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FAMILIES ON THE REAL LINE

ADINA LUMINIT¸A SASU

Received 20 October 2004; Accepted 26 September 2005

We give necessary and sufficient conditions for uniform exponential dichotomy of evolu- tion families in terms of the admissibility of the pair (Lp(R,X),Lq(R,X)). We show that the admissibility of the pair (Lp(R,X),Lq(R,X)) is equivalent to the uniform exponential dichotomy of an evolution family if and only ifpq. As applications we obtain charac- terizations for uniform exponential dichotomy of semigroups.

Copyright © 2006 Adina Luminit¸a Sasu. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

1. Introduction

Exponential dichotomy is one of the most important asymptotic properties of evolution equations (see [1–5,7–10,12,15,19–25]). In the last few years new concepts of exponen- tial dichotomy have been introduced and characterized, using discrete and continuous- time methods.

Integral equations have proved to be significant tools in the study of the asymptotic be- haviour ofC0-semigroups, evolution families, and linear skew-product flows, respectively (see [7–10,19–21,23,24]). For an evolution familyᐁ= {U(t,s)}t,sJ,ts, one considered the integral equation

f(t)=U(t,s)f(s) + t

sU(t,τ)v(τ)dτ, ts,t,sJ, (E) whereJ∈ {R+,R}. In caseJ=R+, an important result has been proved by Van Minh et al. [24] and it is given by the following.

Theorem 1.1. Let= {U(t,s)}ts0be an evolution family such that for everyxXthe mapping (t,s)U(t,s)xis continuous. Then,is uniformly exponentially dichotomic if and only if for everyvC0(R+,X) there is f C0(R+,X) such that the pair (f,v) verifies (E) and the subspaceY1={xX: supt0U(t, 0)x<∞}is closed and complemented inX.

Hindawi Publishing Corporation Abstract and Applied Analysis

Volume 2006, Article ID 31641, Pages1–16 DOI10.1155/AAA/2006/31641

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Theorem 1.1has been generalized for the case of evolution families with nonuniform exponential growth in [8]. There we have proved that in the nonuniform case, the solv- ability inC0(R+,X) of (E) implies the nonuniform exponential dichotomy of the evo- lution familyᐁ= {U(t,s)}ts0. The discrete-time version ofTheorem 1.1has been ob- tained in [9] for the case of discrete and continuous evolution families. Characterizations for uniform exponential dichotomy of evolution families on the half-line withLp-spaces were obtained in [19,23].

For the caseJ=R, a significant result has been obtained by Latushkin et al. [7], as shown in the following.

Theorem 1.2. Let= {U(t,s)}tsbe an evolution family such that for everyxX the mapping (t,s)U(t,s)x is continuous, and letᏲ(R,X) be one of the spaces Cb(R,X), C0(R,X) orLp(R,X), (p[1,)). Then,is uniformly exponentially dichotomic if and only if for everyvᏲ(R,X) there is a unique f Ᏺ(R,X) such that the pair (f,v) verifies (E).

The main tool in [7] was the use of the evolution semigroup associated toᐁ.Theorem 1.2has been generalized in [10], where pointwise and global exponential dichotomy of a linear skew-product flowπ=(Φ,σ) is expressed in terms of the unique solvability in C0(R,X) of an associated integral equation:

f(t)=Φσ(θ,s),tsf(s) + t

sΦσ(θ,τ),tτv(τ)dτ, ts. (Eπ) The purpose of the present paper is to give general characterizations for uniform expo- nential dichotomy of evolution families on the real line. The proofs are direct, the meth- ods being based on input-output techniques, on the use of some specific operators asso- ciated to the integral equation (E), and on the properties of certain subspaces related to the evolution family. We will obtain that the admissibility of the pair (Lp(R,X),Lq(R,X)), withp,q[1,), is a sufficient condition for uniform exponential dichotomy of evolu- tion families, and it becomes necessary forpq.

Finally, we apply our results in order to obtain necessary and sufficient conditions for uniform exponential dichotomy of aC0-semigroup in terms of the unique solvability of an integral equation associated to it.

2. Evolution families

Let X be a real or complex Banach space. The norm on X and onᏮ(X), the Banach algebra of all bounded linear operators onX, will be denoted by · .

