whereB1 is the ball centered at the origin of RN (N 3) andµα0.

Under appropriate hypotheses on the constantλ, we prove existence of at least one radial solution using variational methods.

1. Introduction

In this article we search for a non-trivial radially symmetric solution to the H´enon-type Dirichlet problem

−∆u=λ|x|µu+|x|α|u|2α−2u in B1,

u= 0 on∂B1, (1.1)

where λ >0,µ≥α≥0,B1 is a unity ball centered at the origin of RN (N ≥3), and 2α= 2(NN−2+α).

When α = µ = 0, the pioneering work is due to Br´ezis and Nirenberg in [9], where they obtained aλ1 and positive solutions whenλ < λ1. We refer the reader to the book [39] for a survey about this subject. Devillanova and Solimini [24]

proved multiplicity results for N ≥7, for all λ > 0. Then in [25], they comple- mented the former result for N ≥ 4, but for λ ∈ (0, λ1). Clapp and Weth [20]

extended the above results forN ≥4, for allλ >0, getting lower estimates for the number of solutions. Chen, Shioji and Zou [18] obtained a ground state solution and multiplicity results, and improved results in [20]. The existence is proved in [15], for all λ > 0 and N ≥ 5, and when N = 4 only for λ 6= λk, where λk is eigenvalue of (−∆). In [17] some multiplicity results were obtained forλnear λk. These existence results were improved in [26]. For a version of these results in the quasilinear see [21, 1].

When α, µ > 0, these problems are called H´enon type problems. Actually, H´enon [28] introduced problem (1.1) with λ = 0, as a model of clusters of stars for the case N = 1. Since then, many authors have worked with this type of

2010Mathematics Subject Classification. 35J20, 35J25, 35B33, 35B34.

Key words and phrases. enon type equation; critical Sobolev growth; resonance;

noncompact variational problem.

c

2021 Texas State University.

Submitted October 2, 2019. Published March 29, 2021.

1

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the equations from several points of view. The pioneering paper is due to Ni [32]; he established the compact embeddingH0,rad1 (B1)⊂Lp(B1,|x|α) for allp∈ [1,2α), where 2α = 2(N+α)N−2 . This was used for obtaining radial solutions. Here H0,rad1 (B1) = {u ∈ H01(B1) : uis radial, that is,u(x) = u(|x|),∀x ∈ B1}. This result was extended to more general quasilinear operators in [21]. In the caseλ= 0, Badiale and Serra [2] obtained multiplicity results for non-radial solutions (see [16]

for some extensions). For ground state profile (when the solutions that concentrate at a boundary point ofB1asα→ ∞) and when the growth approaches to the usual Sobolev critical exponent, see [10, 11, 13, 14, 30, 34, 38], and references therein.

For H´enon problems involving the usual Sobolev exponents we cite [31, 29, 35, 36]

and their references. Up to our knowledge, there are only a few works treating problem (1.1) withλ6= 0 involving the Sobolev critical exponent given by Ni, 2α. Nonhomogeneous perturbations are studied in [3], when λ > 0 and smaller than the first eigenvalue. While some concentration phenomena for linear perturbation is studied in [27] when λ is small enough. Long and Yang [31] established the existence of nontrivial solutions for (1.1) withµ= 0, when λ6=λk, for all k, and N ≥7. Also, they proved that (λk,0) is a bifurcation point of problem (1.1), for allk. The aim of this article is to extend above results, for instance, treating allλ positive.

To establish our results, we need to know the spectrum of the problem

−∆u=λ|x|µu inB1;

u= 0 on∂B1. (1.2)

Note thatH0,rad1 (B1) is a Hilbert space, which is compactly embedded inLp(B1,|x|µ), for allp∈(1,2µ) (see [32]). Arguing as in [22, 4], we can show that there exists a sequence of eigenvalues for (1.2), with

λ1≤λ2≤λ3≤ · · · ≤λk≤. . . , λk →+∞, ask→ ∞.

