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Boundary Value Problems

Volume 2009, Article ID 316812,17pages doi:10.1155/2009/316812

Research Article

Variational Method to the Impulsive Equation with Neumann Boundary Conditions

Juntao Sun and Haibo Chen

Department of Mathematics, Central South University, Changsha, 410075 Hunan, China

Correspondence should be addressed to Juntao Sun,[email protected] Received 28 August 2009; Accepted 28 September 2009

Recommended by Pavel Dr´abek

We study the existence and multiplicity of classical solutions for second-order impulsive Sturm- Liouville equation with Neumann boundary conditions. By using the variational method and critical point theory, we give some new criteria to guarantee that the impulsive problem has at least one solution, two solutions, and infinitely many solutions under some different conditions, respectively. Some examples are also given in this paper to illustrate the main results.

Copyrightq2009 J. Sun and H. Chen. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

1. Introduction

In this paper, we consider the boundary value problem of second-order Sturm-Liouville equation with impulsive effects

ptut

rtut qtut gt, ut, t /tk, a.e. t∈0,1,

−Δ

ptkutk

Ikutk, k1,2, . . . , p−1, u0 u

1 0,

1.1

where 0 t0 < t1 < t2 < · · · < tp−1 < tp 1, p ∈ C10,1, r, q ∈ C0,1 withp and q positive functions,g :0,1×R → Ris a continuous function,Ik:R → R,1≤kp−1 are continuous,−Δptkutk −ptkutkutk,utkandutkdenote the right and the left limits, respectively, ofutatttk,u0is the right limit ofu0, andu1is the left limit ofu1.

In the recent years, a great deal of work has been done in the study of the existence of solutions for impulsive boundary value problemsIBVPs, by which a number

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of chemotherapy, population dynamics, optimal control, ecology, industrial robotics, and physics phenomena are described. For the general aspects of impulsive differential equations, we refer the reader to the classical monograph1. For some general and recent works on the theory of impulsive differential equations, we refer the reader to2–9. Some classical tools or techniques have been used to study such problems in the literature. These classical techniques include the coincidence degree theory of Mawhin10, the method of upper and lower solutions with monotone iterative technique11, and some fixed point theorems in cones12–14.

On the other hand, in the last two years, some researchers have used variational methods to study the existence of solutions for impulsive boundary value problems.

Variational method has become a new powerful tool to study impulsive differential equations, we refer the reader to 15–20. More precisely, in 15, the authors studied the following equation with impulsive effects:

ρtφp

ut

stφput ft, ut, t /tj, a.e. t∈a, b,

−Δ ρ

tj φp

u tj

Ij u

tj

, j1,2, . . . , l, αua−βua A, γub σub B,

1.2

wheref :a, b×0,∞ → 0,∞is continuous,Ij:0,∞ → 0,∞, j 1,2, . . . , l, are continuous, andα, β, γ, σ >0. They essentially proved that IBVP1.2has at least two positive solutions via variational method. Recently, in16, using variational method and critical point theory, Nieto and O’Regan studied the existence of solutions of the following equation:

−ut λut ft, ut, t /tj, a.e. t∈0, T, Δ

u tj

Ij

u tj

, j 1,2, . . . , l,

u0 uT 0,

1.3

where f : 0, T×R → Ris continuous, and Ij : R → R, j 1,2, . . . , l are continuous.

They obtained that IBVP1.3has at least one solution. Shortly, in17, authors extended the results of IBVP1.3.

In19,Zhou and Li studied the existence of solutions of the following equation:

−ut gtut ft, ut, t /tj, a.e. t∈0, T, Δ

u tj

Ij u

tj

, j 1,2, . . . , p,

u0 uT 0,

1.4

wheref : 0, T×R → Ris continuous, and Ij : R → R, j 1,2, . . . , p, are continuous.

They proved that IBVP1.4has at least one solution and infinitely many solutions by using variational method and critical point theorem.

