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の-Subgroup of finite nilpotent Groups

       ShSsaburo FUJITA

(Se・。山la・r of Matke。lati。'、Facidりof Literature iuid Scie、lce、Kochi uni、erstり)

   In this note, we shall study some properties of the I/'-subgroups of finite nilpotent groups・

   NOT八TIONS : G denotes a group of finite order. ψ(G),£)(G)andZ (G) denote the ψ-subgroup, the commutator subgroup and the centre of a group G respectively.φs(G) denotes the intersection of a group G with its maximal subgroups containing N.    Theorem 1. The 0 -subgroup of a finite group G is the intersection of normal subgroups y of G such that the φ・subgroup of the factor group G/N is a unit subgroup of G/N.

   Proof. It is evident that 0n(.G) contains N and 0iG). Since N/N=φ(GIN)⊇

Nφ(G)IN and also φ(GZΦ(G))=φ(G)/ゆ(G),we get nN=φ(G).

   Corollary 1. Let G be nilpotent, then the factor group G/N is the direct pro-duct of groups of prime order if and only if y contains the φ-subgroup of G.

   Proof. Since G is nilpotent, Gμ〉(G) is abelian and ψ(GZΦ(G))=φ(G)/ψ(G). Hence GZの(G) is the direct product of groups of prime order''. If N contains 0(G), then, from G/jVaG/ψ(G)/y/の(G), it follows that G/N "isthe direct product of groups of prime order.

   Conversely, if G/N is the direct product of groups of prime ordec, thenの(G/N) = N/N and therefore jv2ψ(G)from Theorem 1.

   Theorem 2. If a normal subgroup y of G is contained in the 0 -subgroup and the factor group G/N is cyclic, then G is cyclic.

   Proof. We put GIN= [aN], then we have G={a]N. Since iV£Φ(G), follows G={a].

   Theorem 3.H a normal subgroup N of G is contained in the centre and the factor group G/N is nilpotent, then G is nilpotent.

   Proof. If y is contained in 0{G), then, by assumption, 0(G/N)=の(G)ZN , contains£)(G/N)=ND(G)/N and so ゆ(G)三£)(G). Hence G is nilpotent. If y is not contained in 0(G), then G has a maximal subgroup G*1 such that G = G*iN and so G*1 is normal in G since jVΞZ(G).From G/G*i=N/G*,nN, it follows that G/G*1 is abelian and so we get G*1ユD(G). Let Gi be a maximal subgroup of G containing N. Since GJN3.0(Gil\f)⊇£)(GIN), we have G1ユ£)(G).Thus we find that£)(G)is con-tained in the intersection of all maximal subgroups,, that is, £)(G)旦ψ(G)and hence G

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  40      J知大学学術研究報告第9巻 自然科学 I 第5号  is nilpotent.

    Corollary 2. H a normal subgroup・y of G is contained in the centre, the  factor group G/N is abelian and 0(.G)nN=[, then G is abelian.

    Proof. From Theorem 3,G is nilpotent and so ゆ(G)ユD(G).AsG/N'is abelian,  7Vユ£)(G). Thus£)(G)辰砂(G)nMthat is, £)(G)=1.

    Theorem 4. Let G be nilpotent and H its subgroup, 山enψ(G)こゆ(と).

    Proof. Let 1⊂H=H,⊂H2⊂…‥⊂Hk-i⊂j飛=G be a normal chain. Thenψ(仔)

 is norma卜n Hui and so ゆ(昂)辰の(昂。i), 7:= 1,2,。‥‥‥,た−1.2)Thus we get ψ(G)  ユの(耳).

    Theorem 5. If G is nil potent and N 1ts normal subgroup, thenのn(G) = N0(G).     PROOI・. If N is contained in の(G), thenのw(G)=Nφ(G) holds clearly. If N  is not contained in 0(G). then G has a possible minimal subgroup H such as G = NH. Let  G, be a maximal subgroup of G containing N, then C = GiH. From G/Gl1召/GInH,  it follows that Hi = G,r\H is a maximal subgroup of H and G.,= NH,.Conversely,  G*,=NH*1 whete H*l is an arbitrary maximal subgroup of H, is a maximal subgroup  of G containing N. As the maximality of NH, and G*l are showed in the same way, we  shall show about G*,. If yn尽⊃NOH*,, then (H*,・.NnH*1)=(μ:Nf]H) and so(G*1  :y)=(G‘:N). This conflicts with G*1⊂G and hence Nr\H=Nnだ*,. Then (/-/・.NnH):  (H*1:jVnH*1)=(G:N):(G*1:AO, and therefore G*1 is a maximal subgroup of G.  Thus we have 0n(G) = Nの(耳)。On the other hand, it is evident that のn(G)ユN0(G)  and by Theorem 4,の(G)ユ0(.H) holds. Thus we getφ。(G)=Nの(G).

