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Journal of Inequalities and Applications Volume 2011, Article ID 873184,16pages doi:10.1155/2011/873184

Research Article

Normality Criteria of Lahiri’s Type and Their Applications

Xiao-Bin Zhang,

1

Jun-Feng Xu,

1, 2

and Hong-Xun Yi

1

1Department of Mathematics, Shandong University, Jinan, Shandong 250100, China

2Department of Mathematics, Wuyi University, Jiangmen, Guangdong 529020, China

Correspondence should be addressed to Jun-Feng Xu,[email protected] Received 22 September 2010; Revised 9 January 2011; Accepted 9 February 2011 Academic Editor: Siegfried Carl

Copyrightq2011 Xiao-Bin Zhang et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

We prove two normality criteria for families of some functions concerning Lahiri’s type, the results generalize those given by Charak and Rieppo, Xu and Cao. As applications, we study a problem related to R. Br ¨uck’s Conjecture and obtain a result that generalizes those given by Yang and Zhang, L ¨u, Xu and Chen.

1. Introduction and Main Results

Let denote the complex plane, and letfzbe a nonconstant meromorphic function in . It is assumed that the reader is familiar with the standard notion used in the Nevanlinna value distribution theory such as the characteristic functionTr, f, the proximity functionmr, f, the counting functionNr, f see, e.g.,1–4, andSr, fdenotes any quantity that satisfies the conditionSr, f oTr, fasr → ∞outside of a possible exceptional set of finite linear measure. A meromorphic functionazis called a small function with respect tofz, provided thatTr, a Sr, f.

Letfzandgzbe two nonconstant meromorphic functions. Letazand bzbe small functions offzandgz.fz azªgz bzmeansfz − azandgzbzhave the same zeroscounting multiplicityandfz ªgz ∞means thatfand ghave the same polescounting multiplicity. Ifgzbz 0 wheneverfzaz 0, we writefz azgz bz. Iffz azgz bzandgz bzfz az, we writefz azgz bz. Iffz azgz az, then we say thatfandg sharea.

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Set

P f

fnn1···nk, M1

f, f, . . . , fk fn

fn1

· · · fknk

,

M2

f, f, . . . , fk fm

fm1

· · · fkmk

,

γM1nn1· · ·nk, γM2mm1· · ·mk,

γM

1k−1

j1

nj, ΓM1k

j1

jnj, γM

2k−1

j1

mj, ΓM2k

j1

jmj,

1.1

where n, n1, . . . , nk, m, m1, . . . , mk are nonnegative integers. Mif, f, . . . , fk is called the differential monomial offandγMi is called the degree ofMif, f, . . . , fk i1, 2.

LetFbe a family of meromorphic functions defined in a domainD ⊂ .Fis said to be normal inD, in the sense of Montel, if for any sequencefn∈ F, there exists a subsequence fnj such thatfnj converges spherically locally uniformly inD, to a meromorphic function or

∞.

According to Bloch’s principle, every condition which reduces a meromorphic function in to a constant makes a family of meromorphic functions in a domainDnormal.

Although the principle is false in general, many authors proved normality criteria for families of meromorphic functions starting from Picard type theorems, for instance.

Theorem Asee5. Letn5 be an integer,a, banda /0. If, for a meromorphic functionf, fafn/bfor allz, thenfmust be a constant.

Theorem Bsee6,7. Letn3 be an integer,a, b,a /0, and letF, be a family of meromorphic functions in a domainD. Iffafn/bfor allf∈ F, thenFis a normal family.

In 2005, Lahiri8got a normality criterion as follows.

Theorem C. LetFbe a family of meromorphic functions in a complex domainD. Leta, bsuch thata /0. Define

Ef

zD:fz a

fz b

. 1.2

If there exists a positive constantMsuch that|fz| ≥Mfor allf∈ FwheneverzEf, thenFis a normal family.

In 2009, Charak and Rieppo9generalized Theorem C and obtained two normality criteria of Lahiri’s type.

