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in PROBABILITY

STABILITY OF THE STOCHASTIC HEAT EQUATION IN L

1

([ 0, 1 ])

NICOLAS FOURNIER1

LAMA, CNRS UMR 8050, Université Paris-Est, 61 avenue du Général de Gaulle, 94010 Créteil Cedex, France

email: [email protected] JACQUES PRINTEMS

LAMA, CNRS UMR 8050, Université Paris-Est, 61 avenue du Général de Gaulle, 94010 Créteil Cedex, France

email: [email protected]

SubmittedFebruary 3, 2011, accepted in final formMay 29, 2011 AMS 2000 Subject classification: 60H15, 35B35

Keywords: Stochastic partial differential equations, White noise, Invariant distributions, Asymp- totic confluence, Stability, Long time behavior, Existence.

Abstract

We consider the white-noise driven stochastic heat equation on [0,∞)×[0, 1] with Lipschitz- continuous drift and diffusion coefficients. We derive an inequality for theL1([0, 1])-norm of the difference between two solutions. Using some martingale arguments, we show that this inequality provides some estimates which allow us to study the stability of the solution with respect the initial condition, the uniqueness of the possible invariant distribution and the asymptotic confluence of solutions.

1 Introduction and results

1.1 The equation

Consider the stochastic heat equation with Neumann boundary conditions:

∂tu(t,x) = ∂x xu(t,x) +b(u(t,x)) +σ(u(t,x))W˙(t,x), t≥0, x∈[0, 1], u(0,x) = u0(x), x∈[0, 1],

∂xu(t, 0) = ∂xu(t, 1) =0, t>0.

(1)

Here b,σ : R 7→ R are the drift and diffusion coefficients and u0 : [0, 1] 7→ R is the initial condition. We write formallyW(d t,d x) =W˙(t,x)d t d x, forW(d t,d x)a white noise on[0,∞)× [0, 1]based ond t d x, see Walsh[14]. We assume in this paper thatb,σare Lipschitz-continuous:

for some constantCb,σ,

1SUPPORTED DURING THIS WORK BY THE GRANT FROM THE AGENCE NATIONALE DE LA RECHERCHE WITH REFERENCE ANR-08-BLAN-0220-01.

337

(2)

for allr,z∈R, |b(r)−b(z)|+|σ(r)−σ(z)| ≤Cb,σ|r−z|. (H)

Our goals in this paper are the following:

• prove some new stability estimates of the solution with respect to the initial condition u0 ∈ L1([0, 1]);

•study the uniqueness of invariant measures and the asymptotic confluence of solutions.

Let us mention that our results extend without difficulty to the case of Dirichlet boundary condi- tions and to the case of the unbounded domainR(withu0∈L1(R)).

This equation has been much investigated, in particular since the work of Walsh [14]. In[14], one can find definitions of weak solutions, existence and uniqueness results, as well as proofs that solutions are Hölder-continuous, enjoy a Markov property, etc. Let us mention for example the works of Bally-Gyongy-Pardoux [1] (existence of solutions when the drift is only measurable), Gatarek-Goldys [7](existence of solutions in law), Donati-Pardoux (comparison results and re- flection problems), Bally-Pardoux (smoothness of the law of the solution), Bally-Millet-Sanz[3] (support theorem), etc. Sowers[13], Mueller[10]and Cerrai[4]have obtained some results on the invariant distributions and convergence to equilibrium.

We denote byLp([0, 1])the set of all measurable functionsf :[0, 1]7→Rsuch that||f||Lp([0,1])= (R1

0|f(x)|pd x)1/p<∞.

1.2 Mild solutions

We now define the classical notion of weak solutions we will use, see Walsh [14]. When we refer to predictability, this is with respect to the filtration(Ft)t≥0generated byW, that isFt = σ(W(A),A∈ B([0,t]×[0, 1])). We denote byGt(x,y)the Green kernel associated with the heat equation∂tu=∂x xuonR+×[0, 1]with Neumann boundary conditions, whose explicit form can be found in Walsh[14]. Here we will only use that for some constantCT, for allx,y∈[0, 1], all t∈(0,T], see[14],

