G G G
EEOEOO---D D D
IIISSASAASSSTTTEERERRP P P
RRREEEVVVEEENNNTTTIIIOONONNS S S
YYYSSTSTTEEMEMM 1/4G G G
EEEOOOS S S
CCICIIEEENNNCCCEEE&& &G G G
EEEOOOE E E
NNGNGGIIINNENEEEEERRRIIINNNGG GLLALAABBB http://www.cm.nitech.ac.jp/maeda-lab/ 3.微分方程式の導出3.1 一次元波動方程式の導入(Introduction to Wave Propagation in 1D)
・ 微分表記(Detonations for differential)
( ) x t
u
u = ,
,x
u
xu
∂ ∂
=
,t
u
tu
∂ ∂
=
, 22
x
u
xxu
∂ ∂
=
, 22
t
u
ttu
∂ ∂
=
・ 微小振幅(Infinitesimal Amplitude)
→ 0
θ
⇒cos θ → 1
,sin θ → θ
,tan θ → θ
:x
x
x
u
∂ ∂
θ ≈
・ 釣合い式・運動方程式(Equilibrium / Motion Equation)
( ) cos 0
cos + + =
− T θ
xT dT θ
x+dx x-direction( ) sin 0
sin + + =
−
⋅
⋅
− ρ dx u
ttT θ
xT dT θ
x+dx y-direction↓
≈ 0
dT
x-direction( − ) = 0
−
⋅
⋅
− ρ dx u
ttT u
xu
x+dx y-direction↓
( ) ( x t T x dx t )
T , = + ,
x-direction→0 +
⎟⎟⎠ ⎞
⎜⎜⎝ ⎛ −
=
=
dx x dx x xx
tt
dx
u
u
u T
u T
ρ
ρ
y-direction 振動する弦の小片(x
,x + ∆ x
)と作用する力Infinitesimal element (
x
,x + ∆ x
)of bowstring in 1D vibration and forcesT
(internal tension) applied to it.x x + dx
dx
T
T d +
T u ( x + dx , t )
( ) x t
u ,
dx x+
θ
x x
u
x= tan θ ≈ sin θ
θ
xG G G
EEOEOO---D D D
IIISSASAASSSTTTEERERRP P P
RRREEEVVVEEENNNTTTIIIOONONNS S S
YYYSSTSTTEEMEMM 2/4G G G
EEEOOOS S S
CCICIIEEENNNCCCEEE&& &G G G
EEEOOOE E E
NNGNGGIIINNENEEEEERRRIIINNNGG GLLALAABBB http://www.cm.nitech.ac.jp/maeda-lab/ 3.微分方程式の解析解:解放3.1 波動方程式の D’Alembert 解(D’Alembert’s Solution for Differential Equations for Wave Propagation)
Differential Equation
xx
tt
V u
u =
2 , (− ∞ < x < ∞
,0 < t < ∞
) (1)Initial Conditions: We must two initial conditions to solve wave propagation with second differential equation
( ) ( )
( ) ( )
⎩ ⎨
⎧
=
=
x
g
x
u
x
f
x
u
t
, 0
0
,
, (− ∞ < x < ∞
) (2)D’Alembert’s Solution
1.- Replacement:
{ } { } x , t ⇒ ξ , η
⎩ ⎨
⎧
−
=
+
=
Vt
x
Vt
x
η ξ
(3)= 0
u
ξη (4)( )
( )
⎪ ⎪
⎩
⎪⎪ ⎨
⎧
+
+
=
+
+
=
−
=
+
=
ηη ξη ξξ
ηη ξη ξξ
η ξ
η ξ
u
u
u
V
u
u
u
u
u
u
u
V
u
u
u
u
tt xx
t x
2
2
2
