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1.Introduction YuanyingJiang andQunyingWu TheAlmostSureLocalCentralLimitTheoremfortheNegativelyAssociatedSequences ResearchArticle

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Volume 2013, Article ID 656257,9pages http://dx.doi.org/10.1155/2013/656257

Research Article

The Almost Sure Local Central Limit Theorem for the Negatively Associated Sequences

Yuanying Jiang

1,2

and Qunying Wu

1

1College of Science, Guilin University of Technology, Guilin 541004, China

2School of Statistics, Renmin University of China, Beijing 100872, China

Correspondence should be addressed to Yuanying Jiang; [email protected] Received 13 May 2013; Accepted 18 June 2013

Academic Editor: Ying Hu

Copyright © 2013 Y. Jiang and Q. Wu. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

In this paper, the almost sure central limit theorem is established for sequences of negatively associated random variables:

lim𝑛 → ∞(1/log𝑛) ∑𝑛𝑘=1(𝐼(𝑎𝑘≤ 𝑆𝑘< 𝑏𝑘)/𝑘)𝑃(𝑎𝑘≤ 𝑆𝑘< 𝑏𝑘) = 1, almost surely. This is the local almost sure central limit theorem for negatively associated sequences similar to results by Cs´aki et al. (1993). The results extend those on almost sure local central limit theorems from the i.i.d. case to the stationary negatively associated sequences.

1. Introduction

Definition 1. Random variables 𝑋1, 𝑋2, . . . , 𝑋𝑛, 𝑛 ≥ 2are said to be negatively associated (NA) if for every pair of disjoint subsets𝐴1and𝐴2of{1, 2, . . . , 𝑛},

Cov(𝑓1(𝑋𝑖, 𝑖 ∈ 𝐴1) , 𝑓2(𝑋𝑗, 𝑗 ∈ 𝐴2)) ≤ 0, (1) where𝑓1and𝑓2are increasing for every variable (or decreas- ing for every variable) such that this covariance exists. A sequence of random variables{𝑋𝑖, 𝑖 ≥ 1}is said to be NA if every finite subfamily of{𝑋𝑖, 𝑖 ≥ 1}is NA.

Obviously, if {𝑋𝑖, 𝑖 ≥ 1} is a sequence of NA random variables and {𝑓𝑖, 𝑖 ≥ 1} is a sequence of nondecreasing (or nonincreasing) functions, then{𝑓𝑖(𝑋𝑖), 𝑖 ≥ 1}is also a sequence of NA random variables.

This definition was introduced by the Joag-Dev and Proschan [1]. Statistical test depends greatly on sampling, and the random sampling without replacement from a finite population is NA, but it is not independent. NA sampling has wide applications such as those in multivariate statistical analysis and reliability theory. Because of the wide applica- tions of NA sampling, the notions of NA random variables have received more and more attention recently. We refer to Joag-Dev and Proschan [1] for fundamental properties, Shao

[2] for the moment inequalities, and Wu and Jiang [3] for Chover’s law of the iterated logarithm.

Assume that{𝑋𝑛, 𝑛 ≥ 1}is a strictly stationary sequence of NA random variables with𝐸𝑋1= 0, 0 < 𝐸𝑋21< ∞. Define 𝑆𝑛= ∑𝑛𝑗=1𝑋𝑗,

𝜎2𝑛:=Var𝑆𝑛, (2)

𝜎2:=Var𝑋1+ 2∑

𝑗=2

Cov(𝑋1, 𝑋𝑗) . (3)

(1) Newman [4] and Matuła [5] showed that NA station- ary sequences satisfy the central limit theorem (CLT) under𝜎2> 0, that is,

sup𝑥∈𝑅

󵄨󵄨󵄨󵄨󵄨󵄨󵄨󵄨𝑃(𝑆𝑛

𝜎𝑛 < 𝑥) − Φ (𝑥)󵄨󵄨󵄨󵄨󵄨󵄨󵄨󵄨 = 𝑜(1). (4) (2) Applying Matuła [6] and Wu’s [7] methods, we can easily show that NA sequences satisfy the almost sure central limit theorem (ASCLT), that is,

𝑛 → ∞lim 1 log𝑛

𝑛 𝑘=1

1

𝑘𝐼 { 𝑆𝑘 ≤ 𝑥𝜎𝑘1/2} = Φ (𝑥) a.s. ∀𝑥 ∈R, (5) whereΦ(𝑥)is the standard normal distribution func- tion and𝐼{𝐴}denotes the indicator of the event𝐴.

(2)

The ASCLT was stimulated by Brosamler [8] and Schatte [9]. Both were concerned with the partial sum of independent and identically distributed (i.i.d.) random variables with more than the second moment. The ASCLT was extensively studied in the past two decades and an interesting direction of the study is to prove it for dependent variables. There are some results for weakly dependent variables such as𝛼, 𝜌, 𝜙-mixing and associated random variables. Among those results, we refer to Peligrad and Shao [10], Matuła [11], and Wu [7].

More general version of ASCLT was proved by Cs´aki et al.

[12]. The following theorem is due to them.

Theorem A. Let {𝑋𝑛, 𝑛 ≥ 1}be a sequence of i.i.d. random variables with𝐸|𝑋1|3< ∞, let𝐸𝑋1= 0.𝑎𝑘, 𝑏𝑘satisfy

−∞ ≤ 𝑎𝑘≤ 0 ≤ 𝑏𝑘≤ ∞, 𝑘 = 1, 2, . . . , (6) and assume that

𝑛 𝑘=1

log𝑘

𝑘3/2𝑃 (𝑎𝑘≤ 𝑆𝑘< 𝑏𝑘) = 𝑂 (log𝑛) , 𝑎𝑠 𝑛 󳨀→ ∞, (7) and then

𝑛 → ∞lim 1 log𝑛

𝑛 𝑘=1

𝐼 {𝑎𝑘≤ 𝑆𝑘 < 𝑏𝑘}

𝑘𝑃 (𝑎𝑘 ≤ 𝑆𝑘< 𝑏𝑘)= 1 a.s. (8) This result may be called almost sure local central limit theorem, while (5) may be called almost sure global central limit theorem. Hurelbaatar [13] extended (8) to the case of𝜌- mixing sequences and Weng et al. [14] derived an almost sure local central limit theorem for the product of partial sums of a sequence of i.i.d. positive random variables under some regular conditions. For more details, we refer to Berkes and Cs´aki [15] and F¨oldes [16].

Our concern in this paper is to give a common general- ization of (8) to the case of NA sequences.

In the next section we present the exact results, postpon- ing some technical lemmas and the proofs toSection 3.

