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(1)

Mahonians and parabolic quotients

FABRIZIO CASELLI

September 21, 2011

(2)

Poincar´ e polynomial

The Poincar´e polynomial of the symmetric groupSn X

σ∈Sn

q`(σ)

= [2]q[3]q· · ·[n]q,

where [r]q= 1 +q+. . .+qr−1 and

`(σ) ={(i,j) :i <j, σ(i)> σ(j)} For a finite reflection groupW

X

u∈W

q`(u)= [d1]q[d2]q· · ·[dr]q,

(3)

Poincar´ e polynomial

The Poincar´e polynomial of the symmetric groupSn X

σ∈Sn

q`(σ)= [2]q[3]q· · ·[n]q,

where [r]q= 1 +q+. . .+qr−1 and

`(σ) ={(i,j) :i <j, σ(i)> σ(j)}

For a finite reflection groupW X

u∈W

q`(u)= [d1]q[d2]q· · ·[dr]q,

(4)

Poincar´ e polynomial

The Poincar´e polynomial of the symmetric groupSn X

σ∈Sn

q`(σ)= [2]q[3]q· · ·[n]q,

where [r]q= 1 +q+. . .+qr−1 and

`(σ) ={(i,j) :i <j, σ(i)> σ(j)}

For a finite reflection groupW X

u∈W

q`(u)= [d1]q[d2]q· · ·[dr]q,

(5)

Parabolic subgroups and quotients

LetW =Sn andsi = (i,i + 1) andS ={s1, . . . ,sn−1}.

IfJ⊆S then

WJ is the subgroup genereted byJ;

JW is a system of coset representatives;

Ifσ ∈W there are uniqueσJ ∈WJ andJσ∈JW: σ =σJ ·Jσ and `(σ) =`(σJ) +`(Jσ).

X

Jσ∈JW

q`(Jσ)= P

σ∈W q`(σ) P

σJ∈WJ q`(σJ)

If J={sn−k+1, . . . ,sn−1} then WJ ∼=Sk

X

σ∈JW

q`(σ)= [2]q[3]q· · ·[n]q

[2]q[3]q· · ·[k]q = [k+ 1]q[k+ 2]q· · ·[n]q.

(6)

Parabolic subgroups and quotients

LetW =Sn andsi = (i,i + 1) andS ={s1, . . . ,sn−1}.

IfJ⊆S then

WJ is the subgroup genereted byJ;

JW is a system of coset representatives;

Ifσ ∈W there are uniqueσJ ∈WJ andJσ∈JW: σ =σJ ·Jσ and `(σ) =`(σJ) +`(Jσ).

X

Jσ∈JW

q`(Jσ)= P

σ∈W q`(σ) P

σJ∈WJ q`(σJ)

If J={sn−k+1, . . . ,sn−1} then WJ ∼=Sk

X

σ∈JW

q`(σ)= [2]q[3]q· · ·[n]q

[2]q[3]q· · ·[k]q = [k+ 1]q[k+ 2]q· · ·[n]q.

(7)

Parabolic subgroups and quotients

LetW =Sn andsi = (i,i + 1) andS ={s1, . . . ,sn−1}.

IfJ⊆S then

WJ is the subgroup genereted byJ;

JW is a system of coset representatives;

Ifσ ∈W there are uniqueσJ ∈WJ andJσ∈JW: σ =σJ ·Jσ and `(σ) =`(σJ) +`(Jσ).

X

Jσ∈JW

q`(Jσ)= P

σ∈W q`(σ) P

σJ∈WJ q`(σJ)

If J={sn−k+1, . . . ,sn−1} then WJ ∼=Sk

X

σ∈JW

q`(σ)= [2]q[3]q· · ·[n]q

[2]q[3]q· · ·[k]q = [k+ 1]q[k+ 2]q· · ·[n]q.

(8)

Parabolic subgroups and quotients

LetW =Sn andsi = (i,i + 1) andS ={s1, . . . ,sn−1}.

IfJ⊆S then

WJ is the subgroup genereted byJ;

JW is a system of coset representatives;

Ifσ ∈W there are uniqueσJ ∈WJ andJσ∈JW: σ =σJ ·Jσ and `(σ) =`(σJ) +`(Jσ).