The eigenvalues are characterized by λ1= min

u∈H0,rad1 (B1)\{0}

R

B1|∇u|2dx R

B1|x|µ|u|2dx, λk+1= min

u∈Pk+1\{0}

R

B1|∇u|2dx R

B1|x|µ|u|2dx, (1.3) where

Pk+1=

u∈H0,rad1 (B1) :hu, eji= Z

B1

∇u∇ejdx= 0, j= 1,2, . . . , k , (1.4) andek denotes the eigenfunction associated with the eigenvalueλk. Also from [22], we know thate1>0, and thatej forj6= 1 changes sign.

The results below follow from the linear theory, which are obtained by adapting the ideas in [7] or [37, Appendix A]):

(1) each λk has finite multiplicity, (2) ek∈C0,σ(B1) for someσ∈(0,1);

(3) the sequence {ek} is an orthonormal basis in L2(B1,|x|µ) and orthogonal inH0,rad1 (B1).

For a fix k∈ Nwe can assumeλk < λk+1, otherwise we can assume that λk has multiplicityp∈N; that is,

λk−1< λkk+1=. . .=λk+p−1< λk+p, and we denoteλk+pk+1.

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The proofs of our results are based on variational methods. To ensure that the considered minimax levels lie in a suitable range, we use approximating functions that are constructed from Talenti functions (H´enon version). When we work with nonlinearities involving Sobolov critical growth, it is common to follow the Br´ezis- Nirenberg approach to estimate the minimax levels with the help of the Talenti functions,

U(x) =hN(N−2) +|x|2

i(N−2)/4

(1.5) which are solutions of the problem

−∆u=|u|2−2u inRN; u(x)→0 as |x| → ∞.

It is well-know that they yield the best Sobolev embedding constant constant for H1(RN)⊂L2(RN), given by

S= inf

u∈H01(B1),u6=0

kuk2 kuk22

.

Using U one can prove that the minimax level of the functional associated with problems with critical growth belongs to the interval where the Palais-Smale com- pactness condition holds.

When searching for solutions to H´enon type equations in H0,rad1 (B1), we note that the weight|x|α modifies the critical exponent, it becomes 2α≥2 forα≥0.

Consequently, we need to invoke a different family of functions adapted for the radial context. More precisely, since we are searching for radial solutions for (1.1) with critical growth, we letSα be the best constant for the Sobolev-Hardy embedding

H0,rad1 (RN)→L2α(RN,|x|α).

The constant is

Sα= inf

u∈H0,rad1 (B1), u6=0

R

RN|∇u|2dx R

RN|x|α|u|2αdx2/2α

(1.6) which is achieved by the family of functions

u(x) = [(N+α)(N−2)](N−2)/2(2+α)

(+|x|2+α)(N−2)/(2+α) (1.7)

defined for >0. Indeed, these functions are minimizers of Sα in the set of radial functions in the caseα >−2. Furthermore, theus are the positive radial solutions of

−∆u=|x|α|u|2α−2u inRN;

u(x)→0 as |x| → ∞. (1.8)

For details and more general results, see [3, 12, 19, 21, 32].

1.1. Statement of main results. We present our results in three theorems. The first theorem deals with the non-trivial solution of problem (1.1) whenλ >0 and N > 4 +µ. The possibility of resonance is also considered in this case. The second theorem also concerns the non-trivial solution, when the working dimension is 4 +µ; in this case we need to consider λ 6= λj for j ∈ N = {1,2,3, . . .}. In the third theorem considers non-trivial solutions whenN <4 +µ. To recover the

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compactness of the functional associated with problem (1.1), we needλlarge, with λ6=λj.

Theorem 1.1. For 0 < λ < λ1 or λk ≤ λ < λk+1, problem (1.1) possesses a non-trivial radial solution when

N > µ−α

2 + 2 + (2 +µ)√

2. (1.9)

Theorem 1.2. For 0 < λ < λ1 or λk < λ < λk+1, problem (1.1) possesses a non-trivial radial solution when N = 4 +µ.

Theorem 1.3. Forλ >0 sufficiently large andλ6=λj, for j ∈N, problem (1.1) possesses a non-trivial radial solution whenN <4 +µ.

Remark 1.4. Observe that (1.9) implies N > 4 +µ. In this sense, Theorem 1.1 provides a partial answer to the question about existence of nontrivial radial solutions whenN >4 +µ.