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Theorem D. LetFbe a family of meromorphic functions in a complex domainD. Leta,bsuch thata /0. Letm1,m2,n1,n2 be positive integers such thatm1n2m2n1 > 0,m1 m21, n1 n22, and put

Ef zD:

fzn1

fzm1 a

fzn2

fzm2 b

. 1.3

If there exists a positive constantMsuch that|fz| ≥Mfor all f∈ FwheneverzEf, thenFis a normal family.

Theorem E. LetFbe a family of meromorphic functions in a complex domainD. Leta,bsuch thata / 0. Letm1,m2,n1,n2be nonnegative integers such thatm1n2m2n1, and put

Ef zD:

fzn1

fzm1

a fzn2

fzm2 b

. 1.4

If there exists a positive constantMsuch that|fz| ≥Mfor allf∈ FwheneverzEf, thenFis a normal family.

Very recently, Xu and Cao10 further extended Theorems D and E by replacingf withfk; they got

Theorem F. LetFbe a family of meromorphic functions in a complex domainD, all of whose zeros have multiplicity at leastk. Leta, bsuch thata / 0. Letm1,m2,n1,n2be nonnegative integers such thatm1n2m2n1>0,m1m21,n1n22, (ifn1n21,k5), and put

Ef zD:

fzn1

fkzm1

a fzn2

fkzm2 b

. 1.5

If there exists a positive constantMsuch that|fz| ≥Mfor allf∈ FwheneverzEf, thenFis a normal family.

Theorem G. LetFbe a family of meromorphic functions in a complex domainD, all of whose zeros have multiplicity at leastk. Leta, bsuch thata / 0. Letm12,m2,n1,n2be positive integers such thatm1n2m2n1, and put

Ef zD:

fzn1

fkzm1

a fzn2

fkzm2 b

. 1.6

If there exists a positive constantMsuch that|fz| ≥Mfor allf∈ FwheneverzEf, thenFis a normal family.

To prove Theorems D–G, the authors used a key lemma Lemma 2.4in this paper besides Zalcman-Pang’s Lemma. It’s natural to ask whether such normality criteria of Lahiri’s

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type still hold for the general differential monomialMf, f, . . . , fk. We study this problem and obtain the following theorem.

Theorem 1.1. LetFbe a family of meromorphic functions in a complex domainD, for everyf ∈ F, all zeros off have multiplicity at least k. Let a, bsuch that a / 0, let m,n,k≥ 1,mj, nj j1,2, . . . , kbe nonnegative integers such that

γM2ΓM1γM1ΓM2>0, nkmk>0, mn≥2. 1.7

Put

Ef zD:M1

f, f, . . . , fk

a M2

f, f, . . . , fk b

. 1.8

If there exists a positive constantMsuch that|fz| ≥Mfor allf∈ FwheneverzEf, thenFis a normal family.

Theorem 1.2. LetFbe a family of meromorphic functions in a complex domainD, for everyf ∈ F, all zeros off have multiplicity at least k. Let a, bsuch that a / 0, let m,n,k≥ 1,mj, nj j 1,2, . . . , kbe nonnegative integers such thatmnmknkγM

1γM

2 > 0, (k /2 whenn 1 or m1),m/nmj/njfor all positive integersmjandnj,1≤jk. Put

Ef zD:M1

f, f, . . . , fk

a M2

f, f, . . . , fk b

. 1.9

If there exists a positive constantMsuch that|fz| ≥Mfor allf∈ FwheneverzEf, thenFis a normal family.

As an application ofTheorem 1.1, we obtain the following theorem.

Theorem 1.3. LetFbe a family of holomorphic functions in a domainD, for everyf∈ F, all zeros of f have multiplicity at leastk. Leta, b/ 0be two finite values andn, k, n1, . . . , nkbe nonnegative integers withn1,k1,nk1. For everyf ∈ F, all zeros off have multiplicity at leastk, if Pf aM1f, f, . . . , fk b, thenFis normal inD.

Example 1.4. LetD {z : |z| < 1}andF {fm}. Ifa 0, letfm : emz. For each function f ∈ F,PfandM1f, f, . . . , fkshare 0 inD. However, it can be easily verified thatFis not normal inD.Example 1.4shows that the conditionb / 0 inTheorem 1.3is sharp.