X

Jσ∈JW

q`(Jσ)= P

σ∈W q`(σ) P

σJ∈WJ q`(σJ)

If J={sn−k+1, . . . ,sn−1} then WJ ∼=Sk

X

σ∈JW

q`(σ)= [2]q[3]q· · ·[n]q

[2]q[3]q· · ·[k]q = [k+ 1]q[k+ 2]q· · ·[n]q.

(9)

Parabolic subgroups and quotients

LetW =Sn andsi = (i,i + 1) andS ={s1, . . . ,sn−1}.

IfJ⊆S then

WJ is the subgroup genereted byJ;

JW is a system of coset representatives;

Ifσ ∈W there are uniqueσJ ∈WJ andJσ∈JW: σ =σJ ·Jσ and `(σ) =`(σJ) +`(Jσ).

X

Jσ∈JW

q`(Jσ)= P

σ∈W q`(σ) P

σJ∈WJ q`(σJ)

If J={sn−k+1, . . . ,sn−1} then WJ ∼=Sk X q`(σ)= [2]q[3]q· · ·[n]q

= [k+ 1] [k+ 2] · · ·[n] .

(10)

The major index in parabolic quotients

We let

Descents ofσ = Des(σ) ={i|σ(i)> σ(i+ 1)}

Major index of σ = maj(σ) = X

i∈Des(σ)

i

We have X

σ∈Sn

q`(σ) = X

σ∈Sn

qmaj(σ) BUTmaj(σ)6=maj(σJ) +maj(Jσ).

Nevertheless,

Theorem (Panova, 2010)

If W =Sn and J={sn−k+1, . . . ,sn−1} then X

σ∈JW

qmaj(σ) = [k+ 1]q[k+ 2]q· · ·[n]q

(11)

The major index in parabolic quotients

We let

Descents ofσ = Des(σ) ={i|σ(i)> σ(i+ 1)}

Major index of σ = maj(σ) = X

i∈Des(σ)

i

We have X

σ∈Sn

q`(σ) = X

σ∈Sn

qmaj(σ) BUTmaj(σ)6=maj(σJ) +maj(Jσ).

Nevertheless,

Theorem (Panova, 2010)

If W =Sn and J={sn−k+1, . . . ,sn−1} then X

σ∈JW

qmaj(σ) = [k+ 1]q[k+ 2]q· · ·[n]q

(12)

The major index in parabolic quotients

We let

Descents ofσ = Des(σ) ={i|σ(i)> σ(i+ 1)}

Major index of σ = maj(σ) = X

i∈Des(σ)

i

We have X

σ∈Sn

q`(σ)= X

σ∈Sn

qmaj(σ)

BUTmaj(σ)6=maj(σJ) +maj(Jσ).

Nevertheless,

Theorem (Panova, 2010)

If W =Sn and J={sn−k+1, . . . ,sn−1} then X

σ∈JW

qmaj(σ) = [k+ 1]q[k+ 2]q· · ·[n]q

(13)

The major index in parabolic quotients

We let

Descents ofσ = Des(σ) ={i|σ(i)> σ(i+ 1)}

Major index of σ = maj(σ) = X

i∈Des(σ)

i

We have X

σ∈Sn

q`(σ)= X

σ∈Sn

qmaj(σ) BUTmaj(σ)6=maj(σJ) +maj(Jσ).

Nevertheless,

Theorem (Panova, 2010)

If W =Sn and J={sn−k+1, . . . ,sn−1} then X

σ∈JW

qmaj(σ) = [k+ 1]q[k+ 2]q· · ·[n]q

(14)

The major index in parabolic quotients

We let

Descents ofσ = Des(σ) ={i|σ(i)> σ(i+ 1)}

Major index of σ = maj(σ) = X

i∈Des(σ)

i

We have X

σ∈Sn

q`(σ)= X

σ∈Sn

qmaj(σ) BUTmaj(σ)6=maj(σJ) +maj(Jσ).

