The
Structure of Fully Prime Rings Under Ascending Chain Conditions
HisayaTsutsui Departmentof Mathematics Embry-Riddle Aeronautical University
Prescott,AZ USA
E-mail address:[email protected]
O. Introduction
Definition A ring$R$ (possiblywithoutidentity)inwhichevery idealis prime $(i.e$. every properideal isaprime ideal and(hence)$R$ isaprimering) iscalledafully prime ring.
The
purpose
ofmytalk atthe conferencewas
tointroducethestudy offully prime rings and presenta
fewopenproblems toa
widerrange
ofaudience. Inthispaper,a
briefsurvey
of resultsonthe structure offullyprime rings with severalexamples is presented.Ourinvestigationfor the structure of fullyprime ringswas initiallymotivated bya
well-known fact thatacommutativefullyprime ringwith identityisa field. Wefirst publisheda
seriesofpapers
on
the subject in 1994 and 1996(Blair-Tsutsui[l], Tsutsui [7]).Conditions similartothe fullyprime condition have receivedattentionin literature. Hirano [3] studied those ringsinwhicheveryideal is completelyprime. Courter[2] studied those ringsin whicheveryidealis semiprime, and Koh [6] studied thoserings in which everyrightideal is prime. More recently,Hirano-Tsutsui [5] studiedrings in which every ideal is $n$-primary, and
Hirano-Poon-Tsutsui [4] studied those ringsin whicheveryidealisweaklyprime. Formany
yearsafter
our
initialpublications,our
focus has been todetermine the structureof noncommutativeright and left Noethrian fullyprime ring.Throughout thisarticle,
we
assume
a
ringtobeassociativebutnotnecessarilycommutative. Due to the considerationthatan
idealofaring beinga
ringofitsown,we
do notassume
the existenceofamultiplicative identityon aringunlessotherwise so stated.Theorem 1 (Blair-Tsutsui [1]). The center ofa hllyprimeringiseither
a
fieldor
zero,anda
ring$R$ is fully primeifand onlyifevery(two sided)ideal $ofR$ is idempotentand thesetofideals$ofR$is totallyorderedunder inclusion.
Inparticular,
as
is wellknown,a
commutative $m[ly$prime ring with identity isa
field.Examples ofanon-commutativefullyprimering include thering ofendomorphisms
$Hom_{D}(V,V)$ofa vector
space
$V$over a
divisionringD.(Thiscan
easily be verifiedby thetheoremabove.)Denotethe cardinality of
a
denumerablesetby $N_{0}$, and foranyinteger $n\geq 1,$let $\dim_{D}V=\aleph_{n-1}$
.
Then is $fu$]$ly$primewithexactly $k$non-zero
properideals$I_{N_{0}}=\{f\in Hom_{D}(V,V)|\dim f(V)<\aleph_{n}\},$ $n=0,2,\ldots,k-1$
.
If$\dim_{D}V=\aleph_{a}b$where $\omega_{0}$ is thefirstlimitordinal,then $Hom_{D}(V,V)$ is
a
$fi\iota 11y$prime ring that has countablymanyideals.Everyrightideal, and henceeveryideal ofaregularring isidempotentandfor
a
regular self-injectiverings$R$,an
ideal $P$is prime if andonly ifRIP is totally ordered. Since there existsa
regularself-injectivering $T$with
a
primeideal$P$such that thesetof ideals of$TlP$isnotwell-ordered,the setof ideals of
a
$fiJ[1y$prime ring isnot necessarilywell-ordered.Blair-Tsutsui[l] gives
an
example ofafully prime ring(withexactlyone
nonzero
properideal) whichisnotprimitive. A ring$R$is called fully isomorphic if$RlI$isisomorphicto$R$for
everyproperideal$I$of$R$
.
Non-commutative hlly isomorphicringsare
fullyprime,and thereexists
an
exampleofa
non-commutativefully isomorphic ring with infinitelymanyideals, from whichan
example ofa non-primitive fully prime ringwith identitywithinfinitely many idealsmayalsobeconstructed.Let$F$be
a
field, and$R$be thesetofall infinitematricesover
$F$that havetheform$[^{A}0bcbc0$ $]$
where$A$ is
an
arbitrary$2n$by$2n$matrix and $b$and$c$are
anyelements of$F$.
Then$R$ isa
prime ringallofwhose idealsare
idempotent that contains non-primeideals.Problem 1. Underwhatconditions,wouldaprime ring inwhichevery idealis idempotent be
Theorem2 (Blair-Tsutsui [1]). Let$R$be
a
fullyprime ring. Thenevery ideal$ofR$is fullyprime when it is consideredas aring without identity. Every ideal ofan ideal of$R$is
an
ideal$ofR$
.
Further,a
properideal$ofR$cannotbea
ringwithidentity.If $P$is
a
proper
ideal ofa fullyprime ring$R$with identity and$F$isa
subfield ofthecenterof$R$,then
$S_{P}=F+P$ is
a
fullyprime ring whose maximal ideal$P$is alsoa
maximalright and leftideal.Further, properideals$ofS$are
preciselythose ideals$ofR$thatare
containedin$P.$Theorem3 (Blair-Tsutsui [1]). $S_{P}=F+P$ is right primitive ifand only$ifR$is right primitive.