0≤Gt(x,y) =Gt(y,x)≤ CT

pte−|x−y|2/4t, Z1

0

Gt(x,y)d x=1, Z1

0

G2t(x,y)d x≤ CT pt. (2) Definition 1. Assume(H)and consider u0 ∈ L1([0, 1]). We say that a predictable process u= (u(t,x))t≥0,x∈[0,1]with values inRis a mild solution to (1) starting from u0if

for all T >0, E

 Z T

0

Z1

0

u2(t,x)d x d t

<∞ (3) and if a.s., for a.e. t≥0, x∈[0, 1],

u(t,x) = Z 1

0

Gt(x,y)u0(y)d y+ Zt

0

Z1

0

Gt−s(x,y)[σ(u(s,y))W(ds,d y) +b(u(s,y))d y ds]. (4)

(3)

Da Prato-Zabczyk[5]have checked that for anyu0∈L2([0, 1]), there exists a unique mild solution uto (1). Using a similar approach, together with the estimate

ZT

0

Z1

0

 Z1

0

Gt(x,y)u0(y)d y

2

d x d t ≤ CT||u0||2L1([0,1]), (5) one easily checks that for anyu0∈L1([0, 1]), there exists a unique mild solution to (1). Further- more, for any pairu,vof mild solutions to (1) starting fromu0,v0∈L1([0, 1]), for anyT>0,

E

 ZT

0

Z1

0

(u(t,x)−v(t,x))2d x d t

≤CT,σ,b||u0−v0||2L1([0,1]), (6) whereCT,σ,b depends only on T and on the Lipschitz constants of σand b. We will prove (5) and (6) for the sake of completeness, which implies uniqueness. A similar approach allows one to prove existence.

1.3 Stability in L

1

([ 0, 1 ])

Our first goal is to prove the following stability estimates inL1([0, 1]).

Theorem 2. Assume(H). For u0,v0∈L1([0, 1]), consider the two mild solutions u and v to (1) starting from u0and v0.

(i) For allγ∈(0, 1), all T≥0, we have E

– sup

[0,T]||u(t)−v(t)||γL1([0,1])

™

≤Cb,γ,T||u0−v0||γL1([0,1]), where Cb,γ,T depends only on b,γ,T .

(ii) Assume now that b is non-increasing. For allγ∈(0, 1), we have Eh

sup

[0,∞)||u(t)−v(t)||γL1([0,1])+

‚Z ∞

0

||b(u(t))−b(v(t))||L1([0,1])d t

Œγ

+

‚Z ∞

0

||σ(u(t))−σ(v(t))||2L2([0,1])d t

Œγ/2

i≤Cγ||u0−v0||γL1([0,1]),

where Cγdepends only onγ.

Point (i), which shows some stability with respect to the initial condition, is complementary to (6): we can consider a supremum in time, but we can only deal with the L1-norm. Point (ii) is quite strong, since it provides some estimates on the time interval[0,∞). This will allow us to study the large time behavior of solutions whenbis non-increasing. To prove these estimates, we rather use theweakform of (1). It seems difficult to obtain such results working directly with the mildequation.

1.4 Large time behavior

We now wish to study the uniqueness of invariant measures.

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Definition 3. A probability measure Q on L1([0, 1])is said to be an invariant distribution for (1) if, for u0a L1([0, 1])-valued random variable with law Q independent of W , for u the mild solution to (1) starting from u0,L(u(t)) =Q for all t≥0.

Theorem 4. Assume(H), that b is non-increasing and that(σ,b):R7→R2is injective. Then (1) admits at most one invariant distribution.

To prove the asymptotic confluence of solutions, we need to strengthen the injectivity assumption.

There is a strictly increasing convex functionρ:R+7→R+withρ(0) =0 such

that for allr,z∈R, |b(r)−b(z)|+|σ(r)−σ(z)|2≥ρ(|r−z|). (I) Theorem 5. Assume(H), that b is non-increasing and(I).

(i) The following asymptotic confluence property holds: for u0,v0 ∈ L1([0, 1]), for u,v the mild solutions to (1) starting from u0and v0,

a.s., lim

t→∞||u(t)−v(t)||L1([0,1])=0.

(ii) Assume additionally that (1) admits an invariant distribution Q. Then for any u0∈L1([0, 1]), for u the mild solution to (1) starting from u0, u(t)goes in law to Q as t→ ∞.

