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Boundary Value Problems

Volume 2008, Article ID 197205,21pages doi:10.1155/2008/197205

Research Article

Multiplicity Results via Topological

Degree for Impulsive Boundary Value Problems under Non-Well-Ordered Upper and Lower

Solution Conditions

Xu Xian,1 Donal O’Regan,2 and R. P. Agarwal3

1Department of Mathematics, Xuzhou Normal University, Xuzhou, Jiangsu 221116, China

2Department of Mathematics, National University of Ireland, Galway, Ireland

3Department of Mathematical Science, Florida Institute of Technology, Melbourne, FL 32901, USA

Correspondence should be addressed to R. P. Agarwal,agarwal@fit.edu Received 14 April 2008; Accepted 26 August 2008

Recommended by R. P. Gilbert

Some multiplicity results for solutions of an impulsive boundary value problem are obtained under the condition of non-well-ordered upper and lower solutions. The main ideas of this paper are to associate a Leray-Schauder degree with the lower or upper solution.

Copyrightq2008 Xu Xian et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

1. Introduction

In this paper, we study multiplicity of solutions of the impulsive boundary value problem yf

t, yt, yt

0, t /tk, Δy|ttk Ik

y tk

, k1,2, . . . , m, Δy|ttk Ik

y tk

, k1,2, . . . , m,

y0 0y1αyη,

1.1

wherefCJ ×R2,R,J 0,1,Ik, IkCR,R,k 1,2, . . . , m,Δy|ttk ytkytk, Δy|ttk ytkytk, 0t0< t1 <· · ·< tm< tm11,α∈0,1.

Impulsive differential equations arise naturally in a wide variety of applications, such as spacecraft control, inspection processes in operations research, drug administration, and threshold theory in biology. In the past twenty years, a significant development in the

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theory of impulsive differential equations was seen. Many authors have studied impulsive differential equations using a variety of methodssee1–5and the references therein.

The purpose of this paper is to study the multiplicity of solutions of the impulsive boundary value problems 1.1 by the method of upper and lower solutions. The method of lower and upper solutions has a very long history. Some of the ideas can be traced back to Picard6. This method deals mainly with existence results for various boundary value problems. For an overview of this method for ordinary differential equations, the reader is referred to7. Usually, when one uses the method of upper and lower solutions to study the existence and multiplicity of solutions of impulsive differential equations, one assumes that the upper solution is larger than the lower solution, that is, the condition that upper and lower solutions are well ordered. For example, Guo1studied the PBVP for second-order integrodifferential equations of mixed type in real Banach spaceE:

−uft, u, Tu, Su ∀t∈0,2π, t /ti, Δu|tti Liu

ti

, Δu|tti Liu

ti

, i1,2, . . . , m,

u0 u2π, u0 u2π,

1.2

wherefC0,2π×E×E×E, E,TandS:EEare two linear operators, 0< t1< t2<· · ·<

tm<1,Li, Li i1,2, . . . , mare constants. In1Guo first obtained a comparison result, and then, by establishing two increasing and decreasing sequences, he proved an existence result for maximal and minimal solutions of the PBVP1.2in the ordered interval defined by the lower and upper solutions.

However, to the best of our knowledge, only in the last few years, it was shown that existence and multiplicity for impulsive differential equation under the condition that the upper solution is not larger than the lower solution, that is, the condition of non-well-ordered upper and lower solutions. In8, Rach ˚unkov´a and Tvrd ´y studied the existence of solutions of the nonlinear impulsive periodic boundary value problem

uf t, u, u

, t /ti

u ti

J u

ti

, i1,2, . . . , m, u

ti Mi

u ti

, i1,2, . . . , m,

u0 uT, u0 uT,

1.3

where fC0, T× R2, Ji,MiCR. Using Leray-Schauder degree, the authors of 8 showed some existence results for 1.3 under the non-well-ordered upper and lower solutions condition. For other results related to non-well-ordered upper and lower solutions, the reader is referred to7,9–14. Also, here we mention the main results of a very recent paper15. In that paper, we studied the second-order three-point boundary value problem

yt ft, y 0, 0≤t≤1,

y0 0, y1αyη 0, 1.4

where 0< η <1, 0< α <1,fC0,1×R,R. In15, we made the following assumption.

