Hyperbolic Systems With Analytic Coefficients:正誤表
[p.2 ↑8] with|τ|< ϵ, satisfiesP u= 0 in =⇒with|τ|< ϵ, satisfiesP u∈C0∞(ω) andP u= 0 in
[p.3 ↑3 — p.4 ↓15] Proof of Proposition 1.1 should be replaced by: Let ω be the open set in Definition 1.1. Take an open setV such thatK⋐V ⋐ω. Then for any f ∈ C0∞(V−ϵ) there exists a unique u ∈H∞(ω) satisfying P u =f in ω and vanishing in x0 ≤ −ϵ. Denote by T the map T : C0∞(V−ϵ)3f 7→u∈ H∞(ω). Note that H∞(ω) is a Fr´echet space equipped with countable semi- norms k · kHp(ω), p = 0,1, . . .. Assume that C0∞(V−ϵ) 3 fj → f in C0∞(V−ϵ) and T fj = uj → u in H∞(ω). SinceP uj = fj it is clear that P u = f and u= 0 in x0 ≤ −ϵ. From the uniqueness of the solution one has T f = uand hence the graph of T is closed. From the Banach’s closed graph theorem it follows thatT is a continuous map. Therefore for anyp∈Nthe inverse image of{u∈H∞(ω)| kukHp(ω) <1}, which is a neighborhood of 0 in H∞(ω), is a neighborhood of 0 inC0∞(V−ϵ), that is there existδ >0 andq∈Nsuch that
f ∈C0∞(V−ϵ), kfkHq(V)< δ=⇒ kT fkHp(ω)<1.
For any f ∈ C0∞(V−ϵ) the Hq(V) norm of δf /kfkHq(V) is less than 1 then from the uniqueness of the solution we conclude that for anyf ∈C0∞(V−ϵ) and u∈H∞(ω) satisfying P u=f inω and vanishing inx0≤ −ϵ satisfies
kukHp(ω)≤δ−1kfkHq(V).
[p.21 ↑12] polynomial inx=⇒polynomial iny [p.27 ↑10]Proof of Proposition 1.6. =⇒Proof.
[p.29 ↑9]Proof of Proposition 1.6. =⇒Proof.
[p.72 ↑5]hρ(sY −tX) = (−1)rhρ (−sY+tX) = (−1)rhρ (Y)∏
(−s−λj(tX)) =⇒ hρ(sY −tX) = (−1)rhρ(−sY +tX) = (−1)rhρ(Y)∏
(−s−λj(tX)) [p.125 ↑5]C|x|−2lt∗(x)2(Q−q−l−1)∑
l1+l2≤l
∫φ(x)
ε(x) |∂tQ+1+l1∂xl2f|2dxdt
=⇒C|x|−2l|r|2(q−k−l)t∗(x)2(Q−q−l−1)∑
l1+l2≤l
∫t∗(x)
ε(x) |∂tQ+1+l1∂lx2f|2dt [p.125 ↑4]C|t−ε|2(Q−k)∫t
ε|∂tQ+1∂xlf|2dxdt
=⇒Delete
[p.125 ↑3] for q+l+ 1≤Q,k+l ≤q and =⇒for|t| ≤t∗(x),q+l+ 1≤Q, k+l≤qand
[p.130 ↓7〜11] should be replaced by
|∂tk∂xlrqFq−1|2
≤C ∑
k1+k2≤k
|r|2(q−l−k1)|x|−2lt∗(x)2(Q−q−l−k2−1)+1 ∑
l1+l2≤l
∫ t∗ ε
|∂tQ+1+l1∂xl2f|2dt
≤C|x|−2l|r|2(q−l−k)t∗(x)2(Q−q−l−1)+1 ∑
l1+l2≤l
∫ t∗ ε
|∂tQ+1+l1∂lx2f|2dt
hence we conclude the proof.
[p.132 ↑10] Since ∂tpu= 0 on t = sν(x) and t = σν+1(x), |x| = δ(T−t) are space-like curves =⇒Since∂tpu= 0 ont=sν(x)
[p.164 ↑1]P(x) =⇒P(ξ)
[p.197 ↓10]intervals=⇒neighborhoods