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Volume 2008, Article ID 469725,7pages doi:10.1155/2008/469725

Research Article

AGQP-Injective Modules

Zhanmin Zhu1 and Xiaoxiang Zhang2

1Department of Mathematics, Jiaxing University, Jiaxing, Zhejiang 314001, China

2Department of Mathematics, Southeast University, Nanjing 210096, China

Correspondence should be addressed to Zhanmin Zhu,zhanmin [email protected] Received 23 December 2007; Revised 20 April 2008; Accepted 20 June 2008

Recommended by Robert Lowen

LetRbe a ring and letMbe a rightR-module withSEndMR.Mis called almost general quasi- principally injectiveor AGQP-injective for shortif, for any 0/sS, there exist a positive integern and a left idealXsnofSsuch thatsn/0 andlSKersn SsnXsn. Some characterizations and properties of AGQP-injective modules are given, and some properties of AGQP-injective modules with additional conditions are studied.

Copyrightq2008 Z. Zhu and X. Zhang. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

1. Introduction

Throughout R is an associative ring with identity, and all modules are unitary. Recall that a ring R is called right principally injective 1 or right P-injective for short if, every homomorphism from a principal right ideal ofRtoRcan be extended to an endomorphism ofR, or equivalently,lra Rafor allaR. The concept of right P-injective rings has been generalized by many authors. For example, in2,3, right P-injective rings are generalized in two directions, respectively. Following2, a ringRis called right GP-injective if, for any 0/aR, there exists a positive integernsuch thatan/0 and any rightR-homomorphism fromanR toR can be extended to an endomorphism ofR. Note that GP-injective rings are also called YJ-injective in 4. From 5, we know that GP-injective rings need not to be P- injective. Following3, a rightR-moduleMR withS EndMRis called quasiprincipally injective or QP-injective for short if, every homomorphism from anM-cyclic submodule of Mto M can be extended to an endomorphism ofM, or equivalently, lSKers Ss for allsS. In 1998, Page and Zhou 6 generalized the concept of GP-injective rings to that of AGP-injective rings. According to 6, a ring R is called right AGP-injective if, for any 0/aR, there exist a positive integer n and a left ideal Xan such that an/0 and lran RanXan. In7, the first author introduced the notion of GQP-injective modules which can be regarded as the generalization of GP-injective rings and QP-injective modules.

According to7, a rightR-moduleMwithS EndMRis called GQP-injective if, for any

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0/sS, there exists a positive integer nsuch thatsn/0 and any rightR-homomorphism from snM to M can be extended to an endomorphism of M, or equivalently, for any 0/sS, there exists a positive integer nsuch thatsn/0 andlSKersn Ssn. The nice structure of AGP-injective rings and GQP-injective modules draws our attention to define almost GQP-injective modules, in a similar way to AGP-injective rings, and to investigate their properties.

2. Results

Definition 2.1. LetMRbe a rightR-module withSEndMR. Then,Mis said to be almost general quasiprincipally injectivebriefly, AGQP-injectiveif, for any 0/sS, there exist a positive integernand a left idealXsn ofSsuch thatsn/0 andlSKersn SsnXsn.

Clearly, a ring R is right AGP-injective if and only if RR is AGQP-injective, GQP- injective modules are AGQP-injective.

Our next result gives the relationship between the AGQP-injectivity of a module and the AGP-injectivity of its endomorphism ring.

Theorem 2.2. LetMRbe a rightR-module withSEndMR. Then, 1ifSis right AGP-injective, thenMRis AGQP-injective;

2ifMR is AGQP-injective andMgenerates Kersfor eachsS, thenSis right AGP- injective.

Proof. 1Suppose thatSis right AGP-injective then for any 0/sS, there exist a positive integernand a left idealIsn ofSsuch thatsn/0 andlSrSsn SsnIsn. IfalSKersn andbrSsn, thensnb0, that is,bM⊆Kersn. Hence,abM0, that is,ab0. This shows thatlSKersnlSrSsn. Therefore, we haveSsnlSKersnSsnIsn, which guarantees that

lSKersn Ssn⊕lSKersnIsn. 2.1

Thus,1is proved.

2Suppose thatMR is AGQP-injective then for any 0/sS, there exist a positive integernand a left idealXsn ofSsuch thatsn/0 andlSKersn SsnXsn. Assume that alSrSsnand Kersn

t∈TtMfor some subsetT ofS. It is easy to see thatat0 for eachtT, so we haveax 0 for eachx∈Kersn. This implies thatlSrSsnlSKersn, from which we have

SsnlSrSsnlSKersn SsnXsn, 2.2

and hence

lSrSsn Ssn⊕lSrSsnXsn. 2.3 Therefore,Sis right AGP-injective.

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Recall that a moduleNis calledM-cyclic3, if it is a homomorphic image ofM. Let SEndMR, following8, we writeWS {s∈S |Kers⊆essM}.

Theorem 2.3. LetMRbe an AGQP-injective module withSEndMR. Then, 1WSJS,

2if every nonzero submodule ofMcontains a nonzeroM-cyclic submodule, thenWS JS.