In [3], it was proved that the non-trivial solution of (1.1) is positive when 0<

λ < λ1.

This article is organized as follows. In Section 2, we introduce the variational framework, prove the boundedness of Palais-Smale sequences of the functional as- sociated with problem (1.1). Since we search for a radial solutions for a problem with critical Sobolev growth nonlinearity, we show the minimax levels are bounded by constants depending on N, α and Sα. In Section 3, we obtain the geometric conditions on the functional for proving the existence of solutions to (1.1). In Sec- tion 4, following [15], we obtain estimates for recovering the compactness of the functional associated with problem (1.1). In Section 5, we prove our main results.

2. Variational formulation

Given a real Banach spaceE and a functional Φ of classC1onE, by definition Φ satisfies Palais-Smale condition at levelc∈R(denoted (P S)c) if every sequence (uj) inE such that

Φ(uj)→c and Φ0(uj)→0 inE (2.1) has a convergent subsequence. Such a sequence is called a (P S) sequence (at level c). We shall use the following version of a well-known critical-point theorem (see [5]).

Theorem 2.1. Let H be a real Hilbert space and f ∈ C1(H,R) be a functional satisfying the following assumptions:

(1) f(u) =f(−u),f(0) = 0for any u∈H;

(2) there existsβ >0 such that f satisfies(P S)c forc∈(0, β);

(3) there exist two closed subspacesV, W ⊂H and positive constantsρ, δ with δ < β such that

(i) f(u)< β for any u∈W;

(ii) f(u)≥δfor any u∈V,kuk=ρ;

(iii) codimV <∞.

Then there exist at leastmpairs of critical points, where m= dim(V ∩W)−codim(V +W).

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We considerH0,rad1 (B1), with the norm kuk=Z

B1

|∇u|2dx1/2

.

The subspace of functions inB1with weight|x|µandµ≥0 is denoted byLz(B1,|x|µ), and it is endowed the norm

kukz,|x|µ =Z

B1

|x|µ|u|zdx1/z .

For finding (weak) solutions of (1.1) we look for critical points of the functional Jλ:H0,rad1 (B1)→Rdefined as

Jλ(v) = 1 2 Z

B1

(|∇v|2−λ|x|µv2) dx− 1 2α

Z

B1

|x|α|v|2αdx.

We do not apply the standard variational arguments because the embedding of H0,rad1 (B1) in L2α(B1,|x|α) is not compact, and that the functional Jλ does not satisfy the Palais-Smale condition. We need to adapt an idea introduced by Br´ezis and Nirenberg [9] and Secchi [35]. This idea was used for the Talenti functions (1.5) for proving that a functional associated with a problem with critical Sobolev growth nonlinearity satisfies the PS-condition in the interval (0, SN/2/N).

Here, in the radial context for a H´enon type equation, we construct minimax levels for the functionalJλ which lie in the interval

0, 2 +α

2(N+α)S(N+α)/(2+α) α

.

For this purpose, we use that positive solutions (1.7) of (1.8) yield the constantSα

in the embedding ofH0,rad1 (RN) inL2α(RN,|x|α).

2.1. Palais-Smale sequences. Recall that the proof of the Palais-Smale condition for the functional associated with Problem (1.1) follows traditional methods. So we present a brief proof for this condition.

Lemma 2.2. Let (um) ⊂ H0,rad1 (B1) be a (P S)c sequence of Jλ. Then (um) is bounded inH0,rad1 (B1).

Proof. Let (um)⊂H0,rad1 (B1) be a (P S)c sequence, that is Jλ(um) =1

2kumk2−λ

2kumk22,|x|µ− 1 2α

Z

B1

|x|α|um|2αdx=c+o(1) (2.2) and

hJλ0(um), vi= Z

B1

∇um∇vdx−λ Z

B1

|x|µumvdx− Z

B1

|x|α|um|2α−2umvdx

=o(1)kvk

(2.3) for allv∈H0,rad1 (B1). From (2.2) and (2.3), it follows that

Jλ(um)−1

2hJλ0(um), umi=2α−2 2·2α

Z

B1

|x|α|um|2αdx

=c+o(1) +o(1)kumk.

