• 検索結果がありません。

HW09 solutions Recent site activity Physics 193

N/A
N/A
Protected

Academic year: 2018

シェア "HW09 solutions Recent site activity Physics 193"

Copied!
2
0
0

読み込み中.... (全文を見る)

全文

(1)

Homework 9 solutions

Notes: Please keep in mind that most of the problems in MasteringPhysics with numerical answers are randomized for each student. The solutions below correspond to the version of the problem that is in the paper copy of the textbook. There may be some differences between the textbook version and the online version.

1. Reading questions

a. This is true. You get out of the shower and dry yourself off with a towel. You hang the towel to dry. An hour later you come back and the towel is no longer wet, just damp. An hour after that the towel is almost totally dry but not quite. After one more hour the towel is completely dry. This can be explained by suggesting that the water absorbed by the towel is made of tiny entities called molecules that gradually escape into the air.

b. This is not true. Fill a metal sphere with air and seal it. Submerge the sphere in water and heat the water. The temperature of the gas increases as does its pressure, but the volume of the gas

remains the same. It does not decrease. (Only when you increase the pressure of gas keeping its temperature constant is the gas’s volume guaranteed to decrease.)

2. Tutorial (the problem parts plus the hints in MasteringPhysics walk you through how to do it)

3.

The estimated number of hydrogen atoms in the Sun is

N

H= 0.70m

SUN

M

H/NA

= 0.70 2×10 30

kg

(

)

1.0×1023kg

(

)

/ 6.02

(

×1023

)

=8.4×1056

4.

We take the density of air to be ρ=1.3 kg/m3. Thus, the mass of air exhaled is

m

exV = 1.3 kg/m

3

(

)

4.8×1023 m3

(

)

=6.24×1023

kg

The air that you exhale has higher concentration of CO2 and water vapor and less O2. The temperatures between

the air inhaled and air exhaled can also be different.

5.

Let the temperatures be 298 K during the day, and 288 K at night, and volume of the house be 900 m3. Using ideal gas model for air, the number of moles of air that must leave the house in order to maintain a constant pressure is

Δn=n

2−n1=

P

2V2

RT

2 − P1V1

RT

1

=

1.0×105

N/m2

(

)

900 m3

(

)

8.3 J/mol⋅K

(

)

1

288 K− 1

298 K

⎛ ⎝⎜

⎠⎟ =1.26×10 3

mol

6.

(2)

n= PV RT =

1.0×105 N/m2

(

)

(

0.0005 m3

)

8.3 J/molK

(

)

(

293 K

)

=

0.021 mol

Since only about 21% of air is O2, the number of oxygen molecules you breathe in each time is

N

O

2

参照

関連したドキュメント

Using general ideas from Theorem 4 of [3] and the Schwarz symmetrization, we obtain the following theorem on radial symmetry in the case of p > 1..

[11] Karsai J., On the asymptotic behaviour of solution of second order linear differential equations with small damping, Acta Math. 61

The main novelty of this paper is to provide proofs of natural prop- erties of the branches that build the solution diagram for both smooth and non- smooth double-well potentials,

Keywords: continuous time random walk, Brownian motion, collision time, skew Young tableaux, tandem queue.. AMS 2000 Subject Classification: Primary:

7, Fan subequation method 8, projective Riccati equation method 9, differential transform method 10, direct algebraic method 11, first integral method 12, Hirota’s bilinear method

Kilbas; Conditions of the existence of a classical solution of a Cauchy type problem for the diffusion equation with the Riemann-Liouville partial derivative, Differential Equations,

As a consequence of this characterization, we get a characterization of the convex ideal hyperbolic polyhedra associated to a compact surface with genus greater than one (Corollary

This paper presents an investigation into the mechanics of this specific problem and develops an analytical approach that accounts for the effects of geometrical and material data on