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doi:10.1155/2010/767620

Research Article

Solvability of a Higher-Order Nonlinear Neutral Delay Difference Equation

Min Liu and Zhenyu Guo

School of Sciences, Liaoning Shihua University, Fushun, Liaoning 113001, China

Correspondence should be addressed to Zhenyu Guo,[email protected] Received 19 March 2010; Revised 10 July 2010; Accepted 5 September 2010 Academic Editor: S. Grace

Copyrightq2010 M. Liu and Z. Guo. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

The existence of bounded nonoscillatory solutions of a higher-order nonlinear neutral delay difference equationΔakn· · ·Δa2nΔa1nΔxnbnxn−dfn, xn−r1n, xn−r2n, . . . , xn−rsn 0,nn0, wheren0 ≥0,d >0,k >0, ands >0 are integers,{ain}n≥n0 i1,2, . . . , kand{bn}n≥n0are real sequences,s

j1{rjn}n≥n0 ⊆ Z, andf : {n : nn0} ×Rs → Ris a mapping, is studied. Some sufficient conditions for the existence of bounded nonoscillatory solutions of this equation are established by using Schauder fixed point theorem and Krasnoselskii fixed point theorem and expatiated through seven theorems according to the range of value of the sequence{bn}n≥n0. Moreover, these sufficient conditions guarantee that this equation has not only one bounded nonoscillatory solution but also uncountably many bounded nonoscillatory solutions.

1. Introduction and Preliminaries

Recently, the interest in the study of the solvability of difference equations has been increasing see 1–17and references cited therein. Some authors have paied their attention to various difference equations. For example,

ΔanΔxn pnxgn0, n≥0 1.1

see 14,

ΔanΔxn qnxn1, ΔanΔxn qnfxn1, n≥0 1.2

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see 11,

Δ2

xnpxn−m

pnxn−kqnxn−l0, nn0 1.3

see 6,

Δ2

xnpxn−k

fn, xn 0, n≥1 1.4

see 10,

Δ2

xnpxn−τ m

i1

qifixn−σi, nn0 1.5

see 9,

ΔanΔxnbxn−τ fn, xn−d1n, xn−d2n, . . . , xn−dkn cn, nn0 1.6 see 8,

Δmxncxn−k pnxn−r 0, nn0 1.7

see 15,

Δmxncnxn−k pnfxn−r 0, nn0 1.8

see 3,4,12,13,

Δmxncxn−k u s1

pnsfsxn−rs qn, nn0 1.9

see 16,

Δmxncxn−k pnxn−rqnxn−l0, nn0 1.10

see 17.

Motivated and inspired by the papers mentioned above, in this paper, we investigate the following higher-order nonlinear neutral delay difference equation:

Δakn· · ·Δa2nΔa1nΔxnbnxn−d fn, xn−r1n, xn−r2n, . . . , xn−rsn 0, nn0, 1.11

wheren0≥0,d >0,k >0, ands >0 are integers,{ain}n≥n0i1,2, . . . , kand{bn}n≥n0are real sequences,s

j1{rjn}n≥n0⊆Z, andf :{n:nn0} ×Rs → Ris a mapping. Clearly, difference

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equations1.1–1.10are special cases of1.11. By using Schauder fixed point theorem and Krasnoselskii fixed point theorem, the existence of bounded nonoscillatory solutions of1.11 is established.

Lemma 1.1Schauder fixed point theorem. LetΩbe a nonempty closed convex subset of a Banach spaceX. LetT :Ω → Ωbe a continuous mapping such thatTΩis a relatively compact subset ofX.

ThenT has at least one fixed point inΩ.

Lemma 1.2 Krasnoselskii fixed point theorem. LetΩ be a bounded closed convex subset of a Banach spaceX, and letT1, T2 : Ω → X satisfy T1xT2y ∈ Ω for each x, y ∈ Ω. If T1 is a contraction mapping andT2is a completely continuous mapping, then the equationT1xT2xxhas at least one solution inΩ.