(2.4)

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Considering 0< λ < λ1, by the variational characterization ofλ1, we have hJλ0(um), umi ≥

1− λ λ1

kumk2− Z

B1

|x|α|um|2αdx.

Hence by (2.4), we obtain

kumk2≤C1+C2kumk

and consequently (um) is a bounded sequence inH0,rad1 (B1).

Now we considerλk < λ < λk+1. It is convenient to decomposeH0,rad1 (B1) into the following subspaces,

H0,rad1 (B1) =Hk⊕Hk, (2.5) whereHk is finite dimensional defined by

Hk= [e1, . . . , ek]. (2.6) ForuinH0,rad1 (B1), letu=uk+u, whereuk ∈Hk andu∈(Hk). We note that

Z

B1

∇u∇ukdx−λ Z

B1

|x|µuukdx=kukk2−λkukk22,|x|µ, (2.7) Z

B1

∇u∇udx−λ Z

B1

|x|µuudx=kuk2−λkuk22,|x|µ. (2.8) By (2.3) and (2.8), we can see that

hJλ(um), umi=kumk2−λkumk22,|x|µ− Z

B1

|x|α|um|2α−2umumdx=o(1)kumk.

Then, from the variational characterization ofλk+1, the Holder and Young inequal- ities, and (2.4), we obtain

1− λ

λk+1

kumk2

≤ Z

B1

|x|α|um|2α−2umumdx+o(1)kumk

≤Z

B1

|x|α|um|2αdx

2 α−1

2 α Z

B1

|x|α|um|2αdx21 α

≤Z

B1

|x|α|um|2αdx2/2α

+cZ

B1

|x|α|um|2αdx

2(2 α−1) 2

α +o(1)kumk

≤kumk2+c

Z

B1

|x|α|um|2αdx

2(2 α−1) 2

α +ckumk.

By (2.4) and [32, Compactness Lemma] which guarantees the compact embedding ofH0,rad1 (B1) inLz(B1,|x|α) for 2≤z <2α, we have

kumk2≤(c+ckumk)

2(2 α−1) 2

α +ckumk. (2.9)

For ukm ∈ Hk, using the variational characterization of λk, similar to (2.9), we obtain

kukmk2≤(c+ckumk)

2(2 α−1) 2

α +ckukmk. (2.10)

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By summing the inequalities in (2.9) and (2.10), we have kumk2≤(C+Ckumk)

2(2 α−1) 2

α +Ckumk,

which proves the boundedness of the sequence (um) inH0,rad1 (B1) as desired.

Lastly, we considerλ=λk for some k∈N. We use the decomposition

H0,rad1 (B1) =Hk−1⊕Hk⊕Eλk, (2.11) whereEλk is the eigenspace associated with eigenvalueλk. For the sequence (um) inH0,rad1 (B1), we have

um=uk−1m +um+wm=vm+wm, whereuk−1m ∈Hk−1,um∈(Hk),vm=uk−1m +umandwm=Pl

i=1yi,mei,λk∈Eλk, whereei,λk is an eigenfunction associated withλk for 1≤i≤l,lis the multiplicity ofλk, andwmcan be consider different from 0 for allm∈N. Note thatkwmk ≤ym, whereym=lmax{|yi,m|; 1≤i≤l}. Using arguments similar to those used in (2.9) and (2.10), we conclude that

kvmk2≤C(1 +kumk)

2(2 α−1) 2

α +Ckvmk. (2.12)

We can assumekumk ≥1 (ifkumk ≤1, the sequence (um) is bounded inH0,rad1 (B1)) and, sincekumk ≤ kvmk+ym, by (2.12), we obtain

kvmk2≤C(kvmk+ym)

2(2 α−1) 2

α +Ckvmk. (2.13)

If ym is bounded, from (2.13), we have that (vm) is bounded in H0,rad1 (B1) and, consequently, (um) is bounded inH0,rad1 (B1). Now let us assumeym→+∞. Using (2.13), we have

kvm

ym

k2≤Ch(kvmk+ym)

(2 α−1)

2 α

ym

i2 + C

ym

kvm

ym

k

≤Ch 1 y1−

(2 α−1)

2

m α

kvm ym

k

(2 α−1) 2

α + 1

y1−

(2 α−1)

2

m α

i2

+ C ym

kvm ym

k.

