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On Positive Solutions of Functional- Differential Equations in Banach Spaces
MIROSLAWA ZIMA
Instituteof Mathematics, Pedagogical University ofRzeszOw, 35-310RzeszSw,Poland
(Received9July1999; Revised17December1999)
Inthispaper, we dealwithtwo pointboundaryvalueproblem (BVP)forthe functional- differential equation of second order
x"(t)
+
kx’(t)+
f(t,x(hl(t)),x(h2(t))) O, ax(-l) bx’(-l):0,cx(l)
+
dx’(1)=0,where thefunctionftakes valuesin aconeKofaBanach space E. For hi(t)---tand h2(t)=-twe obtainthe BVP with reflection of the argument. Applying fixed point theoremonstrictset-contractionfromG.Li,Proc. Amer.Math.Soc.97(1986),277-280, weprove theexistenceof positivesolution inthespaceC([-I,1], E). Someinequalities involvingfand the respectiveGreen’sfunction areused.Wealso give the application of our existenceresultsto the infinite system of functional-differential equations in the caseE
Keywords: Boundary valueprobleminaBanach space;Positivesolution;Cone;
Fixedpoint theorem
1991Mathematics SubjectClassification:34G20,34K10
1
INTRODUCTION
Let K
be a cone in arealBanachspace E.We
will assumethatthenormI[" I[
inE
is monotonic with respect toK,
that is, if 0-<x-< y thenI[x[[g_< ][y[[,
where-<
denotes the partial ordering definedby Kand359
0standsfor the zero elementof
E.
Further,denotebyC(I, E)
the space ofallcontinuous functions defined onthe interval[-1, 1]
and taking valuesinE,
equippedwiththenormIlxll mt x IIx(t)ll .
Obviously,
C(L E)
isaBanach space.Let
Q {x C(I,E):
0-< x(t)
forI}.
It
is easy toprovethatQ
isacone inC(L E).
In
thispaperwe will study the following boundary value problem(BVP
forshort)
for functional-differentialequationofsecond orderx"(t) + kx’(t) + f(t,x(hl(t)),x(h2(t))) O, ax(-1)-bx’(-1)
=0,cx(1) + dx’(1)
=0,where E
L
kEJR,
a,b,c, d>
0 and ad+
bc+
ac>
0. Throughout the paperwewill assumethat(1 o) f: I
xKxK Kisacontinuous function,(2)
hi,ha"
14 1 are continuous functionsmapping theintervalI
onto itself.Notice that for
hi(t)=
andha(t)=-t
we obtain theBVP
involving reflectionofthe argumentx"(t) + kx’(t) + f(t,x(t),x(-t)) O, ax(-1)- bx’(-1)
=0,cx(1) + dx’(1)
=0.Such problems
(that
isBVPs
with reflection ofthe argument) have been considered for example in the papers[8,15]
for k=0 andf:
Ix]Rx lltIR
andin[9,10]
forftaking values inarealHilbertspace.For
moredetailsconcerning thedifferential equations with reflection of the argumentwereferthe readertothepapersmentionedaboveand the referencestherein.Our purposeis to discuss theexistenceof positive solutions of
(1).
We
will use the following fixed point theorem from[12]
which is a modificationofwell-knownKrasnoselskiitheoremonoperators com- pressing and expandingacone(see [7,11]).
PROPOSITION 12]
LetP
beaconeof
arealBanachspaceX,
andlet thenorm
II II
inX bemonotonicwith respecttoP. LetBr {x
EX:I[xll < r}, BR {x
X:Ilxll <
g},0<
r<
g.Suppose
thatFP
fR
-+Pisastrictset-contractionwhich
satisfies
oneof
thefollowingconditions:(i)
x POBr IIFxll _< Ilxll
andx POBR =: Ilrxll _> Ilxll
or(ii) x
e
POB = IIFxll _< Ilxll
and xe
Pf30B IIFx[I _> Ilxll.
Then FhasafixedpointinPN
(BR\Br).
Recall thatF:D-+
X, D c X,
is said to bea strict set-contraction if F is continuous and bounded and there exists 0< L <
such thata(F(S)) <_ La(S)
for all bounded subsets S ofD,
whereadenotesthe Kuratowski measureofnoncompactness(see
for instance[2]).
