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Electronic Journal of Differential Equations, Vol. 2013 (2013), No. 27, pp. 1–10.

ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu ftp ejde.math.txstate.edu

OSCILLATION OF SOLUTIONS TO NEUTRAL NONLINEAR IMPULSIVE HYPERBOLIC EQUATIONS WITH

SEVERAL DELAYS

JICHEN YANG, ANPING LIU, GUANGJIE LIU

Abstract. In this article, we study oscillatory properties of solutions to neu- tral nonlinear impulsive hyperbolic partial differential equations with several delays. We establish sufficient conditions for oscillation of all solutions.

1. Introduction

The theory of partial differential equations can be applied to many fields, such as to biology, population growth, engineering, generic repression, control theory and climate model. In the last few years, the fundamental theory of partial differen- tial equations with deviating argument has undergone intensive development. The qualitative theory of this class of equations, however, is still in an initial stage of development. Many srudies have been done under the assumption that the state variables and system parameters change continuously. However, one may easily visualize situations in nature where abrupt change such as shock and disasters may occur. These phenomena are short-time perturbations whose duration is negligi- ble in comparison with the duration of the whole evolution process. Consequently, it is natural to assume, in modeling these problems, that these perturbations act instantaneously, that is, in the form of impulses.

In 1991, the first paper [4] on this class of equations was published. However, on oscillation theory of impulsive partial differential equations only a few of papers have been published. Recently, Bainov, Minchev, Liu and Luo [1, 2, 6, 7, 8, 9, 10, 11]

investigated the oscillation of solutions of impulsive partial differential equations with or without deviating argument. But there is a scarcity in the study of oscilla- tion theory of nonlinear impulsive hyperbolic equations of neutral type with several delays.

2000Mathematics Subject Classification. 35B05, 35L70, 35R10, 35R12.

Key words and phrases. Oscillation; hyperbolic equation; impulsive; neutral type; delay.

c

2013 Texas State University - San Marcos.

Submitted October 1, 2012. Published January 27, 2013.

1

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In this article, we discuss oscillatory properties of solutions for the nonlinear impulsive hyperbolic equation of neutral type with several delays.

2

∂t2 h

u(t, x) +

m

X

i=1

giu(t−τi, x)i

=a(t)h(u)∆u−q(t, x)f(u(t, x)) +

l

X

r=1

ar(t)hr(u(t−σr, x))∆u(t−σr, x)

n

X

j=1

qj(t, x)fj(u(t−ρj, x)), t6=tk, (t, x)∈R+×Ω =G,

(1.1)

u(t+k, x) =hk(tk, x, u(tk, x)), k= 1,2, . . . , (1.2) ut(t+k, x) =pk(tk, x, ut(tk, x)), k= 1,2, . . . , (1.3) with the boundary conditions

u= 0, (t, x)∈R+×∂Ω, (1.4)

∂u

∂n+ϕ(t, x)u= 0, (t, x)∈R+×∂Ω, (1.5)

and the initial condition

u(t, x) = Φ(t, x), ∂u(t, x)

∂t = Ψ(t, x), (t, x)∈[−δ,0]×Ω.

Here Ω⊂RN is a bounded domain with boundary ∂Ω smooth enough and nis a unit exterior normal vector of∂Ω, δ= max{τi, σr, ρj}, Φ(t, x)∈C2([−δ,0]×Ω,R), Ψ(t, x)∈C1([−δ,0]×Ω,R).

This article is organized as follows. in Section 2, we study the oscillatory prop- erties of solutions for problems (1.1), (1.4). In Section 3, we discuss oscillatory properties of solutions for problems (1.1), (1.5).