(2.14)

Thus, we obtain

kvm

ym

k2≤Ckvm

ym

k

2(2 α−1) 2

α +Ckvm

ym

k+C, which implies the sequence{vym

m}being bounded because(2α2−1) α

<1, and, by (2.14), kvym

mk →0 asm→0.

Therefore, possibly up to a subsequence,vm/ym→0 a.e. inB1and strongly in Lq(B1,|x|α), 1≤q <2α. Notice that

hJλ0(um),wm

ymi= 1 y2m

Z

B1

|∇wm|2dx−λ Z

B1

|x|µwm2 dx

− Z

B1

|x|α|um|2α−1wm

ym

dx=o(1)

(2.15)

and sincewm∈Eλk, we have hJλ0(um),wm

ym

i=− Z

B1

|x|α|um|2α−1wm ym

dx=o(1). (2.16)

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Thus, we have Z

B1

|x|α|um

ym|2α−2um

ymwmdx= 1 y2mα−1

Z

B1

|x|α|um|2α−2um

wm

ym dx→0 (2.17) as n → ∞. Note, since um =vm+wm, we have that uym

m → w0 in Lq(B1,|x|α) for all 1 ≤ q < 2α and a.e. in B1 with w0 ∈ Eλ

k \ {0}. So, by the Dominated Convergence Theorem and using (2.17), it follows that

Z

B1

|x|α|um

ym

|2α−2um

ym

wm

ym

dx→ Z

B1

|x|α|w0|2αdx= 0 (2.18) which is a contradiction. Soymis bounded and, consequently, (um) is also bounded

inH0,rad1 (B1).

We need to show that the minimax levels are below a suitable constant. For this purpose, we need an estimate that allows us to simplify some calculations needed ahead. Initially, we consider a Palais-Smale sequence (um); thus, by Lemma 2.2, we may assume that (eventually passing to a subsequence)

um* u∈H0,rad1 (B1),

um→u∈Lp(B1,|x|α) for anyp∈[1,2α[, um→u∈Lp(B1,|x|µ) for anyp∈[1,2α[, ifµ≥α,

um→u a.e. inB1.

(2.19)

To check thatuis a solution for (1.1), we need the following lemma.

Lemma 2.3. Let (um)be a(P S)c sequence inH0,rad1 (B1), with c < 2 +α

2(N+α)S(N+α)/(2+α)

α ,

and letvm=um−u. Then vm→0strongly in H0,rad1 (B1).

Proof. By Lemma 2.2, kumk is bounded, so from (2.19), u is a weak solution of (1.1). Then, by (2.3) we have

kuk2−λkuk22,|x|µ− Z

B1

|x|α|u|2αdx= 0. (2.20) By the Br´ezis-Lieb Lemma [8], it follows that

Z

B1

|x|α|um|2αdx= Z

B1

|x|α|vm|2αdx+ Z

B1

|x|α|u|2αdx+o(1). (2.21) On the other hand, sinceH0,rad1 (B1) is a Hilbert Space, we obtain

kumk2=kvmk2+kuk2+o(1). (2.22) By (2.2), (2.21), and (2.22), asum→uin L2(B1,|x|µ), we obtain

c+o(1) =Jλ(um)

=Jλ(u) +1

2kvmk2−λ

2kvmk22,|x|µ − 1 2α

Z

B1

|x|α|vm|2αdx+o(1)

=Jλ(u) +1

2kvmk2− 1 2α

Z

B1

|x|α|vm|2αdx+o(1).

(2.23)

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SinceJλ0(u) = 0 andkvmk22,|x|µ =o(1), we conclude that hJλ0(um), vmi=kvmk2

Z

B1

|x|α|vm|2αdx+o(1).

Then

kvmk2= Z

B1

|x|α|vm|2αdx+o(1). (2.24) Now, by (2.3) and takingumas test function, we note that

Z

B1

|x|α|um|2αdx=kumk2−λkumk22,µ+o(1).

