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WEAK AND STRONG CONVERGENCE OF FINITE FAMILY WITH ERRORS OF NONEXPANSIVE NONSELF-MAPPINGS

S. PLUBTIENG AND K. UNGCHITTRAKOOL

Received 27 September 2005; Revised 5 May 2006; Accepted 8 May 2006

We are concerned with the study of a multistep iterative scheme with errors involving a finite family of nonexpansive nonself-mappings. We approximate the common fixed points of a finite family of nonexpansive nonself-mappings by weak and strong conver- gence of the scheme in a uniformly convex Banach space. Our results extend and improve some recent results, Shahzad (2005) and many others.

Copyright © 2006 S. Plubtieng and K. Ungchittrakool. This is an open access article dis- tributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is prop- erly cited.

1. Introduction

LetKbe a subset of a real normed linear spaceEand letTbe a self-mapping onK.T is said to be nonexpansive providedTxT yxyfor allx,yK.

Fixed-point iteration process for nonexpansive mappings in Banach spaces includ- ing Mann and Ishikawa iteration processes has been studied extensively by many au- thors to solve the nonlinear operator equations in Hilbert spaces and Banach spaces;

see [3,7,10,11,15,16]. Tan and Xu [15] introduced and studied a modified Ishikawa process to approximate fixed points of nonexpansive mappings defined on nonempty closed convex bounded subsets of a uniformly convex Banach spaceE. Five years later, Xu [18] introduced iterative schemes known as Mann iterative scheme with errors and Ishikawa iterative scheme with errors. Takahashi and Tamura [14] introduced and stud- ied a generalization of Ishikawa iterative schemes for a pair of nonexpansive mappings in Banach spaces. Recently, Khan and Fukhar-ud-din [6] extended their scheme to the modified Ishikawa iterative schemes with errors for two mappings and gave weak and strong convergence theorems. On the other hand, iterative techniques for approximat- ing fixed points of nonexpansive nonself-mappings have been studied by various au- thors; see [4,8,13,19]. Shahzad [12] introduced and studied an iteration scheme for

Hindawi Publishing Corporation Fixed Point Theory and Applications Volume 2006, Article ID 81493, Pages1–12 DOI10.1155/FPTA/2006/81493

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approximating a fixed point of nonexpansive nonself-mappings (when such a fixed point exists) and gave some strong and weak convergence theorems for such mappings.

Inspired and motivated by these facts, we introduce and study a multistep iterative scheme with errors for a finite family of nonexpansive nonself-mappings. Our schemes can be viewed as an extension for two-step iterative schemes of Shahzad [12]. The scheme is defined as follows.

LetK be a nonempty closed convex subset of a uniformly convex Banach space E, which is also a nonexpansive retract ofE. And letT1,T2,. . .,TN:KEbe nonexpansive mappings, the following iteration scheme is studied:

x1n=Pα1nT1xn+β1nxn+γ1nu1n, x2n=Pα2nT2xn1+β2nxn+γ2nu2n,

... ...

xn+1=xNn =PαNnTNxnN1 +βNnxn+γnNuNn

(1.1)

withx1K,n1, whereP is a nonexpansive retraction with respect to K and{α1n}, {α2n},. . .,{αNn},{β1n},{β2n},. . .,{βNn},{γ1n},{γ2n},. . .,{γNn}are sequences in [0, 1] withαin+ βin+γin=1 for alli=1, 2,. . .,N, and{u1n},{u2n},. . .,{uNn}are bounded sequences inK.

ForN=2,T1=T2T,βn=α1n,αn=α2n, andγ1n=γ2n0, then (1.1) reduces to the scheme for a mapping defined by Shahzad [12]:

x1=xK,

xn+1=P1αnxn+αnTP1βnxn+βnTxn, (1.2) where{αn},{βn}are sequences in [0, 1].

For N=2,T1,T2:K K,T1=T, T2=S, and yn=x1n, then (1.1) reduces to the scheme with errors for two mappings defined by

x1=xK,

yn=α1nTxn+βn1xn+γ1nu1n, xn+1=x2n=α2nSyn+β2nxn+γ2nu2n,

(1.3)

where{α1n},{α2n},{β1n},{β2n},{γn1},{γ2n}are sequences in [0, 1] withα1n+β1n+γn1=1=α2n+ β2n+γ2nand{u1n},{u2n}are bounded sequences inK.

It is our purpose in this paper to establish several weak and strong convergence theorems of the multistep iterative scheme with errors for a finite family of nonexpansive nonself-mappings. More precisely, we prove weak convergence of these implicit iteration

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processes in a uniformly convex Banach space which has the Kadec-Klee property. The results presented in this paper extend and improve the corresponding ones announced by Shahzad [12], and many others.

