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Pasting reproducing kernel Hilbert spaces (General topics on applications of reproducing kernels)

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(1)

Pasting reproducing kernel Hilbert

spaces

Yoshihiro

Sawano

Department of Mathematics and

Information

Sciences

Tokyo Metropolitan University

Abstract:

The

aim

of this article

is

to find

the necessary and

sufficient

condition

for the mapping

$H_{K}(E)\ni f\mapsto(f|E_{1}, f|E_{2})\in H_{K|E_{1}\cross E_{2}}(E_{1})\oplus$

$H_{K|E_{2}\cross E_{2}}(E_{2})$

to

be

isomorphic,

where

$K$

is

a

positive

definite function on

$E=E_{1}+E_{2}.$

1

Introduction

Let

$E$

be

a

set and

$K$

:

$E\cross Earrow \mathbb{C}$

be a

positive

definite

function. For

$f\in H_{K}(E)$

,

we can

easily

check that

$f|E_{0}\in H_{K|E_{0}\cross E_{0}}(E_{0})$

since

$f|E_{0}\otimes f|E_{0}\ll\Vert f\Vert_{H_{K}(E)^{2}}K|E_{0}\cross E_{0}\otimes K|E_{0}\cross E_{0}$

in the

sense

that

$\sum_{j,k=1,2,n}\ldots,(\Vert f\Vert_{H_{K}(E)^{2}}K|E_{0}\cross E_{0}(p_{j}, p_{k})-f|E_{0}\otimes f|E_{0}(p_{j},p_{k}))z_{j}\overline{z_{k}}$

$= \sum_{j,k=1,2,n}\ldots,(\Vert f\Vert_{H_{K}(E)^{2}}K(p_{j},p_{k})-f(p_{j},p_{k}))z_{j}\overline{z_{k}}\geq 0$

for

any finite

set

$\{p_{1},p_{2}, . . . , p_{k}\}\subset E_{0}$

and

$\{z_{1}, z_{2}, . . . , z_{k}\}\subset \mathbb{C}$

. Therefore,

when

$E$

is

partitioned into

the

sum

$E=E_{1}+E_{2}$

,

the operation

the mapping

$R$

:

$H_{K}(E)\ni f\mapsto(f|E_{1}, f|E_{2})\in H_{K|E_{1}\cross E_{2}}(E_{1})\oplus H_{K|E_{2}\cross E_{2}}(E_{2})$

makes

sense.

Note that

$R$

is injection, since

$f|E_{1}=0$

and

$f|E_{2}=0$

imply

$f=0.$

数理解析研究所講究録

(2)

2

Main

result

We show

the necessary

and sufficient condition

for

$R$

to be

isomorphic.

Theorem.

The

mapping

$R$

is isomorphic

if

and

only

if

$K|E_{1}\cross E_{2}$

$0.$

Proof.

Assume

first that

$K|E_{1}\cross E_{2}=$

O. Let

us first

show that

$R$

is

sur-jection.

To

this

end, given

$g_{1}\in H_{K|E_{1}\cross E_{1}}(E_{1})$

and

$92\in H_{K|E_{2}\cross E_{2}}(E_{2})$

,

we

define

a function

$f$

on

$E$

by

$f(p)=g_{1}(p)$

on

$E_{1}$

and

$f(p)=g_{2}(p)$

on

$E_{2}$

.

Let

us

check that

$f\in H_{K}(E)$

.

To

this

end,

we

set

$f_{1}=\chi_{E_{1}}f$

and

$f_{2}=\chi_{E_{2}}f.$

Then

for

$l=1$

, 2,

we

have

$\sum_{j,k=1,2,n}\ldots,(\Vert f_{l}\Vert_{H_{K}(E)^{2}}K(p_{j},p_{k})-f_{l}\otimes f_{l}(p_{j},p_{k}))z_{j}\overline{z_{k}}$

$\geq\sum_{j,k=1,2,\ldots,n,p_{j},p_{k}\in E_{l}}(\Vert f_{l}\Vert_{H_{K}(E)^{2}}K(p_{j},p_{k})-f_{l}\otimes f_{l}(p_{j},p_{k}))z_{j}\overline{z_{k}}$

by assumption.