The forward difference Δ is defined as usual, that is,Δxn xn1xn. The higher-order difference for a positive integermis defined asΔmxn ΔΔm−1xn0xn xn. Throughout this paper, assume thatR −∞,∞,NandZstand for the sets of all positive integers and integers, respectively,α inf{n−rjn : 1 ≤js, nn0},β min{n0d, α}, limn→ ∞n−rjn ∞, 1≤js, andlβdenotes the set of real sequences defined on the set of positive integers lager thanβ where any individual sequence is bounded with respect to the usual supremum normxsupn≥β|xn| forx{xn}n≥βlβ. It is well known thatlβ is a Banach space under the supremum norm. A subset Ωof a Banach spaceXis relatively compact if every sequence inΩhas a subsequence converging to an element ofX.

Definition 1.3see 5. A setΩof sequences inlβ is uniformly Cauchyor equi-Cauchyif, for everyε >0, there exists an integerN0such that

xixj< ε, 1.12

wheneveri, j > N0for anyx{xk}k≥βinΩ.

Lemma 1.4discrete Arzela-Ascoli’s theorem 5. A bounded, uniformly Cauchy subsetΩoflβ is relatively compact.

Let

AM, N

x{xn}n≥βlβ :MxnN,∀n≥β

forN > M >0. 1.13

Obviously,AM, Nis a bounded closed and convex subset oflβ. Put

blim sup

n→ ∞ bn, blim inf

n→ ∞ bn. 1.14

By a solution of 1.11, we mean a sequence {xn}n≥β with a positive integerN0n0d|α|such that1.11is satisfied for allnN0. As is customary, a solution of1.11is said to be oscillatory about zero, or simply oscillatory, if the termsxnof the sequence{xn}n≥β are neither eventually all positive nor eventually all negative. Otherwise, the solution is called nonoscillatory.

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2. Existence of Nonoscillatory Solutions

In this section, a few sufficient conditions of the existence of bounded nonoscillatory solutions of1.11are given.

Theorem 2.1. Assume that there exist constants M and N with N > M > 0 and sequences {ain}n≥n0 1≤ik,{bn}n≥n0,{hn}n≥n0, and{qn}n≥n0such that, fornn0,

bn ≡ −1, eventually, 2.1

fn, u1, u2, . . . , usfn, v1, v2, . . . , vshnmax{|uivi|:ui, vi∈ M, N,1≤is}, 2.2 fn, u1, u2, . . . , usqn, ui∈ M, N, 1≤is, 2.3

tn0

max 1

|ait|, ht, qt: 1≤ik

<∞. 2.4

Then1.11has a bounded nonoscillatory solution inAM, N.

Proof. Choose L ∈ M, N. By2.1, 2.4, and the definition of convergence of series, an integerN0> n0d|α|can be chosen such that

bn≡ −1, ∀n≥N0, 2.5

j1

t1N0jd

t2t1

· · ·

tktk−1

ttk

qt k

i1aiti

≤min{L−M, NL}. 2.6

Define a mappingTL:AM, NXby

TLxn

⎧⎪

⎪⎩

L−−1k

j1

t1njd

t2t1

· · ·

tktk−1

ttk

ft, xt−r1t, xt−r2t, . . . , xt−rst k

i1aiti

, nN0,

TLxN0, βn < N0

2.7

for allxAM, N.

iIt is claimed thatTLxAM, N, for allxAM, N.

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In fact, for everyxAM, NandnN0, it follows from2.3and2.6that

TLxnL

j1

t1njd

t2t1

· · ·

tktk−1

ttk

ft, xt−r1t, xt−r2t, . . . , xt−rst k

i1aiti

L

j1

t1N0jd

t2t1

· · ·

tktk−1

ttk

qt

k

i1aiti

M,

TLxnL

j1

t1N0jd

t2t1

· · ·

tktk−1

ttk

qt

k

i1aiti

N.

2.8

That is,TLxAM, NAM, N.

iiIt is declared thatTLis continuous.

