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(1)

A Nonstandard Counterpart of DNR

Kojiro Higuchi

joint work with

Keita Yokoyama ,

Tokyo Institute of Technology

(2)

Diagonally Non-Recursive function

Kleene’s recursion theorem (1938)

For any recursive function f, we can find e such that {e}={f(e)}. Arslanov’s completeness criterion (1981)

For any r.e. set A,

A is complete ⇐⇒ (∃g≤T A)(∀e)[{e}6={g(e)}]. In fact, ⇐⇒ (∃h≤T A)(∀e)[{e}(e)6=h(e)]. Definition f is d.n.r. ⇐⇒ (∀e)[{e}(e)6=f(e)].

Definition f is d.n.r.(A) ⇐⇒ (∀e)[{e}A(e)6=f(e)]. On this concept, I was asked by Yokoyama-san...

(3)

Question (Yokoyama, March 2010)

Given any infinite recursive binary tree T and dnr function f, (∃f T f)(∃A∈[T])[f is dnr(A)] ??

Yes In fact,

(∃f T f)(∃inf f-rec tree T ⊂T)(∀A∈[T])[f is dnr(A)]. Let us prove this!

(4)

Theorem Given any inf. rec. binary tree T and f:dnr,

(∃f T f)(∃inf f-rec tree T ⊂T)(∀A∈[T])[f is dnr(A)]. Proof. For x∈ N<N and k,e∈ N, define

T(∅):=T and

T(x*k):={y ∈T(x):k6={|x|}y|y|(|x|) if the righthand is defined}, f(e)=f(q(e,f[e])), where

{q(e,x)}(n)= a if (∃a,b)(∀y∈T(x)∩2b)[a={|x|}y|y|(|x|)↓],

= ↑ otherwise.

(5)

Theorem Given any inf. rec. binary tree T and f:dnr,

(∃f T f)(∃inf f-rec tree T ⊂T)(∀A∈[T])[f is dnr(A)]. Proof. For x∈ N<N and k,e∈ N, define

T(∅):=T and

T(x*k):={y ∈T(x):k6={|x|}y|y|(|x|) if the righthand is defined}, f(e)=f(q(e,f[e])), where

{q(e,x)}(n)= a if (∃a,b)(∀y∈T(x)∩2b)[a={|x|}y|y|(|x|)↓],

= ↑ otherwise.

Note f(q(e,f[e]))6={q(e,x)}(q(e,x)).

Hence, T(f[e]) is infinite for all e by induction. Let T=TeT(f[e]).

Note (∀A∈T(f[e]*f(e)))[f(e)6={e}A(e)]. Hence, f is dnr(A).

(6)

Theorem Given any inf. rec. binary tree T and f:dnr,

(∃f T f)(∃inf f-rec tree T ⊂T)(∀A∈[T])[f is dnr(A)]. The above theorem can be used to show some theorem

concerning on reverse mathematics of second order arithmetic.

(7)

Reverse mathematics of second order arithmetic

Reverse mathematics is a study to classify “natural”

mathematical statements according to equivalence over a base system.

Many mathematical concepts and theorems can be formalized in second order arithmetic.

We can also formalize “f is dnr(A)” in second order arithmetic.

(8)

The strength of DNR

Theorems non-provable in RCA0 are quite often equivalent to one of the statements WWKL, WKL, ACA, ATR and Π11-CA over RCA0.

But the statement DNR is neither provable in RCA0 nor equivalent to one of these statements.

Here, DNR = (∀A)(∃f)(∀y)[f(y)6={y}A(y)]. It is known that DNR<WWKL<WKL< · · · .

(9)

Although many mathematical concepts and statements can be formalized in second order arithmetic,

sometimes they will become too complicated.

Nonstandard arithmetic and analysis

In nonstandard arithmetic and analysis, many concepts and theorems can be formalized by a simple notation or formula and can be proved in a simple way.

Example

f is continuous ⇐⇒ (∀x,y)[x ≈y ⇒ f(x)≈f(y)].

(10)

Example of nonstandard argument

Theorem (∀{xn}n∈N ⊂[0,1])[{xn}n has an accumulating point].

Sketch of Proof.

Let n > N and a∈ R such that a≈xn∗ . By Transfer Principle,

(∀k∈ N)(∃m>k)[|xm-a| <1/k]

since (∀k ∈ N)(∃m >k)[|xm∗-a| <1/k].

How about doing reverse mathematics with nonstandard argument??

(11)

Review of RCA0

L :={0,1,=,+,·,<,∈}

There are two sorts for natural numbers and for sets of natural number.

• x,y,· · · for natural numbers,

• X,Y,· · · for sets of natural numbers. The axioms of RCA0 consists of

BASIC axioms + IΣ01 + ∆01-CA.

