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(1)

N-

Fractional

Calculus

of

Some

Multi-

Powers

Functions

Katsuyuki

Nishimoto

Institute

for

Applied

Mathematics, Descartes

Press

Co.

2-13-10

Kaguike, Koriyama,

963-8833.

JAPAN

Fax:

+81-24-922-7596

Abstract

in

a

previous

article of

the

author,

N-

fractional calculus

$(((z-b)^{\beta}-c)^{a})_{\gamma}$

,

$((z-b)^{\beta}-c\neq 0)$

are

discussed.

In

this

article that

of

more

extended forms

$((((z-b)^{\beta}-c)^{\alpha}-d)^{\delta})_{\gamma}$

,

$(((z-b)^{\beta}-c)^{\alpha}-d\neq 0)$

are

discussed.

Moreover their

specIal

cases

$((((z-b)^{\beta}-c)^{\alpha}-d)^{l})_{n}$

,

$(n\in Z_{0}^{*}, ((z-b)^{\beta}-c)^{a}-dz0)$

are

presented.

\S

$0$

.

Introduction

(Definition

of Fractional

Calculus)

(I)

Definition.

(by

K.

Nishimoto)

([1]

Vol.

1)

Let

$Drightarrow\{D_{-}.D_{*}\}$

.

$C-\{C_{-}, C_{*}\}$

,

$C_{-}$

be

a

curve

along

the

cut joining

two

points

$z\bm{t}d-\infty+i$

Im(z),

$C_{*}$

be

a

curve

along

the

cut joining two points

$z$

and

$\infty+i{\rm Im}(z)$

,

$D_{-}$

be

a

domain surrounded

by

$C_{-}$

,

$D_{*}$

be

a

domain surrounded

by

$C_{*}$

.

(Here

$D$

contains the points

over

the

curve

$C$

).

Moreover,

let

$f-f(z)$

be

a

regular

funcdon in

$D(z\in D)$

,

$f_{\nu}-(f)_{\vee^{-}C}(f)_{V}- \frac{\Gamma(v+1)}{2\pi i}\int_{c^{\frac{f(\zeta)}{(\zeta-z)^{\nu*1}}d\zeta}}$

$(v\not\in T)$

,

(1)

$(f)_{-m}- \lim_{\nu\wedge-m}(J)_{v}$

$(m\in Y)$

,

(2)

where

$-\pi\leq\arg(\zeta-z)\leq\pi$

for

$C_{-}$

.

$0\leq\arg(\zeta-z)\leq 2\pi$

for

$C_{*}$

,

$\zeta*z$

.

$z\in C$

,

$v\in R_{*}$

$\Gamma$

; Gamma

function,

then

$(f)_{v}$

is

the

fractional

differtntegration

of

arbitrary

order

$v$

(derivatives

of

order

$v$

for

$v>0$

,

and

integrals

of

$order-v$

for

$v<0$ ),

with

respect to

$Z$

,

of

(2)

(I

I)

On

the fractional calculus

operator

$N^{v}[3]$

Theorem

A.

Let

fractional

calculus

operator

(Nishimoro’s Operator)

$N^{v}$

be

$N^{v} \approx(\frac{\Gamma(v+1)}{2\pi i}\int_{C^{\frac{d\zeta}{(\zeta-z)^{v*1}}}})$

$(v\not\in T)$

,

[Refer

to

(1)]

(3)

with

$N^{-m}= \lim_{varrow-,n}N^{\nu}$

$(m\in Z^{*})$

,

(4)

and

defi

ne

the

$bina\eta$

operation

$\circ$

as

$N^{\beta}\circ N^{a}f-N^{\beta}N^{\alpha}f-N^{\beta}(N^{a}f)$

$(\alpha, \beta\in R)$

,

(5)

then

the

set

$\{N^{v}\}-\{N^{v}|v\in R\}$

(6)

is

an

Abelian

Product

group

(having

continuous

index

$v$

)

which

has the inverse

transfom

operaror

$(N^{v})^{-1}=W^{v}$

to

the

fractional

calculus

operator

$N^{v}$

,

for

the

ftznct

ion

$f$

such that

$f\in F=\{f;0\neq|f_{\vee}|<\infty,$ $v\in R\}$

.

where

$f-f(z)$

and

$z\in C$

.