Definition 2.1. A family= {U(t,s)}tsof bounded linear operators onXis called an evolution family if the following properties hold:

(i)U(t,t)=I, for alltR;

(ii)U(t,s)U(s,t0)=U(t,t0), for alltst0;

(iii) for everyxXand everyt,t0, the mappingsU(s,t0)xis continuous on [t0,) and the mappingsU(t,s)xis continuous on (−∞,t];

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(iv) there existM1 andω >0 such that

Ut,t0Meω(tt0), tt0. (2.1)

Definition 2.2. An evolution family= {U(t,s)}tsis said to be uniformly exponentially dichotomic if there are a family of projections{P(t)}t∈R and two constantsK1 and ν>0 such that

(i)U(t,t0)P(t0)=P(t)U(t,t0), for alltt0;

(ii)U(t,t0)xKeν(tt0)x, for allxImP(t0) and alltt0; (iii)U(t,t0)y(1/K)eν(tt0)y, for allyKerP(t0) and alltt0;

(iv) the restrictionU(t,t0)|: KerP(t0)KerP(t) is an isomorphism, for alltt0. Lemma 2.3. If the evolution family= {U(t,s)}tsis uniformly exponentially dichotomic relative to the family of projections{P(t)}t∈R, then supt∈RP(t)<and for everyxX, the mappingtP(t)xis continuous.

Proof. This is a simple exercise.

Letᐁ= {U(t,s)}tsbe an evolution family onXand letp[1,). For everyt0R, we consider the linear subspace

X1

t0

=

xX:

t0

Ut,t0

xpdt <

. (2.2)

We denote byᏲ(t0) the set of all functionsϕ:RXwith the property thatϕ(t)= U(t+t0,s+t0)ϕ(s), for allst0.

Remark 2.4. Ifϕ(t0), thenϕis continuous onR.

For everyt0R, we denote byX2(t0) the linear space of allxXwith the property that there is a functionϕx(t0) such thatϕx(0)=xand −∞0 ϕx(t)pdt <. Lemma 2.5. If= {U(t,s)}tsis an evolution family, thenU(t,t0)Xk(t0)Xk(t), for all tt0and allk∈ {1, 2}.

Proof. This is immediate.

Proposition 2.6. If the evolution family= {U(t,s)}tsis uniformly exponentially di- chotomic relative to the family of projections{P(t)}t∈R, thenX1(t0)=ImP(t0) andX2(t0)= KerP(t0), for everyt0R.

Proof. Let M1, ω >0 be given by Definition 2.1 and let K1, ν>0 be given by Definition 2.2. Lett0R.

It is easy to see that ImP(t0)X1(t0). IfxX1(t0), letαx:=(t0 U(t,t0)xpdt)1/ p. Forτt0+ 1, from

Uτ,t0

xMeωUt,t0

x, t1,τ], (2.3)

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it follows that

Uτ,t0

xMeωαx, τt0+ 1. (2.4) This implies thatqx:=suptt0U(t,t0)x<. Then from

xPt0

xKeν(tt0)Ut,t0

IPt0

x

Keν(tt0)qx+KPt0

x, tt0,

(2.5) we obtain thatxImP(t0).

IfxKerP(t0), we defineψx:RX,ψx(t)=U(t0,t0+t)|1x, where for everyt0, U(t0,t0+t)|1denotes the inverse of the operatorU(t0,t0+t)|: KerP(t0+t)KerP(t0).

Then,ψx(0)=x,ψx(t0), and

ψx(t)Keνtx, t0, (2.6)

soxX2(t0).

LetxX2(t0). Then there isϕx(t0) such that ϕx(0)=x, λx:=0

−∞

ϕx(t)pdt 1/ p

<. (2.7)

Lett0. From

ϕx(t)=Ut+t0,s+t0

ϕx(s), s[t1,t], (2.8) it follows that

ϕx(t)Meωλx, t0. (2.9)

Then from Pt0

x=Ut0,t0+tPt0+tϕx(t)KeνtPt0+tϕx(t)

KMeωλxsup

s∈R

P(s)eνt, t0, (2.10)

it follows thatP(t0)x=0, soxKerP(t0).

Remark 2.7. If an evolution family= {U(t,s)}ts is uniformly exponentially dicho- tomic with respect to a family of projections, then according to the above result this family of projections is uniquely determined.