Clearly,(I)holds if bisC1withb0≤ −ε <0 (chooseρ(z) =εz) or ifσisC1with|σ0| ≥ε >0 (chooseρ(z) = (εz)2). One may also combine conditions on bandσ. But(I)also holds if bis C1and ifb0≤0 vanishes reasonably. For example ifb(z) =−sg(z)min(|z|,|z|p)for somep≥1, chooseρ=ερp withεsmall enough and ρp(z) =zp forz ∈[0, 1] andρp(z) = pz−p+1 for z≥1. If b(z) =−z−sinz, chooseρ=ερ3withεsmall enough.

One may also consider the case whereσis monotonous withσ0vanishing reasonably.

Observe that the asymptotic confluence of solutions may hold even if there is no invariant distri- bution for (1). Consider e.g. the case where b(x)≥c>0 is non-increasing andσ(x) =x. Then (I)holds, while solutions should tend to infinity (due to the uniformly positive drift).

Let us now compare Theorems 4 and 5 with known results. The works cited below sometimes concern different boundary conditions, but we believe this is not important.

• Sowers[13]has proved the existence of an invariant distribution supported by C([0, 1]), as- suming(H), thatσis bounded and thatbis of the form b(z) =−αz+f(z), for some bounded f and someα >0. He obtained uniqueness of this invariant distribution whenσis sufficiently small and bounded from below.

•Mueller[10]has obtained some surprising coupling results, implying in particular the unique- ness of an invariant distribution as well as a the trend to equilibrium. He assumes(H), thatσis bounded from above and from below and that bis non-increasing, with|b(z)−b(r)| ≥α|z−r| for someα >0.

•Cerrai[4]assumed thatσis strictly monotonous (it may vanish, but only at one point).

(i) She obtained an asymptotic confluence result which we do not recall here and concerns, roughly, the caseb(z)' −sg(z)|z|masz→ ±∞, for somem>1.

(ii) Assuming(H), she proved uniqueness of the invariant distribution as well as an asymptotic confluence property, under the conditions that for all r≤z, b(z)−b(r)≤λ(z−r), and|σ(z)− σ(r)| ≥µ|z−r|, for someµ >0 and someλ < µ2/2 (ifbis non-increasing, chooseλ=0).

(5)

Thus the main advantages of the present paper are that the uniqueness of the invariant measure requires very few conditions, and we allowσto vanish (it may be compactly supported).

Example 1. Assume(H)and that bstrictly decreasing. Then there exists at most one invariant distribution. If b(z) = −z or b(z) = −z−sinz or b(z) =−sg(z)min(|z|,|z|p)for some p > 1, then we have asymptotic confluence of solutions. Here to apply[13, 10]one needs to assume additionally thatσis bounded from above and from below, while to apply[4], one has to suppose thatσis strictly monotonous.

Example 2. Assume(H), that bis non-increasing and thatσis strictly monotonous. Then there exists at most one invariant distribution.

If furthermoreσisC1with 0<c< σ0<C, then we get asymptotic confluence of solutions using [4]or Theorem 5 (here[13,10]cannot apply, sinceσvanishes). But now ifσ0 ≥0 reasonably vanishes then Theorem 5 applies, which is not the case of[4]: take e.g.σ(z) =sg(z)min(|z|,|z|p) for somep>1, orσ(z) =z+sinz.

Example 3.Consider the compactly supported coefficientσ(z) = (1−z2)1{|z|≤1}. Assume thatbis C1, non-increasing, withb0(z)≤ −ε <0 forz∈(−∞,−1)∪ {0} ∪(1,+∞). Then Theorems 4 and 5 apply, while[13,10,4]do not.

Ifb(z0) =0 for somez0∈/(−1, 1), thenu(t)≡z0is the (unique) stationary solution.

If now b(−1)>0 and b(1)<0, then the invariant measureQ(that exists due to Sowers[13]) is unique and one may show, using the comparison Theorem of Donati-Pardoux[6], that Q is supported by[−1, 1]-valued continuous functions on[0, 1].

However, there are some cases where[13,4]provide some better results than ours.

Example 4.Ifσ(z) =µzandb(z) =λz, thenu(t)≡0 is an obvious stationary solution. Theorems 4 and 5 apply ifλ≤0 and|λ|+|µ|>0. Cerrai[4]was able to treat the caseλ >0 provided µ2/2> λ.

Example 5. Ifσis small enough and bounded from below and if b(z) =−αz+h(z), withα >0 andhbounded, then Sowers[13]obtains the uniqueness of the invariant distribution even ifbis not non-increasing.

1.5 Plan of the paper

In the next section, we briefly prove (5) and (6). Section 3 is devoted to the proof of Theorem 2.