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x6

x3

u2

u1

x4

x1

v2

v1

x5

x2

Figure 1: The positions ofu1, u2, v1, v2and six solutionsx1, x2, . . . , x6inTheorem 1.1.

A0There existsM >0 such that

f t, x2

f t, x1

≥ −M

x2x1

, t∈0,1, x2x1. 1.5

Let the functionebeeet tfort∈0,1. In15, we proved the following theorem see,15, Theorem 3.4.

Theorem 1.1. Suppose thatA0holds,u1andu2are two strict lower solutions of 1.4,v1andv2

are two strict upper solutions of 1.4, andu1< v1,u2< v2,u2/v1,u1/v2. Moreover, assume

−ς0eu2u1ς0e, −ς0ev2v1ς0e 1.6

for some ς0 > 0. Then the three-point boundary value problem 1.4 has at least six solutions x1, x2, . . . , x6.

Theorem 1.1 establishes the existence of at least six solutions of the three-point boundary value problem1.4only under the condition of two pairs of strict lower and upper solutions. The positions ofu1, u2, v1, v2and six solutionsx1, x2, . . . , x6inTheorem 1.1can be illustrated roughly byFigure 1.

In some sense, we can say that these two pairs of lower and upper solutions are parallel to each other. The position of these two pairs of lower and upper solutions is sharply different from that of the lower and upper solutions of the main results in14,16,17. The technique to prove our main results of15is to use the fixed-point index of some increasing operator with respect to some closed convex sets, which are translations of some special conesseeQc, Qcof15.

This paper is a continuation of the paper15. The aim of this paper is to study the multiplicity of solutions of the impulsive boundary value problem1.1under the conditions of non-well-ordered upper and lower solutions. In this paper, we will permit the presence of impulses and the first derivative. The main ideas of this paper are to associate a Leray- Schauder degree with the lower or upper solution. We will give some multiplicity results for at least eight solutions. To obtain this multiplicity result, an additional pair of lower and upper solutions is needed, that is, we will employ a condition of three pairs of lower and upper solutions. The position of these three pairs of lower and upper solutions will be illustrated inRemark 2.16.

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2. Results for at least eight solutions

LetJJ\{t1, t2, . . . , tm}, PCJ,R {x|xis a map fromJ intoRsuch thatxtis continuous att /tk, left continuous at ttkand its right-hand limit xtkatttkexits}, and PC1J,R {x|xis a map fromJ intoRsuch thatxtandxtare continuous att /tk, left continuous atttkand their right-hand limitsxtkandxtkatttkexits}. For eachx∈PC1J,R, let

xPC1max

xPC,x

PC

, 2.1

wherexPC supt∈J|xt|andxPC supt∈J|xt|. Then, PC1J,Ris a real Banach space with the norm·PC1. The functionx∈PC1J,R∩C2J,Ris called a solution of the boundary value problem1.1if it satisfies all the equalities of1.1.

Now, for convenience, we make the following assumptions.

H00t0< t1<· · ·< tm< η < tm11, α∈0,1.

H1Ik k1,2, . . . , mis increasing onR.

Letx, y∈PCJ,R. Now, we define the ordering≺by

xy iffxt< yt∀t∈J, xtk< ytk for eachk1,2, . . . , m. 2.2

Definition 2.1. The functionu∈PC1J,R∩C2J,Ris called a strict lower solution of1.1if ut f

t, ut, ut

>0, t /tk,

u0<0, u1αuη<0, 2.3

wheneverIi0x/0 orIj0x/0 for somei0, j0∈ {1,2, . . . , m}and somex∈R Δu|ttk Ik

u tk

, k1,2, . . . , m, Δu|ttk > Ik

u tk

, k1,2, . . . , m,

2.4

wheneverIkx Ikx 0 for eachx∈Randk∈ {1,2, . . . , m},Δu|ttk Δu|ttk 0 for each k∈ {1,2, . . . , m}.

