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A URYSOHN TYPE LEMMA FOR GROUPOIDS

M ˘AD ˘ALINA ROXANA BUNECI

Abstract. Starting from the observation that through groupoids we can express in a unified way the notions of fundamental system of entourages of a uniform structure on a spaceX, respectively the system of neighborhoods of the unity of a topological group that determines its topology, we introduce in this paper a notion ofG-uniformity for a groupoidG. The topology induced by aG-uniformity turnsGinto a topological locally transitive groupoid.

We also prove a Urysohn type lemma for groupoids and obtain metrization theorems for groupoids unifying in two ways the Alexandroff–Urysohn Theorem and Birkhoff- Kakutani Theorem.

1. Introduction and preliminaries

The notion of groupoid is a natural generalization of the notion of group in the following sense: a groupoid is a set G endowed with partially defined product operation (x, y)7→

xy

:G(2) →G

(where G(2) ⊂ G×G) and an inversion operation x 7→ x−1 [:G→G]

satisfying the subsequent weaker versions of the group axioms:

G1 If (x, y) ∈ G(2) and (y, z) ∈ G(2), then (xy, z) ∈ G(2), (x, yz) ∈ G(2) and (xy)z = x(yz).

G2 (x−1)−1 =x for all x∈G.

G3 For all x∈G, (x, x−1)∈G(2), and if (z, x)∈G(2), then (zx)x−1 =z.

G4 For all x∈G, (x−1, x)∈G(2), and if (x, y)∈G(2), thenx−1(xy) = y.

The maps r and d on G, defined by the formulae r(x) = xx−1 and d(x) = x−1x, are called the range (target) map, respectively the domain (source) map. They have a common image called the unit space of G and denotedG(0). The fibres of the range and the domain maps are denoted Gu =r−1({u}) and Gv =d−1({v}), respectively. Also for u, v ∈G(0),Guv =Gu∩Gv.

A topological groupoid is a groupoid G together with a topology on G such that the product operation (x, y) 7→ xy

:G(2) →G

(where G(2) ⊂ G×G is endowed with the topology induced by the product topology on G×G) and the inversion operation

Received by the editors 2016-11-03 and, in final form, 2017-07-31.

Transmitted by Ronald Brown. Published on 2017-08-02.

2010 Mathematics Subject Classification: 22A22; 54E15, 54E35.

Key words and phrases: groupoid, Urysohn-type lemma, metrization theorem.

c ad˘alina Roxana Buneci, 2017. Permission to copy for private use granted.

970

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x 7→ x−1 [:G→G] are continuous functions. A family {Wj}j∈J of neighborhoods of the unit space is said to be compatible with the topology of the r-fibres (respectively, d-fibres) if for every u ∈ G(0) and every open neighborhood U of u, there is j ∈ J such that Wj∩Gu ⊂U ∩Gu and u is in the interior of Wj ∩Gu with respect to the topology onGu coming fromG(respectively,Wj∩Gu ⊂U∩Gu anduis in the interior of Wj∩Gu

with respect to the topology onGu coming from G).

Let us also recall that a uniform space is a setX endowed with a uniform structure. A fundamental system of symmetric entourages of a uniform structure on X is a nonempty familyW of subsets of the Cartesian productX×X that satisfies the following conditions:

U1 if W is in W, thenW contains the diagonal ∆ ={(x, x) :x∈X}.

U2 if W1 and W2 are inW, then there is W3 ∈ W such that W3 ⊂W1∩W2.

U3 if W1 is in W, then there exists W2 inW such that, whenever (x, y) and (y, z) are in W2, then (x, z)∈W1.

U4 if W ∈ W, then W =W−1 ={(y, x) : (x, y)∈W}(W is a symmetric entourage).

The uniform space X becomes a topological space by defining a subset A ⊂X to be open if and only if for everyx∈A there is Wx ∈ W such that {y: (x, y)∈Wx} ⊂A.