Theorems 4 and 5 are checked in Section 4. We briefly discuss the multi-dimensional equation in Section 5 and conclude the paper with an appendix containing technical results.

2 Mild solutions

In the whole section,T >0 is fixed. Foru0∈L1([0, 1])andt∈[0,T], we easily get, using the Cauchy-Schwarz inequality in yand integrating inx using (2):

Z1

0

Z1

0

Gt(x,y)u0(y)d y

!2

d x ≤ ||u0||L1([0,1])

Z1

0

Z1

0

G2t(x,y)|u0(y)|d y d x

≤ CT

pt||u0||2L1([0,1]). (7)

(6)

This implies (5). Consider now two mild solutionsu,vto (1) starting fromu0,v0∈L1([0, 1]). Put δ(t,x) = E[|u(t,x)−v(t,x)|2], d(t) =R1

0δ(t,x)d x and D(t) = Rt

0d(s)ds. A straightforward computation using (4) and(H)shows that for allx∈[0, 1], allt∈[0,T],

δ(t,x)≤2 Z1

0

Gt(x,y)|u0(y)−v0(y)|d y

!2

+CT,σ,b Z t

0

Z1

0

G2t−s(x,y)δ(s,y)d y ds.

Integrating inxusing (7) and (2), we deduce that for allt∈[0,T], d(t)≤ CT

pt||u0−v0||2L1([0,1])+CT,σ,b Zt

0

d(s) pt−sds.

Iterating once this formula and using that for all 0≤r≤t,Rt r

p ds t−sp

s−r =R1 0

p d x xp

1−x<∞, d(t) ≤ CT

pt||u0−v0||2L1([0,1])+CT,σ,b Zt

0

||u0−v0||2L1([0,1])

psp

t−s ds +CT,σ,b

Z t

0

Zs

0

d(r) pt−sp

s−rd r ds

≤ CT,σ,b

pt ||u0−v0||2L1([0,1])+CT,σ,b Zt

0

d(r)d r.

Finally, integrating in t yields D(t) ≤ CT,σ,b||u0−v0||2L1([0,1])+CT,σ,bRt

0D(s)ds. The Gronwall Lemma implies thatD(T)≤CT,σ,b||u0−v0||2L1([0,1]). We have checked (6).

3 On the L

1

([ 0, 1 ]) -norm of the difference between two mild solutions

The aim of this section is to prove Theorem 2. We first consider continuous initial conditions, and then extend the estimates to general L1([0, 1])initial conditions. All our study is based on the following result. We set sg(z) =1 forz≥0 and sg(z) =−1 forz<0.

Proposition 6. Assume(H). For two continuous initial conditions u0,v0, let u,v be the correspond- ing mild solutions to (1). Then, enlarging the probability space if necessary, there is a Brownian motion(Bt)t≥0such that a.s., for all t≥0,

||u(t)−v(t)||L1([0,1]) ≤ ||u0−v0||L1([0,1])+ Zt

0

||σ(u(s))−σ(v(s))||L2([0,1])d Bs (8) +

Zt

0

Z1

0

sg(u(s,x)−v(s,x))(b(u(s,x))−b(v(s,x)))d x ds.

Proof. We divide the proof into several steps, following closely the ideas of Donati-Pardoux [6, Theorem 2.1], to which we refer for technical details.

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Step 1.Consider an orthonormal basis(ek)k≥1ofL2([0, 1]). Fork≥1, we setBkt =Rt 0

R1

0ek(x)W(ds,d x). Then(Bk)k≥1is a family of independent Brownian motions. Forn≥1, consider the unique adapted solutionun∈L2(Ω×[0,T],V), whereV ={f ∈H1([0, 1]),f0(0) =f0(1) =0}, to

un(t,x) =u0(x) + Z t

0

∂x xun(s,x)ds+b(un(s,x))ds+

n

X

k=1

Z t

0

σ(un(s,x))ek(x)d Bsk.