The functionv∈PC1J,R∩C2J, Ris called a strict upper solution of1.1if vt f

t, vt, vt

<0, t /tk,

v0>0, v1αvη>0, 2.5

wheneverIi0x/0 orIj0x/0 for somei0, j0∈ {1,2, . . . , m}and somex∈R Δv|ttk Ik

v tk

, k1,2, . . . , m, Δv|ttk < Ik

v tk

, k1,2, . . . , m, 2.6

and wheneverIkx Ikx 0 for eachx∈Randk∈ {1,2, . . . , m},Δv|ttk Δv|ttk 0 for eachk∈ {1,2, . . . , m}.

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Definition 2.2. Letut, vt ∈ PC1J,R∩C2J,R,utvtfor alltJ. We say thatf satisfies Nagumo condition with respect tou, vif there exists functionφC0,∞,0,∞ such that

ft, x, yφ

|y|

, ∀t, x, y∈J×

ut, vt ×R,

0

s

φsds∞. 2.7

Definition 2.3. Let r1t, r2t· · ·rnt be strict upper solutions of 1.1 and rt min{r1t, r2t, . . . rnt}for eachtJ. Then, we say the upper solutionsr1t, r2t, . . . rnt are well ordered if for eachk∈ {1,2, . . . , m}, there existi0, j0 ∈ {1,2, . . . , n}andδ0 >0 small enough such that

rt

⎧⎨

ri0t, t

tkδ0, tk , rj0t, t∈

tk, tkδ0 .

2.8

Definition 2.4. Let l1t, l2t, . . . lnt be strict lower solutions of 1.1 and lt max{l1t, l2t, . . . lnt} for eachtJ. Then, we say the lower solutionsl1t, l2t, . . . lnt are well ordered if for eachk∈ {1,2, . . . , m}, there existi0, j0 ∈ {1,2, . . . , n}andδ0 >0 small enough such that

lt

⎧⎨

li0t, t

tkδ0, tk , lj0t, t∈

tk, tkδ0 .

2.9

From18, Lemma 5.4.1, we have the following lemma.

Lemma 2.5. H⊂PC1J,Ris a relative compact set if and only if for allxH,xtandxtare uniformly bounded onJ and equicontinuous on eachJk k 1,2, . . . , m, whereJ1 0, t1, Ji ti−1, ti, i2,3, . . . , m1.

The following lemma can be easily proved.

Lemma 2.6. Suppose thatx∈PC1J,R∩C2J,Rsatisfies

−xt f

t, xt, xt

, t /tk k1,2, . . . , m. 2.10 Then

xt x0− t

0

f

s, xs, xs

ds

0<tk<t

x tk

x

tk ∀t∈J,

xt x0 x0t− t

0

t−sf

s, xs, xs

ds

0<tk<t

x tk

x tk

0<tk<t

x tk

x

tk ttk

∀t∈J.

2.11

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Lemma 2.7. Letg ∈PCJ,Randak, bk∈Rk0,1,2, . . . , m. Then,x∈PC1J,R∩C2J,R is a solution of

−xt gt, t /tk, k1,2, . . . , m, Δx|ttk ak, k1,2, . . . , m, Δx|ttk bk, k1,2, . . . , m,

x0 a0, x1αxη b0

2.12

if and only ifx∈PCJ,Rsatisfies

xt a0

1− 1−α 1−αηt

b0t

1−αη t 1−αη

1

0

1−sgsds− αt 1−αη

η

0

η−sgsds

t 1−αη

m k1

1−αak

1−tkα

ηtk bk

t

0

t−sgsds

0<tk<t

akbk

ttk , tJ.

2.13

Proof. Letx∈PC1J,R∩C2J,Rbe a solution of2.12. FromLemma 2.6, we have

xt x0 x0t− t

0

t−sgsds

0<tk<t

Δx|ttk

0<tk<t

Δx|ttk

ttk

a0x0t− t

0

t−sgsds

0<tk<t

ak

0<tk<t

bk

ttk

.

2.14

Thus,

x1 a0x0− 1

0

1−sgsdsm

k1

akm

k1

bk

1−tk

,

xη a0x0η− η

0

η−sgsdsm

k1

akm

k1

bk

ηtk

.