2. Preliminaries

In this section, we recall the well-known concepts and results.

LetEbe a real Banach space. A subsetKofEis said to be a retract ofEif there exists a continuous mapP:EKsuch thatPx=xfor allxK. A mapP:EEis said to be a retraction ifP2=P. It follows that if a mapPis a retraction, thenP y=yfor all yin the range ofP. A mappingT:KEis called demiclosed with respect toyEif for each sequence{xn}inKand eachxE,xnxandTxnyimply thatxKandTx=y. A Banach spaceEis said to satisfy Opial’s condition [9] if for any sequence{xn}inE,xnx implies that

lim sup

n→∞

xnx<lim sup

n→∞

xny (2.1)

for allyEwithx=y. A Banach spaceEis said to have the Kadec-Klee property if for every sequence{xn}inE,xnxandxnxtogether implyxnx0. A family {Ti:i=1, 2,. . .,N}ofNnonself-mappings ofK(i.e.,Ti:KE) withF= Ni=1F(Ti)=∅ is said to satisfy condition (B) onKif there is a nondecreasing functionf : [0,)[0,) with f(0)=0 andf(r)>0 for allr(0,) such that for allxK,

1maxiNxTixfd(x,F). (2.2) The family{Ti:i=1, 2,. . .,N} is said to satisfy condition (AN) if (2.2) is replaced by 1/NNi=1xTixf(d(x,F)) for allxK. Note that condition (B) reduces to condi- tion (AN) whenxT1x = xT2x = ··· = xTNx.

A mappingT:KEis called semicompact if any sequence{xn}inKsatisfyingxn Txn0 asn→ ∞has a convergent subsequence.

Lemma 2.1 (Tan and Xu [15]). Let{sn},{tn}be two nonnegative sequences satisfying

sn+1sn+tn, n1. (2.3)

Ifn=1tn<, then limn→∞snexists. Moreover, if there exists a subsequence{snj}of{sn} such thatsnj0 as j→ ∞, thensn0 asn→ ∞.

Lemma 2.2 (Xu [17]). Let p >1 andR >0 be two fixed numbers andEa Banach space.

ThenEis uniformly convex if and only if there exists a continuous, strictly increasing, and convex function g: [0,)[0,) withg(0)=0 such thatλx+ (1λ)ypλxp+ (1λ)ypWp(λ)g(xy) for allx,yBR(0)= {xE:xR}, andλ[0, 1], whereWp(λ)=λ(1λ)p+λp(1λ).

Lemma 2.3 (Kaczor [5]). LetEbe a real reflexive Banach space such that its dualEhas the Kadec-Klee property. Let{xn}be a bounded sequence inEandx,yωw(xn); hereωw(xn)

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denote the set of all weak subsequential limits of{xn}. Suppose limn→∞txn+(1t)xy exists for allt[0, 1]. Thenx=y.

Lemma 2.4 (Browder [1]). LetEbe a uniformly convex Banach space,Ka nonempty closed convex subset ofE, andT:KEa nonexpansive mapping. ThenIT is demiclosed at zero.

3. Main results

In this section, we prove weak and strong convergence theorems of the iterative scheme given in (1.1) for a finite family of nonexpansive mappings in a Banach space. In order to prove our main results, the following lemmas are needed.

Lemma 3.1. Let E be a uniformly convex Banach space andK a nonempty closed con- vex subset of E which is also a nonexpansive retract of E. Let T1,T2,. . .,TN:KE be nonexpansive mappings. Let {xn} be the sequence defined by (1.1) with n=1γin< for eachi=1, 2,. . .,N. If Ni=1F(Ti)=, then limn→∞xnxexists for allx Ni=1F(Ti).

Proof. For eachn1, we note that

x1nxα1nT1xnx+β1nxnx+γ1nu1nx α1nxnx+β1nxnx+γ1nu1nx xnx+dn0,

(3.1)

wheredn0=γ1nu1nx. Sincen=1γ1n<,n=1d0n<. Next, we note that x2nxα2nT2xn1x+β2nxnx+γ2nu2nx

α2nxn1x+β2nxnx+γ2nu2nx

=

α2n+β2nxnx+α2ndn0+γn2u2nx xnx+dn1,

(3.2)

wheredn1=α2ndn0+γ2nu2nx. Sincen=1dn0<andn=1γ2n<,n=1d1n<. Simi- larly, we have

x3nxα3nxn2x+β3nxnx+γ3nu3nx α3nxnx+dn1+β3nxnx+γ3nu3nx xnx+α3ndn1+γ3nu3nx=xnx+dn2,

(3.3)

wheredn2=α3ndn1+γ3nu3nx, son=1d2n<.

