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Introduction Let A be the class of functions f which are analytic in the open unit disk U = {z∈C:|z|<1}, with f(0

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THE UNIVALENCE OF AN INTEGRAL OPERATOR

Virgil Pescar

Abstract. For analytic functionsf in the open unit diskU, an integral operator Eα,βis defined. In this paper we derive univalence conditions of the integral operator Eα,β.

Key Words: Analytic functions, Integral operator, Univalence.

2000Mathematics Subject Classification: 30C45.

1. Introduction

Let A be the class of functions f which are analytic in the open unit disk U = {z∈C:|z|<1}, with f(0) = f0(0)−1 = 0. Let S denote the subclass of A consisting of the functions f ∈ A, which are univalent in U. We denote by P the class of functions pwhich are analytic inU,p(0) = 1 andRe p(z)>0, for allz∈ U.

In this work, we define a new integral operator, which is given by Eα,β(z) =

Z z

0

f(u) u

α

(g(u))βdu, (1)

forα, β be complex numbers,f ∈ Aandg∈ P.

From (1), for β = 0, α be a complex number, f ∈ A, we have the integral operator Kim-Merkes [2],

Iα(z) = Z z

0

f(u) u

α

du. (2)

Forα = 0, β be a complex number and g∈ P, we obtain the integral operator, which is defined by

Gβ(z) = Z z

0

(g(u))βdu. (3)

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2. Preliminary results Lemma 1. ([1]). If the function f is analytic in U and

1− |z|2

zf00(z) f0(z)

≤1, (4)

for all z∈ U, then the function f is univalent inU.

Lemma 2. (Schwarz [3]). Let f be the function regular in the disk

UR={z∈C:|z|< R} with |f(z)|< M, M fixed. If f has in z= 0 one zero with multiply ≥m, then

|f(z)| ≤ M

Rm|z|m, (z∈ UR), (5)

the equality (in the inequality (5) for z6= 0) can hold only if

f(z) =e M Rmzm, where θ is constant.

3. Main results

Theorem 1. Let α β be complex numbers, M1, M2 positive real numbers and the functions f ∈ A, f(z) =z+a2z2+a3z3+. . .and g∈ P,

g(z) = 1 +b1z+b2z2+. . ..

If

zf0(z) f(z) −1

≤M1, (z∈ U), (6)

zg0(z) g(z)

≤M2, (z∈ U), (7)

and

|α|M1+|β|M2 ≤ 3√ 3

2 , (8)

then the function

Eα,β(z) = Z z

0

f(u) u

α

(g(u))βdu, (9)

is in the class S.

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Proof. The function Eα,β(z) is regular in U and Eα,β(0) = Eα,β0 (0)−1 = 0. We have:

zEα,β00 (z) Eα,β0 (z) =α

zf0(z) f(z) −1

+βzg0(z)

g(z) , (10)

for all z∈ U.

From (10) we obtain:

1− |z|2

zEα,β00 (z) Eα,β0 (z)

≤ 1− |z|2

|α|

zf0(z) f(z) −1

+|β|

zg0(z) g(z)

, (11)

for all z∈ U. By Lemma 2, from (6) and (7) we get

zf0(z) f(z) −1

≤M1|z|, (z∈ U), (12)

zg0(z) g(z)

≤M2|z|, (z∈ U) (13)

and by (11) we have 1− |z|2

zEα,β00 (z) Eα,β0 (z)

≤ 1− |z|2

|z|(|α|M1+|β|M2), (14) for all z∈ U. Since

max|z|≤1

1− |z|2

|z|

= 2

3√ 3, by (14) and (8) we obtain

1− |z|2

zEα,β00 (z) Eα,β0 (z)

≤1, (z∈ U). (15)

By Lemma 1, we obtain that the integral operator Eα,β belongs to the class S.

Theorem 2. Let α, β be complex numbers and the functions f ∈ S, g ∈ P, f(z) =z+a2z2+a3z3+. . ., g(z) = 1 +b1z+b2z2+. . ..

If

2|α|+|β| ≤ 1

2, (16)

then the integral operator Eα,β, defined by (1), is in the class S.

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Proof. From (10) we obtain:

1− |z|2

zEα,β00 (z) Eα,β0 (z)

≤ 1− |z|2

|α|

zf0(z) f(z)

+ 1

+|β|

zg0(z) g(z)

(17) for all z∈ U. Since f ∈ S,g∈ P, we have:

zf0(z) f(z)

≤ 1 +|z|

1− |z|, (z∈ U), (18)

zg0(z) g(z)

≤ 2|z|

1− |z|2, (z∈ U) (19)

and hence, by (17) we get 1− |z|2

zEα,β00 (z) Eα,β0 (z)

≤4|α|+ 2|β|, (z∈ U). (20) From (20), (16) we obtain

1− |z|2

zEα,β00 (z) Eα,β0 (z)

≤1, (z∈ U), (21)

and by Lemma 1, it results thatEα,β∈ S.

3. Corollaries

Corollary 1. Let α be a complex number, α6= 0 and f ∈ A, f(z) =z+a2z2+a3z3+. . .. If

zf0(z) f(z) −1

≤ 3√ 3

2|α|, (z∈ U), (22)

then the integral operator Iα, defined by (2), is in the class S.

Proof. Forβ = 0, from Theorem 1 we obtain Corollary 1.

Corollary 2. Let β be a complex number,β 6= 0 and g∈ P, g(z) = 1 +b1z+b2z2+. . . . If

zg0(z) g(z)

≤ 3√ 3

2|β|, (z∈ U), (23)

then the integral operator Gβ defined by (3), belongs the class S.

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Corollary 3. Let α be a complex number and the function f ∈ S, f(z) =z+a2z2+a3z3+. . ..

If

|α| ≤ 1

4, (24)

then the integral operator Iα defined in (2), is in the class S.

Proof. We takeβ = 0 in Theorem 2, we obtain the Corollary 3.

Corollary 4. Let β be a complex number and the function g∈ P, g(z) = 1 +b1z+b2z2+. . ..

If

|β| ≤ 1

2, (25)

then the integral operator Gβ defined in (3), is in the class S.

Proof. We takeα= 0 in Theorem 2.

References

[1] Becker, J.,L¨ownersche Differentialgleichung Und Quasikonform

Fortsetzbare Schlichte Functionen, J. Reine Angew. Math. , 255 (1972), 23-43.

[2] Kim, Y. J. , E. P. Merkes,On an Integral of Powers of a Spirallike Function, Kyungpook Math. J., 12 (1972), 249-253.

[3] Mayer, O.,The Functions Theory of One Variable Complex, Bucure¸sti, 1981.

Virgil Pescar

Department of Mathematics

”Transilvania” University of Bra¸sov 500091 Bra¸sov, Romania

email:[email protected]

参照

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