Boundary Value Problems
Volume 2009, Article ID 316812,17pages doi:10.1155/2009/316812
Research Article
Variational Method to the Impulsive Equation with Neumann Boundary Conditions
Juntao Sun and Haibo Chen
Department of Mathematics, Central South University, Changsha, 410075 Hunan, China
Correspondence should be addressed to Juntao Sun,[email protected] Received 28 August 2009; Accepted 28 September 2009
Recommended by Pavel Dr´abek
We study the existence and multiplicity of classical solutions for second-order impulsive Sturm- Liouville equation with Neumann boundary conditions. By using the variational method and critical point theory, we give some new criteria to guarantee that the impulsive problem has at least one solution, two solutions, and infinitely many solutions under some different conditions, respectively. Some examples are also given in this paper to illustrate the main results.
Copyrightq2009 J. Sun and H. Chen. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
1. Introduction
In this paper, we consider the boundary value problem of second-order Sturm-Liouville equation with impulsive effects
−
ptut
rtut qtut gt, ut, t /tk, a.e. t∈0,1,
−Δ
ptkutk
Ikutk, k1,2, . . . , p−1, u0 u
1− 0,
1.1
where 0 t0 < t1 < t2 < · · · < tp−1 < tp 1, p ∈ C10,1, r, q ∈ C0,1 withp and q positive functions,g :0,1×R → Ris a continuous function,Ik:R → R,1≤k≤p−1 are continuous,−Δptkutk −ptkutk−ut−k,utkandut−kdenote the right and the left limits, respectively, ofutatttk,u0is the right limit ofu0, andu1−is the left limit ofu1.
In the recent years, a great deal of work has been done in the study of the existence of solutions for impulsive boundary value problemsIBVPs, by which a number
of chemotherapy, population dynamics, optimal control, ecology, industrial robotics, and physics phenomena are described. For the general aspects of impulsive differential equations, we refer the reader to the classical monograph1. For some general and recent works on the theory of impulsive differential equations, we refer the reader to2–9. Some classical tools or techniques have been used to study such problems in the literature. These classical techniques include the coincidence degree theory of Mawhin10, the method of upper and lower solutions with monotone iterative technique11, and some fixed point theorems in cones12–14.
On the other hand, in the last two years, some researchers have used variational methods to study the existence of solutions for impulsive boundary value problems.
Variational method has become a new powerful tool to study impulsive differential equations, we refer the reader to 15–20. More precisely, in 15, the authors studied the following equation with impulsive effects:
− ρtφp
ut
stφput ft, ut, t /tj, a.e. t∈a, b,
−Δ ρ
tj φp
u tj
Ij u
tj
, j1,2, . . . , l, αua−βua A, γub σub B,
1.2
wheref :a, b×0,∞ → 0,∞is continuous,Ij:0,∞ → 0,∞, j 1,2, . . . , l, are continuous, andα, β, γ, σ >0. They essentially proved that IBVP1.2has at least two positive solutions via variational method. Recently, in16, using variational method and critical point theory, Nieto and O’Regan studied the existence of solutions of the following equation:
−ut λut ft, ut, t /tj, a.e. t∈0, T, Δ
u tj
Ij
u tj
, j 1,2, . . . , l,
u0 uT 0,
1.3
where f : 0, T×R → Ris continuous, and Ij : R → R, j 1,2, . . . , l are continuous.
They obtained that IBVP1.3has at least one solution. Shortly, in17, authors extended the results of IBVP1.3.
In19,Zhou and Li studied the existence of solutions of the following equation:
−ut gtut ft, ut, t /tj, a.e. t∈0, T, Δ
u tj
Ij u
tj
, j 1,2, . . . , p,
u0 uT 0,
1.4
wheref : 0, T×R → Ris continuous, and Ij : R → R, j 1,2, . . . , p, are continuous.
They proved that IBVP1.4has at least one solution and infinitely many solutions by using variational method and critical point theorem.
