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(1)

On extension of funtors

L. Karhevska, T. Radul

Abstrat.A.Chigogidze denedforeahnormalfuntorontheategoryComp

anextensionwhihisanormalfuntorontheategoryTyh. Weonsiderthis

extensionforanyfuntorontheategoryCompandinvestigatewhihproperties

itpreservesfromthedenitionofnormalfuntor. Weinvestigateaswellsome

topologialpropertiesofsuhextension.

Keywords:Chigogidzeextensionoffuntors,1-preimagepreservingproperty

Classiation: 18B30,54B30,57N20

Introdution

Thegeneraltheoryoffuntorsatingin theategoryCompofompatHaus-

dorspaes(ompata)andontinuousmappingswasfoundedbyE.V.Shhepin

[15℄. Hedistinguished some elementary properties of suh funtors and dened

thenotionofnormalfuntorthat hasbeomeveryfruitful. Thelassofnormal

funtorsinludesmanylassialonstrutions: thehyperspaeexp,thefuntorof

probabilitymeasuresP,thepowerfuntorandmanyotherfuntors(see[13℄,[9℄

formoredetails). Butsomeimportantfuntorsdonotsatisfysomeoftheprop-

ertiesfrom the Shhepin list. Omitting somepropertiesweobtainwider lasses

offuntorssuhasweaklynormalfuntorsandalmostnormalfuntors.

Thepropertiesfromthedenitionofnormalfuntorouldbeeasilygeneralized

forthefuntors ontheategoryTyhof Tyhonovspaesand ontinuousmaps.

Letusremarkthat TyhontainsCompasasubategory. A.Chigogidzedened

foreahnormalfuntorontheategoryCompanextensionwhihisanormalfun-

torontheategoryTyh[6℄. Thisextension ouldbeonsidered foranyfuntor

on theategoryComp. Butthe situation is moreompliated for wider lasses

offuntors. Forexample,theextensionoftheprojetivepowerfuntor(whihis

weakly normal)doesnotpreserveembeddings,whihmakessuh extensionuse-

less(seeforexample[13, p.67℄). However,ifweapplytheChigogidzeextension

tosuhweakly normalfuntorsasthefuntorO oforder-preservingfuntionals,

thefuntorGofinlusionhyperspaes,thesuperextension,weobtainfuntorson

theategoryTyhwhih preserveembeddings.

Themainaimofthis paperistoinvestigatewhih propertiesfrom thedeni-

tionof normalfuntor are preservedbyChigogidze extension, speially we on-

entrateourattentionon thepreserving of embeddings. Theresults devoted to

(2)

preserving property whih is ruial for preservingof embeddings. In Setion 3

weonsiderwhihfuntorshavethe1-preimagespreservingproperty.

T.BanakhandR. CautyobtainedtopologiallassiationoftheChigogidze

extensionofthefuntorofprobabilitymeasuresforseparablemetrispaes. We

generalizethisresultto onvexfuntorsinSetion4.

x1

All spaes are assumed to be Tyhonov, all mappings are ontinuous. All

funtors are assumed to be ovariant. In the present paper we will onsider

funtorsatingintwoategories: theategoryTyhanditssubategoryComp.

Letusreallthedenitionofnormalfuntor. A funtorF :Comp!Compis

alledmonomorphi (epimorphi)ifitpreservesembeddings(surjetions). Fora

monomorphifuntorF andanembeddingi:A!X weshallidentifythespae

F(A)andthesubspaeF(i)(F(A))F(X).

A monomorphi funtor F is said to be preimage-preserving iffor eah map

f :X !Y andeahlosedsubsetAY wehave(F(f)) 1

(F(A))=F(f 1

(A)).

ForamonomorphifuntorFtheintersetion-preservingpropertyisdenedas

follows: F( T

fX

j2Ag)= T

fF(X

)j2Ag foreveryfamilyfX

j2Ag

oflosedsubsetsofX.