The Cartesian product X×X can be viewed as a trivial groupoid G under the oper- ations: (x, y) (y, z) = (x, z) and (x, y)−1. In the settings of groupoids condition U1 can be written as ”G(0) ⊂ W ⊂G for all W ∈ W” and condition U3 as ”for every W1 ∈ W there is W2 ∈ W such that W2W2 ⊂W1”.

In this paper we work with a collection of subsets of a groupoid G mimicking the properties of fundamental system of symmetric entourages of a uniform structure on X.

Such a collection will be called in this paperG-uniformity. We prove that aG-uniformity induces a topology on G that turns G into a topological locally transitive groupoid. Let us recall that a topological locally transitive groupoid is a topological groupoidGwith the property that for all u∈G(0) the maps ru are open, where ru :Gu →G(0), ru(x) =r(x) for allx∈Gu andGu is endowed with the topology coming fromG(see [12]). If we begin with a topological groupoid (G, τ) and with aG-uniformity given by a fundamental system of neighborhoods of the unit space, then the topology induced by deG-uniformity is finer than τ and coincides with τ if and only if (G, τ) is locally transitive. The main result of this paper is a Urysohn type lemma for groupoids (Theorem 2.5). The existence of a function with properties 1−3 in Theorem 2.5 could also be obtained taking into account that aG-uniformity is a base for a uniform structure onG. However the topology defined by the G-uniformity do not necessarily coincides with the groupoid topology, even if the G-uniformity is given by a fundamental system of neighborhoods of the unit space. The construction in Theorem 2.5 allows us to get a function with additional properties. In particular, in the case of a topological groupoid with open range map and aG-uniformity given by a fundamental system of neighborhoods of the unit space, our construction allows us to put out a connection with the groupoid topology: the functions f associated

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in Theorem2.5 with open subsets of Gor with G(0) are upper semi-continuous on Gand their restrictions to the r-fibres as well as to the d-fibres of the groupoid are continuous functions. Thus these functions can be used to construct convolutions algebras as in [4] and possibly to extend the construction of a C-algebra associated to a topological locally compact groupoid with continuous Haar system introduced in [11]. Moreover the property 9 in Theorem 2.5 allows us to obtain metrization theorems for groupoids and thus to express in an unified way Alexandroff–Urysohn Theorem and Birkhoff-Kakutani Theorem as we explain below. Let us consider the following two theorems:

1.1. Theorem.[Alexandroff–Urysohn Theorem] A topological Hausdorff spaceX is me- trizable if and only if its topology is given by a uniformity with countable base. [1]

1.2. Theorem.[Birkhoff-Kakutani Theorem] A topological group Gis metrizable if and only if there is a countable base for the topology at identity element in G. Furthermore, in such a case, the distance function may be taken to be either left-invariant or right- invariant. ([2], [6])

Let us remark that the space X, respectively the group G can be viewed as r-fibres (as well asd-fibres) of a groupoid (X×X in the first case andGitself in the second case).

We prove in this paper that the previous two results can be express in an unified way in the groupoid language:

1.3. Theorem.Let G be a topological groupoid. Then there are left (respectively, right) invariant metrics compatible with the topology onr-fibres (respectively, thed-fibres) of the groupoid if and only if there is a countable G-uniformity {Wn}n∈

N compatible with the topology of the r-fibres (respectively, d-fibres) such that T

n∈N

Wn=G(0). (Proposition 3.14 and Proposition 3.15)

The proof of this theorem is based on the construction of a function on G satisfying the hypothesis of [8, Theorem 3.26]. This function is obtained as a particular case of Urysohn Lemma for groupoids (Theorem2.5).

We also prove in this paper that:

1.4. Theorem. For a topological locally transitive groupoid G the following statements are equivalent:

(a) G is metrizable

(b) For every neighborhoodW ofG(0) there is a neighborhoodW0 ofG(0) such thatW0W0 ⊂ W andG(0) has a countable fundamental system{Wn}n∈

Nof neighborhoods such that T

n∈N

Wn =G(0) and T

n∈N

(r, d) (Wn) =diag G(0) . (c) There is a countable G-uniformity{Wn}n∈

N compatible with the topology of the fibres such that T

n∈N

Wn =G(0) and T

n∈N

(r, d) (Wn) =diag G(0)

. Each Wn may be taken to be a neighborhood of the unit space.