We will use the following conditions:

(H1) a(t), ai(t) ∈ P C(R+,R+), τi, σr, ρj are positive constants, q(t, x), qj(t, x) are functions inC(R+×Ω,¯ (0,∞)),giis a non-negative constant,Pm

i=1gi<

1,i= 1,2, . . . , m,j= 1,2, . . . , n,r= 1,2, . . . , l; whereP C denote the class of functions which are piecewise continuous intwith discontinuities of first kind only att=tk,k= 1,2, . . ., and left continuous att=tk,k= 1,2, . . .. (H2) h(u), hr(u) ∈ C1(R,R), f(u), fr(u) ∈ C(R,R); f(u)/u ≥ C a positive constant, fj(u)/u ≥ Cj a positive constant, u 6= 0; h(0) = 0, hr(0) = 0, uh0(u) ≥ 0, uh0r(u) ≥ 0, ϕ(t, x) ∈ C(R+×∂Ω,R), h(u)ϕ(t, x) ≥ 0, hr(u)ϕ(t−σr, x) ≥ 0, r = 1,2, . . . , l, 0 < t1 < t2 < · · · < tk < . . ., limk→∞tk=∞.

(H3) u(t, x) and their derivativesut(t, x) are piecewise continuous int with dis- continuities of first kind only att=tk,k= 1,2, . . ., and left continuous at t=tk,u(tk, x) =u(tk, x),ut(tk, x) =ut(tk, x),k= 1,2, . . ..

(H4) hk(tk, x, u(tk, x)), pk(tk, x, ut(tk, x)) ∈ P C(R+ ×Ω¯ ×R,R), k = 1,2, . . ., and there exist positive constants ak, ak, bk, bk and bk ≤ak such that for k= 1,2, . . . ,

ak≤ hk(tk, x, η)

η ≤ak, bk≤ pk(tk, x, φ) φ ≤bk.

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Let us construct the sequence {t¯k} ={tk} ∪ {tki} ∪ {tkr} ∪ {tkj}, where tki =tki, tkr =tkr, tkj =tkj and ¯tk <¯tk+1, i= 1,2, . . . , m, r= 1,2, . . . , l,j= 1,2, . . . , n, k= 1,2, . . ..

Definition 1.1. By a solution of problems (1.1), (1.4) ((1.5)) with initial condition, we mean that any functionu(t, x) for which the following conditions are valid:

(1) If−δ≤t≤0, thenu(t, x) = Φ(t, x), ∂u(t,x)∂t = Ψ(t, x).

(2) If 0≤t≤¯t1=t1, then u(t, x) coincides with the solution of the problems (1.1)–(1.3) and (1.4) ((1.5)) with initial condition.

(3) If ¯tk < t≤¯tk+1, ¯tk ∈ {tk} \({tki} ∪ {tkr} ∪ {tkj}), thenu(t, x) coincides with the solution of the problems (1.1)–(1.3) and (1.4) ((1.5)).

(4) If ¯tk< t≤t¯k+1, ¯tk ∈ {tki} ∪ {tkr} ∪ {tkj}, thenu(t, x) satisfies (1.4) ((1.5)) and coincides with the solution of the problem

2

∂t2 h

u(t+, x) +

m

X

i=1

giu((t−τi)+, x)i

=a(t)h(u(t+, x))∆u(t+, x)−q(t, x)f(u(t+, x)) +

l

X

r=1

ar(t)hr(u((t−σr)+, x))∆u((t−σr)+, x)

n

X

j=1

qj(t, x)fj(u((t−ρj)+, x)), t6=tk, (t, x)∈R+×Ω =G, u(¯t+k, x) =u(¯tk, x), ut(¯t+k, x) =ut(¯tk, x),

for¯tk ∈({tki} ∪ {tkr} ∪ {tkj})\ {tk}, or

u(¯t+k, x) =hki(¯tk, x, u(¯tk, x)), ut(¯t+k, x) =pki(¯tk, x, ut(¯tk, x)), for ¯tk ∈({tki} ∪ {tkr} ∪ {tkj})∩ {tk},

where the numberki is determined by the equality ¯tk=tki. We introduce the notation:

Γk={(t, x) :t∈(tk, tk+1), x∈Ω}, Γ =∪k=0Γk, Γ¯k={(t, x) :t∈(tk, tk+1), x∈Ω},¯ Γ =¯ ∪k=0Γ¯k, v(t) =

Z

u(t, x)dx, q(t) = min

x∈¯

q(t, x), qj(t) = min

x∈¯

qj(t, x).