2. Main Results

Assume in the following that {𝑋𝑛, 𝑛 ≥ 1} is a strictly stationary sequence of NA random variables with𝐸𝑋1 = 0, 0 < 𝐸𝑋21 < ∞. We consider the limit behavior of the logarithmic average

𝑛 → ∞lim 1 log𝑛

𝑛 𝑘=1

𝐼 {𝑎𝑘 ≤ 𝑆𝑘< 𝑏𝑘}

𝑘𝑃 (𝑎𝑘≤ 𝑆𝑘< 𝑏𝑘) (9) with−∞ ≤ 𝑎𝑘 ≤ 0 ≤ 𝑏𝑘 ≤ ∞, where the terms in the sum above are defined to be1if their denominator happens to be 0.

More precisely let {𝑎𝑛, 𝑛 ≥ 1} and{𝑏𝑛, 𝑛 ≥ 1} be two sequences of real numbers and put

𝑝𝑘:= 𝑃 (𝑎𝑘≤ 𝑆𝑘< 𝑏𝑘) ,

𝛼𝑘:={{ {{ {

𝐼 {𝑎𝑘≤ 𝑆𝑘< 𝑏𝑘}

𝑝𝑘 , if 𝑝𝑘 ̸= 0,

1, if 𝑝𝑘= 0.

(10)

So we need to investigate the limit behavior of 𝜇𝑛:=∑𝑛

𝑘=1

𝛼𝑘

𝑘 (11)

under certain conditions.

In our considerations, we will need the following Cox- Grimmett coefficient which describes the covariance struc- ture of the sequence

𝑢 (𝑛) := sup

𝑘∈𝑁

𝑗:|𝑗−𝑘|≥𝑛󵄨󵄨󵄨󵄨󵄨Cov(𝑋𝑗, 𝑋𝑘)󵄨󵄨󵄨󵄨󵄨, 𝑛 ∈ 𝑁 ∪ {0}. (12) We remark that for a stationary sequence of NA random variables

𝑢 (𝑛) = −2 ∑

𝑘=𝑛+1

Cov(𝑋1, 𝑋𝑘) , 𝑛 ∈ 𝑁. (13) By Lemma 8 of Newman [4], we have 𝑢(0) < ∞ and lim𝑛 → ∞𝑢(𝑛) = 0.

In the following,𝜉𝑛 ∼ 𝜂𝑛denotes𝜉𝑛/𝜂𝑛 → 1, 𝑛 → ∞.

𝜉𝑛 = 𝑂(𝜂𝑛)denotes that there exists a constant𝑐 > 0such that𝜉𝑛 ≤ 𝑐𝜂𝑛for sufficiently large𝑛. The symbols𝑐, 𝑐1, 𝑐2, . . ., stand for generic positive constants which may differ from one place to another.

Theorem 2. Let{𝑋𝑛, 𝑛 ≥ 1}be a strictly stationary sequence of NA random variables with𝐸𝑋1 = 0, 𝐸|𝑋1|3 < ∞and let 𝜎2> 0. 𝑎𝑘, 𝑏𝑘satisfy(6). Assume that

𝑛=1𝑢 (𝑛) < ∞, (14)

and for some𝛽 > 1,

1≤𝑘≤𝑛 𝑝𝑘 ̸= 0

(log𝑘)1/3

𝑘𝑝𝑘 = 𝑂 ((log𝑛)2(log log𝑛)−𝛽) . (15)

Then we have

𝑛 → ∞lim 𝜇𝑛

log𝑛= 1, a.s., (16)

where𝜇𝑛is defined by(11).

Remark 3. Let𝑎𝑘 = −∞and𝑏𝑘= 𝑥𝜎𝑘1/2in (6). By the central limit theorem (4), we have𝑝𝑘 = 𝑃(𝑆𝑘/𝜎𝑘1/2 < 𝑥) → Φ(𝑥), obviously (15) satisfies; then (16) becomes (5), which is the almost sure global central limit theorem. Thus the almost sure local central limit theorem is a general result which contains the almost sure global central limit theorem.

Remark 4. The condition (15) is satisfied with a wide range of 𝑝𝑘; for example, if

𝑝𝑘= 0 or 𝑝𝑘≥ 𝑐(log log𝑘)𝛽

(log𝑘)2/3 (17)

(3)

holds, then the condition (15) is satisfied. In fact, letting0 <

𝛿 < 1, we have

1≤𝑘≤𝑛 𝑝𝑘 ̸= 0

(log𝑘)1/3 𝑘𝑝𝑘

≤ 𝑐 ∑

1≤𝑘≤𝑛

(log log𝑘)−𝛽(log𝑘)𝛿(log𝑘)1−𝛿 𝑘

≤ 𝑐(log log𝑛)−𝛽(log𝑛)𝛿

1≤𝑘≤𝑛

(log𝑘)1−𝛿 𝑘

≤ 𝑐(log log𝑛)−𝛽(log𝑛)2

= 𝑂 ((log𝑛)2(log log𝑛)−𝛽) .

(18)

In the given theorem below, we strengthen the condition (6) on𝑎𝑘and𝑏𝑘. Meanwhile, as a compensation, we do not need to impose restricting condition (15) on𝑝𝑘.

Theorem 5. Let{𝑋𝑛, 𝑛 ≥ 1}be a strictly stationary sequence of NA random variables with𝐸𝑋1= 0, 𝐸|𝑋1|3< ∞, and𝜎2> 0, and let𝑎𝑘and𝑏𝑘satisfy

−𝑐1𝑘1/2−𝛼≤ 𝑎𝑘≤ −𝑐2𝑘1/2−𝛼,

𝑐3𝑘1/2−𝛼≤ 𝑏𝑘 ≤ 𝑐4𝑘1/2−𝛼, (19) where0 < 𝛼 < 1/7. Assume that(14)hold, and then we have (16).

3. Proofs

The following lemmas play important roles in the proof of our theorems. The proofs are given in the Appendix.

Lemma 6. Assume that{𝜉𝑛, 𝑛 ≥ 1}are random variables such that

𝜉𝑘 ≥ 0, 𝐸𝜉𝑘= 1, 𝑘 = 1, 2, . . . (20) and furthermore there exists𝑑𝑘 ≥ 0such that𝐷𝑛= ∑𝑛𝑘=1𝑑𝑘

∞, 𝐷𝑛/𝐷𝑛−1 → 1, and Var(∑𝑛

𝑘=1

𝑑𝑘𝜉𝑘) ≤ 𝑐𝐷2𝑛(log𝐷𝑛)−𝛽, (21)

with some𝛽 > 1and positive constant𝑐, and then

𝑛 → ∞lim 1 𝐷𝑛

𝑛 𝑘=1

𝑑𝑘𝜉𝑘= 1 a.s. (22) Remark 7. Let𝑑𝑘 = 1/𝑘in (21), and then𝐷𝑛 = ∑𝑛𝑘=11/𝑘 ∼ log𝑛. Thus, if

Var(∑𝑛

𝑘=1

1

𝑘𝜉𝑘) ≤ 𝑐(log𝑛)2(log log𝑛)−𝛽, (23)

with some𝛽 > 1and positive constant𝑐, then

𝑛 → ∞lim 1 log𝑛

𝑛 𝑘=1

1

𝑘𝜉𝑘= 1 a.s. (24) The followingLemma 8is obvious.