Example 1.5. LetD {z : |z| < 1}andF {fm}. Ifa / 0, letfm : meλze−λz, where λis the root ofz2 b/a. For each functionf ∈ F,f b/af,fn1 afnf bin D. However, it can be easily verified thatFis not normal inD.Example 1.5shows that the multiplicity restriction on zeros offinTheorem 1.3is sharpat least fork2.

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2. Preliminary Lemmas

Lemma 2.1see11. LetFbe a family of meromorphic functions on the unit discΔ, all of whose zeros have the multiplicity at leastk, then ifFis not normal, there exist, for each 0α < k

aa numberr, 0< r <1, bpointszn,|zn|< r,

cfunctionsfn ∈ F, and dpositive numbersρn → 0

such thatρn−αfnznρnξ gnξ → gξlocally uniformly with respect to the spherical metric, wheregξis a nonconstant meromorphic function on , all of whose zeros have multiplicity at least k, such thatg#ξ≤g#0. Here, as usual,g#z |gz|/1|gz|2is the spherical derivative.

Lemma 2.2see1, page 158. LetF {f}be a family of meromorphic functions in a domain D. ThenFis normal inDif and only if the spherical derivatives of functionsf∈ Fare uniformly bounded on each compact subset ofD.

Lemma 2.3see12. Letf be an entire function andMa positive integer. Iff#z ≤ Mfor all z, thenfhas the order at most one.

Lemma 2.4see13. Take nonnegative integersn, n1, . . . , nkwithn1,n1 n2 · · ·nk≥1 and definednn1n2· · ·nk. Letfbe a transcendental meromorphic function with the deficiency δ0, f>3/3d1. Then for any nonzero valuec, the functionfnfn1· · ·fknk−chas infinitely many zeros. Moreover, ifn2, the deficient condition can be omitted.

The following two lemmas can be seen as supplements ofLemma 2.4.

Lemma 2.5. Take nonnegative integersn, n1, . . . , nkwith n1,nk1 and defined nn1 n2· · ·nk. Letfbe a transcendental meromorphic function whose zeros have multiplicity at leastk.

Then for any nonzero valuec, the functionfnfn1· · ·fknkchas infinitely many zeros, provided thatn1 n2 · · · nk−11 andk / 2 whenn1. Specially, iffis transcendental entire, the functionfnfn1· · ·fknkchas infinitely many zeros.

Proof. If n1n2 · · ·nk−1 0, then fnfn1· · ·fknk fnfknk, this case has been consideredsee5,12–20.

Ifn1 n2 · · · nk−1 ≥ 1 and ifn ≥ 2, we immediately get the conclusion from Lemma 2.4. Next we consider the casen1.

LetΨ fnfn1· · ·fknk. Using the proof ofLemma 2.4see13, page 161–163 , we obtain

3d−2T r, f

≤3dN

r,1 f

N

r, 1

f

4N

r, 1 Ψ−c

N

r,Ψ−c Ψ

−3N

r,Ψ−c Ψ

S

r, f .

2.1

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Suppose thatz0 is a zero of f of multiplicityp≥ k, then z0 is a zero of Ψof multiplicity dp−Σkj1jnj, and thus is a pole ofΨ−c/Ψof multiplicitydp−Σkj1jnj−1. Thereby, from 2.1we get

3d−2T r, f

⎝3 k j1

jnj5

N

r, 1 f

4N

r, 1

Ψ−c

S r, f

≤ 3k

j1jnj5

k N

r, 1

f

4N

r, 1 Ψ−c

S

r, f .

2.2

Note thatn1, we deduce from2.2that

k−53k−1

j1

kj nj

k T

r, f

≤4N

r, 1 Ψ−c

S

r, f

. 2.3

Ifk1, thenΨ fnfn1; this case has been proved as mentioned abovesee13–16.

Ifk≥5, then we havek−53k−1

j1k−jnj>0; the conclusion is evident.

If 3≤k≤4, note thatn1 n2 · · · nk−1≥1 and we deduce thatk − 5 3k−1

j1k− jnj >0, thus the conclusion holds.