Motivated by the above facts, in this paper, our aim is to study the variational structure of IBVP1.1in an appropriate space of functions and obtain the existence and multiplicity of solutions for IBVP1.1by using variational method. To the best of our knowledge, there

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is no paper concerned impulsive differential equation with Neumann boundary conditions via variational method. In addition, this paper is a generalization of21, in which impulse effects are not involved.

In this paper, we will need the following conditions.

H1There is constantsβ >2, M >0 such that for everyt∈0,1andu∈Rwith|u| ≥M,

0< βGt, uugt, u, 0< β u

0

Iksds≤uIku, 1.5

whereGt, u u

0gt, sds.

H2limu0gt, u/u0 uniformly fort∈0,1, and limu0Iku/u0.

H3There exist numbersh1, h2>0 andp1 >1 such that

gt, uh1h2|u|p1 foru∈R, t∈0,1. 1.6

H4There exist numbersak, bk>0 andγk∈0,1such that

Iku≤akbk|u|γk foru∈R. 1.7

H5There exist numbersr1, r2>0 andμ∈0,1such that

gt, ur1r2|u|μ foru∈R, t∈0,1. 1.8

H6There exist numbersak, bk >0 andγk ∈1,∞such that

Iku≤akbk|u|γk foru∈R. 1.9

This paper is organized as follows. InSection 2, we present some preliminaries. In Section 3, we discuss the existence and multiplicity of classical solutions to IBVP1.1. Some examples are presented in this section to illustrate our main results in the last section.

2. Preliminaries

Take Lt t

0rs/psds. Then e−LtC10,1. We transform IBVP 1.1 into the following equivalent form:

e−Ltptut

e−Ltqtut e−Ltgt, ut, t /tk, a.e. t∈0,1,

−Δ

e−Ltkptkutk

e−LtkIkutk, k1,2, . . . , p−1, u0 u

1 0.

2.1

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Obviously, the solutions of IBVP2.1are solutions of IBVP 1.1. So it suffices to consider IBVP2.1.

In this section, the following theorem will be needed in our argument. Suppose thatE is a Banach spacein particular a Hilbert spaceandϕC1E,R. We say thatϕsatisfies the Palais-Smale condition if any sequence{uj} ⊂Efor whichϕujis bounded andϕuj → 0 asj → ∞possesses a convergent subsequence inX. LetBr be the open ball inXwith the radiusrand centered at 0 and∂Br denote its boundary.

Theorem 2.1 22, Theorem 38.A. For the functional F : MX → −∞,∞ with M /∅,minu∈MFu αhas a solution for which the following hold:

iXis a real reflexive Banach space;

iiMis bounded and weakly sequentially closed;

iiiF is weakly sequentially lower semicontinuous on M; that is, by definition, for each sequence{un}in Msuch thatun uasn → ∞, one has Fu ≤ lim infn→ ∞Fun holds.

Theorem 2.216, Theorem 2.2. LetEbe a real Banach space and letϕC1E,Rsatisfy the Palais-Smale condition. Assume there existu0, u1Eand a bounded open neighborhoodΩofu0such thatu1Eand

max

ϕu0, ϕu1 < inf

x∈∂Ωϕu. 2.2

Let

Γ {h|h:0,1−→Eis continuous andh0 u0, h1 u1}, cinf

h∈Γmax

s∈0,1ϕhs. 2.3

Thencis a critical value ofϕ; that is, there existsuEsuch thatϕu Θandϕu c, where c >max{ϕu0, ϕu1}.

Theorem 2.3 23. Let Ebe a real Banach space, and let ϕC1E,Rbe even satisfying the Palais-Smale condition andϕ0 0. IfEVY, whereV is finite dimensional, andϕsatisfies that

A1there exist constantsρ, α >0 such thatϕ|∂Br∩Yα,

A2for each finite dimensional subspaceWE, there isR RWsuch thatϕu0 for all uWwithu ≥R.

Thenϕpossesses an unbounded sequence of critical values.