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Moreover the distance function ρ may be taken to satisfy the following properties:

1. ρ(x, y) =ρ(x−1, y−1) for all x, y ∈G.

2. ρ(x, r(x)) =ρ(x, d(x)) for all x∈G.

3. ρ(xy, r(x))≤ρ(x, r(x)) +ρ(y, r(y)) for all (x, y)∈G(2). 4. ρ(x, y)≤ρ(x−1y, d(x)) for all x, y ∈G such that r(x) = r(y).

5. ρ(d(x), d(y))≤2ρ(x, y) and ρ(r(x), r(y))≤2ρ(x, y) for all x,y ∈ G. (Theorem 3.16)

2. Urysohn’s lemma for groupoids

2.1. Definition.LetGbe a groupoid. By aG-uniformity we mean a collection{W}W∈W of subsets of G satisfying the following conditions:

1. G(0) ⊂W ⊂G for all W ∈ W.

2. If W1, W2 ∈ W, then there is W3 ⊂W1∩W2 such that W3 ∈ W.

3. For every W1 ∈ W there is W2 ∈ W such that W2W2 ⊂W1. 4. W =W−1for all W ∈ W.

2.2. Definition. Let G be a groupoid. Two G-uniformities W and W0 are said to be equivalent if for every W ∈ W there is W0 ∈ W0 such that W0 ⊂W and conversely, for every W0 ∈ W0 there is W ∈ W such that W ⊂W0.

LetWbe a family of subsets of a groupoidGsatisfying conditions 1−4 from Definition 2.1 and let

I = 1

2n, n ∈N

Let W0 ∈ W and W1 ∈ W be such that W1W1 ⊂ W0. Inductively we can construct an I-indexed family {Wi}i∈I. Suppose that for Wi ∈ W has already been built. Then according condition 3 in Definition 2.1, there is a Wi0 ∈ W such that Wi0Wi0 ⊂ Wi. Let Wi/2 = Wi0. Thus we obtain an I-indexed family {Wi}i∈I satisfying the following properties:

1. Wi ∈ W for all i∈I.

2. WiWi ⊂W2i for all i∈I, i≤ 12. 3. W1W1 ⊂W0.

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Hence Wi ⊂WiWi ⊂W2i for all i∈I, i≤ 12 and

...W1/2n ⊂W1/2nW1/2n ⊂W1/2n−1 ⊂W1/2n−1W1/2n−1 ⊂...W1/2 ⊂W1/2W1/2 ⊂W1 Let us note that:

1. If i, j ∈I, theni < j iff there is p∈N such that j = 2pi.

2. If i, j ∈I and i < j, then 2i≤j.

3. If i, j ∈I and i≤j, then Wi ⊂Wj.

4. If i1, i2, ..., ik ∈ I and ik ≤ik−1 < ik−2 < ... < i1 <1, then WikWik−1...Wi1 ⊂W2i1 and Wi1...Wik−1Wik ⊂W2i1. Indeed,

WikWik−1Wik−2...Wi1 ⊂ Wik−1Wik−1Wik−2...Wi1

⊂ W2ik−1Wik−2...Wi1

⊂ Wik−2Wik−2...Wi1

⊂ ...⊂W2i1

Similarly, Wi1...Wik−1Wik ⊂Wi1...Wik−1Wik−1 ⊂Wi1...Wik−2W2ik−1 ⊂...W2i1.

5. If i1, i2, ..., ik, j1, j2, ..., jm ∈ I, ik < ik−1 < ... < i1 ≤ 1,jm < jm−1 < ... < j1 ≤ 1 and ik+ik−1+...+i1 ≤jm+jm−1+...+j1, then

WikWik−1...Wi1 ⊂WjmWjm−1...Wj1.