2.15

Using the boundary value conditionx1αxη b0, we have

x0 1

1−αηb0− 1−α

1−αηa0 1 1−αη

1

0

1−sgsdsα

1−αη η

0

η−sgsds

− 1−α 1−αη

m k1

ak− 1 1−αη

m k1

bk 1−tk

α 1−αη

m k1

bk ηtk

.

2.16

The equality2.13now follows from2.14and2.16.

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On the other hand, ifx∈PCJ,Rsatisfies2.13, by direct computation, we can easily show thatxsatisfies2.12. The proof is complete.

Let us define the operatorA: PC1J,R→PC1J,Rby

Axt t 1−αη

1

0

1−sf

s, xs, xs

dsαt 1−αη

η

0

η−sf

s, xs, xs ds

t

0

t−sf

s, xs, xs

ds

0<tk<t

Ik x

tk Ik

x tk

ttk

t 1−αη

m k1

1−αIk

x tk

1−tkα

ηtk Ik x

tk .

2.17

FromLemma 2.5,A: PC1J,R→PC1J,Ris a completely continuous operator.

Theorem 2.8. Suppose thatH0andH1hold. Letαi, βi i1,2, . . . , nbenpairs of strict lower and upper solution, and

αt max

α1t, α2t, . . . , αnt

, tJ,

βt min

β1t, β2t, . . . , βnt

, tJ.

2.18

Suppose thatαiβi i1,2, . . . , n,αβ,fsatisfies Nagumo condition with respect toα1, β1. Moreover, the strict lower solutionsα1, α2, . . . , αnand the strict upper solutionsβ1, β2, . . . , βnare well ordered wheneverIi0x/0 orIj0x/0 for somei0, j0 ∈ {1,2, . . . , m}and somex∈R. Then, there existR0 >0 andL0 >0 sufficiently large such that for eachRR0andL > L0

degI−A,Ω, θ 1, 2.19

where

Ω

xBθ, R|αxβ,LxL ,

Bθ, R

x∈PC1J, R| xPC1 < R .

2.20

Proof. We only prove the case whenIi0x/0 orIj0x/0 for somei0, j0 ∈ {1,2, . . . , m}and somex∈R. The conclusion is achieved in four steps.

Step 1. Since f satisfies Nagumo condition with respect to α1, β1, then there exists φC0,∞,0,∞such that

ft, x, y≤φ

|y|

, t, x, y∈J×

αt, βt ×R,

0

s

φsds∞. 2.21

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Letμ0min1≤k≤m1tktk−1. Takeλ >0 such that

λ >max1≤i≤nsupt∈Jβit−min1≤i≤ninft∈Jαit

μ0 , 2.22

andN >0 such that

N

λ

s

φsds >2λ. 2.23

LetL0max{N,2λ,max1≤i≤nαiPC,max1≤i≤nβiPC}. Define the functionsg, h:J×R2 →R by

gt, x, y

⎧⎪

⎪⎪

⎪⎨

⎪⎪

⎪⎪

ft, x, L, y > L, ft, x, y, −L≤yL, ft, x,−L, y <−L,

ht, x, y

⎧⎪

⎪⎪

⎪⎨

⎪⎪

⎪⎪

g

t, βt, y

, x > βt, gt, x, y, αtxβt, g

t, αt, y

, x < αt.

2.24

For eachk∈ {1,2, . . . , m}, let us define the functionsJk, Jk:R→Rby

Jkx

⎧⎪

⎪⎪

⎪⎨

⎪⎪

⎪⎪

Ik

β tk

, x > β tk

,

Ikx, α

tk

xβ tk

,

Ik

α tk

, x < α tk

,

Jkx

⎧⎪

⎪⎪

⎪⎨

⎪⎪

⎪⎪

Ik

β tk

, x > β tk

,

Ikx, α

tk

xβ tk

, Ik

α tk

, x < α tk

.

2.25

It is easy to see that there existsM1 >0 such that

ht, x, yM1, t, x, y∈J×R2,

Jkx≤M1, Jkx≤M1, x∈R, k1,2, . . . , m. 2.26

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Let us define the operatorA: PC1J,R→PC1J,Rby Ax

t t 1−αη

1

0

1−sh

s, xs, xs

dsαt 1−αη

η

0

η−sh

s, xs, xs ds

t

0

t−sh

s, xs, xs

ds

0<tk<t

Jk x

tk

ttk Jk

x tk

t 1−αη

m k1

1−αJk

x tk

1−tk

α

ηtk Jk x

tk .