Since

$\Vert f_{l}\Vert_{H_{K}(E)}\geq\Vert g_{1}\Vert_{H_{K|E_{l}xE_{l}}(E_{l})}$

from

a

general

result

on

the reproducing kernel

Hilbert

spaces,

we

have

$\sum_{j,k=1,2,n}\ldots,(\Vert f_{l}\Vert_{H_{K}(E)^{2}}K(p_{j},p_{k})-f_{l}\otimes f_{l}(p_{j},p_{k}))z_{j}\overline{z_{k}}$

$\geq\sum_{j,k=1,2,\ldots,n,p_{j},p_{k}\in E_{l}}(\Vert g_{l}\Vert_{H_{K|E_{l}\cross E_{l}}(E_{l})^{2}}K(p_{j},p_{k})-g_{l}\otimes g_{l}(p_{j},p_{k}))z_{j}\overline{z_{k}}\geq 0.$

Thus,

$f_{l}\in H_{K_{l}}(E_{l})$

as was

to be

shown.

It

remains

to show that

$R$

is

an

isomorphism.

In fact,

$\{K(\cdot,p)\}_{p\in E_{l}}$

is

a

dense subspace in

$H_{K|E_{l}\cross E_{l}}(E_{l})$

,

we

have

only

to show that

$( \Vert\sum_{m=1}^{L}(z_{1}^{m}K(\cdot,p_{1}^{m})+z_{2}^{m}K(\cdot,p_{2}^{m}))\Vert_{H_{K}(E)})^{2}$

$=( \Vert_{m=1}\sum^{L}z_{1}^{m}K(\cdot,pm)\Vert_{H_{K|E_{1}xE_{1}}(E_{1})})^{2}+(\Vert\sum_{m=1}^{L}z_{2}^{m}K(\cdot,p_{2}^{m})\Vert_{H_{K|E_{2}\cross E_{2}}(E_{2})})^{2}$

for any

$p_{1}^{m}\in E_{1},$ $p_{2}^{m}\in E_{2},$$z_{1}^{m},$ $z_{2}^{m}\in \mathbb{C}$

with

$m=1$

,

2, . .

.

,

$L.$

(3)

Conversely, if

$R$

is

an

isomorphism,

then

$(\Vert K(\cdot,p_{1})+zK(\cdot,p_{2}))\Vert_{H_{K}(E)})^{2}$

$=(\Vert K(\cdot,p_{1})\Vert_{H_{K|E_{1}\cross E_{1}}(E_{1})})^{2}+|z|^{2}(\VertK(\cdot,p_{2})\Vert_{H_{K|E_{2}\cross E_{2}}(E_{2})})^{2}$

for any

$p_{1}\in E_{1}$

and

$p_{2}\in E_{2}$

and

$z\in \mathbb{C}$

.

Thus

$K|E_{1}\cross E_{2}=0$

.

This

result

is essentially

based

on

[1, 2],

however,

the

representation

is

arranged in the polished version.

References

[1] Y. Sawano, Pasting reproducing kernel Hilbert spaces, Jaen Journal

on

Approximations, 3

(2011),

no.

1,

135-141.

[2]

S.

Saitoh and Y. Sawano, Theory

of

Reproducing

Kernels and

Applica-tions,

to

appear

in Springer.

Yoshihiro

Sawano

Department

of Mathematics and Information

Sciences

Tokyo Metropolitan University

1-1

Minami-Ohsawa,

Hachioji

192-0397,

JAPAN

$E$

-mail address: yoshihiro-sawano@celery.ocn.ne.jp

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