Indeed, let us remark thatik+ik−1+...+i1 = 2nk1 +2nk−11 +...+2n11 is the conversion into decimal system of the following number in base 2: b0, b1b2...bnk where bi = 1 if i∈ {n1, n2, ..., nk} andbi = 0 otherwise. Thus ifik+ik−1+...+i1 =jm+jm−1+...+j1, thenm =k and ik =jk, ..., i1 =j1. Ifik+ik−1+...+i1 < jm+jm−1+...+j1, then there isp∈N such that i1 =j1, ..., ip−1 =jp−1 and ip < jp. Hence

WikWik−1...WipWip−1... Wi1 ⊂ W2ipWip−1... Wi1

⊂ WjpWip−1... Wi1

= WjpWjp−1... Wj1

⊂ WjmWjm−1...Wj1.

2.3. Lemma.Let G be a groupoid, W be a G-uniformity (in the sense of Definition 2.1) and let

I = 1

2n, n∈N

.

Let us consider an I-indexed family {Wi}i∈I satisfying the following properties:

1. Wi ∈ W for all i∈I.

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2. WiWi ⊂W2i for all i∈I, i≤ 12.

For Wik, Wik−1, ..., Wi1 ∈ {Wi}i∈I, let us denote s WikWik−1...Wi1

=ik+ik−1+...+i1.

Let n ∈N, and i1, i2, ..., ik ∈I be such that ik < ik−1 < ik−2 < ... < i1 <1. Then there are j1, j2, ..., jr ∈I such that

1. jr < jr−1 < ir−2 < ... < j1 ≤max 1

2n−1,2i1 ≤1 2. W1/2nWikWik−1...Wi1 ⊂WjrWjr−1...Wj

1

3. 0< s WjrWjr−1...Wj1

−s WikWik−1...Wi1

2n−11

Moreover j1 < s WikWik−1...Wi1

+ 2n−11 and if jr 6= 21n, then jr2n−11 . Also if

1

2n ≤ik, then s WjrWjr−1...Wj

1

−s WikWik−1...Wi1

21n.

Proof. Case 1: 21n < ik. Obviously, 21n < ik < ik−1 < ik−2 < ... < i1 < 1 and s W1/2nWikWik−1...Wi1

=s WikWik−1...Wi1 + 21n.

Case 2: There is m ∈ {2,3, ..., k} such thatim = 21n < im−12 . Then W1/2nWikWik−1...WimWim−1...Wi1 ⊂W1/2nW2imWim−1...Wi1. and we have

s W1/2nW2imWim−1...Wi1

=

= s Wik...WimWim−1...Wi1

−(ik+...+im) + 2im+ 1 2n

≤ s Wik...WimWim−1...Wi1

+im+ 1 2n

= s Wik...WimWim−1...Wi1 + 2

2n. Moreover ik +...+im2k−m1 +2k−m1 +...12 + 1

im < 2im < 2im + 21n. Consequently, s W1/2nW2imWim−1...Wi1

> s Wik...WimWim−1...Wi1 .

Case 3: There is m ∈ {2,3, ..., k} such that im = 21n = im−12 and there is q ∈ {2,3, ..., m−1} such that 4iq ≤iq−1. Let p be the greatest element of the set

{q: 2 ≤q≤m−1, 4iq ≤iq−1}.

Then W1/2nWik...Wi1 ⊂ W1/2nW2imWim−1...Wi1 ⊂ W1/2nW2ipWip−1...Wi1. Moreover s W2ipWip−1...Wi1

