doi:10.1155/2010/767620
Research Article
Solvability of a Higher-Order Nonlinear Neutral Delay Difference Equation
Min Liu and Zhenyu Guo
School of Sciences, Liaoning Shihua University, Fushun, Liaoning 113001, China
Correspondence should be addressed to Zhenyu Guo,[email protected] Received 19 March 2010; Revised 10 July 2010; Accepted 5 September 2010 Academic Editor: S. Grace
Copyrightq2010 M. Liu and Z. Guo. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
The existence of bounded nonoscillatory solutions of a higher-order nonlinear neutral delay difference equationΔakn· · ·Δa2nΔa1nΔxnbnxn−dfn, xn−r1n, xn−r2n, . . . , xn−rsn 0,n≥n0, wheren0 ≥0,d >0,k >0, ands >0 are integers,{ain}n≥n0 i1,2, . . . , kand{bn}n≥n0are real sequences,s
j1{rjn}n≥n0 ⊆ Z, andf : {n : n ≥ n0} ×Rs → Ris a mapping, is studied. Some sufficient conditions for the existence of bounded nonoscillatory solutions of this equation are established by using Schauder fixed point theorem and Krasnoselskii fixed point theorem and expatiated through seven theorems according to the range of value of the sequence{bn}n≥n0. Moreover, these sufficient conditions guarantee that this equation has not only one bounded nonoscillatory solution but also uncountably many bounded nonoscillatory solutions.
1. Introduction and Preliminaries
Recently, the interest in the study of the solvability of difference equations has been increasing see 1–17and references cited therein. Some authors have paied their attention to various difference equations. For example,
ΔanΔxn pnxgn0, n≥0 1.1
see 14,
ΔanΔxn qnxn1, ΔanΔxn qnfxn1, n≥0 1.2
see 11,
Δ2
xnpxn−m
pnxn−k−qnxn−l0, n≥n0 1.3
see 6,
Δ2
xnpxn−k
fn, xn 0, n≥1 1.4
see 10,
Δ2
xn−pxn−τ m
i1
qifixn−σi, n≥n0 1.5
see 9,
ΔanΔxnbxn−τ fn, xn−d1n, xn−d2n, . . . , xn−dkn cn, n≥n0 1.6 see 8,
Δmxncxn−k pnxn−r 0, n≥n0 1.7
see 15,
Δmxncnxn−k pnfxn−r 0, n≥n0 1.8
see 3,4,12,13,
Δmxncxn−k u s1
pnsfsxn−rs qn, n≥n0 1.9
see 16,
Δmxncxn−k pnxn−r−qnxn−l0, n≥n0 1.10
see 17.
Motivated and inspired by the papers mentioned above, in this paper, we investigate the following higher-order nonlinear neutral delay difference equation:
Δakn· · ·Δa2nΔa1nΔxnbnxn−d fn, xn−r1n, xn−r2n, . . . , xn−rsn 0, n≥n0, 1.11
wheren0≥0,d >0,k >0, ands >0 are integers,{ain}n≥n0i1,2, . . . , kand{bn}n≥n0are real sequences,s
j1{rjn}n≥n0⊆Z, andf :{n:n≥n0} ×Rs → Ris a mapping. Clearly, difference
equations1.1–1.10are special cases of1.11. By using Schauder fixed point theorem and Krasnoselskii fixed point theorem, the existence of bounded nonoscillatory solutions of1.11 is established.
Lemma 1.1Schauder fixed point theorem. LetΩbe a nonempty closed convex subset of a Banach spaceX. LetT :Ω → Ωbe a continuous mapping such thatTΩis a relatively compact subset ofX.
ThenT has at least one fixed point inΩ.
Lemma 1.2 Krasnoselskii fixed point theorem. LetΩ be a bounded closed convex subset of a Banach spaceX, and letT1, T2 : Ω → X satisfy T1xT2y ∈ Ω for each x, y ∈ Ω. If T1 is a contraction mapping andT2is a completely continuous mapping, then the equationT1xT2xxhas at least one solution inΩ.