(vis.

$-\infty<v<\infty$

).

(For

our

convenience,

we

call

$N^{\beta}\circ N^{a}$

as

product

of

$N^{\beta}$

and

$N^{a}$

.

)

Theorem

B.

F.O.G.

$\langle N^{\nu}$

}

is

an

*

Action product

group

which

has

continuous

index

$v$

for

the

set

of

F.

(F.O.G.

; Fractional

calculus

operator

group)

131

(III)

Lemma. We

have

[1]

(i)

$((z-c)^{b})$

$-e^{-ir}$

$\frac{\Gamma(\alpha-b)}{\Gamma(-b)}(z-c)^{b-\alpha}$ $(| \frac{\Gamma(\alpha-b)}{\Gamma(-b)}|<\infty)$

,

(7)

(I i)

$(\log(z-c))_{a}--e^{-ira}\Gamma(\alpha)(z-c)^{-a}$

$(|\Gamma(\alpha)|<\infty)$

,

(8)

$(iiI)$

$((z-c)^{-\alpha})_{-\alpha}=-e^{i\pi a} \frac{1}{\Gamma(\alpha)}\log(z-c)$

$(|\Gamma(\alpha)|<\infty)$

,

$t9$

)

where

$z-cx0$

for

(i)

and $z-c*O,$

$1$

for

(i1), (

$i$

il),

(1 v)

$(u\cdot v)_{\alpha}$$:- \sum_{k\cdot 0}^{\infty}\frac{\Gamma(\alpha+1)}{k!\Gamma(\alpha+1-k)}u_{\alpha-k}v_{k}$ $(\begin{array}{l}u-u(z)arrow vv(z)\end{array})$

.

(10)

\S 1.

Preliminary

The

Teorem

below

is

reported

by

the author

already

(cf.

J.

Frac.

Calc. Vol.

29,

May

$(2006),pp.35- 44.)$

.

$[12]$

Theorem

D.

We have

(3)

$x\sum_{k*0}^{\infty}\frac{[-\alpha]_{k}\Gamma(\beta k-\alpha\beta+\gamma)}{k!\Gamma(\beta k\sim\alpha\beta)}(\frac{c}{(z-b)^{\beta}}I^{\text{た}}$

(1)

and

$(ii)$

$(((z-b)^{\beta}-c)^{a})_{\iota}-(-1)^{n}(z-b)^{\alpha\beta-n}$

$x\sum_{k\cdot 0}^{\infty}\frac{[-a]_{k}[\beta k-\alpha\beta]_{n}}{k!}(\frac{c}{(z-b)^{\beta}})^{k}$

$(n\in Z_{0}^{*})$

(2)

where

$| \frac{c}{(z-b)^{\beta}}|<1$

,

and

$[\lambda]_{k}\approx\lambda(\lambda+1)\cdots(\lambda+k-1)\approx\Gamma(\lambda+k)/\Gamma(\lambda)$

with

$[\lambda]_{0}arrow 1$

,

(Notation

of

Pochhammer).

\S 2.

N-

Fractional

Calculus

of

Functions

$(((z-b)^{\beta}-c)^{a}-d)^{\delta}$

Theorem 1.

We

have

(i)

$((((z-b)^{\beta}-c)^{\alpha}-d)^{\delta})_{\gamma}-e^{-i\kappa\gamma}(z-b)^{a\beta\delta-\gamma}$

$x\sum_{k-0}^{\infty}\frac{[-\delta]_{m}[-\alpha(\delta-m)]_{k}\Gamma(\beta k-\alpha\beta(\delta-m)+\gamma)}{m!\cdot k!\Gamma(\beta k-\alpha\beta(\delta-m))}(\frac{c}{(z-b)^{\beta}})^{k}(\frac{d}{(z-b)^{\alpha\beta}}l^{m}$

(1)

and

(Ii)

$(((z-b)^{\beta}-c)^{\alpha}-d)^{\delta})_{n}\approx(-1)^{n}(z-b)^{\alpha\beta\delta-n}$

(4)

where

$((z-b)^{\beta}-c)^{\alpha}-d\neq 0$

,

$| \frac{c}{(z-b)^{\beta}}|<1$

,

$| \frac{d}{(z-b)^{\alpha\beta}}|<1$

,

$n\in Z_{0}^{*}$

.