2.27

By2.26, we have Ax

t≤ 1 1−αη

1

0

1−sh

s, xs, xsds α 1−αη

η

0

η−sh

s, xs, xsds

1

0

1−sh

s, xs, xsdsm

k1

Jk x

tk

1−tkJk x

tk

2 1−αη

m k1

Jk x

tkJk x

tk

M1

1−αη 1

2 1 2αη2 1

22m4m

M1

1−αη36m, tJ, Ax

t≤ 1 1−αη

1

0

1−sh

s, xs, xsds α 1−αη

η

0

η−sh

s, xs, xsds

1

0

h

s, xs, xsdsm

k1

Jk x

tk 2

1−αη m k1

Jk

x

tkJk x

tk

M1 1−αη

1 2 1

2αη215m

M1

1−αη5m3, tJ.

2.28 From2.28, we haveAxPC1 ≤ M1/1αη11m6for eachx ∈ PC1J,R. LetR0 M1/1αη11m6 1. Then,APC1J,R⊂Bθ, R0. By the properties of the Leray- Schauder degree, we have

deg

IA, Bθ, R, θ

1. 2.29

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Thus,Ahas at least one fixed pointx0. FromLemma 2.7,x0satisfies

x0t h

t, x0t, x0t

0, t /tk, Δx0|ttk Jk

x0 tk

, k1,2, . . . , m Δx0

ttk Jk x0

tk

, k1,2, . . . , m, x00 0x01−αx0η,

2.30

Step 2. Next, we will show that

αx0β, 2.31

−L≺x0L. 2.32

We first show that

αtx0t≤βt ∀t∈J. 2.33

To begin, we show thatx0t≤βtfor alltJ. Suppose not, then there existstJsuch that x0t> βt. Setwt x0t−βtfortJ. There are a number of cases to consider.

1w0 supt∈Jwt>0, then, we have

0< w0 x00−β0 −β0<0, 2.34

which is a contradiction.

2w1 supt∈Jwt > 0; assume without loss of generality thatα > 0 andβ1 βi01for somei0 ∈ {1,2, . . . , n}, then, we have

0< w1 x01−βi01≤αx0η−αβi0η≤αx0η−αβη αwηαw1, 2.35

which is a contradiction.

3 There exist k0 ∈ {1,2, . . . , m, m 1} and τ0 ∈ tk0−1, tk0 such that 0

supt∈Jwt > 0. Assume without loss of generality that βτ0 βi0τ0 for some i0 ∈ {1,2, . . . , n}. We have the following two cases:

3Aβjτ0> βi0τ0for eachj∈ {1,2, . . . , n}andj /i0;

3Bthere existsj0∈ {1,2, . . . , n}, j0/i0such thatβj0τ0 βi0τ0.

For case3A, there existsδ0 >0 small enough such thatτ0δ0, τ0δ0⊂tk0−1, tk0 and

wt x0t−βi0t, t

τ0δ0, τ0δ0 . 2.36

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Then,wC2τ0δ0, τ0δ0,0is the maximum ofwonτ0δ0, τ0δ0. Thus,wτ0

0, wτ0≤0. By2.30, we have

0≥w τ0

x0 τ0

βi

0

τ0 −h

τ0, x0 τ0

, x0 τ0

βi

0

τ0

−f τ0, βi0

τ0 , βi

0

τ0

βi

0

τ0 ,

2.37

which is a contradiction.

For case3B, setw1t x0t−βj0tfort∈tk0−1, tk0. For anyt∈tk0−1, tk0, we have

w1 τ0

x0 τ0

βj0 τ0

x0 τ0

βi0 τ0

w τ0

w t

x0 t

β t

x0 t

βj0 t

w1 t

.

2.38

This implies that w1τ0 is a local maximum. Since w1C2tk0−1, tk0, then w1τ0 0, w1τ0≤0. Therefore,

0≥w1 τ0

x0 τ0

βj

0

τ0 −f

τ0, βj0 τ0

, βj

0

τ0

βj

0

τ0

>0, 2.39

which is a contradiction.

