• 検索結果がありません。

発表ファイル 数理物理・物性基礎論セミナー Watanabe 2 examples

N/A
N/A
Protected

Academic year: 2018

シェア "発表ファイル 数理物理・物性基礎論セミナー Watanabe 2 examples"

Copied!
10
0
0

読み込み中.... (全文を見る)

全文

(1)

1. Goldstone model (relativistic, n

NGB

= dim G  H)

J. Goldstone, Nuovo Cimento 19, 154 (1961)



Ÿ Lagrangian

L = ¶Μj*Μj - VHj*jL

= ¶Μj*Μj + m2j*j -g

2Hj

*jL2.

- G = UH1L: j' HxL = ãä Q ΕjHxL ã-ä Q Ε= jHxL ãä Ε.

Ÿ Potential minimum

V 'Hj*jL = gHj*jL - m2= 0 ® v2=m2

g.

- For example, we can set Xj\ = v Î R.

- H =8e<: U(1) symmetry is completely broken. X@ä Q, jHxLD\ = X∆ j\ = ä v ¹ 0.

- dimHGL - dimHHL = 1 - 0 = 1.

Ÿ Fluctuation around the minimum Substitute j = v +Σ+ä Π

2 and expand L in the series of Σ, Π: L = 12ΜΣ ¶ΜΣ + ¶ΜΠ ¶ΜΠM + m2Jv2+ 2 v Σ +Σ22

2 N - g 2Jv

2+ 2 v Σ +Σ22

2 N

2

= 1

2ΜΠ ¶ ΜΠ+ 1

2ΜΣ ¶

ΜΣ - 2 m2Σ2M+m4 2 g-

g v 2

3+ Σ Π2M -g 8

2+ Π2M2

- No mass term for the Goldstone mode Π. The linear dispersion Ω = c k.

- The detailed form of the Lagrangian depends on the parametrization. We could choose, e.g., j =Hv + ΣL ãä Π. - This example: OH2L ® OH1L

® Can be generalized to OHnL ® OHn - 1L. dimHGL - dimHHL = nHn-1L2 -Hn-1L Hn-2L

2 = n - 1.

2. U(2)/U(1) model (nonrelativistic, n

NGB

< dim G  H when Μ ¹ 0)

T. Schäfer, D.T. Son, M.A. Stephanov, D. Toublan, J.J.M. Verbaarschot, Phys. Lett. B 522, 67 (2001) V. A. Miransky, I. A. Shovkovy, PRL 88 111601 (2002)

Ÿ Lagrangian j =Kj1

j2O: two-component bosonic field.

L

¹ 0

H2L H L

Σ

Printed by Mathematica for Students

(2)

K 2O

L =Ν+ä ∆Ν 0ΜL j*Ν-ä ∆Ν 0ΜLj - VHj*jL

=Ν+ä ∆Ν 0ΜL j*Ν-ä ∆Ν 0ΜL j + m2j*j -g

2Hj

*jL2.

- U(1) chemical potential A0= Μ ¹ 0

(i) explicitely breaks the Lorentz symmetry, (ii) reduces O(4) symmetry down to U(2). (iii) breaks the charge conjugation. - G = UH2L: j' HxL = ãä QiΕijHxL ã-ä QiΕi= ãä Εi Σ2ijHxL.

Σ0: unit matrix Σ1,2,3: Pauli matrices

Ÿ Potential minimum

V 'Hj*jL = gHj*jL - Im2+ Μ2M = 0 ® v2=m

22

g .

- For example, we can set Xj\ = 0

v , v Î R. - H = UH1L generated by Q0+ Q3.

X@ä Q0, jHxLD\ = äΣ20 0v = ä 12 0v , X@ä Q1, jHxLD\ = äΣ21 0v = ä 12 v0 , X@ä Q2, jHxLD\ = äΣ22 0v = ä 12 -ä v0 , X@ä Q3, jHxLD\ = äΣ3

2

0 v = ä

1 2

0 -v . - dimHGL - dimHHL = 4 - 1 = 3.