Iffis a transcendental entire function, we only need to consider the casek ≥2. Note thatsee Hu et al.21, page 67

dT r, f

dN

r,1 f

N

r, 1

Ψ−c

N

r,Ψ−c Ψ

S

r, f

. 2.4

With similar discussion as above, we obtain

n k−1

j1

kj nj−1 k

T r, f

N

r, 1 Ψ−c

S

r, f

. 2.5

In view ofn≥1 andk≥2, we getn k−1

j1k−jnj−1/k >0, thus we immediately obtain the conclusion. This completes the proof ofLemma 2.5.

Lemma 2.6. Take nonnegative integers n, n1, . . . , nk, k with n ≥ 1, nk1, k1 and define dn n1 n2 · · · nk. Letfbe a nonconstant rational function whose zeros have multiplicity at leastk. Then for any nonzero valuec, the functionfnfn1· · ·fknkchas at least one finite zero.

Proof. Since the casek 1 has been proved by Charak and Rieppo 9, we only need to considerk≥2.

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Suppose thatfnfn1· · ·fknkchas no zero.

Case 1. Iff is a nonconstant polynomial, since the zeros offhave multiplicity at leastk, we know thatfnfn1· · ·fknkis also a nonconstant polynomial, sofnfn1· · ·fknkchas at least one zero, which contradicts our assumption.

Case 2. Iffis a nonconstant rational function but not a polynomial. Set fz Az−a1m1z−a2m2· · ·z−asms

z−b1l1z−b2l2· · ·z−btlt , 2.6 whereAis a nonzero constant andmiki1,2, . . . , s,lj≥1j 1,2, . . . , t.

Then by mathematical induction, we get

fkz Az−a1m1−kz−a2m2−k· · ·z−asms−kgkz

z−b1l1kz−b2l2k· · ·z−btltk , 2.7 wheregkz M−NM−N−1· · ·M−Nk1zkst−1cmzkst−1−1· · ·c0,cm, . . . , c0 are constants and

m1m2· · ·msMks, 2.8

l1l2· · ·ltNt. 2.9

It is easily obtained that

deg gk

kst−1. 2.10

Combining2.6and2.7yields

fn fn1

· · · fknk

Adz−a1dm1kj1jnj· · ·z−asdmskj1jnjgz

z−b1dl1kj1jnj· · ·z−btdltkj1jnj , 2.11 wheregz k

j1gjnjzwith degg≤k

j1jnjst−1.

Moreover,gzis not a constant, or else, we getgjis a constant forj 1, . . . , k. The leading coefficient ofgjisMN−j−1st.

Ifg1is a constant, then we get

MN. 2.12

Ifgkis a constant, then we get

k−1st 0, 2.13 which impliesk1, a contradiction with the assumptionk≥2.

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Then from2.11, we obtain

fn

fn1· · · fk

nk

Adz−a1dm1kj1jnj−1· · ·z−asdmskj1jnj−1hz

z−b1dl1kj1jnj1· · ·z−btdltkj1jnj1 , 2.14 wherehzis a polynomial withst−1≤degh≤k

j1jnj1 st−1.

Sincefnfn1· · ·fknkc / 0, we obtain from2.11that fn

fn1

· · · fknk

c B

z−b1dl1kj1jnj· · ·z−btdltkj1jnj, 2.15 whereBis a nonzero constant. Then

fn

fn1

· · ·

fknk

B·Hz

z−b1dl1kj1jnj1· · ·z−btdltkj1jnj1, 2.16 whereHzis a polynomial with degH t−1.

From2.14and2.16, we deduce that

dM

k

j1

jnj1

sdegh degH t−1, 2.17

in view of degh≥st1, together with2.8, we have

dksk

j1

jnjs, 2.18

namely

nksk

j1

kj

njs≤0. 2.19

which is a contradiction sincen≥1.

Hencefnfn1· · ·fknkchas at least one finite zero.

This provesLemma 2.6.

Remark 2.7. Lemma 2.6is a generalization of Lemma 2.2 in10. The proof ofLemma 2.6is quite different from its proof. Actually, the proof of Lemma 2.2 in10is incorrect. The main problem appears at2.2in10. Sincef has only zero with multiplicity at leastk, then each zero offnis of multiplicity at leastnk, but this does not mean that each zero offnfkmis of multiplicity at leastnkbecause the zeros offkmay not be the zeros off, and thus their multiplicity may less thannk. Therefore, the inequality of2.2in10is not valid, which implies that the proof of Lemma 2.2 in10is not correct.

