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doi:10.1155/2010/868059

Research Article

Exact Solutions for Nonclassical Stefan Problems

Adriana C. Briozzo and Domingo A. Tarzia

Departamento de Matem´atica-CONICET, FCE, Universidad Austral, Paraguay 1950, S2000FZF Rosario, Argentina

Correspondence should be addressed to Domingo A. Tarzia,[email protected] Received 17 February 2010; Revised 17 June 2010; Accepted 3 August 2010

Academic Editor: Maurizio Grasselli

Copyrightq2010 A. C. Briozzo and D. A. Tarzia. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

We consider one-phase nonclassical unidimensional Stefan problems for a source functionFwhich depends on the heat flux, or the temperature on the fixed facex0. In the first case, we assume a temperature boundary condition, and in the second case we assume a heat flux boundary condition or a convective boundary condition at the fixed face. Exact solutions of a similarity type are obtained in all cases.

1. Introduction

The one-phase Stefan problem for a semi-infinite material is a free boundary problem for the classical heat equation which requires the determination of the temperature distribution u of the liquid phase melting problem or the solid phase solidification problem and the evolution of the free boundary x st.Phase change problems appear frequently in industrial processes and other problems of technological interest1–4.

Nonclassical heat conduction problem for a semi-infinite material was studied in5–

11. A problem of this type is the following:

i utuxx−FWt, t, x >0, t >0, ii u0, t ft, t >0,

iii ux,0 hx, x >0,

1.1

where functionsfftand hhxare continuous real functions, andFis a given function of two variables. A particular and interesting case is the following:

FWt, t λ0

tWt λ0>0, 1.2

(2)

where W Wt represents the heat flux on the boundary x 0, that is Wt ux0, t.Problems of the types1.1and1.2can be thought of by modelling of a system of temperature regulation in isotropic mediums10,11, with a nonuniform source term which provides a cooling or heating effect depending upon the properties ofFrelated to the course of the heat fluxor the temperature in other casesat the boundaryx010.

In the particular case of a bounded domain, a class of problems, when the heat source is uniform and belongs to a given multivalued function fromRinto itself, was studied in 8 regarding existence, uniqueness, and asymptotic behavior. Moreover, in5conditions are given on the nonlinearity of the source termF so as to accelerate the convergence of the solution to the steady-state solution. Other references on the subject are in7,12,13.

Nonclassical free boundary problems of the Stefan type were recently studied in14–

16from a theoretical point of view by using an equivalent formulation through a system of second kind Volterra integral equations17–19. A large bibliography on free boundary problems for the heat equation was given in20.

In this paper, firstly we consider a free boundary problem which consists in determining the temperature u ux, t and the free boundary x st such that the following conditions are satisfied:

ρcutkuxx −γFWt, t, 0< x < st, t >0, 1.3

u0, t f >0, t >0, 1.4

ust, t 0, t >0, 1.5

kuxst, t −ρlst,˙ t >0, 1.6

s0 0, 1.7

where the thermal coefficientsk, ρ, c, l, γ >0,the boundary temperaturef >0,and the control functionFdepend on the evolution of the heat flux at the boundaryx0 as follows:

Wt ux0, t, FWt, t Fux0, t, t √λ0

tux0, t, 1.8 whereλ0>0 is a given constant.The existence and the uniqueness of the solution of a general free boundary problem of the type1.3–1.8was given recently in14,15. Moreover, we consider other two free boundary problems which consist in determining the temperature uux, tand the free boundaryxstsuch that1.3,1.5,1.6, and1.7are satisfied, and in these cases the control functionF depends on the evolution of the temperature at the boundaryx0 as follows:

Wt u0, t, FWt, t Fu0, t, t λ0

t u0, t, λ0>0. 1.9 In this case, a heat flux boundary condition

kux0, t −q0

t >0, t >0 1.10

(3)

or a convective boundary condition

kux0, t q0

t

u0, tf

>0, t >0 1.11

can be considered at the fixed face x 0 in order to obtain the corresponding explicit solutions.

The plan of this paper is the following. InSection 2, we show an explicit solution of a similarity type for the nonclassical one-phase Stefan problem1.3–1.7for a control function Fgiven by1.8.