Proof. 1LetsWS. Then, for eachtS,tsWSand so 1−ts /0. SinceMRis AGQP- injective, there exist a positive integernand a left ideal X1−tsn such that1−tsn/0 and lSKer1−tsn S1tsnX1−tsn. Note that1−tsn 1−ufor someuWS. Since Keru∩Ker1−u 0, we have Ker1−u 0, and thenSS1uX1−u. So 1exfor someeS1−uandxX1−u, it follows thate2eandS1−u Se⊕S1−e∩S1−u Se.

Therefore, 1−uvefor somevS, since Keruis essential inMR, ife /1, then there exists a nonzero element1−em∈1−eM∩Keru, and hence1−u1em 1−em. But 1−u1emve1em0, a contradiction. Soe1,and hence 1−uis left invertible, which impliessJS.

2We need only to prove that JSWS. Let sJS. Ifs /WS, then there exists 0/tSsuch that Kers∩tM 0 by hypothesis. Clearly,st /0 and Kerst Kert.

SinceMR is AGQP-injective, there exist a positive integernand a left idealXstn such that stn/0 and

lSKerstn SstnXstn. 2.4

If m ∈ Kerstn, then stn−1m ∈ Kerst Kert, and som ∈ Kertstn−1. This shows that Kerstn Kertstn−1. Hence, tstn−1SstnXstn. Write tstn−1 ustnv, whereuS, vXstn. Then1−uststn−1 v, which gives thatstn s1us−1vSstnXstn 0, a contradiction.

Corollary 2.4see6, Corollary 2.3. IfRis a right AGP-injective ring, thenJR ZRR. Following9, for a setX⊆HomNR, MR, the submodule

KerX∩{Kerg | gX} 2.5

ofN is called anM-annihilator submodule ofN. By7, Lemma 9andTheorem 2.3, we have the following corollary.

Corollary 2.5. Let MR be an AGQP-injective module with S EndMR. If every nonzero submodule ofM contains a nonzero M-cyclic submodule, andM/SocM satisfies ACC on M- annihilator submodules, thenJSis nilpotent.

Recall that a moduleMR is said to be a GC2 module10if every submoduleNM withNMis a direct summand ofM. For convenience, we writeN |Mto denote thatN is a direct summand ofM.

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Theorem 2.6. LetMRbe an AGQP-injective module. Then,

1if M1 and M2 are submodules ofM such that M1M2 and M1M2 | M, then M1|M. In particularMis a GC2 module;

2ifM1andM2are simple submodules ofMsuch thatM1M2|M, thenM1 |M.

Proof. 1LetSEndMR. It is trivial in caseM1 0. Now suppose thatM1/0 andM2f M1. ThenM1aMandM2 eM, wheree2eSandafe. SinceMRis AGQP-injective, there exist a positive integernand a left idealXansuch thatan/0 andlSKeran San⊕Xan. Leta0 e, thenf−1ai1M aiMi0,1, . . . , n−1sinceM1M2eM. So we have

aiM|ai−1M⇐⇒f−1ai1M|f−1aiM⇐⇒ai1M|aiM i1, . . . , n−1. 2.6

Consequently,aM | eMa2M | aM ⇔ · · · ⇔ anM | an−1M. Thus, to showaM | M, it suffices to show thatanM | M. Note thata|eM : eMeM is monic andanm anem for everymM,eM a

n

anMand hence Keran Kere. It follows thatelSKere lSKeran SanXan. Now, lete banxwith bS andxXan, then an ane anbananxanban. Finally, letganb, theng2 gandanMgMas required.

2Let M2 e1M, wheree21 e1S, and letM2 f1 M1. ThenM1 a1M, where a1 f1e1. SinceMRis AGQP-injective, there exist a positive integern1and a left idealXan1 1

such thatan11/0 andlSKeran11 San11⊕Xan1

1 . Note that 0/an11Ma1M,anda1Mis simple.

We havean11Ma1M. Clearly, Kere1 Kera1becausef1is a monomorphism. Sincea1M is simple, Kera1is a maximal submodule ofM. But Kera1⊆ Keran11/M, so Kera1

Keran11and then Kere1 Keran11. It follows thate1lSKere1 lSKeran11 San11Xan1

1 . Now, lete1 b1an11ywithb1SandyXan1

1 , thenan11 an11e1 an11b1an11an11y an11b1an11. Finally, letg1an11b1, theng12 g1andM1 a1Man11Mg1Mas required.

Recall that a moduleMis said to be weakly injective11if, for any finitely generated submoduleNEM, there existsXEMsuch thatNXM.

Corollary 2.7. LetMbe a finitely generated module. Then,Mis injective if and only ifMis weakly injective and AGQP-injective. In particular, a ringRis right self-injective if and only ifRRis weakly injective and AGP-injective.

Proof. We need only to prove the sufficiency. LetxEM. Then, there existsXEMsuch thatMxRXM. Hence,Xis AGQP-injective andM|Xfollows fromTheorem 2.61.

ButMis essential inEM, soMXand hencexM.

Corollary 2.8. LetMRbe an AGQP-injective module withSEndMR. 1IfMRis of finite Goldie dimension, then S is semilocal.