A funtor F is alled ontinuous if it preservesthe limits of inverse systems

S =fX

;p

;Agoveradireted setA. Letusalsonote that foranyontinuous

funtor F : Comp ! Comp the map F : C(X;Y) ! C(FX;FY) (the spae

C(X;Y)isonsideredwiththeompat-opentopology)isontinuous.

Finally, afuntor F isalled weight-preserving ifw(X)=w(F(X))for every

inniteX2Comp.

A funtor F is alled normal [15℄ if it is ontinuous, monomorphi, epimor-

phi,preservesweight,intersetions,preimages, singletonsandtheemptyspae.

A funtor F is said to be weakly normal (almost normal) if it satises all the

properties fromthedenition of anormalfuntorexeptperhapsthepreimage-

preservingproperty(epimorphiity)(see[13℄ formoredetails).

Similarly, one andene the sameproperties fora funtor F : Tyh ! Tyh

withtheonlydierenethatthepropertyofpreservingsurjetionsisreplaedby

thepropertyofsendingk-overingmapsto surjetions(reallthat f :X !Y is

ak-overingmapifforanyompatsetB Y thereexistsaompatsetAX

withf(A)=B)(see[13, Denition2.7.1℄).

A. Chigogidze dened an extension onstrution of a funtor in Comp onto

Tyh thefollowingway[6℄. Forany normalfuntor F :Comp!Compand any

X 2Tyh,thespae

F

(X)=fa2F(X)j there existsaompatset AX with a2F(A)g

isonsideredwiththetopologyinduedfromF(X),whereXistheStone-

Ceh

ompatiationofthespaeX. Next,givenanyontinuousmappingf :X !Y

betweenTyhonovspaes,putF

(f)=F(f)j

F (X)

. ThenF

formsaovariant

(3)

funtor in the ategoryTyh. Chigogidzeshowedthat in ase F is normal, the

funtorF

isalso normal.

x2

LetusmodifytheChigogidzeonstrutionforanyfuntorF :Comp!Comp.

For X2Tyh weput

F

(X)=fa2F(X)j thereexistsaompatset AX

with a2F(i

A

)(F(A))g

where by i

A

wedenote the naturalembedding i

A

: A,!X (wedo notassume

that the map F(i

A

) is an embedding). Evidently F

preserves empty set and

one-pointspaeiF does.

Now weonsider the problem when F

preserves embeddings. Extension of

anynormalfuntorpreservesembeddings, but, ifwedropthepreimagepreserv-

ing property, the situation ould be dierent. However, theexamples from the

introdutionshowthatthepreimage-preservingpropertyisnotneessary. Wede-

nesomeweakerpropertywhihwillgiveusaneessaryandsuÆientondition.

Denition1. WesaythatamonomorphifuntorF :Comp!Comppreserves

1-preimages, ifforanyf :X !Y,where X;Y 2Comp, anylosed AY suh

thatfj

f 1

(A)

isahomeomorphism,wehavethat(Ff) 1

(FA)=F(f 1

(A)). (Let

us remark itis equivalent to theonditionthat the map Ff j(Ff) 1

(FA) is a

homeomorphism.)

Letus note that this denition wasindependentlyintrodued byT. Banakh,

M.KlymenkoandA.Kuharski[3℄.

Proposition1. If F isamonomorphifuntorthatpreserves1-preimagesinthe

lassofopenmappings,thenF preserves1-preimages.

Proof: Takeanymappingf : X !Y suh that fj

f 1

(A)

is ahomeomorphism

for somelosed subsetA Y. Let i

1

: X !XY be theembedding dened

bythe formulai

1

(x)=(x;f(x)). Denote Z =XY=", where therelation" is

givenby"=fpr 1

Y

(a)ja2Ag(pr

Y

:XY !Y istherespetiveprojetion).