In Sections3and4, we obtain sufficient conditions on data in order to have a similarity type solution to the problems 1.3,1.5, 1.6, and 1.7, where the control functionF is given by1.9 instead of1.8and we take into account the heat flux condition1.10or the convective condition1.11at the fixed facex0, respectively.

The restrictions on data we have obtained for these two free boundary problems with a heat flux boundary condition1.10or a convective boundary condition1.11at the fixed facex 0 can be interpreted in the same way as we have obtained in the classical Stefan problem with the same boundary conditions in21,22in order to have an instantaneous phase-change problemsee, e.g., sufficient conditionλ0< ρc/2γin Theorems3.2and4.1.

2. Explicit Solution to a One-Phase Stefan Problem for a Nonclassical Heat Equation with Control Function of the Type Fu

x

0 , t, t λ

0

/

tu

x

0 , t and

a Temperature Condition at the Fixed Boundary

We consider the following free boundary problem for a semi-infinite material given by the following conditions:

ρcutkuxx−γFux0, t, t, 0< x < st, t >0, u0, t f >0, t >0,

ust, t 0, t >0, kuxst, t −ρlst,˙ t >0,

s0 0,

2.1

where the thermal coefficients k, ρ, c, l, γ are positive and the control function F, which depends on the evolution of the heat flux at the extremumx0,is given by1.8.

In order to obtain an explicit solution of a similarity type, we define

Φ η

ux, t, η x

2a√

t, 2.2

(4)

wherea2 k/ρcis the diffusion coefficient of the phase change material. The problem2.1 and1.8become

Φ η

2ηΦ η

2λΦ0, 0< η < η0, 2.3

Φ0 f, 2.4 Φ

η0

0, 2.5

Φ η0

−2l

0, 2.6

where the dimensionless parameterλis defined by

λ γλ0

ρca >0, 2.7

and the free boundarystmust be of the type st 2aη0

t, 2.8

where η0 is an unknown parameter to be determined later. The general solution of the differential equation2.3is given by

Φ η

C2C1

π 2 erf

η

η

0

f1zdz

, 2.9

whereC1and C2 are arbitrary constants, and

erfx 2

π x

0

exp

−z2

dz, f1x exp

−x2 x

0

exp r2

dr 2.10

are the error function and the Dawson’s integral see 23, page 298 and 24, page 43, respectively.

After some elementary computations, from2.3,2.4, and2.5we obtain

Φ η

f 1− E η, λ E

η0, λ

, 0< η < η0, 2.11

where

Ex, λ erfx 4λ

π x

0

f1rdr. 2.12

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Taking into account condition2.6, the unknown parameterη0 η0λ,Stemust be the solution of the following equation:

√Ste π

exp

−x2

2λf1x x

erfx 4λ

π x

0

f1zdz

, x >0, 2.13

where Ste fc/l > 0 is the Stefan’s number. Equation2.13is equivalent to the following one:

W1x 2λW2x, x >0, 2.14

where the real functionsW1 andW2are defined by

W1x Ste exp

−x2

−√

πxerfx, 2.15

W2x 2x x

0

f1rdr−Stef1x. 2.16

Remark 2.1. Ifλ 0i.e.,λ0 0, then the problem2.1and1.8represented the classical Lam´e-Clapeyron problem 25. In this case, there exists a unique solution η00 of 2.17 equivalent to2.13given by

F0x Ste

π, x >0, 2.17

where

F0x xerfxexp x2

, 2.18

and the explicit solution is given by2,23:

ux, t f 1− erf η erf

η00

, 0< η x 2a√

t < η00, st 2aη00

t.

2.19

In order to solve2.14, we will study firstly the behavior of functionf1.We obtain some preliminary properties.

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Lemma 2.2. The Dawson’s integral satisfies the following properties:

if10 0, iif1∞ 0, iii

f1x 1−2xf1x

⎧⎪

⎪⎪

⎪⎪

⎪⎩

>0 if 0< x < x1, 0 ifxx1,

<0 ifx > x1,

2.20

wherex10.924, f1x10.541, iv

f1x −2

1f1x

1−2x2

⎧⎪

⎪⎪

⎪⎪

⎪⎩

<0 if 0< x < x2, 0 ifxx2,

>0 ifx > x2,

2.21

wherex21.502, f1x20.428, vlimx2xf1x 1.

