ISSN:1083-589X in PROBABILITY
Parameter sensitivity of CIR process
S. M. Ould Aly
∗Abstract
We study the differentiability of the CIR process with respect to its parameters. We give a stochastic representation for these derivatives in terms of the paths ofV.
Keywords:CIR process ;sensitivity.
AMS MSC 2010:65C30 ; 62P05.
Submitted to ECP on May 18, 2012, final version accepted on March 13, 2013.
1 Introduction
The CIR process is defined as the unique solution of the following stochastic differ- ential equation:
dVt= (a−bVt)dt+σp
VtdWt, V0=v, (1.1)
wherea, σ, v ≥0and b∈R(see [8] for the existence and uniqueness of the solution of the SDE). This process is widely used in finance to model short term interest rate (see [3]) but also used to model stochastic volatility in the Heston stochastic volatility model. The option prices in these models depend in the values of the parameters of CIR process. On the other hand, these parameters are often calibrated to market prices of derivatives, so they tend to change their values regularly. The knowledge of the derivatives of the CIR process with respect to its parameters is therefore crucial for the study the sensitivities of prices in these models.
The most common approach to study the sensitivity of stochastic differential equa- tion with respect to its parameters is to use the Malliavin calculus, especially for the sensitivity with respect to the initial value. The Malliavin derivative gives a stochastic representation of the sensitivity of process with respect to its initial value. We note that the coefficients of (1.1) are neither differentiable in 0 nor globally Lipschitz, so the standard results (see e.g [9],[5]) cannot be used here. Nevertheless, for the special case of CIR process, Alòs and Ewald ([1]) show the existence of Malliavin derivative of the CIR process under assumption (2a > σ2). In mathematical finance, the sensitivities of option prices with respect to not only the initial point, but also other parameters, need to be studied very carefully.
In this article, we study the differentiability of the solution of (1.1) with respect to the parametersa, b andσ inLp sense (see next section). We show that, under some assumptions, this process is differentiable with respect to these parameters and give a stochastic representation of its derivatives.
∗Université Paris-Est Marne-la-Vallée, France. E-mail:[email protected]
2 Differentiability
For technical reasons, we will rather consider the square root ofVv, denoted Xv. Throughout this paper, we assume that
2a≥σ2 (2.1)
Under this assumption, we have for any T, v > 0, P(∀t∈[0, T] : Vtv >0) = 1. The processXvis the unique solution of the following stochastic differential equation
dXtv= a
2 −σ2 8
1 Xtv −b
2Xtv
dt+σ
2dWt, X0v=√
v. (2.2)
We start by studying the differentiability ofX with respect to the parametera. We consider here theLp-differentiability of the functiona7−→Xv(a), i.e the existence of a processX˙aso that
→0lim
sup
s≤t
Xsv(a+)−Xsv(a)
−X˙a(s) p
= 0 (2.3)
We have the following result
Proposition 2.1. Letb∈Randσ, x≥0. For everya∈]σ2,+∞[, letXa be the unique solution of the SDE :
dXt= a
2 −σ2 8
1 Xt
− b 2Xt
dt+σ
2dWt, X(0) =x
and leta0 > σ2. Then the functiona7−→Xa isLp-differentiable ata0, for any1 ≤p≤
2a0
σ2 −1and its derivative (X˙a) is given by
X˙a(t) = Z t
0
1 2Xs
exp
−b
2(t−u)−(a 2−σ2
8 ) Z t
s
du Xu2
ds. (2.4)
Proof. LetXbe the unique solution of the stochastic differential equation dXt=
a+ 2 −σ2
8 1
Xt − b 2Xt
dt+σ
2dWt, X0=√ v.
For >0, defineR0(t) :=Xt−Xt. We can easily see thatR0is given by R0(t) =Ut
Z t 0
(Us)−1 1 2Xs
ds,
where
U= exp
− Z t
0
αsds
, with αt= a+
2 −σ2 8
1 XsXs
+b 2.
We have, using the fact that for anys≤t,e−Rstαudu≤e−bt/2∨1 a.s,
|R0(t)|
≤ t(e−bt/2∨1)
2 sup
s≤t
1 Xsv.
On the other hand, we have, using Lemma 2.3.2 of [4] ,
∀p <2 2a
σ2 −1
, E
sup
s≤t
1 Xsp
<+∞. (2.5)
In particular, we have for anyp∈
1,2 σ2a2 −1 , kR0kp≤C.