We refer to Pardoux[11]for existence, uniqueness and properties of this solution. We also con- sider the solutionvnto the same equation starting fromv0. Then, as shown in[6],

limn sup

[0,T]×[0,1]E[|un(t,x)−u(t,x)|2+|vn(t,x)−v(t,x)|2] =0. (9) Step 2.Forε >0, we introduce a nonnegativeC2functionφεsuch thatφε(z) =|z|for|z| ≥ε, with

|φε0(z)| ≤1 and 0≤φ00ε(z)≤2ε−11{|z|<ε}. When applying the Itô formula (see[6]for details), we get

Z1

0

φε(un(t,x)−vn(t,x))d x= Z1

0

φε(u0(x)−v0(x))d x (10) +

Z t

0

Z1

0

φ0ε(un(s,x)−vn(s,x))∂x x[un(s,x)−vn(s,x)]d x ds

+ Z t

0

Z1

0

φ0ε(un(s,x)−vn(s,x))[b(un(s,x))−b(vn(s,x))]d x ds

+

n

X

k=1

Z t

0

Z1

0

φε0(un(s,x)−vn(s,x))[σ(un(s,x))−σ(vn(s,x))]ek(x)d x d Bsk

+1 2

n

X

k=1

Zt

0

Z1

0

φε00(un(s,x)−vn(s,x))[σ(un(s,x))−σ(vn(s,x))]2e2k(x)d x ds

=:Iε1+Iε2(t) +Iε3(t) +Iε4(t) +Iε5(t). Since|z| ≤φε(z)≤ |z|+εfor allz, we easily get, a.s.,

limε→0

Z1

0

φε(un(t,x)−vn(t,x))d x =||un(t)−vn(t)||L1([0,1]) and lim

ε→0Iε1=||u0−v0||L1([0,1]). An integration by parts, using that∂x[un(t, 0)−vn(t, 0)] =∂x[un(t, 1)−vn(t, 1)] =0 shows that

Iε2(t) =− Z t

0

Z1

0

φε00(un(s,x)−vn(s,x))[∂x(un(s,x)−vn(s,x))]2≤0.

Sinceφε00(z−r)(σ(z)−σ(r))2≤ Cε−11{|z−r|≤ε}|z−r|2 ≤ Cεby (H), we have Iε5(t) ≤ C ntε, whence

ε→0limIε5(t) =0 a.s.

(8)

Using that|φ0ε(z)−sg(z)| ≤1{|z|≤ε}and(H), one obtains a.s.

ε→0lim

Iε3(t)− Z t

0

Z1

0

sg(un(s,x)−vn(s,x))(b(un(s,x))−b(vn(s,x)))d x ds

≤ lim

ε→0

Zt

0

Z1

0

1{|un(s,x)−vn(s,x)|≤ε}|b(un(s,x))−b(vn(s,x))|d x ds≤lim

ε→0C tε=0.

Similarly,

limε→0E

Iε4(t)−

n

X

k=1

Zt

0

Z1

0

sg(un(s,x)−vn(s,x))[σ(un(s,x))−σ(vn(s,x))]ek(x)d x d Bks

!2

≤lim

ε→0E

n

X

k=1

Z t

0

Z1

0

1{|un(s,x)−vn(s,x)|≤ε}[σ(un(s,x))−σ(vn(s,x))]2e2k(x)d x ds

≤lim

ε→0C t nε2=0.

Thus we can pass to the limit asε→0 in (10) and get, a.s.,

||un(t)−vn(t)||L1([0,1])≤ ||u0−v0||L1([0,1])

+ Z t

0

Z1

0

sg(un(s,x)−vn(s,x))[b(un(s,x))−b(vn(s,x))]d x ds +

n

X

k=1

Z t

0

Z1

0

sg(un(s,x)−vn(s,x))[σ(un(s,x))−σ(vn(s,x))]ek(x)d x d Bsk. (11) Step 3.Using(H), there holds, for allr1,z1,r2,z2inR,

sg(r1−z1)[σ(r1)−σ(z1)]−sg(r2−z2)[σ(r2)−σ(z2)]

≤C(|r1−r2|+|z1−z2|), (12)

sg(r1−z1)[b(r1)−b(z1)]−sg(r2−z2)[b(r2)−b(z2)]

≤C(|r1−r2|+|z1−z2|). (13) Indeed, it suffices, by symmetry, to check that

sg(r1−z1)[σ(r1)−σ(z1)]−sg(r2−z1)[σ(r2)− σ(z1)]

≤C|r1−r2|. If sg(r1−z1) =sg(r2−z2), this is obvious. If nowr1≤z1≤r2(orr1≥z1≥r2) we get the upper-bound|σ(r1) +σ(r2)−2σ(z1)| ≤C(|r1−z1|+|r2−z1|) =C|r1−r2|.