Proof. The propertiesi–ivhave been proved in23, page 298 see also24, pages 42–45 vBy the L’Hopital Theorem, we have

xlim2xf1x lim

x

2xx

0 exp r2

dr expx2 lim

x→∞

x

0 exp r2

drxexp x2 xexpx2 lim

x

1

x

0 exp r2

dr xexpx2

lim

x

1f1x x

1,

2.22

thenvholds.

Next, we define the following auxiliary functions:

ϕ1x x

0

f1rdr, ϕ2x 1x x x

0

f1rdr, ϕ3x xf1x, ϕ4x x

2xf1x−1

−xf1x, ϕ5x f1x−xf1x, ϕ6x Ste−21Stexf1x.

2.23

We have the following results.

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Lemma 2.3.

aFunctionϕ1 satisfies the following properties:

iϕ10 0, iiϕ1x f1x, iiiϕ10 0, ivϕ1∞ ∞,

v

ϕ1x f1x 1−2xf1x

⎧⎪

⎪⎨

⎪⎪

>0 if 0< x < x1, 0 ifxx1,

<0 ifx > x1,

2.24

vilimxϕ1x/logx 1/2, viilimxϕ1xf1x 0.

bFunctionϕ4 satisfies the following properties:

iϕ40 0,

iiϕ4x −14xf1x−2x22xf1x−1, iiiϕ4∞ 0,

ivϕ40 −1, vϕ4∞ 0,

viϕ4x 0⇔xx1 the maximum point of f1, viiϕ4x1 1.

cFunctionϕ3 satisfies the following properties:

iϕ30 0, iiϕ3∞ 1/2,

iiiϕ3x f1x x1−2xf1x, ivϕ30 0,

vϕ3∞ 0,

viϕ3x1 x1f1x10.4999, viiϕ3x2 x2f1x20.64.

dFunctionϕ2 satisfies the following properties:

iϕ20 0, iiϕ2∞ ∞,

iiiϕ2x ϕ1x xf1x>0,for allx >0, ivϕ20 0,

vϕ2∞ ∞,

viϕ2x 2f1x−x2xf1x−1, viiϕ2∞ 0,

viiiϕ20 0.

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eFunctionϕ5 satisfies the following properties:

iϕ50 0, iiϕ5∞ 0, iii

ϕ5x −xf1x

⎧⎪

⎪⎪

⎪⎪

⎪⎩

>0 if 0< x < x2, 0 ifxx2,

<0 ifx > x2,

2.25

ivϕ5x>0,for allx >0.

fFunctionϕ6 satisfies the following properties:

iϕ60 Ste>0, iiϕ6∞ −1,

iiiϕ6x −21Steϕ3x, ivϕ60 0,

vϕ6∞ 0,

viϕ6x1 x1f1x10.4999, viiϕ6x2 x2f1x20.64.

Proof. aTaking into account properties off1, we have

ϕ1x f1x>0, ∀x >0, ϕ10 f10 0, 2.26 andvholds. If we considerLemma 2.2v, we getϕ1∞ ∞and we have

xlim

ϕ1x

logx lim

xxf1x 1

2, 2.27

thenivandvihold.

To provevii, we consider ϕ1xf1x

x

0

f1rdr

f1x f1cxf1x, 2.28

whereccx∈0, x.Then limx→∞ϕ1xf1x 0 because limx→∞xf1x 0 andf1 is a bounded function.

bFrom the definition ofϕ4,we obtainiandii. To proveiii, we have

ϕ4∞ lim

x→∞x

2xf1x−1 lim

x

2xf1x−1 1/x lim

x→∞2

f1x x

1−2xf1x

1/x2 2 lim

x→∞

x2f1x x2x

1−2xf1x ,

2.29

(9)

then

xlim→∞x

2xf1x−1

2 lim

x

x2x

2xf1x−1

x2f1x

. 2.30

If we suppose that

xlim→∞x

2xf1x−1

L >0, 2.31

we get

L2 lim

x→∞

x2x

2xf1x−1

x2f1x

∞, 2.32

which is a contradiction. If we suppose that

xlimx

2xf1x−1

∞, 2.33

then

ϕ4∞ lim

x−14xf1x−2x2

2xf1x−1

−∞, 2.34

which is also a contradiction. Therefore, limx→∞x2xf1x−1 0 andiiihold.