- Even when Μ = 0: G = OH4L, H = OH3L, dimHGL - dimHHL = 6 - 3 = 3.

Ÿ Fluctuation around the minimum

Substitute j =

Π1+ä Π2 2

v +Σ+ä Π3

2

and expand L in the series of Σ, Πa:

L =12ΜΣ ¶ΜΣ + ¶ΜΠaΜΠaM + Im2+ Μ2M Jv2+ 2 v Σ +Σ22aΠaN - g2Jv2+ 2 v Σ +Σ22aΠaN2

=1

2 ΜΠ

aΜΠa+ Μ 1Π

 

2- Π2Π

 

1L + ΜHΣ Π 3- Π3Σ  L +

1 2ΜΣ ¶

ΜΣ - 2Im2+ Μ2M Σ2E + Im22M

2

2 g -

g v 2

3+ Σ ΠaΠaM -g 8

2+ ΠaΠaM2

>A12 ΜΠ1ΜΠ1+ 1 2ΜΠ

2ΜΠ2+ Μ 1Π

 

2- Π2Π

 

1LE + B12ΜΠ3ΜΠ3+ Μ2 m22Π

 

32F - Im2+ Μ2M JΣ -m2Μ2Π

 

3N2+ … - Completing square for massive modes ® “integrating out” at the tree level.

- Π3 gives a mode with the dispersion J1 + Μ

2

m22N Ω

2- k2= 0.

- Π1,2 together give a single gapless mode. EOM: det

2- k2 2 ä Μ Ω

-2 ä Μ Ω Ω2- k2 = 0 [solve this together?]

2= k2+ 2 Μ2± 2 Μ4+ k2Μ2 =Jk2

2 ΜN 2

+ OIk6M, 4 Μ2+ 2 k2+ OIk4M - In total, only two Goldstone modes appear.

nNGB= 2 < dimHGHL = 3

] ]

= 0

= k ]

Printed by Mathematica for Students

(3)

nNGB= 2 < dimHGHL = 3

In this example, the total number of mode agrees with the expected number.

- Nonzero (Noether) charge density: ji0=0+ä ΜL j*äΣi

2 j + c.c.

Yj00] =-Μ v2, Yj10] = 0, Yj20] = 0, Yj30] = Μ v2.

- When Μ = 0, L =A1

2ΜΠ

1ΜΠ1+ 1 2ΜΠ

2ΜΠ2+ Μ

1Π 2- Π2Π 1LE + B21ΜΠ3ΜΠ3+ Μ

2

m22Π

 

32F - Im2+ Μ2M JΣ -m2Μ2Π

 

3N2+ … each Πa=1,2,3 corresponds to a linear mode with Ω = k. No charge densities Yji0] = 0.

- Set Ω = k2

2 Μ:

2- k2 2 ä Μ Ω -2 ä Μ Ω Ω2- k2 µ

-1 ä -ä -1 . Eigenvector: 1

-ä ¬ “circular polarization”

Þ ja=10= Φ, ja=20= -ä Φ. So, Q1- ä Q2 does not couple to any zero mode but this is not a contradiction. (cf. S+ 0\ = 0 for ferromagnet)

Ÿ Normalization of the field...

We can change parametrization j =

Π1+ä Π2 2

v +Σ+ä Π3

2

® j =Hv + ΣL ãä

Σa 2 Π

a

L =Bv2

4 ΜΠ

1ΜΠ1+v2 4 ΜΠ

2ΜΠ2+ Μ v2 2 2Π

 

1- Π1Π 2LF + B v2

4 ΜΠ

3ΜΠ3+v2 2

Μ2 m22Π

 

32F

3. Ferromagnet (nonrelativistic, n

NGB

< dimHG  H L)

Ÿ Heisenberg Hamiltonian H = -JÚXi,j\si× sj (J > 0)

G = SOH3L leaves H and Asix, sjyE = i ∆i jsiz intact.

c.f. Li= S cosΘiΦ

 

i+ J si× si+1.