Using (9), it is thus routine to makentend to infinity in (11) and to obtain, a.s.,

||u(t)−v(t)||L1([0,1])≤ ||u0−v0||L1([0,1])

+ Zt

0

Z1

0

sg(u(s,x)−v(s,x))[b(u(s,x))−b(v(s,x))]d x ds +

X∞

k=1

Zt

0

Z1

0

sg(u(s,x)−v(s,x))[σ(u(s,x))−σ(v(s,x))]ek(x)d x d Bsk. (14) For the last term, we used that, by the Plancherel identity, setting for simplicity

αn(s,x) = sg(un(s,x)−vn(s,x))[σ(un(s,x))−σ(vn(s,x))], α(s,x) = sg(u(s,x)−v(s,x))[σ(u(s,x))−σ(v(s,x))],

(9)

there holds

EhXn

k=1

Z t

0

Z1

0

αn(s,x)ek(x)d Bsk− X∞

k=1

Zt

0

Z1

0

α(s,x)ek(x)d Bsk2i

≤ Z t

0

Eh X

k≥1

Z1 0

nαn(s,x)−α(s,x)o

ek(x)d x2i ds

+ X

k≥n+1

Zt

0

EhZ1 0

α(s,x)ek(x)d x2i ds

≤ Z t

0

Eh

||αn(s)−α(s)||2L2([0,1])

ids

+ X

k≥n+1

Zt

0

EhZ1 0

α(s,x)ek(x)d x2i

ds=:In(t) +Jn(t).

Using (12) and then (9),In(t)≤CRt 0

R1

0E[|un(s,x)−u(s,x)|2+|vn(s,x)−v(s,x)|2]d x dstends to 0 asn→ ∞. Finally,Jn(t)tends to 0 becauseP

k≥1

Rt 0E[(R1

0α(s,x)ek(x)d x)2]ds=Rt

0E[||α(s)||2L2([0,1])]ds≤ CRt

0

R1

0E(|u(s,x)−v(s,x)|2)d x ds<∞.

Step 4.A standard representation argument (see e.g. Revuz-Yor[12, Proposition 3.8 and Theorem 3.9 p 202-203]) concludes the proof, because the last term on the RHS of (14) is a continuous local martingale with bracket

Zt

0

X∞

k=1

Z1

0

sg(u(s,x)−v(s,x))[σ(u(s,x))−σ(v(s,x))]ek(x)d x

!2

ds

= Zt

0

||σ(u(s))−σ(v(s))||2L2([0,1])ds.

We used here again that(ek)k≥1is an orthonormal basis ofL2([0, 1]). Corollary 7. Adopt the notation and assumptions of Proposition 6.

(i) For allγ∈(0, 1), all T≥0, E

– sup

[0,T]||u(t)−v(t)||γL1([0,1])

™

≤Cb,γ,T||u0−v0||γL1([0,1]), where Cb,γ,T depends only on b,γ,T .

(ii) Assume that b is non-increasing. Then for allγ∈(0, 1), Eh

sup

[0,∞)||u(t)−v(t)||γL1([0,1])+

‚Z ∞

0

||b(u(t))−b(v(t))||L1([0,1])d t

Œγ

+

‚Z ∞

0

||σ(u(t))−σ(v(t))||2L2([0,1])d t

Œγ/2

i≤Cγ||u0−v0||γL1([0,1]),

where Cγdepends only onγ.

(10)

Proof. Let us first prove point (i). LetCbbe the Lipschitz constant of b. Denote byLt the RHS of (8). The Itô formula yields

||u(t)−v(t)||L1([0,1])e−Cbt≤Lte−Cbt

=||u0−v0||L1([0,1])−Cb Z t

0

e−CbsLsds

+ Z t

0

||σ(u(s))−σ(v(s))||L2([0,1])e−Cbsd Bs

+ Z t

0

Z1

0

e−Cbssg(u(s,x)−v(s,x))(b(u(s,x))−b(v(s,x)))d x ds.

ButR1

0sg(u(s,x)−v(s,x))(b(u(s,x))−b(v(s,x)))d x≤Cb||u(s)−v(s)||L1([0,1])≤CbLs. Hence

||u(t)−v(t)||L1([0,1])e−Cbt ≤ ||u0−v0||L1([0,1])+ Zt

0

||σ(u(s))−σ(v(s))||L2([0,1])e−Cbsd Bs.

