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1 cos tan sin θ

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(1)

次の問いに答えよ。

(1) 次の等式を証明せよ。

(ⅰ)

sin 1 1

1 cos tan sin θ

θ + θ = θ +

(ⅱ)

(1 sin + θ + cos ) θ

2

+ + (1 sin θ − cos ) θ

2

4(1 sin ) θ

= +

(ⅲ)

2 2

cos sin 1 tan

1 2 sin cos 1 tan

θ θ θ

θ θ θ

− = −

+ +

(2) 次の値を求めよ。

(ⅰ)

4

cos θ = − 5

のとき,

sin θ

tan θ

の値

(ⅱ)

tan θ = 2

のとき,

1 1

1 sin + θ + 1 sin − θ

の値

(ⅲ)

1

sin cos

θ + θ = 2

のとき,

1

tan θ tan

+ θ

の値 78.三角関数の相互関係

参照

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