HΘ, ΦL: sphererical coordinate of S = S n. HcosΘ - 1L Φ  = nyn 1+nx-nzxn y: the Berry phase term

® very complicated but still SU(2) invariant up to a surface term.

Printed by Mathematica for Students

(4)

nx=Sin@Θ@tDDCos@Φ@tDD; ny=Sin@Θ@tDDSin@Φ@tDD; nz=Cos@Θ@tDD;

FullSimplifyB-

nx D@ny, tD -ny D@nx, tD 1+nz

-HCos@Θ@tDD -1LD@Φ@tD, tDF 0

Ÿ Ground state configuration S =Úisi

Szi GS\ = S  GS\

X@ä Sx, siyD\ = -Xsiz\ = -S ¹ 0. X@ä Sy, sixD\ = Xsiz\ = S ¹ 0. - H = SOH2L generated by Sz. - Spin (charge) density Xsiz\ = S.

- S+ 0\ = ISx+ ä SyM  0\ = 0 Þ Sx 0\ = -ä Sy 0\.

Ÿ Excitation (Holstein-Primakov transformation with the large S approximation) siz= S - n`i

si+= 2 S - n`i b`i» 2 S b`i

si-= b`i¾ 2 S - n`i » b`i¾ 2 S

H S =

-J S ÚXi,j\J

s-isj++sj-s+i

2 + si

zsz jN

= -JÚXi,j\Ib`i¾ b`j+ b`j¾ b`i- 2 b`i¾ b`iM + OJ b3

SN

= 2 JÚkÚΑ@1 - cosHkΑaLD b`k¾ b`k+ OJbS3N

Only one NGB with a quadratic dispersion Ω =IJ S a2M k2.

Ÿ Excitation (effective Lagrangian) L =ÚiS cosΘiΦ i+ JÚXi,j\si× sj

=Úiad S

ad

nyn x-nxn y

1+nz -ÚXi,j\a

d J

2 adBIsi- sjM

2- 2 SHS + 1LF

»Ù ddxBS

ad

nyn x-nxn y 1+nz -

J a2

2 adΑs × ¶ΑsF

L » 1

2 S ad AHΠ

yΠ x - ΠxΠ yL - J S a2

xΠaxΠaE ¬ s = Sy

Πx 1 EOM: det -J S a

2k2 ä Ω

- ä Ω - J S a2k2 = 0 [solve this together?] Ω = J S a2k2.

(5)

4. Antiferromagnet (nonrelativistic, n

NGB

= dimHG  H L)

Ÿ Heisenberg Hamiltonian (for simplicity, d=1.) Hi=+J si× si+1 (J > 0).

G = SOH3L leaves H and Asix, sjyE = i ∆i jsiz intact. Li= S cosΘiΦ i- J si× si+1.

Ÿ Holstein-Primakov transformation with the large S approximation s2 iz= S - n`2 i

s2 i+= 2 S - n`2 i b`2 i» 2 S b`2 i

s2 i-= b`i¾ 2 S - n`2 i » 2 S b`2 i¾ and

s2 i+1z= n`2 i+1- S

s2 i+1+= b`2 i+1¾ 2 S - n`2 i+1 » 2 S b`2 i+1¾ s2 i+1-= 2 S - n`2 i+1 b2 i+1» 2 S b`2 i+1

Then,

H S =

J SÚiJ

s2 i+1-s2 i++s2 i-s2 i+1+

2 + s2 i

zs

2 i+1zN +JSÚiJs2 i-s2 i-1++s22 i-1-s2 i+ + s2 izs2 i-1zN

> J ÚiIb`2 i+1b`2 i+ b`2 i¾ b`2 i+1¾ + n`2 i+1+ n`2 iM + J ÚiIb`2 i¾ b`2 i-1¾ + b`2 i-1b`2 i+ n`2 i-1+ n`2 iM