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Lemma 2.8. Leta,bsuch thata / 0. Letm,n,k≥1,mj,nj j 1,2, . . . , kbe nonnegative integers such thatmnmknkγM

1γM

2>0, (k / 2 whenn1 orm1),m/nmj/njfor all positive integersmjandnj,1≤jk. Letfbe a meromorphic function in ; all zeros offhave multiplicity at leastk. Define

Φz M1

f, f, . . . , fk

a M2

f, f, . . . , fkb. 2.20

ThenΦzhas a finite zero.

Proof. The algebraic complex equation

x a

xm/n b 2.21

has always a nonzero solution, say x0 ∈ . By Lemmas 2.5 and 2.6, the differential monomial M1f, f, . . . , fk cannot avoid it and thus there exists z0 ∈ such that M1fz0, fz0, . . . , fkz0 x0.

Under the assumptions, for all positive integersm,n,mj,nj, we have mnm

n, mjnjm

n. 2.22

Thus

Φz0 M1

fz0, fz0, . . . , fkz0

a M1m/n

fz0, fz0, . . . , fkz0b0. 2.23

This provesLemma 2.8.

Lemma 2.9see2, page 51. Iffis an entire function of orderσf, then

σ f

lim sup

r→ ∞

logν r, f

logr , 2.24

whereνr, fdenotes the central-index offz.

Lemma 2.10see22, page 187–199or2, page 51. Ifgis a transcendental entire function, let 0 < δ < 1/4 andzbe such that|z| rand that|gz| Mr, gνr, g−1/4δ holds. Then there exists a setFof finite logarithmic measure, that is,

Fdt/t <such that gmz

gz

ν r, g

z m

1o1 2.25 holds for allm0 and allr /F.

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3. Proof of Theorem 1.1

Without loss of generality, we may assumeD Δ {z : |z| < 1}. Suppose thatFis not normal atz0D. ByLemma 2.1, for 0≤ α < k, there existr < 1,zj ∈Δsuch thatzjz0, fj ∈ Fandρj → 0 such thatgjξ ρ−αj fjzjρjξgξlocally uniformly with respect to the spherical metric, whereis a nonconstant meromorphic function on , all of whose zeros have multiplicity at leastk. For simplicity, we denotefjzjρjξbyfj. By Lemmas2.4 and2.6, there existsξ0∈ such that

gξ0n

gξ0n1

· · ·

gkξ0nk

a 0m

gξ0m1

· · ·

gkξ0mk 0. 3.1 Obviously,0 / 0,∞, so in some neighborhood ofξ0,gjξconverges uniformly togξ.

We have gjξn

gjξn1

· · ·

gjkξnk

a gjξm

gjξm1

· · ·

gkj ξmkρjαγM2−ΓM2b ρj−αγM1ΓM1fjn

fjn1

· · · fjknk

a ρ−αγj M2ΓM2fjm

fj

m1

· · · fjk

mkραγj M2−ΓM2b

ρjαγM2−ΓM2

⎢⎣ρj−αγM1γM2ΓM1ΓM2fjn fjn1

· · · fjknk

a fjm

fjm1

· · ·

fjkmkb

⎥⎦. 3.2 Letα ΓM1 ΓM2M1γM2< k, and under the assumptionγM2ΓM1γM1ΓM2 >0, we obtain

gn gn1

· · · gknk

a gm

gm1

· · ·

gkmk 3.3

is the uniform limit of

ργjM2ΓM1−γM1ΓM2M1γM2

⎢⎣fjn fjn1

· · · fjknk

a fjm

fjm1

· · ·

fjkmkb

⎥⎦ 3.4

in some neighborhood ofξ0.

By3.1and Hurwitz’s theorem, there exists a sequenceξjξ0such that for all large values ofjandζjzjρjξj,

fj

ζj

n fj

ζj

n1

· · · fjk

ζj

nk

a fj

ζj

m fj

ζj

m1

· · · fjk

ζj

mk b. 3.5

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Hence for all large values ofj,ζjzjρjξjEf, it follows from the condition that gj

ξj fj ζj ραjM

ραj . 3.6

Sinceξ0is not a pole ofg, there exists a positive numberKsuch that in some neighborhood ofξ0we get|gξ| ≤K.