Let’s now set
X˙a(t) := lim
→0
R0
(t) =Ut0 Z t
0
(Us0)−1 1 2Xs
ds.
We have
X˙a
p≤C. Furthermore,X˙ais solution of the stochastic differential equation:
dX˙a(t) =− a
2 −σ2 8
1 Xt2 +b
2
X˙a(t)dt+ 1 2Xt
dt.
LetR1(t) =Xt−Xt−X˙a(t). The processR1is a solution of the stochastic differential equation
dR1(t) =
−αtR1(t)−X˙a(t)
αt−
(a 2 −σ2
8 ) 1 Xt2+ b
2
dt.
On the other hand, we have αt−
(a
2 −σ2 8 ) 1
Xt2+ b 2
=− αt
Xt− b 2Xt
R0(t) + 2Xt2.
It follows thatR1can be written as R1(t) =Ut
Z t 0
(Us)−1
X˙a(t)
αt
Xt− b 2Xt
R0(t)− 2 2Xt2
ds,
Using (2.5) and the fact that for anys≤t, we havee−Rstαudu≤1∨e−bt/2andRt
0αse−Rstαududs= 1−e−R0tαudu, we get
∀1≤p < 2a
σ2 −1, kR1kp≤C2.
The differentiability with respect tobis obtained in the same. The proof of the next Proposition is almost identical to Proposition 2.1.
Proposition 2.2. Letx, a, σ≥0so that4a >3σ2. For everyb∈R, letXbbe the unique solution of the SDE :dXt=
a 2−σ82
1
Xt −b2Xt
dt+σ2dWt, X0=xand letb0∈R. The functionb7−→Xb isLp-differentiable atb0, for any1≤p <2(2aσ2 −1)and its derivative X˙bis given by
X˙b(t) =− Z t
0
Xs
2 exp
−b
2(t−u)−(a 2 −σ2
8 ) Z t
s
du Xu2
ds (2.6)
We now consider the differentiability of X with respect to the parameter σ. We propose an extension of the result of Benhamou et al (cf. [2]) who show thatσ7−→X is C2in neighborhood of 0. We will show that this function isC1in[0,√
a[andC∞ around 0.
Proposition 2.3. For anyσ∈ [0,√
a[, the functionσ 7−→X isC1at σinLp-sense, for everyp∈[1,σ2a2 −1[and its derivative is the unique solution of the SDE :
dX˙σ(t) = − σ 4Xt −
a 2 −σ2
8
X˙σ(t) Xt − b
2 X˙σ(t)
! dt+1
2dWt. (2.7)
Proof. LetXbe the unique solution of the SDE : dXt=
a
2 −(σ+)2 8
1 Xt −b
2Xt
dt+σ+
2 dWt, X0=√ v.
Let setR0(t) =Xt−Xt. In particular,R0solves the stochastic differential equation:
dR0(t) = a
2 −(σ+)2 8
1 Xt −b
2Xt− a
2 −σ2 8
1 Xt+ b
2Xt
dt+
2dWt
=
− a
2 −(σ+)2 8
1 XsXs
+b 2
R0(t)−2σ+2 8Xt
dt+
2dWt.
It follows thatR0can be written as R0(t) =Ut
Z t 0
(Us)−1
−2σ+2 8Xs ds+
2dWs
,
whereUis given by
Ut= exp
− Z t
0
αsds
(2.8) and
αs= a
2 −(σ+)2 8
1 XsXs +b
2. (2.9)
Applying the Itô formula to the product(Ut)−1Wt, we have R0(t) =−2σ+2
8 Ut Z t
0
(Us)−1ds Xs
+
2Wt+Ut Z t
0
Wsd(U)−1s .
On the other hand, using the fact thatαt≥b/2, a.s, we know that for anys≤t, we have 0≤Ut(Us)−1≤1∨e−bt/2, a.s. It follows that
|R0(t)| ≤ c(t) Z t
0
ds Xs
+ 2
sup
s≤t
Ws+ sup
s≤t
Ws(1−Ut)Ut
≤ c(t) sup
s≤t
1 Xs
+sup
s≤t
Ws(1 +Ut)Ut.
Using (2.5), we have, for any1≤p <2 2aσ2 −1 ,
kR0kp≤C. (2.10)
Let’s now set
X˙σ(t) :=Ut0 Z t
0
(Us0)−1
− σ 4Xs
ds+1 2dWs
.