Let us recall some basic knowledge. Denote byXthe Sobolev spaceW1,20,1, and consider the inner product

u, v 1

0

utvtdt 1

0

utvtdt 2.4

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which induces the usual norm

u 1

0

ut2dt 1

0

|ut|2dt 1/2

. 2.5

We also consider the inner product

u, vX 1

0

e−Ltptutvtdt 1

0

e−Ltqtutvtdt, 2.6

and the norm

uX 1

0

e−Ltptut2dt 1

0

e−Ltqt|ut|2dt 1/2

, 2.7

then the norm · Xis equivalent to the usual norm · inW1,20,1. Hence,Xis reflexive.

We define the norm inC0,1, L20,1asu maxt∈0,1|ut|andu2 1

0|u|2dt1/2, respectively.

ForuW2,20,1, we have thatu, uare absolutely continuous, anduL20,1, hence −Δe−Ltkptkutk −e−Ltkptkutkutk 0,for any tk ∈ 0,1. IfuX, thenuis absolutely continuous and uL20,1. In this case, the one-side derivatives u0, u1, utk, utk, k 1,2, . . . , p−1 may not exist. As a consequence, we need to introduce a different concept of solution. We say thatuC0,1is a classical solution of IBVP2.1if it satisfies the equation in IBVP 2.1a.e. on0,1, the limitsutk, utk, k 1,2, . . . , p−1 exist and impulsive conditions in IBVP2.1hold,u0, u1exist andu0 u1 0. Moreover, for everyk0,1, . . . , p−1, uku|tk,tk1satisfyukW2,2tk, tk1.

For eachuX, consider the functionalϕdefined onXby

ϕu 1

2u2Xp−1

k1

e−Ltk utk

0

Iksds− 1

0

e−LtGt, udt. 2.8

It is clear thatϕis differentiable at anyuXand

ϕuv

1

0

e−Ltptutvt e−Ltqtutvt dt

p−1

k1

e−LtkIkutkvtk1

0

e−Ltgt, utvtdt

2.9

for anyvX. Obviously,ϕis continuous.

Lemma 2.4. IfuX is a critical point of the functionalϕ, thenuis a classical solution of IBVP 2.1.

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Proof. LetuXbe a critical point of the functionalϕ. It shows that 1

0

e−Ltptutvte−Ltqtutvt dt

p−1

k1

e−LtkIkutkvtk1

0

e−Ltgt, utvtdt0

2.10

holds for any vX. Choose any j ∈ {0,1,2, . . . , p−1} and vX such that vt 0 if t∈tk, tk1fork /j. Equation2.10implies

tj1

tj

e−Ltptutvt e−Ltqtutvte−Ltgt, utvt

dt0. 2.11

This means, for anywW01,2tj, tj1, tj1

tj

e−Ltptujtwt e−Ltqtujtwt−e−Ltg t, ujt

wt

dt0, 2.12

whereuju|tj,tj1. Thusujis a weak solution of the following equation:

e−Ltptut

e−Ltqtut e−Ltgt, ut ttj, tj1

, 2.13

and therefore ujW01,2tj, tj1Ctj, tj1.Let ht : e−Ltgt, u−qu, then 2.13 becomes the following form:

e−Ltptut

hton tj, tj1

, j0,1,2, . . . , p−1. 2.14

Then the solution of2.14can be written as

ujt C1C2

t

tj

eLs−lnpsdst

tj

eLs−lnps s

tj

hr

prelnprdr

ds ttj, tj1

, 2.15

whereC1 andC2 are two constants. ThenujCtj, tj1andujCtj, tj1. Therefore,uj is a classical solution of2.13andusatisfies the equation in IBVP2.1a.e. on0,1. By the

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previous equation, we can easily get that the limitsutj, utj, j 1,2, . . . , p−1, ut0and utpexist. By integrating2.10, one has