= J ÚiIb`i+1b`i+ b

`

i¾ b`i+1¾ + 2 n`iM

= J Ú-Π

a£k £ Π a

AcosHk aL b`-kb`k+ cosHk aL b`-k¾ b`k¾ + bk¾ bk+ b-k¾ b-kE

= 2 J Ú0£k £Π a

H bk¾ b-kL cos1Hk aL cos1Hk aL bbk

-k¾

= 2 J Ú0£k £Π

aH Β

k¾ Β-kL

cosh Θ sinh Θ sinh Θ cosh Θ

1 cosHk aL cosHk aL 1

cosh Θ sinh Θ sinh Θ cosh Θ

Βk

Β-k¾

= 2 J Ú0£k £Π

aH Β

k¾ Β-kL

1 - cos2Hk aL 0 0 1 - cos2Hk aL

Βk

Β-k¾

¬ tanhH2 ΘL = -cosHk aL

= 2 J Ú-Π

2 a£k £ Π 2 a

1 - cos2Hk aL JΒk¾ Βk+ ΒΠ

a+k

¾ ΒΠ

a+kN

Two NGBs with the linear dispersion Ω =H2 J S aL k.

Ÿ Excitation (effective Lagrangian)

Printed by Mathematica for Students

(6)

IÙ d t cosΘ Φ  M

=Ù d t IcosΘ ∆ Φ  - sinΘ ∆Θ Φ  M

=Ù d t IsinΘ ∆Φ Θ  - sinΘ ∆Θ Φ  M

=Ù d t IsinΘ ∆Φ Θ  - sinΘ ∆Θ Φ  M

=Ù d t ∆n×n´n  nŽi=H-1Lini

L = SÚicosΘiΦ i- J S2Úini× ni+1

= SÚiH-1Licos ȎiΦ

Ž 

i+ J S2Úin

Ž

i× n

Ž

i+1

= S

2ÚiH-1L

i+1Jcos Ȏ

i+1֎ i+1- cos Ȏi֎ iN -1

2J S 2Ú

iHnŽi+1- nŽiL2

®S

2 ÚiH-1L i+1HnŽ

i+1- nŽiL×nŽi´ nŽ i-1

2J S 2Ú

iHnŽi+1- nŽiL2

= S

2ÚiH-1L i+1HnŽ

i+1- nŽiL×nŽi´ nŽ i- 1

2J S 2Ú

iHnŽi+1- nŽiL2 We introduce slowly varying fields n and s by nŽi= nHxiL + H-1LisHxiL

L > 12S ¶xn × n ´ n  +S

as × n ´ n

  - 1

2 a J S

2A4 s2+Ha ¶ xnL2E

= 1

2S ¶xn × n ´ n

  -2 J S2

a Js - n´n  4 J SN

2

+ 2 J S2

a J

n´n  4 J SN

2

- 1

2 aJ S 2Ha ¶

xnL2

> 8 a J1 An 2- H2 J S aL2xnL2E+ S

2xn × n ´ n

  - 2 J S2

a Js - n´n  4 J SN

2

- Topological term 2 Π S W@nD = 2 Π S Ùd x d t4 Π xn × n ´ n  is particular to 1D. - Do the same for “ferri”magnet. e.g, SA¹ SB.

5. BEC (nonrelativistic, n

NGB

= dimHG  HL)

Ÿ Lagrangian

L = i Ψ¾ Ψ  - 1

2 mÑ Ψ¾ × Ñ Ψ + Μ Ψ¾ Ψ -g

2HΨ¾ ΨL 2

- G = UH1L: Ψ' HxL = ãä Q ΕΨHxL ã-ä Q Ε= ΨHxL ãä Ε.