Motivated by the above facts, in this paper, our aim is to study the variational structure of IBVP1.1in an appropriate space of functions and obtain the existence and multiplicity of solutions for IBVP1.1by using variational method. To the best of our knowledge, there
is no paper concerned impulsive differential equation with Neumann boundary conditions via variational method. In addition, this paper is a generalization of21, in which impulse effects are not involved.
In this paper, we will need the following conditions.
H1There is constantsβ >2, M >0 such that for everyt∈0,1andu∈Rwith|u| ≥M,
0< βGt, u≤ugt, u, 0< β u
0
Iksds≤uIku, 1.5
whereGt, u u
0gt, sds.
H2limu→0gt, u/u0 uniformly fort∈0,1, and limu→0Iku/u0.
H3There exist numbersh1, h2>0 andp1 >1 such that
gt, u≤h1h2|u|p1 foru∈R, t∈0,1. 1.6
H4There exist numbersak, bk>0 andγk∈0,1such that
Iku≤akbk|u|γk foru∈R. 1.7
H5There exist numbersr1, r2>0 andμ∈0,1such that
gt, u≤r1r2|u|μ foru∈R, t∈0,1. 1.8
H6There exist numbersak, bk >0 andγk ∈1,∞such that
Iku≤akbk|u|γk foru∈R. 1.9
This paper is organized as follows. InSection 2, we present some preliminaries. In Section 3, we discuss the existence and multiplicity of classical solutions to IBVP1.1. Some examples are presented in this section to illustrate our main results in the last section.
2. Preliminaries
Take Lt t
0rs/psds. Then e−Lt ∈ C10,1. We transform IBVP 1.1 into the following equivalent form:
−
e−Ltptut
e−Ltqtut e−Ltgt, ut, t /tk, a.e. t∈0,1,
−Δ
e−Ltkptkutk
e−LtkIkutk, k1,2, . . . , p−1, u0 u
1− 0.
2.1
Obviously, the solutions of IBVP2.1are solutions of IBVP 1.1. So it suffices to consider IBVP2.1.
In this section, the following theorem will be needed in our argument. Suppose thatE is a Banach spacein particular a Hilbert spaceandϕ∈C1E,R. We say thatϕsatisfies the Palais-Smale condition if any sequence{uj} ⊂Efor whichϕujis bounded andϕuj → 0 asj → ∞possesses a convergent subsequence inX. LetBr be the open ball inXwith the radiusrand centered at 0 and∂Br denote its boundary.
Theorem 2.1 22, Theorem 38.A. For the functional F : M ⊆ X → −∞,∞ with M /∅,minu∈MFu αhas a solution for which the following hold:
iXis a real reflexive Banach space;
iiMis bounded and weakly sequentially closed;
iiiF is weakly sequentially lower semicontinuous on M; that is, by definition, for each sequence{un}in Msuch thatun uasn → ∞, one has Fu ≤ lim infn→ ∞Fun holds.
Theorem 2.216, Theorem 2.2. LetEbe a real Banach space and letϕ ∈ C1E,Rsatisfy the Palais-Smale condition. Assume there existu0, u1∈Eand a bounded open neighborhoodΩofu0such thatu1∈E\Ωand
max
ϕu0, ϕu1 < inf
x∈∂Ωϕu. 2.2
Let
Γ {h|h:0,1−→Eis continuous andh0 u0, h1 u1}, cinf
h∈Γmax
s∈0,1ϕhs. 2.3
Thencis a critical value ofϕ; that is, there existsu∗∈Esuch thatϕu∗ Θandϕu∗ c, where c >max{ϕu0, ϕu1}.
Theorem 2.3 23. Let Ebe a real Banach space, and let ϕ ∈ C1E,Rbe even satisfying the Palais-Smale condition andϕ0 0. IfEV⊕Y, whereV is finite dimensional, andϕsatisfies that
A1there exist constantsρ, α >0 such thatϕ|∂Br∩Y ≥α,
A2for each finite dimensional subspaceW ⊂E, there isR RWsuch thatϕu≤0 for all u∈Wwithu ≥R.
Thenϕpossesses an unbounded sequence of critical values.