1

0

e−Ltptutvt e−Ltqtutvt dt

p−1

k1

e−LtkIkutkvtk1

0

e−Ltgt, utvtdt

p−1

k1

Δ

e−Ltkptkutk

vtk e−L1p1u 1

v1

e−L0p0u0v0−p−1

k1

e−LtkIkutkvtk

1

0

e−Ltptut

e−Ltqtute−Ltgt, ut

vtdt

p−1

k1

Δ

e−Ltkptkutk

e−LtkIkutk vtk

e−L1p1u 1

v1e−L0p0u0v0

1

0

e−Ltptut

e−Ltqtute−Ltgt, ut

vtdt0,

2.16

and combining with2.13we get

p−1

k1

Δ

e−Ltkptkutk

e−LtkIkutk vtk

e−L1p1u 1

v1e−L0p0u0v00.

2.17

Next we will show thatusatisfies the impulsive conditions in IBVP2.1. If not, without loss of generality, we assume that there existsi∈ {1,2, . . . , p−1}such that

e−LtiIiuti Δ

e−Ltiptiuti

/0. 2.18

Let

vt p k0, k /i

t−tk. 2.19

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Obviously,vX. Substituting them into2.17, we get

Δe−Ltiptiuti e−LtiIiuti

vti 0 2.20

which contradicts2.18. Sousatisfies the impulsive conditions in IBVP2.1. Thus,2.17 becomes the following form:

e−L1p1u 1

v1e−L0p0u0v0 0, 2.21

for all vX. Since v0, v1 are arbitrary, 2.21 shows that e−L1p1u1 e−L0p0u0 0,and it impliesu1 u0 0. Therefore, uis a classical solution of IBVP2.1.

Lemma 2.5. LetuX. ThenuM1uX, where

M121/2max

1

mint∈0,1e−Ltpt1/2, 1

mint∈0,1e−Ltqt1/2

. 2.22

Proof. By using the same methods of15, Lemma 2.6, we easily obtain the above result, and we omit it here.

3. Main Results

In this section, we will show our main results and prove them.

Theorem 3.1. Assume that (H1) and (H2) hold. Moreover,gt, uand the impulsive functionsIku are odd aboutu, then IBVP1.1has infinitely many classical solutions.

Proof. Obviously,ϕis an even functional andϕ0 0. We divide our proof into three parts in order to showTheorem 3.1.

Firstly, We will show that ϕ satisfies the Palais-Smale condition. Let {ϕun} be a bounded sequence such that limnϕun 0. Then there exists constants C3 > 0 such that

ϕunC3, ϕun

XC3. 3.1

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By2.8,2.9,3.1, andH1, we have β

2 −1

un2X β

2un2Xun2X βϕunϕununβ

p−1 k1

e−Ltk untk

0

Iksdsβ 1

0

e−LtGt, undt

p−1

k1

e−LtkIkuntkuntk1

0

e−Ltgt, unundt

p−1

k1

e−Ltk

β untk

0

Iksds−Ikuntkuntk

1

0

e−Lt

βGt, ungt, unun

dtβϕunϕunun

βC3M21C3unX

1

0

e−Ltdt max

t∈0,1, unt∈−M,MβGt, ungt, unun p−1

k1

e−Ltk max

untk∈−M,M

β

untk

0

Iksds−Ikuntkuntk .

3.2

It follows that{un} is bounded in X. From the reflexivity of X, we may extract a weakly convergent subsequence that, for simplicity, we call{un}, un uinX. In the following we will verify that{un}strongly converges touinX. By2.9we have

ϕunϕu

unu unu2X

p−1

k1

e−LtkIkuntkIkutnuntkutk

1

0

e−Lt

gt, unt−gt, ut

unt−utdt.

3.3

Byun uinX, we see that{un}uniformly converges touinC0,1. So 1

0

e−Lt

gt, unt−gt, ut

unt−utdt−→0, p−1

k1

e−LtkIkuntkIkutkuntkutk−→0, ϕunϕu

unu−→0 asn−→∞.