Nevertheless,

Theorem (Panova, 2010)

If W =Snand J ={sn−k+1, . . . ,sn−1} then X

σ∈JW

qmaj(σ) = [k+ 1]q[k+ 2]q· · ·[n]q

(15)

Signed Mahonians

An alternating version of the Poincar´e polynomial Theorem (Gessel-Simion)

X

σ∈Sn

(−1)`(σ)qmaj(σ)

= [2]−q[3]q[4]−q· · ·[n](−1)n−1q.

Problem: for J ={sn−k+1, . . . ,sn−1} compute the polynomial X

σ∈JW

(−1)`(σ)qmaj(σ).

Does it factorize nicely? Is it an alternating version of Panova’s result? Yes. Yes.

(16)

Signed Mahonians

An alternating version of the Poincar´e polynomial Theorem (Gessel-Simion)

X

σ∈Sn

(−1)`(σ)qmaj(σ) = [2]−q[3]q[4]−q· · ·[n](−1)n−1q.

Problem: for J ={sn−k+1, . . . ,sn−1} compute the polynomial X

σ∈JW

(−1)`(σ)qmaj(σ).

Does it factorize nicely? Is it an alternating version of Panova’s result? Yes. Yes.

(17)

Signed Mahonians

An alternating version of the Poincar´e polynomial Theorem (Gessel-Simion)

X

σ∈Sn

(−1)`(σ)qmaj(σ) = [2]−q[3]q[4]−q· · ·[n](−1)n−1q.

Problem: for J ={sn−k+1, . . . ,sn−1} compute the polynomial X

σ∈JW

(−1)`(σ)qmaj(σ).

Does it factorize nicely?

Is it an alternating version of Panova’s result? Yes. Yes.

(18)

Signed Mahonians

An alternating version of the Poincar´e polynomial Theorem (Gessel-Simion)

X

σ∈Sn

(−1)`(σ)qmaj(σ) = [2]−q[3]q[4]−q· · ·[n](−1)n−1q.

Problem: for J ={sn−k+1, . . . ,sn−1} compute the polynomial X

σ∈JW

(−1)`(σ)qmaj(σ).

Does it factorize nicely? Is it an alternating version of Panova’s result?

Yes. Yes.

(19)

Signed Mahonians

An alternating version of the Poincar´e polynomial Theorem (Gessel-Simion)

X

σ∈Sn

(−1)`(σ)qmaj(σ) = [2]−q[3]q[4]−q· · ·[n](−1)n−1q.

Problem: for J ={sn−k+1, . . . ,sn−1} compute the polynomial X

σ∈JW

(−1)`(σ)qmaj(σ).

Does it factorize nicely? Is it an alternating version of Panova’s result? Yes. Yes.

(20)

An idea of Adin-Gessel-Roichman

Difficult to generalize Panova’s and Wachs’s proofs.

Use a catalytic parameter! (after an idea of Adin-Gessel-Roichman)

JW ={σ= [. . . ,n−k+ 1, . . . ,n−k+ 2, . . . ,n, . . .]}. Example

Ifn= 5 andk = 3 then

JW ={[12345],[13452],[21345],[23145],[23451],[31245], . . .} Let

s(σ) :=

σ(n)−1, ifσ(n)∈[n−k]; n−k, otherwise.

(21)

An idea of Adin-Gessel-Roichman

Difficult to generalize Panova’s and Wachs’s proofs.

Use a catalytic parameter!

(after an idea of Adin-Gessel-Roichman)

JW ={σ= [. . . ,n−k+ 1, . . . ,n−k+ 2, . . . ,n, . . .]}. Example

Ifn= 5 andk = 3 then

JW ={[12345],[13452],[21345],[23145],[23451],[31245], . . .} Let

s(σ) :=

σ(n)−1, ifσ(n)∈[n−k]; n−k, otherwise.

(22)

An idea of Adin-Gessel-Roichman

Difficult to generalize Panova’s and Wachs’s proofs.

Use a catalytic parameter! (after an idea of Adin-Gessel-Roichman)

JW ={σ= [. . . ,n−k+ 1, . . . ,n−k+ 2, . . . ,n, . . .]}. Example

Ifn= 5 andk = 3 then

JW ={[12345],[13452],[21345],[23145],[23451],[31245], . . .} Let

s(σ) :=

σ(n)−1, ifσ(n)∈[n−k]; n−k, otherwise.