    Corollary 3. If there is a homomorphism of G onto G' and G is nil potent- then there is a homomorphism of <D{G) onto 0(Gり.

    Proof. Let Khe the kernel of the homomorphism of G onto G≒then G∼GノK三  C. From Theorem 5,it follows that ψ(G/K)=Kφ(G)/Kaψ(G)/尺∩の(G) and there- fore 0(G)∼ψ(G/K)aの【Gり.

    Theorem 6. Let G be ni】potentand N its normal subgroupバfの(G)ny=の(yV),  山en the maxima! subgroups of y ・are all normal in G.

    Proof. Let Nl be an arbitrary maximaトsubgroup of N and A be the normalizer  of N, in G. H every maximal subgroup Gにof G containing iV, a】ways contains N,

 ・hen by Theorem 5,ψ肖(A)=N1φ(j)ユy would h6ぼ Then we could have an ele・

. merit, n of y such that 7zEの(G) and ・,z百A', and so φ(N)百n, this conflicts with ψ(G)  ny=φ(N). Therefore G has a maximal subgroup G, such that G=NG,, C:石⊃N,.  Since y and Gi are normal in G, yt=Glny is normaトin G.

    Corollary 4. Let G be nilpotent and y its normal subgroup. If 0(G)nA'' =

】, then every subgroup

of 7vis normal

in G.

    Proof.

Letルf be a subgroup

of jV and y≒Noニ)yl⊃y2⊃

sequence

of subgroups of 7V where y, is maχimalin Ah-1.

Since

2) Cf. (1), p. 162

‥‥⊃N.,= M be a

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       旦旦ubgroup of finitenilpotent Groups (S. Fujita)      41 TV, is normal in G by Theorem 6. Then, sinceの(G)∩N1=φ(y1), N, Vs normal in G also. For repeating the argument with N。N。..・・。N。-1 in turn, we see yχfis nor・ mal in G.

   Corollary 5. Let G be nilpotent and y its normal subgroup. If there exists a subgroup H of G such that G=NH, NnH=l, then the maximal subgroups of y are all normal in G if and only if 0(G)nN=0(.N).

   Proof. l£(D(G)nN=の(AO, then by Theorem 6 the maximal subgroups of N are all normal in G.

  Conversely, if the maximal subgroups of y are all normal in G, then N^H and NH, where Ni andH, are arbitrary maximal subgroups of y and H lespectively, are

maximal in G. Hence we get ゆ(G)Ξ(Z)(N)Handゆ(G)こNψ(H)and so ゆ(G)瓜ψ

(N)0(H'). On the other hand, by Theorem 4, ψ(G)2の(jV)の(H).ヽThus we have ゆ

(G)=の(N)の(H) and so ゆ(G)nN=の(y).

   Corollary 6. Let the normal subgroup y of a nilpotent group G be the direct product of groups of prime order which are normal in G・Then G has a subgroup 77 such that G=NH,  Nr\H=[ if and only if 0(.G)nN = i.

   Proof. By assumption about j\≒ φ(N)=1 and the maximal subgroups of N are all normal in C. Hence by Corollary 5,ψ(G)nN=1 holds.

   Converse】y, since y is abeliari andの(G)nN=1,G has a subgroup H such that G=NH,Nn耳=13).

   Theorem 7. Let y be a nil potent normal subgroup of G and N (Z0(G), then there exists a subgroup 尺such that G=NK,  N∩尺こゆ(G).

   Proof. Since NΦ(G) is normal in G, 0(NΦ(G)) is normal in G. Hence

の(G/の(G))Ξ0(N0CG)/の(G))and so  φ(yゆ(G)/の(G))=ゆ(G)/の(G)・holds.

yの(G)/の(G) is nilpotent and so Nの(G)/の(G)is abelian. Moreoverの(GZΦ(G))∩ yの(G)Z(1)(G)=の(G)/の(G)so we. have a factor groupKid)(G) such that G/の(G)=

N0(G)/<1>(G:)・尺/の(G), Nφ(G)∩尺=・0(G). This shows G = NK, Nn尺瓜ψ(G).

田岡

       References

W. Gaschijtz, Uber die (P-Untergruppe endlicher Gruppen. Math. Zeit., vol. 58, 160-170(1953) H. Zassenhaus, Lehrbuch der Gruppentheorie, vol. 1. (1937)

(Received June 25, 1960)

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