3. Exponential dichotomy and admissibility of the pair (Lp(R,X),Lq(R,X)) for evolution families

LetXbe a Banach space and letᏴ(R,X) be the space of all Bochner measurable func- tionsv:RX, identifying the functions which are equal almost everywhere. For every

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p[1,), the linear space Lp(R,X)=

vᏴ(R,X) :

−∞

v(τ)pdτ <

(3.1) is a Banach space with respect to the norm

vp:=

−∞

v(τ)p 1/ p

. (3.2)

Letᐁ= {U(t,s)}tsbe an evolution family onXand letp,q[1,). We consider the integral equation

f(t)=U(t,s)f(s) + t

sU(t,τ)v(τ)dτ, ts, (E) with f Lp(R,X) andvLq(R,X).

Definition 3.1. The pair (Lp(R,X),Lq(R,X)) is said to be admissible for the evolution familyᐁ= {U(t,s)}tsif for everyvLq(R,X) there is a unique f Lp(R,X) such that the pair (f,v) verifies (E).

If the pair (Lp(R,X),Lq(R,X)) is admissible for the evolution familyᐁ= {U(t,s)}ts, then it makes sense to define the operator

Γ:Lq(R,X)−→Lp(R,X), Γv=f . (3.3) It is easy to see thatΓis linear and it is closed. It follows thatΓis bounded, so there is γ >0 such thatΓvpγvq, for allvLq(R,X).

Proposition 3.2. If the pair (Lp(R,X), Lq(R,X)) is admissible for the evolution family ᐁ= {U(t,s)}ts, then

(i)X1(t0)X2(t0)= {0}, for allt0R; (ii)X1(t0) +X2(t0)=X, for allt0R;

(iii) the restrictionU(t,t0)|:X2(t0)X2(t) is an isomorphism, for alltt0.

Proof. (i) Lett0Rand letxX1(t0)X2(t0). Then, there is a functionϕx(t0) such thatϕx(0)=xand −∞0 ϕx(t)pdt <. We define

f :R−→X, f(t)=

Ut,t0

x, t > t0, ϕxtt0

, tt0. (3.4)

Then, it is easy to see that f(t)=U(t,s)f(s), for allts. SincexX1(t0), we obtain that f Lp(R,X). It follows thatf =0, sox= f(t0)=0.

(ii) LetxXand lett0R. We consider the function v:R−→X, v(τ)=χ[t0,t0+1](τ)Uτ,t0

x, (3.5)

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whereχ[t0,t0+1]denotes the characteristic function of the interval [t0,t0+ 1]. From hypoth- esis, there is f Lp(R,X) such that the pair (f,v) verifies (E). Then

f(t)=Ut,t0

ft0

+ t

t0

U(t,τ)v(τ)dτ=Ut,t0

ft0

+x, tt0+ 1. (3.6)

Since f Lp(R,X), it follows that f(t0) +xX1(t0). Letϕ:RX,ϕ(t)= f(t+t0).

From the fact that the pair (f,v) verifies (E), it follows that

ϕ(t)=Ut0+t,t0+sϕ(s), st0 (3.7) which shows thatϕ(t0). Since f Lp(R,X), it follows that f(t0)X2(t0). Finally, we obtain thatx=(x+f(t0))f(t0)X1(t0) +X2(t0).

(iii) Lett > t0. LetyKerU(t,t0)X2(t0), and letϕy(t0) withϕy(0)=yand

0

−∞ϕy(s)pds <. Considering the function h:R−→X, h(τ)=

Uτ,t0

y, τ > t0, ϕyτt0

, τt0, (3.8)

we have thathLp(R,X). It is easy to observe that the pair (h, 0) verifies (E). This implies thath=0. In particular, it follows that y=h(t0)=0, so, the operatorU(t,t0)|: X2(t0)X2(t) is injective.

To prove the surjectivity, letxX2(t). We consider the functions v:R−→X, v(τ)= −χ[t,t+1](τ)U(τ,t)x, f : [t,)−→X, f(τ)=

(t+ 1τ)U(τ,t)x, τ[t,t+ 1],

0, τ > t+ 1.

(3.9)

We observe thatvLq(R,X) and f(r)=U(r,s)f(s) +

r

sU(r,τ)v(τ)dτ, rst. (3.10) From hypothesis there isgLp(R,X) such that the pair (g,v) verifies (E). It follows that f(r)g(r)=U(r,t)(f(t)g(t)), for allrtwhich implies thatxg(t)= f(t)g(t) X1(t).