The right hand sideMtof this inequality is a nonnegative continuous local martingale starting from

||u0−v0||L1([0,1]), whence by Lemma 8, for anyγ∈(0, 1),E”

sup[0,∞)Mγt—

≤Cγ||u0−v0||γL1([0,1]). We deduce that

E

– sup

[0,∞)

||u(t)−v(t)||γL1([0,1])e−Cbγt™

≤Cγ||u0−v0||γL1([0,1]). Point (i) immediately follows (withCb,γ,T=CγeCbγT).

We now check point (ii). Sincebis non-increasing, Proposition 6 yields

||u(t)−v(t)||L1([0,1])+ Z t

0

||b(u(s))−b(v(s))||L1([0,1])ds

≤ ||u0−v0||L1([0,1])+ Zt

0

||σ(u(s))−σ(v(s))||L2([0,1])d Bs=:Nt,

which is a nonnegative continuous local martingale starting from ||u0−v0||L1([0,1]) with bracket

〈N〉t =Rt

0||σ(u(s))−σ(v(s))||2L2([0,1])ds. Due to Lemma 8, E[sup[0,∞)Ntγ+〈N〉γ/2∞ ]≤ Cγ||u0− v0||γL1([0,1])holds true for allγ∈(0, 1). Hence

E

– sup

[0,∞)||u(t)−v(t)||γL1([0,1])

™

≤ E

– sup

[0,∞)

Ntγ

™

≤Cγ||u0−v0||γL1([0,1]), E

–‚Z∞

0

||b(u(t))−b(v(t))||L1([0,1])d t

Œγ™

≤ E

– sup

[0,∞)

Ntγ

™

≤Cγ||u0−v0||γL1([0,1]),

E

‚Z ∞

0

||σ(u(t))−σ(v(t))||2L2([0,1])d t

Œγ/2

 = E”

〈N〉γ/2∞ —

≤Cγ||u0−v0||γL1([0,1]). This ends the proof.

(11)

Finally, we extend the previous estimates to general initial conditions.

Proof of Theorem 2.We divide the proof into two steps.

Step 1. Letube the mild solution to (1) starting fromu0 ∈L1([0, 1]). Consider a sequence of continuous initial conditions(un0)n≥1 such that ||un0−u0||L1([0,1]) ≤ 2−n, and the corresponding sequence(un)n≥1of mild solutions to (1) starting fromun0. The aim of this step is to check that for anyT>0,

a.s., limn→∞sup[0,T]||un(t)−u(t)||L1([0,1])=0, (15) limn→∞EhRT

0 ||un(t)−u(t)||2L2([0,1])d ti

=0. (16)

First, (16) follows immediately from (6). Next, we use Corollary 7-(i) (withγ=1/2) to deduce that

E

 X

n≥1

sup

[0,T]||un+1(t)−un(t)||1/2L1([0,1])

≤Cb,γ,TX

n≥1

||un0+1−u0n||1/2L1([0,1])<∞. As a consequence,P

n≥1sup[0,T]||un+1(t)−un(t)||1/2L1([0,1])<∞a.s., which finally implies that a.s., P

n≥1sup[0,T]||un+1(t)−un(t)||L1([0,1]) < ∞. Using some completeness arguments, we deduce that there is a processvsuch that a.s., for allT >0, limnsup[0,T]||un(t)−v(t)||L1([0,1])=0. But recalling (16), we necessarily havev=u, which ends the step.

Step 2. We now prove the desired estimates. Foru0 and v0 in L1([0, 1]), we consider un0 and v0n continuous with ||un0−u0||L1([0,1])+||v0n−v0||L1([0,1]) ≤ 2−n. We denote by u,v,un,vn the corresponding mild solutions to (1). For eachn≥1, we may apply Corollary 7-(i) toun,vn. Using the Fatou Lemma and Step 1, we deduce that for allT >0, allγ∈(0, 1),

E

– sup

[0,T]||u(t)−v(t)||γL1([0,1])

™

≤ lim inf

n E

– sup

[0,T]||un(t)−vn(t)||γL1([0,1])

™

≤ lim inf

n Cb,γ,T||u0n−v0n||γL1([0,1])=Cb,γ,T||u0−v0||γL1([0,1]). If furthermore b is non-increasing, we get similarly, using Corollary 7-(ii), for any T > 0, any γ∈(0, 1),

E

– sup

[0,T]||u(t)−v(t)||γL1([0,1])

™

≤Cγ||u0−v0||γL1([0,1]).