Let us recall some basic knowledge. Denote byXthe Sobolev spaceW1,20,1, and consider the inner product
u, v 1
0
utvtdt 1
0
utvtdt 2.4
which induces the usual norm
u 1
0
ut2dt 1
0
|ut|2dt 1/2
. 2.5
We also consider the inner product
u, vX 1
0
e−Ltptutvtdt 1
0
e−Ltqtutvtdt, 2.6
and the norm
uX 1
0
e−Ltptut2dt 1
0
e−Ltqt|ut|2dt 1/2
, 2.7
then the norm · Xis equivalent to the usual norm · inW1,20,1. Hence,Xis reflexive.
We define the norm inC0,1, L20,1asu∞ maxt∈0,1|ut|andu2 1
0|u|2dt1/2, respectively.
Foru∈W2,20,1, we have thatu, uare absolutely continuous, andu ∈L20,1, hence −Δe−Ltkptkutk −e−Ltkptkutk−ut−k 0,for any tk ∈ 0,1. Ifu ∈ X, thenuis absolutely continuous and u ∈ L20,1. In this case, the one-side derivatives u0, u1−, utk, ut−k, k 1,2, . . . , p−1 may not exist. As a consequence, we need to introduce a different concept of solution. We say thatu ∈ C0,1is a classical solution of IBVP2.1if it satisfies the equation in IBVP 2.1a.e. on0,1, the limitsutk, ut−k, k 1,2, . . . , p−1 exist and impulsive conditions in IBVP2.1hold,u0, u1−exist andu0 u1− 0. Moreover, for everyk0,1, . . . , p−1, uku|tk,tk1satisfyuk∈W2,2tk, tk1.
For eachu∈X, consider the functionalϕdefined onXby
ϕu 1
2u2X−p−1
k1
e−Ltk utk
0
Iksds− 1
0
e−LtGt, udt. 2.8
It is clear thatϕis differentiable at anyu∈Xand
ϕuv
1
0
e−Ltptutvt e−Ltqtutvt dt
−p−1
k1
e−LtkIkutkvtk− 1
0
e−Ltgt, utvtdt
2.9
for anyv∈X. Obviously,ϕis continuous.
Lemma 2.4. Ifu ∈ X is a critical point of the functionalϕ, thenuis a classical solution of IBVP 2.1.
Proof. Letu∈Xbe a critical point of the functionalϕ. It shows that 1
0
e−Ltptutvte−Ltqtutvt dt
−p−1
k1
e−LtkIkutkvtk− 1
0
e−Ltgt, utvtdt0
2.10
holds for any v ∈ X. Choose any j ∈ {0,1,2, . . . , p−1} and v ∈ X such that vt 0 if t∈tk, tk1fork /j. Equation2.10implies
tj1
tj
e−Ltptutvt e−Ltqtutvt−e−Ltgt, utvt
dt0. 2.11
This means, for anyw∈W01,2tj, tj1, tj1
tj
e−Ltptujtwt e−Ltqtujtwt−e−Ltg t, ujt
wt
dt0, 2.12
whereuju|tj,tj1. Thusujis a weak solution of the following equation:
−
e−Ltptut
e−Ltqtut e−Ltgt, ut t∈ tj, tj1
, 2.13
and therefore uj ∈ W01,2tj, tj1 ⊂ Ctj, tj1.Let ht : e−Ltgt, u−qu, then 2.13 becomes the following form:
−
e−Ltptut
hton tj, tj1
, j0,1,2, . . . , p−1. 2.14
Then the solution of2.14can be written as
ujt C1C2
t
tj
eLs−lnpsds− t
tj
eLs−lnps s
tj
hr
prelnprdr
ds t∈ tj, tj1
, 2.15
whereC1 andC2 are two constants. Thenuj ∈ Ctj, tj1anduj ∈ Ctj, tj1. Therefore,uj is a classical solution of2.13andusatisfies the equation in IBVP2.1a.e. on0,1. By the
previous equation, we can easily get that the limitsutj, ut−j, j 1,2, . . . , p−1, ut0and ut−pexist. By integrating2.10, one has
1
0
e−Ltptutvt e−Ltqtutvt dt
−p−1
k1
e−LtkIkutkvtk− 1
0
e−Ltgt, utvtdt
−p−1
k1
Δ
e−Ltkptkutk
vtk e−L1p1u 1−
v1
−e−L0p0u0v0−p−1
k1
e−LtkIkutkvtk
1
0
−
e−Ltptut
e−Ltqtut−e−Ltgt, ut
vtdt
−p−1
k1
Δ
e−Ltkptkutk
e−LtkIkutk vtk
e−L1p1u 1−
v1−e−L0p0u0v0
1
0
−
e−Ltptut
e−Ltqtut−e−Ltgt, ut
vtdt0,
2.16
and combining with2.13we get
−p−1
k1
Δ
e−Ltkptkutk
e−LtkIkutk vtk
e−L1p1u 1−
v1−e−L0p0u0v00.