(23)

An idea of Adin-Gessel-Roichman

Difficult to generalize Panova’s and Wachs’s proofs.

Use a catalytic parameter! (after an idea of Adin-Gessel-Roichman)

JW ={σ= [. . . ,n−k+ 1, . . . ,n−k+ 2, . . . ,n, . . .]}.

Example

Ifn= 5 andk = 3 then

JW ={[12345],[13452],[21345],[23145],[23451],[31245], . . .}

Let

s(σ) :=

σ(n)−1, ifσ(n)∈[n−k]; n−k, otherwise.

(24)

An idea of Adin-Gessel-Roichman

Difficult to generalize Panova’s and Wachs’s proofs.

Use a catalytic parameter! (after an idea of Adin-Gessel-Roichman)

JW ={σ= [. . . ,n−k+ 1, . . . ,n−k+ 2, . . . ,n, . . .]}.

Example

Ifn= 5 andk = 3 then

JW ={[12345],[13452],[21345],[23145],[23451],[31245], . . .}

Let

s(σ) :=

σ(n)−1, ifσ(n)∈[n−k];

n−k, otherwise.

(25)

A recursion

We let

fn,k(q,z) = X

σ∈JW

`(σ)qmaj(σ)zs(σ)

where=−1.

Theorem

For k= 1,2, . . . ,n−1

fn,k(q,z) = 1 1 +z

kzn−k + (−q)n−1

fn−1,k(q,1) + +nz(1−qn−1)fn−1,k(q,−z)

+zn−kfn−1,k−1(q,1). Does not restrict to a recursion forfn,k(q,1).

(26)

A recursion

We let

fn,k(q,z) = X

σ∈JW

`(σ)qmaj(σ)zs(σ)

where=−1.

Theorem

For k= 1,2, . . . ,n−1

fn,k(q,z) = 1 1 +z

kzn−k + (−q)n−1

fn−1,k(q,1) + +nz(1−qn−1)fn−1,k(q,−z)

+zn−kfn−1,k−1(q,1).

Does not restrict to a recursion forfn,k(q,1).

(27)

Explicit formulas

Now guess a formula and prove it.

Theorem (C, 2011) If k<n is odd we have

fn,k(q,z) = [k+ 1]−q[k+ 2]q· · ·[n−1]nq

·n−k−1X

i=0

(n+1)(n−i−1)ziqn−i−1+zn−k[k]n−1q .

If k<n−1 is even we have

fn,k(q,z) = [k+ 2]−q· · ·[n1]nq·

[k+ 1]nq[n]n−1q+ (z 1)

·n−k−1X

i=0

[k+ 1]nq[ni1]n+1qzi+

n−k−1

X

i=0 ieven

qn−i−1zi [k]−q[k]q .

(28)

Explicit formulas

Now guess a formula and prove it.

Theorem (C, 2011) If k<n is odd we have

fn,k(q,z) = [k+ 1]−q[k+ 2]q· · ·[n−1]nq

·n−k−1X

i=0

(n+1)(n−i−1)ziqn−i−1+zn−k[k]n−1q .

If k<n−1 is even we have

fn,k(q,z) = [k+ 2]−q· · ·[n1]nq·

[k+ 1]nq[n]n−1q+ (z 1)

·n−k−1X

i=0

[k+ 1]nq[ni1]n+1qzi+

n−k−1

X

i=0 ieven

qn−i−1zi [k]−q[k]q .

(29)

Explicit formulas

Now guess a formula and prove it.

Theorem (C, 2011) If k<n is odd we have

fn,k(q,z) = [k+ 1]−q[k+ 2]q· · ·[n−1]nq

·n−k−1X

i=0

(n+1)(n−i−1)ziqn−i−1+zn−k[k]n−1q .

If k<n−1 is even we have

fn,k(q,z) = [k+ 2]−q· · ·[n1]nq·

[k+ 1]nq[n]n−1q+ (z1)

·n−k−1X

[k+ 1]nq[ni1]n+1qzi+

n−k−1

X qn−i−1zi [k]−q[k]q .