Taking into accountii, we haveϕ4x −14xf1x−2x22xf1x−1,then ϕ40

−1 and if we consideriiiwe haveϕ4∞ 0.From properties off1,we have

ϕ4x 0⇐⇒2xf1x−10⇐⇒f1x 0⇐⇒xx1, 2.35 andviholds. Taking into accountf1x 1−2xf1x 0,we getϕ4x1 1.

cFrom Lemmas2.2and2.3bwe geti–vii.

dWe haveϕ2x 1x xx

0 f1rdr,then fromaandbiiiwe geti–vi.

eAs we haveϕ5x f1x−xf1x f1x ϕ4x,then by using the properties of f1 andbwe obtain the properties ofϕ5.

fWe haveϕ6x Ste−21Stexf1x Ste−21Steϕ3x,and from the properties ofϕ3,we obtaini–v.

Corollary 2.4. One has

ilimxx22xf1x−1 1/2,

iilimxxx22xf1x−1−xf1x 0.

Now, we are in conditions to enunciate properties of functionsW1 andW2in order to study after2.14.

Lemma 2.5. The functionsW1xandW2x,defined by2.15and2.16, respectively, satisfy the following properties.

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aProperties of functionW1: iW10 Ste, iiW1∞ −∞,

iiilimxW1x/x −√ π, ivlimxW1x √

πx 0, vW1x<0,for allx >0,

viW1η00 0,whereη00is the unique solution of 2.17, vii

W1x

⎧⎪

⎪⎪

⎪⎪

⎪⎩

<0 if 0< x < x0, 0 ifxx0,

<0 ifx > x0,

2.36

where

x0

32 Ste

41Ste, 2.37

viiiW10 −232 Ste<0.

bProperties of functionW2: iW20 0,

iiW2∞ ∞,

iiithere exists a uniquex4>0 such thatW2x4 0, ivW2x 2x

0f1rdr2xf1x1Ste−Ste,

vthere exists a uniquex3>0 such that W2x3 0 andW2x3<0, viW20 −Ste<0,

viiW2∞ ∞,

viiiW2x 21Stex2f1x2Ste−21Stex2, ixW20 0,

xW2η00<0.

Proof. aTaking into account the definition of the functionW1,we getiandii.

iiiWe have

xlim

W1x

x lim

x Steexp

−x2

x −√

πerfx

−√

π. 2.38

(11)

ivWe have

xlim

W1x √ πx

lim

x→∞

Ste exp

−x2

−√

πxerfx √ πx lim

x→∞

Ste exp

−x2

πxerfcx lim

x→∞

Ste exp

−x2

Qxexp

−x2

lim

x→∞exp

−x2

SteQx 0,

2.39

whereQis the function defined by

Qx

πxexp x2

erfcx, erfcx 1−erfx, 2.40

which satisfies the following properties:

Q0 0, Q∞ 1, Qx>0, ∀x >0. 2.41 vWe have

W1x −√

πerfx−2xexp

−x2

Ste1<0, ∀x >0. 2.42 viTaking into accounti,iii, andv, we get that there exists a unique zero ofW1

which is given byη00,the unique solution of2.17.

viiWe have

W1x −2 exp

−x2

32Ste−41Stex2

, 2.43

then

W1x 0⇐⇒41Stex2 32Ste⇐⇒xx0

32Ste

41Ste. 2.44

Since signW1x sign41Stex2−3−2Ste,then we obtainvii.

bTaking into account Lemmas2.2and2.3, we haveiandii.

We can write W2x 2

x

0

f1rdr2xf1x1Ste−Ste2ϕ1x−ϕ6x, 2.45

thenW20 −Ste, W2∞ ∞ andW2x 2ϕ1x−ϕ6xsatisfiesW20 0.Then iv,vi,vii,viii, andixhold.

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We have

W2x 0⇐⇒2ϕ2x Stef1x, 2.46

then taking into account the properties ofϕ2 andf1, we get that there exists a uniquex4 >

0 such that

W2x 0, x >0. 2.47

Moreover, we have

W2x

⎧⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎩

0 ifx0,

<0 if 0< x < x4, 0 ifxx4,

>0 ifx > x4.

2.48

In the same way, we have

W2x 0⇐⇒2ϕ1x ϕ6x. 2.49

Then, if we consider the properties of the functions ϕ1 andϕ2, we have that there exists a uniquex3 such thatW2x3 0.Moreover,W2x3 −2x23f1x3−Steϕ5x3<0 and thenv holds.