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By continuing the above method, there exists a nonnegative real sequence{dni1}such thatn=1dni1<and

xnixxnx+dni1, n1,i=1, 2,. . .,N. (3.4) Thusxn+1x = xNn xxnx+dnN1for allnN. Hence, byLemma 2.1,

limn→∞xnxexists. This completes the proof.

Lemma 3.2. LetEbe a uniformly convex Banach space andK a nonempty closed convex subset ofEwhich is also a nonexpansive retract ofE. LetT1,T2,. . .,TN:KEbe nonex- pansive mappings. Let{xn}be the sequence defined by (1.1) withn=1γni <and{αin} ⊆ [ε, 1ε] for alli=1, 2,. . .,N, for someε(0, 1). If Ni=1F(Ti)=, then limn→∞xn Tixn =0 for alli=1, 2,. . .,N.

Proof. Letx Ni=1F(Ti). Then, by Lemma 3.1, limn→∞xnxexists. Let limn→∞

xnx =r. Ifr=0, then by the continuity of eachTi the conclusion follows. Sup- pose thatr >0. Firstly, we are now to show that limn→∞TNxnxn =0. Since{xn}and {uin}are bounded for alli=1, 2,. . .,N, there existsR >0 such thatxnx+γin(uinxn), Tixni1x+γin(uinxn)BR(0) for alln1 and for alli=1, 2,. . .,N. UsingLemma 2.2, we have

xNn x2αNnTNxNn1+βNnxn+γNnuNnx2

=αNnTNxNn1x+γNnuNnxn+1αNnxnx+γNnuNn xn2 αNnTNxNn1x+γnNuNnxn2+1αNnxnx+γNnuNn xn2

W2

αNngTNxNn1xn

αNnxNn1x+γnNuNn xn2+1αNnxnx+γNnuNn xn2

W2

αNngTNxNn1xn

αNnxnx+dNn2+γNnuNn xn2 +1αNnxnx+dnN2+γnNuNn xn2

W2

αNngTNxNn1xn

=xnx+λNn22W2

αNngTNxnN1xn,

(3.5) whereλNn2:=dNn2+γNnuNn x. Observe thatε3W2Nn) now (3.5) implies that ε3g(TNxNn1xn)xnx2xn+1x2+ρnN2, where ρNn2:=Nn2xn x2+ (λNn2)2. Sincen=1dNn2<andn=1γNn2<, we getn=1ρNn2<. This implies that limn→∞g(TNxNn1xn)=0. Sinceg is strictly increasing and continuous

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at 0, it follows that limn→∞TNxNn1xn =0. Note that

xnxxnTNxNn1+TNxNn1x xnTNxNn1+xNn1x,

(3.6)

for alln1. Thusr=limn→∞xnxlim infn→∞xNn1xlim supn→∞xnN1 xrand therefore limn→∞xNn1x =r. Using the same argument in the proof above, we have

xNn1x2αNn1xNn2x+γNn1uNn1x2 +1αNn1xnx+γNn1uNn1x2

W2

αNn1gTN1xnN2xn

αNn1xnx+dnN3+γnN1uNn1x2 +1αNn1xnx+dnN3+γNn1uNn1x2

W2

αNn1gTN1xnN2xn xnx2+ρNn3W2

αNn1gTN1xnN2xn.

(3.7)

This implies thatε3g(TN1xNn2xn)xnx2xNn1x2+ρNn3and there- fore limn→∞TN1xnN2xn =0. Thus, we have

xnTNxnxnTNxnN1+TNxnN1TNxn xnTNxnN1+xNn1xn

=xnTNxNn1+PαNn1TN1xNn2+βNn1xn+γnN1uNn1Pxn xnTNxnN1+αNn1xnTN1xNn2+γnN1uNn1xn.

(3.8) Since limn→∞xnTNxnN1 =0, limn→∞xnTN1xNn2 =0, andn=1γNn1<, it follows that limn→∞xnTNxn =0. Similarly, by using the same argument as in the proof above, we have limn→∞xnTN2xNn3 =limn→∞xnTN3xNn4 =,. . .,= limn→∞xnT2x1n=0. This implies that limn→∞xnTN1xn=limn→∞xnTN2xn = ,. . .,=limn→∞xnT3xn =0. It remains to show that

limn→∞xnT1xn=0, limn→∞xnT2xn=0. (3.9)

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