(30)

The specialization

Corollary

For J ={sn−k+1,sn−k+2, . . . ,sn−1} we have fn,k(q,1) = X

σ∈JW

`(σ)qmaj(σ)

= [k+ 1]k+n+nkq[k+ 2]k+1q[k+ 3]k+2q· · ·[n]n−1q.

Hope someone will be able to explain this result. I have only been able to prove it.

(31)

The specialization

Corollary

For J ={sn−k+1,sn−k+2, . . . ,sn−1} we have fn,k(q,1) = X

σ∈JW

`(σ)qmaj(σ)

= [k+ 1]k+n+nkq[k+ 2]k+1q[k+ 3]k+2q· · ·[n]n−1q. Hope someone will be able to explain this result.

I have only been able to prove it.

(32)

The specialization

Corollary

For J ={sn−k+1,sn−k+2, . . . ,sn−1} we have fn,k(q,1) = X

σ∈JW

`(σ)qmaj(σ)

= [k+ 1]k+n+nkq[k+ 2]k+1q[k+ 3]k+2q· · ·[n]n−1q. Hope someone will be able to explain this result.

I have only been able to prove it.

(33)

Complex reflection groups

The group of r-colored permutations:

G(r,n) ={[σ1z1, . . . , σnzn] : σ∈Sn and zi ∈Zr}.

The infinite family of irreducible complex reflection groups: if p|r,

G =G(r,p,n) ={[σz11, . . . , σnzn]∈G(r,n) : z1+· · ·+zn≡0 mod p}.

And other related groups: we let Cp=h[1r/p, . . . ,nr/p]i and G :=G(r,n)/Cp.

(34)

Complex reflection groups

The group of r-colored permutations:

G(r,n) ={[σ1z1, . . . , σnzn] : σ∈Sn and zi ∈Zr}.

The infinite family of irreducible complex reflection groups: if p|r,

G =G(r,p,n) ={[σz11, . . . , σnzn]∈G(r,n) : z1+· · ·+zn≡0 mod p}.

And other related groups: we let Cp=h[1r/p, . . . ,nr/p]i and G :=G(r,n)/Cp.

(35)

Complex reflection groups

The group of r-colored permutations:

G(r,n) ={[σ1z1, . . . , σnzn] : σ∈Sn and zi ∈Zr}.

The infinite family of irreducible complex reflection groups: if p|r,

G =G(r,p,n) ={[σz11, . . . , σnzn]∈G(r,n) : z1+· · ·+zn≡0 mod p}.

And other related groups: we let Cp=h[1r/p, . . . ,nr/p]i and G :=G(r,n)/Cp.

(36)

Flag-major index

Ifg = [23 ,51 ,40 ,75 ,35,14,64]∈G(6,7) then

g = [215,513,412,711,35,14,64]. The exponents are

non-increasing;

strict at the “homogeneous” descents; as small as possible with these properties. We letλ(g) = (15,13,12,11,5,4,4) and fmaj(g) =|λ(g)|= 15 + 13 +· · ·+ 4 = 64.

Originally defined by Adin and Roichman for the groupG(r,n). X

g∈G

qfmaj(g)= [d1]q[d2]q· · ·[dn]q,

wheredi are the fundamental degrees ofG.

(37)

Flag-major index

Ifg = [23 ,51 ,40 ,75 ,35,14,64]∈G(6,7) then g = [215,513,412,711,35,14,64].

The exponents are non-increasing;

strict at the “homogeneous” descents; as small as possible with these properties. We letλ(g) = (15,13,12,11,5,4,4) and fmaj(g) =|λ(g)|= 15 + 13 +· · ·+ 4 = 64.

Originally defined by Adin and Roichman for the groupG(r,n). X

g∈G

qfmaj(g)= [d1]q[d2]q· · ·[dn]q,

wheredi are the fundamental degrees ofG.

(38)

Flag-major index

Ifg = [23 ,51 ,40 ,75 ,35,14,64]∈G(6,7) then g = [215,513,412,711,35,14,64].