To provex,we take into account that

W2x 2x x

0

f1rdr−Stef1x √

πxerfxFx−√ πx

x

0

erfrexp r2

dr−Ste exp

−x2 Fx

πexp

−x2

F0x− Ste

π

Fx−√ πx

x

0

erfrexp r2

dr,

2.50

whereFx x

0expr2drand F0was defined in2.18. Then by using2.17, we have

W2

η00

−√ πη00

η00

0

erfrexp r2

dr <0. 2.51

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Lemma 2.6. For eachλ > 0,there exists a unique solutionη0of 2.14. This solutionη0 η0λ satisfies the following properties:

i η00 η00, ii η0x4,

iii η0 η0λis an increasing function onλ,

2.52

whereη00andx4are the unique solution of 2.17and2.47, respectively.

Proof. Taking into accountLemma 2.5, we get that there exists a unique solutionη0of2.14.

Let 0 < λ1 < λ2 be given, taking into account properties of functionW2,we obtain that the real functionsZ1 andZ2defined by

Z1x 2λ1W2x, Z2x 2λ2W2x 2.53

satisfy the following properties:

Z2x< Z1x if 0< x < x4, Z2x Z1x if xx4, Z2x> Z1x if x > x4.

2.54

Then η0λ1 < η0λ2, where η0λiis the solution of equation Zix W1x, i 1,2.Therefore,η0 η0λis an increasing function onλ.Moreover, we obtainη00 < η0λ <

x4 becauseW2η00<0.

Then, we have proved the following result.

Theorem 2.7. For eachλ > 0,the free boundary problem2.1, whereF is defined by1.8, has a unique similarity solution of the type

ux, t, λ f 1− En, λ E

η0λ, λ

, 0< η x 2a√

t < η0λ, st, λ 2aη0λ√

t,

2.55

where

E η, λ

erf η

√4λ π

η

0

f1rdr 2.56

andη0η0λis the unique solution of 2.14withη00 < η0λ< x4.

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3. Explicit Solution to a One-Phase Stefan Problem for a Nonclassical Heat Equation with Control Function of the Type Fu0 , t, t λ

0

/tu0 , t and

a Heat Flux Condition at the Fixed Face

In this section, the free boundary problem consists in determining the temperatureuux, t and the free boundaryxstwith a control functionFwhich depends on the evolution of the temperature at the extremumx0 given by the following conditions:

ρcutkuxx −γFu0, t, t, 0< x < st, t >0, kux0, t −q0

t >0, t >0, ust, t 0, t >0, kuxst, t −ρlst,˙ t >0,

s0 0,

3.1

where the coefficientq0 > 0 characterizes the heat flux on the x 0 21and the control functionF is given by1.9.

In order to obtain an explicit solution of a similarity type, we define the same transformation given by2.2. The problem3.1and1.9are equivalent to the following one:

Φ η

2ηΦ η

ΛΦ0, 0< η < μ0, 3.2 Φ0 −q0, 3.3

Φ μ0

0, 3.4

Φ μ0

−2l

0, 3.5

where the dimensionless parametersΛ andq0are defined by

Λ 4γλ0

ρc >0, q0 2aq0

k , 3.6

st 2aμ0

t 3.7

is the free boundary, whereμ0is an unknown parameter to be determined.

From3.2,3.3, and3.4, we obtain the similarity solution

Φ η

q0π 2G

μ0,Λ erf

μ0

G η,Λ

−erf η

G μ0,Λ

, 0< η < μ0, 3.8

(15)

where

Gx,Λ 1 Λ x

0

f1rdr 1 Λϕ1x, 3.9

andf1is the Dawson’s integral andϕ1is given by2.23.

By condition3.5, the unknown parameterμ0μ0Λ, l, c, q0must be solution of the following equation:

Λerfxf1x 2

πGx,Λ exp

−x2

− 2l cq0x

, x >0, 3.10

which is equivalent to the following one:

H2x H3x, x >0, 3.11

where the real functionsH2 andH3are defined by

H2x Λerfxf1x, 3.12

H3x 2

πGx,ΛH1x, 3.13

H1x exp

−x2

− 2l cq0x

. 3.14

Remark 3.1. IfΛ 0i.e.,λ00, we have the solution

Φ η

q0π 2

erf μ00

−erf η

, 0< η < μ00, 3.15

whereμ00 is the unique solution of the following equation:

exp

−x2 2l

cq0x. 3.16

In order to solve3.11, we consider properties of Dawson’s integral, error function, and some auxiliary functions, and then we obtain the following result.