Definition 1.2. The solutionu∈C2(Γ)∩C1(¯Γ) of problems (1.1), (1.4) ((1.5)) is called non-oscillatory in the domainGif it is either eventually positive or eventually negative. Otherwise, it is called oscillatory.

2. Oscillation properties for (1.1),(1.4) For the main result of this article, we need following lemmas.

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Lemma 2.1. Let u∈ C2(Γ)∩C1(¯Γ) be a positive solution of (1.1), (1.4) in G, then functionw(t) satisfies the impulsive differential inequality

w00(t) +C 1−

m

X

i=1

gi

q(t)w(t) +

n

X

j=1

Cj

1−

m

X

i=1

gi

qj(t)w(t−ρj)≤0, t6=tk, (2.1) ak≤ w(t+k)

w(tk) ≤ak, k= 1,2, . . . , (2.2) bk≤ w0(t+k)

w0(tk) ≤bk, k= 1,2, . . . , (2.3) wherew(t) =v(t) +Pm

i=1giv(t−τi).

Proof. Letu(t, x) be a positive solution of the problem (1.1), (1.4) inG. Without loss of generality, we may assume that there exists a T > 0, t0 > T such that u(t, x) > 0, u(t−τi, x) > 0, i = 1,2, . . . , m, u(t−σr, x) > 0, r = 1,2, . . . , l, u(t−ρj, x)>0,j= 1,2, . . . n, for any (t, x)∈[t0,∞)×Ω.

Fort≥t0,t6=tk, k= 1,2, . . ., integrating (1.1) with respect toxover Ω yields d2

dt2 hZ

u(t, x)dx+

m

X

i=1

gi Z

u(t−τi, x)dxi

=a(t) Z

h(u)∆u dx− Z

q(t, x)f(u(t, x))dx +

l

X

r=1

ar(t) Z

hr(u(t−σr, x))∆u(t−σr, x)dx

n

X

j=1

Z

qj(t, x)fj(u(t−ρj, x))dx.

By Green’s formula and the boundary condition, we have Z

h(u)∆u dx= Z

∂Ω

h(u)∂u

∂nds− Z

h0(u)|gradu|2dx

=− Z

h0(u)|gradu|2dx≤0, Z

hr(u(t−σr, x))∆u(t−σr, x)dx≤0.

From condition (H2), we can easily obtain Z

q(t, x)f(u(t, x))dx≥Cq(t) Z

u(t, x)dx, Z

qj(t, x)fj(u(t−ρj, x))dx≥Cjqj(t) Z

u(t−ρj, x)dx.

From the above it follows that d2

dt2 h

v(t) +

m

X

i=1

giv(t−τi)i

+Cq(t)v(t) +

n

X

j=1

Cjqj(t)v(t−ρj)≤0.

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Setw(t) =v(t) +Pm

i=1giv(t−τi), we havew(t)≥v(t), then we can obtain w00(t) +Cq(t)v(t) +

n

X

j=1

Cjqj(t)v(t−ρj)≤0, t6=tk.

From this inequality, we have w00(t)<0, and w0(t) >0, w(t)> 0 for t ≥t0. In fact, ifw0(t)<0, there existst1≥t0 such thatw0(t1)<0. Hence we have

w(t)−w(t1) = Z t

t1

w0(s)ds≤ Z t

t1

w0(t1)ds=w0(t1)(t−t1),

t→+∞lim w(t) =−∞.

This is a contradiction, sow0(t)>0. Because v(t) =w(t)−

m

X

i=1

giv(t−τi)

=w(t)−

m

X

i=1

gi

h

w(t−τi)−

m

X

i=1

giv(t−2τi)i

=w(t)−

m

X

i=1

giw(t−τi) +

m

X

i=1

gi

hXm

i=1

giv(t−2τi)i

≥ 1−

m

X

i=1

gi w(t),

v(t−ρj)≥ 1−

m

X

i=1

gi

w(t−ρj).