3.4

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By3.3,3.4, we obtainunuX → 0 asn → ∞. That is,{un}strongly converges touin X, which means the that P. S. condition holds forϕ.

Secondly, we verify the conditionA1 in Theorem 2.3. Let V R, Y {u ∈ X | 1

0utdt 0}, then X VY, where dimV 1 < ∞. In view of H2, take ε min{1/8M211

0e−Ltdt,1/8M21p−1

k1e−Ltk} > 0, there exists anδ > 0 such that for every u with|u|< δ,

Gt, uε|u|2, u

0

Iksds≤ε|u|2. 3.5

Hence, for anyuY withuXδ/M1, by2.8and3.5, we have

ϕu 1

2u2Xp−1

k1

e−Ltk utk

0

Iksds− 1

0

e−LtGt, udt

≥ 1

2u2Xp−1

k1

e−Ltkε|uktk|21

0

e−Ltε|ut|2dt

≥ 1

2u2XεM21 p−1 k1

e−Ltku2XεM21 1

0

e−Ltdtu2X

≥ 1

2u2X−1

8u2X−1 8u2X 1

4u2X.

3.6

Takeαδ2/4M12, ρδ/M1, thenϕuα,∀u∈Y∂Bρ.

Finally, we verify conditionA2inTheorem 2.3. According toH1, for anyuM >0 andt∈0,1we have that

Gt, u uβ

u

uβgt, u−βuβ−1Gt, u

u ugt, uβGt, u

uβ1 ≥0. 3.7

Hence

Gt, u

uβGt, M

MβM−βmin

t∈0,1Gt, M C>0 3.8

for allt∈0,1anduM >0. This implies thatGt, uCuβfor allt∈0,1anduM >0.

Similarly, we can prove that there is a constantC>0 such thatGt, uC|u|βfor allt∈0,1 andu≤ −M. SinceGt, uC4|u|βis continuous on0,1×−M, M, there existsC5>0 such

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thatGt, uC4|u|β>−C5on0, T×−M, M. Thus, we have

Gt, uC4|u|βC5 ∀t, u∈0,1×R, 3.9

whereC4min{C, C}.

Similarly, there exist constantsC6, C7>0 such that u

0

Iksds≥C6|u|βC7 ∀t, u∈0,1×R. 3.10

For everyξ ∈ R\ {0}anduW\ {0}, by2.8,3.9, and3.10, we have that the following inequality:

ϕξu≤ 1

2ξu2Xp−1

k1

e−Ltk

C6|ξutk|βC7

1

0

e−Lt

C4|ξu|βC5 dt

ξ2

2u2X−C6|ξ|β p−1 k1

e−Ltk|utk|βC7

p−1 k1

e−Ltk−C4|ξ|β 1

0

e−Lt|ut|βdtC5

1

0

e−Ltdt 3.11

holds. TakewWsuch thatwX1, sinceβ >2,3.11implies that there existsξ>0 such thatξwX > ρandϕξw<0 forξξ >0. SinceWis a finite dimensional subspace, there existsRW>0 such thatϕu≤0 onW\BRW. ByTheorem 2.3,ϕpossesses infinite many critical points; that is, IBVP1.1has infinite many classical solutions.

Theorem 3.2. Assume that (H1) and the first equality in (H2) hold. Moreover,gt, uis odd about uand the impulsive functionsIkuare odd and nonincreasing. Then IBVP1.1has infinitely many classical solutions.

Proof. We only verifyA1inTheorem 2.3. SinceIkuare odd and nonincreasing continuous functions, then for anyu ∈R,u

0Iksds < 0. So we havep−1

k1e−Ltkuntk

0 Iksds < 0. Take ε1/8M211

0e−Ltdt >0, α3δ2/8M21, ρδ/M1, like in3.6we can obtain the result.

Theorem 3.3. Suppose that the first inequalities in (H1), (H3), and (H4) hold. Furthermore, one assumes thatgt, uand the impulsive functionsIkuare odd aboutuand we have the following.