Proof of

(i).

We have

$(((z-b)^{\beta}-c)^{a}-d)^{\delta}\approx X^{\delta}(1-\cdot 4X)^{\delta}$

$(X\approx((z-b)^{\beta}-c)^{a})$

(3)

$arrow X^{s}\sum_{m\triangleleft}^{\infty}\frac{[-\delta 1_{n}}{m!}(\frac{d}{X})^{m}$

(4)

$- \sum_{m\cdot 0}^{\infty}\frac{[-\delta]_{m}(d^{m})}{m!}X^{\delta\sim m}$

(5)

(6)

hence,

operating

N- fractional

calculus

operator

$N^{\gamma}$

to

the

$bo$

th

sIdes

of

(6),

we

obtain

$((((z-b)^{\beta}-c)^{a}-d)^{\delta})_{\gamma}$

$\approx\sum_{m-0}^{\infty}\frac{[-\delta]_{m}(d^{m})}{m!}(((z-b)^{\beta}-c)^{\alpha(\delta-\iota n)})_{\gamma}$

(7)

$- \sum_{m-0}^{\infty}\frac{[-\delta]_{m}(d^{m})}{m!}[e^{-\dot{l}*\gamma}(z-b)^{\alpha\beta(\delta-m)-\gamma}$

$xz_{-0^{k!\Gamma(\beta k-\alpha\beta(\delta-m))}}^{\ovalbox{\tt\small REJECT}}\infty[-a(\delta-m)]\Gamma(\beta k-\alpha\beta(\delta-m)+\gamma)(\frac{c}{(z-b)^{\beta}}I^{k}$

(8)

applying Theorem D.

(1),

under

the

conditions

stated

before.

We

have

then

(1)

from

(8)

clearly.

Proof

of

(1i).

Set

$y-n$

in

(1).

Note

1.

We

use

the

notatlons

$\sum_{m.k-0}^{\infty}\cdots\approx\sum_{m-0}^{\infty}\sum_{k-0}^{\infty}\cdots$

for

our

convenience.

(5)

Corollary

1.

We

have

(i)

$((((z^{\beta}-c)^{\alpha}-d)^{\delta})_{\gamma}=e^{-i\pi\gamma}z^{\alpha\beta\delta-\gamma}$

$xm\sum_{-0}^{\ovalbox{\tt\small REJECT}^{k}}[-\delta][-m\alpha!(\delta k-!m)]\Gamma(\beta k-\alpha\beta(\delta-m)+\gamma)(\frac{c}{z^{\beta}}I^{k}(\frac{d}{z^{\alpha\beta}}I^{m}\infty\cdot$

(9)

and

$(ii)$

$(((z^{\beta}-c)^{\alpha}-d)^{\delta})_{n}\approx(-1)^{n}z^{\alpha\beta l-n}$

$x\sum_{m.k-0}^{\infty}\frac{[-\delta]_{m}[-\alpha(\delta-m)]_{k}[\beta k-\alpha\beta(\delta-m)]_{*}}{m!\cdot k!}(\frac{c}{z^{\beta}})^{k}(\frac{d}{z^{\alpha\beta}})^{m}$

,

(10)

where

$(z^{\beta}-c)^{\alpha}-.d\prime 0$

,

$| \frac{c}{z^{\beta}}|<1$

,

$| \frac{d}{z^{\alpha\beta}}|<1$

,

$n\in Z_{0}^{*}$

.

Proof.

Set

$b-0$

in

Theorem 1.

\S 3.

Some Special Cases

[I]

When

$\beta\approx\alpha-1$

,

we

obtain

$((((z-b-c-\phi^{\delta})_{\gamma}\infty e^{-i\kappa\gamma}(z-b)^{\delta-\gamma}$

$x\sum_{mk-01}^{\infty}\frac{[-\delta]_{m}[m.-\delta]_{k}I\chi k+m-\delta+y)}{m!k!\Gamma(k+m-\delta)}(\frac{c}{z-b})^{k}(\frac{d}{z-b})^{m}$

(1)

$(\vdash_{z-}c_{b}|$

,

$| \frac{d}{z-b}|<1$

,

$| \frac{\Gamma(k+m-\delta+\gamma)}{r\chi k+m-\delta)}|<\infty)$

from

Theorem

1.