Hence, we obtain w00(t) +C

1−

m

X

i=1

gi

q(t)w(t) +

n

X

j=1

Cj

1−

m

X

i=1

gi

qj(t)w(t−ρj)≤0, t6=tk. Fort≥t0, t=tk, k= 1,2, . . ., from (1.2), (1.3) and condition (H4), we obtain

ak≤ u(t+k, x)

u(tk, x) ≤ak, (2.4)

bk≤ ut(t+k, x)

ut(tk, x) ≤bk. (2.5)

According to thev(t) =R

u(t, x)dx, we obtain ak≤ v(t+k)

v(tk) ≤ak, bk≤ v0(t+k) v0(tk) ≤bk. Becausew(t) =v(t) +Pm

i=1giv(t−τi),we finally have ak ≤ w(t+k)

w(tk) ≤ak, bk≤ w0(t+k) w0(tk) ≤bk.

Hence we obtain thatw(t) is a solution of impulsive differential inequality (2.1)–

(2.3). This completes the proof.

Lemma 2.2 ([5, Theorem 1.4.1]). Assume that

(A1) the sequence {tk} satisfies0< t0< t1< t2< . . .,limk→∞tk=∞;

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(A2) m(t)∈P C1[R+,R]is left continuous at tk fork= 1,2, . . .; (A3) fork= 1,2, . . . andt≥t0,

m0(t)≤p(t)m(t) +q(t), t6=tk, m(t+k)≤dkm(tk) +ek,

where p(t), q(t)∈C(R+,R), dk ≥0 and ek are constants. P C denote the class of piecewise continuous function from R+ toR, with discontinuities of the first kind only at t=tk, k= 1,2, . . ..

Then

m(t)≤m(t0) Y

t0<tk<t

dkexpZ t t0

p(s)ds +

Z t

t0

Y

s<tk<t

dkexpZ t s

p(r)dr q(s)ds

+ X

t0<tk<t

Y

tk<tj<t

djexpZ t tk

p(s)ds ek.

Lemma 2.3 ([11]). Let w(t) be an eventually positive (negative) solution of the differential inequality (2.1)–(2.3). Assume that there existsT ≥t0such thatw(t)>

0 (w(t)<0)fort≥T. If

t→+∞lim Z t

t0

Y

t0<tk<s

bk ak

ds= +∞ (2.6)

hold, thenw0(t)≥0 (w0(t)≤0)fort∈[T, tl]∪ ∪+∞k=l(tk, tk+1]

, wherel= min{k: tk ≥T}.

The following theorem is the first main result of this article.

Theorem 2.4. If condition (2.6)and the following condition holds,

t→+∞lim Z t

t0

Y

t0<tk<s

ak

bkF(s)ds= +∞, (2.7)

where

F(s) =C 1−

m

X

i=1

gi q(s) +

n

X

j=1

Cj 1−

m

X

i=1

gi

qj(s) exp(−δz(t0)).

Then each solution of (1.1)–(1.3),(1.4)oscillates inG.

Proof. Let u(t, x) be a non-oscillatory solution of (1.1), (1.4). Without loss of generality, we can assume that there exists T >0, t0 ≥T, such thatu(t, x)>0, u(t−τi, x)>0,i = 1,2, . . . , m, u(t−σr, x)>0,r = 1,2, . . . , l, u(t−ρj, x)>0, j= 1,2, . . . , nfor any (t, x)∈[t0,∞)×Ω. From Lemma 2.1, we know thatw(t) is a solution of (2.1)–(2.3).