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Theorem 3.2. For eachλ0< ρc/2γ, the free boundary problem3.1, whereFis defined by1.9, has a unique similarity solution of the type

ux, t, λ0 q0aπ kG

μ0λ0,4γλ0/ρc

erf x

2a√ t

G

μ0λ0,4γλ0

ρc

−erf μ0λ0

G x

2a√ t,4γλ0

ρc

, 0< x

2a√

t < μ0λ0, t >0, st, λ0 2aμ0λ0

t, t >0,

3.17

whereμ0μ0λ0is the unique solution of 3.11, 0< μ0λ0< μ00. Proof. We follow a similar method developed inTheorem 2.7.

4. Explicit Solution to a One-Phase Stefan Problem for a Nonclassical Heat Equation with Control Function of the Type Fu0 , t, t λ

0

/tu0 , t and

a Convective Condition at the Fixed Face

In this section, we consider a similar problem to the one given inSection 3for a convective boundary condition22,26on the fixed face given by

ρcutkuxx −γFu0, t, t, 0< x < st, t >0, kux0, t √h0

t

u0, tf

>0, t >0, ust, t 0, t >0,

kuxst, t −ρlst,˙ t >0, s0 0,

4.1

whereF is defined by1.9andh0characterizes the heat transfer coefficients22,26. To solve this problem, we consider again a similarity type solution given by2.2. Then, the problem 4.1and1.9are equivalent to the following one:

Φ η

2ηΦ η

ΛΦ0, 0< η < μ0, 4.2

Φ0 h0

Φ0−f

, h0 2ah0

k , 4.3

Φ μ0

0, 4.4

Φ μ0

−2l

0, 4.5

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where the dimensionless parameterΛis defined by3.6and st 2aμ0

t 4.6

is the free boundary, whereμ0 is an unknown parameter to be determined. We obtain the solution

Φ η

h0fπ 2

erf μ0

G η,Λ

−erf η

G μ0,Λ G

μ0,Λ

h0π/2

erf μ0

, 0< η < μ0, 4.7

where Gx,Λ is given by 3.9. Taking into account the condition 4.5, the unknown parameterμ0μ0Λ, l, c, h0must be the solution of the following equation:

Λerfxf1x 2

Steerfxx 2

πGx,Λ exp

−x2

− 2 h0Stex

, x >0, 4.8

which is equivalent to

H2x H3x, x >0, 4.9

where

H2x H2x 2

Steerfxx, x >0, H3x 2

πGx,Λ exp

−x2

− 2 h0Stex

, x >0,

4.10

and the functionH2is defined by3.12.

Similarly to the previous cases, we can enunciate the following result.

Theorem 4.1. aFor eachΛ<2 (λ0< ρc/2γ, the free boundary problem4.1, whereFis defined by1.9, has a unique similarity solution given by

ux, t, λ0

−h0afπ k

⎢⎣ erf x/2a

t G

μ0λ0,4γλ0/ρc h0af

π/k erf

μ0λ0 G

μ0λ0,4γλ0/ρc

− erf μ0λ0

G x/2a

t,4γλ0/ρc h0af

π/k erf

μ0λ0 G

μ0λ0,4γλ0/ρc

⎥⎦,

0< x 2a√

t < μ0λ0, t >0, st, λ0 2aμ0λ0

t, t >0,

4.11

whereμ0μ0λ0is the unique solution of 4.9.

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bLetMx Λf1xandNx 2xGx,Λbe, there exists a unique solutionx>0 of the equationMx Nx.

For eachΛ>0> ρc/2γsuch thatMαΛ−NαΛ<2/h0Ste, where 0< αΛ< x satisfiesMαΛ−NαΛ 0,there exists a unique similarity solution to the free boundary problem3.1, whereFis defined by1.9. The solution is given by4.11.

Acknowledgments

This paper has been partially sponsored by Projects PIP no. 0460 from CONICET-UA Rosario, Argentina and Fondo de Ayuda a la Investigacion de la Universidad Austral Argentina. The authors would like to thank the three referees for their constructive comments which improved the readability of the paper.

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