Ÿ Potential minimum

V '*ΨL = gHΨ*ΨL - Μ = 0 ® XΨ*Ψ\ = n0= Μ

g.

- H =8e<: U(1) symmetry is completely broken. X@ä Q, ΨHxLD\ = X∆ Ψ\ = ä n0 ¹ 0. - dimHGL - dimHHL = 1 - 0 = 1.

Ÿ Fluctuation around the minimum Substitute Ψ = n ã-ä Π:

L = n Π  - nÑΠ×ÑΠ

2 m - Μ

2 n0Hn - n0L 2+ Μ

2 n0n0

2-Ñn×Ñn 8 m n

> n Π  - n0 ÑΠ×ÑΠ

2 m - Μ

2 n0Jn - n0- n0 Π Μ

 N2-Hn - n0L Π  + 2 nΜ

0

Π 2-Ñn×Ñn

8 m n

= n0

2 Μ

 2

- Μ

m Ñ Π × Ñ ΠM- Μ

2 n0Jn - n0- n0 Π Μ

 N2-Ñn×Ñn8 m n +n0Π 

- The Goldstone mode Π has the linear dispersion Ω2= Μk2.

(7)

- No dynamics for n. No amplitude mode. - If integrate out “Π” first,

Ln=1

2 ∆ n

*Jm Ω2 n0k2-

Μ n0-

k2 4 m n0N ∆ n

® X∆ n ∆ n\ = n0 1

m Ω2 k2 -Μ-

k2 4 m

Power-law decaying XnHx, tL nHy, tL\ » x-y¤1d+1¬ gapless contribution of Goldstone mode.

6. Spinor BEC (nonrelativistic, n

NGB

< dimHG  H L)

T. L. Ho, PRL 81, 742, (1998)

T. Ohmi, and K. Machida, J. Phys. Soc. Jpn. 67, 1822 (1998)

Ÿ Lagrangian

L = i Ψ¾ Ψ  - 1

2 mÑ Ψ¾ × Ñ Ψ + Μ Ψ¾ Ψ -g

2HΨ¾ ΨL 2+ J

2HΨ¾ TaΨL 2

- UH1L´SOH3L T1=

0 0 0 0 0 -ä 0 ä 0

, T2=

0 0 ä 0 0 0 -ä 0 0

, T3=

0 -ä 0 ä 0 0

0 0 0

.

Ÿ Potential minimum for g>J>0

T3XΨ\ = H+1L XΨ\, ¬ ferromagnetic XΨ\ = n0

1 2

1 ä 0

, n0= Μ g-J

HT3- T0L XΨ\ = 0 ® Q3- Q0: unbroken. - dimHGL - dimHHL = 4 - 1 = 3.

Ÿ Fluctuation around the minimum

Substitute, e.g., Ψ = n ãä T1Π1+ä T2Π2+ä Π3 1

2

1 ä 0

:

Up to total derivatives,

L =An202Π 1 - Π1Π 2M - n0

4 mIÑΠ

1× Ñ Π1+ Ñ Π2× Ñ Π2ME + B-n Π 3- n0

m Ñ Π

3× Ñ Π3- Μ

2 n0Hn - n0L 2- Ñn×Ñn

8 m n0F

- Only two NGBs: one linear Ω = mΜ k and one quadratic Ω = k2

2 m.

- Spin (charge) density Xs3\ = XΨ¾ T3Ψ\ = n0.