Let q : XY ! Z be the quotient mapping. The map h : Z ! Y given by

the onditions h(z) = y for any z = (x;y) 2 Z nq(X A) and h(z) = a for

any z = q(pr 1

Y

(a)), a 2 A, is open and satises the following twoonditions:

pr

Y

=hÆq,hj

h 1

(A)

isahomeomorphism. Apparently, themapi=qÆi

1 isan

embedding, moreover, hÆi = f. Sine F preserves1-preimages in the lass of

openmappings,wehave(Fh) 1

(FA)=F(h 1

(A)),whih givesus theequality

(Ff) 1

(FA)=F(f 1

(A)).

Proposition2. If F isamonomorphifuntorthatpreserves1-preimages,then

F

preservesembeddings.

(4)

Proof: Takeanyembedding f :X !Y. Thenthemap F

(f)islosed asthe

restritionof a losedmap onto afull preimage and, moreover,injetive,hene

anembedding.

ForanyX 2TyhandanyitsompatiationbX weandene

F

b

(X)=fa2F(bX)j thereisaompatsubset AX

with a2F(A)gF(bX)

andonsideritwiththerespetivesubspaetopology.

Corollary 1. If F is a monomorphi, 1-preimage-preserving funtor, then

F

(X)

= F

b

(X)foranyTyhonovspaeX and itsompatiationbX.

Proposition 3. If F is monomorphi, preserves1-preimagesand weight, then

F

preservesweight.

Proof: Thestatementfollowsfromthepreviousorollaryandthefat thatfor

any X 2 Tyh there exists its ompatiation bX whih has the same weight

asX.

Asthefollowingpropositionshows,thereverseimpliationtothatofProposi-

tion2alsoholds.

Proposition 4. Let F be aontinuous funtorsuh that F

preservesembed-

dings. ThenF preserves1-preimages.

Proof: Assume the ontrary. Then there exist a map f : X ! Y and a

losed subsetAY suh that fj

f 1

(A)

is ahomeomorphism andFf 1

(FA) 6=

F(f 1

(A)). We ansuppose that the map f is open by Proposition 1. There

exist 2FAand2FXnF(f 1

(A))suhthatFf()=. Wewillonstruta

spaeS2TyhanditsompatiationSsuhthatthemapF

(id

S ):F

(S)!

F

(S)=F(S)isnotanembedding,whereid

S

:S!S isanidentityembed-

ding.

FirstputZ =XN,wherethespaeofnaturalnumbersNisonsideredwith

thedisrete topologyand N =N [fg isthe one-point ompatiationof N.

Deneaontinuousfuntiong:Z !Y byg(x;n)=f(x)foranyx2X,n2N.

LetT =Z =" beaquotientspae, where " isan equivalene relationdened by

its lasses of equivalene ffxg j x 2 (X nf 1

(A))Ng[fg 1

(y)\X fg j

y 2Y nAg[ffagN ja2f 1

(A)g. Byq:Z !T wedenotethe respetive

quotient mapping. Then the map h:T !Y dened by theequality g =hÆq

is ontinuous. Theset D = q(Xfg) is ompat asa ontinuousimage of a

ompat set and moreoverhj

D

is one-to-one, hene ahomeomorphism between

D andY. Wedenote byj:Y !T theinverse embedding. Also,foranyn2N

thespaeS

n

=q(Xfng)is homeomorphito X andwedenej

n

:X !T by

j

n

(x)=q(x;n). ThenwehavehÆj

n

=f. FinallynotethatTisaompatiation

1

(5)

Put

n

=F(j

n

)()forn2N. Thesequenej

n

onvergestojÆf in thespae

C(X;T). SineF isontinuous,thesequeneF(j

n

)onvergestoF(jÆf)inthe

spaeC(FX;FT). Henethesequene

n

onvergestoF(jÆf)()=F(j)()2

F(q(f 1

(A)N)) .

