Internat. Math. &
VOL. 21 NO. 2 (1998) 403-408
ON NEW STRENGTHENED HARDY-HILBERT’S
INEQUAUTYBICHENG YANG
Department
of Mathematics GuangdongEducationCollege Guangzhou,Guangdong510303,P.R.CHINAand LOKENATHDEBNATH
Department
of Mathematics UniversityofCentral Florida Orlando,Florida32816, U.S.A.(Received February27, 1997 andinrevisedform September 8,
1997)
ABSTRACT. Inthispaper,a newinequality for the weight coefficientw(q, n)
intheformsin(r/p) 2mi/p
+
n_i/q q> I,-
P+
q I, 6N isproved. This isfollowed byastrengthenedversionof the Hardy-I-lilbeninequality.KEY
WORDS AND PHRASES: Hardy-Hilbert’s inequality, weight coefficient, Holder’s inequality.1991AMS SUBCTCLASSIFICATION CODES: 26D15.
INTRODUC’HON
If
a _>
0, 0<
n2a2. <
oo, then the Karlson’sinequalityiso < a,,
n.=1 .=1
where theconstant cannotbe made smaller.
However,
it canbestrengthened(see
Mikhlin ],p. 7) as2 2
an < n
rt- n"r=l n=l
(1.2)
In
recent years, considerable attention has been given to develop some types ofstrengthened inequality(see[2]-[ 10])
byestimating the weight coefficientw(q,n)
as1
(mn--)l/q q-1 N)
(1.3)w(q,
n)----
(m + n) (q > I’P- +
1, nSomeimprovement ofHardy-Hilbert’s inequality
(see
Hardyetal. 11])
has been madeinthe form(
a
bq, (I 4)m
+
n sin(Tr/p)m=l n=l n=l
Intheir recentwork, Xu and Gau
[2]
considered thefollowing weight coefficient(1.3)
andproved the followinginequality404 B.C.YANG ANDL.DEBNATH
co(el, n) <
sin(r/p) nt/p
+
n-a/q r;p---p-1. (1.$)ThenastrengthenedHardy-Hilbert’s inequality
wasproved. Thekeyis to estimatethecorresponding weightcoefficiemeffectively. Hsuand
Wang [3]
provedthe followinginequality
0 3
w(2,n)<r---_, 0=:-I----1.12132
+(n6N). (1.7)
vn
Then they gave a new strengthened Hilbert’s inequality which is the same as
(1.6)
with p 2.Since 0 in
(1.7)
is not the best possible, Gau[5]
obtained the best possible value of0=- k=1
1.2811+ Subsequently, C-au[6]
consideredthe general caseandproved a newinequality for the weight coefficientco(q,n)
asco(q, n) <
sin(m/p) nl/; q
>
1,P- + -q
1,n6.N(1.8)
where
0p
(p-1).
Recently, C-au[7]
replaced(p-1)
by0, O,(n) >
0 in(1.8). Buttheproblemis thatO,(n)
dependsonbothpandq. Simultaneously,Yang
[8]foundthat0p
0 0.341295+,
but the constant0p
0 isnotthebest possiblevalue. Finally,Yang
andOau[9]
found the bestpossiblevalue for0,
0 1 C 0.42278433+,
whereCis aEulerconstant. Theyalsoprovedthefollowingnew Hardy-Hilbert’s inequalitym+n
sin(r/p)z-i’/ an
sin(Tr/p)z’i’/
bq(1.9)
m=l n=l n=l n=l
Itisimportanttopointoutthat
(1.5)
and(1.8)
aredifferent,and theconstantrt
in(1.5)
dependson p.Themainobjective of thispaperistoprovean improved versionof
(1.5)
as(q, ) <
sinQr/p) 2n]/
+
r-l/q q>
1,1 1
-+-=l,n6N
P q
(1.10)
and thenproveastrengthenedversion ofHardy-Hilbert’s inequalityasfollows:
EE m+n bn sin(/p)
r 2rtl/P-t-rt-1/q1sin(r/p)
r 2nl/qn-1/’
1 bqm=ln=l n=l n=l
1/q
(1.11) Forthis,weneed thefollowinginequality
(see Yang [8]
Lemma1):
Iff(m) >
0,/(2"-l) (x) < 0,/(2")(m) >
O,z6[1, oo)(r 1,2), f(’)(oo) ---0(r--
O,1,2,3,4),
andfo f(z)dz <
oo,then rtt=l_ f(m) <_ f(z)dz-I-- f(1) f’(:).
(1.12)
STRENGTHENEDI-IARDY-I-IILBERT’S INEQUALITY 405 2. SOME LEMMAS
LEMMA2.1. Ifq
>
1,p-z + q-Z
1,nEN, thenr 1
w(q,n) <
sin(vr/p)
nVn [fn(p) + g"(P)]’
where
w(q, n)
is definedby(1.5),
and1 1
Y"(P)
:=P+ + (1 +
-1 1
g.):=
12pn
2(1 +
2p)n21 1
12n + 3(1 +
3p)n3’7 1 1
12 2n 12n2 12n3"
PROOF.
Let
f(w)
zE[I, oo)(q > I,
nEN).
By
(1.12),we obtainthat1
/’
1wz--l_
dz
+
12 1
’1 +
n+
112(1 + n)
2" (2.2)Since
Puttingz n3/,wefindthat 1
wethenfindthat
and
l+n 1
( I+ _ln)-I <- 1{
1--+1
1(nl_.)