2.17
Next we will show thatusatisfies the impulsive conditions in IBVP2.1. If not, without loss of generality, we assume that there existsi∈ {1,2, . . . , p−1}such that
e−LtiIiuti Δ
e−Ltiptiuti
/0. 2.18
Let
vt p k0, k /i
t−tk. 2.19
Obviously,v∈X. Substituting them into2.17, we get
Δe−Ltiptiuti e−LtiIiuti
vti 0 2.20
which contradicts2.18. Sousatisfies the impulsive conditions in IBVP2.1. Thus,2.17 becomes the following form:
e−L1p1u 1−
v1−e−L0p0u0v0 0, 2.21
for all v ∈ X. Since v0, v1 are arbitrary, 2.21 shows that e−L1p1u1− e−L0p0u0 0,and it impliesu1− u0 0. Therefore, uis a classical solution of IBVP2.1.
Lemma 2.5. Letu∈X. Thenu∞≤M1uX, where
M121/2max
1
mint∈0,1e−Ltpt1/2, 1
mint∈0,1e−Ltqt1/2
. 2.22
Proof. By using the same methods of15, Lemma 2.6, we easily obtain the above result, and we omit it here.
3. Main Results
In this section, we will show our main results and prove them.
Theorem 3.1. Assume that (H1) and (H2) hold. Moreover,gt, uand the impulsive functionsIku are odd aboutu, then IBVP1.1has infinitely many classical solutions.
Proof. Obviously,ϕis an even functional andϕ0 0. We divide our proof into three parts in order to showTheorem 3.1.
Firstly, We will show that ϕ satisfies the Palais-Smale condition. Let {ϕun} be a bounded sequence such that limn→∞ϕun 0. Then there exists constants C3 > 0 such that
ϕun≤C3, ϕun
X≤C3. 3.1
By2.8,2.9,3.1, andH1, we have β
2 −1
un2X β
2un2X− un2X βϕun−ϕununβ
p−1 k1
e−Ltk untk
0
Iksdsβ 1
0
e−LtGt, undt
−p−1
k1
e−LtkIkuntkuntk− 1
0
e−Ltgt, unundt
p−1
k1
e−Ltk
β untk
0
Iksds−Ikuntkuntk
1
0
e−Lt
βGt, un−gt, unun
dtβϕun−ϕunun
≤βC3M21C3unX
1
0
e−Ltdt max
t∈0,1, unt∈−M,MβGt, un−gt, unun p−1
k1
e−Ltk max
untk∈−M,M
β
untk
0
Iksds−Ikuntkuntk .
3.2
It follows that{un} is bounded in X. From the reflexivity of X, we may extract a weakly convergent subsequence that, for simplicity, we call{un}, un uinX. In the following we will verify that{un}strongly converges touinX. By2.9we have
ϕun−ϕu
un−u un−u2X
−p−1
k1
e−LtkIkuntk−Ikutnuntk−utk
− 1
0
e−Lt
gt, unt−gt, ut
unt−utdt.
3.3
Byun uinX, we see that{un}uniformly converges touinC0,1. So 1
0
e−Lt
gt, unt−gt, ut
unt−utdt−→0, p−1
k1
e−LtkIkuntk−Ikutkuntk−utk−→0, ϕun−ϕu
un−u−→0 asn−→∞.