Fort≥t0,t6=tk, k= 1,2, . . ., define z(t) = w0(t)

w(t), t≥t0. (2.8)

From Lemma 2.3, we havez(t)≥0,t ≥t0, w0(t)−z(t)w(t) = 0. We may assume thatw(t0) = 1, thus in view of (2.1)–(2.3) we have that fort≥t0,

w(t) = expZ t t0

z(s)ds

, (2.9)

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w0(t) =z(t) expZ t t0

z(s)ds

, (2.10)

w00(t) =z2(t) expZ t t0

z(s)ds

+z0(t) expZ t t0

z(s)ds

. (2.11)

We substitute (2.9)–(2.11) into (2.1) and obtain z2(t) expZ t

t0

z(s)ds

+z0(t) expZ t t0

z(s)ds +C

1−

m

X

i=1

gi

q(t) expZ t t0

z(s)ds

+

n

X

j=1

Cj

1−

m

X

i=1

gi

qi(t) expZ t−ρj

t0

z(s)ds

≤0.

Hence we have

z2(t) +z0(t) +C 1−

m

X

i=1

gi

q(t)

+

n

X

j=1

Cj 1−

m

X

i=1

gi

qj(t) exp

− Z t

t−ρj

z(s)ds

≤0, t6=tk, then we have

z0(t) +C 1−

m

X

i=1

gi

q(t)

+

n

X

j=1

Cj

1−

m

X

i=1

gi

qj(t) exp

− Z t

t−ρj

z(s)ds

≤0, t6=tk.

From above inequality and conditionbk ≤ak, we know thatz(t) is non-increasing, thenz(t)≤z(t0), fort≥t0, we obtain

z0(t) +C 1−

m

X

i=1

gi q(t) +

n

X

j=1

Cj 1−

m

X

i=1

gi

qj(t) exp(−δz(t0))≤0, t6=tk. From (2.2), (2.3) and (2.8), we obtain

z(t+k) =w0(t+k)

w(t+k) ≤ bkw0(tk) akw(tk) = bk

akz(tk), so we can easily obtain

z0(t)≤ −C 1−

m

X

i=1

gi q(t)−

n

X

j=1

Cj 1−

m

X

i=1

gi

qj(t) exp(−δz(t0)) t6=tk,

z(t+k)≤ bk

akz(tk).

Let

−F(t) =−C 1−

m

X

i=1

gi q(t)−

n

X

j=1

Cj 1−

m

X

i=1

gi

qj(t) exp(−δz(t0)).

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Then according to Lemma 2.2, we have z(t)≤z(t0) Y

t0<tk<t

bk

ak + Z t

t0

Y

s<tk<t

bk

ak (−F(s))ds

= Y

t0<tk<t

bk ak

hz(t0)− Z t

t0

Y

t0<tk<s

ak bk

F(s)dsi

<0.

Sincez(t)≥0, this is a contradiction. The proof is complete.

3. Oscillation properties of the problem (1.1),(1.5) For the second main theorem, we need following lemma.

Lemma 3.1. Let u∈ C2(Γ)∩C1(¯Γ) be a positive solution of (1.1), (1.5) in G, then functionw(t) satisfies the impulsive differential inequality

w00(t) +C 1−

m

X

i=1

gi

q(t)w(t) +

n

X

j=1

Cj

1−

m

X

i=1

gi

qj(t)w(t−ρj)≤0, t6=tk, (3.1) ak≤ w(t+k)

w(tk) ≤ak, k= 1,2, . . . , (3.2) bk≤ w0(t+k)

w0(tk) ≤bk, k= 1,2, . . . , (3.3) wherew(t) =v(t) +Pm

i=1giv(t−τi).

Proof. Letu(t, x) be a positive solution of the problem (1.1), (1.5) inG. Without loss of generality, we may assume that there exists a T > 0, t0 > T such that u(t, x) > 0, u(t−τi, x) > 0, i = 1,2, . . . , m, u(t−σr, x) > 0, r = 1,2, . . . , l, u(t−ρj, x) > 0, j = 1,2, . . . n, for any (t, x) ∈ [t0,∞)×Ω. For t ≥ t0, t 6= tk, k= 1,2, . . ., integrating (1.1) with respect toxover Ω yields

d2 dt2

hZ

u(t, x)dx+

m

X

i=1

gi

Z

u(t−τi, x)dxi

=a(t) Z

h(u)∆u dx− Z

q(t, x)f(u(t, x))dx +

l

X

r=1

ar(t) Z

hr(u(t−σr, x))∆u(t−σr, x)dx

n

X

j=1

Z

qj(t, x)fj(u(t−ρj, x))dx.