Printed by Mathematica for Students

(8)

T0=881, 0, 0<,80, 1, 0<,80, 0, 1<<; T1=880, 0, 0<,80, 0,- ä<,80,ä, 0<<; T2=880, 0,ä<,80, 0, 0<,8-ä, 0, 0<<; T3=880,- ä, 0<,, 0, 0<,80, 0, 0<<; Ψ =SeriesB

1 2

n0+ Εn@tD MatrixExp@Ε HäT1Π1@tD + äT2Π2@tD + äT0Π3@tDLD.81,ä, 0<,, 0, 2<F; Ψd=SeriesB

1 2

n0+ Εn@tD 81,- ä, 0<.MatrixExp@-Ε HäT1Π1@tD + äT2Π2@tD + äT0Π3@tDLD, , 0, 2<F;

HT3-T0L.HΨ .Ε ®0L; Simplifyd.ΨD

Simplify@Series@Dd, tD.D, tD,, 0, 2<DD SimplifyBSeriesB

ä Ψd.D, tD - äDd, tD 2

,, 0, 2<FF

n0+n@tD Ε +O@ΕD3 1

4 n0I

n¢@tD2+2 n021¢@tD2+ Π2¢@tD2+2Π3¢@tD2MM Ε2+O@ΕD3 -n0Π3¢@tD Ε +

1 2 H

n0Π2@tD Π1¢@tD -n0Π1@tD Π2¢@tD -2 n@tD Π3¢@tDL Ε2+O@ΕD3

7. Charged crystals under magnetic field in 2+1 D

(nonrelativistic, n

NGB

< dimHG  H L when B ¹ 0)

L =ÚiA1

2m x

 

i2+ 1

2q BHxiy

 

i- yix

 

iLE - Úi< jVIxi- xjM

® Leff= 1

2 a2m u

 2

+ 1

2J- q B

a2N Hu

yu x- uxu yL - EH¶ iuL where we introduced xiHtL = xi 0+ uHxi, tL.

- only one phonon mode when q B ¹ 0.

- no charge density but nonzero commutation relation 1

V@PB x, P

ByD = -ä q B

a2 (central extension). Here, PBx=ÚiIpx,i- 1

2q B yiM, PB y=Ú

iIpy,i+ 1

2q B xiM is the magnetic momentum. This is consistent with the empirical fact that any U(1) charges do not change nNGB. - Debye’s Td law Þ modified to Tdz

(9)

8. Free bosons (nonrelativistic, n

NGB

< dimHG  HL)

L = ä Ψ¾ ¶tΨ - 1

2 mÑ Ψ¾ Ñ Ψ,

Free bosons can be seen NGB (Ω = k2

2 m) of shift symmetries: Q1: Ψ ® Ψ + Ε1,

Q2: Ψ ® Ψ + ä Ε2,

which prohibit the mass term µ Ψ¾Ψ. - dimHGHL = 2, but only one NGB. - 1

V@Q1, Q2D = ä 2 ¬ Q1=Ù d

dx äHΨ¾ - ΨL, Q2= -Ù ddxHΨ + Ψ¾L - L =1

222Π

 

1- Π1Π

 

2L - ÑΠ1ÑΠ12 m+ÑΠ2ÑΠ2

Summary of examples

Ÿ 1. Goldstone model, 5. nonrelativistic BEC UH1L ® 8e<; dimHGHL = 1.

Leff=1

2ΜΠ ¶

ΜΠ + …. , L eff= n0

2 Μ

 2

- Μ

m Ñ Π × Ñ ΠM. 1

V X@Qa, QbD\ = 0.

Ÿ 2. U(2)/U(1) model, 6. Spinor BEC Μ =0

OH4L ® OH3L; dimHGHL = 3. Leff=v2

4 ΜΠ

1ΜΠ1+ v2 4 ΜΠ

2ΜΠ2+ v2 4 ΜΠ

3ΜΠ3+ …. 1

V X@Qa, QbD\ = 0.

nNGB- dimHGHL = 0. Μ ¹0

UH2L ® UH1L. Leff=Bv2

4 ΜΠ

1ΜΠ1+v2 4 ΜΠ

2ΜΠ2+ Μ v2 2 2Π

 

1- Π1Π

 

2LF + Bv42 mm22+3 Μ22 Π

 

3Π

 

3- v2 4 Ñ Π

3× Ñ Π3F + …. 1

V X@Q1, Q2D\ = Μ v 2

(nonzero Μ explicitely breaks the charge conjugation and nonzero charge density is allowed.) nNGB- dimHGHL =1.