Lemma 8. Assume that the nonnegative random sequence {𝜉𝑛, 𝑛 ≥ 1}satisfies(24)and the sequence{𝜂𝑛, 𝑛 ≥ 1}is such that, for any𝜀 > 0, there exists a𝑘0= 𝑘0(𝜀, 𝜔)for which

(1 − 𝜀) 𝜉𝑘 ≤ 𝜂𝑘≤ (1 + 𝜀) 𝜉𝑘, 𝑘 > 𝑘0. (25) Then we have also

𝑛 → ∞lim 1 log𝑛

𝑛 𝑘=1

1

𝑘𝜂𝑘 = 1 a.s. (26) The followingLemma 9is an easy corollary to the Corol- lary 2.2 in Matuła [5] under strictly stationary condition, which studies the rate of convergence in the CLT under neg- ative dependence. It was also studied in Pan [17]. Of course this is the Berry-Esseen inequality for the NA sequence.

Lemma 9. Let{𝑋𝑗, 𝑗 ∈ 𝑁}be a strictly stationary sequence of NA random variables with𝐸𝑋1 = 0, 𝐸|𝑋1|3 < ∞, 𝜎2 > 0 satisfying(14). Then one has

sup𝑥∈𝑅

󵄨󵄨󵄨󵄨󵄨󵄨󵄨󵄨𝑃(𝑆𝑛

𝜎𝑛 < 𝑥) − Φ (𝑥)󵄨󵄨󵄨󵄨

󵄨󵄨󵄨󵄨 = 𝑂(𝑛−1/5) . (27) Lemma 10. If the conditions ofLemma 9hold,𝑎𝑘and𝑏𝑘satisfy (19). Then one has

𝑐1󸀠𝑘−𝛼 ≤ 𝑝𝑘≤ 𝑐2󸀠𝑘−𝛼 (𝑘 ≥ 𝑘0) , (28) where𝛼is as(19).

Lemma 11. If the conditions ofLemma 9hold,𝑎𝑘and𝑏𝑘satisfy (19), and 𝛼is as(19). Assume that𝜀𝑙 = 𝑙3𝛼/2, and then the following asymptotic relations hold:

1≤𝑘<𝑙≤𝑛 𝑘<𝑙−𝑙𝛼

1

𝑘𝑙𝑝𝑙𝑃 (󵄨󵄨󵄨󵄨𝑆𝑙𝛼󵄨󵄨󵄨󵄨 ≥ 𝜀𝑙) = 𝑂 (log𝑛) , (29)

1≤𝑘<𝑙≤𝑛 𝑘<𝑙−𝑙𝛼

1 𝑘𝑙𝑝𝑙

1

(𝑙 − 𝑘 − 𝑙𝛼)1/5 = 𝑂 (log𝑛) , (30)

1≤𝑘<𝑙≤𝑛 𝑘<𝑙−𝑙𝛼

1

𝑘𝑙𝑝𝑙󵄨󵄨󵄨󵄨󵄨󵄨󵄨󵄨󵄨Φ ( 𝑎𝑙− 𝑏𝑘− 𝜀𝑙

(𝑙 − 𝑘 − 𝑙𝛼)1/2) − Φ ( 𝑎𝑙 𝑙1/2)󵄨󵄨󵄨󵄨󵄨󵄨󵄨󵄨󵄨

= 𝑂 (log𝑛) ,

(31)

1≤𝑘<𝑙≤𝑛 𝑘<𝑙−𝑙𝛼

1

𝑘𝑙𝑝𝑙󵄨󵄨󵄨󵄨󵄨󵄨󵄨󵄨󵄨(Φ ( 𝑏𝑙− 𝑎𝑘+ 𝜀𝑙

(𝑙 − 𝑘 − 𝑙𝛼)1/2) − Φ ( 𝑏𝑙 𝑙1/2))󵄨󵄨󵄨󵄨󵄨󵄨󵄨󵄨󵄨

= 𝑂 (log𝑛) .

(32)

(4)

The main point in our proof is to verify the condition (23).

We use global central limit theorem with remainders and the following elementary inequalities:

󵄨󵄨󵄨󵄨Φ(𝑥) − Φ(𝑦)󵄨󵄨󵄨󵄨 ≤ 𝑐󵄨󵄨󵄨󵄨𝑥 − 𝑦󵄨󵄨󵄨󵄨, for every𝑥, 𝑦 ∈R (33) with some constant𝑐. Moreover, for each𝑘 > 0, there exists 𝑐1= 𝑐1(𝑘), such that

󵄨󵄨󵄨󵄨Φ(𝑥) − Φ(𝑦)󵄨󵄨󵄨󵄨

≥ 𝑐1󵄨󵄨󵄨󵄨𝑥 − 𝑦󵄨󵄨󵄨󵄨, for every𝑥, 𝑦 ∈R, |𝑥| + 󵄨󵄨󵄨󵄨𝑦󵄨󵄨󵄨󵄨 ≤ 𝑘. (34) Let{𝑋𝑛, 𝑛 ≥ 1}be a strictly stationary sequence of NA random variables with𝜎2 > 0; we can immediately get𝜎𝑛2 ∼ 𝑛𝜎2, that is,

𝑐1𝑛 ≤Var(𝑆𝑛) = 𝜎𝑛2≤ 𝑐2𝑛 (35) for some constant𝑐1, 𝑐2> 0and sufficiently large𝑛.

Proof ofTheorem 2. First assume that

𝑏𝑘− 𝑎𝑘≤ 𝑐𝑘1/2, 𝑘 = 1, 2, . . . (36) with some constant𝑐. Let1 ≤ 𝑘 < 𝑙and𝜀𝑘 = 𝑘1/2(log𝑘)1/3.