(5)
2.- Integration
( ) ( ) ξ η φ η
η
, =
u
; Arbitrary Functionφ ( ) η
asη
(6)( ) ( ) ( ) ξ , η = Φ η + θ ξ
u
(7)Arbitrary Function
θ ( ) ξ
asξ
( ) = ∫ ( )
Φ η φ η d η
G G G
EEOEOO---D D D
IIISSASAASSSTTTEERERRP P P
RRREEEVVVEEENNNTTTIIIOONONNS S S
YYYSSTSTTEEMEMM 3/4G G G
EEEOOOS S S
CCICIIEEENNNCCCEEE&& &G G G
EEEOOOE E E
NNGNGGIIINNENEEEEERRRIIINNNGG GLLALAABBB http://www.cm.nitech.ac.jp/maeda-lab/ 3.- Replacement:{ } { } ξ , η ⇒ x, t
( ) ( x t x Vt ) ( x Vt )
u , = φ − + θ +
(8)4.- Initial Condition:
( ) ( x t x Vt ) ( x Vt )
u , = φ − + θ +
( ) ( )
( ) ( )
⎩ ⎨
⎧ =
=
x
g
x
u
x
f
x
u
t
, 0
0
,
( ) ( ) ( )
( ) ( ) ( )
⎩ ⎨
⎧
′ =
′ +
−
=
+
x
g
x
V
x
V
x
f
x
x
θ
φ θ
φ
(9)( ) + ( ) = ∫ ( ) +
−
xx
K
d
g
x
V
x
V
0
ξ
ξ
θ
φ
(10)( ) = ( ) − ∫x ( ) −
x
K
d
V g
x
f
x
0
2
1
2
1 ξ ξ
φ
(11)( ) = ( ) + ∫x ( ) +
x
K
d
V g
x
f
x
0
2
1
2
1 ξ ξ
θ
(12)( ) [ ( ) ( ) ]
+∫ ( )
−
+
+
+
−
=
xVtVt x
d
V g
Vt
x
f
Vt
x
f
t
x
u ξ ξ
2
1
2
, 1
(13) ux 0
V: propagation velocity
1 2
t=0 t=1/V t=2/V
φ (η )=C
u
x 0 -1
t=0 t=1/V
t=2/V
θ (ξ )=C
-2
G G G
EEOEOO---D D D
IIISSASAASSSTTTEERERRP P P
RRREEEVVVEEENNNTTTIIIOONONNS S S
YYYSSTSTTEEMEMM 4/4G G G
EEEOOOS S S
CCICIIEEENNNCCCEEE&& &G G G
EEEOOOE E E
NNGNGGIIINNENEEEEERRRIIINNNGG GLLALAABBB http://www.cm.nitech.ac.jp/maeda-lab/ - 特性曲線(Characteristic Curve)Example-1
Initial condition
( ) ( )
( ) ( )
⎩ ⎨
⎧
=
=
=
0
0
,
0
,
x
g
x
u
x
f
x
u
t
(14)
( ) x t [ f ( x Vt ) ( f x Vt ) ]
u = − + +
2
, 1
(15)characteristic curve
⎩ ⎨
⎧
+
=
+
−
=
−
a a
a a
Vt
x
Vt
x
Vt
x
Vt
x
(16)Example-2
( ) ( ) ( )
⎪⎩ ( )
⎪ ⎨
⎧
⎩ =
⎨ ⎧ − ≤ ≤
=
=
0
0
,
int
0
1
1
0 1
,
x
u
s
po
other
the
x x
f
x
u
t
(17)
Characteristic curve x = -1 or 1 , t=0
⎩ ⎨
⎧
±
=
+
±
=
−
1
1
Vt
x
Vt
x
(18)t
x
u(x
a, t
a)
(x
a-Vt
a, 0) 0 (x
a+ Vt
a, 0)
x-Vt=x
a-Vt
ax + Vt=x
a+ Vt
ax-Vt=0
x + Vt=0
u
x
-1 0 1
1
u
x
-1 0 1
1
1/2 1/2
t
x -1
u=0 u=1/2 u=1/2 u=0
u=0 u=0
0 1
u=1
x-Vt=1 x-Vt=-1
x+Vt=1 x+Vt=-1