=s Wim−1...WipWip−1...Wi1

−(im−1 +..+ip) + 2ip

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= s Wim−1...WipWip−1...Wi1

−(im−1+ 2im−1+...+ 2m−p−1im−1) + 2m−pim−1

= s Wim−1...WipWip−1...Wi1

−im−1 2m−p−1

+im−12m−p

= s Wik...WipWip−1...Wi1

−(ik+...+im) +im−1, and since 2n−11 =im−1, it follows that

s W1/2nW2ipWip−1...Wi1

=s W2ipWip−1...Wi1 + 1

2n

= s WikWik−1...Wi1

−(ik+...+im) +im−1+ 1 2n

= s WikWik−1...Wi1

−(ik+...+im+1)− 1

2n + 1 2n−1 + 1

2n

= s WikWik−1...Wi1

−(ik+...+im+1) + 1 2n−1. On the other hand, ik +... +im2k−m+11 + 2k−m1 +...12

im−1 < im−1 and therefore s W1/2nW2ipWip−1...Wi1

> s WikWik−1...Wi1 .

Case 4: There is m∈ {2,3, ..., k}such that im = 21n = im−12 = im−222 =...= 2m−1i1 . Then W1/2nWik...Wi1 ⊂ W1/2nW2imWim−1...Wi1 ⊂ W1/2nW2i1 and

s W1/2nW2i1

= s(Wim...Wi1)−(im+..+i1) + 2i1+ 1 2n

= s(Wim...Wi1)−(im+ 2im+...+ 2m−1im) + 2mim+ 1 2n

= s(Wim...Wi1)−im(2m−1) +im2m+ 1 2n

= s Wik...Wim+1Wim...Wi1

−(ik+...+im−1) +im+ 1 2n

< s WikWik−1...Wi1

+ 1

2n−1. Also s W1/2nW2i1

= 21n + 2i1 >2i1 > s WikWik−1...Wi1 and j1 = 2i1 < s WikWik−1...Wi1

+ 1

2n−1. Case 5: There is m ∈ {2,3, ..., k} such thatim < 21n < im−12 . Then

W1/2nWikWik−1...WimWim−1...Wi1 ⊂ W1/2nW2imWim−1...Wi1

⊂ W1/2nW1/2nWim−1...Wi1

⊂ W1/2n−1Wim−1...Wi1. and

s W1/2n−1Wim−1...Wi1

= s Wik...WimWim−1...Wi1

−(ik+...+im) + 1 2n−1

< s WikWik−1...Wi1

+ 1

2n−1.

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Moreover ik+...+im2k−m1 + 2k−m1 +...12 + 1

im < 2im21n < 2n−11 . Consequently, s W1/2n−1Wim−1...Wi1

> s Wik...WimWim−1...Wi1

.

Case 6: There is m ∈ {2,3, ..., k} such that im < 21n = im−12 and there is q ∈ {2,3, ..., m−1} such that 4iq ≤iq−1. If p is the greatest element of the set

{q: 2 ≤q≤m−1, 4iq ≤iq−1}, then

W1/2nWikWik−1...WimWim−1...Wi1 ⊂ W1/2nW2imWim−1...Wi1

⊂ W1/2nW1/2nWim−1...Wi1

⊂ W1/2n−1Wim−1...Wi1

⊂ W2ipWip−1...Wi1. Moreover

s W2ipWip−1...Wi1

=s Wim−1...WipWip−1...Wi1

−(im−1 +..+ip) + 2ip

= s Wim−1...WipWip−1...Wi1

−(im−1+ 2im−1+...+ 2m−p−1im−1) + 2m−pim−1

= s Wim−1...WipWip−1...Wi1

−im−1 2m−p−1

+im−12m−p

= s Wik...WimWim−1...Wi1

−(ik+...+im) +im−1

= s WikWik−1...Wi1

−(ik+...+im) + 1 2n−1. Hence

s W2ipWip−1...Wi1

< s WikWik−1...Wi1

+ 1

2n−1. Since we have ik+...+im2k−m+11 +2k−m1 +...12

im−1 < im−1, it follows that im−1− (ik+...+im) > 0. Thus s W2ipWip−1...Wi1

> s Wik...WimWim−1...Wi1

. We also have yr= 2ip2n−11 .