3.4
By3.3,3.4, we obtainun−uX → 0 asn → ∞. That is,{un}strongly converges touin X, which means the that P. S. condition holds forϕ.
Secondly, we verify the conditionA1 in Theorem 2.3. Let V R, Y {u ∈ X | 1
0utdt 0}, then X V ⊕ Y, where dimV 1 < ∞. In view of H2, take ε min{1/8M211
0e−Ltdt,1/8M21p−1
k1e−Ltk} > 0, there exists anδ > 0 such that for every u with|u|< δ,
Gt, u≤ε|u|2, u
0
Iksds≤ε|u|2. 3.5
Hence, for anyu∈Y withuX ≤δ/M1, by2.8and3.5, we have
ϕu 1
2u2X−p−1
k1
e−Ltk utk
0
Iksds− 1
0
e−LtGt, udt
≥ 1
2u2X−p−1
k1
e−Ltkε|uktk|2− 1
0
e−Ltε|ut|2dt
≥ 1
2u2X−εM21 p−1 k1
e−Ltku2X−εM21 1
0
e−Ltdtu2X
≥ 1
2u2X−1
8u2X−1 8u2X 1
4u2X.
3.6
Takeαδ2/4M12, ρδ/M1, thenϕu≥α,∀u∈Y ∩∂Bρ.
Finally, we verify conditionA2inTheorem 2.3. According toH1, for anyu≥M >0 andt∈0,1we have that
Gt, u uβ
u
uβgt, u−βuβ−1Gt, u
u2β ugt, u−βGt, u
uβ1 ≥0. 3.7
Hence
Gt, u
uβ ≥ Gt, M
Mβ ≥M−βmin
t∈0,1Gt, M C>0 3.8
for allt∈0,1andu≥M >0. This implies thatGt, u≥Cuβfor allt∈0,1andu≥M >0.
Similarly, we can prove that there is a constantC>0 such thatGt, u≥C|u|βfor allt∈0,1 andu≤ −M. SinceGt, u−C4|u|βis continuous on0,1×−M, M, there existsC5>0 such
thatGt, u−C4|u|β>−C5on0, T×−M, M. Thus, we have
Gt, u≥C4|u|β−C5 ∀t, u∈0,1×R, 3.9
whereC4min{C, C}.
Similarly, there exist constantsC6, C7>0 such that u
0
Iksds≥C6|u|β−C7 ∀t, u∈0,1×R. 3.10
For everyξ ∈ R\ {0}andu ∈ W\ {0}, by2.8,3.9, and3.10, we have that the following inequality:
ϕξu≤ 1
2ξu2X−p−1
k1
e−Ltk
C6|ξutk|β−C7
− 1
0
e−Lt
C4|ξu|β−C5 dt
≤ ξ2
2u2X−C6|ξ|β p−1 k1
e−Ltk|utk|βC7
p−1 k1
e−Ltk−C4|ξ|β 1
0
e−Lt|ut|βdtC5
1
0
e−Ltdt 3.11
holds. Takew∈Wsuch thatwX1, sinceβ >2,3.11implies that there existsξ>0 such thatξwX > ρandϕξw<0 forξ ≥ξ >0. SinceWis a finite dimensional subspace, there existsRW>0 such thatϕu≤0 onW\BRW. ByTheorem 2.3,ϕpossesses infinite many critical points; that is, IBVP1.1has infinite many classical solutions.
Theorem 3.2. Assume that (H1) and the first equality in (H2) hold. Moreover,gt, uis odd about uand the impulsive functionsIkuare odd and nonincreasing. Then IBVP1.1has infinitely many classical solutions.
Proof. We only verifyA1inTheorem 2.3. SinceIkuare odd and nonincreasing continuous functions, then for anyu ∈R,u
0Iksds < 0. So we havep−1
k1e−Ltkuntk
0 Iksds < 0. Take ε1/8M211
0e−Ltdt >0, α3δ2/8M21, ρδ/M1, like in3.6we can obtain the result.