If either𝑝𝑘 = 0or𝑝𝑙= 0, then obviously Cov(𝛼𝑘, 𝛼𝑙) = 0, and so we may assume that𝑝𝑘𝑝𝑙 ̸= 0; then, we have

Cov(𝛼𝑘, 𝛼𝑙)

= 1

𝑝𝑙𝑝𝑘(𝑃 (𝑎𝑘≤ 𝑆𝑘 < 𝑏𝑘, 𝑎𝑙≤ 𝑆𝑙< 𝑏𝑙) − 𝑝𝑙𝑝𝑘)

≤ 1

𝑝𝑙𝑝𝑘(𝑃 (𝑎𝑙− 𝑏𝑘≤ 𝑆𝑙− 𝑆𝑘< 𝑏𝑙 − 𝑎𝑘, 𝑎𝑘≤ 𝑆𝑘< 𝑏𝑘) − 𝑝𝑙𝑝𝑘)

≤ 1

𝑝𝑙𝑝𝑘(𝑃 (𝑎𝑙− 𝑏𝑘≤ 𝑆𝑙− 𝑆𝑘< 𝑏𝑙− 𝑎𝑘)

×𝑃 (𝑎𝑘≤ 𝑆𝑘< 𝑏𝑘) − 𝑝𝑙𝑝𝑘)

= 1

𝑝𝑙(𝑃 (𝑎𝑙− 𝑏𝑘 ≤ 𝑆𝑙− 𝑆𝑘< 𝑏𝑙− 𝑎𝑘) − 𝑝𝑙)

≤ 1

𝑝𝑙(𝑃 (𝑎𝑙− 𝑏𝑘− 𝜀𝑘< 𝑆𝑙< 𝑏𝑙− 𝑎𝑘+ 𝜀𝑘)

−𝑝𝑙+ 𝑃 (󵄨󵄨󵄨󵄨𝑆𝑘󵄨󵄨󵄨󵄨 ≥ 𝜀𝑘))

≤ 1

𝑝𝑙(𝑃 (𝑎𝑙− 𝑏𝑘− 𝜀𝑘≤ 𝑆𝑙< 𝑎l)

+ 𝑃 (𝑏𝑙≤ 𝑆𝑙< 𝑏𝑙− 𝑎𝑘+ 𝜀𝑘) +𝑃 (󵄨󵄨󵄨󵄨𝑆𝑘󵄨󵄨󵄨󵄨 ≥ 𝜀𝑘)) . (37)

ApplyingLemma 9, (33), (35), and (36) and noting that 𝜀𝑘= 𝑘1/2(log𝑘)1/3, we obtain

𝑃 (𝑎𝑙− 𝑏𝑘− 𝜀𝑘 ≤ 𝑆𝑙< 𝑎𝑙) + 𝑃 (𝑏𝑙≤ 𝑆𝑙< 𝑏𝑙− 𝑎𝑘+ 𝜀𝑘)

≤ (Φ (𝑎𝑙

𝜎𝑙) − Φ (𝑎𝑙− 𝑏𝑘− 𝜀𝑘 𝜎𝑙 )) + (Φ (𝑏𝑙− 𝑎𝑘+ 𝜀𝑘

𝜎𝑙 ) − Φ (𝑏𝑙

𝜎𝑙)) + 𝑐 1 𝑙1/5

≤ 𝑏𝑘+ 𝜀𝑘

𝜎𝑙 +−𝑎𝑘+ 𝜀𝑘 𝜎𝑙 + 𝑐 1

𝑙1/5 = 𝑏𝑘− 𝑎𝑘 𝜎𝑙 +2𝜀𝑘

𝜎𝑙 + 𝑐 1 𝑙1/5

≤ 𝑐 (𝑘1/2 𝑙1/2 + 𝜀𝑘

𝑙1/2 + 1

𝑙1/5) ≤ 𝑐 (𝑘1/2(log𝑘)1/3 𝑙1/2 + 1

𝑙1/5) . (38) By the condition of (15), we have

𝑛 𝑙=1

𝑙 𝑘=1

1 𝑘𝑙𝑝𝑙

𝑘1/2(log𝑘)1/3 𝑙1/2

≤∑𝑛

𝑙=1

1 𝑙3/2𝑝𝑙

𝑙 𝑘=1

(log𝑘)1/3 𝑘1/2

≤ 𝑐∑𝑛

𝑙=1

(log𝑙)1/3 𝑙3/2𝑝𝑙

𝑙 𝑘=1

1 𝑘1/2 ≤ 𝑐∑𝑛

𝑙=1

(log𝑙)1/3 𝑙3/2𝑝𝑙 𝑙1/2

≤ 𝑐∑𝑛

𝑙=1

(log𝑙)1/3

𝑙𝑝𝑙 = 𝑂 ((log𝑛)2(log log𝑛)−𝛽) ,

𝑛 𝑙=1

𝑙−1

𝑘=1

1 𝑘𝑙𝑝𝑙

1 𝑙1/5

=∑𝑛

𝑙=1

1 𝑙6/5𝑝𝑙

𝑙−1

𝑘=1

1 𝑘 ≤ 𝑐∑𝑛

𝑙=1

1 𝑙6/5𝑝𝑙log𝑙

≤ 𝑐∑𝑛

𝑙=1

(log𝑙)1/3

𝑙𝑝𝑙 = 𝑂 ((log𝑛)2(log log𝑛)−𝛽) . (39)

By Chebyshev’s inequality and the condition of (15) and (35), we obtain

𝑛 𝑙=1

𝑙 𝑘=1

1

𝑘𝑙𝑝𝑙𝑃 (󵄨󵄨󵄨󵄨𝑆𝑘󵄨󵄨󵄨󵄨 ≥ 𝜀𝑘)

≤∑𝑛

𝑙=1

1 𝑙𝑝𝑙

𝑙 𝑘=1

Var(𝑆𝑘) 𝑘𝜀2𝑘 ≤ 𝑐∑𝑛

𝑙=1

1 𝑙𝑝𝑙

𝑙 𝑘=1

1 𝑘(log𝑘)2/3

≤ 𝑐∑𝑛

𝑙=1

(log𝑙)1/3

𝑙𝑝𝑙 = 𝑂 ((log𝑛)2(log log𝑛)−𝛽) . (40)

Hence (37)–(40) imply that

𝑛 𝑙=1

𝑙−1 𝑘=1

Cov(𝛼𝑘, 𝛼𝑙)

𝑘𝑙 = 𝑂 ((log𝑛)2(log log𝑛)−𝛽) . (41)

(5)

But Var(𝛼𝑘) = 0if𝑝𝑘= 0and Var(𝛼𝑘) =1 − 𝑝𝑘

𝑝𝑘 ≤ 1

𝑝𝑘 if𝑝𝑘 ̸= 0. (42) Thus

𝑛 𝑘=1

Var(𝛼𝑘) 𝑘2

≤ ∑

1≤𝑘≤𝑛 𝑝𝑘 ̸= 0

1

𝑘2𝑝𝑘 ≤ ∑

1≤𝑘≤𝑛 𝑝𝑘 ̸= 0

(log𝑘)1/3 𝑘𝑝𝑘

= 𝑂 ((log𝑛)2(log log𝑛)−𝛽) .