We have
X˙σ
p≤C. Furthermore, we can easily see thatX˙σis solution to the stochas- tic differential equation:
dX˙σ(t) =− a
2 −σ2 8
1 Xt2 +b
2
X˙σ(t)dt− σ 4Xt
dt+1 2dWt.
SetR1(t) =Xt−Xt−X˙σ(t). The processR1solves the stochastic differential equation:
dR1(t) =
−αtR1(t)−X˙σ(t)
αt−
(a 2 −σ2
8 ) 1 Xt2+ b
2
− 2 8Xt
dt.
On the other hand, we can easily see that αt−
(a
2 −σ2 8 ) 1
Xt2+ b 2
=− αt
Xt
− b 2Xt
R0(t)−2σ+2 8Xt2 .
It follows thatR1can be written as R1(t) =Ut
Z t 0
(Us)−1
− 2 8Xs
ds+X˙σ(s) αs
Xs
− b 2Xs
R0(s) +2σ+2 8Xs2
ds.
We have
|R1(t)| ≤ Z t
0
Ut(Us)−1 2
8Xsds+|X˙σ(s)|
αt Xs + b
2Xs
|R0(s)|+2σ+2 8Xs2
ds
≤ Z t
0
Ut(Us)−1 2
8Xs
ds+|X˙σ(t)|
b 2Xs
|R0(s)|+2σ+2 8Xs2
ds+
Z t
0
Ut(Us)−1αt Xs
|X˙σ(s)||R0(s)|ds
≤ c(t) Z t
0
2 8Xs
ds+|X˙σ(t)|
b 2Xs
|R0(s)|+2σ+2 8Xs2
ds
+c2(t) sup
s≤t
|X˙σ(s)||R0(s)|
Xs
! .
Finally, using (2.5), we have, for any1≤p < σ2a2 −1 , kR1kp≤C2.
Proposition 2.4. Under the assumptions of Propositions 2.1, 2.2, 2.3, the solution of the SDE(1.1)is differentiable with respect to the parametersa,bandσ. Its derivatives, denoted byV˙a,V˙bandV˙σrespectively, are given as
V˙a(t) = √ Vt
Z t 0
√1 Vs
exp
−b
2(t−u)−(a 2 −σ2
8 ) Z t
s
du Vu
ds, V˙b(t) = −√
Vt
Z t 0
√ Vsexp
−b
2(t−u)−(a 2 −σ2
8 ) Z t
s
du Vu
ds,
V˙σ(t) = 2 σVt− 2
σ pVt
√ve−b2t−(a2−σ
2 8 )Rt
0 dr Vr +a
Z t 0
e−b2(t−u)−(a2−σ
2 8 )Rt
u dr
√ Vr
Vu
du
(2.11). Proof. AsVt=Xt2,V is differentiable with respect to the parametersa,bandσunder the assumptions of Propositions 2.3, 2.1, 2.2. The derivativesV˙σis given as solution of the SDE :
dV˙σ(t) =−bV˙σ(t)dt+p
VtdWt2+σV˙σ(t) 2√
Vt
dWt, V˙σ(0) = 0.
One can see that the processZt:= ˙Vσ(t)−σ2Vtis solution of the SDE : dZt=
−2a σ −bZt
dt+σ Zt
2√ Vt
dWt2, Z0=−2 σx.
On the other hand, applying Itô formula to the processZVα, forα∈R∗, we have d(ZVα)(t) = (−2a
σVtα−b(1 +α)ZtVtα+ (αa+α2
2 σ2)ZtVα−1)dt+ (α+1
2)ZVα−12dWt2.
It follows that, forα=−12, the processY =ZV−12, Y has finite variation and is given as solution of
dYt=
−2a
σVt−12 −b
2Yt−(a 2 −σ2
8 )Yt
Vt
dt , Y0=−2 η
√v.
We can easily solve this equation, we get Yt:= Vσ(t)−σ2Vt
√Vt
=−2 σ
√ve−γt−2a σ
Z t 0
e−(γt−γu)
√Vu
du, a.s,
where
γt:= b 2t+ (a
2−σ2 8 )
Z t 0
dr Vr
. (2.12)
Thus V˙σ(t) = 2
σVt− 2 σ
pVt
√ve−b2t−(a2−σ
2 8 )Rt
0 dr Vr +a
Z t 0
e−b2(t−u)−(a2−σ
2 8 )Rt
u dr
√ Vr
Vu
du
, a.s.
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Acknowledgments.I would like to thank Professor Damien Lamberton for many useful discussions and anonymous referee who read the first version and helped me improve the presentation.