The exponents are non-increasing;

strict at the “homogeneous” descents;

as small as possible with these properties. We letλ(g) = (15,13,12,11,5,4,4) and fmaj(g) =|λ(g)|= 15 + 13 +· · ·+ 4 = 64.

Originally defined by Adin and Roichman for the groupG(r,n). X

g∈G

qfmaj(g)= [d1]q[d2]q· · ·[dn]q,

wheredi are the fundamental degrees ofG.

(39)

Flag-major index

Ifg = [23 ,51 ,40 ,75 ,35,14,64]∈G(6,7) then g = [215,513,412,711,35,14,64].

The exponents are non-increasing;

strict at the “homogeneous” descents;

as small as possible with these properties.

We letλ(g) = (15,13,12,11,5,4,4) and fmaj(g) =|λ(g)|= 15 + 13 +· · ·+ 4 = 64.

Originally defined by Adin and Roichman for the groupG(r,n). X

g∈G

qfmaj(g)= [d1]q[d2]q· · ·[dn]q,

wheredi are the fundamental degrees ofG.

(40)

Flag-major index

Ifg = [23 ,51 ,40 ,75 ,35,14,64]∈G(6,7) then g = [215,513,412,711,35,14,64].

The exponents are non-increasing;

strict at the “homogeneous” descents;

as small as possible with these properties.

We letλ(g) = (15,13,12,11,5,4,4) and fmaj(g) =|λ(g)|= 15 + 13 +· · ·+ 4 = 64.

Originally defined by Adin and Roichman for the groupG(r,n). X

g∈G

qfmaj(g)= [d1]q[d2]q· · ·[dn]q,

wheredi are the fundamental degrees ofG.

(41)

Flag-major index

Ifg = [23 ,51 ,40 ,75 ,35,14,64]∈G(6,7) then g = [215,513,412,711,35,14,64].

The exponents are non-increasing;

strict at the “homogeneous” descents;

as small as possible with these properties.

We letλ(g) = (15,13,12,11,5,4,4) and fmaj(g) =|λ(g)|= 15 + 13 +· · ·+ 4 = 64.

Originally defined by Adin and Roichman for the groupG(r,n).

X

g∈G

qfmaj(g)= [d1]q[d2]q· · ·[dn]q,

wheredi are the fundamental degrees ofG.

(42)

Flag-major index

Ifg = [23 ,51 ,40 ,75 ,35,14,64]∈G(6,7) then g = [215,513,412,711,35,14,64].

The exponents are non-increasing;

strict at the “homogeneous” descents;

as small as possible with these properties.

We letλ(g) = (15,13,12,11,5,4,4) and fmaj(g) =|λ(g)|= 15 + 13 +· · ·+ 4 = 64.

Originally defined by Adin and Roichman for the groupG(r,n).

X

g∈G

qfmaj(g)= [d1]q[d2]q· · ·[dn]q,

wheredi are the fundamental degrees ofG.

(43)

A bijection ` a la Garsia-Gessel

Want to extend Panova’s result to these groups.

Lemma The map

G× Pn× {0,1, . . . ,p−1} −→ Nn

(g, λ,h) 7→ f = (f1, . . . ,fn), where fi|g−1(i)|(g) +rλ|g−1(i)|+hrp for all i ∈[n], is a bijection. And in this case we say that f is g -compatible. Fork <n we let

Ck ={[σ10, σ20, . . . , σ0k,gk+1, . . . ,gn]∈G : σ1<· · ·< σk}.

(44)

A bijection ` a la Garsia-Gessel

Want to extend Panova’s result to these groups.

Lemma The map

G× Pn× {0,1, . . . ,p−1} −→ Nn

(g, λ,h) 7→ f = (f1, . . . ,fn), where fi|g−1(i)|(g) +rλ|g−1(i)|+hrp for all i ∈[n], is a bijection. And in this case we say that f is g -compatible.

Fork <n we let

Ck ={[σ10, σ20, . . . , σ0k,gk+1, . . . ,gn]∈G : σ1<· · ·< σk}.

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A bijection ` a la Garsia-Gessel

Want to extend Panova’s result to these groups.