Letx {xn} ∈ AM, N and xu {xnu} ∈ AM, Nbe any sequence such that xunxnasu → ∞. FornN0,2.2guarantees that

TLxunTLxn

j1

t1njd

t2t1

· · ·

tktk−1

ttk

f t, xut−r

1t, xut−r

2t, . . . , xut−r

st

ft, xt−r1t, xt−r2t, . . . , xt−rst k

i1aiti

j1

t1njd

t2t1

· · ·

tktk−1

ttk

htmaxxut−rjtxt−rjt: 1≤js k

i1aiti

xux

j1

t1N0jd

t2t1

· · ·

tktk−1

ttk

ht k

i1aiti.

2.9

This inequality and2.4imply thatTLis continuous.

iiiIt can be asserted thatTLAM, Nis relatively compact.

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By2.4, for anyε >0, takeN3N0large enough so that

j1

t1N3jd

t2t1

· · ·

tktk−1

ttk

qt k

i1aiti

< ε

2. 2.10

Then, for anyx{xn} ∈AM, Nandn1, n2N3,2.10ensures that

|TLxn1TLxn2| ≤

j1

t1n1jd

t2t1

· · ·

tktk−1

ttk

ft, xt−r1t, xt−r2t, . . . , xt−rst k

i1aiti

j1

t1n2jd

t2t1

· · ·

tktk−1

ttk

ft, xt−r1t, xt−r2t, . . . , xt−rst k

i1aiti

j1

t1N3jd

t2t1

· · ·

tktk−1

ttk

qt

k

i1aiti

j1

t1N3jd

t2t1

· · ·

tktk−1

ttk

qt k

i1aiti

< ε 2 ε

2 ε,

2.11

which means thatTLAM, Nis uniformly Cauchy. Therefore, byLemma 1.4,TLAM, Nis relatively compact.

ByLemma 1.1, there existsx{xn} ∈AM, Nsuch thatTLxx, which is a bounded nonoscillatory solution of1.11. In fact, fornN0d,

xnL−−1k

j1

t1njd

t2t1

· · ·

tktk−1

ttk

ft, xt−r1t, xt−r2t, . . . , xt−rst k

i1aiti ,

xn−dL−−1k

j1

t1nj−1d

t2t1

· · ·

tktk−1

ttk

ft, xt−r1t, xt−r2t, . . . , xt−rst k

i1aiti ,

2.12

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which derives that

xnxn−d −1k

j1 njd−1

t1nj−1d

t2t1

· · ·

tktk−1

ttk

ft, xt−r1t, xt−r2t, . . . , xt−rst k

i1aiti ,

Δxnxn−d −1k

j1 njd

t1n1j−1d

t2t1

· · ·

tktk−1

ttk

ft, xt−r1t, xt−r2t, . . . , xt−rst k

i1aiti

−−1k

j1 njd−1

t1nj−1d

t2t1

· · ·

tktk−1

ttk

ft, xt−r1t, xt−r2t, . . . , xt−rst k

i1aiti

−−1k

j1

t2nj−1d

t3t2

· · ·

tktk−1

ttk

ft, xt−r1t, xt−r2t, . . . , xt−rst

a1nj−1dk

i2aiti

−1k

j1

t2njd

t3t2

· · ·

tktk−1

ttk

ft, xt−r1t, xt−r2t, . . . , xt−rst a1njdk

i2aiti

−1k−1

t2n

t3t2

· · ·

tktk−1

ttk

ft, xt−r1t, xt−r2t, . . . , xt−rst a1nk

i2aiti .

2.13

That is,

a1nΔxnxn−d −1k−1

t2n

t3t2

· · ·

tktk−1

ttk

ft, xt−r1t, xt−r2t, . . . , xt−rst k

i2aiti , 2.14

by which it follows that

Δa1nΔxnxn−d −1k−1

t2n1

t3t2

· · ·

tktk−1

ttk

ft, xt−r1t, xt−r2t, . . . , xt−rst k

i2aiti

−−1k−1

t2n

t3t2

· · ·

tktk−1

ttk

ft, xt−r1t, xt−r2t, . . . , xt−rst k

i2aiti

−1k−2

t3n

t4t3

· · ·

tktk−1

ttk

ft, xt−r1t, xt−r2t, . . . , xt−rst a2nk

i3aiti

,

...