Case 7: There is m∈ {2,3, ..., k}such that im < 21n = im−12 = im−222 =...= 2m−1i1 . Then W1/2nWik...Wi1 ⊂W1/2nW2imWim−1...Wi1 ⊂W1/2n−1Wim−1...Wi1W1/2nW2i1 ⊂...W2i1 and

s(W2i1) = s Wim−1...Wi1

−(im−1+..+i1) + 2i1

= s Wim−1...Wi1

−(im−1+ 2im−1+...+ 2m−2im−1) + 2m−1im−1

= s Wim−1...Wi1

−im−1 2m−1−1

+im−12m−1+ 1 2n

= s Wik...WimWim−1...Wi1

−(ik+...+im) +im−1

< s WikWik−1...Wi1

+ 1

2n−1.

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Also s(W2i1) = 2i1 > 2k−11 +...+ 12 + 1

i1 ≥ ik +ik−1 +...i1 ≥ s WikWik−1...Wi1 . Moreover j1 = 2i1 =s(W2i1)< s WikWik−1...Wi1

+2n−11 . Case 8: 21n =i1. We have

W1/2nWikWik−1...Wi1 ⊂W1/2nW2i1,

s W1/2nW2i1

= 1

2n + 2i1 ≤s WikWik−1...Wi1 + 1

2n +i1

= s WikWik−1...Wi1

+ 1

2n−1. and 21n + 2i1 > 2i1 > 2k−11 +...+12 + 1

i1 ≥ ik+ik−1+...i1 = s WikWik−1...Wi1 . We also have j1 = 2i1 < s W1/2nW2i1

≤s WikWik−1...Wi1

+ 2n−11 . Case 9: 21n > i1. We have

W1/2nWikWik−1...Wi1 ⊂W1/2nW2i1 ⊂W1/2nW1/2n ⊂W1/2n−1, s W1/2n−1

= 1

2n−1 < s WikWik−1...Wi1

+ 1

2n−1 and 2n−11 >2i1 > 2k−11 +...+12 + 1

i1 ≥ik+ik−1+...i1 =s WikWik−1...Wi1

. Moreover j1 = 2n−11 < s WikWik−1...Wi1

+2n−11 .

Let us also remark that if 21n = ik , then W1/2nWikWik−1...Wi1 ⊂ W2imWim−1...Wi1, where m is the greatest element of the set {q: 2 ≤q≤k, 4iq ≤iq−1} if the set is not empty or m= 1, otherwise. We have

s W2imWim−1...Wi1

= s Wik...WimWim−1...Wi1

−(ik+...+im) + 2im

= s WikWik−1...Wi1

− 1 + 2 +...+ 2k−m 1

2n +2k−m+1 2n

= s WikWik−1...Wi1 + 1

2n. Moreover ik+...+im2k−m1 +2k−m1 +...12 + 1

im <2im. Consequently, s W2imWim−1...Wi1

> s Wik...WimWim−1...Wi1 .

2.4. Remark. In the preceding lemma since W1/2nWikWik−1...Wi1 ⊂ WjrWjr−1...Wj1, it follows that W1/2nWikWik−1...Wi1−1

⊂ WjrWjr−1...Wj

1

−1

and consequently, Wi1Wi2...WikW1/2n ⊂Wj1Wj2...Wjr.

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2.5. Theorem.LetGbe a groupoid,W be aG-uniformity (in the sense of Definition2.1) and letW ∈ W. Let us consider anI = 1

2n, n∈N -indexed subfamilyWI ={Wi}i∈I of W as in Lemma2.3 such that W1 ⊂W. Then for every subsetA of Gthere is a function f =fA,WI :G→[0, 1] satisfying the following conditions:

1. If n ∈N, n ≥2, x∈G and y∈W1/2nxW1/2n, then |f(x)−f(y)|< 2n−21 . 2. f(x) = 0 for all x∈A.

3. f(x) = 1 for all x /∈W AW.

4. If A=A−1, then f(x) = f(x−1) for all x∈G.

5. If G is endowed with a topology such that WikWik−1...Wi1A Wi1...Wik−1Wik is open for all i1, i2, ..., ik ∈I, ik < ik−1 < ... < i1 <1, then f is upper semi-continuous.