NowonsiderF

(S)asasubspaeofF(S). Deneamaps

1

:S!X bythe

onditions

1 Æj

n

=id

X

foralln. Letusshowtheontinuityofs

1

. Considerany

pointt2SandanyopenneighborhoodU ofs

1

(t)inX. Sinethemapf isopen,

theset q(UN) =q((UN)[(f 1

(f(U))fg)) isan openset in T whih

ontainsthepointt. The set V =q(UN)\S isan openneighborhood of t

suhthat s

1

(V)U.

Lets:S!X betheextensionofs

1

. ThenFs(

n

)=2=F(f 1

(A)). Then

thesequene

n

does notonvergeto anyelementof F(q(f 1

(A)N)). The

propositionisproved.

Propositions2and4yieldthefollowing

Theorem 1. Forany ontinuous monomorphi funtor F the funtor F

pre-

servesembeddingsifandonlyif F preserves1-preimages.

Theproofofthefollowingpropositionisaroutinehekingandweomitit.

Proposition 5. LetF :Comp!Compbeafuntor.

(1) If F preserves embeddings, 1-preimages and intersetions then F

pre-

servesintersetions.

(2) If F preservesembeddingsand preimagesthenF

preservespreimages.

(3) If F preservessurjetionsthenF

sendsk-overingmapsto surjetions.

Now let us onsider ontinuity of the Chigogidze extension. The following

example shows that in the absene of the preimage-preserving property of the

funtorF,itis diÆulttospeakofontinuityofF

, sineeventheextensionof

suhknownweaklynormalfuntorasGdoesnotpossessit.

Example. LetusdenetheinlusionhyperspaefuntorG. Reallthatalosed

subset A 2 exp 2

X (where X 2 Comp) is alled aninlusion hyperspae, if for

everyA2AandeveryB2expX theinlusionABimpliesB 2A. ThenGX

isthespaeofallinlusion hyperspaeswith theinduedtopologyfromexp 2

X.

For any map f : X ! Y dene Gf : GX ! GY by Gf(A) = fB 2 expY j

f(A)B forsomeA2Ag. ThefuntorG isweakly normal(see [13℄for more

details). InthenextsetionwewillseethatthefuntorGpreserves1-preimages.

Let us show that the funtor G

is not ontinuous. Consider the following

inverse system. Foranyn2N put X

n

=N f1;:::;ng(here thespaesN and

f1;:::;ng are onsidered with the disrete topology). Dene p m

n : X

m

! X

n ,

where m n, in the following way: p m

n

(x;k) = (x;min fk;ng). We obtained

theinversesystem S =fX

m

;p m

n

;Ng. Thenthe limitspae X =limS ishome-

omorphi to the spae N A (here A = N = N [fg is the one-point om-

patiation of N, i.e. a onvergent sequene; also we put to begreater than

any natural number), and the limit projetionsp : X ! X anbe given by

(6)

p

n

(x;k)=(x;min fk;ng),k 2N. Theontinuity ofG

meansthat limG

(p

n ):

G

(limS)!limG

(S)isahomeomorphism.HerebothG

(limS)andlimG

(S)

anbethoughtassubspaesofG(bX),wherebisaompatiationofXwiththe

propertybX =limS. Therstinlusion followsfrom Corollary1,andthese-

ondinlusionis duetoontinuityofG(heneG(limS)=G(bX)=limG(S))

and existeneof the embedding limG

(S),!limG(S) whih is thelimit of a

morphismthatnaturallyembedseahG

(X

n

)into G(X

n ).

Now we will onstrut K 2 limG

(S) whih does not belong to limG

(p

n )

(G

(limS)). Considerthe spaeX embedded into itsompatiation bX. For

anyn2AnfgputK

n

=f1;:::;ngfng. Ifwewanttoobtainalosedfamilyof

sets,thesetK

=Nfgmustbeaddedtothefamily e

K=fK

n g

n2N

. Nowput

K=fBbXjK

n

B forsomen2Ag. ThenK2limG

(S). However,there

isnoelementC2G

(limS)withlimG

(p

n

)(C)=K. Indeed,theprojetionof

anyompatsetBX ontothefatorN ofNA isnite,henelimG

(p

n )(C)

does not ontain K

or ontains some nite subsets in N N fg. Hene,

limG

(p

n

),beingnotsurjetive,isnotahomeomorphism.