From (ii) there is y1X1(t0) and y2X2(t0) such thatg(t0)=y1+y2. Sinceg(t)= U(t,t0)g(t0), we obtain that g(t)=U(t,t0)y1+U(t,t0)y2, then xU(t,t0)y2=(x g(t)) +U(t,t0)y1. FromLemma 2.5and from (i), we deduce thatxU(t,t0)y2=0, so xU(t,t0)X2(t0).

This shows that the operatorU(t,t0)|:X2(t0)X2(t) is surjective and completes the

proof.

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Lemma 3.3. Lett0< t1≤ ∞and letα: [t0,t1)R+be a continuous function with the prop- erty that there areM1 andω,h(0,) such that

α(t)Meω(ts)α(s), s,t t0,t1

,st, (3.11)

t+2h

t+h α(τ)dτ1 e

t+h

t α(τ)dτ, (3.12)

for everyt[t0,t1) witht+ 2h < t1. Then α(t)Keν(tt0)αt0

, t t0,t1

, (3.13)

whereK=(Me)2e3ωhandν=1/h.

Proof. Lett[t0,t1),nN, andr[0,h) such thatt=t0+nh+r. Ifn2, then t0+nh

t0+(n1)hα(τ)dτe(n1) t0+h

t0

α(τ)dτ. (3.14)

Using the relation (3.11), we have that t0+h

t0

α(τ)dτMheωhαt0

, α(t)M he2ωh

t0+nh

t0+(n1)hα(τ)dτ. (3.15) From relations (3.14)–(3.15), it follows that

α(t)M2e3ωhe(n1)αt0

. (3.16)

Denotingν=1/hand takingK=(Me)2e3ωh, we obtain that α(t)Keν(tt0)αt0

. (3.17)

Ifn∈ {0, 1}, thentt0<2h. It follows that α(t)Me2ωhαt0

Keν(tt0)αt0

. (3.18)

Theorem 3.4. If the pair (Lp(R,X),Lq(R,X)) is admissible for the evolution family= {U(t,s)}ts, then there existK1 andν>0 such that

Ut,t0

xKeν(tt0)x, xX1 t0

,tt0. (3.19) Proof. From hypothesis there isγ1 such that

Γvpγvq, vLq(R,X). (3.20) We denoteh=(γe)p.

Lett0R, letxX1(t0)\ {0}, and lett1=sup{tt0:U(t,t0)x=0}. We consider the functionϕ: [t0,t1)X,ϕ(t)=U(t,t0)x.

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Ift1> t0+ 2h, for everytt0witht+ 2h < t1, we consider the functions v:R−→X, v(τ)=χ[t,t+h](τ) ϕ(τ)

ϕ(τ), f :R−→X, f(τ)=

τ

−∞

χ[t,t+h](s) ϕ(s) dsϕ(τ).

(3.21)

We have thatvLq(R,X) and since xX1(t0), it follows that f Lp(R,X). It is easy to see that the pair (f,v) verifies (E), soΓv= f. From (3.20) it follows thatfp γvq=γh1/q. In particular, this inequality shows that

t+2h t+h

f(τ)p 1/ p

γh1/q. (3.22)

We denoteδ= tt+h(1/ϕ(s))ds. Then, from (3.22) we deduce that t+2h

t+h

ϕ(τ)p 1/ p

γ

δh1/q. (3.23)

Let

h=

1, forp=1,

h1/ p, forp(1,), p= p

p1. (3.24)

Then, we have

t+2h

t+h

ϕ(τ)h t+2h

t+h

ϕ(τ)p 1/ p

. (3.25)

Using (3.23), we deduce that t+2h

t+h

ϕ(τ)γ

δhh1/q. (3.26)

Since

h2 t+h

t

ϕ(τ)1 t+h

t

ϕ(τ)

=δ t+h

t

ϕ(τ)

(3.27) from (3.26) we obtain that

t+2h

t+h

ϕ(τ)γhh1/q h2

t+h

t

ϕ(τ)γh h

t+h

t

ϕ(τ)dτ. (3.28)

By the definition ofh, from (3.28) it follows that t+2h

t+h

ϕ(τ)1 e

t+h

t

ϕ(τ)dτ. (3.29)

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LetM,ωbe given byDefinition 2.1. ApplyingLemma 3.3forα= ϕ, it follows that ϕ(t)Keν(tt0)ϕt0, t

t0,t1

, (3.30)

whereK=(Me)2e3ωhandν=1/h.