(43)

Equations (41) and (43) together imply that Var(∑𝑛

𝑘=1

𝛼𝑘

𝑘) = 𝑂 ((log𝑛)2(log log𝑛)−𝛽) , as𝑛 → ∞.

(44) Hence applyingRemark 7, our theorem is proved under the restricting condition (36).

Now we drop the restricting condition (36). Fix𝑥 > 0and define

̃𝑎𝑘=max(𝑎𝑘, −𝑥𝜎𝑘1/2) ,

̃𝑏𝑘=min(𝑏𝑘, 𝑥𝜎𝑘1/2) ,

̃𝑝𝑘 = 𝑃 (̃𝑎𝑘≤ 𝑆𝑘< ̃𝑏𝑘) ,

(45)

where𝜎is defined by (3).

Clearly ̃𝑝𝑘 ≤ 𝑝𝑘, and so assuming ̃𝑝𝑘 ̸= 0; then, also we have𝑝𝑘 ̸= 0, and thus

𝛼𝑘= 1

𝑝𝑘𝐼 {𝑎𝑘 ≤ 𝑆𝑘 < 𝑏𝑘}

= 1

𝑝𝑘(𝐼 {̃𝑎𝑘≤ 𝑆𝑘 < ̃𝑏𝑘}

+𝐼 {𝑎𝑘≤ 𝑆𝑘< ̃𝑎𝑘} + 𝐼 {̃𝑏𝑘≤ 𝑆𝑘< 𝑏𝑘})

≤ 1

̃𝑝𝑘𝐼 {̃𝑎𝑘≤ 𝑆𝑘 < ̃𝑏𝑘} + 1

𝑝𝑘 (𝐼 {𝑎𝑘≤ 𝑆𝑘< ̃𝑎𝑘} + 𝐼 {̃𝑏𝑘 ≤ 𝑆𝑘 < 𝑏𝑘})

≤ 1

̃𝑝𝑘𝐼 {̃𝑎𝑘≤ 𝑆𝑘 < ̃𝑏𝑘} + 𝐼 { 𝑆𝑘< −𝑥𝜎𝑘1/2}

𝑃 (−𝑥𝜎𝑘1/2≤ 𝑆𝑘< 0)+ 𝐼 { 𝑆𝑘≥ 𝑥𝜎𝑘1/2} 𝑃 (0 ≤ 𝑆𝑘 < 𝑥𝜎𝑘1/2).

(46)

By (35) and the central limit theorem for NA random variables (4), that is,

sup𝑥∈𝑅

󵄨󵄨󵄨󵄨󵄨󵄨󵄨󵄨𝑃(𝑆𝑛

𝜎𝑛 < 𝑥) − Φ (𝑥)󵄨󵄨󵄨󵄨󵄨󵄨󵄨󵄨 = 𝑜(1), (47)

we obtain

𝑘 → ∞lim𝑃 (−𝑥𝜎𝑘1/2≤ 𝑆𝑘< 0)

= lim

𝑘 → ∞𝑃 (−𝑥𝜎𝑘≤ 𝑆𝑘< 0) = Φ (0) − Φ (−𝑥) ,

𝑘 → ∞lim𝑃 (0 ≤ 𝑆𝑘< 𝑥𝜎𝑘1/2)

= lim

𝑘 → ∞𝑃 (0 ≤ 𝑆𝑘< 𝑥𝜎𝑘) = Φ (𝑥) − Φ (0) .

(48)

Applying the almost sure central limit theorem for NA random variables (5), that is,

𝑛 → ∞lim 1 log𝑛

𝑛 𝑘=1

1

𝑘𝐼 {𝑆𝑘≤ 𝑥𝜎𝑘1/2} = Φ (𝑥) a.s. ∀𝑥 ∈R, (49) Lemma 8, and (48), we have

𝑛 → ∞lim 1 log𝑛

𝑛 𝑘=1

𝐼 { 𝑆𝑘< −𝑥𝜎𝑘1/2} 𝑘𝑃 (−𝑥𝜎𝑘1/2≤ 𝑆𝑘< 0)

= Φ (−𝑥)

Φ (0) − Φ (−𝑥) a.s.,

𝑛 → ∞lim 1 log𝑛

𝑛 𝑘=1

𝐼 { 𝑆𝑘> 𝑥𝜎𝑘1/2} 𝑘𝑃 (0 ≤ 𝑆𝑘 < 𝑥𝜎𝑘1/2)

= 1 − Φ (𝑥) Φ (𝑥) − Φ (0) a.s.

(50)

Sincẽ𝑎𝑘and̃𝑏𝑘satisfy (36), we get

𝑛 → ∞lim 1 log𝑛

𝑛 𝑘=1

̃𝛼𝑘

𝑘 = 1 a.s., (51)

where

̃𝛼𝑘={{ {{ {

𝐼 {̃𝑎𝑘≤ 𝑆𝑘< ̃𝑏𝑘}

̃𝑝𝑘 , if ̃𝑝𝑘 ̸= 0,

1, if ̃𝑝𝑘 = 0.

(52)

Equations (46) and (50)–(51) together imply that lim sup

𝑛 → ∞

1 log𝑛

𝑛 𝑘=1

𝛼𝑘

𝑘 ≤ 1 + 2 1 − Φ (𝑥)

Φ (𝑥) − Φ (0) a.s. (53) On the other hand, if̃𝑝𝑘 ̸= 0, then we have

1

𝑝𝑘𝐼 {𝑎𝑘≤ 𝑆𝑘< 𝑏𝑘}

≥ 1

̃𝑝𝑘𝐼 {̃𝑎𝑘 ≤ 𝑆𝑘< ̃𝑏𝑘} (1 −𝑝𝑘− ̃𝑝𝑘 𝑝𝑘 )

≥ ̃𝛼𝑘(1 − 𝑃 (𝑆𝑘< −𝜎𝑥𝑘1/2) + 𝑃 (𝑆𝑘> 𝜎𝑥𝑘1/2) min{𝑃 (0 ≤ 𝑆𝑘 < 𝜎𝑥𝑘1/2) , 𝑃 (−𝜎𝑥𝑘1/2≤ 𝑆𝑘< 0)}),

(54)

(6)

and by the central limit theorem,

𝑘 → ∞lim

𝑃 (𝑆𝑘< −𝜎𝑥𝑘1/2) + 𝑃 (𝑆𝑘> 𝜎𝑥𝑘1/2) min{𝑃 (0 ≤ 𝑆𝑘< 𝜎𝑥𝑘1/2) , 𝑃 (−𝜎𝑥𝑘1/2≤ 𝑆𝑘 < 0)}

= 1 − 2 1 − Φ (𝑥) Φ (𝑥) − Φ (0).