x3

We start this setion with denitions of some funtors we deal with in this

paper. Let X be aompatum. By C(X) we denote the Banah spae of all

ontinuous funtions : X ! R with the usual sup-norm. We onsider C(X)

with thenaturalorder. Let : C(X) !R be afuntional (we donot suppose

a priori that is linear or ontinuous). We say that is 1) non-expanding if

j(') ( )jd('; )forall'; 2C(X);2)weakly additive ifforanyfuntion

2 C(X) and any 2R we have(+

X

) =()+ (by

X

wedenote the

onstant funtion); 3) preserves order if for any '; 2 C(X) suh that '

theinequality(') ( )holds; 4)linear if forany , 2R and forany two

funtions ,2C(X)wehave(+ )=()+( ).

NowforanyspaeX denoteVX= Q

'2C(X)

[min';max'℄. Foranymapping

f :X !Y denethemapVf asfollows: Vf()(')=('Æf)forevery2VX,

'2C(Y). ThenV isaovariantfuntorintheategoryComp[11℄.

LetusremarkthatthespaeVX ouldbeonsideredasthespaeofallfun-

tionals :C(X)!R withtheonlyonditionmin'(X)(')max'(X)for

every'2C(X). ByEX wedenotethesubsetofVX denedbytheondition1)

(non-expandingfuntionals;see[5℄formoredetails),byEAXthesubsetdened

by the onditions 1) and 2). The onditions 2) and 3) dene the subset OX

(order-preservingfuntionals,see[10℄);nally,theonditions3)and4)denethe

well-knownsubset PX (probability measures,see for example[13℄). Foramap

f :X !Y themappingFf, where F is oneofP, O, EA, E, isdened asthe

restrition of Vf on FX. It is easy to hek that the onstrutions P, O, EA

andE denesubfuntorsofV. ItisknownthatthefuntorsOandEareweakly

normal(see [10℄ and [5℄). Using the sameargumentsone anhek that EA is

(7)

The question arises naturally whih of the funtors dened above have the

propertyofpreserving1-preimages. Itiseasytohekthatwehavetheinlusions

PXOX EAXEXVX. WewillshowthatthefuntorEAsatisesthis

property and E doesnot. Sine subfuntors inherit the 1-preimagespreserving

property,thisistheompleteanswer. Letusalsoremark thattheresultsof[11℄

and[12℄showthatmanyotherknownfuntorsouldbeonsideredassubfuntors

of EA, for example the superextension, the hyperspae funtor, the inlusion

hyperspaefuntoret. Thisshowsthatthelassoffuntorswiththe1-preimages

preservingpropertyiswideenough.

Westartwithadenition ofanAR -ompatum. Reallthat aompatumX

isalledanabsoluteretrat(brieyX 2AR ) ifforanyembeddingi:X !Z of

X into ompatumZ theimagei(X)isaretratofZ.

Thenextlemmawill beneededinthefollowingdisussion.

Lemma1. LetF beamonomorphisubfuntor of V whihpreservesinterse-

tionsandBbealosedsubsetofaompatumX. Then2FBi ('

1 )=('

2 )

foreah'

1

;'

2

2C(X)suhthat'

1 j

B

='

2 j

B .

Proof: Neessity. Theinlusion2FB FXmeansthatthereexists

0 2FB

withF(i

B )(

0

)=,wherei

B

:B!X isthenaturalembedding. Hene,forany

'

1 ,'

2

2C(X)suhthat'

1 j

B

='

2 j

B

wehave('

1 )=

0 ('

1 Æi

B )=

0 ('

2 Æi

B )=

('

2 ).

SuÆieny. Wean ndanembedding j:B ,!Y,where Y 2AR . Dene Z

tobethequotientspaeofthedisjointunionX[Y obtainedbyattahingX and

Y byB. Denote byr:Z !Y aretrationmapping.

