Has Miku scored yet ? Yes, she has . Has the game finished yet ? No, it has n’t. ( has not ) .

The proof there does not use the fact that H ∗ (X, C[2]) has a counit, in fact it only uses its diagonal map. It relies on the earlier work in [Leh99], which has been extended to

If r ′ is placed in the board B (0) , it cancels no cells in B (0) and it cancels the lowest cell in each subcolumn to its right, which has yet to be canceled by a rook to its left,

Under these hypotheses, the union, ⊂ M/T , of the set of zero and one dimensional orbits has the structure of a graph: Each connected component of the set of one-dimensional orbits

Acknowledgement.This work was partially done while the second author was visiting the University of Texas at Austin and Texas A&M University, and in the Linear Analysis Workshop

Theorem 1.2 If an n-manifold with compact (possibly empty) boundary is inward tame at innity, then it has nitely many ends, each of which has semistable fundamental group and

Indeed, in order to conclude from Gromov’s Theorem that G has a nilpotent subgroup of finite index, it suffices to know that G has a connected Cayley graph of finite valency that

There is a robust collection of local existence results, including [7], in which Kato proves the existence of local solutions to the Navier-Stokes equation with initial data in L n (

Some new oscillation and nonoscillation criteria are given for linear delay or advanced differential equations with variable coef- ficients and not (necessarily) constant delays