The forward difference Δ is defined as usual, that is,Δxn xn1 −xn. The higher-order difference for a positive integermis defined asΔmxn ΔΔm−1xn,Δ0xn xn. Throughout this paper, assume thatR −∞,∞,NandZstand for the sets of all positive integers and integers, respectively,α inf{n−rjn : 1 ≤j ≤s, n ≥n0},β min{n0−d, α}, limn→ ∞n−rjn ∞, 1≤j ≤s, andlβ∞denotes the set of real sequences defined on the set of positive integers lager thanβ where any individual sequence is bounded with respect to the usual supremum normxsupn≥β|xn| forx{xn}n≥β∈l∞β. It is well known thatl∞β is a Banach space under the supremum norm. A subset Ωof a Banach spaceXis relatively compact if every sequence inΩhas a subsequence converging to an element ofX.
Definition 1.3see 5. A setΩof sequences inl∞β is uniformly Cauchyor equi-Cauchyif, for everyε >0, there exists an integerN0such that
xi−xj< ε, 1.12
wheneveri, j > N0for anyx{xk}k≥βinΩ.
Lemma 1.4discrete Arzela-Ascoli’s theorem 5. A bounded, uniformly Cauchy subsetΩofl∞β is relatively compact.
Let
AM, N
x{xn}n≥β∈l∞β :M≤xn≤N,∀n≥β
forN > M >0. 1.13
Obviously,AM, Nis a bounded closed and convex subset ofl∞β. Put
blim sup
n→ ∞ bn, blim inf
n→ ∞ bn. 1.14
By a solution of 1.11, we mean a sequence {xn}n≥β with a positive integerN0 ≥ n0d|α|such that1.11is satisfied for alln≥N0. As is customary, a solution of1.11is said to be oscillatory about zero, or simply oscillatory, if the termsxnof the sequence{xn}n≥β are neither eventually all positive nor eventually all negative. Otherwise, the solution is called nonoscillatory.
2. Existence of Nonoscillatory Solutions
In this section, a few sufficient conditions of the existence of bounded nonoscillatory solutions of1.11are given.
Theorem 2.1. Assume that there exist constants M and N with N > M > 0 and sequences {ain}n≥n0 1≤i≤k,{bn}n≥n0,{hn}n≥n0, and{qn}n≥n0such that, forn≥n0,
bn ≡ −1, eventually, 2.1
fn, u1, u2, . . . , us−fn, v1, v2, . . . , vs≤hnmax{|ui−vi|:ui, vi∈ M, N,1≤i≤s}, 2.2 fn, u1, u2, . . . , us≤qn, ui∈ M, N, 1≤i≤s, 2.3
∞ tn0
max 1
|ait|, ht, qt: 1≤i≤k
<∞. 2.4
Then1.11has a bounded nonoscillatory solution inAM, N.
Proof. Choose L ∈ M, N. By2.1, 2.4, and the definition of convergence of series, an integerN0> n0d|α|can be chosen such that
bn≡ −1, ∀n≥N0, 2.5
∞ j1
∞ t1N0jd
∞ t2t1
· · · ∞
tktk−1
∞ ttk
qt k
i1aiti
≤min{L−M, N−L}. 2.6
Define a mappingTL:AM, N → Xby
TLxn
⎧⎪
⎨
⎪⎩
L−−1k∞
j1
∞ t1njd
∞ t2t1
· · · ∞
tktk−1
∞ ttk
ft, xt−r1t, xt−r2t, . . . , xt−rst k
i1aiti
, n≥N0,
TLxN0, β≤n < N0
2.7
for allx∈AM, N.
iIt is claimed thatTLx∈AM, N, for allx∈AM, N.
In fact, for everyx∈AM, Nandn≥N0, it follows from2.3and2.6that
TLxn≥L−∞
j1
∞ t1njd
∞ t2t1
· · · ∞
tktk−1
∞ ttk
ft, xt−r1t, xt−r2t, . . . , xt−rst k
i1aiti
≥L−∞
j1
∞ t1N0jd
∞ t2t1
· · · ∞
tktk−1
∞ ttk
qt
k
i1aiti
≥M,
TLxn≤L∞
j1
∞ t1N0jd
∞ t2t1
· · · ∞
tktk−1
∞ ttk
qt
k
i1aiti
≤N.
2.8
That is,TLxAM, N⊆AM, N.
iiIt is declared thatTLis continuous.