(12)

Lns

L :={0,1,=,+,·,<,∈}

L:={0,1,=,+,·,<,} Lns:=L ∪ L∪{}

• x,y,· · · for standard natural numbers,

• X,Y,· · · for sets of standard natural numbers.

• x,y,· · · for nonstandard natural numbers,

• X,Y,· · · for sets of nonstandard natural numbers.

(13)

Structures for Lns=L ∪ L∪{}

N =(N,SN ,0N ,1N ,+N ,·N ,<N ) is an L-structure is defined in a natural way.

N ns=(N ,N ,N ns) is an Lns-structure ⇐⇒

• N is an L-structure,

• N is an L-structure,

is a function mapping N (resp. SN ) into N (resp. SN ∗).

(14)

Terms and Formulas for Lns=L ∪ L∪{}

I hope you can imagine what are Lns-terms and Lns-formulas. Example.

1. “x is a bigger than any standard natural number (x > N)”

≡ (∀y)[(y)<x].

2. “If A is unbounded, then (A) has an infinitely large number”

≡ (∀A)[(∃x)[x∈A]⇒(∃y > N)[y(A)]]. 3. “N ⊂e N

≡ (∀x)(∀y < (x))(∃z)[y=(z)].

(15)

Notations

Given an L-formula F,

F: an Lns-formula obtained by adding * to all L-symbols in F.

(16)

RCAns0 =RCA0 +

: N ֒→ N and N ⊂e N .

• N ≡Σ1

1 N

: for any sentence F in Σ11(L)

F ⇐⇒ F

• N ≺Σ0

0 N

: for any F(x,X) in Σ00(L) (∀x)(∀X)[F(x,X) ⇐⇒ F((x),(X))]

• Σ01 overspill: for any F(x,y) in Σ01(L)

(∀x)(∃y>x)[F(x,y)]⇒(∃y > N)(∀x)[F((x),y)]

• Finite standard part principle:

(∀X)[card(X)∈ N ⇒(∃Y)(∀x)[x∈Y ⇐⇒ (x)∈X]]

(17)

WKLns0 =WKL0 +

: N ֒→ N and N ⊂e N .

• N ≡Σ1

1 N

: for any sentence F in Σ11(L)

F ⇐⇒ F

• N ≺Σ0

0 N

: for any F(x,X) in Σ00(L) (∀x)(∀X)[F(x,X) ⇐⇒ F((x),(X))]

• Σ01 overspill: for any F(x,y) in Σ01(L)

(∀x)(∃y>x)[F(x,y)]⇒(∃y > N)(∀x)[F((x),y)]

• Standard part principle:

(∀X)(∃Y)(∀x)[x∈Y ⇐⇒ (x)∈X]

(18)

RCA and WKL

It is known that

• RCAns0 is a conservative extension of RCA0.

• WKLns0 is a conservative extension of WKL0.

(19)

WKL0 conWKLns0

It is clear that every theorem in WKL0 is a theorem in WKLns0 . To see the converse, note that it suffices to prove:

(∀cntb nonst M |=WKL0)(∃N |=WKLns0 )[N ↾ L ∼= M].

(20)

(∀cntb nonst M |=WKL0)(∃N |=WKLns0 )[N ↾ L ∼= M] Theorem (Tanaka, 1997)

(∀cntb nonst M |=WKL0)(∃I (e M)[I ∼= M and SI=Code(I/M)].

Given cntb nonst M |=WKL0, take I (e M as in the above theorem.

Consider N =(I,M,Id(-like)).

(21)

(∀cntb nonst M |=WKL0)(∃N |=WKLns0 )[N ↾ L ∼= M] Theorem (Tanaka, 1997)

(∀cntb nonst M |=WKL0)(∃I (e M)[I ∼= M and SI=Code(I/M)].

Given cntb nonst M |=WKL0, take I (e M as in the above theorem.

Consider N =(I,M,Id(-like)). N satisfies:

• I ≡Σ1

1 M since I ∼= M;

• I ≺Σ0

0 M since I ⊂e M;

• Σ01 overspill since I (e M |=IΣ01;

• (∀X)(∃Y)(∀x)[x∈Y⇔ (x)∈X] since SI=Code(I/M).

(22)

DNR and DNRns

DNR0 = RCA0 + (∀A)(∃f)(∀y)[f(y)6={y}(A;y)].

DNRns0 = RCAns0 + (∀x)(∃f)(∀y)[f(y)6={y}(Code(x);y)]. Main Theorem DNR0 conDNRns0 .

We see an idea of proof and end this talk.

(23)

DNR0 conDNRns0 .

• DNR0 = RCA0 + (∀A)(∃f)(∀y)[f(y)6={y}(A;y)].

• DNRns0 = RCAns0 + (∀x)(∃f)(∀y)[f(y)6={y}(Code(x);y)].