$S_{P}$ is semiprimitiveif and only if$R$is semiprimitive.
2. Right Noetherian Fully Prime Rings
Inthis section,
we assume
thata
ring hasa
multiplicative identity.Theorem4(Blair-Tsutsui [1]). Afullyprime, right fully bounded right Noetherian ring is simpleArtinian.
More generally, aprime rightfully bounded right Noetherianring, all ofwhose idealsare
idempotent, is
a
simple Artinian ring(Tsutsui [7]).Asshownin Blair-Tsutsui [1],
a
fullyprime ringis, in general, notsemiprimitive. By Nakayama’slemma,it isevident, however, thatarightNoetherian fullyprime ring is semiprimitive.Further,an
inductionargumenton
the Krulldimensionyields the following result.Theorem5(Tsutsui [8]). A fullyprime ringwith right Krull dimension is semiprimitive.
Let $A_{1}(k)be$thefirst Weyl algebraover
a
fieldofcharacteristic O. Then $S=k+xA_{1}(k)is$aright and leftNotherian fullyprime ringwith exactly
one nonzero
proper
ideal $xA_{1}(k)$.
Thus,Noetherian$fi_{J}11y$prime ring isnotnecessarilyasimple ring.
Theorem6(Tsutsui [8]). Let $S=k+xA_{1}(k)$where the characteristic of$k$ is
zero.
Thenthe idealizer ofanymaximal right ideal$M$of$S$different from $xA_{1}(k)$isnota
fully primering.Whether thereexists
a
fullyprime rightNoetherianringwithmore
thanone nonzero
proper
idealsremainsa
tantalizingopenquestion. Let $R=k+xA_{1}(k)\otimes_{k}(k+xA_{1}(k))$.
Then $R$ hasexactly two
nonzero
properideals $xA_{1}(k)\otimes_{k}xA_{1}(k)$ and $x4(k)\otimes_{k}(k+xA_{1}(k))$and$R$is a fUlly prime ring.Problem 2. Is $R=k+xA_{1}(k)\otimes_{k}(k+xA_{1}(k))$
a
right Noetherian ring?Theorem 7.(Tsutsui [8]). Afully prime ring with identity that has
a
rightKrull dimension anda
minimalnonzero
ideal is arightprimitivering.Let $R$ bearing with identity and $\mathfrak{M}_{R}$bethe class of allright$R$-modules. The class of
modulesthat
are
closed under takingfactors, sum, extensions, and submodules is calleda
hereditarytorsion class. Ahereditary torsion class is calledaTTF-classifit is also closed undertaking direct products. Itis well-known that $s^{arrow}$ isa
TTF-class ifand onlyif$s^{\sim}=\{M\in \mathfrak{M}_{R}|MI=0\}$for
some
idempotent ideal$I$of$R$.
Sinceevery
ideal $P$ ofafUllyprime ring $R$ is idempotent and theset ofidealsis linearlyordered,the TTF-classes
$K_{P}=\{M\in \mathfrak{M}_{R}|MP=0\}$ofa ffilly prime ring $R$
are
linearly ordered. Let$\mathfrak{A}=\bigcup_{0\neq P\triangleleft R}K_{P}$where
$R$ is afullyprimering. Itisevident that $\mathfrak{A}$isahereditarytorsionclass. Let $\overline{\mathfrak{A}}$
bethe smallest TTF-class Containing$\mathfrak{A}$
.
Thensince $K_{P}\subseteq\overline{\mathfrak{A}}$forevery
nonzero
ideal$P,$$\overline{\mathfrak{A}}=K_{\bigcap_{0\neq P\triangleleft R}P}$
.
Consideringa
module representationof$R$ in $\overline{\mathfrak{A}}_{\rangle}$
we are
stronglyhopefulto prove,bycontradiction, thata
fullyprime ring is primitiveifand only ifitissemiprimitive. Thisresult, ifaffirmative, will in particular implythata
fullyprime ring is primitiveifitis
von
Neumannregular. Itwould alsoimply thata
fullyprime right Noetherian ring isprimitive withfinitelymanyideals.Acknowledgement
IsincerelythankProfessor Tsunekazu Nishinakafor theinvitationandhis superb hospitality duringthe conferenceand
our
research meetings inJapanthisyear.References
[1] W.D.BlairandH. Tsutsui, Fully Prime Rings, Comm. Algebra(1994).
[3] Y. Hirano, Onringsall
ofwhose
factor
ringsaredomain. J.Austral.Math.Soc. (1993).[4] Y. Hirano, E.Poon, and H.Tsutsui, Onrings inwhicheveryidealisweaklyprime,
Bulletin, KMSVo147,No.5 (2010).
[5] Y. HiranoandH.Tsutsui,Fully$k$-primaryrings, Comm.Algebra(2009).
[6] K. Koh, Onone-sided idealsofprime type, Proc. Amer. Math Soc. (1971). [7] H. Tsutsui,Fully Prime Rings$\Pi$, Comm. Algebra22 (1996).