Since Cγ does not depend on T, we can let T increase to infinity. Next, using again Step 1, Corollary 7-(ii) and(H), we deduce that for anyT>0, anyγ∈(0, 1),

E

 ZT

0

||b(u(t))−b(v(t))||L1([0,1])d t

!γ

+ Z T

0

||σ(u(t))−σ(v(t))||2L2([0,1])d t

!γ/2

= lim

n Eh Z T

0

||b(un(t))−b(vn(t))||L1([0,1])d t

!γ

+ ZT

0

||σ(un(t))−σ(vn(t))||2L2([0,1])d t

!γ/2

i

≤ lim

n Cγ||un0−v0n||γL1([0,1])=Cγ||u0−v0||γL1([0,1]).

(12)

To conclude the proof, it suffices to letT increase to infinity. ƒ

4 Large time behavior

We now prove the uniqueness of the invariant measure.

Proof of Theorem 4. Consider two invariant distributionsQand ˜Qfor (1), see Definition 3. Letu0 beQ-distributed and ˜u0be ˜Q-distributed. Consider the corresponding (stationary) mild solutions u, ˜uto (1). Applying Theorem 2-(ii) and the Cauchy-Schwarz inequality,R∞

0 Ksds<∞a.s., where Ks:=K(u(s), ˜u(s)) =||b(u(s))−b(˜u(s))||L1([0,1])+||σ(u(s))−σ(u˜(s))||2L1([0,1]).

Using Lemma 9, there is a (deterministic) sequence(tn)n≥1such thatKt

ntends to 0 in probability.

Consider the functionφ(r) =r/(1+r)onR+, and defineΨ:L1([0, 1])×L1([0, 1])7→[0, 1]as Ψ(f,g) =φ(K(f,g)). Then limnE[Ψ(u(tn),v(tn))] =limnE[φ(Ktn)] =0.

We now apply Lemma 10. The space L1([0, 1])is Polish and for eachn≥1,L(u(tn)) =Q and L(˜u(tn)) = Q. The function˜ Ψ is clearly continuous on L1([0, 1])× L1([0, 1]), (because σ,b are Lipschitz-continuous). Finally, Ψ(f,g)> 0 for all f 6= g (because Ψ(f,g) = 0 implies that b◦f =b◦gandσ◦f =σ◦ga.e., whence f = ga.e. since(σ,b)is injective). Lemma 10 thus

yieldsQ=Q.˜ ƒ

Finally, we give the

Proof of Theorem 5. Point (ii) is immediately deduced from point (i). Let thusu0,v0∈L1([0, 1]) be fixed and letu,vbe the corresponding mild solutions to (1). We know from(I), the Jensen inequality and Theorem 2-(ii) that a.s.,

Z∞

0

ρ(||u(t)−v(t)||L1([0,1]))d t≤ Z∞

0

||ρ(|u(t)−v(t)|)||L1([0,1])d t

≤ Z∞

0

|b(u(t))−b(v(t))|+|σ(u(t))−σ(v(t))|2

L1([0,1])d t<∞.

Using Lemma 9, one may thus find an increasing (deterministic) sequence (tn)n≥1 such that ρ(||u(tn)−v(tn)||L1([0,1]))tends to 0 in probability, so that ||u(tn)−v(tn)||L1([0,1]) also tends to 0 in probability (because due toI,ρis strictly increasing and vanishes only at 0). Next, we use Theorem 2-(ii) with e.g.γ=1/2 to get, setting∆t=sup[t,∞)||u(s)−v(s)||L1([0,1]),

E

•∆1/2tn

Ftn

˜

≤C||u(tn)−v(tn)||1/2L1([0,1])→0 in probability.

We used here that conditionally onFtn,(u(tn+t,x))t≥0,x∈[0,1] is a mild solution to (1), starting fromu(tn)(with a translated white noise). Thus for anyε >0, using the Markov inequality

P”

∆tn> ε—

=E” P€

∆tn> ε Ftn

Š—≤E

• min



1,ε−1/2E

•∆1/2tn

Ftn

˜‹˜

, which tends to 0 asn→ ∞by dominated convergence. Consequently, asntends to infinity,

∆tntends to 0 in probability. (17)

But a.s.s7→∆s=sup[s,∞)||u(t)−v(t)||L1([0,1])is non-increasing, and thus admits a limit ass→ ∞,

which can be only 0 due to (17). ƒ

参照

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