BecauseKandνdo not depend ont0orx, the proof is complete.

Corollary 3.5. If the pair (Lp(R,X),Lq(R,X)) is admissible for the evolution familyᐁ= {U(t,s)}ts, thenX1(t0) is a closed linear subspace, for allt0R.

Proof. Lett0Rbe fixed and let (xn)X1(t0) be a sequence convergent toxX. It fol- lows that there isL >0 such thatxnL, for allnN. IfK,νare given byTheorem 3.4, we deduce thatU(t,t0)xnKLeν(tt0), for all tt0 and all nN. Hence, we ob- tain thatU(t,t0)xKLeν(tt0), for all tt0, soxX1(t0). It follows thatX1(t0) is

closed.

Lemma 3.6. Letα: [t0,)R+be a continuous function with the property that there are M1 andω,h(0,) such that

α(t)Meω(ts)α(s), tst0, (3.31) t+2h

t+h α(τ)dτe t+h

t α(τ)dτ, tt0. (3.32) Then

α(t) 1

Keν(ts)α(s), tst0+h, (3.33) whereK=M2e3ωhandν=1/h.

Proof. Lett > st0+h,nN, andr[0,h) such that ts=nh+r. From (3.32) it follows that

s+(n+2)h

s+(n+1)hα(τ)dτen+2 s

shα(τ)dτ. (3.34)

Using the relation (3.31), we have that s+(n+2)h

s+(n+1)hα(τ)dτMhe2ωhα(t), hα(s)Meωh s

shα(τ)dτ. (3.35) From (3.34)–(3.35), it follows that

α(t) en+2

M2e3ωhα(s) 1

Keν(ts)α(s), (3.36)

whereν=1/handK=M2e3ωh.

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Theorem 3.7. If the pair (Lp(R,X),Lq(R,X)) is admissible for the evolution family= {U(t,s)}ts, then there existK1 andν>0 such that

Ut,t0

y 1

Keν(tt0)y, yX2

t0),tt0. (3.37) Proof. From hypothesis there isγ1 such that

Γvpγvq, vLq(R,X). (3.38) We denoteh=(γe)p.

Lett0Rand let yX2(t0)\ {0}. FromProposition 3.2(iii) there iszX2(t0h)\ {0}such thatU(t0,t0h)z=y. Denoting byϕ: [t0h,)X,ϕ(t)=U(t,t0h)z, and usingProposition 3.2(iii), we have thatϕ(t)=0, for alltt0h.

Lettt0h. We consider the function

v:R−→X, v(τ)= −χ[t+h,t+2h](τ) ϕ(τ)

ϕ(τ). (3.39)

Since

z1= t+2h

t+h

ϕ(s)ds

zX2

t0h, (3.40)

there isλ(t0h) withλ(0)=z1and −∞0 λ(s)pds <. Let

f :R−→X, f(τ)=

τ

χ[t+h,t+2h](s)

ϕ(s) dsϕ(τ), τt0h, λτt0+h, τ < t0h.

(3.41)

We have thatvLq(R,X), f Lp(R,X), and the pair (f,v) verifies (E). SoΓv=f and from (3.38) it follows thatfpγvq=γh1/q. In particular, from this inequality, we deduce that

t+h

t

f(τ)p 1/ p

γh1/q. (3.42)

We denoteδ= t+ht+2h(1/ϕ(s))ds. Then, from (3.42) we obtain that t+h

t

ϕ(τ)p 1/ p

γ

δh1/q. (3.43)

Let

h=

1, forp=1,

h1/ p, forp(1,), p= p

p1. (3.44)

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Using analogous arguments as in the proof ofTheorem 3.4, we immediately deduce that t+h

t

ϕ(τ)γhh1/q h2

t+2h

t+h

ϕ(τ)1 e

t+2h

t+h

ϕ(τ)dτ. (3.45)

LetM,ωbe given byDefinition 2.1. ApplyingLemma 3.6forα= ϕ, it follows that ϕ(t) 1

Keν(ts)ϕ(s), tst0, (3.46) whereK=M2e3ωhandν=1/h. This implies that

Ut,t0hz 1

Keν(tt0)Ut0,t0hz, tt0 (3.47) which means that

Ut,t0

y 1

Keν(tt0)y, tt0. (3.48) SinceKandνdo not depend ont0ory, we obtain the conclusion.