Theorem 3.3. Suppose that the first inequalities in (H1), (H3), and (H4) hold. Furthermore, one assumes thatgt, uand the impulsive functionsIkuare odd aboutuand we have the following.
H7There existsA0>0 such that
A0
2 > M1 p−1 k1
e−Ltk
bkMγ1kAγ0k ak M1
h2Mp11Ap01h11
0
e−Ltdt. 3.12
Then IBVP1.1has infinitely many classical solutions.
Proof. Obviously,ϕis an even functional andϕ0 0. Firstly, we will show thatϕsatisfies the Palais-Smale condition. As in the proof of Theorem 3.1, by 2.8, 2.9, 3.1, the first inequalities inH1andH4, we have
β 2 −1
un2X β
2un2X− un2X βϕun−ϕununβ
p−1 k1
e−Ltk untk
0
Iksdsβ 1
0
e−LtGt, undt
−p−1
k1
e−LtkIkuntkuntk− 1
0
e−Ltgt, unundt
βϕun−ϕunun 1
0
e−Lt
βGt, un−gt, unun
dt
β
p−1
k1
e−Ltk untk
0
Iksds−p−1
k1
e−LtkIkuntkuntk
≤βC3M21C3unX 1
0
e−Ltdt max
t∈0,1, unt∈−M,MβGt, un−gt, unun
β1p−1
k1
e−Ltk
akM1unXbkM1γk1unγXk1 .
3.13
It follows that{un}is bounded inX. In the following, the proof of P. S. condition is the same as that inTheorem 3.1, and we omit it here.
Secondly, as in Theorem 3.1, we can obtain that condition A2 in Theorem 2.1 is satisfied.
Take the same direct sum decompositionXV⊕Yas inTheorem 3.1. For anyu∈Y, by2.8,H3, andH4, we obtain
ϕu 1
2u2X−p−1
k1
e−Ltk utk
0
Iksds− 1
0
e−LtGt, udt
≥ 1
2u2X−p−1
k1
e−Ltk
akM1uXbkMγ1k1uγXk1
− 1
0
e−Ltdt
h1M1uXh2Mp111upX11
1
2u2X−p−1
k1
e−LtkbkMγ1k1uγXk1−h2Mp111 1
0
e−LtdtupX11
−M1uX p−1
k1
e−Ltkakh1 1
0
e−Ltdt
.
3.14
In view ofH7, setuXρ:A0>0, then we have
ϕu≥α 1
2A20−p−1
k1
e−LtkbkMγ1k1Aγ0k1−h2M1p11 1
0
e−LtdtAp011
−M1A0
p−1
k1
e−Ltkakh1
1
0
e−Ltdt
>0.
3.15
Therefore,ϕu≥α,∀u∈Y ∩∂Bρ.ByTheorem 2.3,ϕpossesses infinite many critical points, that is, IBVP1.1has infinite many classical solutions.
Theorem 3.4. Assume that the second inequalities in (H1), (H5), and (H6) hold, moreover, one assumes the following.
H8There existsA1>0 such that
A1
2 > M1
p−1
k1
e−Ltk
bkM1γkAγ1k ak M1
r2Mμ1Aμ1r11
0
e−Ltdt. 3.16
Then IBVP1.1has at least two classical solutions.
Proof. We will use Theorems2.1and2.2to prove the main results. Firstly, we will show that ϕsatisfies the Palais-Smale condition. Similarly, as in the proof ofTheorem 3.1, by2.8,2.9, 3.1, the second inequalities inH1andH5, we have
β 2−1
un2X β
2un2X− un2X βϕun−ϕununβ
p−1 k1
e−Ltk untk
0
Iksdsβ 1
0
e−LtGt, undt
−p−1
k1
e−LtkIkuntkuntk− 1
0
e−Ltgt, unundt
≤βC3M21C3unX 1
0
e−Ltdt
r1r2M1μunμX
β 1
0
e−Ltdt
M1r1unXr2Mμ11 unμ1X
p−1
k1
e−Ltk max
untk∈−M,M
β
untk
0
Iksds−Ikuntkuntk
βC3M21C3unX 1
0
e−Ltdt
r1r2M1μunμX
βM1unX1
p−1
k1
e−Ltk max
untk∈−M,M
β
untk
0
Iksds−Ikuntkuntk .