6. For all n∈N, n≥2, we have W1/2n+1AW1/2n+1

x:f(x)< 1 2n

⊂W1/2n−1AW1/2n−1.

In particular, if A =G(0), then W1/2n+1W1/2n+1

x:f(x)< 1 2n

⊂W1/2n−1W1/2n−1 ⊂W1/2n−2

for all n∈N, n≥2.

7. If A=G(0), then f(xy)≤3f(x) +f(y) for all (x, y)∈G(2). 8. If A=G(0), then f(xy)≤2 (f(x) +f(y)) for all (x, y)∈G(2).

9. If A=G(0), then f(x1x2...xn)≤3 (f(x1) +f(x2) +...+f(xn)) for all n ∈N and x1, x2, ..., xn ∈G such that d(xi) =r(xi+1) for all i∈ {1,2, ..., n−1}.

10. If A = G(0) and for every x ∈ G\ G(0) there is ix ∈ I such that x /∈ Wix (or equivalently, T

n

W1/2n =G(0)), then f−1({0}) = G(0). Proof.For each x∈G, let us define

i(x) = inf

ik+ik−1+...+i1 : i1, i2, ..., ik ∈I, ik< ik−1 < ... < i1, x∈WikWik−1...Wi1A Wi1...Wik−1Wik

(with convention inf∅=∞) and

f(x) = min{i(x),1}.

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1. Letx ∈Gand y∈W1/2nxW1/2n. If i(x)≥ 1 and i(y)≥1, thenf(x) =f(y) = 1.

Let us suppose that i(x)<1 or i(y)<1.

Case 1: i(x) < 1. Then there are i1, i2, ..., ik ∈ I, ik < ik−1 < ... < i1 < 1 such that x ∈ WikWik−1...Wi1A Wi1...Wik−1Wik and ik+ik−1 +...+i1 < i(x) + 21n. By Lemma 2.3, there are j1, j2, ..., jr ∈ I, jr < jr−1 < ir−2 < ... < j1 ≤ 1 such that W1/2nWikWik−1...Wi1 ⊂WjrWjr−1...Wj

1 and

0<(jr+...+j1)−(ik+ik−1+...+i1)< 3 2n Hence

ik+ik−1+...+i1 ≤jr+...+j1 < i(x) + 1 2n−2 and since

y ∈ W1/2nxW1/2n

⊂ W1/2nWikWik−1...Wi1AWi1...Wik−1WikW1/2n

⊂ WjrWjr−1...Wj

1AWj1Wj2...Wjr

it follows that i(y)< i(x) +2n−21 . If i(y)<1, then sincey∈W1/2nxW1/2n is equivalently to x ∈ W1/2nyW1/2n it follows that i(x) < i(y) + 2n−21 . Therefore |f(x)−f(y)| =

|i(x)−i(y)| < 2n−21 . If i(y) ≥ 1, then |f(x)−f(y)| =|i(x)−1| = 1−i(x) ≤ i(y)− i(x)< 2n−21 .

Case 2: i(y)<1. Since y∈W1/2nxW1/2n is equivalently tox∈W1/2nyW1/2n, the case i(y)<1 can be treated similarly as the case i(x)<1.

2. Let us prove that f(x) = 0 for all x ∈ A. Since A ⊂ W1/2nAW1/2n for all n, it follows that i(x) = 0, and consequently, f(x) = 0 for all x∈A.

3.Let us prove thatf(x) = 1 for allx /∈W AW. Letx /∈W AW. By contradiction, let us supposef(x)<1. We necessarily havei(x)<1,and hence there arei1, i2, ..., ik∈I, ik < ik−1 < ... < i1 <1 such that

x ∈ WikWik−1...Wi1A Wi1...Wik−1Wik ⊂W2i1AW2i1

⊂ W1AW1 ⊂W AW

This is in contradiction to the hypothesis x /∈W AW. 4. Since A=A−1, it follows that

WikWik−1...Wi1A Wi1...Wik−1Wik−1

=WikWik−1...Wi1A Wi1...Wik−1Wik. Thusx∈WikWik−1...Wi1A Wi1...Wik−1Wik if and only if

x−1 ∈WikWik−1...Wi1A Wi1...Wik−1Wik. Therefore f(x) =f(x−1) for all x∈G.

