Internat. J. Math. & Math. Sci.
VOL. 13 NO. 4 (1990) 737-740
737
A PROOF OF POLLACZEK-SPITZER IDENTITY
S. PARAMASAMY
Department
of Mathematics TheUniversityoftheWest
IndiesSt.
Augustine Trinidad,W.I.
(Received November 27, 1989 and in revised form July 12, 1990)
ABSTRACT. In
this note we derive aproof
ofPollaczek-Spitzer identity usingageneralization
ofTakacs ballottheorem.KEY WORDS AND PHRASES.
Randomwalk,
ballottheorem,Pollaczek-Spitzer
identity.1980 AMS SUBJECT CLASSIFICATION CODE.
60J15.1.
INTRODUCTION.
Consider thefollowing generalizationofTakacs ballot theorem
(Takacs ]): Suppose k,
k.k,,,
arenon-negative integerswithsumk<mn for someintegertnandletn,
be the number ofcyclic permutations(kl,k ki,)of (kl, k.z, ...,k,)
such thatkil
+k6
+ +k
jm rfor allj 1,2 n, withequality holding for at least one of thesej’s,r 1,2 ,m. Then, rn,-nm-k (1.1)
On
settingr
tn ki,wegetthefollowing generalization:Let r,
r2,...,r,,
beintegerswithsum s and letn,
be the numberof cyclic permutationsin whichall thepartial sumsaregreaterorequal
to r withat leastone sumequal
tor. Thenrn,-s (1.2)
PROOF
of(1.1).
Consider n boxesarranged
in a circle andnumbered 1tonin the clockwise direction. Initiallybox containsk
balls.Starting
frombox nsearchthe boxes in the anti-clockwise direction and should a box containtn+ r balls for some r>0,then remove r balls from the boxcontaining thesem+ r ballsandplace
them inthe boxthat follows immediately in theanti-clockwise direction.Repeat
the above
steps
untilthe numberofballs contained ineachbox isless than orequal
tom.Let B
be thenumberof balls contained in box after the re-allocations asspecifiedare
completed
andlet nl be the number ofintegers amongB,B2, B,,
whichareequal
tom i,0,1
m. SinceE (m i)ni
kandE n
n,wehave
E ini
-nm k.Letk,/i-kiand So-ki+ki+l+... +ki+j, i,j- 1,2
n. ThenBi-m-r
1rm, ifandonly ifSii
jm r foralljwith atleast one index forwhichS,
tm r.To prove
thisassume withoutloss of generalitythat 1.Suppose B
m r, 1 r m,andS,
> tm rforsome >2. Thenwe must738 S. PARAMASAMY
have
Bt-B,_t B2.m
andBt>m-r,
a contradiction.So So<jm-r
for all j>l.Suppose S
0<jm rforallj. Then we must havekt
m andki
gm for all2,
whichimpliesthatBt
<m r,acontradiction.
Now (1.1)
follows immediately.2.
POLLACZEK-SPITZER IDENTITY.
Using (1.2),
wegiveaproof
ofthe well-knownPollaczek-Spitzer
identity(2.1).
Thisproof appears
tobenew.
To
keepthearguments simple,weconsiderinteger-valuedrandom variablesonly.THEOREM. Let X,
1, 2 beaninfinitesequence
of independentandidenticallydistributed integer-valued random variables;S,-X1 +X2
++X,; mi.
andMi.,
the minimum and maximumrespectively ofX/,X/+X/+,...,X/+X,./
++X/+j;
F,- , exp(-Xs)P{S,-s}/i,
i-1,2,;
.>0G,- X exp(-)P{Mt.,-t O,S-s},
1,2,...;F tF, G- , G,
0< <1-1 -1
Then
F log(1 -G) (2.1)
PROOF. By (1.2),
wehaveXJ P{ml.. "J IS. -s}
-s/n(2.2)
providedthe conditionalprobabilityexists.
Now
forr<s,{mx..-rlS..s}.u[{(mt.,-rlS,-s-t)n(s,-s-t)}n{m,/l,.-tls.-$,-t}] (2.3)
wherethe union is over all z1andall1 s r. Alsonote the
easily
verifiabledualityproperty
P{m.. -sis s} P{M.._ OIS s} (2.4)
Consequently,
using(2.3)
and(2.4),
wehaveforr<s,P{mL.-s IS. -s} -P{ml,,-r IS,-s-t}P{S,-s-t}P{M,/t.._ <OIS.-S,-t} (2.5)
So multiplying (2.5) by
r s1,
addingthequantityP {mr,.
sS.
s}
tobothsidesoftheequation,
andsumming,weget,
by (2.2),
s/n-s
P{M.._t
gOIS. -s}
+(s -t) p{s
-s-t}P{M/t.._t O IS -s -t}
whichimpliesthat
s
P{S. -s}ln
-sP{M,._t
.:0IS. -s}P{S. -s}
+ (s-t)p{S,’s-t}P{M,/,.. OIS.-S,’t}P{S.-S,’t} (2.6)
Then
multiplying (2.6) by exp(-,a)
andsumming
overall sa1,
we obtainF,,’- G,,’
+, Fi’G,, _, (2.7)
where
F/-dFdd
andG’-dGdd. Multiplying (2.7) by ",
0<t<1, and summing overn1,2
we haveA PROOF OF POLLACZEK-SPITZER IDENTITY 739
So
integrating,wegettheidentity(2.1). (Let
k ootoshowthat thearbitraryconstant iszero.)
Proofsof(2.1)
and othercloselyrelated results can be found in the references[2] [10].
ACKNOWLEDGEMENT.
The author would liketothanktheanonymous
referee for pointingoutsome notable omissions in theoriginal referencelist.10.
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