Letx {xn} ∈ AM, N and xu {xnu} ∈ AM, Nbe any sequence such that xun → xnasu → ∞. Forn≥N0,2.2guarantees that
TLxun −TLxn
≤∞
j1
∞ t1njd
∞ t2t1
· · · ∞
tktk−1
∞ ttk
f t, xut−r
1t, xut−r
2t, . . . , xut−r
st
−ft, xt−r1t, xt−r2t, . . . , xt−rst k
i1aiti
≤∞
j1
∞ t1njd
∞ t2t1
· · · ∞
tktk−1
∞ ttk
htmaxxut−rjt−xt−rjt: 1≤j ≤s k
i1aiti
≤xu−x∞
j1
∞ t1N0jd
∞ t2t1
· · · ∞
tktk−1
∞ ttk
ht k
i1aiti.
2.9
This inequality and2.4imply thatTLis continuous.
iiiIt can be asserted thatTLAM, Nis relatively compact.
By2.4, for anyε >0, takeN3≥N0large enough so that
∞ j1
∞ t1N3jd
∞ t2t1
· · · ∞
tktk−1
∞ ttk
qt k
i1aiti
< ε
2. 2.10
Then, for anyx{xn} ∈AM, Nandn1, n2≥N3,2.10ensures that
|TLxn1−TLxn2| ≤∞
j1
∞ t1n1jd
∞ t2t1
· · · ∞
tktk−1
∞ ttk
ft, xt−r1t, xt−r2t, . . . , xt−rst k
i1aiti
∞
j1
∞ t1n2jd
∞ t2t1
· · · ∞
tktk−1
∞ ttk
ft, xt−r1t, xt−r2t, . . . , xt−rst k
i1aiti
≤∞
j1
∞ t1N3jd
∞ t2t1
· · · ∞
tktk−1
∞ ttk
qt
k
i1aiti
∞
j1
∞ t1N3jd
∞ t2t1
· · · ∞
tktk−1
∞ ttk
qt k
i1aiti
< ε 2 ε
2 ε,
2.11
which means thatTLAM, Nis uniformly Cauchy. Therefore, byLemma 1.4,TLAM, Nis relatively compact.
ByLemma 1.1, there existsx{xn} ∈AM, Nsuch thatTLxx, which is a bounded nonoscillatory solution of1.11. In fact, forn≥N0d,
xnL−−1k∞
j1
∞ t1njd
∞ t2t1
· · · ∞
tktk−1
∞ ttk
ft, xt−r1t, xt−r2t, . . . , xt−rst k
i1aiti ,
xn−dL−−1k∞
j1
∞ t1nj−1d
∞ t2t1
· · · ∞
tktk−1
∞ ttk
ft, xt−r1t, xt−r2t, . . . , xt−rst k
i1aiti ,
2.12
which derives that
xn−xn−d −1k∞
j1 njd−1
t1nj−1d
∞ t2t1
· · · ∞
tktk−1
∞ ttk
ft, xt−r1t, xt−r2t, . . . , xt−rst k
i1aiti ,
Δxn−xn−d −1k∞
j1 njd
t1n1j−1d
∞ t2t1
· · · ∞
tktk−1
∞ ttk
ft, xt−r1t, xt−r2t, . . . , xt−rst k
i1aiti
−−1k∞
j1 njd−1
t1nj−1d
∞ t2t1
· · · ∞
tktk−1
∞ ttk
ft, xt−r1t, xt−r2t, . . . , xt−rst k
i1aiti
−−1k∞
j1
∞ t2nj−1d
∞ t3t2
· · · ∞
tktk−1
∞ ttk
ft, xt−r1t, xt−r2t, . . . , xt−rst
a1nj−1dk
i2aiti
−1k∞
j1
∞ t2njd
∞ t3t2
· · · ∞
tktk−1
∞ ttk
ft, xt−r1t, xt−r2t, . . . , xt−rst a1njdk
i2aiti
−1k−1∞
t2n
∞ t3t2
· · · ∞
tktk−1
∞ ttk
ft, xt−r1t, xt−r2t, . . . , xt−rst a1nk
i2aiti .
2.13
That is,
a1nΔxn−xn−d −1k−1∞
t2n
∞ t3t2
· · · ∞
tktk−1
∞ ttk
ft, xt−r1t, xt−r2t, . . . , xt−rst k
i2aiti , 2.14
by which it follows that
Δa1nΔxn−xn−d −1k−1 ∞
t2n1
∞ t3t2
· · · ∞
tktk−1
∞ ttk
ft, xt−r1t, xt−r2t, . . . , xt−rst k
i2aiti
−−1k−1∞
t2n
∞ t3t2
· · · ∞
tktk−1
∞ ttk
ft, xt−r1t, xt−r2t, . . . , xt−rst k
i2aiti
−1k−2∞
t3n
∞ t4t3
· · · ∞
tktk−1
∞ ttk
ft, xt−r1t, xt−r2t, . . . , xt−rst a2nk
i3aiti
,
...