(i).

Now

we

have the identities

$\Gamma(m-\delta)-\Gamma(-\delta)[-\delta]_{m}$

,

(2)

$\Gamma(k+m-\delta)\approx\Gamma(m-\delta)[m-\delta\iota$

,

(3)

(6)

then

applying

(2)

$\sim(4)$

into

the

RHS of

(1)

,

we

obtain

RHS

of

(1)

$=e^{-in\gamma}(z-b)^{\delta-\gamma}$

$x\sum_{m-0}^{\infty}\frac{\Gamma(m-\delta+y)}{m!\Gamma(-\delta)}(\frac{d}{z-b})^{m}\sum_{k-0}^{\infty}\frac{[m-\delta+\gamma]_{k}}{k!}(\frac{c}{z-b})^{k}$

(5)

$arrow e^{-i\pi\gamma}(z-b)^{\delta-\gamma}$ $\sum_{m-0}^{\infty}\frac{\Gamma(m-\delta+\gamma)}{m!\Gamma(-\delta)}(\frac{d}{z-b})^{m}(1-\frac{c}{z-b})^{\delta-\gamma-m}$

(6)

$\approx e^{-i\eta}(z-b-c)^{\delta-\gamma}$

$\frac{\Gamma(-\delta+y)}{\Gamma(-\delta)}\sum_{m-0}^{\infty}\frac{[-\delta+\gamma]_{m}}{m!}(\frac{d}{z-b-c})^{m}$

(7)

$=e^{-in\gamma} \frac{\Gamma(-\delta+y)}{\Gamma(-\delta)}(z-b-c-d\gamma^{\delta-\gamma}$

.

$(| \frac{\Gamma(-\delta+y)}{\Gamma(-\delta)}|<\infty)$

(8)

$us\dot{i}g$

the

relationship

$\sum_{-0}^{\infty}\frac{[\lambda]_{k}}{k!}z^{k}=(1-z)^{-\lambda}$

.

(9)

The result

(8)

ls

same as

the

one

obtained by

Lemma

(i).

[II]

When

$d-0$

and

$\delta\approx 1$

,

we

obtaIn

$(((z-b)^{\beta}-c)^{a})_{\gamma}-e^{-l\kappa\gamma}(z-b)^{a\beta-\gamma}$

$xm2_{-0^{m!\cdot k!\Gamma(\beta k-\alpha\beta(1-m))}}^{\ovalbox{\tt\small REJECT}(\frac{c}{(z-b)^{\beta}})^{k}(\frac{0}{(z-b)^{\phi}}I^{m}}\infty[-1][-\alpha(1-m)]\Gamma(\beta k-\alpha\beta(1-m)+\gamma)$

(10)

$\approx e^{-i\eta}(z-b)^{a\beta-\gamma}’\geq\triangleleft\frac{[-\alpha]_{k}\Gamma(\beta k-\alpha\beta+y)}{k!\Gamma(\beta k-\alpha\beta)}\infty(\frac{c}{(z-b)^{\beta}}I^{k}$

(11)

from Theorem

1.

(i).

That

is,

in this

case

we

have Theorem

D.

(1)lt

self,

clearly.

[III

I

When

$n-0$

,

we

have

$(((z-b)^{\beta}-c)^{a}-d)^{\delta})_{0}-(z-b)^{\alpha\beta\delta}$

(7)

$((z-b)^{\beta}-c)^{\alpha}-d\neq 0$

,

$| \frac{c}{(z-b)^{\beta}}|<1$

,

$| \frac{d}{(z-b)^{\alpha\beta}}|<1$

,

.

from Theorem

1.

$(ii)$

.

Indeed

we

obtain

RHS of

(12)

.