So, asum→uinL2(B1,|x|µ) and using (2.22), we obtain Jλ(um) =1

2(kumk2−λkumk22,|µ|)− 1 2α

Z

B1

|x|α|um|2αdx

=1

2(kumk2−λkumk22,|µ|)− 1

2α(kumk2−λkumk22,µ+o(1))

= 2 +α

2(N+α)(kumk2−λkumk22,|x|µ) +o(1)

= 2 +α

2(N+α)(kuk2−λkuk22,|x|µ+kvmk2) +o(1).

(2.25)

From (2.20), we conclude that

kuk2−λkuk22,|x|µ ≥0. (2.26)

Thus, by (2.25) and (2.26), we have kvmk2≤ 2(N+α)

2 +α Jλ(um) +o(1).

By (2.2), sincec < 2(N2+α+α)S(N+α)/(2+α)

α , formsufficiently large we obtain

kvmk2≤c+o(1)< Sα(N+α)/(2+α). (2.27) From (1.6) and (2.24), we obtain

kvmk2≤S−2

α/2

α kvmk2α+o(1), which implies

kvmk2(S2α/2− kvmk2α−2)≤o(1).

This and (2.27) imply thatvm→0 strongly inH0,rad1 (B1).

3. Geometric conditions

Here we prove thatJλsatisfies the geometric condition of Theorem 2.1. Firstly, givenλ >0, we defineλ+= min{λj : λ < λj}and set

H1=⊕[ej]λ

j≥λ+

H0,rad1 (B1)

H2= [e1, . . . , ej]λ

j+. (3.1) Lemma 3.1. There exist δ, ρ >0such that, foru∈H1,

Jλ(u)≥δ if kuk=ρ.

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Proof. Let us takeu∈H1, by the variational characterization ofλ+ we obtain that Jλ(u)≥1

2 1− λ λ+

kuk2−Ckuk2α≥δ >0

whenkuk=ρwithρ >0 small enough.

4. Estimates of minimax levels

In this section, we obtain some estimates to show that the minimax levels are below an appropriate constant in order to recover a similar compactness property for the functionalJλ.

First, letr∈(0,1) and Br={x∈RN :|x| ≤r}. We takeξr∈C0(Br,[0,1]), a radial cut-off function such thatξr= 1 inBr/2 and|∇ξr| ≤4/r, and set ur(x) = ξr(x)u(x). In [3, Proof of Theorem 3.3] were obtained the following estimates of Br´ezis-Nirenberg type [9, Lemma 1.2], which also can be found in [3, 21].

Lemma 4.1. Let K1, K2 and K3 be positive constants. For fixed r ∈ (0,1) and µ, α≥0 and >0 small enough, we have

(a) kurk2=Sα(N+α)/(2+α)+O (N−2)/(2+α)

; (b) kurk22α

α,|x|α =Sα(N+α)/(2+α)+O (N+α)/(2+α)

; (c)

kurk22,|x|µ =





K1(2+µ)/(2+α) if N >4 +µ;

K1(2+µ)/(2+α)|log|+O (2+µ)/(2+α)

if N = 4 +µ;

K1(N−2)/(2+α) if N <4 +µ;

(d) kurk1,|x|µ ≤K2(N−2)/[2(2+α)]; (e) kurk22α−1

α−1,|x|α ≤K3(N−2)/[2(2+α)].

Now we shall prove some main technical lemmas. First of all, we define W(, r) ={u∈H0,rad1 (B1);u=u+tur, u∈H2, t∈R}.

Remark 4.2. Since u is solution for (1.8), ur 6∈ [e1, e2, . . . , ek] for any k ∈ N. Thus,W(, r)6=H2.

Lemma 4.3. If u∈W(, r), then for >0 sufficiently small kuk22α

α,|x|α≥ kturk22α

α,|x|α−Ct2α(N−2)(N+α)/[(N+2α+2)(2+α)] (4.1) for any t∈R.

Proof. Note that from kuk22α

α,|x|α= 2α Z

B1

|x|αdx Z u

0

|s|2α−2sds, (4.2) and the Mean Value Theorem, we obtain

kuk22α

α,|x|α− kturk22α

α,|x|α− kuk22α α,|x|α

= 2α Z 1

0

ds Z

B1

|x|α[|tur+su|2α−2(tur+su)− |su|2α−2su]udx

= 2α(2α−1) Z 1

0

ds Z

B1

|x|α|tur+τ su|2α−2tur·udx

(4.3)

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whereτ =τ(x) is a measurable function such that 0< τ(x)<1.