2
PRELIMINARY RESULTS
Firstwewillstudysome properties of the functions
e-kt[ek(s-l)]
q-][ek(t+l)l
2a]
-1< <
s<
G(
t,s) - e-kt[ek(s+l)[2 a][ek(t-1)ll + c]
-1<
s< <
1,(2)
where
kO,
# bk+
a and p[ae-:# + cek/2],
and
G*(t,s) { -(c (a + +
d-b+ cs)(a as)(c + +
bd-+ at), ct),
-1 <t<s< 1, -1 <s<t< 1,(3)
wherep* 2ac
+
bc+
ad.It
iseasy to show thatthefunction(2)
fulfils the following inequalities:A a(t, s) >
0(4)
t,s.l
and
A G(t,s) < G(s,s). (5)
t,sEI
Moreover,
forany-1<
7<
6<
and[7, 6]
wehaveG(
t,s) > mG(s, s), (6)
wheres E
I
andmin
J" ek#2
ae-k’e-kl
zl+ ce-k* I
m e
*#2-ae-’
e-#l+ce J" (7)
It
iseasilyseenthatrn<
1.ThefunctionG* alsosatisfiesthe inequalities
(4), (5)
and(6)
with rn replacedbym*=min{
a+
2ab+ +
ba7 c+ " i
d---(- "d
c6I j" (8)
Clearly, m*
<
1.Next,
considerthe integral-functional operator(Fx)(t) G(t,s)f(s,x(hl(s)),x(h2(s)))ds, (9)
where EL
xQ,
the function G is definedby (2)
andf, h
andh2
satisfy and2
. Let
M
maxG(t, s),
t,sEl
L {x E: IIXlIE r},
and
r-- {x c(I, E). Ilxll < r}.
The followinglemma isaslight modification of that given in
[6].
LEMMA Assume
thatfor
anyr>
0:(3)
thefunction f
isuniformlycontinuous onIx(K
Nr) (K
fq’r),
(4)
thereexistsa non-negative constantLr,
such that4MLr <
anda(f(t,
2,f)) < Lrc(2)
for
all EI andfc K
fqTr.
Then,for
anyr>
0theoperator(9)
isa strict set-contraction onQ
fqB.
Proof From
3 itfollowsthatfis
boundedonIx(K
f’) (K
f3’).
By
theuniformcontinuityoff(see [3])
a(f(I
x f xf))
maxa(f(t, f,f)),
tel
hence,in viewof4
a(f (I
x f xf)) <_ Lra(Vt) (lO)
for every f
c
KTr.
The uniform continuity and boundedness off
on Ix
(K ’)
x(Kf3 )
implies also continuity and boundedness of operator FonQ
fqB. Let
Sc Q
fqB.
Since the functions Fx are equicontinuous and uniformlyboundedfor xES,
weobtain(see [4])
a(F(S)) supa(F(S)(t)),
tel
where
F(S)(t)
denotesthe cross-section ofF(S)
atthepointt,thatisF(S)(t) {(Fx)(t)"
xS,
isfixed}.
Furthermore, forevery Iweget
(see [14])
!2
(Fx)(t)
!f
1G(t,s)f(s,x(h(s)) x(h2(s)))ds
Conv{G(t,s)f(s,x(hl(s)),x(h2(s))):
sI,
xS}
c conv{{Mf(s,x(hl(s)),x(h2(s)))"
sI,
xS}
t.J{0}}.
Thus, in view of the properties of the Kuratowski measure of non- compactnessweobtain for I
a(1/2f(S)(t))
<_ Ma({f(s,x(h(s)),x(h2(s)))"
sI,
xS})
<_ Ma(f(I
xS(I)
xS(I))),
where
S(I) {x(s)’
s/, xS}. Hence,
by(10)
wehavea(F(S)(t)) <_ 2Ma(f(I
xS(I) S(I))) <_ 2MLra(S(I)).
Finally, proceedingas in theproofof
Lemma
2[6],
we canshowthata(S(I)) < 2a(S).
Hence
forany Sc Q
f3B
a(r(s)) supa(F(S)(t)) <_ 4MLra(S),
tI
which meansthat
F
is a strict set-contractiononQ o Br.