By Green’s formula and the boundary condition, we have Z

h(u)∆u dx= Z

∂Ω

h(u)∂u

∂nds− Z

h0(u)|gradu|2dx

=− Z

∂Ω

h(u)ϕ(t, x)u ds− Z

h0(u)|gradu|2dx

≤ − Z

h0(u)|gradu|2dx≤0,

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Z

hr(u(t−σr, x))∆u(t−σr, x)dx≤0.

The rest of the proof is similar to the one in Lemma 2.1. We omit it.

The following theorem is the second main result of this article.

Theorem 3.2. If conditions(2.6)and (2.7)hold, then each solution of (1.1)–(1.3), (1.5)oscillates inG.

The proof of the above theorem is similar to that of Theorem 2.4. We omit it.

4. Examples Example 4.1. Consider the equation

2

∂t2 h

u(t, x) +1

2u(t−π 2, x)i

=u2∆u−ueu2+etu2(t−π

2, x)∆u(t−π 2, x)

−(x2+ 1)etu(t−3π

2 , x)eu2(t−2,x), t >1, t6= 2k, (t, x)∈R+×Ω =G,

u((2k)+, x) = (4 + sin 2kcosx)u(2k, x), k= 1,2, . . . , ut((2k)+, x) = (2 + sin 2kcosx)ut(2k, x), k= 1,2, . . . , with the boundary condition

u= 0, (t, x)∈R+×∂Ω,

where a(t) = 1, a1(t) = et, τ1 = π2, σ1 = π2, ρ1 = 2, h(u) = u2, h1(u) = u2, f(u) =ueu2,f1(u) =ueu2,q(t, x) = 1,q1(t, x) = (x2+ 1)et, g1= 12,tk = 2k. It is easy to verify that the condition (H1)–(H4) and the conditions of Theorem 2.4 are satisfied. Hence the all solutions of above problem oscillate.

Example 4.2. Consider the equation

2

∂t2

hu(t, x) +1

2u(t−π 2, x)i

=u2∆u−ueu2+etu2(t−π

2, x)∆u(t−π

2, x)−(x2+ 1)etu(t−3π

2 , x)eu2(t−2,x), t >1, t6= 3k, (t, x)∈R+×Ω =G,

u((3k)+, x) = (4 + sin 3kcosx)u(3k, x), k= 1,2, . . . , ut((3k)+, x) = (2 + sin 3kcosx)ut(3k, x), k= 1,2, . . . , with the boundary condition

∂u

∂n+t2x2u= 0, (t, x)∈R+×∂Ω,

where a(t) = 1, a1(t) = et, τ1 = π2, σ1 = π2, ρ1 = 2, h(u) = u2, h1(u) = u2, f(u) = ueu2, f1(u) = ueu2, q(t, x) = 1, q1(t, x) = (x2+ 1)et, g1 = 12, tk = 3k, ϕ(t, x) =t2x2. It is easy to verify that the condition H) and condition of Theorem 3.2 are satisfied. Hence the all solutions of the above problem oscillate.

Acknowledgments. This research was partially supported by grants from the Na- tional Basic Research Program of China, nos. 2010CB950904 and 2011CB710604.

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Jichen Yang

School of Mathematics and Physics, China University of Geosciences, Wuhan, Hubei, 430074, China

E-mail address: yjch [email protected]

Anping Liu (corresponding author)

School of Mathematics and Physics, China University of Geosciences, Wuhan, Hubei, 430074, China

E-mail address:wh [email protected]

Guangjie Liu

School of Mathematics and Physics, China University of Geosciences, Wuhan, Hubei, 430074, China

E-mail address:[email protected]

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