Using (4.3) and sinceu∈H2, which is a finite-dimension subspace, we obtain kuk22α

α,|x|α− kturk22α

α,|x|α− kuk22α α,|x|α

≤C Z 1

0

ds Z

B1

|x|α(|tur|2α−1|u|+|u|2α−1|tur|) dx

≤Ckturk22α−1

α−1,|x|αkuk+kuk2∞,|x|α−1αkturk1

≤Ckturk22α−1

α−1,|x|αkuk2+kuk22α−1

α,|x|αkturk1,

(4.4)

where C is positive constant. From (4.4), the Young inequality and the items (d) and (e) of Lemma 4.1, we have that

kuk22α

α,|x|α− kturk22α

α,|x|α− kuk22α α,|x|α

≤Ct2α−1(N−2)/(2(2+α))kuk2+N+ 2 + 2α 2(N+α) kuk22α

α,|x|α+Ct2α(N+α)/(2+α). Finally, again by the Young inequality, we have

kuk22α

α,|x|α− kturk22α

α,|x|α− kuk22α α,|x|α

≤Ct2α−1

(N−2)

(2(2+α))kuk2α,|x|α+N+ 2 + 2α 2(N+α) kuk22α

α,|x|α+Ct2α

(N+α) (2+α)

≤Ct2α

(N−2)(N+α) [(N+2α+2)(2+a)] + 1

2αkuk22α

α,|x|α+N+ 2 + 2α 2(N+α) kuk22α

α,|x|α+Ct2α(N+α)(2+α)

=Ct2α

(N−2)(N+α)

[(N+2α+2)(2+α)] +kuk22α

α,|x|α+Ct2α(N+α)(2+α)

≤Ct2α

(N−2)(N+α)

[(N+2α+2)(2+α)] +kuk22α α,|x|α.

for >0 small enough. The proof is complete.

Lemma 4.4. For >0 sufficiently small, we have kurk2−λkurk22,|x|µ

kurk22 α,|x|α

=





Sα−C(2+µ)/(2+α) if N >4 +µ;

Sα−C(2+µ)/(2+α)|log()|+O((2+µ)/(2+α)) if N= 4 +µ;

Sα+(N−2)/(2+α)(O(1)−λC) if N <4 +µ.

(4.5)

The statement of the lemma above is obtained from (a)–(c) in Lemma 4.1.

Now we separate our study into three cases: non-resonant case assuming (1.9), and consequently, N >4 +µ, or N = 4 +µ; resonant case when (1.9) holds; and non-resonant case with N < 4 +µ. This separation occurs because to prove the (P S)c condition forc below an appropriate constant whenλ=λj for some j∈N, we need to haveN >4 +µ. When N <4 +µ, it is crucial to assume in addition thatλis sufficiently large to prove the (P S)c condition.

4.1. Non-resonant case withN≥4 +µ. Initially, we consider the non-resonant case and we obtain the following results.

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Lemma 4.5. Assume (1.9), for sufficiently small and positive. If λ6= λj, for every j∈N, then

sup

W(,r)

Jλ(u)< (2 +α)

2(N+α)S(N+α)/(2+α)

α . (4.6)

Proof. Note that for fixedu∈H0,rad1 (B1) withu6= 0, we obtain sup

t

Jλ(tu) = (2 +α) 2(N+α)

kuk2−λkuk22,|x|µ

kuk22 α,|x|α

(N+α)/(2+α)

. (4.7)

Since

sup{Jλ(u) :u∈W()\ {0}}

= supn

Jλ(kuk2α,|x|α

u kuk2α,|x|α

) :u∈W(, r)\ {0}o

≤sup{Jλ(tu) :u∈W(, r)\ {0}with kuk2α,|x|α = 1 andt∈R}, to show that (4.6) is true, we need to estimate

sup

u∈W(,r),kuk2 α ,|x|α=1

kuk2−λkuk22,|x|µ . (4.8) Letu=u+tur ∈W(, r) with kuk2α,|x|α = 1. By (4.1) and item (b) of Lemma 4.1, forsmall enough, we have

1 =kuk22α α,|x|α

≥ kturk22α

α,|x|α−Ct2α(N−2)(N+α)/(N+2α+2)(2+α)

=t2α

S(N+α)/(2+α)

α +O (N−2)/(2+α)

−Ct2α(N−2)(N+α)/(N+2α+2)(2+α)

=t2α

S(N+α)/(2+α)

α +O (N−2)(N+α)/(N+2α+2)(2+α) .