(55) ApplyingLemma 8, (51) and (54) imply that

lim inf𝑛 → ∞ 1 log𝑛

𝑛 𝑘=1

𝛼𝑘

𝑘 ≥ 1 − 2 1 − Φ (𝑥)

Φ (𝑥) − Φ (0) a.s., (56) and hence

1 + 2 1 − Φ (𝑥)

Φ (𝑥) − Φ (0) ≥lim sup

𝑛 → ∞

1 log𝑛

𝑛 𝑘=1

𝛼𝑘 𝑘

≥lim inf

𝑛 → ∞

1 log𝑛

𝑛 𝑘=1

𝛼𝑘 𝑘

≥ 1 − 2 1 − Φ (𝑥) Φ (𝑥) − Φ (0) a.s.

(57)

By the arbitrariness of𝑥, let𝑥 → ∞in (57); we have 1 ≥lim sup

𝑛 → ∞

1 log𝑛

𝑛 𝑘=1

𝛼𝑘 𝑘

≥lim inf𝑛 → ∞ 1 log𝑛

𝑛 𝑘=1

𝛼𝑘

𝑘 ≥ 1 a.s.

(58)

Thus

𝑛 → ∞lim 1 log𝑛

𝑛 𝑘=1

𝛼𝑘

𝑘 = 1 a.s. (59)

This completes the proof ofTheorem 2.

Proof ofTheorem 5. Let𝑘 < 𝑙 − 𝑙𝛼,1 ≤ 𝑘 < 𝑙, and𝜀𝑙 = 𝑙3𝛼/2; we have

Cov(𝛼𝑘, 𝛼𝑙)

≤ 1

𝑝𝑙𝑝𝑘 (𝑃 (𝑎𝑙− 𝑏𝑘≤ 𝑆𝑙− 𝑆𝑘+𝑙𝛼+ 𝑆𝑘+𝑙𝛼− 𝑆𝑘

< 𝑏𝑙− 𝑎𝑘, 𝑎𝑘≤ 𝑆𝑘 < 𝑏𝑘) − 𝑝𝑙𝑝𝑘)

≤ 1

𝑝𝑙𝑝𝑘 (𝑃 (𝑎𝑙− 𝑏𝑘≤ 𝑆𝑙− 𝑆𝑘+𝑙𝛼+ 𝑆𝑘+𝑙𝛼− 𝑆𝑘

< 𝑏𝑙− 𝑎𝑘) 𝑃 (𝑎𝑘≤ 𝑆𝑘< 𝑏𝑘) − 𝑝𝑙𝑝𝑘)

≤ 1

𝑝𝑙(𝑃 (𝑎𝑙− 𝑏𝑘− 𝜀𝑙< 𝑆𝑙− 𝑆𝑘+𝑙𝛼 < 𝑏𝑙− 𝑎𝑘+ 𝜀𝑙)

−𝑝𝑙+ 𝑃 (󵄨󵄨󵄨󵄨𝑆𝑘+𝑙𝛼− 𝑆𝑘󵄨󵄨󵄨󵄨 ≥ 𝜀𝑙))

≤ 1

𝑝𝑙(𝑃 (𝑎𝑙− 𝑏𝑘− 𝜀𝑙< 𝑆𝑙−𝑘−𝑙𝛼< 𝑏𝑙− 𝑎𝑘+ 𝜀𝑙)

−𝑝𝑙+ 𝑃 (󵄨󵄨󵄨󵄨𝑆𝑙𝛼󵄨󵄨󵄨󵄨 ≥ 𝜀𝑙)) .

(60)

ApplyingLemma 9, (33), and (35), we obtain 𝑃 (𝑎𝑙− 𝑏𝑘− 𝜀𝑙< 𝑆𝑙−𝑘−𝑙𝛼< 𝑏𝑙− 𝑎𝑘+ 𝜀𝑙) − 𝑝𝑙

≤ (Φ ( 𝑏𝑙− 𝑎𝑘+ 𝜀𝑙

(𝑙 − 𝑘 − 𝑙𝛼)1/2) − Φ ( 𝑏𝑙 𝑙1/2)) + (Φ ( 𝑎𝑙

𝑙1/2) − Φ ( 𝑎𝑙− 𝑏𝑘− 𝜀𝑙 (𝑙 − 𝑘 − 𝑙𝛼)1/2)) + 𝑐 ( 1

𝑙1/5+ 1

(𝑙 − 𝑘 − 𝑙𝛼)1/5) .

(61)

HenceLemma 11, (60), and (61) imply that

1≤𝑘<𝑙≤𝑛 𝑘<𝑙−𝑙𝛼

Cov(𝛼𝑘, 𝛼𝑙)

𝑘𝑙 = 𝑂 (log𝑛) . (62)

On the other hand,

1≤𝑘<𝑙≤𝑛 𝑘>𝑙−𝑙𝛼

Cov(𝛼𝑘, 𝛼𝑙)

𝑘𝑙 = 𝑂 (log𝑛) , (63)

because𝑙 − 𝑙𝛼 < 𝑘 < 𝑙, 𝑙𝛾 − (𝑙 − 𝑙𝛼)𝛾 → 0as𝑙 → ∞for 𝛾 < 1, 𝛼 < 1.

But Var(𝛼𝑘) = 0if𝑝𝑘= 0and Var(𝛼𝑘) = 1 − 𝑝𝑘

𝑝𝑘 ≤ 1

𝑝𝑘 if𝑝𝑘 ̸= 0. (64) Then

𝑛 𝑘=1

Var(𝛼𝑘)

𝑘2 ≤ ∑

1≤𝑘≤𝑛 𝑝𝑘 ̸= 0

1 𝑘2𝑝𝑘 ≤∑𝑛

𝑘=1

1

𝑘5/2−𝛼 = 𝑂 (log𝑛) . (65) Noting that

Var(∑𝑛

𝑘=1

𝛼𝑘 𝑘)

=∑𝑛

𝑘=1

Var(𝛼𝑘) 𝑘2 + 2 ∑

1≤𝑘<𝑙≤𝑛 𝑘>𝑙−𝑙𝛼

Cov(𝛼𝑘, 𝛼𝑙)

𝑘𝑙 + 2 ∑

1≤𝑘<𝑙≤𝑛 𝑘<𝑙−𝑙𝛼

Cov(𝛼𝑘, 𝛼𝑙)

𝑘𝑙 ,

(66)

thus (62)–(66) imply that Var(∑𝑛

𝑘=1

𝛼𝑘

𝑘) = 𝑂 (log𝑛) , as𝑛 󳨀→ ∞. (67) Hence applyingRemark 7, we have

𝑛 → ∞lim 1 log𝑛

𝑛 𝑘=1

𝛼𝑘

𝑘 = 1 a.s. (68)

This completes the proof ofTheorem 5.