Remark Obviously, the above lemmaremainsvalid forthe operator
(9)
withthe function G* givenby(3)
and the constantM*
maxG*(t,s).
t,sl
3
EXISTENCE THEOREMS
FORPROBLEM(1)
Now
westateand prove ourresultsonpositivesolutions of(1).
First, considerthecasek 0.THEOREM
Let
G be given by(2)
and let -l<_’y<
6<
be such thathi"
[’y,]
[’y,],
1,2. Suppose that the assumptions 1-4 aresatisfied
and(5)
thereexistsA
EK, A O,
such thatf
t,x,y) -< [ f G(s, s) ds]
-lfor
all Iandx,yK
such thatIlxll, IlYiI [0, IIXll],
(6)
thereexist EK,
rl: O, I111 IIAII
andto
I suchthatG(to, s) n
for
all Iandx,y Ksuch thatllxlle, [lYlle [mll01le, llnll],
wherem isgivenby
(7).
Thentheproblem
(1)
hasatleastone positivesolution.Proof
Noticethat each positive solutionof theproblem(1) (with
k0)
isafixedpoint oftheintegral-functional operator(9),
thatis(Fx)(t) a(t,s)f(s,x(h(s)),x(h(s)))ds
where
L
xC(L E)
and the functionGis givenby(2).
Onthe other hand,ifxbelongingtoQ
isafixedpointofF,
thenx is a solution of(1) (see [6]).
Thus,toproveourtheoremitisenoughto showthatF hasa fixedpointinQ. In
the spaceC(L E)
considerthesetP=
{xC(I,E): Ox(’)on
landte[7,]A
seIClearly, Pisacone in
C(L E)
and the normI1" II
inC(L E)
is monotonic withrespecttoP.Considertheoperator(9)
for I andx P.We
will show thatFsatisfies the assumptions ofProposition 1. First, wewill prove thatF(P)
CP.To
thisend observe thatby and(4)
o (ex)(t) ( l)
for every x P and
L Moreover,
it follows from(6)
thatfor any[7, 6]
ands Im(fx)(s)
ma(s,s)f(s,x((s)),x(h(s)))ds a(t,s)f(s,x(h(s)),x(h(s)))ds
Combining it with
(11)
we conclude thatF(P)C
P. Without. loss of generalitywemayassume
thatIIlle< IIlle.
Fix r=lllle
andRBy Lemma
1,F
is a strict set-contraction on PqBn. Moreover,
forxEPfqOBrwehave0
-X(hl(t))
onlandIlxll II,lle,
henceA Ilx(ht(t))ll IIll.
tel
Analogously
A IIx(hz(t))ll IIll.
tel
Thus, by 5
,
for any EI
weobtain(Fx)(t)
-4G(s,s)f(s,x(hl(s)),x(hz(s)))ds
-1
Ads=).
Hence,
in view ofmonotonicity of[1. lie
weget[l(Fx)(t)ll IIAII,
tel
and in consequence
IIFxllllxll
on PfqOBr. Furthermore, for xP f30BI
wehaveA A
0 -’<rex(hi (s)) < x(h, (t)).
tel’),,6 sEl
Sincethenorm
II" lie
is monotonic we obtainA A Ilmx(h @)lie -< IIx(h(t))lle,
tE[7,6 sEI which gives
A
mmaxIIx(h @)lie < IIx(h (t))lle.
t[-,]
But hi
mapsIontoitself,hence forIlxll Ilwlle
/ mllll IIx(h(t))ll I111.
t[,]
In
the same mannerweget/ mllll IIx(h2(t))ll I111.
t[,]
Thus in view of 6
fj, G(t0, s) G(t0, r)
drr/ds
- G(t.,s)f(s,x(h(s)),x(h(s)))ds
- a(to, s)f(s,x(h(s)),x(h(s)))ds (Fx)(to),
so
II(Fx)(to)ll II[le,
which implies
IlFxl[ [[xll
on PfqCgBR.By
Proposition the operator F has a fixed point in the set Pf(BR\Br).
This means that theproblem
(1)
hasatleastonepositivesolution xEP such thatThisends theproofofTheorem 1.