Now takeany 2 FX FZ with the property ('

1

)= ('

2

) for eah '

1 ,

'

2

2 C(X) suh that '

1 j

B

= '

2 j

B

. We laim that F(r)() =. Indeed, take

any'2C(Z). ThenF(r)()(')=('Ær)=(') sine'Ærj

Y

='j

Y

. Hene,

2FX\FY =FB.

Proposition 6. ThefuntorEApreserves1-preimages.

Proof: Letf :X !Y beaontinuousopenmapbetweenompata X andY

andB be alosedsubsetof Y suhthat fj

f 1

(B)

is ahomeomorphism. Choose

any 2 EA(B) EA(Y). Using Lemma 1we an dene

0

2 EA(f 1

(B))

by the ondition

0

(') = ( ) for eah ' 2 C(X) and 2 C(Y) suh that

Æf jf 1

(B)='j

f 1

(B) .

Itisenoughtoshowthatforeah2(EA(f)) 1

()wehave=

0

. Suppose

the ontrary. Then there exist ' 2 C(X) and 2 C(Y) suh that Æf j

f 1

(B)='j

f 1

(B)

and(')6=( ). Weansuppose that(')>( ). Dene

afuntion 0

:Y !R by 0

(y)=max'f 1

(y)foranyy 2Y. Thefuntion 0

isontinuoussinef isopen. Also,sine 0

j

B

= j

B

,wehavethat( 0

)=( ).

Put =( 0

D)Æf,whereD=supfmax'f 1

(y) min'f 1

(y)jy2Yg. Then

d(;') D but (') () =(') ((

0

D)Æf) = (') ( 0

)+D =

(') ( )+D>Dandweobtainaontradition. Theproofissimilarforthe

(8)

Hene,EApreserves1-preimagesinthelassofopenmappings,and,byPropo-

sition1,wearedone.

Proposition 7. The funtor of nonexpanding funtionals E does not preserve

1-preimages.

Proof: Considerthemappingf :X!Y betweendisretespaesX =fx;y;s;tg

andY =fa;b;gwhihisdenedasfollows: f(x)=a,f(y)=b,f(s)=f(t)=.

PutA=f'2C(X)j'(s) ='(t)g. Denethefuntional :A!R asfollows:

(') =minf'(x);'(y)g if 'j

fx;yg

0, (') = maxf'(x);'(y)g if 'j

fx;yg 0,

and (') =0otherwise. Onean hekthat isnonexpanding. Nowtakethe

funtion :X !R dened asfollows (x)=1, (y)= 1, (s)=0, (t)=4.

Oneanhekthatweanextend toanonexpandingfuntionalonA[f gby

deningitsvalueon tobe 1. Thisnewfuntionalanbefurther extendedto

anonexpanding funtional on thewhole C(X) [5℄. Denote this extension by e.

Evidently,Ef(e)2E(fa;bg). Ontheotherhand,e2=E(fx;yg).

x4

Weonsider in this setion a monomorphiontinuous funtor F whih pre-

servesintersetions,weight,emptyset,pointand1-preimages. Weinvestigatethe

topologyofthespaeF

Y whereY isametrizableseparablenon-ompatspae.

Weonsider Y asadense subsetofametrizableompatumX. Itfollowsfrom

Corollary1that F

Y ishomeomorphito F

b

Y FX (whereX isonsidered as

aompatiationbY ofY)andinwhatfollowsweidentifyF

Y withF

b

Y. Also,

thepropertiesweimposeonF implythatF

Y isadensepropersubspaeofFX.

T. Banakh proved in [1℄ that F

Y is a F

-subset of FX when Y is loally

ompat;F

Y isF

Æ

-subsetwhenY isaG

Æ

-subset. IfY isnotaG

Æ

-subset,then

F

Y isnotanalyti.