Sincegjξconverges uniformly toin some neighborhood ofξ0, we get for all large values ofjand for allξin that neighborhood ofξ0

gjξ−gξ<1. 3.7

By3.7, we get

Kg

ξjgj

ξjgj ξj

g

ξjM

ραj −1, 3.8

which is a contradiction sinceρj → 0 asj → ∞.

This completes the proof ofTheorem 1.1.

4. Proof of Theorem 1.2

Without loss of generality, we may assumeD Δ {z : |z| < 1}. Suppose thatFis not normal inD. ByLemma 2.1, for 0≤α < k, there existr <1,zj ∈Δ,fj ∈ Fandρj → 0such thatgjξ ρ−αj fjzj ρjξlocally uniformly with respect to the spherical metric, whereis a nonconstant meromorphic function on , all of whose zeros have multiplicity at leastk. ByLemma 2.8, we get

0n

gξ0n1

· · ·

gkξ0nk

a 0m

gξ0m1

· · ·

gkξ0mkb0, 4.1 for someξ0 ∈ .

We can arrive at a contradiction by using the same argument as in the latter part of proof ofTheorem 1.1.

This completes the proof ofTheorem 1.2.

5. Applications

Proof ofTheorem 1.3. We shall divide our argument into two cases.

Case 1a / 0. LetMbe a positive constant withMγM1

|a|; under the assumptions, we have

Ef

zD:M1

f, f, . . . , fk b

5.1

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and|fz| ≥Mfor allf∈ FwheneverzEf; by Lemmas2.5and2.6, using the similar proof ofTheorem 1.1, we obtain the conclusion.

Case 2a0. Forf∈ F, iffz0 0 forz0D, sincePf 0⇒M1f, f, . . . , fk b, we haveb0, which is a contradiction, hencef / 0.

IfM1fz0, fz0, . . . , fkz0 bforz0D, sinceM1f, f, . . . , fk bPf 0, we immediately get fz0 0 and hence M1f, f, . . . , fk b 0, which is still a contradiction, henceM1f, f, . . . , fk / b.

Suppose thatFis not normal inD, byLemma 2.1, there existr < 1,zj ∈ Δ,fj ∈ F, andρj → 0 such thatgjξ ρ−Γj M1M1fjzjρjξlocally uniformly with respect to the spherical metric, whereis a nonconstant entire function, all of whose zeros have multiplicity at leastk. By Hurwitz’s theorem, we have

ig≡0 org / 0, and

iigngn1· · ·gknkborgngn1· · ·gknk / b.

Sincegis not a constant, we haveg / 0. ByLemma 2.3,ghas the order at most 1, so ecξd, wherec/0,dare two constants. Thus

gnξ gn1

ξ· · · gknk

ξ cΓM1eγM1cξd. 5.2

Ifgngn1· · ·gknkb, we immediately get a contradiction. Hence gn

gn1

· · · gknk

/b, 5.3

but by Lemmas2.5and2.6we get a contradiction again.

This provesTheorem 5.1.

Further more, usingTheorem 1.3, we obtain a uniqueness theorem related to R. Br ¨uck’s Conjecture. Firstly, we recall this conjecture.

R. Br ¨uck’s Conjecture

Letfbe a nonconstant entire function such that the hyper-orderσ2fis not a positive integer and σ2f<∞. If fandfshare a finite valueaCM, then

fa

fa c, 5.4

wherecis a nonzero constant and the hyper-orderσ2fis defined as follow:

σ2

f

lim sup

r→ ∞

loglogT r, f

logr . 5.5

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Since then, many results related to this conjecture have been obtained. We refer the reader to Br ¨uck23, Gundersen and Yang24, Yang25, Chen and Shon26, Li and Gao 27, and Wang28.

It’s interesting to ask what happens if f is replaced by fn in Br ¨uck’s Conjecture.

Recently, Yang and Zhang29considered this problem and got the following theorem.