Spinor BEC

UH1L´SOH3L´ T® UH1L ¬ time-reversal is spontaneously broken Leff=An0

2 2Π 1

- Π1Π 2M- n0

4 mIÑΠ

1× Ñ Π1+ Ñ Π2× Ñ Π2ME + n0

2 Μ

 3

Π 3-2 Μ

m Ñ Π

3× Ñ Π3F + …. 1

V X@S1, S2D\ = ä n0.

nNGB- dimHGHL =1.

Ÿ 3. Ferromagnet, 4. Antiferromagnet Ferromagnet: XSz\

V ¹ 0

SOH3L´ T® SOH2L.

] S L =1

Antiferromagnet

L T

L E E]

L = 0

Printed by Mathematica for Students

(10)

SOH3L´ T® SOH2L. Leff= S

ad

nyn x-nxn y 1+nz -

J a2

2 adΑs × ¶Αs

= 1

2 S ad AHΠ

yΠ x - ΠxΠ yL- J S a2

xΠaxΠaE + … .

1

V YASx, SyE] = S ad.

nNGB- dimHGHL =1.

Antiferromagnet: XSVz\= 0 ¬ unbroken time-reversal symmetry SOH3L´ T® SOH2L´ T.

Leff= 1

8 a JAn

 2

- H2 J S aL2xnL2E.

1

V YASx, SyE] = 0.

nNGB- dimHGHL = 0.

Ÿ 7. Charged crystals under B, 8 Free bosons

Charged crsytals:

R2® Z2 ¬ time-reversal symmetry is explicitely broken by the applied B Leff= 1

2 a2 m u

 2

+ 1

2J- q B

a2NHu

yu x- uxu yL- E iuL

1 V@PB

x, P

ByD = äJ-q Ba2N. nNGB- dimHGHL =1. Free bosons:

R2®8e< Leff=1

222Π

 

1- Π1Π 2L-ÑΠ1ÑΠ1+ÑΠ2ÑΠ2

2 m .

1

V@Q1, Q2D = ä2.

nNGB- dimHGHL =1.

The matrix 1

V X@Qa, QbD\ = äBfa b c XQc\

V + za bF is more fundamental than XQVc\. za b’s are central extentions.

What we learned from examples: - In general, 1 £ nNGB£ dimHGHL. - When nNGB< dimHGHL, ä Ρa bº 1

V X@Qa, QbD\ ¹ 0 for some a, b. - Ρa b= -ä1

V X@Qa, QbD\ appears in the low-energy Lagrangian as a coefficient of ΠbΠ a- ΠaΠ b term. - Can we develop a theory that captures this universal feature?

参照

関連したドキュメント

(4) It is immediate from the definition (2) that our sequence A is equal to its curling number transform, and in fact is the unique sequence with this property!. 2 The

(Furthermore, a bound on the number of elementary matrices can be found that depends only on n, and is universal for all fields.) In the case of fields, this can easily be

It is known that quasi-continuity implies somewhat continuity but there exist somewhat continuous functions which are not quasi-continuous [4].. Thus from Theorem 1 it follows that

We do not know whether this can be generalized to arbitrary smoothly compact groups, that is, smooth groups which are compact with respect to the initial topology induced on them

The aim of the present section is to prove that the Orthogonality Logic is complete (for all classes of morphisms) in all locally presentable categories iff the following

But in fact we can very quickly bound the axial elbows by the simple center-line method and so, in the vanilla algorithm, we will work only with upper bounds on the axial elbows..

Proof: The proof that k − Gonal(V ) is a k-gonal algebra does not present any difficulties and is left to the reader. We construct its universal extension φ as follows. It appears

this to the reader. Now, we come back to the proof of Step 2. Assume by contradiction that V is not empty.. Let u be the minimal solution with the given boundary values and let P be