Δakn· · ·Δa2nΔa1nΔxnbnxn−d −1k−k1fn, xn−r1n, xn−r2n, . . . , xn−rsn −fn, xn−r1n, xn−r2n, . . . , xn−rsn.
2.15 Therefore,xis a bounded nonoscillatory solution of1.11. This completes the proof.
Remark 2.2. The conditions of Theorem 2.1 ensure the 1.11 has not only one bounded nonoscillatory solution but also uncountably many bounded nonoscillatory solutions.
In fact, let L1, L2 ∈ M, N with L1/L2. For L1 and L2, as the preceding proof in Theorem 2.1, there exist integers N1, N2 ≥ n0 d |α| and mappings TL1, TL2
satisfying 2.5–2.7, where L, N0 are replaced by L1, N1 and L2, N2, respectively, and ∞
j1∞
t1N4jd∞
t2t1· · ·∞
tktk−1
∞
ttkht/|k
i1aiti| < |L1 − L2|/2N for some N4 ≥ max{N1, N2}. Then the mappingsTL1andTL2have fixed pointsx, y∈AM, N, respectively, which are bounded nonoscillatory solutions of1.11inAM, N. For the sake of proving that1.11possesses uncountably many bounded nonoscillatory solutions inAM, N, it is only needed to show thatx /y. In fact, by2.7, we know that, forn≥N4,
xnL1−−1k∞
j1
∞ t1njd
∞ t2t1
· · · ∞
tktk−1
∞ ttk
ft, xt−r1t, xt−r2t, . . . , xt−rst k
i1aiti
,
ynL2−−1k∞
j1
∞ t1njd
∞ t2t1
· · · ∞
tktk−1
∞ ttk
f
t, yt−r1t, yt−r2t, . . . , yt−rst k
i1aiti
.
2.16
Then,
xn−yn≥ |L1−L2|
−∞
j1
∞ t1njd
∞ t2t1
· · · ∞
tktk−1
∞ ttk
ft, xt−r1t, xt−r2t, . . . , xt−rst−f
t, yt−r1t, yt−r2t, . . . , yt−rst k
i1aiti
≥ |L1−L2| −x−y∞
j1
∞ t1N4jd
∞ t2t1
· · · ∞
tktk−1
∞ ttk
ht k
i1aiti
≥ |L1−L2| −2N ∞ j1
∞ t1N4jd
∞ t2t1
· · · ∞
tktk−1
∞ ttk
ht k
i1aiti
>0, n≥N4,
2.17
that is,x /y.
Theorem 2.3. Assume that there exist constants M and N with N > M > 0 and sequences {ain}n≥n0 1≤i≤k,{bn}n≥n0,{hn}n≥n0,{qn}n≥n0, satisfying2.2–2.4and
bn≡1, eventually. 2.18
Then1.11has a bounded nonoscillatory solution inAM, N.
Proof. ChooseL∈M, N. By2.18and2.4, an integerN0> n0d|α|can be chosen such that
bn≡1, ∀n≥N0, ∞
j1
N02jd−1
t1N02j−1d
∞ t2t1
· · · ∞
tktk−1
∞ ttk
qt
k
i1aiti ≤min{L−M, N−L}. 2.19 Define a mappingTL:AM, N → Xby
TLxn
⎧⎪
⎪⎪
⎪⎪
⎪⎪
⎪⎨
⎪⎪
⎪⎪
⎪⎪
⎪⎪
⎩
L −1k∞
j1
n2jd−1
t1n2j−1d
∞ t2t1
· · · ∞
tktk−1
∞ ttk
ft, xt−r1t, xt−r2t, . . . , xt−rst k
i1aiti
, n≥N0,
TLxN0, β≤n < N0
2.20
for allx∈AM, N.
The proof that TL has a fixed point x {xn} ∈ AM, N is analogous to that in Theorem 2.1. It is claimed that the fixed pointxis a bounded nonoscillatory solution of1.11.