2IfMRis a noetherian self-generator, thenSis semiprimary.

Proof. 1SinceMR is AGQP-injective, it satisfies the GC2-condition byTheorem 2.61and then1follows immediately by12, Lemma 1.1.

2By1andCorollary 2.5.

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Recall that ifMandUare two rightR-modules, thenUis called M-projective in case for each epimorphismg : MRNR and each homomorphism γ : URNR, there is an R-homomorphismγ :URMRsuch thatγ gγ. A moduleMRis called quasiprojective if it isM-projective.

LetRbe a ring. Recall that an elementaRis calledπ-regular if there exists a positive integermsuch thatam ambam 13for somebR. An elementxRis called generalized π-regular if there exists a positive integer n such thatxn xnyx for some yR. A ring R is calledπ-regularresp., generalizedπ-regularif every element in Risπ-regularresp., generalizedπ-regular. IfAis a subset ofR, then we say thatAis regular if every element in Ais regular.

Proposition 2.9. LetMR be quasiprojective withS EndMR. Then,Sis regular if and only if MRis AGQP-injective andsMisM-projective for everysS.

Proof. Assume that S is regular. Then, every right ideal of S is a direct summand of SS, and so every homomorphism from a principal right ideal of S to S can be extended to an endomorphism of S. Hence, S is right P-injective and then right AGP-injective. By Theorem 2.2,MR is AGQP-injective. The regularity of Salso implies that sMis a direct summand ofMby14, Theorem 37.7. ButMis quasiprojective, sosMisM-projective for everysS.

Conversely, supposeMRis AGQP-injective andsMisM-projective for everysS.

Then for any 0/aS, by the AGQP-injectivity ofMR, there exist a positive integernand a left idealXan ofSsuch thatan/0 andlSKeran SanXan. SinceanMisM-projective, Keran eMfor somee2eS. Then, we haveS1−e lSeM lSKeran San⊕Xan, and so 1−ebanxfor somebSandxXan. Thus,anan1−e anbananxanban. This proves thatSisπ-regular and hence generalizedπ-regular. Clearly,N1S {0/aS | a2 0}is regularin this case,nmust be equal to 1. Therefore or,Sis regular by13, Theorem 2.2.

Recall that a moduleMRis called an IN-module15iflSA∩B lSA lSBfor any submodulesAandBofM, whereSEndMR.

Proposition 2.10. LetMRbe an AGQP-injective IN-module withSEndMR. Then,Sis regular if and only ifWS 0.

Proof. By Theorem 2.3, we need only to prove the sufficiency. Let 0/aS. Since MR is AGQP-injective, there exist a positive integernand a left idealXan ofSsuch thatan/0 and lSKeran SanXan. SinceWS 0, Keranis not essential inMand then there exists a nonzero submoduleKsuch that KeranKis essential inM. Moveover, we also have

lSKeran lSK lSKeranK S,

lSKeranlSK⊆lSKeran K 0, 2.7

becauseMRis an IN-module andWS 0. Thus,

SlSKeranlSK SanXanlSK. 2.8

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Let 1banxwithbS,xXanlSK, thenananban. It follows thatSis regular by the last part of the proof ofProposition 2.9.

Lemma 2.11. LetMRbe an AGQP-injective module in which every nonzero submodule contains a nonzeroM-cyclic submodule andSEndMR. Ifs /WS, then the inclusion Kers⊆Kers− stsis strict for sometS.

Proof. Ifs /WS, then Kers∩K0 for some nonzero submoduleKofM, and so KerssM 0 for some 0/sSby hypothesis. Clearly, ss/0. Since MR is AGQP-injective, there exist a positive integernand a left idealXssn such thatssn/0 andlSKerssn SssnXssn. Thus,

sssn−1lSKersssn−1 lSKerssn SssnXssn. 2.9

Writesssn−1 tssnx,wheretSandxXssn, then1−tssssn−1xand hence 1−stssn s−stssssn−1sxSssnXssn. 2.10 This means thats−stssssn−1 0. It is obvious that Kers ⊆ Kers−sts. Note that sssn−1Mis contained in Kers−stsbut not contained in Kers, the inclusion Kers⊆ Kers−stsis strict.

Theorem 2.12. LetMR be AGQP-injective withSEndMR. If every nonzero submodule ofM contains a nonzeroM-cyclic submodule, then the following conditions are equivalent:

1Sis right perfect;

2for any sequence{s1, s2, . . .} ⊆S, the chain Kers1⊆Kers2s1⊆ · · · terminates.

Proof. ByTheorem 2.3,Lemma 2.11, and 16, Lemma 2.8, one can complete the proof in a similar way to that of16, Theorem 2.9.

Acknowledgment

The authors are very grateful to the referees for their useful comments and suggestions.

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2 S. B. Nam, N. K. Kim, and J. Y. Kim, “On simple GP-injective modules,” Communications in Algebra, vol. 23, no. 14, pp. 5437–5444, 1995.

3 N. V. Sanh, K. P. Shum, S. Dhompongsa, and S. Wongwai, “On quasi-principally injective modules,”

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