3.17
It follows that{un}is bounded inX. In the following, the proof of P. S. condition is the same as that inTheorem 3.1, and we omit it here.
Let A > 0, which will be determined later. Set BA : {u ∈ X : uX < A}, then BA : {u ∈ X : uX ≤ A} is a closed ball. From the reflexivity ofX, we can easily obtain thatBA is bounded and weakly sequentially closed. We will show thatϕ is weakly lower semicontinuous onBA. Let
ϕ1u 1 2
1
0
e−Ltptut2dt 1
0
e−Ltqt|ut|2dt,
ϕ2u −p−1
k1
e−Ltk utk
0
Iksds− 1
0
e−LtGt, udt.
3.18
Thenϕu ϕ1u ϕ2u. By un u onX we see that{un} uniformly converges to u inC0,1. Soϕ2is weakly continuous. Clearly, ϕ1is continuous, which, together with the convexity ofϕ1, implies thatϕ1is weakly lower semicontinuous. Therefore,ϕis weakly lower semi-continuous onBA. So byTheorem 2.1, without loss of generality, we assume thatϕu0
infu∈B
Aϕu. Now we will show that
ϕu0< inf
u∈∂BA
ϕu. 3.19
For anyu∈∂BA, byH5andH6, we have
ϕu 1
2u2X−p−1
k1
e−Ltk utk
0
Iksds− 1
0
e−LtGt, udt
≥ 1
2u2X−M1
p−1 k1
e−Ltk
bkMγ1kuγXk1akuX
−M1 1
0
e−Ltdt
r2M1μuμ1X r1uX .
3.20
Hence
u∈∂BinfA
ϕu≥ 1
2u2X−M1
p−1
k1
e−Ltk
bkMγ1kuγXk1akuX
−M1
1
0
e−Ltdt
r2Mμ1uμ1X r1uX .
3.21
In view ofH8, takeA A1 > 0, we have infu∈∂BA
1ϕu > 0, for anyu ∈∂BA1. Soϕu0 <
ϕ0 0<infu∈∂BA1ϕu.
Next we will verify that there exists a u1 with u1X > A1 such that ϕu1 <
infu∈∂BA
1ϕu. Letξ∈R\ {0}, Bt 1. Then by3.10andH5, we have ϕξB ξ2
2 1
0
e−Ltqtdt−p−1
k1
e−Ltk ξ
0
Iksds− 1
0
e−LtGt, ξdt
≤ ξ2 2
1
0
e−Ltqtdt−C6|ξ|βp−1
k1
e−LtkC7
p−1 k1
e−Ltk
r2|ξ|μ1r1|ξ|1
0
e−Ltdt.
3.22
Sinceβ > 2,0 ≤ μ < 1, we have lim|ξ| →∞ϕξB −∞. Therefore, there exists a sufficiently largeξ0 > 0 withξ0BX > A1such that ϕξ0B < infu∈∂BA
1ϕu. Setu1 ξ0B, thenϕu1 <
infu∈∂BA
1ϕu. So byTheorem 2.2, there existsu2 ∈X such thatϕu2 0. Therefore,u0and u2are two critical points ofϕ, and they are classical solutions of IBVP1.1.
Remark 3.5. Obviously, ifgis a bounded function, in view ofTheorem 3.4, we can obtain the same result.
Theorem 3.6. Suppose that (H4) and (H5) hold. Then IBVP1.1has at least one solution.
Proof. The proof is similar to that in19, and we omit it here.
Corollary 3.7. Suppose thatgand impulsive functionsIk, k1,2, . . . , p−1 are bounded, then IBVP 1.1has at least one solution.
4. Some Examples
Example 4.1. Consider the following problem:
−ut ut ut gt, ut, t /tk, a.e. t∈0,1,
−Δ utk
Ikutk, k1,2, u0 u
1− 0,
4.1
wheregt, u 4u36tu5, Iku u3.