In fact, forn≥N0d,
xnL −1k∞
j1
n2jd−1
t1n2j−1d
∞ t2t1
· · · ∞
tktk−1
∞ ttk
ft, xt−r1t, xt−r2t, . . . , xt−rst k
i1aiti ,
xn−dL −1k∞
j1
n2j−1d−1
t1n2j−1d
∞ t2t1
· · · ∞
tktk−1
∞ ttk
ft, xt−r1t, xt−r2t, . . . , xt−rst k
i1aiti
,
2.21
by which it follows that
xnxn−d2L −1k∞
j1 njd−1
t1nj−1d
∞ t2t1
· · · ∞
tktk−1
∞ ttk
ft, xt−r1t, xt−r2t, . . . , xt−rst k
i1aiti . 2.22
The rest of the proof is similar to that inTheorem 2.1. This completes the proof.
Theorem 2.4. Assume that there exist constantsb,M, andN with N > M > 0 and sequences {ain}n≥n01≤i≤k,{bn}n≥n0,{hn}n≥n0,{qn}n≥n0, satisfying2.2–2.4and
|bn| ≤b < N−M
2N , eventually. 2.23
Then1.11has a bounded nonoscillatory solution inAM, N.
Proof. ChooseL∈MbN, N−bN. By2.23and2.4, an integerN0> n0d|α|can be chosen such that
|bn| ≤b < N−M
2N , ∀n≥N0, ∞
t1N0
∞ t2t1
· · · ∞
tktk−1
∞ ttk
qt k
i1aiti
≤min{L−bN−M, N−bN−L}. 2.24
Define two mappingsT1L, T2L:AM, N → Xby
T1Lxn
⎧⎨
⎩
L−bnxn−d, n≥N0, T1LxN0, β≤n < N0, T2Lxn
⎧⎪
⎨
⎪⎩
−1k∞
t1n
∞ t2t1
· · · ∞
tktk−1
∞ ttk
ft, xt−r1t, xt−r2t, . . . , xt−rst k
i1aiti
, n≥N0,
T2LxN0, β≤n < N0
2.25
for allx∈AM, N.
iIt is claimed thatT1LxT2Ly∈AM, N, for allx, y∈AM, N.
In fact, for everyx, y∈AM, Nandn≥N0, it follows from2.3,2.24that T1LxT2Ly
n≥L−bN− ∞
t1N0
∞ t2t1
· · · ∞
tktk−1
∞ ttk
qt k
i1aiti
≥M, T1LxT2Ly
n≤LbN ∞
t1N0
∞ t2t1
· · · ∞
tktk−1
∞ ttk
qt k
i1aiti
≤N.
2.26
That is,T1LxT2LyAM, N⊆AM, N.
iiIt is declared thatT1Lis a contraction mapping onAM, N.
In reality, for anyx, y∈AM,Nandn≥N0, it is easy to derive that T1Lxn−
T1Ly
n≤ |bn|xn−d−yn−d≤bx−y, 2.27 which implies that
T1Lx−T1Ly≤bx−y. 2.28 Then,b <N−M/2N <1 ensures thatT1Lis a contraction mapping onAM, N.
iiiSimilar toiiandiiiin the proof ofTheorem 2.1, it can be showed thatT2Lis completely continuous.
ByLemma 1.2, there existsx{xn} ∈AM, Nsuch thatT1LxT2Lxx, which is a bounded nonoscillatory solution of1.11. This completes the proof.
Theorem 2.5. Assume that there exist constantsMandNwithN >2−b/1−bM >0 and sequences{ain}n≥n01≤i≤k,{bn}n≥n0,{hn}n≥n0,{qn}n≥n0, satisfying2.2–2.4and
bn≥0, eventually, and 0≤b≤b <1. 2.29
Then1.11has a bounded nonoscillatory solution inAM, N.
Proof. ChooseL ∈ M 1b/2N, N b/2M. By 2.29and 2.4, an integerN0 >
n0d|α|can be chosen such that
b
2 ≤bn≤ 1b
2 , ∀n≥N0, ∞
t1N0
∞ t2t1
· · · ∞
tktk−1
∞ ttk
qt
k
i1aiti≤min
L−M−1b
2 N, N−Lb 2M
.
2.30
Define two mappingsT1L, T2L:AM, N → Xas2.25. The rest of the proof is analogous to that inTheorem 2.4. This completes the proof.