-2(1 + n)
2 n-’"
1+ <- 1( I----+
2Substitutingthe above resultsin(2.2),by(1.5),wehave(2.1). Thisproves the lemma.
406 B.C. YANG AND L.DEBNATH
LEMMA
2.2. Ifp>
1,n EN,
thenf. (,) + o (,) >
21 12n1 2n1s"(2.3)
and
PROOF. Since
f’(,) x
>1 11
1
+n
1 12n (+)n (+
1
+n
1 112n2
(1 + 1)2n (1 + 3)2n
s1 1 1
12n 4n 16ns
>
0,1 1
a’.()
2, +
( + 2), > o,
then
fn(P) +
gn(P)is strictly increasingfor pE(1, co),
and’.) + .() > i.(/.O,) + .0,))
211 1
12n 2ns"
Thus the lemmaisproved.
LEMMA
2.3. Ifq>
1,p-1 + q-1
1,n EN,
theninequality(1.10)
is valid. Soisthefollowing inequality:7r 1
w(p,
n) < sin(r/p--’---
2nUq+
n-Up"(2.4)
PROOF. Sinceforn
>_
3,2 12n 2n 1
+ +-
n 6 24n 2n2 4ns>
2’
then
1 1 1 1
2 12n 2n3
>
2+n-1
(n>3).
By
(2.1)and(2.3),wehaver 1
(1
1,(,n) <
sin(/,)
,/\2
12nr 1
<
sin(r/p) 2n/p+
n-Uq2n3
(n 3).
Taking
0,
1C,
by(1.8) (see Yang
andGau[9]),
we findthatr 1-U r
w(q, 1) < <
sin(/p) 1 sin(r/p) 1
2xl+l
(2.5)
SinceC
< 3/5
0.6, then we have1 1-C
2x2a/p
+
2-Uq<
21/pand
r I-C r 1
w(q, 2) <
.(mQr/p) "2V’ < sin(r/p’-
2 2/P+
2-x/q"(2.6)
Itfollows that forn 1, 2,
(1.10)
also holds. Then(1.10)
isvalidfor anynN.
Interchanging p,q in (l.10),sincesi,(,]/j;) in(}q),
wehave(2.4).
The lemmaisproved.NEW STRENGHARDY-HILBERT’SINEQUALITY &07 3. MAIN RESULTS
THEOREM3.1. Ifp>l,
p-I+q-l=l,
an_0, b,_0, and0<a, <oo,
n=l
0
< b, <
oo, theninequality (l.1)
isvalid. Wealso havem=l n=l n=l
When p q 2, this inequality reducestotheform
/
<Tr,._ .=
m+
n .--x2v + (3.2)
PROOF.
By
Holder’s inequality,wehaveHence,
by(1.10)
and(2.4),
inequality(1.11)
holds.Sinceby
(2.4), w(p, n) < ,
then by Holder’s inequality,weobtainn=l U,
By
(1.10),wefinda, r I /q
Thisproves result
(3.1).
ThustheproofofTheorem3.1 iscomplete.08 B.C.YANGAND L.DEBNATH 4.
CONCLUDING
REMARKS(a) Inequality
(1.11)
is a definiteimprovementover(1.6).
"--’)
then(b)
Since, forn _)3,C>
2.+gin(Trip) 2rd/n
+
n-1/q<
Sin(Tr/p)(1 -C)
t l/p
(n >_ 3). (4.1)
Inviewof(2.5),
(2.6)
and (3.3),itfollows that(1.9)
and(1.11)
representtwo distinct versionsof strengthenedinequalities. But theyarenotcomparable.(c)
Inequality(3. l)
reducestoThisisanequivalent formofHardy-Hilbert’s inequality
(1.4) (see
Hardyetal.[11],
Chapter 9).[l]
MIKtK,IN,
S.G., Constantsm Some
Inequalitiesof
Analysis, John Wiley& Sons,
New York, 1986.[2] XU,
L.C. and GAU,Y.K.,
Note on Hardy-Riesz’s extension ofI-Iilben’s inequality, Chinese QuarterlyJournalof
Mathematfcs,6, (1991),75-77.[3]
HSU, L.C. andWANG,Y.J.,
Arefinement ofHilbert’sdouble seriestheorem, J.Math.Res.Exp.
11, (1991), 143-144.
[4] ZHAO, D.J.,
Onarefinementof Hilbert’s double seriestheorem,Math. Practiceand Theory,(1993),
85-90.[5]
GAU,M.Z.,
A note onHilbertdouble seriestheorem, HunanAnnalsof
Mathematics, 12, 1-2 (1992), 142-147.[6] GAU,
M.Z.,
An improvement ofHardy-Riesz’sextensionoftheI-filbertinequality, J.Math.Res.Exp.
I4,2(1994),255-259.[7]
GAU,M.Z.,
AnoteontheHardy-Hbertinequality,J.Math. Aria.Appl.204(1996),
346-351.[8] YANG,
B.C., Arefinement on thegeneralHilbert’sdoubleseriestheorem,J.
Math.Study, 29, 2 (1996),64-70.[9] YANG,
B.C. andGAU, M.Z.,
Onabest valueofHardy-Hilbert’sinequality,AdvancesinMath., 26, 2(1997),
159-164.[10] YANG, B.C.and