(7)

Appendix

Proof ofLemma 6. Let𝜇𝑛= ∑𝑛𝑘=1𝑑𝑘𝜉𝑘, and then∀𝜀 > 0 𝑃 (󵄨󵄨󵄨󵄨󵄨󵄨󵄨󵄨𝜇𝑛

𝐷𝑛 −𝐸𝜇𝑛

𝐷𝑛 󵄨󵄨󵄨󵄨󵄨󵄨󵄨󵄨 ≥ 𝜀) ≤ Var(𝜇𝑛/𝐷𝑛)

𝜀2 ≤ 𝑐(log𝐷𝑛)−𝛽. (A.1) Let𝑟 < 1,𝑟𝛽 > 1, and𝑛𝑘 = inf{𝑛𝑘, 𝐷𝑛𝑘 ≥ exp(𝑘𝑟)}, and then𝐷𝑛𝑘 ≥exp(𝑘𝑟), 𝐷𝑛𝑘−1<exp(𝑘𝑟), for𝐷𝑛 ∼ 𝐷𝑛−1; we get

1 ≤ 𝐷𝑛𝑘

exp(𝑘𝑟) ∼ 𝐷𝑛𝑘−1

exp(𝑘𝑟) < 1 󳨀→ 1, (A.2) that is,

𝐷𝑛𝑘 ∼exp(𝑘𝑟) , (A.3) and thus

𝐷𝑛𝑘

𝐷𝑛𝑘−1 ∼ exp(𝑘𝑟) exp((𝑘 − 1)𝑟)

=exp(𝑘𝑟[1 − (1 −1

𝑘)𝑟]) ∼exp(𝑘𝑟⋅ 𝑟 ⋅1 𝑘)

=exp(𝑟 ⋅ 𝑘𝑟−1) .

(A.4) On account of𝑟 < 1, then

𝐷𝑛𝑘

𝐷𝑛𝑘−1 ∼exp(𝑟 ⋅ 𝑘𝑟−1) 󳨀→ 1, as𝑘 󳨀→ ∞,

𝑘=1

𝑃 (󵄨󵄨󵄨󵄨󵄨󵄨󵄨󵄨󵄨 𝜇𝑛𝑘 𝐷𝑛𝑘 −𝐸𝜇𝑛𝑘

𝐷𝑛𝑘 󵄨󵄨󵄨󵄨󵄨󵄨󵄨󵄨󵄨≥ 𝜀)

≤ 𝑐∑

𝑘=1

1

(log𝐷𝑛)−𝛽 ≤ 𝑐∑

𝑘=1

1 𝑘𝑟𝛽 < ∞.

(A.5)

By the Borel-Cantelli lemma, 𝜇𝑛𝑘 𝐷𝑛𝑘 −𝐸𝜇𝑛𝑘

𝐷𝑛𝑘 󳨀→ 0 a.s. (A.6)

Since

𝐸𝜇𝑛𝑘

𝐷𝑛𝑘 = ∑𝑛𝑘=1𝑘 𝑑𝑘

𝐷𝑛𝑘 = 1, (A.7)

thus

𝜇𝑛𝑘

𝐷𝑛𝑘 󳨀→ 1, a.s. (A.8)

Now for𝑛𝑘−1≤ 𝑛 < 𝑛𝑘, for𝐷𝑛 ↑ ∞, 𝐷𝑛𝑘/𝐷𝑛𝑘−1 → 1, and by 𝜉𝑘≥ 0, then𝜇𝑛↑, and we have

1 ←󳨀 𝐷𝑛𝑘−1 𝐷𝑛𝑘

𝜇𝑛𝑘−1 𝐷𝑛𝑘−1 ≤ 𝜇𝑛

𝐷𝑛 ≤ 𝜇𝑛𝑘 𝐷𝑛𝑘

𝐷𝑛𝑘

𝐷𝑛𝑘−1 󳨀→ 1 a.s. (A.9) hence

𝜇𝑛

𝐷𝑛 󳨀→ 1 a.s. (A.10)

This completes the proof ofLemma 6.

Proof ofLemma 10. ApplyingLemma 9, (33), and noting the conditions of (19) and0 < 𝛼 < 1/7, we get

𝑝𝑘= 𝑃 (𝑎𝑘≤ 𝑆𝑘 ≤ 𝑏𝑘)

≤ (Φ ( 𝑏𝑘

𝑘1/2) − Φ ( 𝑎𝑘

𝑘1/2)) + 𝑐 1 𝑘1/5

≤ 𝑐 (𝑘1/2−𝛼 𝑘1/2 + 1

𝑘1/5) ≤ 𝑐2󸀠𝑘−𝛼.

(A.11)

ApplyingLemma 9, (34), and noting the conditions of (19) and0 < 𝛼 < 1/7, we have

𝑝𝑘= 𝑃 (𝑎𝑘≤ 𝑆𝑘 ≤ 𝑏𝑘)

≥ (Φ ( 𝑏𝑘

𝑘1/2) − Φ ( 𝑎𝑘

𝑘1/2)) − 𝑐 1 𝑘1/5

≥ 𝑐 (𝑘1/2−𝛼 𝑘1/2 + 1

𝑘1/5) ≥ 𝑐1󸀠𝑘−𝛼.

(A.12)

ThusLemma 10immediately follows from (A.11) and (A.12).

Proof ofLemma 11.By Lemma 10, Chebyshev’s inequality, and noting the condition of0 < 𝛼 < 1/7, we have

1≤𝑘<𝑙≤𝑛 𝑘<𝑙−𝑙𝛼

1

𝑘𝑙𝑝𝑙𝑃 (󵄨󵄨󵄨󵄨𝑆𝑙𝛼󵄨󵄨󵄨󵄨 ≥ 𝜀𝑙)

≤ ∑

1≤𝑘<𝑙≤𝑛 𝑘<𝑙−𝑙𝛼

1 𝑘𝑙𝑝𝑙

Var(𝑆𝑙𝛼) 𝑙3𝛼 ≤ 𝑐∑𝑛

𝑙=1

1 𝑙1+𝛼

𝑙−𝑙𝛼

𝑘=1

1 𝑘

≤ 𝑐∑𝑛

𝑙=1

log(𝑙 − 𝑙𝛼)

𝑙1+𝛼 = 𝑂 (log𝑛) .