Theorem H. Letfbe a nonconstant entire function.n7 be an integer, and letF fn. IfFandF share 1 CM, thenFF, andfassumes the form

fz cez/n, 5.6

wherecis a nonzero constant.

L ¨u et al.30improves Theorem H and obtained the following theorem.

Theorem I. LetQ1/≡0be a polynomial, and letn2 be an intege; letfzbe a transcendental entire function, and letFz fzn. IfFzandFzshareQ1CM, then

fz Aez/n, 5.7

whereAis a nonzero constant.

We obtain a more general result as follows.

Theorem 5.1. Letn, k, n1, . . . , nkbe nonnegative integers withn1,k1,nk1, anda,bbe two finite nonzero values. Letfbe a nonconstant entire function whose zeros have multiplicity at leastk.

Iffnn1···nk aªfnfn1· · ·fknk b, then

fn fn1

· · ·

fknkb

fnn1···nka c, 5.8

wherecis a nonzero constant. Specially, ifab, thenf c1eωz, wherec1is a nonzero constant,ω is the root oftΓM1 1.

Proof ofTheorem 5.1. First we assert thatσf≤1. Let F gωz fzω, ω∈ !

, zD Δ. 5.9

Under the assumptions of Theorem 1.3, we get thatF is a normal family of holomorphic functions inD. ByLemma 2.2, there exists a constantMsuch that

f#ω fω

1fω2 gω0

1gω02 gω#0≤M, 5.10 for allω∈ . Hence byLemma 2.3,fhas the order at most 1.

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Sincefnn1···nk a ª fnfn1· · ·fknk b, f must be a transcendental entire function and

fn fn1

· · ·

fknkb

fnn1···nka eαz. 5.11

From5.11, we haveTr, eαz OTr, f, henceσeασf≤1 andαzis a polynomial with degα ≤ 1. Note that f is transcendental, we haveMr, f → ∞, as r → ∞. Let Mrn, f fzn, whereznrnen, we deduce

rnlim→ ∞

1

fzn lim

rn→ ∞

1 M

rn, f 0. 5.12

By Lemma 2.10, there exists a subset F1 ⊂ 1,∞ of finite logarithmic measure, namely

F1dt/t < ∞such that for some pointzn rnen θn ∈ 0,2πsatisfying|zn| rn/ F1 andMrn, f |fzn|, we obtain

fkzn fzn

ν rn, f

zn k

1o1, 5.13

asr → ∞.

Rewrite5.11as

f/fn1· · ·

fk/fnkb/fnn1···nk

1−a/fnn1···nk eαz, 5.14

it follows from5.12–5.14and Lemma 2.8 that

|αzn|logeαznΓM1

logν

rn, f

−log

rnen o1 ΓM1

logν rn, f

−logrniθrn o1

O logrn

,

5.15

asrn → ∞. Sinceαzis a polynomial, from5.15, we deduce thatαzis a constant. Let eα c, thencis a nonzero constant. Thus

fn fn1

· · · fknk

b

fnn1···nka c. 5.16

Specially, ifab, suppose thatfhas a zeroz0, by lettingzz0in5.16, we getc1; hence fn1···nk

fn1

· · · fknk

. 5.17

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Suppose that z0 is a zero of f with multiplicity p≥ k, thenz0 is a zero offn1···nk with multiplicityn1· · ·nkp, and a zero offn1· · ·fknkwith multiplicityn1· · ·nkp−ΓM1, which is a contradiction. Sofhas no zero, note thatfis a transcendental entire function and σf≤ 1, we havef c1etz, wherec1andtare two finite nonzero values. In view of5.16 andab, we deduce that

cΓ1M1

tΓM1c

eγM1tzb1c; 5.18

hencec1 andtΓM1 c1.fc1eωz,ωis the root oftΓM1 1.

This completes the proof ofTheorem 5.1.

Acknowledgments

The authors thank the referees for reading the manuscript very carefully and making a number of valuable suggestions to improve the readability of the paper. The authors were supported by NSF of Chinano. 10771121, NSF of Shandong Provinceno. Z2008A01and NSF of Guangdong Provinceno. 9452902001003278.

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