Δakn· · ·Δa2nΔa1nΔxnbnxn−d −1k−k1fn, xn−r1n, xn−r2n, . . . , xn−rsn −fn, xn−r1n, xn−r2n, . . . , xn−rsn.

2.15 Therefore,xis a bounded nonoscillatory solution of1.11. This completes the proof.

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Remark 2.2. The conditions of Theorem 2.1 ensure the 1.11 has not only one bounded nonoscillatory solution but also uncountably many bounded nonoscillatory solutions.

In fact, let L1, L2 ∈ M, N with L1/L2. For L1 and L2, as the preceding proof in Theorem 2.1, there exist integers N1, N2n0 d |α| and mappings TL1, TL2

satisfying 2.5–2.7, where L, N0 are replaced by L1, N1 and L2, N2, respectively, and

j1

t1N4jd

t2t1· · ·

tktk−1

ttkht/|k

i1aiti| < |L1L2|/2N for some N4 ≥ max{N1, N2}. Then the mappingsTL1andTL2have fixed pointsx, yAM, N, respectively, which are bounded nonoscillatory solutions of1.11inAM, N. For the sake of proving that1.11possesses uncountably many bounded nonoscillatory solutions inAM, N, it is only needed to show thatx /y. In fact, by2.7, we know that, fornN4,

xnL1−−1k

j1

t1njd

t2t1

· · ·

tktk−1

ttk

ft, xt−r1t, xt−r2t, . . . , xt−rst k

i1aiti

,

ynL2−−1k

j1

t1njd

t2t1

· · ·

tktk−1

ttk

f

t, yt−r1t, yt−r2t, . . . , yt−rst k

i1aiti

.

2.16

Then,

xnyn≥ |L1L2|

j1

t1njd

t2t1

· · ·

tktk−1

ttk

ft, xt−r1t, xt−r2t, . . . , xt−rstf

t, yt−r1t, yt−r2t, . . . , yt−rst k

i1aiti

≥ |L1L2| −xy

j1

t1N4jd

t2t1

· · ·

tktk−1

ttk

ht k

i1aiti

≥ |L1L2| −2N j1

t1N4jd

t2t1

· · ·

tktk−1

ttk

ht k

i1aiti

>0, nN4,

2.17

that is,x /y.

Theorem 2.3. Assume that there exist constants M and N with N > M > 0 and sequences {ain}n≥n0 1≤ik,{bn}n≥n0,{hn}n≥n0,{qn}n≥n0, satisfying2.2–2.4and

bn≡1, eventually. 2.18

Then1.11has a bounded nonoscillatory solution inAM, N.

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Proof. ChooseL∈M, N. By2.18and2.4, an integerN0> n0d|α|can be chosen such that

bn≡1, ∀n≥N0,

j1

N02jd−1

t1N02j−1d

t2t1

· · ·

tktk−1

ttk

qt

k

i1aiti ≤min{L−M, NL}. 2.19 Define a mappingTL:AM, NXby

TLxn

⎧⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎨

⎪⎪

⎪⎪

⎪⎪

⎪⎪

L −1k

j1

n2jd−1

t1n2j−1d

t2t1

· · ·

tktk−1

ttk

ft, xt−r1t, xt−r2t, . . . , xt−rst k

i1aiti

, nN0,

TLxN0, βn < N0

2.20

for allxAM, N.

The proof that TL has a fixed point x {xn} ∈ AM, N is analogous to that in Theorem 2.1. It is claimed that the fixed pointxis a bounded nonoscillatory solution of1.11.