Corollary 3.8. If the pair (Lp(R,X),Lq(R,X)) is admissible for the evolution familyᐁ= {U(t,s)}ts, thenX2(t0) is a closed linear subspace, for allt0R.

Proof. Lett0R. If yX2(t0) andϕy is a function given by the definition of the space X2(t0) withϕy(0)=y, then it is easy to see thatϕy(s)X2(t0+s), for alls0.

Let (xn)X2(t0) be a sequence convergent toxX. For everynNthere is a func- tionϕn(t0) such thatϕn(0)=xnand −∞0 ϕn(τ)pdτ <. Since

ϕn(0)=Ut0,t0+sϕn(s), s0,nN, (3.49) forK,νgiven byTheorem 3.7, it follows that

xnxm=Ut0,t0+sϕn(s)ϕm(s)

1

Keνsϕn(s)ϕm(s), s0,m,nN. (3.50) Using the fact that (xn) is fundamental, from (3.50) we obtain that for everys0 the sequence (ϕn(s)) is fundamental, so it is convergent. We denoteϕ(s) :=limn→∞ϕn(s), for alls0. Henceϕ(0)=xandϕ(t0). From (3.50) we deduce that

ϕ(s)Keνsxnx+ϕn(s), (s,n)R×N. (3.51) This implies thatxX2(t0) and the proof is complete.

The first main result of this section is given by the following.

Theorem 3.9. If the pair (Lp(R,X),Lq(R,X)) is admissible for the evolution family= {U(t,s)}ts, thenis uniformly exponentially dichotomic.

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Proof. FromProposition 3.2,Corollary 3.5, andCorollary 3.8, it follows that for everyt R,X1(t)X2(t)=X. LetP(t) be the projection corresponding toX1(t), that is, ImP(t)= X1(t) and KerP(t)=X2(t). UsingLemma 2.5, we have thatP(t)U(t,t0)=U(t,t0)P(t0), for alltt0. FromProposition 3.2, the restriction U(t,t0)|: KerP(t0)KerP(t) is an isomorphism, for alltt0. Finally, usingTheorem 3.4andTheorem 3.7, we obtain that

ᐁis uniformly exponentially dichotomic.

Theorem 3.9gives a sufficient condition for the uniform exponential dichotomy of an evolution family. In what follows, we will establish when the uniform exponential di- chotomy of an evolution family implies the admissibility of the pair (Lp(R,X),Lq(R,X)).

Lemma 3.10. Letp,q[1,) withpq, letν>0, and letvLq(R,R+). Then, the func- tions f1,f2:RR+defined by

f1(t)= t

−∞eν(ts)v(s)ds, f2(t)=

t eν(st)v(s)ds (3.52) belong toLp(R,R+).

Proof. This follows using H¨older’s inequality.

Proposition 3.11. Let= {U(t,s)}ts be an evolution family and let p,q[1,). If X1(t0)X2(t0)= {0}, for allt0R, then for everyvLq(R,X) there exists at most one

f Lp(R,X) such that the pair (f,v) verifies (E).

Proof. LetvLq(R,X). Suppose that there are f,f1Lp(R,X) such that the pairs (f,v) and (f1,v) verify (E). Then, we have

f1(t)f(t)=U(t,s)f1(s)f(s), ts. (3.53) Lett0R. From f1(t)f(t)=U(t,t0)(f1(t0)f(t0)) and f,f1Lp(R,X), it follows that f1(t0)f(t0)X1(t0).

Letψ:RX,ψ(s)= f1(t0+s)f(t0+s). From (3.53) we obtain thatψ(t0).

Because f1,f Lp(R,X), it follows that ψ(0)= f1(t0) f(t0)X2(t0). Using the hy- pothesis, we obtain that f1(t0)= f(t0). Since t0Rwas arbitrary, we deduce that f =

f1.

Theorem 3.12. Let= {U(t,s)}tsbe an evolution family and letp,q[1,) withp q. Thenis uniformly exponentially dichotomic if and only if the pair (Lp(R,X),Lq(R,X)) is admissible forᐁ.

Proof (Necessity). Let{P(t)}t∈Rbe the family of projections given byDefinition 2.2. For vLq(R,X) we consider the function

f :R−→X, f(t)= t

−∞U(t,s)P(s)v(s)ds

t U(s,t)|1IP(s)v(s)ds,

(3.54)

参照

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