WeonsiderintheHilbertubeQ=[ 1;1℄

!

thefollowingsubsets: =f(t

i )2

Qjsup

i jt

i

j<1g;=f(t

i

)2Qjt

i

6=0fornitely manyigand

!

Q

!

= Q.

Itisshownin[2℄thatanyanalytiP

Y ishomeomorphitooneofthespaes

,or

!

. Wegeneralizethisresultforonvexfuntors.

ByConvwedenotetheategoryofonvexompata(ompatonvexsubsets

ofloallyonvextopologiallinearspaes)andaÆnemaps. LetU :Conv!Comp

be the forgetful funtor. A funtor F is alled onvex if there exists afuntor

F 0

: Comp ! Conv suh that F =UF 0

. It is easy to see that the funtors V,

E, EA, O and P are onvex. It is shown in [14℄ that for eah onvexfuntor

F there exists a unique natural transformation l : P ! F suh that the map

lX:PX !FX isanaÆneembeddingforeahompatumX.

Lemma2. P

Y =(lX) 1

(F

Y).

Proof: Take any measure 2 P(X) suh that lX() = 0

2 F

Y. By the

denition of F

Y it means that 0

2 FB for some ompatum B Y. We

will show that 2 PB P

Y. Choose a ompat absolute retrat T whih

(9)

obtained by attahing X and T by B. By r : Z ! T denote the retration.

Sinelisanaturaltransformationand ristheidentityonT Z, wehavethat

F(r)ÆlZ()= 0

=lTÆP(r)(). Hene,=P(r)()2P(T)dueto injetivity

oflZ. Therefore,2PX\PT =PB. Thelemma isproved.

We need some notions from innite-dimensional topology. See [4℄ for more

details. All spaesareassumed tobemetrizableand separable. A losedsubset

AofaompatumT isalledZ-setifthereexistsahomotopyH :T[0;1℄!T

suh that Hj

Tf0g

= id

Tf0g

and H(T (0;1℄)\A = ;; aountable unionof

Z-setsofT isalled aZ-set.

WedonotknowifF

Y isontainedinaZ-setofFXforanyonvexfuntorF.

Thus, weintroduesomeadditional property. We onsiderthe ompatumFX

asaonvexsubsetof aloallyonvexlinearspae.

ReallthatforanysubsetAofalinearspaeLthenotationa(A)standsfor

theaÆnehullofA,that is,theseta(A)=fta+(1 t)bja;b2A;t2Rg.

Denition2. AonvexfuntorF :Comp!Compisalledstronglyonvexiffor

eahompatumX,eahlosedsubsetAX wehave(FXnFA)\aFA=;.

Proposition 8. EahonvexsubfuntorF ofthefuntorV is stronglyonvex.

Proof: ByLemma 1anyelementfromaFAtakesthesamevalueatanytwo

funtionsfrom C(X)whihoinideonA,whihisnottrueforfuntionalsfrom

FXnFA.

Proposition 9. LetF beastronglyonvexfuntor. Then F

Y is ontainedin

aZ-setinFX.

Proof: Take any y 2 XnY. Then F

Y F

(Xnfyg), and Xnfyg an be

represented as a ountable union of its ompat subsets A

n

with the property

that A

n

int A

n+1

, hene, F

(Xnfyg) = S

n2N F(A

n

). Let us show that all

F(A

n

) are Z-sets in FX. Take any 2 FX nF

(X nfyg) and the set Z =

ft+(1 t)jt2(0;1℄;2F

(Xnfyg)g. SineF isstronglyonvex,wehave

Z\F

(Xnfyg)=;. SineZ isaonvexanddensesubsetofFX,thereexistsa

homotopyH :FX[0;1℄!FXsuhthatH(FX(0;1℄)Z(see,forexample,

Example12,13toSetion1.2 in[4℄).

Now,wearegoingto obtaintheompletetopologiallassiationofthepair

(FX;F

Y)whereXisametrizableompatumandY itsproperdenseG

Æ

-subset.