Similar to the proof ofTheorem 2.5, we have the following theorem.
Theorem 2.6. Assume that there exist constantsMandNwithN >2b/1bM >0 and sequences{ain}n≥n01≤i≤k,{bn}n≥n0,{hn}n≥n0,{qn}n≥n0, satisfying2.2–2.4and
bn≤0, eventually, and −1< b≤b≤0. 2.31
Then1.11has a bounded nonoscillatory solution inAM, N.
Theorem 2.7. Assume that there exist constantsMandNwithN >bb2−b/bb2−bM >0 and sequences{ain}n≥n0 1≤i≤k,{bn}n≥n0,{hn}n≥n0,{qn}n≥n0, satisfying2.2–2.4and
bn>1, eventually, 1< bandb < b2<∞. 2.32
Then1.11has a bounded nonoscillatory solution inAM, N. Proof. Takeε∈0, b−1sufficiently small satisfying
1< b−ε < bε <
b−ε2 , bε
b−ε2−
bε2
N >
bε2 b−ε
−
b−ε2 M.
2.33
ChooseL∈bεM bε/b−εN,b−εN b−ε/bεM. By2.33, an integer N0> n0d|α|can be chosen such that
b−ε < bn< bε, ∀b≥N0, ∞
t1N0
∞ t2t1
· · · ∞
tktk−1
∞ ttk
qt k
i1aiti
≤min b−ε bεL−
b−ε
M−N,b−ε bεM
b−ε N−L
.
2.34 Define two mappingsT1L, T2L:AM, N → Xby
T1Lxn
⎧⎪
⎪⎨
⎪⎪
⎩ L
bnd −xnd
bnd, n≥N0, T1LxN0, β≤n < N0, T2Lxn
⎧⎪
⎪⎨
⎪⎪
⎩
−1k bnd
∞ t1n
∞ t2t1
· · · ∞
tktk−1
∞ ttk
ft, xt−r1t, xt−r2t, . . . , xt−rst k
i1aiti
, n≥N0,
T2LxN0, β≤n < N0
2.35
for allx∈AM, N. The rest of the proof is analogous to that inTheorem 2.4. This completes the proof.
Similar to the proof ofTheorem 2.7, we have
Theorem 2.8. Assume that there exist constantsMandNwithN >1b/1bM >0 and sequences{ain}n≥n0 1≤i≤k,{bn}n≥n0,{hn}n≥n0,{qn}n≥n0, satisfying2.2–2.4and
bn <−1, eventually, −∞< bandb <−1. 2.36
Then1.11has a bounded nonoscillatory solution inAM, N.
Remark 2.9. Similar toRemark 2.2, we can also prove that the conditions of Theorems2.3–2.8 ensure that 1.11has not only one bounded nonoscillatory solution but also uncountably many bounded nonoscillatory solutions.
Remark 2.10. Theorems 2.1–2.8 extend and improve Theorem 1 of Cheng 6, Theorems 2.1–2.7 of Liu et al. 8, and corresponding theorems in 3,4,9–17.
3. Examples
In this section, two examples are presented to illustrate the advantage of the above results.
Example 3.1. Consider the following fourth-order nonlinear neutral delay difference equation:
Δ4nΔ3nΔ2nΔxn−xn−1 0, n≥1. 3.1
ChooseM1 andN2. It is easy to verify that the conditions ofTheorem 2.1are satisfied.
ThereforeTheorem 2.1ensures that3.1has a nonoscillatory solution inA1,2. However, the results in 3,4,6,8–17are not applicable for3.1.
Example 3.2. Consider the following third-order nonlinear neutral delay difference equation:
Δ
2n−nΔ
n2−n1 Δ
xn2n−1 3n xn−4
sin2xn−2
n2 −cos3xn−3
n3 0, n≥5, 3.2
where
a1nn2−n1, a2n2n−n, bn 2n−1 3n , fn, u1, u2 sin2u1
n2 −cos3u2
n3 , hnqn 2 n2.
3.3
ChooseM1 andN5. It can be verified that the assumptions ofTheorem 2.5are fulfilled.
It follows fromTheorem 2.5that3.2has a nonoscillatory solution inA1,5. However, the results in 3,4,6,8–17are unapplicable for3.2.
Acknowledgment
The authors are grateful to the editor and the referee for their kind help, careful reading and editing, valuable comments and suggestions.
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