In fact, fornN0d,

xnL −1k

j1

n2jd−1

t1n2j−1d

t2t1

· · ·

tktk−1

ttk

ft, xt−r1t, xt−r2t, . . . , xt−rst k

i1aiti ,

xn−dL −1k

j1

n2j−1d−1

t1n2j−1d

t2t1

· · ·

tktk−1

ttk

ft, xt−r1t, xt−r2t, . . . , xt−rst k

i1aiti

,

2.21

by which it follows that

xnxn−d2L −1k

j1 njd−1

t1nj−1d

t2t1

· · ·

tktk−1

ttk

ft, xt−r1t, xt−r2t, . . . , xt−rst k

i1aiti . 2.22

The rest of the proof is similar to that inTheorem 2.1. This completes the proof.

Theorem 2.4. Assume that there exist constantsb,M, andN with N > M > 0 and sequences {ain}n≥n01≤ik,{bn}n≥n0,{hn}n≥n0,{qn}n≥n0, satisfying2.2–2.4and

|bn| ≤b < NM

2N , eventually. 2.23

Then1.11has a bounded nonoscillatory solution inAM, N.

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Proof. ChooseL∈MbN, NbN. By2.23and2.4, an integerN0> n0d|α|can be chosen such that

|bn| ≤b < NM

2N , ∀n≥N0,

t1N0

t2t1

· · ·

tktk−1

ttk

qt k

i1aiti

≤min{L−bNM, NbNL}. 2.24

Define two mappingsT1L, T2L:AM, NXby

T1Lxn

⎧⎨

Lbnxn−d, nN0, T1LxN0, βn < N0, T2Lxn

⎧⎪

⎪⎩

−1k

t1n

t2t1

· · ·

tktk−1

ttk

ft, xt−r1t, xt−r2t, . . . , xt−rst k

i1aiti

, nN0,

T2LxN0, βn < N0

2.25

for allxAM, N.

iIt is claimed thatT1LxT2LyAM, N, for allx, yAM, N.

In fact, for everyx, yAM, NandnN0, it follows from2.3,2.24that T1LxT2Ly

nLbN

t1N0

t2t1

· · ·

tktk−1

ttk

qt k

i1aiti

M, T1LxT2Ly

nLbN

t1N0

t2t1

· · ·

tktk−1

ttk

qt k

i1aiti

N.

2.26

That is,T1LxT2LyAM, NAM, N.

iiIt is declared thatT1Lis a contraction mapping onAM, N.

In reality, for anyx, yAM,NandnN0, it is easy to derive that T1Lxn

T1Ly

n≤ |bn|xn−dyn−dbxy, 2.27 which implies that

T1LxT1Lybxy. 2.28 Then,b <N−M/2N <1 ensures thatT1Lis a contraction mapping onAM, N.

iiiSimilar toiiandiiiin the proof ofTheorem 2.1, it can be showed thatT2Lis completely continuous.

ByLemma 1.2, there existsx{xn} ∈AM, Nsuch thatT1LxT2Lxx, which is a bounded nonoscillatory solution of1.11. This completes the proof.

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Theorem 2.5. Assume that there exist constantsMandNwithN >2−b/1bM >0 and sequences{ain}n≥n01≤ik,{bn}n≥n0,{hn}n≥n0,{qn}n≥n0, satisfying2.2–2.4and

bn≥0, eventually, and 0bb <1. 2.29

Then1.11has a bounded nonoscillatory solution inAM, N.

Proof. ChooseL ∈ M 1b/2N, N b/2M. By 2.29and 2.4, an integerN0 >

n0d|α|can be chosen such that

b

2 ≤bn≤ 1b

2 , ∀n≥N0,

t1N0

t2t1

· · ·

tktk−1

ttk

qt

k

i1aiti≤min

LM−1b

2 N, NLb 2M

.

2.30

Define two mappingsT1L, T2L:AM, NXas2.25. The rest of the proof is analogous to that inTheorem 2.4. This completes the proof.

Similar to the proof ofTheorem 2.5, we have the following theorem.