H7There existsA0>0 such that

A0

2 > M1 p−1 k1

e−Ltk

bkMγ1kAγ0k ak M1

h2Mp11Ap01h11

0

e−Ltdt. 3.12

Then IBVP1.1has infinitely many classical solutions.

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Proof. Obviously,ϕis an even functional andϕ0 0. Firstly, we will show thatϕsatisfies the Palais-Smale condition. As in the proof of Theorem 3.1, by 2.8, 2.9, 3.1, the first inequalities inH1andH4, we have

β 2 −1

un2X β

2un2Xun2X βϕunϕununβ

p−1 k1

e−Ltk untk

0

Iksdsβ 1

0

e−LtGt, undt

p−1

k1

e−LtkIkuntkuntk1

0

e−Ltgt, unundt

βϕunϕunun 1

0

e−Lt

βGt, ungt, unun

dt

β

p−1

k1

e−Ltk untk

0

Iksds−p−1

k1

e−LtkIkuntkuntk

βC3M21C3unX 1

0

e−Ltdt max

t∈0,1, unt∈−M,MβGt, ungt, unun

β1p−1

k1

e−Ltk

akM1unXbkM1γk1unγXk1 .

3.13

It follows that{un}is bounded inX. In the following, the proof of P. S. condition is the same as that inTheorem 3.1, and we omit it here.

Secondly, as in Theorem 3.1, we can obtain that condition A2 in Theorem 2.1 is satisfied.

Take the same direct sum decompositionXVYas inTheorem 3.1. For anyuY, by2.8,H3, andH4, we obtain

ϕu 1

2u2Xp−1

k1

e−Ltk utk

0

Iksds− 1

0

e−LtGt, udt

≥ 1

2u2Xp−1

k1

e−Ltk

akM1uXbkMγ1k1uγXk1

1

0

e−Ltdt

h1M1uXh2Mp111upX11

1

2u2Xp−1

k1

e−LtkbkMγ1k1uγXk1h2Mp111 1

0

e−LtdtupX11

M1uX p−1

k1

e−Ltkakh1 1

0

e−Ltdt

.

3.14

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In view ofH7, setuXρ:A0>0, then we have

ϕuα 1

2A20p−1

k1

e−LtkbkMγ1k1Aγ0k1h2M1p11 1

0

e−LtdtAp011

M1A0

p−1

k1

e−Ltkakh1

1

0

e−Ltdt

>0.

3.15

Therefore,ϕuα,∀u∈Y∂Bρ.ByTheorem 2.3,ϕpossesses infinite many critical points, that is, IBVP1.1has infinite many classical solutions.

Theorem 3.4. Assume that the second inequalities in (H1), (H5), and (H6) hold, moreover, one assumes the following.

H8There existsA1>0 such that

A1

2 > M1

p−1

k1

e−Ltk

bkM1γkAγ1k ak M1

r2Mμ1Aμ1r11

0

e−Ltdt. 3.16

Then IBVP1.1has at least two classical solutions.

Proof. We will use Theorems2.1and2.2to prove the main results. Firstly, we will show that ϕsatisfies the Palais-Smale condition. Similarly, as in the proof ofTheorem 3.1, by2.8,2.9, 3.1, the second inequalities inH1andH5, we have

β 2−1

un2X β

2un2Xun2X βϕunϕununβ

p−1 k1

e−Ltk untk

0

Iksdsβ 1

0

e−LtGt, undt

p−1

k1

e−LtkIkuntkuntk1

0

e−Ltgt, unundt

βC3M21C3unX 1

0

e−Ltdt

r1r2M1μunμX

β 1

0

e−Ltdt

M1r1unXr2Mμ11 unμ1X

p−1

k1

e−Ltk max

untk∈−M,M

β

untk

0

Iksds−Ikuntkuntk

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βC3M21C3unX 1

0

e−Ltdt

r1r2M1μunμX

βM1unX1

p−1

k1

e−Ltk max

untk∈−M,M

β

untk

0

Iksds−Ikuntkuntk .