(A.13)

It proves (29). ByLemma 10and0 < 𝛼 < 1/7, we get

1≤𝑘<𝑙≤𝑛 𝑘<𝑙−𝑙𝛼

1 𝑘𝑙𝑝𝑙

1 (𝑙 − 𝑘 − 𝑙𝛼)1/5

≤ 𝑐∑𝑛

𝑙=1

1

𝑙1−𝛼( ∑

1≤𝑘<(𝑙−𝑙𝛼)/2

1 𝑘(𝑙 − 𝑙𝛼− 𝑘)1/5

+ ∑

(𝑙−𝑙𝛼)/2<𝑘<𝑙−𝑙𝛼

1

𝑘(𝑙 − 𝑙𝛼− 𝑘)1/5)

≤ 𝑐∑𝑛

𝑙=1

1

𝑙1−𝛼( 1

(𝑙 − 𝑙𝛼)1/5

1≤𝑘<(𝑙−𝑙𝛼)/2

1 𝑘 + 1

𝑙 − 𝑙𝛼

1≤𝑘<(𝑙−𝑙𝛼)/2

1 𝑘1/5)

≤ 𝑐∑𝑛

𝑙=1

log𝑙 𝑙1−𝛼+1/5 ≤ 𝑐∑𝑛

𝑙=1

1

𝑙 = 𝑂 (log𝑛) .

(A.14)

(8)

It proves (30). ApplyingLemma 9, (33), (35),𝜀𝑙 = 𝑙3𝛼/2, and noting the condition of0 < 𝛼 < 1/7, we obtain

1≤𝑘<𝑙≤𝑛 𝑘<𝑙−𝑙𝛼

1

𝑘𝑙𝑝𝑙󵄨󵄨󵄨󵄨󵄨󵄨󵄨󵄨󵄨Φ ( 𝑎𝑙− 𝑏𝑘− 𝜀𝑙

(𝑙 − 𝑘 − 𝑙𝛼)1/2) − Φ ( 𝑎𝑙 𝑙1/2)󵄨󵄨󵄨󵄨󵄨󵄨󵄨󵄨󵄨

≤ 𝑐 ∑

1≤𝑘<𝑙≤𝑛 𝑘<𝑙−𝑙𝛼

−𝑎𝑙

𝑘𝑙𝑝𝑙( 1

(𝑙 − 𝑘 − 𝑙𝛼)1/2− 1

√𝑙)

+ 𝑐 ∑

1≤𝑘<𝑙≤𝑛 𝑘<𝑙−𝑙𝛼

1 𝑘𝑙𝑝𝑙

𝑏𝑘 (𝑙 − 𝑘 − 𝑙𝛼)1/2 + 𝑐 ∑

1≤𝑘<𝑙≤𝑛 𝑘<𝑙−𝑙𝛼

1 𝑘𝑙𝑝𝑙

𝜀𝑙

(𝑙 − 𝑘 − 𝑙𝛼)1/2 := Σ1+ Σ2+ Σ3. (A.15)

Now applying the same procedure as before, we have

Σ1≤ 𝑐 ∑

1≤𝑘<𝑙≤𝑛 𝑘<𝑙−𝑙𝛼

−𝑎𝑙

𝑘𝑙𝑝𝑙( 1

𝑙1−𝛼(𝑙 − 𝑘 − 𝑙𝛼)1/2 + 𝑘 𝑙(𝑙 − 𝑘 − 𝑙𝛼)1/2)

≤ 𝑐 ∑

1≤𝑙≤𝑛

1 𝑙3/2−𝛼

× ( 1

(l− 𝑙𝛼)1/2

1≤𝑘<(𝑙−𝑙𝛼)/2

1 𝑘+ 1

𝑙 − 𝑙𝛼

1≤𝑘<(𝑙−𝑙𝛼)/2

1 𝑘1/2) + 𝑐 ∑

1≤𝑙≤𝑛

1 𝑙3/2

1≤𝑘<𝑙−𝑙𝛼

1 (𝑙 − 𝑘 − 𝑙𝛼)1/2

≤ 𝑐 ∑

1≤𝑙≤𝑛

log𝑙 𝑙2−𝛼 ≤ 𝑐 ∑

1≤𝑙≤𝑛

1

𝑙 = 𝑂 (log𝑛) , Σ2≤ 𝑐 ∑

1≤𝑘<𝑙≤𝑛 𝑘<𝑙−𝑙𝛼

1

𝑙1−𝛼𝑘1/2+𝛼(𝑙 − 𝑙𝛼− 𝑘)1/2

≤ 𝑐 ∑

1≤𝑙≤𝑛

1

𝑙1−𝛼( 1

(𝑙 − 𝑙𝛼)1/2

1≤𝑘<(𝑙−𝑙𝛼)/2

1 𝑘1/2+𝛼

+ 1

(𝑙 − 𝑙𝛼)1/2+𝛼

1≤𝑘<(𝑙−𝑙𝛼)/2

1 𝑘1/2)

≤ 𝑐 ∑

1≤𝑙≤𝑛

1

𝑙1−𝛼( 1

(𝑙 − 𝑙𝛼)1/2𝑙1/2−𝛼+ 1

(𝑙 − 𝑙𝛼)1/2+𝛼(𝑙 − 𝑙𝛼)1/2)

≤ 𝑐 ∑

1≤𝑙≤𝑛

1

𝑙 = 𝑂 (log𝑛) .

(A.16)

Noting that0 < 𝛼 < 1/7, we deduce Σ3≤ 𝑐 ∑

1≤𝑘<𝑙≤𝑛 𝑘<𝑙−𝑙𝛼

1

𝑙1−(7/2)𝛼𝑘1/2(𝑙 − 𝑙𝛼− 𝑘)1/2

≤ 𝑐 ∑

1≤𝑙≤𝑛

1 𝑙1−(7/2)𝛼

× ( 1

(𝑙 − 𝑙𝛼)1/2

1≤𝑘<(𝑙−𝑙𝛼)/2

1

𝑘+ 1

(𝑙 − 𝑙𝛼) ∑

1≤𝑘<(𝑙−𝑙𝛼)/2

1 𝑘1/2)

≤ 𝑐 ∑

1≤𝑙≤𝑛

log𝑙

𝑙3/2−(7/2)𝛼 ≤ 𝑐 ∑

1≤𝑙≤𝑛

1

𝑙 = 𝑂 (log𝑛) .

(A.17) It proves (31). The proof of (32) is similar to the proof of (31).

This completes the proof ofLemma 11.

Acknowledgments

The authors are very grateful to the academic editor, pro- fessor Ying Hu, and the two anonymous reviewers for their valuable comments and helpful suggestions, which significantly contributed to improving the quality of this paper. This work is jointly supported by National Natural Science Foundation of China (11061012,71271210), Project Supported by Program to Sponsor Teams for Innovation in the Construction of Talent Highlands in Guangxi Institutions of Higher Learning ((2011)47), the Guangxi China Science Foundation (2013GXNSFDA019001).

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