4There existsk0 ∈ {1,2, . . . , m}such thatwtk0 supt∈Jwt > 0. Without loss of generality, we may assumewτ<supt∈Jwtfor eachτ ∈tk−1, tkandk ∈ {1,2, . . . , m, m 1}.Otherwise, if there exists τ0 ∈ tk0−1, tk0 for somek0 ∈ {1,2, . . . , m, m1} such that 0 supt∈Jwt, then we can get a contradiction as in case3. In this case, we have the following two subcases:

4Athere existsi0∈ {1,2, . . . , n}such thatβi0tk0< βjtk0forj 1,2, . . . , nandj /i0; 4Bthere exists a subset{n1, n2, . . . , ns} ⊂ {1,2, . . . , n}such that

β tk0

βn1

tk0

βn2

tk0

· · ·βns

tk0

, 2.40

whileβltk0> βtk0for eachl∈ {1,2, . . . , n} \ {n1, n2, . . . , ns}, s≥2.

First, we consider case4A. SinceIk0is increasing onR, then

βi0 tk

0

βi0 tk0

Ik0 βi0

tk0

< βj tk0

Ik0 βj

tk0 βj

tk

0

, j /i0. 2.41

Then, there existsδ0 > 0 small enough such thatβt βi0tfort ∈ tk0δ0, tk0δ0and so wt x0t−βi0tfort ∈ tk0δ0, tk0 δ0. Sinceβi0tis a strict upper solution, we

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have

w tk0

x0

tk0

βi0

tk0

x0

tk0 Jk0

x0

tk0βi0

tk0 Ik0

βi0 tk0

x0 tk0

βi0

tk0 Jk0

x0 tk0

Ik0 βi0

tk0 w

tk0

Ik0 βi0

tk0

Ik0 βi0

tk0 w

tk0 .

2.42

Since < wtk0 for eachτ ∈ tk0−1, tk0, then we havewtk0 ≥ 0. Similarly, we have wtk0≤0. Therefore,

0≥w tk

0

x tk

0

βi

0

tk

0

>

x0 tk0

Jk0 x0

tk0βi0

tk0

Ik0

βi0

tk0

w tk0

Ik0

βi0 tk0

Ik0 βi0

tk0 w tk0

≥0,

2.43

which is contradiction.

Now we consider case4B. SinceIk0is increasing, then we have

β tk

0

βn1 tk

0

βn2 tk

0

· · ·βns tk

0

, 2.44

whileβltk

0 > βtk

0for eachl ∈ {1,2, . . . , n} \ {n1, n2, . . . , ns}. For case4B, we have two subcases:

4Bathere existsδ0 > 0 small enough andi0 ∈ {n1, n2, . . . , ns}such thatβi0t βt fort∈tk0δ0, tk0δ0;

4Bbthere existsδ0>0 small enough andi0/j0,i0, j0∈ {n1, n2, . . . , ns}such that

βt

⎧⎨

βi0t, t

tk0δ0, tk0 , βj0t, t∈

tk0, tk0δ0 .

2.45

For case4Baas in case4A, we can easily obtain a contradiction. For case4Bb, we have

wt

⎧⎨

x0t−βi0t, t

tk0δ0, tk0 , x0t−βj0t, t∈

tk0, tk0δ0 .

2.46

(13)

In the same way as in the proof of case4A, we see thatwtk0 wtk0,wtk0≥0 and we havewtk

0≤0. Note thatβj

0tk0βi

0tk0, and we have 0≥w

tk

0

x0 tk

0

βj

0

tk

0

x0 tk0

Δx0|ttk0βj0

tk0

Δβj0|ttk0

>

x0 tk0

βj0

tk0 Jk0

x0

tk0

Ik0

βj0

tk0

x0 tk0

βi0 tk0

Ik0

βj0

tk0

Ik0

βj0

tk0

w tk0

≥0,

2.47

which is a contradiction.