It is easy to see that every theorem in DNR0 is a theorem in DNRns0 .

To show the converse, note that it suffices to prove:

(∀cntb nonst M |=DNR0)(∃N |=DNRns0 )[N ↾ L ∼= M].

(24)

(∀cntb nonst M |=DNR0)(∃N |=DNRns0 )[N ↾ L ∼= M].

• DNR0 = RCA0 + (∀A)(∃f)(∀y)[f(y)6={y}(A;y)].

• DNRns0 = RCAns0 + (∀x)(∃f)(∀y)[f(y)6={y}(Code(x);y)].

(25)

(∀cntb nonst M |=DNR0)(∃N |=DNRns0 )[N ↾ L ∼= M].

• DNR0 = RCA0 + (∀A)(∃f)(∀y)[f(y)6={y}(A;y)].

• DNRns0 = RCAns0 + (∀x)(∃f)(∀y)[f(y)6={y}(Code(x);y)]. Definition M0 d M1 iff M0 ω M1 and

(∀A∈SM1)(∃f∈SM0)[M1 |=f is dnr(A)].

(26)

(∀cntb nonst M |=DNR0)(∃N |=DNRns0 )[N ↾ L ∼= M].

• DNR0 = RCA0 + (∀A)(∃f)(∀y)[f(y)6={y}(A;y)].

• DNRns0 = RCAns0 + (∀x)(∃f)(∀y)[f(y)6={y}(Code(x);y)]. Definition M0 d M1 iff M0 ω M1 and

(∀A∈SM1)(∃f∈SM0)[M1 |=f is dnr(A)]. Recall the following theorem holds,

Given any inf. rec. binary tree T and f:dnr,

(∃f T f)(∃inf f-rec tree T ⊂T)(∀A∈[T])[f is dnr(A)]. By the same argument of proof, we can modify the above theorem to...

(27)

(∀cntb nonst M |=DNR0)(∃N |=DNRns0 )[N ↾ L ∼= M].

• DNR0 = RCA0 + (∀A)(∃f)(∀y)[f(y)6={y}(A;y)].

• DNRns0 = RCAns0 + (∀x)(∃f)(∀y)[f(y)6={y}(Code(x);y)]. Definition M0 d M1 iff M0 ω M1 and

(∀A∈SM1)(∃f∈SM0)[M1 |=f is dnr(A)].

Given any inf. binary tree T∈SM1 and A∈SM1,

(∃inf tree T ⊂T in SM1)(∀B∈[T])(∃f∈SM1)[M1 |=f is dnr(A⊕B)].

(28)

(∀cntb nonst M |=DNR0)(∃N |=DNRns0 )[N ↾ L ∼= M].

• DNR0 = RCA0 + (∀A)(∃f)(∀y)[f(y)6={y}(A;y)].

• DNRns0 = RCAns0 + (∀x)(∃f)(∀y)[f(y)6={y}(Code(x);y)]. Definition M0 d M1 iff M0 ω M1 and

(∀A∈SM1)(∃f∈SM0)[M1 |=f is dnr(A)].

Given any inf. binary tree T∈SM1 and A∈SM1,

(∃inf tree T ⊂T in SM1)(∀B∈[T])(∃f∈SM1)[M1 |=f is dnr(A⊕B)].

Theorem (Harrington, 1977)

(∀cntb M0 |=RCA0)(∃M1 ω M0)[M1 |=WKL0]. Combining the technique of these theorems, we have...

(29)

(∀cntb nonst M |=DNR0)(∃N |=DNRns0 )[N ↾ L ∼= M].

• DNR0 = RCA0 + (∀A)(∃f)(∀y)[f(y)6={y}(A;y)].

• DNRns0 = RCAns0 + (∀x)(∃f)(∀y)[f(y)6={y}(Code(x);y)]. Definition M0 d M1 iff M0 ω M1 and

(∀A∈SM1)(∃f∈SM0)[M1 |=f is dnr(A)].

Theorem (∀cntb M |=DNR0)(∃Md M)[M |=WKL0].

(30)

(∀cntb nonst M |=DNR0)(∃N |=DNRns0 )[N ↾ L ∼= M].

• DNR0 = RCA0 + (∀A)(∃f)(∀y)[f(y)6={y}(A;y)].

• DNRns0 = RCAns0 + (∀x)(∃f)(∀y)[f(y)6={y}(Code(x);y)]. Definition M0 d M1 iff M0 ω M1 and

(∀A∈SM1)(∃f∈SM0)[M1 |=f is dnr(A)].

Theorem (∀cntb M |=DNR0)(∃Md M)[M |=WKL0]. From this theorem, we can conclude our claim by the same

argument for WKL0 conWKLns0 .

(31)

fin.

参照

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