$(z-b)^{a\beta\delta}$

$x\sum_{m-0}^{\infty}\frac{[-\delta]_{m}}{m!}(\frac{d}{(z-b)^{\alpha\beta}}I^{m}z_{\triangleleft}\infty\frac{[-\alpha(\delta-m)]_{k}}{k!}(\frac{c}{(z-b)^{\beta}})^{k}$

(13)

$\approx(z-b)^{\alpha\mu}$ $\sum_{m-0}^{\infty}\frac{[-\delta]_{m}}{m!}(\frac{d}{(z-b)^{\alpha\beta}}\}^{m}(1$一 $\frac{c}{(z-b)^{\beta}}1^{\alpha\delta}$

(14)

$arrow((z-b)^{\beta}-c)^{a\delta}\sum_{\dot{m}-0}^{\infty}\frac{[-\delta]_{m}}{m!}(\frac{d}{((z-b)^{\beta}-c)^{\alpha}})^{m}$

(15)

$-((z-b)^{\beta}-c)^{\alpha\delta}$

$(1- \frac{d}{((z-b)^{\beta}-c)^{\alpha}})^{\delta}$

(16)

$-(((z-b)^{\beta}-c)^{\alpha}-d)^{\delta}$

,

(17)

dearly.

[IV]

When

$n-1$

,

we

have

$(((z-b)^{\beta}-c)^{\alpha}-d)^{\delta})_{1}--(z-b)^{a\beta\delta-1}$

$x\sum_{m.k-0}^{\infty}\frac{[-\delta]_{m}[-\alpha(\delta-m)]_{k}\cdot(\beta k-\alpha\beta\delta+a\beta m)}{m!\cdot k!}(\frac{c}{(z-b)^{\beta}})^{k}(\frac{d}{(z-b)^{a\beta}}I^{n}$

.

(18)

from Theorem

1.

$(ii)$

.

Then

lettig

$R:-( \frac{u}{(z-b)^{\beta}}I^{\alpha}$

$(u-(z-b)^{\beta}-c)$

(19)

and

(8)

we

have

$\sum_{m.k0}^{\infty}.\frac{[-\delta]_{m}[-\alpha(\delta-m)]_{k}\cdot\beta k}{m!\cdot k!}(\frac{c}{(z-b)^{\beta}}I^{k}(\frac{d}{(z-b)^{\alpha\beta}}I^{m}$

$- \frac{-c\alpha\beta\delta}{u}R^{\delta}S-\frac{cd\alpha\beta\delta}{u(u^{a}-d)}R^{\delta}S$

(21)

$- \alpha\beta\delta m\sum_{\triangleleft}^{\infty}\frac{[-\delta L[-\alpha.(\delta-m)]_{k}}{m!k!}(\frac{c}{(z-b)^{\beta}}I^{\iota}(\frac{d}{(z-b)^{a\beta}})^{m}$

$–a\beta\delta R^{\delta}S$

,

(22)

and

$\alpha\beta\sum_{m,k0}^{\infty}.\frac{[-\delta]_{m}\cdot m[-.\alpha(\delta-m)]_{k}}{m!k!}(\frac{c}{(z-b)^{\beta}})^{k}(\frac{d}{(z-b)^{\alpha\beta}}I^{m}$

$– \frac{da\beta\delta}{a}R^{\delta}S$

(23)

$(u-d)$

Therefore,

applying

(23), (22)

and

(21)

into

(18),

we

obtain

$(((z-b)^{\beta}-c)^{a}-d)^{\delta})_{1}-(z-b)^{\alpha\beta\delta-1}R^{\delta}S$

$x[\frac{ca\beta\delta}{u}+\frac{cda\beta\delta}{u(u^{a}-d)}+\alpha\beta\delta+\frac{da\beta\delta}{u^{a}-d}]$

(24)

$\approx a\beta\delta(z-b)^{\alpha\beta\delta-1}(\frac{c}{u}+1)(\frac{d}{u^{\alpha}-d}+\iota)$

(25)

(26)

$\simeq\alpha\beta\delta(z-b)^{-1}(u^{\alpha}-d)^{\delta}(\frac{(z-b)^{\beta}}{u}I\{\frac{u^{\alpha}}{u^{a}-d}I$

$-a\beta\delta(u^{\alpha}-d)^{\delta-1}(u^{\alpha-1})(z-b)^{\beta-1}$

(27)

$-\alpha\beta\delta(((z-b)^{\beta}-c)^{\alpha}-d)^{\delta-1}((z-b)^{\beta}-c)^{a-1}(z-b)^{\beta-1}$

(28)

clearly.

(9)

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Iwanami

Zensho,

(1957),

Iwanami, Japan.

Katsuyuki

Nishimoto

In

$s$

titute for Appled

Mathematics

Descartes Press

Co.

2-13-10

Kaguike,

KorIyama

963-8833

Japan

参照

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