5There exists ak0 ∈ {1,2, . . . , m}such thatwtk

0 supt∈Jwt > 0. Without loss of generality, we may assume that < wtk

0for eachk ∈ {1,2, . . . , m, m1} andτ ∈ tk−1, tk. We have two subcases:

5Athere existsi0∈ {1,2, . . . , n}such thatβi0tk0< βjtk0for eachj /i0; 5Bthere exists a subset{n1, n2, . . . , ns} ⊂ {1,2, . . . , n}such that

β tk

0

βn1

tk

0

βn2

tk

0

· · ·βns

tk

0

, 2.48

whileβltk0> βtk0for eachl∈ {1,2, . . . , n} \ {n1, n2, . . . , ns}, s≥2.

SinceIk0is increasing, then for case5A, we have βi0

tk0

< βj

tk0 j /i0

, x0

tk0

> βi0

tk0

, 2.49

and for case5B, we havex0tk0> βi0tk0and β

tk0

βn1

tk0

βn2

tk0

· · ·βns

tk0

, 2.50

whileβltk0> βtk0for eachl∈ {1,2, . . . , n} \ {n1, n2, . . . , ns}. Therefore, we can use the same method as in case4to obtain a contradiction.

From the discussions of1–5, we see thatx0t ≤ βtfortJ. Similarly, we can prove thatαtx0tfortJ. Thus,2.33holds.

Next, we prove thatαx0β. If the inequalityx0βdoes not hold, then either there existsτ0Jsuch thatx0τ0 βτ0or there existsk0∈ {1,2, . . . , m}such thatx0tk

0

βtk0. Setwt x0t−βtfortJ. Then, we have eitherwτ0 supt∈Jwtorwtk0 supt∈Jwtfor some k0 ∈ {1,2, . . . , m}. Essentially the same reasoning as in 1–5above yields a contradiction. Thus,x0β. Similarly,αx0. Consequently,2.31holds.

Step 3. Now, we show2.32. Suppose not, then we have the following two subcases:

Ithere existss1Jsuch that|x0s1| ≥L;

IIthere existsk0∈ {1,2, . . . , m}such that|x0tk

0| ≥L.

(14)

We only consider case II. A similar argument works for caseI. We may assume without loss of generality that x0tk

0L. By the mean-value theorem, there exists s2 ∈ tk0, tk01such that

x0 s2

x0 tk01

x0 tk0

tk01tk0 ≤ max1≤i≤nsupt∈Jβit−min1≤i≤ninft∈Jαit

μ0 < λ < L. 2.51

LetL1be such thatL0< L1< L, then, there exists3, s4∈tk0, s2such thats3< s4,x0s3 L1, x0s4 λ, andλx0s≤L1fors∈s3, s4. Therefore,

x0sh

s, x0s, x0sf

s, x0s, x0s≤φ x0s

, s

s3, s4 . 2.52

Consequently, s4

s3

x0sx0s φ

x0s ds

s4

s3

x0sds s4

s3

x0sdsx0

s4

x0

s3

< λ. 2.53

On the other hand, s4

s3

x0sx0s φ

x0s ds

L1

λ

s φsds

N

λ

s

φsds > λ, 2.54

which is a contradiction. Thus,2.32holds.

Step 4. From the excision property of Leray-Schauder degree and2.29, we have

deg

IA,Ω, θ

deg

IA, Bθ, R, θ

1. 2.55

From2.31and2.32, we see thatAxAxfor eachx∈Ω, and so

degI−A,Ω, θ 1. 2.56 The proof is complete.

Remark 2.9. From the proof of Theorem 2.8, we see thatAhas no fixed point on∂Ω.

Theorem 2.10. Suppose thatH0,H1hold,u1t, u2tare strict lower solutions,v1t, v0tare strict upper solutions,u1v1v0,u2v0,u2t> v1tfor sometJ, andfsatisfies Nagumo condition with respect tou1, v0. Moreover, the strict lower solutionsu1t, u2tare well ordered wheneverIi0x/0 orIj0x/0 for somei0, j0 ∈ {1,2, . . . , m}and somex∈ R. Then,1.1has at least three solutionsx1, x2, andx3, such that

u1x1v1, u1x2v0, u2x2v0, u1x3v0, 2.57 andv1s1< x3s1, x3s2< u2s2for somes1, s2J.

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