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5. Letα ∈Rand let us consider the set

Uα ={x∈G:f(x)< α}.

If α > 1, then Uα = G, hence Uα is an open set. Let us consider α ≤ 1 and let x ∈ Uα. Then f(x) < 1. Thus i(x) < 1, and hence there are i1, i2, ..., ik ∈ I, ik < ik−1 < ... < i1 <1 such that

x∈WikWik−1...Wi1A Wi1...Wik−1Wik

ik+ik−1+...+i1 < α.

For all y∈WikWik−1...Wi1A Wi1...Wik−1Wik we have i(y)< α. Consequently, x∈WikWik−1...Wi1A Wi1...Wik−1Wik ⊂Uα.

Therefore Uα is open.

6. Ifx∈W1/2n+1AW1/2n+1, then i(x)≤ 2n+11 . Thus f(x)≤ 2n+11 < 21n. If f(x)< 21n <

1, then i(x) < 21n and there are i1, i2, ..., ik ∈ I, ik < ik−1 < ... < i1 < 1 such that x ∈ WikWik−1...Wi1A Wi1...Wik−1Wik and ik+ik−1 +...+i1 < i(x) + 21n < 2n−11 . Hence i1 < 2n−11 and therefore x∈W2i1AW2i1 ⊂W1/2n−1AW1/2n−1.

7. Let (x, y) ∈ G(2). If 3f(x) + f(y) ≥ 1, then obviously, f(xy) ≤ 3f(x) +f(y).

Let us suppose that 3f(x) +f(y) < 1 or equivalently, 3i(x) +i(y) < 1 (consequently, i(x) < 13 and i(y) < 1). Let ε > 0 such that ε < 1−3i(x)−i(y). Then there are i1, i2, ..., ik ∈ I, ik < ik−1 < ... < i114 such that x ∈ WikWik−1...Wi1Wi1...Wik−1Wik, ik+ik−1 +...+i1 < i(x) + ε3 and there are j1, j2, ..., jm ∈ I, jm < jm−1 < ... < j112 such that y ∈ WjmWjm−1...Wj1Wj1...Wjm−1Wjm, jm +jm−1 + ...+j1 < i(y) + ε3. By Lemma 2.3, there are q11, q21, ..., qr11 ∈ I, qr11 < qr11−1 < q1r1−2 < ... < q11 ≤ 1 such that WikWjmWim−1...Wj1 ⊂Wqr1

1Wq1

r1−1...Wq1

1, 0< q1r

1 +...+q11

−(jm+jm−1+...+j1)≤2ik.

andq11 ≤jm+jm−1+...+j1+2ik < i(y)+ε3+2i(x)+3 <1. Repeatedly applying Lemma 2.3, for p= 2,3, ..., k there areq1p, qp2, ..., qrpp ∈I, qrp

p < qpr

p−1 < qrp

p−2 < ... < q1p ≤ 1 such that Wik−p+1Wqp=1

rp=1Wqp−1

rp−1−1...Wqp−1

1 ⊂WqprpWqp

rp−1...Wqp

1 , 0≤

qrpp+...+q1p

qrp−1p−1 +...+qp−11

≤2ik−p+1. and

q1p−1 < qp−1rp−1 +...+q1p−1+ 2ik−p+1

< qp−2rp−2 +...+q1p−2+ 2ik−p+ 2ik−p+1

...

< jm+jm−1+...+j1 + 2ik+...+ 2ik−p+ 2ik−p+1

< i(y) + ε

3 + 2i(x) + 2ε 3 <1.

参照

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