Thus, we can conclude that t is bounded for small positive . From item (e) in Lemma 4.1, the variational characterization ofλj and Green’s Theorem, we obtain

kuk2−λkuk22,|x|µ

≤ kturk2−λkturk22,|x|µ+kuk2−λkuk22,|x|µ

+ 2 Z

B1

{|tur| |∆u|+λ|x|µ|u||tur|}dx

≤ kturk2−λkturk22,|x|µ+kuk2−λkuk22,|x|µ+C{kturk1k∆uk

+λkukkturk1,|x|µ}

≤ kturk2−λkturk22,|x|µ+kuk2−λkuk22,|x|µ+Ckuk2(N−2)/[2(2+α)]

≤ kturk2−λkturk22,|x|µ

kturk22 α,|x|α

kturk22

α,|x|α+ (λ−λ)kuk22,|x|µ

+Ckuk2,|x|µ(N−2)/[2(2+α)],

(4.9)

whereλ= max{λjj < λ}.

(13)

Now we defineA(u, , c) = (λ−λ)kuk22,|x|µ+Ckuk2,|x|µ(N−2)/[2(2+α)]. No- tice that

A(u, , c)≤0 or A(u, , c)≤ c2

λ−λ(N−2)/(2+α). (4.10) On the other hand by (4.1) and the boundedness oft, we obtain

kturk22

α,|x|α ≤ 1 +C(N−2)(N+α)/[(N+2α+2)(2+α)]2/2α

≤1 +C(N−2)(N+α)/[(N+2α+2)(2+α)].

(4.11) From (1.9), we obtainN >4 +µ, then using (4.5), (4.9), (4.10) and (4.11), we have

kuk2−λkuk22,|x|µ

Sα−C(2+µ)/(2+α) 1 +C[(N−2)(N+α)]/[(N+2α+2)(2+α)]

+A(u, , c).

(4.12) By (1.9), we also conclude that

(N−2)(N+α)

(N+ 2α+ 2)(2 +α) > 2 +µ 2 +α.

Thus,kuk2−λkuk22,|x|µ < Sα forpositive and small enough.

Lemma 4.6. For > 0 sufficiently small and N = 4 +µ, if λ 6= λj, for every j∈N, then

sup

W(,r)

Jλ(u)< (2 +α)

2(N+α)S(N+α)/(2+α)

α . (4.13)

Proof. WhenN = 4+µ, as for (4.12), from (4.5), (4.9), (4.10) and (4.11), we obtain kuk2−λkuk22,|x|µ

Sα−C(2+µ)/(2+α)|log()|+O((2+µ)/(2+α))

×

1 +C[(2+µ+α)(4+µ+α)]/[(6+µ+2α)(2+α)]

+A(u, , c).

Because of the behavior of|log()| near zero, for small enough we conclude the

result.

4.2. Resonant case with N >4 +µ. Now we consider, λ=λj for somej∈N. We will find estimates which will help us in obtaining a result similar to Lemma 4.5 for the resonant case when (1.9) is satisfied.

First, we denote byPj the projector on the eigenspace corresponding toλj and set

r=ur−Pjur. (4.14) Thus, by item (d) in Lemma 4.1, we have

kPjurk22,|x|µ =X

k

Z

B1

|x|µekurdx2

≤Ckurk21,|x|µ ≤C(N−2)/(2+α). (4.15) Consequently, asPjur is in a finite dimensional space, we obtain

kPjurk∞,|x|µ ≤C(N−2)/2[(2+α)]. (4.16) Furthermore,

ku˜rk22α

α,|x|α− kurk22α α,|x|α

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