Next,
consider the problem(1)
withk 0. Usingthe properties of the function G*givenby(3)
we canprove the following theorem in the samewayasTheorem 1.THEOREM 2 LetG* begivenby
(3)
and let -1<
"7< <
be such that hi’[’)/,6] [’7,
iS], 1,2.Suppose
that -4aresatisfied
and(7)
thereexistsA
EK, A O,
suchthatf(t,x,y) G*(s,s)ds
for I
andx,y Ksuch that(8)
there exist,K, O, , [,
andto I
such that[6 G*
to,s) ds]
-1rlf(t,x,y)
for I
and x, yK
such thatllxil, llyll [m* ilwll, llwll],
wherem*
isgivenby(8).
Then theproblem
(1)
hasatleastone positivesolution.Remark
For
similar theorems on positive solutions ofBVPs
in the casef:
Ix[0, o)
--.[0, o)
wereferthereaderto[5,13].
Finally, we willgiveanexampleofapplicationofTheorem 2tothe infinitesystemof functional-differentialequations.
Example
Let E
be the space of allboundedsequences x{xn}
with the supremumnormIlxlle suplx, I. (12)
nEN
Then
is a cone in
E
and the norm(12)
is monotonic with respect toK.
Consider the following
BVP
of an infinite system of functional- differentialequations:Xnr(t)
q-A(t)xn(hl (t))
q-B(t)xn(h2(t))
q-C(t) +
wnV/xn(h|(t))+ xn(hz(t))
O,Xn(-1) Xn(-1 O, xn(1) +Xn(1 O, (13)
wheren 1,2, 3,..., E/, x
{xn}
EQ c C(I, E),
thefunctionsA, B,
C"[-
1,1] [0, c)
are continuous, w{w,} K
and lim,,_wn
0.In
our case
M* =max""
"o*it,sl..=t,sEl
and
Assume
thatG*(s,s)
dsll
mtx(A(t + B(t)) <
andmintE1 C(t) >
O.Moreover,
suppose that the functionsh
satisfy 2 andhi(I-1/2, 1/2]) c [-1/2, 1/2],
i=1,2. Thenfor7=-1/2, 6=1/2
wehavem*-2-!
andfor
to
1,-1
Consider the function
f(t,x,y) A(t)x + B(t)y + C(t) +wv/X +
y,where /,
f= {f},
x,yK,
x{x,},
y {y}. Obviously,f
is uni-formly continuous on Ix
(Kfq Tr)
x(Kf3 Tr)
for any r>
0.We
will showthatfsatisfies
4.
Noticethatfadmits
asplittingf=f+f,
whereand
f(t,
x,y) A(t)x + B(t)y + C(t)
f(t,
x,y) Wv/X +
y.Evidently,the
functionfis
lipschitzian, hencea(f(t,
f,f)) < mtx(A(t + B(t))a(f) (14)
for all EI and
c
K f)Tr.To
findc(f(t,
Q,Q))
we will apply the followingcompactness criterion inthe space(see [1 ])’
If
D c
is bounded and limsupn [sup,olx,,I]
0, thenD
is relatively compactinl.
Denote
X(t) =f(t,f,) {ff(t,x,y)"
x,y Q, isfixed}.
For
nN
and x,y 9tc
KNTr
wehaveIL(t,x,y)l Iw.x/x. +
yn<_
Since
lim
w,, O,weobtainlim sup
]
supn--,c [f(t,x,y)EX(t)
andinconsequence
X(t)
isrelativelycompact.Thereforea(f(t,Q, ft))
=0.(15)
By (14)
and(15)
and thepropertyofthe Kuratowski measure ofnon- compactnesswehavec(f(t,
9t,f)) < c(](t,
f,9t) + f (t,
2,f))
_< m,x((t) + (t))()
which means that 4 is fulfilled. Finally, we can show by simple calculationthat7 and8 arealso satisfied with
A {A,},
r/={r/,}
6K,
such thatAn i /a), + :2w
2+fmaxtet C(t)
and
minC(t)
n= 2,...tel
By
Theorem2,theproblem(13)
hasapositivesolution xEP such thatAcknowledgements
The author wishes toexpressherthankstoProfessor TadeuszDtotko forhelpfulcommentsand suggestions.
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