3.17

It follows that{un}is bounded inX. In the following, the proof of P. S. condition is the same as that inTheorem 3.1, and we omit it here.

Let A > 0, which will be determined later. Set BA : {u ∈ X : uX < A}, then BA : {u ∈ X : uXA} is a closed ball. From the reflexivity ofX, we can easily obtain thatBA is bounded and weakly sequentially closed. We will show thatϕ is weakly lower semicontinuous onBA. Let

ϕ1u 1 2

1

0

e−Ltptut2dt 1

0

e−Ltqt|ut|2dt,

ϕ2u −p−1

k1

e−Ltk utk

0

Iksds− 1

0

e−LtGt, udt.

3.18

Thenϕu ϕ1u ϕ2u. By un u onX we see that{un} uniformly converges to u inC0,1. Soϕ2is weakly continuous. Clearly, ϕ1is continuous, which, together with the convexity ofϕ1, implies thatϕ1is weakly lower semicontinuous. Therefore,ϕis weakly lower semi-continuous onBA. So byTheorem 2.1, without loss of generality, we assume thatϕu0

infu∈B

Aϕu. Now we will show that

ϕu0< inf

u∈∂BA

ϕu. 3.19

For anyu∂BA, byH5andH6, we have

ϕu 1

2u2Xp−1

k1

e−Ltk utk

0

Iksds− 1

0

e−LtGt, udt

≥ 1

2u2XM1

p−1 k1

e−Ltk

bkMγ1kuγXk1akuX

M1 1

0

e−Ltdt

r2M1μuμ1X r1uX .

3.20

(15)

Hence

u∈∂BinfA

ϕu≥ 1

2u2XM1

p−1

k1

e−Ltk

bkMγ1kuγXk1akuX

M1

1

0

e−Ltdt

r2Mμ1uμ1X r1uX .

3.21

In view ofH8, takeA A1 > 0, we have infu∈∂BA

1ϕu > 0, for anyu∂BA1. Soϕu0 <

ϕ0 0<infu∈∂BA1ϕu.

Next we will verify that there exists a u1 with u1X > A1 such that ϕu1 <

infu∈∂BA

1ϕu. Letξ∈R\ {0}, Bt 1. Then by3.10andH5, we have ϕξB ξ2

2 1

0

e−Ltqtdtp−1

k1

e−Ltk ξ

0

Iksds− 1

0

e−LtGt, ξdt

ξ2 2

1

0

e−LtqtdtC6|ξ|βp−1

k1

e−LtkC7

p−1 k1

e−Ltk

r2|ξ|μ1r1|ξ|1

0

e−Ltdt.

3.22

Sinceβ > 2,0 ≤ μ < 1, we have lim|ξ| →ϕξB −∞. Therefore, there exists a sufficiently largeξ0 > 0 withξ0BX > A1such that ϕξ0B < infu∈∂BA

1ϕu. Setu1 ξ0B, thenϕu1 <

infu∈∂BA

1ϕu. So byTheorem 2.2, there existsu2X such thatϕu2 0. Therefore,u0and u2are two critical points ofϕ, and they are classical solutions of IBVP1.1.

Remark 3.5. Obviously, ifgis a bounded function, in view ofTheorem 3.4, we can obtain the same result.

Theorem 3.6. Suppose that (H4) and (H5) hold. Then IBVP1.1has at least one solution.

Proof. The proof is similar to that in19, and we omit it here.

Corollary 3.7. Suppose thatgand impulsive functionsIk, k1,2, . . . , p−1 are bounded, then IBVP 1.1has at least one solution.

4. Some Examples

Example 4.1. Consider the following problem:

−ut ut ut gt, ut, t /tk, a.e. t∈0,1,

−Δ utk

Ikutk, k1,2, u0 u

1 0,

4.1

wheregt, u 4u36tu5, Iku u3.

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