Theorem 2.6. Assume that there exist constantsMandNwithN >2b/1bM >0 and sequences{ain}n≥n01≤ik,{bn}n≥n0,{hn}n≥n0,{qn}n≥n0, satisfying2.2–2.4and

bn≤0, eventually, and −1< bb≤0. 2.31

Then1.11has a bounded nonoscillatory solution inAM, N.

Theorem 2.7. Assume that there exist constantsMandNwithN >bb2b/bb2bM >0 and sequences{ain}n≥n0 1≤ik,{bn}n≥n0,{hn}n≥n0,{qn}n≥n0, satisfying2.2–2.4and

bn>1, eventually, 1< bandb < b2<∞. 2.32

Then1.11has a bounded nonoscillatory solution inAM, N. Proof. Takeε∈0, b−1sufficiently small satisfying

1< bε < bε <

bε2 ,

bε2

2

N >

2 bε

bε2 M.

2.33

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ChooseL∈bεM bε/bεN,b−εN b−ε/bεM. By2.33, an integer N0> n0d|α|can be chosen such that

bε < bn< bε, ∀b≥N0,

t1N0

t2t1

· · ·

tktk−1

ttk

qt k

i1aiti

≤min bε bεL

bε

MN,bε bεM

bε NL

.

2.34 Define two mappingsT1L, T2L:AM, NXby

T1Lxn

⎧⎪

⎪⎨

⎪⎪

L

bndxnd

bnd, nN0, T1LxN0, βn < N0, T2Lxn

⎧⎪

⎪⎨

⎪⎪

−1k bnd

t1n

t2t1

· · ·

tktk−1

ttk

ft, xt−r1t, xt−r2t, . . . , xt−rst k

i1aiti

, nN0,

T2LxN0, βn < N0

2.35

for allxAM, N. The rest of the proof is analogous to that inTheorem 2.4. This completes the proof.

Similar to the proof ofTheorem 2.7, we have

Theorem 2.8. Assume that there exist constantsMandNwithN >1b/1bM >0 and sequences{ain}n≥n0 1≤ik,{bn}n≥n0,{hn}n≥n0,{qn}n≥n0, satisfying2.2–2.4and

bn <−1, eventually, −∞< bandb <−1. 2.36

Then1.11has a bounded nonoscillatory solution inAM, N.

Remark 2.9. Similar toRemark 2.2, we can also prove that the conditions of Theorems2.3–2.8 ensure that 1.11has not only one bounded nonoscillatory solution but also uncountably many bounded nonoscillatory solutions.

Remark 2.10. Theorems 2.1–2.8 extend and improve Theorem 1 of Cheng 6, Theorems 2.1–2.7 of Liu et al. 8, and corresponding theorems in 3,4,9–17.

3. Examples

In this section, two examples are presented to illustrate the advantage of the above results.

Example 3.1. Consider the following fourth-order nonlinear neutral delay difference equation:

Δ4nΔ3nΔ2nΔxnxn−1 0, n≥1. 3.1

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ChooseM1 andN2. It is easy to verify that the conditions ofTheorem 2.1are satisfied.

ThereforeTheorem 2.1ensures that3.1has a nonoscillatory solution inA1,2. However, the results in 3,4,6,8–17are not applicable for3.1.

Example 3.2. Consider the following third-order nonlinear neutral delay difference equation:

Δ

2n

n2n1 Δ

xn2n−1 3n xn−4

sin2xn−2

n2 −cos3xn−3

n3 0, n≥5, 3.2

where

a1nn2n1, a2n2nn, bn 2n−1 3n , fn, u1, u2 sin2u1

n2 −cos3u2

n3 , hnqn 2 n2.

3.3

ChooseM1 andN5. It can be verified that the assumptions ofTheorem 2.5are fulfilled.

It follows fromTheorem 2.5that3.2has a nonoscillatory solution inA1,5. However, the results in 3,4,6,8–17are unapplicable for3.2.

Acknowledgment

The authors are grateful to the editor and the referee for their kind help, careful reading and editing, valuable comments and suggestions.

References

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