Lemma The map

G× Pn× {0,1, . . . ,p−1} −→ Nn

(g, λ,h) 7→ f = (f1, . . . ,fn), where fi|g−1(i)|(g) +rλ|g−1(i)|+hrp for all i ∈[n], is a bijection. And in this case we say that f is g -compatible.

Fork <n we let

Ck ={[σ10, σ20, . . . , σ0k,gk+1, . . . ,gn]∈G : σ1<· · ·< σk}.

(46)

The result

Theorem (C. 2011) Let G =G(r,p,n). Then

X

g∈Ck

qfmaj(g−1)= [p]qkr/p[r(k+ 1)]q· · ·[r(n−1)]q[rn/p]q.

Corollary

If G =G(r,n), then Ck is a system of coset representatives for the (parabolic) subgroup G(r,k) and

X

g∈Ck

qfmaj(g−1) = [r(k+ 1)]q[r(k+ 2)]q· · ·[rn]q.

(47)

The result

Theorem (C. 2011) Let G =G(r,p,n). Then

X

g∈Ck

qfmaj(g−1)= [p]qkr/p[r(k+ 1)]q· · ·[r(n−1)]q[rn/p]q.

Corollary

If G =G(r,n), then Ck is a system of coset representatives for the (parabolic) subgroup G(r,k) and

X

g∈Ck

qfmaj(g−1) = [r(k+ 1)]q[r(k+ 2)]q· · ·[rn]q.

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Longest increasing subsequence

Elements starting with a longest 0-colored increasing subsequence Πr,n,k := {g = [σ01, . . . , σn−k0 , σn−k+1zn−k+1, . . . , σznn]∈G(r,n) :

σ1 <· · ·< σn−k and no increasing subsequence of lengthn−k+ 1colored with 0}.

Theorem

If n≥2k we have that X

g∈Πr,n,k

qfmaj(g−1)=

k

X

i=0

(−1)i k

i

[r(n−i+1)]q[r(n−i+2)]q· · ·[rn]q.

(49)

Longest increasing subsequence

Elements starting with a longest 0-colored increasing subsequence Πr,n,k := {g = [σ01, . . . , σn−k0 , σn−k+1zn−k+1, . . . , σznn]∈G(r,n) :

σ1 <· · ·< σn−k and no increasing subsequence of lengthn−k+ 1colored with 0}.

Theorem

If n≥2k we have that X

g∈Πr,n,k

qfmaj(g−1)=

k

X

i=0

(−1)i k

i

[r(n−i+1)]q[r(n−i+2)]q· · ·[rn]q.

(50)

Open problems

Problem

Let J0 = [k]. Numerical evidence shows that X

σ∈J0Sn

(−1)`(σ)qmaj(σ)= X

u∈JSn

(−1)`(σ)qmaj(σ)

if and only if n is odd or k is even (or both). Give a (possibly bijective) proof of this phenomenon.

Problem

Unify the main results of this work in a unique statement, i.e. compute the polynomials

X

g∈Ck

`(|g|)qfmaj(g−1).

This is known to have nice factorization ifk = 0 (Biagioli-C.)

(51)

Open problems

Problem

Let J0 = [k]. Numerical evidence shows that X

σ∈J0Sn

(−1)`(σ)qmaj(σ)= X

u∈JSn

(−1)`(σ)qmaj(σ)

if and only if n is odd or k is even (or both). Give a (possibly bijective) proof of this phenomenon.

Problem

Unify the main results of this work in a unique statement, i.e.

compute the polynomials X

g∈C

`(|g|)qfmaj(g−1).

This is known to have nice factorization ifk = 0 (Biagioli-C.)

(52)

Open problems

Problem

Let J0 = [k]. Numerical evidence shows that X

σ∈J0Sn

(−1)`(σ)qmaj(σ)= X

u∈JSn

(−1)`(σ)qmaj(σ)

if and only if n is odd or k is even (or both). Give a (possibly bijective) proof of this phenomenon.

Problem

Unify the main results of this work in a unique statement, i.e.

compute the polynomials X

g∈Ck

`(|g|)qfmaj(g−1).

This is known to have nice factorization ifk = 0 (Biagioli-C.)

参照

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