Weneedsomeharaterizationtheorems.

TheoremA ([8℄). LetCbeaninnite-dimensionaldenseonvexsubspaeof a

onvexmetrizableompatumK,CisontainedinaZ-setof Kandadditionally

letCbeaountableunionofitsnite-dimensionalompatsubspaes. Thenthe

pair(K ;C)is homeomorphito(Q;).

TheoremB ([7℄). LetKbeaonvexmetrizableompatum,andletCK be

itsproperdenseonvex-ompatsubspaethatontainsaninnite-dimensional

onvexompatumandis ontainedin aZ-set of K. Then thepair (K ;C)is

(10)

Thefollowingtheoremfollowsfrom5.3.6,5.2.6,3.1.10in[4℄.

TheoremC. LetKbeaonvexompatsubsetofaloallyonvexlinearmetri

spae, and let C K be its proper dense onvex F

Æ

subspae suh that C is

ontainedin aZ-set of K,(KnC)\aC=;,andadditionallythereexists a

ontinuousembeddingh:Q!K suhthat h 1

(C)=

!

. Thenthepair(K ;C)

ishomeomorphito thepair(Q;

!

).

Theorem2. LetF beastronglyonvexfuntor,X isametrizableompatum

andY isitsproperdenseG

Æ

-subset. Thepair(FX;F

Y)ishomeomorphito

(1) (Q;),if Y isadisretesubspaeof X andF(n)isnite-dimensionalfor

eah n2N;

(2) (Q;),if Y isadisretesubspaeof X andF(n)isinnite-dimensional

forsomen2N orY isaloallyompatnon-disretesubspaeof X;

(3) (Q;

!

),if Y isnotloally ompat.

Proof: Itiseasytoseethat F

Y isaonvexsubsetofFX.

Weprovethe rst assertion. Sine X is metrizable, Y is ountable. We an

represent Y = S

1

n=1 Y

n

where jY

n

j = n. Then F

Y =

S

1

n=1 FY

n

. Sine PY

n

ouldbeonsidered asan (n 1)-dimensionalsubspaeof FY

n

, the spae F

Y

isinnite-dimensional. Moreover,F

Y is aZ-set byProposition 9. Sineeah

FY

n

isanite-dimensionalompatum,weanapplyTheorem A.

We prove the seond assertion. In the ase when Y is disrete, FY

n is an

innite-dimensional onvex ompatumfor some n. When Y is not disrete, it

ontains an innite ompatum Y 0

and FY 0

is an innite-dimensional onvex

ompatum. WeapplyProposition9andTheoremB.

For the third assertion, note that the pair (PX;P

Y) is homeomorphi to

(Q;

!

)[2℄. Sine F isstronglyonvex,wehave(FXnF

Y)\aF

Y =;. We

applyLemma2,Proposition9andTheoremC.

Corollary 2. Suppose that F isastrongly onvexfuntor. Then foranysepa-

rablemetrizablespaeX

(1) X

=

N implies F

(X)

= Q

f

in ase F(n) is nite-dimensional for any

n2N orF

(X)

=

otherwise;

(2) if X isloallyompatnon-disreteandnon-ompatthenF

(X)

=

;

(3) if X istopologially ompletenotloally ompatthenF

(X)

=

!

.

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408{410.

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2

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[13℄ TeleikoA.,ZarihnyiM.,CategorialTopologyofCompatHausdorSpaes,VNTLPub-

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3{62(Russian).

DepartmentofMehanisandMathematis,LvivNationalUniversity,

Universytetskast. 1,79000Lviv, Ukraine

E-mail: razymathsukr.net

InstituteofMathematis,CasimirustheGreatUniversity,Bydgoszz,

Poland

and

DepartmentofMehanisandMathematis,LvivNationalUniversity,

Universytetskast. 1,79000Lviv, Ukraine

E-mail: tarasradulyahoo.o.uk

(Reeived June4,2011 , revised February2,2012)

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